1.

यदि `f(x)={{:((1-cos 4 x)/(x^(2))",","जब",x lt 0),(" "a",","जब",x = 0),(((sqrt(x)))/((16+sqrt(x))-4))",","जब",x gt 0):}` और f बिन्दु x = 0 पर संतत है, तो k का मान ज्ञात कीजिए ।

Answer» (i) `f(0) = a`
(ii) R.H.L. `=underset(x rarr 0^(+))(lim)f(x)=underset(h rarr 0)(lim)f(0+h)`
`=underset(h rarr 0)(lim)(sqrt((0+h)))/((sqrt(16+sqrt((0+h))))-4)," "[because x = 0 + h gt 0]`
`=underset(h rarr 0)(lim)(sqrt(h))/(sqrt(16+sqrt(h)))-4`
`=underset(h rarr 0)(lim)(sqrt(h))/((sqrt(16+sqrt(h)))-4)xx(sqrt(16+sqrt(h))+4)/((sqrt(16+sqrt(h)))+4)`
`=underset(h rarr 0)(lim)(sqrt(h)[sqrt(16+sqrt(h))+4])/(sqrt(h))`
`=underset(h rarr 0)(lim)(sqrt(h)[sqrt(16+sqrt(h))+h])/(sqrt(h))`
`=underset(h rarr 0)(lim)[sqrt(16+sqrt(h))+4]`
`=sqrt(16+0)+4`
`=4 + 4 = 8`
(iii) L.H.L. `underset(x rarr 0^(-))(lim)f(x)=underset(h rarr 0)(lim)f(0-h)`
`=underset(h rarr 0)(lim)(1-cos 4(0-h))/((0-h)^(2))," "[because x = 0 - h lt 0]`
`=underset(h rarr 0)(lim)(1-cos 4h)/(h^(2))`
`=underset(h rarr 0)(lim)(1-(1-2 sin^(2)2h))/(h^(2))," "[because sin 2 theta = 1 - 2 sin^(2)theta]`
`=underset(h rarr 0)(lim)(2 sin^(2)2h)/(h^(2))`
`=2 underset(h rarr 0)(lim)((sin 2h)/(2h))^(2)xx 4`
`= 2 xx 1 xx 4 = 8`
चूँकि दिया गया फलन x = 0 पर संतत है ।
`therefore" ""R.H.L.=L.H.L."=f(0)`
`rArr" "a = 8`


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