InterviewSolution
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InterviewSolution
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यदि (If) `y=sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))` , (find) `(dy)/(dx)` निकालें। |
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Answer» दिया है, `y=sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))` … (1) `thereforelogy=(1)/(2)log[((x-1)(x-2))/((x-3)(x-4)(x-5))]` `=(1)/(2)[log(x-1)+log(x-2)-log(x-3)-log(x-4)-log(x-5)]` x के सापेक्ष दोनों तरफ अवकलित (differentiate) करने पर हमें मिलता है, `(1)/(y)(dy)/(dx)=(1)/(2)[(1)/(x-1)+(1)/(x-2)-(1)/(x-3)-(1)/(x-4)-(1)/(x-5)]` `therefore(dy)/(dx)=(1)/(2)y[(1)/(x-1)+(1)/(x-2)-(1)/(x-3)-(1)/(x-4)-(1)/(x-5)]` `=(1)/(2)sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))[(1)/(x-1)+(1)/(x-2)-(1)/(x-3)-(1)/(x-4)-(1)/(x-5)]` |
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