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    				| 1. | यदि x + y + z = 9 और x2 + y2 + z2 = 35, तब x3 + y3 + z3 – 3xyz के मान ज्ञात कीजिए। | 
| Answer» x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz – zx) ……..(1) ∵ x + y + z = 9 वर्ग करने पर . x2 + y2 + z2 + 2(xy + y + zx) = 81 35 + 2(xy + yz + zx) = 81 2(xy + yz + zx) = 81 – 35 = 46 xy + yz + zx = 46/2 = 23 समी० (1) से x3 + y3 + z3 – 3xyz = 9(35 – 23) = 9 × 12 = 108 | |