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You are supplied with supplied with 500mL each of 2NHCL and HCL solutions.What is the maximum volume of 2M HCL solution that you can prepare using only these two solution ? |
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Answer» For HCI, Molarity=Normality. Let x mL be the maximum volume of 3M HCL that can be prepared by mixing 500 mL of 2MHCL solution and same volume of 5M HCI solution. `M_(1)V_(1)+M_(2)V_(2)=M_(3)V_(3)` `(2Mxx500mL)+(5MxxxmL)=3Mxx(500+x)mL` (100+5x)=(1500+3x) 2x= 1500-1000=500orx=250mL Thus , the maximum volume of 3M solution that can be prepared =(500+250)=750 mL |
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