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151.	Two compounds A and B were being tested for their boiling points. It was observed that A started boiling after B, when both were subjected to same conditions. If the compound B is acetone, which of the following can be compound A?(a) n-Butane(b) Methoxyethane(c) Propanal(d) PropanolThis question was addressed to me during an interview for a job.My doubt is from Aldehydes and Ketones Physical Properties in portion Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» The correct answer is (d) Propanol The best I can explain: It can be inferred that B has a higher boiling point than A. Since hydrocarbons, ethers and aldehydes have LOWER boiling points than ketones of similar molecular MASSES, NONE of them can be COMPOUND A. Also, ALCOHOLS have a higher boiling point than similar ketones hence, the compound A is propanol.

152.	Which of the following has a higher acidic character than benzoic acid?(a) Acetic acid(b) p-Methoxybenzoic acid(c) p-Bromobenzoic acid(d) p-Aminobenzoic acidThe question was posed to me in an international level competition.I'd like to ask this question from Carboxylic Acids Chemical Reactions topic in section Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» The correct answer is (c) p-Bromobenzoic acid To explain I would SAY: Bromine is an electron withdrawing GROUP that DISPERSE the negative charge on the carboxylate ion and strengthens its acidic character. p-Bromobenzoic acid has a pKa value of 3.96 COMPARED to 4.19, which is the pKa value of benzoic acid.

153.	How many products are formed from the aldol condensation reaction between ethanal and propanal?(a) 1(b) 2(c) 3(d) 4The question was asked in an online quiz.This key question is from Aldehydes and Ketones Chemical Reactions in portion Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» Right answer is (d) 4 To elaborate: Ethanal and propanal both CONTAIN α-hydrogen ATOMS and undergo aldol condensation to form a mixture of four products. The self-aldol products of ethanal and propanal are but-2-enal and 2-methylpent-2-enal respectively. The two products FORMED from the cross-aldol condensation between one MOLECULE of ethanal and one molecule of propanal are 2-methylbut-2-enal and pent-2-enal.

154.	What is the IUPAC name of (C6H5)CH2CH2COOH?(a) 2-Phenylethanoic acid(b) 2-Phenylpropanoic acid(c) 3-Phenylethanoic acid(d) 3-Phenylpropanoic acidI had been asked this question in final exam.My question comes from Nomenclature and Structure of Carboxyl Groups in chapter Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» Correct OPTION is (d) 3-Phenylpropanoic acid Explanation: The COMPOUND has the group (-CH2CH2COOH) directly attached to a BENZENE ring. The preference is given to the carboxyl group and the compound is named as a carboxylic acid derivative. There are total three carbons making it propanoic acid with the benzene ring as SUBSTITUENT on the last CARBON (C-3) as a phenyl group.

155.	What is the name of the shown compound?(a) Ethane-1,2-dione(b) Butane-1,2-dione(c) Butanone(d) Butane-2,3-dioneI have been asked this question in a national level competition.The doubt is from Nomenclature and Structure of Carbonyl Groups topic in section Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» Right choice is (d) Butane-2,3-dione For explanation I would say: This is a symmetrical dimethyl diketone. There are four carbons in the PARENT CHAIN, including the TWO carbons of ketonic group and numbering can start from either END of the chain.

156.	Identify the correct IUPAC name of CH3-CH=CH-CHO.(a) But-2-enal(b) 2-Butenal(c) Buten-2-al(d) ButenalI had been asked this question during an interview.This key question is from Nomenclature and Structure of Carbonyl Groups in portion Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» CORRECT choice is (a) But-2-enal To explain: The carbon ATOM of the CHO group is assigned the first number. So, in this case, the double bond OCCURS at second carbon and HENCE, the prefix 2- is used for the naming of double bond -en.

157.	The prefix valer- is used for generally used for naming aldehydes with how many carbon atoms in the structure?(a) 3(b) 4(c) 5(d) 6The question was posed to me by my college professor while I was bunking the class.I would like to ask this question from Nomenclature and Structure of Carbonyl Groups topic in chapter Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» RIGHT answer is (c) 5 To explain I would SAY: When aldehydes have exactly 5 carbon atoms in their structure, INCLUDING the carbonyl group and any substituted groups, the aldehyde is given the PREFIX valer- in the common naming system. For example, pentanal is named as n-Valeraldehyde.

158.	Which of the following is the incorrect name for the following compound?(a) 3-Methylbutanal(b) β-Methylbutyraldehyde(c) γ-Methylbutyraldehyde(d) IsovaleraldehydeThe question was asked in homework.My question is taken from Nomenclature and Structure of Carbonyl Groups topic in division Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» RIGHT CHOICE is (c) γ-Methylbutyraldehyde Easiest explanation: The compound is a 4-carbon chain aldehyde with a methyl group substituted at the beta-carbon POSITION, i.e., the carbon next to the carbon DIRECTLY linked to the aldehyde group.

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