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1551.

In which form carbohydrate Is stored in plants and animals?

Answer»
  • plants – starch.
  • In animals – Glycogen.
1552.

Which is not a protein ?A. TrypsinB. CollagenC. RubiscoD. N-acetylglucosamine

Answer» Correct Answer - D
(D) N-acetylglucosamine is not a protein it is sugar
1553.

Describe the secondary structure of protein with examples.

Answer»

1. There are two types of secondary structure of protein: a-helix and pleated sheets. 

2. The polypeptide chain is arranged in a spiral helix. These spiral helices are of two types: a-helix (right handed) and Phelix (left handed). 

3. This spiral configuration is held together by hydrogen bonds. 

4. The sequence of amino acids in the polypeptide chain determines the location of its bend or fold and the position of formation of hydrogen bonds between different portions of the chain or between different chains.

Thus, peptide chains form an a-helix structure. 

5. Example of a-helix structure is keratin. 

6. In some proteins two or more peptide chains are linked together by intermolecular hydrogen bonds. Such structures are called P-pleated sheets. 

7. Example of P-pleated sheet is silk fibres. 

8. Due to formation of hydrogen bonds peptide chains assume a secondary structure.

1554.

Explain the induced fit model for mode of enzyme action.

Answer»

1. The induced fit model shows that enzymes are flexible structures in which the active site continually reshapes by its interactions with the substrate until the time the substrate is completely bound to it. It is also the point at which the final form and shape of the enzyme is determined. 

2. Three-Dimensional conformation: 

a. All enzymes have specific 3-dimensional conformation. 

b. They have one or more active sites to which substrate (reactant) combines. 

c. The points of active site where the substrate joins with the enzyme is called substrate binding site.

1555.

According to induced fit theory of enzyme actionA. Substrate induces conformational change in enzymeB. Substrate changes its shape after bindingC. Conformational change takes place in substrateD. There is no conformational change in enzyme

Answer» Correct Answer - A
(A) According to induced fit theory of enzymes action substrate induces confromational change in enzyme.
1556.

Most of the amino acid have chiral centres but not inA. phenyl alanineB. tryptophaneC. tyrocineD. glycine

Answer» Correct Answer - D
1557.

Write the names of two water soluble vitamins.

Answer» Vitamin `B_(12)` (Cyanocobalamin) , Vitamin C (Ascorbic acid)
1558.

A nucleotide contains (A) sugar + phosphate (B) N-base + phosphate (C) sugar + nitrogenous base (D) sugar + N-base + phosphate

Answer»

The correct answer is (D) sugar + N-base + phosphate

1559.

Which of the following is the correct statement ?A. Starch is a polymer of `alpha`-glucoseB. Amylose is not a component of starchC. Proteins are composed of only one type of amino acid.D. In cyclic structure of fructose, there are five carbon and one oxygen atoms.

Answer» Correct Answer - A
1560.

Keratin is a protein having larger amount ofA. hairB. woolC. silkD. all of these

Answer» Correct Answer - D
1561.

Keratin is a ________ protein.(A) transport (B) protective (C) structural (D) storage

Answer»

The correct answer is (C) structural

1562.

Keratin is a protein having larger amount ofA. SulfurB. CalcuiumC. MagnesiumD. Phosphorous

Answer» Correct Answer - A
1563.

Explain primary structure of protein.

Answer»

The linear sequence of amino acids in polypeptide chain of a protein forms the primary structure of a protein.

1564.

Observe the following figure and name the type of bond shown by arrow in the structure.

Answer»

The type of bond shown in the diagram is hydrogen bond.

1565.

Find out final produt:A. B. C. D.

Answer» Correct Answer - B
1566.

DNA consist ofA. `beta` D-ribose sugarB. `beta`-D 2-deoxyribose sugarC. `alpha`-D ribose sugarD. `alpha`-D-deoxyribose sugar

Answer» Correct Answer - B
1567.

Vitamin-C isA. aliphatic vitaminB. aromatic vitaminC. alicyclic vitaminD. heterocyclic vitamin

Answer» Correct Answer - A
1568.

The vitamins generated in body in sun raysA. vit-CB. vit-`B_2`C. vit-`B_1`D. vit-D

Answer» Correct Answer - D
1569.

Describe competitive inhibition with an example. 

Answer»

When the inhibitor closely resembles the substrate in its molecular structure and inhibits the activity of the enzyme, it is known as a competitive inhibitor and the process is called competitive inhibition. Due to its close structural similarity with the substrate, the inhibitor competes with the substrate for the substrate-binding site of the enzyme. Consequently, the substrate cannot bind and as a result, the enzyme action declines.

Eg:- Inhibition of succinic dehydrogenase by malonate which closely resembles the substrate succinate in structure.

1570.

With reference to enzymes, turnover number means……….A. The number of substrate molecules that a molicule of an enzyme converts into products per hourB. The number of substrate molecules that a molecule of an enzyme converts into products per secondC. The number of substrate molecules that a molecule of an enzyme convert into produsts per minuteD. The number of substrate molicules that a molecule of an enzyme converts into products per day

Answer» Correct Answer - C
1571.

the transiton state structure of the substrate formed during and enzymatic reaction isA. Permanent but unstableB. Transient and unstableC. Permanent and stableD. Transient but stable

Answer» Correct Answer - B
1572.

the most abundant intracellular cation isA. `Ca^(+)`B. `H^(+)`C. `K^(+)`D. `Na^(+)`

Answer» Correct Answer - C
1573.

Explain the following terms : (i) Invert sugar (ii) Polypeptides.

Answer» Correct Answer - The product formed on the hydrolysis of sucrose with dilute acids or enzyme invertase is called invert sugar These are known so because sign of rotation changes from dextro `(+)` to lavevo `(-)`
(ii) Two amino acids combine to form a peptide bond When the number of combining amino acids is more than ten the product obtained is known as polypeptide .
Maltose will give positive test with fehling reagent but benzaldehyde does not give fehling test.
1574.

Which of the following aldoses will give achiral product with `NaBH_(4)`?A. B. C. D.

Answer» Correct Answer - B::C
1575.

Which of the following statements about amino acids is falseA. They are constituents of all proteinsB. Alanine having one amino and one carboxylic group.C. Most naturally occuring amino acids have D-configuration.D. Glycine is the only naturally occuring amino acid which is optically inactive.

Answer» Correct Answer - C
Most naturally occuring amino acids have L-configuration.
1576.

Number of fatty acids in triglyceride is …………… . (a) 1 (b) 2 (c) 3 (d) 4

Answer»

Number of fatty acids in triglyceride is 3.

1577.

Bakelite is obtained form phenol by reacting with.A. `CH_(3)CHO`B. `CH_(3)COCH_(3)`C. `HCHO`D. `(CH_(2)OH)_(2)`

Answer» Correct Answer - C
Bakelite is polymer of phenol and formaldehyde.
1578.

Assertion : Monellim is the sweetest chemical. reason : Monellin is a protein .A. If both assertion and Reason are true and the Reason is the correct explanation of the assertion .B. If both Assertion and Reason ate true , but the reason is not the correct explanation of the assertion .C. If Assertion is true , but Reason is falseD. if both Assertion and Reason are false.

Answer» Correct Answer - B
1579.

Active site of enzyme is formed byA. Primary structure of proteinB. Secondary structure of proteinC. Tertiary structure of proteoinD. Quaternary structure of protein

Answer» Correct Answer - C
1580.

Collagen is a example ofA. carbohydratesB. oilsC. fatsD. proteins

Answer» Correct Answer - D
1581.

Name the principle on which the enzymes work.

Answer» Correct Answer - Lock-and-key.
1582.

Read the following statements and find out the incorrect statement(s)A. In proteins, only left handed helices are observed.B. `3^(@)` structure of protein is hollow woolen ball like.C. Adult human haemoglobin(Hb) consists of 4 subunints. Two subunits of `alpha`-type and two subunits of `beta`-typeD. All of the above

Answer» Correct Answer - A
(A) In proteins, only right handed helices are observed.
`3^(@)` structure of protein is hollow woolen ball like.
Adult human haemoglobin (Hb) consists of 4 subunits. Two subunits of `alpha`-type and two subunits of `beta`-type.
1583.

inhibition of succinate dehydrogenase by malonate is an example ofA. non-competitive inhibitionB. competitive inhibitionC. allosteric inhibitionD. negative feedback.

Answer» Correct Answer - B
The enzyme succinate dehydrogenase is a classical example of competitive inhibition with succinic acid as its substrate. The compounds, namely, malonic acid, glutaric acid and oxalic, have structural similarity with succinic acid and compete with the substrate for binding at the active site of succinate dehydrogenase enzyme .
1584.

The melting points and solubility in water of amino acids are generally higher than those of corresponding Haloacids . Explain.

Answer»

The amino acids exists as Zwitter ions H3N+ -CHRCOO- , due to this dipolar salt like character, they have dipole- dipole interactions. 

Therefore, their melting points are higher than corresponding haloacids which do not have salt like character.

Due to salt like character amino acids interact strongly with water. As a result their solubility in water is higher than corresponding haloacids which do not have salt like character. 

1585.

Find the incorrect matching.A. Essential oils-Lemon grass oilB. Terpenoids- Monoterpenes, diterpenesC. Polymeric substance- Rubber , gums, nucleotidesD. Pigment-Carotenoids, anthocyanins

Answer» Correct Answer - C
(C) Essential oils - Lemon grass oil
Terpenoids- Monoterpenes, diterpenes
Polymeric substances - Rubber, gums, cellulose
Pigments - Carotenoids, anthocyanins
Nucleotides are `1^(@)` metabolites
1586.

Cytidine is aA. nitrogenous baseB. nucleosideC. nucleotideD. nucleic acid.

Answer» Correct Answer - B
Cytosine (C) is a pyrimidine i.e., a nitrogenous base. A combination of a nitrogenous base (purine pr pyrimidine) with a pentose sugar is known as nucleside. Thus, the combination of cytosine with ribose sugar results in the formation of a nucleoside called as cytidine. similarly, the combination of cytosine with dexyribose sugar is called as deoxycytidine.
1587.

Which one of the following is not a constituent of RNA?(a) Ribose (b) Uracil (c) Thymine(d) Phosphate

Answer»

Option : (b) Uracil

1588.

Protein are also called :(a) polysaccharides (b) polypeptides (c) polyglycerides (d) polyster

Answer»

Option : (b) polypeptides

1589.

DNA is a polymer of units of :(a) sugars (b) ribose (c) amino acids (d) nucleotides

Answer»

Option : (c) amino acids

1590.

What are non-reducing sugars?

Answer»

Non-reducing sugars : 

Carbohydrates which do not reduce Fehling solution and Tollen’s reagent are called non-reducing sugars. E.g. sucrose.

1591.

Give an example each of reducing and non-reducing sugars.

Answer»

Reducing sugars : Maltose or lactose 

Non-reducing sugars : Sucrose.

The most common examples of reducing sugar are maltose, lactose, gentiobiose, cellobiose, and melibiose while sucrose and trehalose are placed in the examples of non-reducing sugars.06-Sept-2021

Chemicals of this type: Glucose

Higher classifications: monosaccharides, Carbohydrates


1592.

The simplest amino acid is :(a) glycine (b) oxalic acid (c) adipic acid (d) caprolactam

Answer»

Option : (a) glycine

1593.

Which protein is found in maximum amount ?A. catalaseB. zinc carbonic anhydraseC. transferaseD. rubisco

Answer» Correct Answer - D
1594.

Which of the following does not contin metal ?A. glycoproteinsB. ferritinC. cytochromesD. chromoproteins

Answer» Correct Answer - A
1595.

Name the disease caused by the deficiency of vitamin C.

Answer» It is scurvy which leads to bleeding from the gums.
1596.

Amylopectin isA. liner polymer of `alpha`-D-glucopyranoseB. branched polymer of `alpha`-D-glucopyranoseC. Linear polymer of `beta`-D-glucopyanoseD. Branched polymer of `beta`-D-glucopyranose

Answer» Correct Answer - B
1597.

Amylose and amylopectin chains occur inA. glycogenB. starchC. celluloseD. chitin

Answer» Correct Answer - B
1598.

The difference between amylose and amylopectin isA. Amylopectin have `1 rarr 4 alopha-`linkage and `1 rarr 6 alpha - ` linkageB. Amylose have `1 rarr 4 alpha-` linkage and `1 rarr 6 beta-` linkageC. Amylopectin have `1 rarr 4 alph - ` linkage and `1 rarr 6 beta -` linkageD. Amylose is made up of glucose and galactose

Answer» Correct Answer - A
Amylose is long unbranched chain with `alpha-D-`Glucose with held by `C_(1)-C_(4)` glycosidic linkage whereas amylopectin is branched chain polymer of `alpha-D` glucose unit in which chain is formed by `C_(1)-C_(4)` glycosidic linkage while branching occurs by `C_(1)-C_(6)` glucosidic linkage.
1599.

In amylopectin glycosidic long chain and branching occurs in betweenA. C-1 of one `alpha`-D-glucopyranos`to`C-4 of another `alpha`-D-glucopyranose and branching at C-1 of one glucopyranose C-6 of another glucopyranoseB.C.D.

Answer» Correct Answer - A
1600.

In amylopectin glycosidic branching present in betweenA. 1-4 `alpha`-D-glucopyranoseB. 1-4-`beta`-D-glucopyranoseC. 1-6-`alpha`-D-glucopyranoseD. 1-6 `beta`-D-glucopyranose

Answer» Correct Answer - C