InterviewSolution

Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

201.	When capacitors are connected in parallel, what happens to the effective plate area?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroI got this question by my school principal while I was bunking the class.My query is from Capacitors in Parallel topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The CORRECT answer is (a) Increases To explain I would say: When capacitors are CONNECTED in PARALLEL, the top plates of each of the capacitors are connected together while the bottom plates are connected to each other. This EFFECTIVELY increases the top PLATE area and the bottom plate area.

202.	Capacitance increases with __________(a) Increase in distance between the plates(b) Decrease in plate area(c) Decrease in distance between the plates(d) Increase in density of the materialThis question was posed to me during an interview.The query is from Capacitors topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (c) DECREASE in distance between the plates Best explanation: CAPACITANCE is inversely proportional to the distance between the two parallel plates. Hence, as the distance between the plate DECREASES, the capacitance increases.

203.	Capacitance increases with ________(a) Increase in plate area(b) Decrease in plate area(c) Increase in distance between the plates(d) Increase in density of the materialThe question was posed to me in examination.This interesting question is from Capacitors topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (a) Increase in PLATE area Explanation: Capacitance is directly PROPORTIONAL to the plate area. HENCE as the plate area increases, the capacitance also increases.

204.	Which of the following depends on charging and discharging rate of a capacitor?(a) Time constant(b) Current(c) Power(d) VoltageThe question was posed to me by my college professor while I was bunking the class.I would like to ask this question from Charging and Discharging Currents in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct OPTION is (a) TIME constant The EXPLANATION is: The time constant in a circuit consisting of a capacitor is the product of the resistance and the capacitance. Smaller the time constant, faster is the CHARGING and discharging rate and vice versa.

205.	The electric field strength is 10N/C and the thickness of the dielectric is 3m. Calculate the potential drop in the dielectric.(a) 10V(b) 20V(c) 30V(d) 40VThis question was posed to me during an interview.This intriguing question originated from Composite Dielectric Capacitor in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (c) 30V The explanation is: The potential DROP in a dielectric= ELECTRIC field strengthAREA of cross section = 103 = 30V.

206.	Calculate the actual permittivity of a medium whose relative permittivity is 5.(a) 4.4310^-11F/m(b) 4.4310^-12F/m(c) 4.4310^11F/m(d) 4.4310^12F/mThis question was posed to me in a job interview.This interesting question is from Relative Permittivity in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right OPTION is (a) 4.4310^-11F/m Best EXPLANATION: Actual permittivity = Relative permittivityABSOLUTE permittivity. Actual permittivity = 58.8510^-12 = 4.43*10^-11F/m.

207.	A capacitor does not allow sudden changes in _________(a) Current(b) Voltage(c) Resistance(d) InductanceThis question was posed to me during an online interview.This is a very interesting question from Distribution of Voltage Across Capacitors in Series topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (b) VOLTAGE For explanation I WOULD say: CAPACITOR does not allow sudden changes in voltage because these changes occur in zero TIME which results in the current being infinity, which is not POSSIBLE.

208.	Calculate the voltage across the 1F capacitor.(a) 33.33V(b) 66.67V(c) 56.56V(d) 23.43VI got this question in homework.This question is from Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (B) 66.67V The EXPLANATION is: When capacitors are connected in series, 1/Ctotal=1/C1+1/C2 = 1/2+1=3/2 Q = CV = (2/3)*100 = 66.67C. V ACROSS the 1F CAPACITOR = 66.67/1 = 66.67V.

209.	Air has a dielectric constant of ___________(a) Unity(b) Zero(c) Infinity(d) HundredThis question was addressed to me during an internship interview.This key question is from Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct ANSWER is (a) Unity Best explanation: DIELECTRIC constant of air is the same as that of a VACUUM which is EQUAL to unity. DIELCTRIC constant of air is taken as the reference to measure the dielectric constant of all other materials.

‹ 1 … 3 4 5 ›