209 + Interview Questions in Capacitance And Capacitors in Basic Electrical Engineering Page 4 InterviewSolution

151.	Which, among the following, is the field where electric charge experiences a force?(a) Electric field(b) Magnetic field(c) Gravitational field(d) Electric, magnetic and gravitational fieldThis question was addressed to me in exam.My question is taken from Electric Fields in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct CHOICE is (a) ELECTRIC field Explanation: Charges EXPERIENCE a force in an electric field because charges come under the INFLUENCE of a field which already has charges- electric field.

Discussion

152.	Capacitor blocks__________ after long time.(a) alternating current(b) direct current(c) both alternating and direct current(d) neither alternating nor direct currentThis question was posed to me in an online interview.This interesting question is from Capacitance and the Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct ANSWER is (b) direct CURRENT The explanation is: Capacitor blocks direct current at steady state and PASS ALTERNATING current.

Discussion

153.	Two capacitors having voltage 2F and 4F are connected in series. This combination is connected to a 100V supply, calculate the voltage across the 2F capacitor.(a) 66.67V(b) 33.33V(c) 100V(d) 0VThe question was posed to me in an internship interview.My question is from Distribution of Voltage Across Capacitors in Series topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct CHOICE is (a) 66.67V Explanation: Ctotal = 24/(2+4) = 4/3F Q = CV = (4/3)100 = 400/3 C. V ACROSS 2F capacitor = Q/C = (400/3)/2 = 200/3 = 66.67F.

Discussion

154.	Which among the following equations is incorrect?(a) Q=CV(b) Q=C/V(c) V=Q/C(d) C=Q/VThis question was posed to me by my college director while I was bunking the class.I want to ask this question from Capacitance in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT answer is (b) Q=C/V Best explanation: Q is directly proportional to V. The CONSTANT of proportionality in this case is C, that is, the capacitance. Hence Q=CV. From the given RELATION we can derive all the EQUATIONS except for Q=C/V.

Discussion

155.	What happens to the current flow in a fully charged capacitor?(a) Current flow stops(b) Current flow doubles(c) Current flow becomes half its original value(d) Current flow becomes one-fourth its original valueThe question was asked in semester exam.I would like to ask this question from Charge and Voltage in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct choice is (a) CURRENT FLOW stops The best EXPLANATION: When a capacitor is fully CHARGED, it does not store any more charge. There is no change in charge with time. Current is the rate of change of charge, hence it BECOMES zero, or stops.

Discussion

156.	What is the voltage across the capacitor if the switch is closed and steady state is reached?(a) 8V(b) 0V(c) 10V(d) InfinityI have been asked this question during an interview for a job.This key question is from Charge and Voltage in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (C) 10V To explain I would say: When steady state is reached, the capacitor ACTS as a open CIRCUIT and the 10V is CONNECTED in PARALLEL to it. Hence Vc=10V.

Discussion

157.	Calculate the current in the capacitor having 2V supply voltage and 3F capacitance in 2seconds.(a) 2A(b) 5A(c) 6A(d) 3AI got this question in semester exam.I'm obligated to ask this question of Capacitors topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right ANSWER is (d) 3A Best explanation: Q is directly PROPORTIONAL to V. The CONSTANT of proportionality in this case is C, that is, the capacitance. Hence Q=CV. Q=3*2=6C. I=Q/t = 6/2 = 3A.

Discussion

158.	If the charge in a conductor is 16C and the area of cross section is 4m^2. Calculate the electric flux density.(a) 64C/m^2(b) 16C/m^2(c) 4C/m^2(d) 2C/m^2I have been asked this question in an interview.Question is from Electric Field Strength and Electric Flux Density topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (c) 4C/m^2 For EXPLANATION: Electric Flux density is the charge PER UNIT area. The formula is: D = Q/A = 16/4 = 4C/m^2.

Discussion

159.	What is the relative permittivity when the actual permittivity is 4F/m?(a) 4.5710^-11(b) 4.5710^12(c) 4.5710^11(d) 4.5710^-12This question was posed to me in an international level competition.This intriguing question comes from Relative Permittivity in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right CHOICE is (C) 4.5710^11 The explanation: RELATIVE permittivity= ACTUAL permittivity/ Absolute permittivity. Relative permittivity = 4/(8.8510^-12) = 4.57*10^11.

Discussion

160.	What happens when one material is rubbed against another?(a) The material becomes electrically neutral(b) The material becomes electrically charged(c) The material becomes negatively charged(d) The material becomes positively chargedI have been asked this question in an international level competition.This intriguing question originated from Electric Fields topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (b) The material becomes ELECTRICALLY charged The best I can EXPLAIN: When one material is rubbed against ANOTHER, there is a transfer of charges from one material to another hence the material becomes electrically charged.

Discussion

161.	Capacitor is a device used to__________(a) store electrical energy(b) vary the resistance(c) store magnetic energy(d) dissipate energyI have been asked this question during an interview for a job.My question is based upon Capacitance and the Capacitor in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct OPTION is (a) store electrical energy To explain: Capacitor is USED to store the charge. It STORES electrical energy between the PLATES.

Discussion

162.	What is the total capacitance when two capacitors C1 and C2 are connected in series?(a) (C1+C2)/C1C2(b) 1/C1+1/C2(c) C1C2/(C1+C2)(d) C1+C2This question was addressed to me during an online interview.I would like to ask this question from Capacitors in Series topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT CHOICE is (c) C1C2/(C1+C2) Explanation: When CAPACITORS are connected in series, the EQUIVALENT capacitance is: 1/Ctotal=1/C1+1/C2, therefore Ctotal = C1C2/(C1+C2).

Discussion

163.	What is the value of capacitance of a capacitor which has a voltage of 4V and ha 8C of charge?(a) 2F(b) 4F(c) 6F(d) 8FI have been asked this question during an interview.This intriguing question comes from Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct CHOICE is (a) 2F The BEST EXPLANATION: Q is directly proportional to V. The constant of PROPORTIONALITY in this case is C, that is, the capacitance. HENCE Q=CV. From the relation, C=Q/V= 8/4=2F.

Discussion

164.	The electric fields of dielectrics having the same cross sectional area in series are related to their relative permittivities in which way?(a) Directly proportional(b) Inversely proportional(c) Equal(d) Not relatedThis question was posed to me in a job interview.My question is based upon Composite Dielectric Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT answer is (b) INVERSELY proportional The best I can explain: LET us consider two plates having fields E1 and E2 and RELATIVE permittivities e1 and e2. Then, E1=Q/(e0e1A) and E2=Q/(e0e2A), where e0=absolute permittivity and A=area of cross section. From the GIVEN expression, we see that E1/E2=e2/e1, hence the electric field is inversely proportional to the relative permittivities.

Discussion

165.	Find the number of plates in the multi plate capacitor having C=20F absolute permittivity=5F/m, A=4m^2 and d=2m.(a) 1(b) 2(c) 3(d) 4I had been asked this question by my school principal while I was bunking the class.This intriguing question comes from Capacitance of a Multi Plate Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (c) 3 Best EXPLANATION: The formula for capacitance of a multi plate capacitor: C=Actual PERMITTIVITY(n-1)A/d. Substituting the GIVEN VALUES in the equation, we get n=3.

Discussion

166.	The conventional direction of electric field is ________(a) Positive to negative(b) Negative to positive(c) No specific direction(d) Direction cannot be determinedThe question was asked in final exam.The doubt is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct OPTION is (a) Positive to negative To EXPLAIN: The conventional direction of field lines is from positive to negative. The field lines originate at the positive CHARGE and TERMINATE at the negative charge.

Discussion

167.	What happens to relative permittivity when actual permittivity decreases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroThe question was posed to me in examination.I would like to ask this question from Relative Permittivity in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT choice is (B) Decreases To explain I would SAY: Relative PERMITTIVITY is the ratio of ACTUAL permittivity to the absolute permittivity. Relative permittivity is directly proportional to actual permittivity. Hence, as actual permittivity decreases, relative permittivity also decreases.

Discussion

168.	Two 4F capacitors are connected in series, calculate the voltage across each if the total voltage is 20V.(a) 10V(b) 5V(c) 20V(d) 0VThe question was posed to me in final exam.My query is from Distribution of Voltage Across Capacitors in Series topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT option is (a) 10V Easiest EXPLANATION: The TWO capacitors have the same capacitance, hence the voltage gets divides EQUALLY. V across each=Total voltage/2 = 20/2 = 10V.

Discussion

169.	Calculate the capacitance of a capacitor that stores 40microC of charge and has a voltage of 2V.(a) 20F(b) 20microF(c) 10F(d) 10microFThis question was posed to me at a job interview.My question comes from Charge and Voltage in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (b) 20microF To elaborate: Q is DIRECTLY PROPORTIONAL to V. The constant of PROPORTIONALITY in this case is C, that is, the capacitance. HENCE C=Q/V. C=40microC/2V=20microF.

Discussion

170.	When capacitors are connected in series, the equivalent capacitance is ___________ each individual capacitance.(a) Greater than(b) Less then(c) Equal to(d) Insufficient data providedThe question was asked during a job interview.My question is taken from Capacitors in Series topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» The CORRECT answer is (b) Less then For EXPLANATION I would say: When capacitors are CONNECTED in series, the equivalent capacitance is: 1/Ctotal=1/C1+1/C2. Since we find the reciprocals of the SUM of the reciprocals, the equivalent capacitance is less than the individual capacitance values.

Discussion

171.	If 2V is supplied to a 3F capacitor, calculate the charge stored in the capacitor.(a) 1.5C(b) 6C(c) 2C(d) 3CI got this question in an interview.The origin of the question is Capacitors topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT option is (B) 6C The best explanation: Q is directly proportional to V. The constant of proportionality in this case is C, that is, the CAPACITANCE. Hence Q=CV. Q=3*2=6C.

Discussion

172.	Which, among the following, is the correct expression for electric flux density?(a) D=epsilonE(b) D=epsilon/E(c) D^2=epsilonE(d) D=epsilon*E^2The question was asked during an online exam.My doubt stems from Electric Field Strength and Electric Flux Density in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (a) D=EPSILONE To EXPLAIN: Electric flux DENSITY is directly PROPORTIONAL to the electric field, epsilon(permittivity of free space) being the constant of proportionality. Hence D=epsilonE.

Discussion

173.	What is the value of capacitance of a capacitor which has a voltage of 4V and has 16C of charge?(a) 2F(b) 4F(c) 6F(d) 8FThe question was posed to me by my college director while I was bunking the class.My query is from Capacitance and the Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (b) 4F To elaborate: Q is directly proportional to V. The constant of proportionality in this case is C, that is, the capacitance. HENCE Q=CV. From the relation, C=Q/V= 16/4=4F.

Discussion

174.	Calculate the voltage across AB if the total charge stored in the combination is 13C.(a) 1V(b) 2V(c) 3V(d) 4VThe question was posed to me during a job interview.My doubt stems from Capacitors in Parallel in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (a) 1V The BEST explanation: The equivalent CAPACITANCE when CAPACITORS are CONNECTED in PARALLEL is the sum of all the capacitors = 1+2+10 = 13F. V = Q/C = 13/13 = 1V.

Discussion

175.	Calculate the total capacitance.(a) 10F(b) 15F(c) 13F(d) 20FThe question was asked by my school teacher while I was bunking the class.My question is based upon Capacitors in Parallel topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT option is (c) 13F For EXPLANATION: The EQUIVALENT CAPACITANCE when CAPACITORS are connected in parallel is the sum of all the capacitors = 1+2+10 = 13F.

Discussion

176.	Unit of capacitance is___________(a) Volts(b) Farad(c) Henry(d) NewtonThis question was posed to me in exam.Asked question is from Capacitance topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT answer is (B) FARAD Explanation: Volts is the unit of VOLTAGE, Henry for inductance and Newton for a force. Hence the unit for capacitance is Farad.

Discussion

177.	Capacitor preferred when there is high frequency in the circuits is __________(a) Electrolyte capacitor(b) Mica capacitor(c) Air capacitor(d) Glass capacitorI have been asked this question at a job interview.The doubt is from Capacitors topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (B) Mica capacitor To elaborate: Mica capacitors are preferred for HIGH frequency circuits because they have LOW OHMIC losses and less reactance.

Discussion

178.	A capacitor consists of_________(a) Two conductors(b) Two semiconductors(c) Two dielectrics(d) Two insulatorsI got this question in an online interview.My question is taken from Capacitors topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT choice is (a) Two CONDUCTORS Best explanation: A capacitor CONSISTS of two conductors CONNECTED in PARALLEL to each other so that it can store charge in between the plates.

Discussion

179.	Which, among the following, will be unity in free space?(a) Absolute permittivity(b) Relative permittivity(c) Actual permittivity(d) Both absolute and relative permittivityI got this question in an interview.My question is based upon Relative Permittivity in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct ANSWER is (b) Relative permittivity To explain I WOULD say: Relative permittivity is constant for a particular medium. For air or FREE space, it is UNITY. Absolute permittivity does not depend on the medium, its value is always constant=8.85*10^-12F/m. Actual permittivity is the PRODUCT of relative permittivity and absolute permittivity.

Discussion

180.	Gauss law is applicable for_________(a) Point charge(b) Sheet charge(c) Line charge(d) Point, sheet and line chargeThe question was posed to me in examination.This interesting question is from Electric Field Strength and Electric Flux Density topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (d) POINT, sheet and line CHARGE Best explanation: Gauss law STATES that the total electric FLUX through any closed surface is equal to the charge enclosed by that surface. HENCE it is applicable for all point, surface and volume.

Discussion

181.	As area increases, what happens to electric flux density?(a) Increases(b) Decreases(c) Remains constant(d) Becomes zeroThis question was posed to me in final exam.My question is from Electric Field Strength and Electric Flux Density topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT option is (b) Decreases The best I can explain: Electric flux density is the CHARGE per UNIT area. The EXPRESSION for flux density is: D=Q/A. Electric flux is inversely PROPORTIONAL to area, hence an area increases, electric flux decreases.

Discussion

182.	The insulant between the two plates of a capacitor is called _______(a) Conductor(b) Semi-conductor(c) Dielectric(d) SuperconductorThe question was posed to me in my homework.The question is from Electric Fields in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (c) DIELECTRIC The best I can explain: The material between the TWO plates of a capacitor is an insulator, more SPECIFICALLY KNOWN as a dielectric.

Discussion

183.	A field that spreads outwards in all directions is __________(a) Linear(b) Radial(c) Weak(d) StrongThe question was asked by my college director while I was bunking the class.This intriguing question comes from Electric Fields topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT ANSWER is (B) Radial Easy explanation: A radial field is one which spreads in all directions. This field is known as the radial field because it spreads out radially from a SOURCE.

Discussion

184.	N capacitors having capacitance C are connected in series, calculate the equivalent capacitance.(a) C/N(b) C(c) CN(d) N/CI had been asked this question in an interview for job.This intriguing question originated from Capacitors in Series in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (d) N/C Best EXPLANATION: When CAPACITORS are connected in series, the equivalent CAPACITANCE is: 1/Ctotal = 1/C+1/C+1/C+……..N times. 1/Ctotal=N/C. Ctotal=C/N.

Discussion

185.	Calculate the charge in the 2F capacitor.(a) 200C(b) 100C(c) 300C(d) 400CThis question was addressed to me by my school teacher while I was bunking the class.Enquiry is from Capacitors in Parallel in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct option is (a) 200C To explain I would SAY: Since the capacitors are connected in parallel, the voltage ACROSS each is the same, it does not get divided. Q = CV = 2*100 = 200C.

Discussion

186.	What is the voltage across a capacitor at the time of switching, that is, when t=0?(a) Infinity(b) 0V(c) Cannot be determined(d) 1VThis question was posed to me in examination.This question is from Charge and Voltage topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right OPTION is (b) 0V Explanation: At the time of SWITCHING, when t=0, the capacitor ACTS as a short circuit. The VOLTAGE across a short is always equal to zero HENCE the voltage across the capacitor is equal to zero.

Discussion

187.	Calculate the number of plates in the multi plate capacitor having C=1.77*10^-10F relative permittivity=5, A=4m^2 and d=2m.(a) 1(b) 2(c) 3(d) 4I have been asked this question in homework.Asked question is from Capacitance of a Multi Plate Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (c) 3 Easy EXPLANATION: The FORMULA for CAPACITANCE of a multi plate CAPACITOR: C=Relative permittivityabsolute permittivity(n-1)*A/d. Substituting the GIVEN values in the equation, we get n=3.

Discussion

188.	What happens to the capacitance of a multi plate capacitor when the number of plates increases?(a) Increases(b) Decreases(c) Remains constant(d) Becomes zeroI have been asked this question in an interview for job.My doubt stems from Capacitance of a Multi Plate Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct ANSWER is (a) Increases Easiest explanation: When the NUMBER of CAPACITORS increases, the CAPACITANCE also increases since it is related by the formula C=Actual PERMITTIVITY(n-1)A/d. Here, we can see that the capacitance is directly proportional to the number of capacitors.

Discussion

189.	As charge increases, what happens to flux density?(a) Increases(b) Decreases(c) Remains constant(d) Becomes zeroI have been asked this question during an internship interview.My query is from Electric Field Strength and Electric Flux Density topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct ANSWER is (a) Increases The explanation: ELECTRIC flux density is the charge per UNIT area. The EXPRESSION for flux density is: D=Q/A. Electric flux is directly proportional to charge, hence as charge increases, electric flux also increases.

Discussion

190.	Which, among the following is the correct expression for an electric field?(a) E=F/C(b) E=FC(c) E=F/Q(d) E=FQI got this question by my college director while I was bunking the class.Enquiry is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The CORRECT choice is (c) E=F/Q The best I can explain: Electric field is the force per UNIT charge HENCE, the correct EXPRESSION among the following is: E=F/Q.

Discussion

191.	Which among the following statements is true with regard to electric field lines?(a) Electric field lines always intersect(b) Electric field lines may or may not intersect(c) Electric field lines can be seen(d) Electric field lines never intersectThis question was posed to me during an interview.The doubt is from Electric Fields topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT ANSWER is (d) Electric field LINES never intersect Explanation: Electric field lines can never intersect because tangent at any point on electric field lines represent the DIRECTION of electric field and if they intersect at a point it means that at that point there are two different directions for electric field which is not POSSIBLE.

Discussion

192.	Capacitors C1, C2 and C3 have voltage drops 2V, 3V and 5V respectively. Calculate the total voltage in the circuit.(a) 10V(b) 2V(c) 5V(d) 0VThe question was posed to me in unit test.My doubt stems from Distribution of Voltage Across Capacitors in Series topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (a) 10V The best I can EXPLAIN: When CAPACITORS are connected in series: Vtotal=V12+V2+V3 = 2+3+5 = 10V.

Discussion

193.	Capacitance is directly proportional to__________(a) Area of cross section between the plates(b) Distance of separation between the plates(c) Both area and distance(d) Neither area nor distanceI have been asked this question at a job interview.Question is taken from Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct option is (a) Area of cross SECTION between the plates The EXPLANATION: The relation between capacitance, area and distance between the plates is: C=epsilon*A/D. ACCORDING to this relation, the capacitance is directly proportional to the area.

Discussion

194.	What is the initial current while charging a capacitor?(a) High(b) Low(c) 0(d) Cannot be determinedThis question was posed to me in quiz.This interesting question is from Charging and Discharging Currents in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right option is (a) HIGH Easiest explanation: The initial CURRENT of a capacitor is very high because the voltage source will transport charges from ONE PLATE of the capacitor to the other plate.

Discussion

195.	A dielectric is basically a ________(a) Capacitor(b) Conductor(c) Insulator(d) SemiconductorI have been asked this question in an online interview.The doubt is from Composite Dielectric Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct CHOICE is (c) INSULATOR Explanation: A dielectric is basically an insulator because it has all the PROPERTIES of an insulator.

Discussion

196.	Calculate the capacitance if the dielectric constant=4, area of cross section= 10m^2 and the distance of separation between the plates is 5m.(a) 7.0810^-11F(b) 7.0810^11F(c) 7.0810^-12F(d) 7.0810^-10FI had been asked this question in exam.Origin of the question is Composite Dielectric Capacitor in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (a) 7.0810^-11F To explain: The expression to find capacitance when a DIELECTRIC is introduced between the plates is: C=ke0A/d. SUBSTITUTING the given values in the EQUATION, we get C = 7.0810^-11F.

Discussion

197.	What happens to the capacitance of a multi plate capacitor when the distance of separation between the plate increases?(a) Increases(b) Decreases(c) Remains constant(d) Becomes zeroThis question was posed to me in quiz.My question is from Capacitance of a Multi Plate Capacitor topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct answer is (b) Decreases The explanation is: When the distance of separation between the plates INCREASES, the capacitance decreases SINCE it is related by the formula C=Actual PERMITTIVITY(n-1)A/d. Here, we can see that the capacitance is inversely proportional to the distance of separation.

Discussion

198.	What is the electric flux density in free space if the electric field intensity is 1V/m?(a) 7.7610^-12C/m^2(b) 8.8510^-12C /m^2(c) 1.2310^-12C /m^2(d) 3.4310^-12C /m^2This question was addressed to me by my school principal while I was bunking the class.This intriguing question comes from Electric Field Strength and Electric Flux Density topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT choice is (B) 8.8510^-12C /m^2 Easy explanation: The formula for electric filed DENSITY is: D=epsilonE = 18.8510^-12 = 8.85*10^-12C /m^2.

Discussion

199.	Electric field terminates at ________(a) Positive charge(b) Negative charge(c) Neither positive nor negative(d) Both positive and negativeThe question was posed to me in examination.The doubt is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (B) NEGATIVE charge To explain: ELECTRIC FIELD originates at the POSITIVE charge and terminates at the negative charge. The conventional direction of the field is from positive to negative.

Discussion

200.	Which of the following is a passive device?(a) Transistor(b) Rectifier(c) Capacitor(d) Vaccuum TubesThe question was asked in a job interview.This key question is from Capacitance and the Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right CHOICE is (c) CAPACITOR To EXPLAIN I would say: Capacitor is a passive device as it CONSUMES power rest all generate power so, they are ACTIVE devices.

Discussion

Explore topic-wise InterviewSolutions in .

Which among the following equations is incorrect?(a) Q=CV(b) Q=C/V(c) V=Q/C(d) C=Q/VThis question was posed to me by my college director while I was bunking the class.I want to ask this question from Capacitance in division Capacitance and Capacitors of Basic Electrical Engineering

Calculate the current in the capacitor having 2V supply voltage and 3F capacitance in 2seconds.(a) 2A(b) 5A(c) 6A(d) 3AI got this question in semester exam.I'm obligated to ask this question of Capacitors topic in division Capacitance and Capacitors of Basic Electrical Engineering

What is the value of capacitance of a capacitor which has a voltage of 4V and ha 8C of charge?(a) 2F(b) 4F(c) 6F(d) 8FI have been asked this question during an interview.This intriguing question comes from Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering

Calculate the capacitance of a capacitor that stores 40microC of charge and has a voltage of 2V.(a) 20F(b) 20microF(c) 10F(d) 10microFThis question was posed to me at a job interview.My question comes from Charge and Voltage in portion Capacitance and Capacitors of Basic Electrical Engineering

If 2V is supplied to a 3F capacitor, calculate the charge stored in the capacitor.(a) 1.5C(b) 6C(c) 2C(d) 3CI got this question in an interview.The origin of the question is Capacitors topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Calculate the voltage across AB if the total charge stored in the combination is 13C.(a) 1V(b) 2V(c) 3V(d) 4VThe question was posed to me during a job interview.My doubt stems from Capacitors in Parallel in division Capacitance and Capacitors of Basic Electrical Engineering

Calculate the total capacitance.(a) 10F(b) 15F(c) 13F(d) 20FThe question was asked by my school teacher while I was bunking the class.My question is based upon Capacitors in Parallel topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Unit of capacitance is___________(a) Volts(b) Farad(c) Henry(d) NewtonThis question was posed to me in exam.Asked question is from Capacitance topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

A capacitor consists of_________(a) Two conductors(b) Two semiconductors(c) Two dielectrics(d) Two insulatorsI got this question in an online interview.My question is taken from Capacitors topic in section Capacitance and Capacitors of Basic Electrical Engineering

The insulant between the two plates of a capacitor is called _______(a) Conductor(b) Semi-conductor(c) Dielectric(d) SuperconductorThe question was posed to me in my homework.The question is from Electric Fields in chapter Capacitance and Capacitors of Basic Electrical Engineering

Calculate the charge in the 2F capacitor.(a) 200C(b) 100C(c) 300C(d) 400CThis question was addressed to me by my school teacher while I was bunking the class.Enquiry is from Capacitors in Parallel in portion Capacitance and Capacitors of Basic Electrical Engineering

What is the voltage across a capacitor at the time of switching, that is, when t=0?(a) Infinity(b) 0V(c) Cannot be determined(d) 1VThis question was posed to me in examination.This question is from Charge and Voltage topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Which, among the following is the correct expression for an electric field?(a) E=F/C(b) E=F*C(c) E=F/Q(d) E=F*QI got this question by my college director while I was bunking the class.Enquiry is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering

What is the initial current while charging a capacitor?(a) High(b) Low(c) 0(d) Cannot be determinedThis question was posed to me in quiz.This interesting question is from Charging and Discharging Currents in section Capacitance and Capacitors of Basic Electrical Engineering

A dielectric is basically a ________(a) Capacitor(b) Conductor(c) Insulator(d) SemiconductorI have been asked this question in an online interview.The doubt is from Composite Dielectric Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Electric field terminates at ________(a) Positive charge(b) Negative charge(c) Neither positive nor negative(d) Both positive and negativeThe question was posed to me in examination.The doubt is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering

Which of the following is a passive device?(a) Transistor(b) Rectifier(c) Capacitor(d) Vaccuum TubesThe question was asked in a job interview.This key question is from Capacitance and the Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering

Which, among the following is the correct expression for an electric field?(a) E=F/C(b) E=FC(c) E=F/Q(d) E=FQI got this question by my college director while I was bunking the class.Enquiry is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering