209 + Interview Questions in Capacitance And Capacitors in Basic Electrical Engineering Page 3 InterviewSolution

101.	Capacitor stores which type of energy?(a) kinetic energy(b) vibrational energy(c) potential energy(d) heat energyThis question was addressed to me during an interview for a job.The query is from Capacitance and the Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT OPTION is (c) POTENTIAL energy For explanation I would say: Capacitor store CHARGE in between the PLATES. This charge is stationary so we can say capacitor store potential energy.

Discussion

102.	What happens to the capacitance when the voltage across the capacitor increases?(a) Decreases(b) Increases(c) Becomes 0(d) No effectThe question was posed to me in an online interview.My question is based upon Charge and Voltage in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT option is (d) No effect Explanation: Q is directly proportional to V. The CONSTANT of proportionality in this CASE is C, that is, the CAPACITANCE. Capacitance is a constant so it will not change on changing voltage.

Discussion

103.	When will capacitor fully charged?(a) When the voltage across its plates is half the voltage from ground to one of its plates(b) When the current through the capacitor is a 1/root2 time its value(c) When the supply voltage is equal to the capacitor voltage(d) NeverI got this question during an interview for a job.My question is taken from Charge and Voltage topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct OPTION is (c) When the supply voltage is EQUAL to the capacitor voltage The EXPLANATION: When the capacitor voltage is equal to the supply voltage the current STOPS flowing through the circuit and the CHARGING phase is over.

Discussion

104.	Which, among the following, do not have any unit?(a) Absolute permittivity(b) Relative permittivity(c) Actual permittivity(d) Both absolute and relative permittivityThe question was asked during a job interview.My doubt is from Relative Permittivity topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (b) Relative permittivity Explanation: Relative permittivity is the ratio of ACTUAL permittivity to the relative permittivity of the medium. SINCE it is a ratio, and we know that a ratio does not have any UNIT, relative permittivity does not have any unit.

Discussion

105.	When capacitors are connected in series, which of the following rules are applied?(a) Voltage divider(b) Current divider(c) Both voltage divider and current divider(d) Neither voltage divider nor current dividerThe question was asked at a job interview.My doubt is from Distribution of Voltage Across Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT choice is (a) VOLTAGE divider Easy EXPLANATION: Voltage divider is the RULE applied when capacitors are connected in series because when capacitors are connected in series, the voltage is different ACROSS each capacitor.

Discussion

106.	What is the voltage across the 2F capacitor?(a) 240V(b) 200V(c) 220V(d) 120VThe question was asked by my college director while I was bunking the class.Query is from Distribution of Voltage Across Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct option is (d) 120V Explanation: CAPACITORS are in series. 1/C=1/2+1/4+1/6, therefore, C=(12/11)F. Q = CV = 220(12/11) = 240C. V across 2F capacitor = Q/C = 240/2 = 120V.

Discussion

107.	The total voltage drop across a series of capacitors is __________(a) The voltage drop across any one of the capacitors(b) The sum of the voltage drop across each of the capacitors(c) The product of the voltage drop across each of the capacitors(d) ZeroI got this question during an online exam.This interesting question is from Distribution of Voltage Across Capacitors in Series in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct answer is (B) The SUM of the voltage drop across each of the capacitors Explanation: The TOTAL voltage drop across a SERIES of capacitors is equal to the sum of the voltage drop across each of the capacitors because when capacitors are connected in series, the voltage drops across each CAPACITOR.

Discussion

108.	Calculate the charge in the circuit.(a) 66.67C(b) 20.34C(c) 25.45C(d) 30.45CI had been asked this question during an online interview.This key question is from Capacitors in Series topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right ANSWER is (a) 66.67C The EXPLANATION is: When capacitors are CONNECTED in series, the EQUIVALENT capacitance is: 1/Ctotal=1/C1+1/C2 = 1/2+1=3/2 Ctotal=2/3 F Q=CV=(2/3)*100 = 200/3 C=66.67C.

Discussion

109.	When capacitors are connected in series _______________ Varies(a) Voltage across each capacitor(b) Charge(c) Capacitance(d) ResistanceThis question was posed to me by my school teacher while I was bunking the class.My question is from Capacitors in Series topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT ANSWER is (a) Voltage across each CAPACITOR Explanation: When capacitors are connected in series, the voltage VARIES because the voltage drop across each capacitor is DIFFERENT.

Discussion

110.	Calculate the charge in the 1F capacitor.(a) 200C(b) 100C(c) 300C(d) 400CI have been asked this question during an interview.I'm obligated to ask this question of Capacitors in Parallel in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right choice is (b) 100C The EXPLANATION: Since the CAPACITORS are connected in PARALLEL, the voltage across each is the same, it does not GET DIVIDED. Q = CV = 1*100 = 100C.

Discussion

111.	What is the total capacitance when three capacitors, C1, C2 and C3 are connected in parallel?(a) C1/(C2+C3)(b) C1+C2+C3(c) C2/(C1+C3)(d) 1/C1+1/C2+1/C3This question was posed to me in homework.Origin of the question is Capacitors in Parallel topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (B) C1+C2+C3 Explanation: When capacitors are CONNECTED in PARALLEL, the total capacitance is equal to the sum of the capacitance of each of the capacitors. Hence Ctotal=C1+C2+C3.

Discussion

112.	Calculate the area of cross section of the multi plate capacitor having C=20F, actual permittivity=5F/m n=3 and d=2m.(a) 1m^2(b) 2m^2(c) 3m^2(d) 4m^2The question was posed to me during a job interview.My query is from Capacitance of a Multi Plate Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT answer is (d) 4m^2 Easiest explanation: The formula for capacitance of a multi plate capacitor: C=Actual PERMITTIVITY(n-1)A/d. Substituting the given VALUES in the EQUATION, we GET A=4m^2.

Discussion

113.	Find the capacitance of a multi plate capacitor whose actual permittivity= 5F/m, n=3, A=4m^2and d=2m.(a) 10F(b) 20F(c) 30F(d) 40FThis question was addressed to me in quiz.The above asked question is from Capacitance of a Multi Plate Capacitor in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT CHOICE is (b) 20F To EXPLAIN: The FORMULA for capacitance of a multi plate capacitor: C=Actual permittivity(n-1)A/d. Thus, C=5(3-1)4/2 = 20F.

Discussion

114.	What is relative permittivity?(a) Equal to the absolute permittivity(b) Ratio of actual permittivity to absolute permittivity(c) Ratio of absolute permittivity to actual permittivity(d) Equal to the actual permittivityI have been asked this question in exam.I'm obligated to ask this question of Relative Permittivity topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct ANSWER is (B) Ratio of actual PERMITTIVITY to absolute permittivity The BEST EXPLANATION: Relative permittivity is the ratio of actual permittivity to the absolute permittivity. As the actual permittivity increases, the relative permittivity also increases.

Discussion

115.	When the voltage across a capacitor increases, what happens to the charge stored in it?(a) Increases(b) Decreases(c) Becomes zero(d) Cannot be determinedThe question was posed to me during an interview.My question is based upon Charge and Voltage in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The CORRECT answer is (a) INCREASES For explanation: When the VOLTAGE across a CAPACITOR increases, the CHARGE stored in it also increases because a charge is directly proportional to voltage, capacitance being the constant of proportionality.

Discussion

116.	For very low frequencies, capacitor acts as ________(a) Open circuit(b) Short circuit(c) Amplifier(d) RectifierThis question was addressed to me in a national level competition.This intriguing question comes from Capacitors topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (a) Open CIRCUIT To elaborate: Capacitive IMPEDANCE is INVERSELY proportional to frequency. Hence at very low frequencies the impedance is almost INFINITY and hence acts as an open circuit and no current flows through it.

Discussion

117.	What is the voltage across the 4F capacitor?(a) 120V(b) 60V(c) 100V(d) 220VI have been asked this question during an online exam.I need to ask this question from Distribution of Voltage Across Capacitors in Series in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT OPTION is (b) 60V The best explanation: Capacitors are in series. 1/C=1/2+1/4+1/6, therefore, C=(12/11)F. Q = CV = 220(12/11) = 240C. V across 4F capacitor = Q/C = 240/4 = 60V.

Discussion

118.	What is the relation between current and voltage in a capacitor?(a) I=1/C*integral(Vdt)(b) I=CdV/dt(c) I=1/CdV/dt(d) I=CtThis question was posed to me in my homework.This interesting question is from Capacitors topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct ANSWER is (b) I=CdV/dt For EXPLANATION: Current=rate of CHANGE of charge I=dQ/dt. Q=CV. C(CAPACITANCE) is constant for a given capacitor so I=CdV/dt.

Discussion

119.	What happens to absolute permittivity when relative permittivity increases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroThe question was asked in an internship interview.I would like to ask this question from Relative Permittivity topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (C) Remains the same For explanation I would say: ABSOLUTE PERMITTIVITY does not DEPEND on the value of relative permittivity. Absolute permittivity is the permittivity of free space and it is a constant value = 8.85*10^-12F/m.

Discussion

120.	Four 10F capacitors are connected in series, calculate the equivalent capacitance.(a) 1.5F(b) 2.5F(c) 3.5F(d) 0.5FThe question was posed to me in unit test.This intriguing question originated from Capacitors in Series topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct ANSWER is (B) 2.5F Easiest EXPLANATION: When capacitors are CONNECTED in series, 1/Ctotal=1/C1+1/C2+1/C3+1/C4=1/10+1/10+1/10+1/10=4/10F. Ctotal=10/4=2.5F.

Discussion

121.	When capacitors are connected in series ___________ remains the same.(a) Voltage across each capacitor(b) Charge(c) Capacitance(d) ResistanceThe question was posed to me in an online interview.This intriguing question originated from Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right choice is (B) Charge Best explanation: When CAPACITORS are connected in series, the charge remains the same because the same AMOUNT of current flow exists in each CAPACITOR.

Discussion

122.	Two capacitors having capacitance value 4F, three capacitors having capacitance value 2F and 5 capacitors having capacitance value 1F are connected in parallel, calculate the equivalent capacitance.(a) 20F(b) 19F(c) 18F(d) 17FI had been asked this question by my school principal while I was bunking the class.I need to ask this question from Capacitors in Parallel topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT OPTION is (b) 19F The best EXPLANATION: When capacitors are CONNECTED in parallel, the total capacitance is equal to the sum of the capacitance of each of the capacitors. Hence Ctotal=4+4+2+2+2+1+1+1+1+1=19F.

Discussion

123.	Two capacitors having capacitance value 4F, three capacitors having capacitance value 2F and 5 capacitors having capacitance value 1F are connected in parallel, calculate the equivalent capacitance.(a) 20F(b) 19F(c) 18F(d) 17FThe question was posed to me by my school teacher while I was bunking the class.My doubt stems from Capacitors in Parallel in section Capacitance and Capacitors of Basic Electrical Engineering
Answer»

Discussion

124.	A power factor of a circuit can be improved by placing which, among the following, in a circuit?(a) Inductor(b) Capacitor(c) Resistor(d) SwitchI have been asked this question in an internship interview.My enquiry is from Capacitance topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct CHOICE is (b) CAPACITOR Best explanation: Power factor = Real power/Apparent power = KW/kVA By adding a capacitor in a circuit, an additional kW load can be added to the SYSTEM WITHOUT altering the kVA. Hence, the power factor is improved.

Discussion

125.	A power factor of a circuit can be improved by placing which, among the following, in a circuit?(a) Inductor(b) Capacitor(c) Resistor(d) SwitchThis question was addressed to me in homework.The query is from Capacitance topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer»

Discussion

126.	If a 2F capacitor has 1C charge, calculate the voltage across its terminals.(a) 0.5V(b) 2V(c) 1.5V(d) 1VThe question was asked by my school teacher while I was bunking the class.My question comes from Charge and Voltage topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (a) 0.5V Explanation: Q is directly proportional to V. The CONSTANT of PROPORTIONALITY in this case is C, that is, the CAPACITANCE. HENCE Q=CV. V=Q/C=1/2 V=0.5V.

Discussion

127.	For high frequencies, capacitor acts as _________(a) Open circuit(b) Short circuit(c) Amplifier(d) RectifierI have been asked this question during an interview for a job.The query is from Capacitors in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct choice is (b) Short circuit To ELABORATE: Capacitive impedance is INVERSELY PROPORTIONAL to frequency. Hence at very HIGH frequencies, the impedance is almost equal to zero, hence it acts as a short circuit and there is no voltage across it.

Discussion

128.	In order to obtain a high value for capacitance, the permittivity of the dielectric medium should be?(a) Low(b) High(c) Zero(d) UnityThe question was asked in examination.Question is taken from Relative Permittivity in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT CHOICE is (b) High To elaborate: FORM the expression: C=epsilon*A/d. From this expression, it is seen that capacitance is DIRECTLY proportional to the PERMITTIVITY, hence for capacitance value to be high, permittivity value should be high.

Discussion

129.	What is the final current while charging a capacitor?(a) High(b) Zero(c) Infinity(d) LowThis question was addressed to me in homework.The above asked question is from Charging and Discharging Currents in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (b) Zero The best explanation: The final CURRENT is ALMOST equal to zero while CHARGING a capacitor because the capacitor is charged up to the source voltage.

Discussion

130.	What is the unit for relative permittivity?(a) F/m(b) Fm(c) F/m^2(d) No unitThe question was posed to me in a national level competition.I would like to ask this question from Relative Permittivity topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT choice is (d) No unit The EXPLANATION: Relative PERMITTIVITY is the ratio of actual permittivity to the relative permittivity of the medium. SINCE it is a ratio, and we know that a ratio does not have any unit, relative permittivity does not have any unit.

Discussion

131.	The force applied to a conductor is 10N if the charge in the conductor is 5C, what is the electric field intensity?(a) 10V/m(b) 2V/m(c) 3V/m(d) 15V/mI have been asked this question by my college director while I was bunking the class.My question is taken from Electric Field Strength and Electric Flux Density topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right CHOICE is (b) 2V/m For explanation I would say: Electric FIELD intensity is the FORCE per unit charge. The formula is: E = F/Q = 10/5 = 2V/m.

Discussion

132.	Why does capacitor block dc signal at steady state?(a) due to high frequency of dc signal(b) due to zero frequency of dc signal(c) capacitor doesnot pass any current at steady state(d) due to zero frequency of dc signalThe question was asked during an interview for a job.Question is taken from Capacitance and the Capacitor topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» The CORRECT answer is (d) due to ZERO frequency of dc SIGNAL The explanation is: Frequency of dc signal is zero. So, Capacitive reactance XC=1/2πfc becomes infinite and capacitor BEHAVES as open circuit for dc signal. HENCE, capacitor block dc signal.

Discussion

133.	Which of the following expressions is correct with respect to the voltage across capacitors in series?(a) V1/V2=C2/C1(b) V2/V1=C2/C1(c) V1V2=C1C2(d) V1/C1=V2/C2The question was posed to me in exam.I'd like to ask this question from Distribution of Voltage Across Capacitors in Series in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct option is (a) V1/V2=C2/C1 The explanation is: When CAPACITORS are CONNECTED in series, the CHARGE across each capacitor remains the same whereas the voltage across each VARIES. When TWO capacitors are connected in series: Q=V1C1; Q=V2C2. Thus: V1/V2=C2/C1.

Discussion

134.	What will happen to the capacitor just after the source is removed?(a) It will not remain in its charged state(b) It will remain in its charged state(c) It will start discharging(d) It will become zeroThis question was posed to me in a job interview.This intriguing question originated from Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT choice is (B) It will REMAIN in its CHARGED state Easy explanation: As soon as the source is removed, the capacitor does not start discharging it remains in the same charged state.

Discussion

135.	Three capacitors having a capacitance equal to 2F, 4F and 6F are connected in parallel. Calculate the effective parallel.(a) 10F(b) 11F(c) 12F(d) 13FThis question was posed to me in an interview for internship.The query is from Capacitors in Parallel topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (c) 12F Easiest EXPLANATION: When capacitors are connected in PARALLEL, the TOTAL CAPACITANCE is EQUAL to the sum of the capacitance of each of the capacitors. Hence Ctotal = C1+C2+C3 = 2+4+6 = 12F.

Discussion

136.	A 4microF capacitor is charged to 120V, the charge in the capacitor would be?(a) 480C(b) 480microC(c) 30C(d) 30microCThis question was addressed to me in semester exam.My question comes from Capacitors in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT answer is (b) 480microC Best explanation: Q is DIRECTLY proportional to V. The constant of proportionality in this CASE is C, that is, the CAPACITANCE. Hence Q=CV. Q=4*120=480microC.

Discussion

137.	Electric flux density is a function of_______(a) Volume(b) Charge(c) Current(d) VoltageThis question was addressed to me by my school teacher while I was bunking the class.This is a very interesting question from Electric Field Strength and Electric Flux Density topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (b) Charge To EXPLAIN I would SAY: Electric FLUX density is the charge per UNIT area. Hence it is a FUNCTION of charge and not any of the other values.

Discussion

138.	“Total electric flux through any closed surface is equal to the charge enclosed by that surface divided by permittivity”. This is the statement for?(a) Gauss law(b) Lenz law(c) Coloumb’s law(d) Faraday’s lawI got this question in quiz.Asked question is from Electric Field Strength and Electric Flux Density topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct choice is (a) Gauss LAW To EXPLAIN: Total ELECTRIC flux through any closed surface is equal to the charge enclosed by that surface divided by permittivity is the statement for Gauss law because among the four laws, Gauss law DEALS with electric flux.

Discussion

139.	If a parallel plate capacitor of plate area 2m^2 and plate separation 1m store the charge of 1.77*10^-11 C. What is the voltage across the capacitor?(a) 1V(b) 2V(c) 3V(d) 4VThe question was posed to me in class test.The question is from Capacitance and the Capacitor topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct answer is (a) 1V Explanation: C=€0A/d On SUBSTITUTING VALUES of d, A, we GET C=2€0. Q=CV V=1 V.

Discussion

140.	Calculate the voltage across the 2F capacitor.(a) 33.33V(b) 66.67V(c) 56.56V(d) 23.43VI got this question in class test.The origin of the question is Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct option is (a) 33.33V Explanation: When capacitors are CONNECTED in series, 1/Ctotal=1/C1+1/C2 = 1/2+1 = 3/2 Q = CV = (2/3)*100 = 66.67C. V across the 2F capacitor = 66.67/2 = 33.33V.

Discussion

141.	What is the equivalent capacitance?(a) 1.5F(b) 0.667F(c) 2.45F(d) 2.75FThe question was asked by my school teacher while I was bunking the class.The question is from Capacitors in Series in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» CORRECT CHOICE is (b) 0.667F The best explanation: When CAPACITORS are CONNECTED in series, 1/Ctotal = 1/C1+1/C2 = 1/2+1 = 3/2 Ctotal = 2/3 = 0.667F.

Discussion

142.	Capacitors charge and discharge in __________ manner.(a) Linear(b) Constant(c) Square(d) ExponentialI have been asked this question in unit test.Asked question is from Capacitance in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct OPTION is (d) Exponential The EXPLANATION is: Capacitors charge and discharge in an exponential manner because of the RELATION: XC=1/(2πfC) and Q=CV ∴ Q=V/(2πf XC) XC is complex which can be written in the form of exponent through euler FORMULA.

Discussion

143.	When the supply frequency increases, what happens to the capacitive reactance in the circuit?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroThe question was posed to me in an interview for job.My question is based upon Capacitance in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right answer is (b) Decreases The explanation: The expression for capacitive reactance is: Xc=1/(2PIf*C). This RELATION shows that frequency is INVERSELY RELATED to capacitive reactance. Hence, as supply frequency increases, the capacitive reactance decreases.

Discussion

144.	Which among the following expressions relate charge, voltage and capacitance of a capacitor?(a) Q=C/V(b) Q=V/C(c) Q=CV(d) C=Q^2VI got this question at a job interview.I want to ask this question from Charge and Voltage topic in portion Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT option is (c) Q=CV To explain: Q is directly proportional to V. The constant of PROPORTIONALITY in this case is C, that is, the CAPACITANCE. Hence Q=CV.

Discussion

145.	Calculate the distance between the plates of the capacitor having C=20F, actual permittivity = 5F/m n=3 and A=4m^2.(a) 1m(b) 2m(c) 3m(d) 4mI got this question in an interview.The query is from Capacitance of a Multi Plate Capacitor in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (b) 2m To EXPLAIN: The formula for capacitance of a MULTI plate capacitor: C=Actual permittivity(n-1)A/d. Substituting the GIVEN VALUES in the equation, we GET d=2m.

Discussion

146.	Electric field originates at __________(a) Positive charge(b) Negative charge(c) Neither positive nor negative(d) Both positive and negativeI have been asked this question in exam.My doubt is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering
Answer» Right choice is (a) Positive charge The BEST I can EXPLAIN: Electric field originates at the positive charge and terminates at the NEGATIVE charge. The conventional DIRECTION of the field is from positive to negative.

Discussion

147.	When capacitors are connected in parallel, the total capacitance is always __________ the individual capacitance values.(a) Greater than(b) Less than(c) Equal to(d) Cannot be determinedThe question was posed to me during an interview for a job.I want to ask this question from Capacitors in Parallel topic in chapter Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (a) GREATER than The best explanation: When capacitors are connected in parallel, the TOTAL CAPACITANCE is equal to the sum of the capacitance of each of the capacitors. HENCE Ctotal=C1+C2+C3. SINCE it is the sum of all the capacitance values, the total capacitance is greater the individual capacitance values.

Discussion

148.	Calculate the time constant of a series RC circuit consisting of a 100microF capacitor in series with a 100ohm resistor.(a) 0.1 sec(b) 0.1 msec(c) 0.01 sec(d) 0.01 msecI had been asked this question during an interview.My query is from Capacitance topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» Correct choice is (c) 0.01 sec To elaborate: The TIME constant of a RC CIRCUIT= RC= 10010^-6*100=0.01 sec.

Discussion

149.	If one plate of a parallel plate capacitor is charged to positive charge the other plate is charged to?(a) Positive(b) Negative(c) Positive or negative(d) Not chargedI had been asked this question in examination.Enquiry is from Charge and Voltage topic in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» RIGHT CHOICE is (b) Negative Best explanation: If one PLATE is charged to positive, the other plate is automatically charged to negative so that it can STORE electrical charge.

Discussion

150.	What happens to the potential difference between the plates of a capacitor as the thickness of the dielectric slab increases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroThis question was addressed to me in a job interview.Enquiry is from Composite Dielectric Capacitor in division Capacitance and Capacitors of Basic Electrical Engineering
Answer» The correct answer is (B) Decreases Explanation: When a dielectric is introduced between the plates of a CAPACITOR, its POTENTIAL difference decreases. New potential difference= potential difference without dielectric-potential difference of dielectric. Hence as the thickness of the dielectric slab INCREASES, a larger value is subtracted from the original potential difference.

Discussion

Explore topic-wise InterviewSolutions in .

What happens to the capacitance when the voltage across the capacitor increases?(a) Decreases(b) Increases(c) Becomes 0(d) No effectThe question was posed to me in an online interview.My question is based upon Charge and Voltage in chapter Capacitance and Capacitors of Basic Electrical Engineering

What is the voltage across the 2F capacitor?(a) 240V(b) 200V(c) 220V(d) 120VThe question was asked by my college director while I was bunking the class.Query is from Distribution of Voltage Across Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering

Calculate the charge in the circuit.(a) 66.67C(b) 20.34C(c) 25.45C(d) 30.45CI had been asked this question during an online interview.This key question is from Capacitors in Series topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Calculate the charge in the 1F capacitor.(a) 200C(b) 100C(c) 300C(d) 400CI have been asked this question during an interview.I'm obligated to ask this question of Capacitors in Parallel in chapter Capacitance and Capacitors of Basic Electrical Engineering

For very low frequencies, capacitor acts as ________(a) Open circuit(b) Short circuit(c) Amplifier(d) RectifierThis question was addressed to me in a national level competition.This intriguing question comes from Capacitors topic in portion Capacitance and Capacitors of Basic Electrical Engineering

What is the voltage across the 4F capacitor?(a) 120V(b) 60V(c) 100V(d) 220VI have been asked this question during an online exam.I need to ask this question from Distribution of Voltage Across Capacitors in Series in chapter Capacitance and Capacitors of Basic Electrical Engineering

What is the relation between current and voltage in a capacitor?(a) I=1/C*integral(Vdt)(b) I=CdV/dt(c) I=1/CdV/dt(d) I=CtThis question was posed to me in my homework.This interesting question is from Capacitors topic in division Capacitance and Capacitors of Basic Electrical Engineering

Four 10F capacitors are connected in series, calculate the equivalent capacitance.(a) 1.5F(b) 2.5F(c) 3.5F(d) 0.5FThe question was posed to me in unit test.This intriguing question originated from Capacitors in Series topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

A power factor of a circuit can be improved by placing which, among the following, in a circuit?(a) Inductor(b) Capacitor(c) Resistor(d) SwitchThis question was addressed to me in homework.The query is from Capacitance topic in portion Capacitance and Capacitors of Basic Electrical Engineering

If a 2F capacitor has 1C charge, calculate the voltage across its terminals.(a) 0.5V(b) 2V(c) 1.5V(d) 1VThe question was asked by my school teacher while I was bunking the class.My question comes from Charge and Voltage topic in section Capacitance and Capacitors of Basic Electrical Engineering

For high frequencies, capacitor acts as _________(a) Open circuit(b) Short circuit(c) Amplifier(d) RectifierI have been asked this question during an interview for a job.The query is from Capacitors in portion Capacitance and Capacitors of Basic Electrical Engineering

In order to obtain a high value for capacitance, the permittivity of the dielectric medium should be?(a) Low(b) High(c) Zero(d) UnityThe question was asked in examination.Question is taken from Relative Permittivity in portion Capacitance and Capacitors of Basic Electrical Engineering

What is the final current while charging a capacitor?(a) High(b) Zero(c) Infinity(d) LowThis question was addressed to me in homework.The above asked question is from Charging and Discharging Currents in portion Capacitance and Capacitors of Basic Electrical Engineering

What is the unit for relative permittivity?(a) F/m(b) Fm(c) F/m^2(d) No unitThe question was posed to me in a national level competition.I would like to ask this question from Relative Permittivity topic in division Capacitance and Capacitors of Basic Electrical Engineering

A 4microF capacitor is charged to 120V, the charge in the capacitor would be?(a) 480C(b) 480microC(c) 30C(d) 30microCThis question was addressed to me in semester exam.My question comes from Capacitors in division Capacitance and Capacitors of Basic Electrical Engineering

Calculate the voltage across the 2F capacitor.(a) 33.33V(b) 66.67V(c) 56.56V(d) 23.43VI got this question in class test.The origin of the question is Capacitors in Series in division Capacitance and Capacitors of Basic Electrical Engineering

What is the equivalent capacitance?(a) 1.5F(b) 0.667F(c) 2.45F(d) 2.75FThe question was asked by my school teacher while I was bunking the class.The question is from Capacitors in Series in section Capacitance and Capacitors of Basic Electrical Engineering

Capacitors charge and discharge in __________ manner.(a) Linear(b) Constant(c) Square(d) ExponentialI have been asked this question in unit test.Asked question is from Capacitance in chapter Capacitance and Capacitors of Basic Electrical Engineering

Which among the following expressions relate charge, voltage and capacitance of a capacitor?(a) Q=C/V(b) Q=V/C(c) Q=CV(d) C=Q^2VI got this question at a job interview.I want to ask this question from Charge and Voltage topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Electric field originates at __________(a) Positive charge(b) Negative charge(c) Neither positive nor negative(d) Both positive and negativeI have been asked this question in exam.My doubt is from Electric Fields topic in section Capacitance and Capacitors of Basic Electrical Engineering