Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

If a large amount of voltage is applied to a capacitor, what is the current that flows through it?(a) Displacement current(b) Conduction current(c) Both conduction and displacement current(d) Neither conduction nor displacement currentThe question was posed to me by my college professor while I was bunking the class.This key question is from Leakage and Conduction Currents in Capacitors topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right choice is (b) Conduction current

For explanation I WOULD say: When a large amount of voltage is applied between the PLATES of a capacitor, the DIELECTRIC between the plates does not BEHAVE as an insulator anymore and starts conducting and conduction currents flow through it.

2.

A capacitor using chemical reactions to store charge is _______(a) Paper capacitor(b) Ceramic capacitor(c) Polyester capacitor(d) Electrolyte capacitorI have been asked this question in a national level competition.The doubt is from Types of Capacitor and Capacitance topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct CHOICE is (d) Electrolyte capacitor

To EXPLAIN: Electrolyte capacitors use chemical processes like pyrolysis to STORE CHARGE between its plates.

3.

When the potential gradient increases, what happens to the force between the plates?(a) Increases(b) Decreases(c) Remains the same(d) becomes zeroThis question was posed to me during an interview.The query is from Force of Attraction Between Oppositely Charged Plates topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right CHOICE is (a) INCREASES

The explanation is: The FORCE of attraction between the two plates of the capacitor is directly proportional to the SQUARE of potential gradient, HENCE as a potential gradient increases, the force of attraction also increases.

4.

Calculate the energy in the 2F capacitor.(a) 8.6kJ(b) 64kJ(c) 64J(d) 6.4kJThe question was asked at a job interview.Query is from Energy Stored in a Charged Capacitor topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT answer is (d) 6.4kJ

To elaborate: From the EXPRESSION:

WD= CV^2/2 = 2*80^2/2=6400J=6.4kJ.
5.

What is the voltage in the resistor as soon as the switch is closed at t=0.(a) 0V(b) Infinity(c) 220V(d) Insufficient information providedI got this question by my school principal while I was bunking the class.My question is taken from Transients in CR Networks topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right OPTION is (c) 220V

For explanation: As soon as the switch is CLOSED at t=0, there is no charge in the capacitor, HENCE the voltage across the capacitor is zero and all the 220V voltage is the voltage across the RESISTOR.

6.

The flow of electrons which does not pass through the battery is known as ________(a) Displacement current(b) Leakage current(c) Either displacement or leakage current(d) Neither displacement nor leakage currentThe question was asked by my school principal while I was bunking the class.Origin of the question is Leakage and Conduction Currents in Capacitors in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT CHOICE is (a) DISPLACEMENT current

Explanation: Displacement current is the flow of electrons from the positive plate of the capacitor to the negative plate of the capacitor, not through the battery. HENCE the type of current which flows without passing through the battery is displacement current.
7.

The thickness of a material having dielectric strength 10MV/m is 5m, calculate the potential difference.(a) 2MV(b) 10MV(c) 50MV(d) 100MVThe question was posed to me in final exam.This question is from Dielectric Strength topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The CORRECT option is (c) 50MV

For EXPLANATION: Dielectric strength is the potential gradient required to cause a breakdown in the MATERIAL. Potential gradient is the ratio of VOLTAGE and thickness.

V=t*dielectric strength= 5*10=50MV.

8.

What is the value of current in a discharging capacitive circuit if the initial current is 2A at time t=RC.(a) 0.74A(b) 1.26A(c) 3.67A(d) 2.89AThis question was posed to me in semester exam.The origin of the question is Growth and Decay topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct choice is (b) 1.26A

For EXPLANATION: At TIME t=RC, that is the time CONSTANT, we know that the value of current at that time interval is equal to 63% of the initial charge in the discharging CIRCUIT. Hence, I = 2*0.63 = 1.26A.

9.

A CR network is one which consists of _________(a) A capacitor and resistor connected in parallel(b) A capacitor and resistor connected in series(c) A network consisting of a capacitor only(d) A network consisting of a resistor onlyI had been asked this question by my school teacher while I was bunking the class.Question is taken from Transients in CR Networks in section Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT option is (B) A capacitor and RESISTOR CONNECTED in series

Easiest EXPLANATION: A CR network is one which consists of a capacitor connected in series with a resistor. The capacitor discharges or charges through the resistor.
10.

What is the value of current in a charging capacitive circuit if the initial current is 2A at time t=RC.(a) 0.74A(b) 1.26A(c) 3.67A(d) 2.89AI got this question in an interview for internship.This is a very interesting question from Growth and Decay topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT option is (a) 0.74A

The explanation is: At time t=RC, that is the time constant, we know that the value of CURRENT at that time interval is EQUAL to 37% of the INITIAL charge in the discharging circuit. Hence, I = 2*0.37 = 0.74A.
11.

Capacitor preferred when there is high frequency in the circuits is _______(a) Electrolyte capacitor(b) Mica capacitor(c) Air capacitor(d) Glass capacitorThe question was posed to me during an interview for a job.The query is from Types of Capacitor and Capacitance topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct choice is (b) MICA capacitor

Explanation: Mica CAPACITORS are preferred for high frequency circuits because they have low OHMIC LOSSES and less reactance.

12.

Paper capacitor is a type of _________(a) Fixed capacitor(b) Variable capacitor(c) Either fixed or variable depending on its usage(d) Neither fixed nor variableI had been asked this question during an internship interview.The doubt is from Types of Capacitor and Capacitance in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct choice is (a) Fixed capacitor

The BEST I can EXPLAIN: PAPER capacitors are fixed capacitors because, like fixed capacitors, its capacitance value remains CONSTANT. In paper capacitors, paper is used as the DIELECTRIC.

13.

The free electrons in practical dielectrics are due to ________(a) There are no free electrons(b) Conductors(c) Impurities(d) Displacement currentsI had been asked this question in semester exam.Enquiry is from Displacement Current in a Dielectric in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct option is (c) IMPURITIES

Easy explanation: Ideally, dielectrics are insulators and do not CONTAIN any free electrons. But no dielectric is a perfect dielectric, hence the free electrons are due to impurities PRESENT in each dielectric.

14.

Calculate d^2i(0)/dt^2 from the given circuit.(a) 10^-6A/s^2(b) 10^-3A/s^2(c) 10^6A/s^2(d) 10^3A/s^2I have been asked this question in an interview for job.Origin of the question is Transients in CR Networks in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct answer is (b) 10^-3A/s^2

The BEST EXPLANATION: APPLYING KVL to the given circuit, we get:

100+10i(0)+1/10*integral(i(0)dt)=0

Differentiating once, we get:

10di(0)/dt+1/10*i.

Differentiating once again, we get:

10d^2i(0)/dt^2+10di(0)/dt=0.

Substituting the values of di/dt from the previous explanation, we get d^2i(0)/dt^2=10^-3A/s^2.

15.

If the switch is closed at t=0, what is the current in the circuit?(a) 0A(b) 10A(c) 20A(d) InfinityThis question was posed to me in a job interview.My query is from Transients in CR Networks topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right answer is (b) 10A

The EXPLANATION: As SOON as the SWITCH is closed at t=0, the capacitor ACTS as a SHORT circuit. The current in the circuit is:

I=V/R = 100/10 = 10A.

16.

At DC, capacitor acts as _________(a) Open circuit(b) Short circuit(c) Resistor(d) InductorI got this question during an interview.My enquiry is from Transients in CR Networks in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT answer is (a) OPEN circuit

Easy explanation: Capacitive Reactance XC = 1/(2πfC)

For DC, f=0 so, XC becomes infinite. Hence for dc, the capacitor ACTS as an open circuit.
17.

While discharging, what happens to the current in the capacitive circuit?(a) Decreases linearly(b) Increases linearly(c) Decreases exponentially(d) Increases exponentiallyThis question was addressed to me in an interview.Question is from Growth and Decay in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct answer is (d) Increases exponentially

Best explanation: The equation for the VALUE of current in a DISCHARGING CAPACITIVE circuit is:

I=I0(1-e^-t/RC). From this equation, we can see that the current is exponentially INCREASING.

18.

______________ capacitors have a high leakage voltage.(a) Electrolyte capacitor(b) Variable capacitor(c) Air capacitor(d) Polyester capacitorThe question was posed to me in an interview for internship.Question is from Types of Capacitor and Capacitance topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct choice is (d) Polyester capacitor

For EXPLANATION I would SAY: Polyester capacitors can operate at HIGH voltages, that is, a few thousand volts and the leakage resistance is high, that is, USUALLY 100 M.

19.

In a variable capacitor, capacitance can be varied by ______(a) Turning the rotatable plates in or out(b) Sliding the rotatable plates(c) Changing the plates(d) Changing the material of platesThe question was asked during an online exam.I'm obligated to ask this question of Types of Capacitor and Capacitance in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct OPTION is (a) Turning the rotatable plates in or out

Best explanation: As the plates are rotated, the AREA of the plates between which the field exists, will vary. CAPACITANCE DEPENDS on area, hence as area varies, capacitance also varies.

20.

What is the energy in a capacitor if the voltage is 5V and the charge is10C?(a) 25J(b) 35J(c) 54J(d) 55JThis question was addressed to me in examination.Question is taken from Discharge of a Capacitor Through a Resistor in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT option is (a) 25J

Explanation: We KNOW that Q/V=C. Hence the value of capacitance is 2F.

U=(Q*V)/2 = (10*5)/2 = 25 J.
21.

While charging, what happens to the voltage in the capacitive circuit?(a) Decreases linearly(b) Increases linearly(c) Decreases exponentially(d) Increases exponentiallyI have been asked this question in final exam.I need to ask this question from Growth and Decay topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT option is (d) Increases EXPONENTIALLY

For explanation: The equation for the VALUE of VOLTAGE in a CHARGING capacitive circuit is:

V=V0(1-e^-t/RC). From this equation, we can see that the voltage is exponentially increasing.
22.

A circuit has a resistance of 5 ohm connected in series with a capacitance of 10F. Calculate the discharging time constant.(a) 15(b) 50(c) 5(d) 10I have been asked this question in final exam.The doubt is from Growth and Decay topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct ANSWER is (b) 50

Best explanation: The discharging TIME constant in a circuit consisting of a CAPACITOR and resistor in series is the product of the resistance and capacitance = 5*10 = 50.

23.

A capacitor is charged to a voltage of 400V and has a resistance of 20ohm. Calculate the final value of charging current.(a) 10A(b) 0A(c) Infinity(d) 20AI have been asked this question during an online interview.My doubt stems from Charging and Discharging Currents in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The CORRECT ANSWER is (b) 0A

To explain: When the capacitor is charging, the final voltage of the capacitor becomes EQUAL to the voltage of source. HENCE, the current becomes equal to zero.

24.

If the dielectric strength of a material is 4MV/m and its potential difference is 28MV, calculate the thickness of the material.(a) 4m(b) 7m(c) 5m(d) 11mThe question was posed to me in an interview for job.Query is from Dielectric Strength in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct option is (B) 7m

Explanation: Dielectric strength is the POTENTIAL gradient REQUIRED to CAUSE a breakdown in the material. Potential gradient is the ratio of voltage and thickness.

V/dielectric strength= t= 28/4=7m.

25.

A metal parallel plate capacitor has ‘a’mm diameter and the distance between the plates is 1mm. The capacitor is placed in air. Force on each plate is 0.035N and the potential difference between the plates is 1kV. Find ‘a’.(a) 10mm(b) 100mm(c) 1000m(d) 1000cmThis question was posed to me during an online exam.The query is from Force of Attraction Between Oppositely Charged Plates topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right ANSWER is (b) 100mm

To EXPLAIN: From the given data:

A=pi*d^2/4=pi*a^2/4

Potential GRADIENT = V/x = 10^6V/m

F=epsilon*A*(V/x)^2/2

Substituting the given values, we GET d=100mm.

26.

Calculate the energy in the 4F capacitor.(a) 128kJ(b) 1.28kJ(c) 12.8kJ(d) 1280JThe question was posed to me by my school principal while I was bunking the class.Question is from Energy Stored in a Charged Capacitor topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer» RIGHT OPTION is (C) 12.8kJ

The BEST explanation: From the expression:

WD = CV^2/2 = 4*80^2/2 = 12800J = 12.8kJ.
27.

A metal parallel plate capacitor has 100mm diameter and the distance between the plates is 1mm. The capacitor is placed in air. Calculate the potential difference between the plates if the force on each plate is 0.035N.(a) 1kV(b) 1V(c) 2kV(d) 2VI got this question during an online interview.My question is based upon Force of Attraction Between Oppositely Charged Plates topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The CORRECT answer is (a) 1kV

Explanation: From the given DATA:

A=pi*d^2/4=0.007854m^2

Potential gradient = V/x = 1000*V

F=epsilon*A*(V/x)^2/2

Substituting the given VALUES in the above EXPRESSION, we get V=1kV.

28.

If the charge in a capacitor is 4C and the energy stored in it is 4J, find the value of capacitance.(a) 2F(b) 4F(c) 8F(d) 16FThe question was asked in an internship interview.The above asked question is from Energy Stored in a Charged Capacitor topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT CHOICE is (a) 2F

To EXPLAIN: The expression for finding the value of energy is:

U=Q^2/2C.

Substituting the VALUES of U and Q, we get C=2F.
29.

If the charge stored in a capacitor is 4C and the value of capacitance is 2F, calculate the energy stored in it.(a) 2J(b) 4J(c) 8J(d) 16JI have been asked this question in examination.This interesting question is from Energy Stored in a Charged Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct answer is (b) 4J

Easy explanation: The expression for finding the VALUE of ENERGY is:

U=Q^2/2C = 4*4/(2*2) = 4J.

30.

Calculate the voltage across the capacitor at t=0.(a) 0V(b) 10V(c) 20V(d) InfinityThis question was addressed to me by my school principal while I was bunking the class.This interesting question is from Transients in CR Networks topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right choice is (a) 0V

To elaborate: When the switch is closed at t=0, the capacitor has no VOLTAGE across it since it has not been charged. The capacitor acts as a SHORT CIRCUIT and the voltage across it is ZERO.

31.

The discharging time constant of a circuit consisting of a capacitor is the time taken for the charge in the capacitor to become __________ % of the initial charge.(a) 33(b) 63(c) 37(d) 36I got this question in class test.The above asked question is from Growth and Decay in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct option is (C) 37

To explain: We know that: Q=Q0(1-e^-t/RC).

When RC=t, we have: Q=Q0(1-e^-1) = 0.37*Q0.

Hence the TIME CONSTANT is the time taken for the charge in a capacitive circuit to BECOME 0.37 times its initial charge.

32.

A capacitor is charged to a voltage of 400V and has a resistance of 20ohm. Calculate the final value of the discharge current.(a) 10A(b) 0A(c) Infinity(d) 20AThe question was posed to me in an interview.This intriguing question comes from Charging and Discharging Currents topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct option is (d) 20A

The EXPLANATION: In a discharging circuit, the final voltage is equal to ZERO for capacitor. For a RESISTOR, final voltage is 400V.So,final CURRENT = V/R = 400/20 = 20A.

33.

A capacitor is charged to a voltage of 400V and has a resistance of 20ohm. Calculate the initial value of the discharge current.(a) 10A(b) 0A(c) Infinity(d) 20AI got this question in class test.I'd like to ask this question from Charging and Discharging Currents topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right ANSWER is (b) 0A

For explanation I WOULD SAY: When the capacitor is discharging the value of the INITIAL CURRENT is zero.

34.

An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the initial charging current.(a) 100 microA(b) 500 microA(c) 400 microA(d) 1000microAThe question was asked during an interview.My query is from Discharge of a Capacitor Through a Resistor in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct CHOICE is (C) 400 microA

For explanation: In a series RC circuit, the initial charging CURRENT is:

I=V/R = 200/(0.5*10^6s) = 400*10^-6A = 400 microA.

35.

The flow of electrons which does not pass through the battery is known as ____________(a) Conduction current(b) Leakage current(c) Charging current(d) Displacement currentThis question was posed to me in a national level competition.This key question is from Displacement Current in a Dielectric topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer» RIGHT answer is (a) Conduction CURRENT

To explain I would say: Conduction current is the flow of electrons from the POSITIVE plate of the capacitor to the negative plate of the capacitor, not through the BATTERY. HENCE the type of current which flows without passing through the battery is conduction current.
36.

The current in conductors connecting the voltage source to the plates of a capacitor is _______(a) Conduction current(b) Leakage current(c) Charging current(d) Displacement currentI have been asked this question during an online exam.Origin of the question is Displacement Current in a Dielectric in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right choice is (c) Charging CURRENT

For explanation I would say: The current in conductors connecting the voltage source to the plates of a capacitor is the charging current and not the CONDUCTION or LEAKAGE current.

37.

What is the type of current where the electrons actually move?(a) Displacement current(b) Conduction current(c) Both conduction and displacement current(d) Neither conduction nor displacement currentThe question was asked in a job interview.This question is from Leakage and Conduction Currents in Capacitors in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct option is (b) CONDUCTION current

Easiest explanation: Conduction current is the current caused by the actual flow of electrons and DISPLACEMENT current is the current where no CHARGE CARRIERS are involved.

38.

In which of the following mediums, will the force of attraction between the plates of a capacitor be greater?(a) Air(b) Water(c) Does not depend on the medium(d) Cannot be determinedThis question was addressed to me during an online interview.My doubt is from Force of Attraction Between Oppositely Charged Plates in division Capacitance and Capacitors of Basic Electrical Engineering

Answer» RIGHT answer is (b) Water

The best I can explain: The absolute permittivity(epsilon) of water is greater than that of air. The EXPRESSION relating F and epsilon is F=epsilon*A*(V/x)^2/2. From this expression, we can see that as epsilon increases, the force of ATTRACTION also increases.
39.

If the charge in a capacitor is 4C and the energy stored in it is 4J, calculate the voltage across its plates.(a) 2V(b) 4V(c) 8V(d) 16VThis question was posed to me during an online exam.My doubt is from Energy Stored in a Charged Capacitor topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct option is (a) 2V

The best I can EXPLAIN: The expression for FINDING the VALUE of ENERGY is:

U=Q^2/2C.

Substituting the values of U and Q, we get C=2F.

V=Q/C, hence V=4/2=2V.

40.

An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the voltage in the capacitor 4s after the power is supplied.(a) 123.4V(b) 126.4V(c) 124.5V(d) 132.5VI got this question in a national level competition.I'm obligated to ask this question of Discharge of a Capacitor Through a Resistor in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right choice is (b) 126.4V

Explanation: We can get the VALUE of the potential difference across the capacitor in 4s, from the following equation:

VC=V(1-e^-t /RC). SUBSTITUTING the VALUES in the given equation, we get Vc = 126.4V.

41.

What is the type of current caused due to variations in the field?(a) Displacement current(b) Conduction current(c) Both conduction and displacement current(d) Neither conduction nor displacement currentThe question was posed to me in homework.I would like to ask this question from Leakage and Conduction Currents in Capacitors in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct OPTION is (a) Displacement current

For EXPLANATION I WOULD say: Displacement current is the current where no charge CARRIERS are involved. It is caused due to variations in the electric field.

42.

The expression for the current in an RC circuit is?(a) i=(V/R)e^t/RC(b) i=(V/R)e^-t/RC(c) i=(V/R)(1-e^-t/RC)(d) i=(V/R) (1-e^t/RC)This question was addressed to me in unit test.I want to ask this question from Transients in CR Networks topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right CHOICE is (B) i=(V/R)e^-t/RC

Easy explanation: APPLYING KVL to the GIVEN circuit, we get:

i=i0e^-t/RC = (100/10)e^-t/100

i=10 e^-t/100.

43.

The charging time constant of a circuit consisting of a capacitor is the time taken for the charge in the capacitor to become __________ % of the initial charge.(a) 33(b) 63(c) 37(d) 36This question was addressed to me in an online quiz.My query is from Growth and Decay in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right option is (B) 63

The best I can EXPLAIN: We know that: Q=Q0(1-e^-t/RC).

When RC=t, we have: Q=Q0(1-e^-1) = 0.63*Q0.

Hence the time CONSTANT is the time taken for the charge in a CAPACITIVE circuit to become 0.63 times its initial charge.

44.

Which, among the following, is the odd one out?(a) Ceramic capacitor(b) Electrolyte capacitor(c) Tuning capacitor(d) Paper capacitorI have been asked this question during an interview.My doubt stems from Types of Capacitor and Capacitance topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right OPTION is (C) Tuning CAPACITOR

Easy explanation: Ceramic capacitor, electrolyte capacitor and paper capacitor are FIXED capacitors WHEREAS tuning capacitors is a variable capacitor, hence it is the odd one out.

45.

Under normal conditions capacitors have _______(a) Displacement current(b) Conduction current(c) Both conduction and displacement current(d) Neither conduction nor displacement currentThe question was posed to me in final exam.I want to ask this question from Displacement Current in a Dielectric topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct choice is (a) Displacement current

The explanation: Under NORMAL conditions capacitors contain an insulating material called DIELECTRIC sandwiched between the plates of the capacitor. SINCE insulators can CARRY only an electric field but not moving carriers, therefore NORMALLY a capacitor has displacement current and not conduction current.

46.

What is the conduction current when a capacitor is fully charged?(a) Infinity(b) Zero(c) 100A(d) 1000AThe question was asked in an interview for job.Query is from Leakage and Conduction Currents in Capacitors in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct CHOICE is (B) Zero

To elaborate: When a capacitor is fully charged, there is no CONDUCTION of electrons from ONE plate of the capacitor to ANOTHER, hence there is no conduction current and conduction current is equal to zero.

47.

Leakage in capacitors is primarily caused by _________(a) Transistors(b) Resistors(c) Inductors(d) DC motorsThis question was posed to me by my college professor while I was bunking the class.I'd like to ask this question from Leakage and Conduction Currents in Capacitors in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct OPTION is (a) TRANSISTORS

The explanation: Leakage is primarily caused DUE to electronic devices, such as transistors, connected to the CAPACITORS. Transistors conduct a small amount of current even when they are turned off, hence they are RESPONSIBLE for leakage current.

48.

What happens to the force of attraction between the capacitors when the distance of separation between the plates increases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroI had been asked this question during an online exam.This key question is from Force of Attraction Between Oppositely Charged Plates topic in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct OPTION is (b) Decreases

The explanation: The FORCE of attraction between the TWO PLATES of the capacitor is inversely proportional to the square of the distance between the plates, hence as distance increases, the force of attraction decreases.

49.

A metal parallel plate capacitor has 100mm diameter and the distance between the plates is 1mm. The capacitor is placed in air. Calculate the force on each plate if the potential difference between the plates is 1kV.(a) 350N(b) 0.035kN(c) 0.035N(d) 3.35kNThis question was addressed to me during an interview.My doubt stems from Force of Attraction Between Oppositely Charged Plates in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The correct OPTION is (C) 0.035N

To explain: From the given data:

A=pi*d^2/4=0.007854m^2

Potential GRADIENT = V/x = 10^6V/m

F=epsilon*A*(V/x)^2/2

Therefore, F=0.035N.

50.

Calculate the energy stored in the combination of the capacitors.(a) 192kJ(b) 1.92kJ(c) 19.2kJ(d) 1920JI had been asked this question in homework.This interesting question is from Energy Stored in a Charged Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer» RIGHT OPTION is (c) 19.2kJ

The best EXPLANATION: The equivalent capacitance is: Ceq=4+2=6F.

From the expression:

WD = CV^2/2 = 6*80^2/2 = 19200J = 19.2kJ.