InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 451. |
Which of the following is the electron-deficient molecule?A. `C_(2)H_(6)`B. `B_(2)H_(6)`C. `SiH_(6)`D. `PH_(3)` |
|
Answer» Correct Answer - b The compound of which central atom is octeless is known as electron -deficient compound .Hence `B_(2)H_(6)` is electron-deficient compound. |
|
| 452. |
Which of the following is electron deficient ?A. `(SiH_(3))_(2)`B. `(BH_(3))_(2)`C. `PH_(3)`D. `(CH_(3))_(2)` |
|
Answer» Correct Answer - b In `B_(2)H_(6)` two three -centre two -electron bond exist due to electron deficiency on boron atom .Also it is more electropositive than other |
|
| 453. |
Which one is the electron deficient compound ?A. ICIB. `NH_(3)`C. `BCl_(3)`D. `PCl_(3)` |
|
Answer» Correct Answer - c `BCI_(2)` is electron deficient compound because it has only `6` electron after forming bond |
|
| 454. |
Which of the following is polar ?A. `BF_3`B. `C_2H_5-F`C. `CO_2`D. `CH_4` |
| Answer» Correct Answer - B | |
| 455. |
Which of the following is electron deficient?A. `BCl_3`B. `PCl_3`C. `PCl_5`D. `NH_3` |
| Answer» Correct Answer - A | |
| 456. |
Assertion . When two hydrogen atoms approach each other to form a cavalent bond , nearly ` 435.8 KJ mol^(-1)` of energy is released . Reason . When two atoms approach eachother to form a covalent bond between them, potential energy of the system is released .A. If both assertion and reason are correct, and reason is the correct explanation of the assertion.B. If both assertion and reason are correct , but reason is not the correct explanation of the assertion.C. If assertion is correct, but reason is incorrect .D. If both assertion and reason are incorrect. |
|
Answer» Correct Answer - c Correct R . When two atoms approach each other to form a covalent bond between them , potential energy of the system first decreases and then increases . |
|
| 457. |
Assertion : `NO_(2)` is readily dimerised to `N_(2)O_(4)` Reason :`NO_(2)` has one unpaired electron and two such electron with opposite spin in two `NO_(2)` molecules form bond between two N-atoms readily.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
|
Answer» Correct Answer - a Since the process does not require any rearrangement and thus energy of activation for dimension of `NO_(2)` is low. |
|
| 458. |
Which is not true according to `VBT`?A. A covalent bond is formed by the overlapping of orbitals with umpaired electron of opposite spinsB. A covalent bond is formed by the overlapping of orbitals with umpaired electron of same spinsC. The greater the extent of overlapping the strong is the bondD. Overlapping takes place only in the direction of maximum electron density of the orbital |
|
Answer» Correct Answer - b Element of same spin never combine to from a bond. Other facts are true for `VBT`. |
|
| 459. |
`CO_(2)` is isostructural withA. `HgCI_(2)`B. `C_(2)H_(2)`C. `SnCI_(2)`D. `NO_(2)` |
|
Answer» Correct Answer - A::B Carbon dioxide is a liear molecule `HgCI_(2)` and `C_(2)H_(2)` are linear molecules . |
|
| 460. |
Ot of `CH_(3)OH` and `(CH_(3))_(3)N` both exhibit H-bonding . |
|
Answer» Correct Answer - F Only `CH_(3)OH` exhibits H-bonding there is no H-atom in `(CH_(3))_(3)N` . |
|
| 461. |
Which of the following hydrides has the least boilling point ?A. `H_(2)S`B. `H_(2)O`C. `H_(2)Se`D. `H_(2)Te` |
|
Answer» Correct Answer - A Concrptual question. |
|
| 462. |
Which overlap is involved in HCl molecule ?A. s-s overlapB. p-p overlapC. s-d overlapD. s-p overlap. |
| Answer» Correct Answer - D | |
| 463. |
The bond angle in `PH_3` is close toA. `90^@`B. `105^@`C. `109^@`D. `120^(@)` |
| Answer» Correct Answer - A | |
| 464. |
Why `PCl_(5)` exists but `NCl_(5)` does not ? |
|
Answer» Electron configuration of `""_(15)P` is `1s^(2) 2sp^(2) 2sp^(2) 2p^(6) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)` . Thus, the 3d orbitals of the valence shell are empty . Hence , an electron from 3s can jump to 3d , giving the configuration `1s^(2) 2sp^(2) 2p^(6) 3s^(1) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)3d^(1)` . Thus , it can extend its covalency to 5. in case of `""_(7)N` , elec- tronic configuration `1s^(2) 2s^(2) 2p_(x)^(1) 2p_(y)^(1)2p_(z)^(1)` . As there is no 2d orbital , it connot extend its covalency to 5. |
|
| 465. |
Shape of `O_(2)F_(2)` is similar to that ofA. `C_(2) F_(2)`B. `H_(2) O_(2)`C. `H_(2_) F_(2)`D. `C_(2) H_(2)` |
|
Answer» Correct Answer - B `O_(2)F_(2) and H_(2) O_(2)` both have open book type structure They , however, differ in bond angles and bond lengths . |
|
| 466. |
Lattice energy of an ionic compound depedns upon :A. Charge on the ion onlyB. Size of the ion onlyC. Packing of the ion onlyD. Charge and size of the ion |
| Answer» Correct Answer - D | |
| 467. |
Lattice energy of an ionic compound depedns upon :A. Charge on the ion and size of the ionB. Packing of ions onlyC. Size of the ion onlyD. Charge on the ion only |
|
Answer» Correct Answer - A The packing of a crystal and lattice energy depends on charge and size of the ion . |
|
| 468. |
Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`, Structure of `XeF_(4)` isA. linearB. pyramidalC. tetrahedralD. squre planner |
|
Answer» Correct Answer - d `XeF_(4)` molecule has `Xe` `sp^(2) d^(2)` hydridized and its shape is square planar due to the presence of two lone pair of electrons |
|
| 469. |
Which of the least bond angle ?A. `NH_(3)`B. `BeF_(2)`C. `H_(2)O`D. `CH_(4)` |
|
Answer» Correct Answer - c Due to lp- lp repulsions bond angle is `H_(2)O` is lower `(104^(@) - 5)` than in` NH_(3)`and ` CH_(4)(109^(@) 28^(@) ) BeF_(1)`On the other band ,has sp-hybridration and hence has a bond angle of `180^(@)` |
|
| 470. |
Bond order of `O_(2), O_(2)^(-) and O_(2)^(2-)` is in orderA. `O_(2)`B. `O_(2)^(-1)`C. `O_(2)^(+1)`D. `O_(2)^(-2)` |
|
Answer» Correct Answer - c `B O of O_(2) is 2 B O of O_(2)^(-1) is 1.5 , B O of O_(2)^(+1) is 2.5 and of O_(2)^(2+) is 1` |
|
| 471. |
Which of the following sequence represents the correct increasing order of bond angle in the given molecular ?A. `CIO_(2) lt OF_(2) lt OCI_(2) lt H_(2)O`B. `OF_(2) lt H_(2)O lt OCI_(2) lt CIO_(2)`C. `OCI_(2) lt CIO_(2) lt H_(2)O lt OP_(2)`D. `H_(2)O lt OF_(2) lt OCI_(2) lt CIO_(2)` |
|
Answer» Correct Answer - b Bond angle in `CIO_(2) = 118^(@)` Bond angle in `CI_(2)O = 111^(@)` Bond angle in `F_(2)O = 103^(@)` Bond angle in `H_(2)O = 105^(@)` |
|
| 472. |
In which of the following compound all the bond angles are sameA. `CCI_(4)`B. `CHCI_(3)`C. `CH_(3)CI`D. `CH_(3)CI_(2)` |
|
Answer» Correct Answer - a Since all `4C - CI` bonds are at the equivvalent position |
|
| 473. |
Which of the following compounds the one having linear structure isA. `NH_(2)`B. `CH_(4)`C. `C_(2)H_(2)`D. `H_(2)O` |
|
Answer» Correct Answer - c `C_(2)H_(2)` has linear structure because carbons are sp- hybridased and lies at `180^(@)` |
|
| 474. |
The isoelectronic pair isA. `Cl_(2)O,ICl_(2)`B. `ICl_(2)ClO_(2)`C. `IF_(2)^(+)I_(3)^(-)`D. `ClO_(2)^(-)O_(2),CIF_(2)^(+)` |
|
Answer» Correct Answer - d Number of electron in `CO_(2)^(-)` `= 7 + 6 + 6 + 1 = 20 ` Number of electron is `OF_(2)^(+) = 7 + 7 - 1 = 20 ` |
|
| 475. |
The correect order of decreasing bond angle isA. `NH_(1) gt NH_(2) gt NH_(4)`B. `NH_(4) gt NH_(2) gt NH_(2)`C. `NH_(2) gt NH_(3) gt NH_(4)`D. `NH_(4) gt NH_(2) gt NH_(3)` |
|
Answer» Correct Answer - b As the number of lone pair of electrons of N increases bond angle decreases `NH_(4)^(+),NH_(3) and NH_(2)` cotain `0,1, and 2` lone pairs respectively |
|
| 476. |
The correct order of bond strength is :A. `O_(2)^(2-)`B. `O_(2)`C. `O_(2)^(+)`D. `O_(2)^(-)` |
|
Answer» Correct Answer - d `KK sigma_(2s)^(2) sigma**_(2s)^(4 2)sigma_(2p_(x)^(2) pi_(2p)^(2) pi_(2p)^(2), pi**_(2px)^(4 2) pi**_(2p_(y)^(1)` `rArr B O = (8 - 5)/(2) = 1.5` |
|
| 477. |
The electronic configuration of the outer most shell of the most electronegative element is :A. `2s^(2)2p^(5)`B. `3s^(2)3p^(5)`C. `4s^(2)4p^(5)`D. `5s^(2)5p^(5)` |
|
Answer» Correct Answer - A a) The electronic configuration represents `2s^(2)2p^(5)`= fluorine= most electronegative element. `3s^(2)3p^(5)` = chlorine. `4s^(2)4p^(5)`=bromine `5s^(2)5p^(5)`= iodine. |
|
| 478. |
The molecule which has the largest dipole moment amongst the following isA. `CH_(4)`B. `CHCl_(3)`C. `C Cl_(4)`D. `CHl_(3)` |
| Answer» Correct Answer - B | |
| 479. |
Iso-structural species among the folwong are `(l) CH_(3)^(+)(ll)H_(3)O^(+)(lll)NH_(3)(IV)CH_(3)^(-)`A. l and llB. lll and IVC. l and lllD. ll,lll and lV |
|
Answer» Correct Answer - B::D (b,d) are the correct answer. |
|
| 480. |
Explain the formation of a chemical bond. |
| Answer» A chemical bond is defined as an attractive force that holds the constituents (atoms, ions etc.) together in a chemical species.Various theories have been suggested for the formation of chemical bonds such as the electronic theory, valence shell electron pair repulsion theory, valence bond theory, and molecular orbital theory.A chemical bond formation is attributed to the tendency of a system to attain stability. It was observed that the inertness of noble gases was because of their fully filled outermost orbitals. Hence, it was postulated that the elements having incomplete outermost shells are unstable (reactive). Atoms, therefore, combine with each other and complete their respective octets or duplets to attain the stable configuration of the nearest noble gases. This combination can occur either by sharing of electrons or by transferring one or more electrons from one atom to another. The chemical bond formed as a result of sharing of electrons between atoms is called a covalent bond. An ionic bond is formed as a result of the transference of electrons from one atom to another. | |
| 481. |
In which of the following bond angle is maximumA. `NH_(3)`B. `NH_(4)^(+)`C. `PCI_(3)`D. `SCL_(2)` |
|
Answer» Correct Answer - b `NH_(4)^(+)` has abgle of `109^(@)28^(@)` |
|
| 482. |
In which of the following substances will hydrogen bond be strongest ?A. `XeF_(4)`B. `BF_(4)^(-)`C. `C_(2)H_(4)`D. `SiF_(4)` |
|
Answer» Correct Answer - C In `C_(2)H_(4)(H_(2)C=CH_(2))` all the bonds are not equal. |
|
| 483. |
Explain the structure of `CO_(3)^(2-)` ion in terms of resonance (b) Explain the resonance structures of `CO_(2)` molecule . |
|
Answer» The experimentally determined carbon to oxygen bond length in `CO_(2)` is 115 pm. The lengths of a normal carbon to oxygen double bond `(C=O)` and carbon to oxygen triple bond `(C-=O)` are 121 pm and 110 pm respectively. The carbon-oxygen bond lengths in` CO_(2)` (115 pm) lie between the values for `C=O` and `C-=O`. Obviously, a single Lewis structure cannot depict this position and it becomes necessary to write more than one Lewis structures and to consider that the structure of `CO_(2)` is best described as a hybrid of the canonical or resonance forms I, II and III `{:( :overset(..)O::C::" "overset(..)O:, harr,:underset(..)overset(..^(-))O:Cvdotsvdotsoverset(+)O:, harr,:overset(+)OvdotsvdotsC:underset(..)overset(..^(-))O: ),(" "I,," "II,," "III):}` Resonance in `CO_(2) molecule. I,II and III represent the three canonical forms. |
|
| 484. |
Which of the following is not different for two atoms in N-Cl bondA. ElectronegativityB. ValencyC. Atomic sizeD. Ionisation potential |
| Answer» Correct Answer - A | |
| 485. |
A molecule is square planar with no lone pair. What type of hybridisation is associated with it?A. `sp^(3)d`B. `sp^(3)d^(2)`C. `dsp^(3)`D. `dsp^(2)` |
|
Answer» Correct Answer - D `dsp^(2)` hybridissation is associated with square planar molecule. |
|
| 486. |
Octrahedral shape is associated withA. `PF_(5)`B. `SF_(4)`C. `TeF_(6)`D. `ClF_(3).` |
|
Answer» Correct Answer - C `TeF_(6)` has octahedral shape. |
|
| 487. |
What is the number of molecular orbitals obtained by mixing of two atomic orbitals ? (b) Out of `F_(2)` and `OF` which of these molecules is (are) paramagnetic (ii) Which should be more stable towards dissociation into atoms `OF` or `F_(2)` (c ) Explain why `NO^(o+)` is more stable towards dissociation into atoms than `NO` whereas `CO^(o+)` is less stable than `CO` (d) Predict whether `He_(2)^(o+)` ion in its electronic ground state is stable towards dissociation into he and `He^(o+)` . |
|
Answer» Two (b) `OF` is paramagnetic since it has one unpaired antibonding electron (c ) `NO^(o+)` has lost an antibonding electron Whereas `CO^(o+)` has lost a bonding electron (d) It should be stabel because it has one more bonding electron the antibonding . |
|
| 488. |
The molecule having smaller bond angle isA. `NC_(3)`B. `AsCI_(3)`C. `SbCI_(3)`D. `PCI_(3)` |
|
Answer» Correct Answer - c `{:(N),(P),(As),(Sb):}]{:("Group =15"),({:[("Valence"),("electros"):}]=5):}` `MCI_(3)` has `sp^(2)` hybridized M- electron with one lone pair .Lone pair and bond repulsion decreases bond angle .However, the bond -pair of electron are much father away from the central atom than they are in `NCI_(1)` .Thus lone- pair cause ever greater distrotion in `PCI_(3)AsCI_(3) and SbCI_(2)` ,Tjus bond angle decreases from `NCI_(23)` (maximum ) to `SbCI+_(3)` (minimum) |
|
| 489. |
Which is incorrect regarding S and P mixing (along Z axis.) ?A. Nodal plane(s) present in ABMOB. Nodel plane is absent in BMOC. MO formed may have highest energy than parent AOD. `MO` formed are aysmmetric |
|
Answer» Correct Answer - b Nodal palne is absent in BMO. |
|
| 490. |
Assertion : Bond order can assume any value number including zero. Reason :Higher the bond order ,shorter is bond length and greater is bond energy.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
|
Answer» Correct Answer - b Bond order `= (1)/(2) [({:("no of" e^(-) "in" ),("bonding" M.O.):})] -[({:("no of" e^(-) "in" ),("bonding" M O):})]` Bond order zero indicates that the bond does not exist |
|
| 491. |
Assertion . Bond order can assume any value including zero. Reason. Higher the bond order, shorter is the bond length and greater is the bond energy.A. If both assertion and reason are correct, and reason is the correct explanation of the assertion.B. If both assertion and reason are correct , but reason is not the correct explanation of the assertion.C. If assertion is correct, but reason is incorrect .D. If both assertion and reason are incorrect. |
|
Answer» Correct Answer - b Correct explanation . Bond order ` = (1)/(2) (N_(b) - N_(a))` |
|
| 492. |
The total number of electrons that take part in forming the bond in `N_(2)` is .A. `2`B. `4`C. `6`D. `10` |
|
Answer» Correct Answer - C `N-= N :N::N:`. |
|
| 493. |
Choose the paramagnetic oxide in the followingA. `Na_(2) O `B. `MgO `C. `BeO `D. `KO_(2)` |
|
Answer» Correct Answer - D ` KO_(2)` contains ` O_(2)^(-)` , others contain ` O^(2 - )`. |
|
| 494. |
What is the magnetic character of the anion of `KO_(2)` ? |
| Answer» Anion of `KO_(2) = O_(2)^(-)` (superoxide ion) which has one unpaired electron and hence in paramagnetic. | |
| 495. |
In ` BrF_(3) ` molecule, the lone pairs occupy requatorial position to minizeA. lone pair - bond pair repulsion onlyB. bond pari - bond pair repulsion onlyC. lone pair - lone pair repulsion and lone pair-bond pair repulsionD. lone pair - lone pair repulsion only |
|
Answer» Correct Answer - D `BrF_(3) ` is similar to ` CIF_(3)`, |
|
| 496. |
Which one of the following species does not exist under normal conditions ?A. `Li_(2)`B. `Be_(2)^(+)`C. `Be_(2)`D. `B_(2)` |
|
Answer» Correct Answer - C `Be_(2) = sigma _(1s)^(2) sigma _(1s)^(**2) sigma_(2s)sigma _(2s)^(**2)B.O. = 0 ` , |
|
| 497. |
How will bond order in `N_(2) and O_(2)` be influenced in the following ionization process ? (a) ` N_(2) to N_(2)^(+) + ^(-) (b) O_(2) to O_(2)^(+) P e^(-)` |
| Answer» (a) Bond order decreases from 3.0 to 2.5 . (b) Bond order increases from 2.0 to 2.5 | |
| 498. |
According to is M.O. theory, which is the correct increasing sequence of B.O. in `N_(2),N_(2)^(-)and N_(2)^(2-)` ?A. `N_(2)^(2-) lt N_(2)^(-) lt N_(2)`B. `N_(2) lt N_(2)^(2-) lt N_(2)^(-)`C. `N_(2)^(-) lt N_(2)^(2-) lt N_(2)`D. `N_(2)^(-) lt N_(2) lt N_(2)^(2-)` |
| Answer» Correct Answer - C | |
| 499. |
Which of the following has pyramidal structure ?A. `NH_(3)`B. `BF_(3)`C. `C Cl_(4)`D. `H_(2)O.` |
| Answer» Correct Answer - A | |
| 500. |
`H_(2)O` moleule is linear |
|
Answer» Correct Answer - F False `H_(2)O` molecuels is V-shaped . |
|