

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
651. |
The dipole moment of CO2 is …………… |
Answer» 0 μ = μ1 + μ2 = μ1 + (-μ1) = 0 (for CO2) |
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652. |
The shape of sulphur hexafluoride is ………… |
Answer» Octahedral The shape of sulphur hexafluoride is Octahedral. |
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653. |
Give reason behind the lustrous nature, high melting point and boiling point of metals? |
Answer» 1. The metallic lustre is due to the reflection of light by the electron cloud. 2. As the metallic bond is strong enough. the metal atoms are reluctant to break apart into a liquid or gas, so the metals have high melting and boiling points. |
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654. |
Statement I: In sulphur hexafluoride, the central atom has more than eight valence electrons. Statement II: The central atom can accommodate additional electron pairs by using outer vacant d orbitals.(a) Statements I and II are correct and statement II is the correct explanation of statement I.(b) Statements I and II are correct but statement II is not the correct explanation of statement I.(c) Statement I is correct but statement II is wrong.(d) Statement I is wrong but statement II is correct. |
Answer» (a) Statements I and II are correct and statement II is the correct explanation of statement I. |
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655. |
Metals have high thermal conductivity. Give reason. |
Answer» High thermal conductivity of metals is due to thermal excitation of many electrons from the valence band to the conduction band. |
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656. |
Assertion (A): Metals have high thermal conductivity. Reason (R): Due to thermal excitation of many electrons from the valence band to the conductance band, metals have high thermal conductivity. (a) Both (A) and (R) are correct and (R) is the correct explanation of(A).(b) Both (A) and (R) are correct but (R) is not the correct explanation of(A). (c) (A) is wrong but (R) is correct. (d) (A) is correct but (R) is wrong. |
Answer» (a) Both (A) and (R) are correct and (R) is the correct explanation of(A). |
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657. |
Choose the correct statement.(a) The metallic luster is due to reflection of light by the electron cloud. (b) Metals have low inciting point and low boiling point. (c) Metals have low thermal conductivity. (d) Electrical conductivity of metals is low. |
Answer» (a) The metallic luster is due to reflection of light by the electron cloud. |
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658. |
The bond order in N2 molecule is …………(A) 1 (B) 2 (C) 3 (D) 4 |
Answer» Correct Option is : (C) 3 Molecular Configuration of \(N_2\) \( 15 \sigma^2 \ 15 \sigma^{\ast 2} \ 25 \sigma^2 \ 15 \sigma^{\ast 2} \ 2p_x \sigma^2 \ 2p_y \pi^2 = 2p_z{\pi^2}\) Bond Order = \(\frac{bonding \ e^- \ - \ antibonding \ e^- }{2}\) = \(\frac{10-4}{2}\) = 3 Option : (C) 3 |
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659. |
Choose the correct statement.(a) NO molecules is diamagnetic (b) O2 molecules is paramagnetic (c) N2 molecules is paramagnetic (d) Li2 molecules is paramagnetic |
Answer» (b) O2 molecules is paramagnetic |
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660. |
Write Lewis symbol of potassium and calcium. |
Answer» Potassium – K and Calcium – •Ca• |
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661. |
Which of the following is / are true? 1) Ionic compounds exist as solids. 2) Ionic compounds have high melting and boiling points. 3) Ionic compounds conduct electricity in solid state. 4) Ionic compounds have low melting and boiling points. |
Answer» Ionic compounds generally exists as solids and they have very high melting and boiling points and they conduct electricity in aqueous or molten state. So first and second statements are true. |
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662. |
Explain briefly the information provided by the electronic configuration of molecules. |
Answer» The electronic configuration of molecules provides the following information :
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663. |
Electronic configuration of X is 2, 8, 1 and electronic configuration of Y is 2, 8, 7. Explain what type of bond is formed between them. |
Answer» The element with electronic configuration 2, 8,1 is sodium which is a metal. Similarly the element with electronic configuration 2, 8, 7 is chlorine which is a non-metal. The electronegativity difference between these two elements is more than 1.9 so they form ionic bond. |
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664. |
Why are molecules more stable than atoms? |
Answer» Molecules have lower energy than that of the combined atoms. Molecules are more stable than atoms since chemical species with lower energy are more stable. |
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665. |
Why electrovalent compounds in crystalline state do not conduct electricity ? |
Answer» Electrovalent crystalline solids do not conduct electricity because the oppositely charged ions in them are held together by a strong electrostatic force of attraction. These ions occupy fixed position in the crystals and do not move when an electric field is applied. . |
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666. |
What is electronic configuration? |
Answer» A systematic arrangement of electrons in the atomic orbits is called electronic configuration. |
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667. |
Explain the following:(a) Electrovalent compounds conduct electricity.(b) Electrovalent compounds have a high melting point and boiling point while covalent compounds have low melting and boiling points.(c) Electrovalent compounds dissolve in water whereas covalent compounds do not.(d) Electrovalent compounds are usually hard crystals yet brittle.(e) polar covalent compounds electricity. |
Answer» (a) Electrovalent compounds in the solid state do not conduct electricity because movement of ions in the solid state is not possible due to their rigid structure. But these compounds conduct electricity in the molten state. This is possible in the molten state since the electrostatic forces of attraction between the oppositely charged ions become weak. Thus, the ions move freely and conduct electricity. (b) The atoms of covalent compounds are bound tightly to each other in stable molecules, but the molecules are generally not very strongly attracted to other molecules in the compound. On the other hand, the atoms (ions) in electrovalent compounds show strong attractions to other ions in their vicinity. This generally leads to low melting points for covalent solids, and high melting points for electrovalent solids. (c) Electrovalent compounds dissolve in polar solvents like water because the forces of attraction between positive and negative charges become weak in water. But since covalent compound are made up of molecules, they do not ionize in water and hence do not dissolve in water. (d) Since it takes a lot of energy to break the positive and negative charges apart from each other, the ionic compounds are so hard. But on applying stress, Ions of the same charge are brought side-by-side and so the opposite ions repel each other and crystal breaks into pieces. (e) Since polar covalent compounds are made up of charged particles, they conduct electricity in aqueous solution |
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668. |
A solid is crystalline, has a high melting point and is water soluble. Describe the nature of the solid. |
Answer» The solid is ionic in nature as the oppositely charged ions are being held tightly by strong intermolecular force of attraction and that's the reason for its high melting point and solubility in water |
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669. |
Which compounds exhibit high melting and boiling points? |
Answer» Ionic compounds exhibit high melting and boiling points. |
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670. |
Element M forms a chloride with the formula MCI2 which is a solid with high melting point. M would most likely be in the group in which ………….. is placed.[ (a) Na (b) Mg (c) Al (d) Si ] |
Answer» (b) Mg M would most likely be in the group in which Mg is placed. |
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671. |
Write a neutral molecule which is isoelectronic with ClO-. |
Answer» OF2 a neutral molecule which is isoelectronic with ClO-. |
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672. |
What is the state of hybridisation of Carbon in CO32- ion? |
Answer» Sp2 is the state of hybridisation of Carbon in CO32- ion. |
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673. |
Which one of the following has trigonal bipyramidal shape?(a) SF6(b) IF4+(c) AsF5(d) SF4 |
Answer» The correct option is- (c)AsF5 |
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674. |
Which one of the following does not have tetrahedral shape?(a) NH4+(b) ClO4-(c) HCHO(d) CH4 |
Answer» The correct option is- (c) HCHO |
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675. |
Which one of the following has pentagonal bipyramidal shape?(a) XeF4(b) XeOF4(c) IF7(d) IOF5 |
Answer» The correct option is-(c) IF7 |
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676. |
Which one of the following has linear shape?(a) O3(b) CO32-(c) NO3-(d) BCl3 |
Answer» The correct option is- (a) O3 |
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677. |
Which one of the following has tetrahedral shape?(a) HCHO(b) BeCl2(c) PbCl2(d) CF2Cl2 |
Answer» The correct option is- (d) CF2Cl2 |
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678. |
Which one of the following pair has T – shaped structure?(a) BrF3 , CIF3(b) SF4 , IF4+(c) PCl5 , AsF5(d) NH3 , PF3 |
Answer» (a) BrF3 , CIF3 |
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679. |
Which of the following has linear shape?(a) PCl5(b) SnBr2(c) BeCl2(d) CCl2F2 |
Answer» The correct option is- (c) BeCl2 |
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680. |
Match the following:List-IList-IIA.T-shaped1.SOF4B.See saw2.CIF3C.Pyramidal3.XeOF2D.Trigonal bipyramidal4.ClO3-Code:ABCD(a)1234(b)3412(c)4123(d)2341 |
Answer» The correct option is-(d) 2 3 4 1 |
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681. |
Match the following:List-IList-IIA.Linear1.ClO4-B.Trigonal planar2.CO2C.Bent3.CO32-D.Tetrahedral4.O3Code:ABCD(a)1234(b)3412(c)2341(d)4123 |
Answer» The correct answer is:- (c) 2 3 4 1 |
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682. |
Match the following:List-IList-IIA.O=C=O1.1.47 DB.2.1.04 DC.3.ZeroD.CHCl34.1.85 DCode:ABCD(a)2341(b)3412(c)1234(d)4123 |
Answer» The correct option is:-(b) 3 4 1 2 |
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683. |
Match the following:List-IList-IIA.CH41.120ºB.NH32.104º 28'C.H2O3.109º 28'D.BF34.107º 18'Code:ABCD(a)3421(b)4213(c)1342(d)2134 |
Answer» The correct option is-(a) 3 4 2 1 |
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684. |
Dimagnetic species are those which contain no unpaired electrons. Which among the following are dimagnetic?(i) N2(ii) N22–(iii) O2(iv) O22– |
Answer» (i) N2 (iv) O22– |
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685. |
There are large number of compounds used in the household besides a large number of others which we use in our everyday life. From the point of view of chemistry, these compounds are either ionic or covalent . quite often, these compounds are given some common names instead of their chemical names. Now answer the following questions : (i) Give one important use of each of the following compounds : Magnesium hydroxide, magnesium sulphate, potassium nitrate, sodium carbonate. (ii) Which compound of Li is used for treatment of manic depression. (iii) Which compound of Zn is present in calamine lotion used for protection of skin. (iv) Which acid is present in the orange juice & which acid is present in batteries. (v) Which compound of sodium is used as a (a) bleach (b) as drain cleaner (c) in tooth paste. |
Answer» (i) Magnesium hydroxide - milk of magnesia an antacid magnesium sulphate - laxative & anti convulsant. potassium nitrate - igniter in fireworks & matchstics. sodium carbonate - as washing soda. (ii) lithium carbonate is used for treatment of manic depression (which is due to over anxiety & excitement) (iii) Zinc oxide. (iv) Citric acid & sulphuric acid. (v) (a) Sodium hypochlorite. (b) Sodium hydroxide. (c) sodium flouride. |
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686. |
Define the terms: 1. Electrovalent or ionic bond2. Electrovalent or ionic compound. |
Answer» 1. Electrovalent or ionic bond: The chemical bond formed between two atoms by transfer of one or more electrons from the atom. 2. Electrovalent or ionic compound: The chemical compound formed as a result of transfer of one or more electrons from atom. |
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687. |
Learning Objectives of Chemical Bonding. |
Answer» After studying this unit the student should be able to :
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688. |
Chemical Bonding. |
Answer» It is observed that the atoms of all the elements, except those for noble gases, tend to remain in combined state with the atoms of same or other element. They do not exist as single atoms under ordinary conditions. Such atomic aggregates occur as molecules or as giant network. A molecule may be defined as a small electrically neutral cluster or group of mutually bonded atoms. A chemical bond may be defined as “binding force between two atoms in a molecule”. |
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689. |
What is chemical bonding? |
Answer» Chemical bonding is the attractive force that holds or binds constituents were atoms, ions or molecules together in a substance. |
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690. |
Define electrovalent bond. |
Answer» The bond formed, as a result of the electrostatic attraction between the positive and negative ions are termed as the electrovalent bond. |
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691. |
Explain the geometry of NH3 and H2O molecule based on VSEPR theory. |
Answer» NH3 molecule: According to VSEPR theory, NH3 should have tetrahedral shape due to presence of 4 electron pairs. The presence of lone pair on nitrogen causes greater repulsion to the bond pairs. As a result of which the three N-H bonds move slightly closer. So it decreases the normal tetrahedral bond angle of 109.50 to 1070 . Therefore, ammonia has irregular geometry. Since one of the tetrahedral position is occupied by lone pair, the shape of ammonia molecule is pyramidal. |
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692. |
Write the bond angle in each – SO42- ,CO32- ,[H3O]+,NO3, PCl5, SF4 |
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693. |
Identify the geometry represented by the following diagram.(A) Trigonal bipyramidal (B) T-shape (C) square planar (D) square pyramidal |
Answer» Option : (D) square pyramidal |
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694. |
Choose the correct pair.(a) CH4 – ionic bond (b) BF3 – dative bond(c) NH3 – metallic bond (d) CCI4 – covalent bond |
Answer» (d) CCI4 – covalent bond |
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695. |
Choose the correct pair.(a) CH4 – 107° 18’ (b) H2O – 109°28’ (c) NH3 – 104°35’ (d) BF3 – 120° |
Answer» (d) BF3 – 120° |
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696. |
Choose the Incorrect pair.(a) AB3 – Trigonal planar (b) AB3L2 – T-shape (c) AB5 – Trigonal bipyramidal (d) AB3L – Bent |
Answer» (a) AB3L : Bent. Actually AB3L is pyramidal. |
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697. |
In CH4 , NH3 and H2O, the central atom undergoes sp3 hybridisation-yet their bond angles are different, why? |
Answer» 1. In CH4 , NH3 and H2O the central atom undergoes sp3 hybridisation. But their bond angles are different due to the presence of lone pair of electrons. 2. It can be explained by VSEPR theory. According to this theory, even though the hybridisation is same, the repulsive force between the bond pairs and lone pairs arc not same. 3. Bond pair-Bond pair < Bond pair – Lone pair < Lone pair – Lone pair So due to the varying repulsive force the bond pairs and lone pairs are distorted from regular geometry and organise themselves in such a way that repulsion will be minimum and stability will be maximum. 4. In case of CH4 , there are 4 bond pairs and no lone pair of electrons. So it remains in its regular geometry. i.e., tetrahedral with bond angle 109° 28’. 5. H2O has 2 bond pairs and 2 lone pairs. There is large repulsion between lp – lp. Again repulsion between lp – bp is more than that of 2 bond pairs. So 2 bonds are more restricted to form inverted V shape (or) bent shape molecule with a bond angle of 104° 35’. 6. NH3 has 3 bond pairs and 1 lone pair. There is repulsion between lp – bp. So 3 bonds are more restricted to form pyramidal shape with bond angle equal to 107° 18’. |
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698. |
Choose the Incorrect pair.(a) CS2 – Linear (b) BF1 – Trigonal planar (c) CH4 – T-shape (d) NH3 – Pyramidal |
Answer» (c) CH4 – T-shape |
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699. |
Define octet rule. Write its significance & limitations. |
Answer» Octet Rule- Every element tries to acquire 8 electrons in its outermost orbit by loosing or gaining or sharing electron. Significance – Most of the molecules are formed by following octet rule eg. N2,O2,Cl2,Br2 etc it is useful for understanding most of the organic compounds and it applies mainly to the second period elements of the periodic table. Limitations- Although octet rule is very useful but is not universal.In some compounds, the number of electron surrounding the central atom is less than 8.In NO,NO2 octet rule is not satisfied they are odd electron molecule In PF5,SF6,IF7 these expanded octets or super octets i.e. 10,12 and 14 electrons respectively after sharing. |
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700. |
Limitations of octet rule. |
Answer» Formation of electron deficient compounds like BeCl3 , BF3 , AlCl3 . Central atom has less than 8e . Formation of hypervalent compounds like PCl5, SF6, IF7, H2SO4 in which central atom has more than 8 electrons. Formation of compounds of noble gases like XeF2, XeF4, XeF6 . Odd electron molecules like NO, NO2. |
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