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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
701. |
The correct stability order of the following resonance structrue is : `H_2 C = overset (+)(N) = overline(N) ` `H_2 overset (+)C = (N) = overline(N) ` `H_2overline( C) - overset (+) (N) -= N` `H_2overline( C) - overset (+) (N) -= N`.A. ` (I) gt (II) gt (IV) gt (III)`B. ` (I) gt (III) gt (II) gt (IV)`C. ` (II) gt (I) gt (III) gt (IV)`D. `(III) gt (I) gt (IV) gt (II)` |
Answer» Correct Answer - B `underset("-ve charge on carbon")underset("Octet complete")underset((III)) underset(H_(2)overset(-)(C)overset(+)(N)equivoverset(-)(N))underset("-ve charge on bitrogen")underset("Octet complete")underset((I))(H_(2)C=overset(+)(N)=overset(-)(N))" "underset("-ve charge on carbon")underset("Octet complete")underset((IV)) underset(H_(2)overset(-)(C)-(N)equivoverset(+)(N))underset("-ve charge on bitrogen")underset("OCtet complete")underset((I))(H_(2)overset(+)(C)-N=overset(-)(N)`. |
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702. |
This section contains some integer type question Estimate the percent ionic character of the HBr molecule, given that the dipole moment `(mu)` is 0.63 D and HBr bond length 187.5 pm |
Answer» Correct Answer - 7 Calculated value of `mu=exxl` `=4.8xx10^(-10)esuxx187.5 xx10^(-10)cm` `=9xx10^(-18)esu cm ` `(1xx10^(-18)esu-cm=1"Debye")=9 Debye` Observed value of `mu=0.63` debye ltbr. % ionic character =`("Observed value x 100)/("calculated value")` `=0.63/9xx100=7%` |
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703. |
The correct stability order of the following resonance structure is A. `IgtIIgtIVgtIII`B. `IgtIIIgtIIgtIV`C. `IIgtIgtIIIgtIV`D. `IIIgtIgtIVgtII` |
Answer» (b) I has maximum covalent bond and negative charge on electronegative nitrogen, most stable. III has more convalent bond than both II and IV, III is second most stable .II is more stable than IV, since it has negative charge on nitrogen. So the order is `I gt III gt II gt IV` | |
704. |
The bond angle and dipole moment of water respectively are `:`A. `105.5^(@)`, 1.84DB. `107.5^(@)`, 1.56 DC. `104.5^@`, 1.84 DD. `102.5^@` , 1.56 D |
Answer» Correct Answer - C Bond angle of `H_2O` is `104-5^(@)` and dipole moment is 1.84 |
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705. |
The bond angle and dipole moment of water respectively are `:`A. `109.5^(@),1.84D`B. `107.5^(@),1.56D`C. `104.5^(@),1.84D`D. `102.5^(@),1.56D` |
Answer» Correct Answer - C Bond angle of `H_(2)O` is `104.5^(@)` due to lp-lp repulsion. |
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706. |
Which of the following has a regular geometryA. `CHCl_(3)`B. `PCl_(3)`C. `XeF_(6)`D. `SF_(4)` |
Answer» Correct Answer - A `CHCl_(3) to ` Tetrahedral `PCl_(3) to ` Pyramidal `XeF_(6) to `Distorted octahedral `SF_(4) to `Distorted trigonal bipyramidal |
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707. |
Correct order of Bond angle isA. `NH_(3) gt PCl_(3) gt BCl_(3)`B. `BCl_(3) gt NH_(3) gt PCl_(3)`C. `BCl_(3) gt PCl_(3) gt NH_(3)`D. `PCl_(3) gt BCl_(3) gt NH_(3)` |
Answer» Correct Answer - B `BCl_(3)` is trigonal in shape where bond angle is `120^(@)`. In `NH_(3)` and `PCl_3` (both are having tetrahedral geometry) through the central atom has equal no. of lone pairs and bond pairs, the valence shell of P is relatively bigger and bond angle is lower. |
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708. |
Which bond is most polar?A. Cl-FB. Br-FC. I-FD. F-F |
Answer» Correct Answer - C More is the electronegativity difference, more is polarity. `{:(,"Electronegativity difference"),(Cl-F,4.0-3.0=1.0),(Br-F,4.0-2.8=1.2),(I-F,4.0-2.4=1.6),(F-F,4.0-4.0=0.0) :}` |
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709. |
Which of the following possesses highest melting point ?A. chlorobenzeneB. o-dichlorobenzeneC. m-dichlorobenzeneD. p-dichlorobenzene |
Answer» Correct Answer - D p-dichloro benezene have highest mp. |
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710. |
Which of the following is least ionicA. `C_(2)H_(5)Cl`B. KClC. `BaCl_(2)`D. `C_(6)H_(5)N^(+)H_(3)Cl^(-)` |
Answer» Correct Answer - A Ethyl chloride is an organic compound so it will be covalent |
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711. |
Which one is the strogest bondA. Bi-FB. F-FC. Cl-FD. Br-Cl |
Answer» Correct Answer - A Generally Br-F contain maximum eletronegativity difference compare to other compound. |
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712. |
Highest melting point would be ofA. HeB. CsClC. `NH_(3)`D. `CHCl_(3)` |
Answer» Correct Answer - B CsCl has ionic bonding. |
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713. |
Which of the following is electron deficient molecule ?A. `B_2 H_6`B. `C_2H_6`C. `PH_3`D. `SiH_4` |
Answer» Correct Answer - A Out of the given four choice `B_2H_6` is an electron deficient molecule. |
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714. |
Sodium chloride is an ionic compound whereas hydrogen chloride is a gas becauseA. sodium is reactiveB. covalent bond is weaker than ionic bondC. hydrogen chloride is a gasD. covalent bond is stronger than ionic bond |
Answer» Correct Answer - B | |
715. |
In which of the following set do all the three compunds have bonds that are mainly ionic:-A. `NaCl,NCl_(3),C Cl_(4)`B. `CsBr,BaBr_(2),SrO`C. `CsF,BF_(3),NH_(3)`D. `Al_(2)O_(3),CaO,SO_(2)` |
Answer» Correct Answer - B | |
716. |
Which one is most ionic ?A. Cs-ClB. Al-ClC. C-ClD. H-Cl |
Answer» Correct Answer - A Cs is more electropositive |
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717. |
What is the effect of more electronegative atoms on the strength of an ionic bond ?A. DecreasesB. IncreasesC. Decreases slowlyD. Remains the same |
Answer» Correct Answer - B As soon as the electronegativity increases, ionic bond strength increases. |
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718. |
A compound is formed by the substitution of two chlorine atoms for two hydrogen atoms in propane. Write the structures of the isomers possible. Give the IUPAC name of the isomer which can exhibit enantiomerism.A. H-ClB. Cl-ClC. Na-ClD. C-Cl |
Answer» Correct Answer - C M-X bond is a strongest bond so between Na-Cl is a strongest bond. |
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719. |
The increassing order of bond order of `O_(2),O_(2)^(+),O_(2)^(-)`and O_(2)^(--)` is :A. `O_(2)^(-),O_(2)^(-),O_(2)^(+),O_(2)`B. `O_(2)^(+),O_(2),O_(2)^(-),O_(2)^(--)`C. `O_(2),O_(2)^(+),O_(2)^(-),O_(2)^(--)`D. `O_(2)^(--),O_(2)^(-),O_(2),O_(2)^(+)` |
Answer» Correct Answer - D Molecular orbitals electronic configuration of `O_(2)` is `(sigma1s)^(2)(sigma^(**)1s)^(2)(simga2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi2p_(x))^(2)(pi 2p_(y))^(2)(pi 2p_(y))^(2)(pi^(**)2p_(x))^(1)(pi^(**)2p_(y))^(1)` `:. B.O. ` of `O_(2)=1/2 (10-6)=2` Molecular orbitals electronic configuration of `O_(2)^(+)` is `(sigma1s)^(2)(sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x))^(2)(pi 2p_(y))^(2)(pi^(**)2p_(x))^(1)` `:. B.O. ` of `O_(2)^(+) =1/2 (10-5) =2.5` Molecular orbitals electronic configuration of `O_(2)^(-)` is `(sigma1s)^(2)(sigma^(**)2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x))^(2)(pi2p_(y))^(2)(pi^(**)2p_(x))^(2)(pi^(**)2p_(x))^(2)(pi^(**)2p_(y))^(1)` `:. B.O.` of `O_(2)^(-)=1/2 (10-7) =1.5` molecular orbitals electronic configuration of `O_(2)^(2-)` is `(sigma1s)^(2)(sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x))^(2)(pi2p_(y))^(2)(pi^(**)2p_(x))^(2)(pi^(**)2p_(y))^(2)` `:. B.O.` of `O_(2)^(2-) =1/2(10-8)=1.0` `:.` increasing order of B.O. is `O_(2)^(2-) gt O_(2)^(-) gt O_(2) gt O_(2)^(+)` |
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720. |
What will be the bond order of the species with electronic configuration `1s^(2) 2s^(2) 2p^(5)`?A. OneB. TwoC. ThreeD. Zero |
Answer» Correct Answer - A Electronic configuration of atom ` : 1s^(2) 2s^(2) 2p^(5) ` M.O. configuration: `(sigma 1s^(2))(sigma^(**)1s^(2))(sigma2s^(2)) (sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi 2p_(x)^(2) = pi 2p_(y)^(2))(pi^(**)2p_(x)^(2)=pi^(**)2p_(y)^(2))` B.O. ` = 1/2 xx (10 - 8) = 1` |
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721. |
Which of the following H-bonds is expected to have maximum strength ?A. H-O.. .HB. H-N.. .HC. H-S......HD. All have same strength |
Answer» Correct Answer - A The strength of H-bonds is attributed to the electronegativity of the atom bonded to hydrogen. Oxygen atom being more electronegative as compared to N and S, has greater strength of H-bonds. |
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722. |
The correct stability order for `N_2` and its given ions is :A. `N_(2) gt N_(2)^(+) = N_(2)^(-) gt N_(2)^(2-)`B. `N_(2)^(+) gt N_(2)^(-) gt N_(2) gt N_(2)^(2-)`C. `N_(2)^(-)gt N_(2)^(+) gt N_(2) gt N_(2)^(2-)`D. `N_(2)^(2-) gt N_(2)^(-) = N_(2)^(+) gt N_(2)` |
Answer» Correct Answer - A Bond order of `N_(2) = 3, N_(2)^(+) = 2.5, N_(2)^(-) = 2.5 and N_(2)^(2-)` is 2. Higher the bond order , more is the stability. |
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723. |
The correct stability order for `N_2` and its given ions is :A. `N_2 gt N_2^+ gtN_2^-1 gt N_2^(2-)`B. `N_2 lt N_2^+ ltN_2^-1 lt N_2^(2-)`C. `N_2 gt N_2^+ ltN_2 gt N_2^(2)`D. `N_2gt N_2^+ = N2^- gt N_2^(2-)` |
Answer» Correct Answer - A M.O. configuration of `N_2 : sigma 1s^2 , sigma^(**) 1s^2` . ` sigma s^2 , sigma2s^2 , [( pi 2 p_y^2) ,(pi2p_z^2)] sigma2p_x^2` The bond order for `N_2 =3` Fro `N_2^+ = 5/2` , For `N_2^- = 5/2` (with one moer antibonding electron than ` N_2^(+)` and 2 presoectivley . Thus Thus bond order is `N_2 gt N_2^+ = N_2^- gt N_2^(2-)` and stability order will be ` N_2 gt gt N_2^+ gt N_2^- gt N_2^(2-)`. |
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724. |
How many extreme types of chemical bonds exists in chemical species?A. TwoB. ThreeC. FourD. Five |
Answer» Correct Answer - B Ionic bond, covalent bond, and metallic bond are three extreme types. On the other hand, hydrogen bond is just an attractive force. |
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725. |
The symbol for resonance isA. `harr`B. `hArr`C. `=`D. `rarr` |
Answer» Correct Answer - A We represent ozone molecule by using two Lewis structures: `overset(..)underset(..)O=overset(+)underset(..)O-overset(..)underset(..)O:^(-)harr^(-) :overset(..)underset(..)O-overset(..)underset(+)O=overset(..)underset(..)O` The symbol `harr` indicates that the structures shown are resonance structures. |
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726. |
What is the geometry of the molecule with `sp^(3) d^(2)` hybridised contral atom isA. square planarB. Trigonal bipyramidalC. octahedralD. square puramidal |
Answer» Correct Answer - C Generally octahedral compound show `sp^(3)d^(2)-` hybridization. |
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727. |
`O_(2)^(2-)` is the symbol of ...... IonA. OxideB. SuperoxidwC. PeroxideD. Monoxide |
Answer» Correct Answer - C | |
728. |
A) C-H bond in ethyne is shorter than C-H bonds in ethene. R) Carbon atom in ethene is sp-hybridised while it is `sp^(2)` in ethyne.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. if both assertion and reason are true but reason is not the correct explanation of the assertionC. if assertion is true but reason is falseD. if the assertion and reason both are false |
Answer» Correct Answer - C The correct reason is the carbon atom is `sp^(2)` hybridised in ethene and sp hybridised in ethyne. `H-overset(sp^(2))underset(H)underset(|)©=overset(sp^(2))underset(H)underset(|)©-H-H -overset(sp)©-=overset(sp)©-H` |
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729. |
Which of the following statement `s` is `(are)` true ?A. ` sp^2 -`hybride orbitals are at `120^@` to one anotherB. `dsp^2 -`Hybride orbitals are directed towards the corners of a regular tetrahedronC. `sp^3 d^3 -` hybrid orbitls are directed towards the corners of a regular octahedronD. `sp^3 d^3 -` hybrid orbitls are directed towards the corners of a regular octahedron |
Answer» Correct Answer - A::B::D | |
730. |
In which , central atom `s` has have one lone pair of electron ?A. ` Cl_2`B. ` NH_3`C. `PCl_3`D. `XeF_6` |
Answer» Correct Answer - A::B::C | |
731. |
The valency of carbon in four. On what principle it can be explained in a better wayA. ResonanceB. HybridizationC. Electron transferD. None of the above |
Answer» Correct Answer - B Carbon has only two unpaired electrons by its configuration but hybridization is a concept by which we can explain its valency 4. |
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732. |
Out of the following hybrid orbitals, the one which forms the bond at angle `120^(@)` , isA. `d^(2)sp^(3)`B. `sp^(3)`C. `sp^(2)`D. `sp` |
Answer» Correct Answer - C | |
733. |
The structure of `[Cu(H_(2)O)_(4)]^(++)` ion isA. Square planarB. tetrahedralC. Distorted rectangleD. Octahedral |
Answer» Correct Answer - A | |
734. |
A square planar complex is formed by hybridisation of which atomic orbitals?A. `s,p_(x),p_(y),d_(yz)`B. `s,p_(x),p_(y),d_(x^(2)-y^(2))`C. `s,p_(x),p_y,d_(z^(2))`D. `s,p_(y),p_(z),d_(xy)` |
Answer» Correct Answer - B for square planar geometry hybridisation is `dsp^(2)` involving `s,p_(x),p_(y)` and `d_(x^(2)-y^(2))` orbital. |
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735. |
As compared to pure atomic orbitals, hybrid orbitals haveA. Low energyB. Same energyC. High energyD. None of these |
Answer» Correct Answer - A As compare to pure atomic orbitals, hybrid orbitals have low energy. |
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736. |
Using the `VSEPR` theory, identify the type of hybisation and draw the structure of `OF_(2)` What are the oxidation states of `O` and `F` ? .A. LinearB. Square planarC. TetrahedralD. Octahedral |
Answer» Correct Answer - C | |
737. |
The electronic structure of molecule `OF_(2)` is a hybrid ofA. spB. `sp^(2)`C. `sp^(3)`D. `sd^(3)` |
Answer» Correct Answer - C In molecule `OF_(2)` oxygen in `sp^(3)` hybridised. |
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738. |
Which of the following has tetrahedral structureA. `CO_(3)^(2-)`B. `NH_(4)^(+)`C. `K_(4)[Fe(CN)_(6)]`D. None of these |
Answer» Correct Answer - B Generally `NH_(4)^(+)` shows `sp^(3)` hybridization. |
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739. |
In which of the following species the underlined C atom has `sp^3` hybridization?A. `SiF_(4),BeH_(2)`B. `NF_(3),H_(2)O`C. `NF_(3),BF_(3)`D. `H_(2)S,BF_(3)` |
Answer» Correct Answer - B Applying VSEPR theory, both `NF_(3)` and `H_(2)O` are `sp^(3)` hybridized. |
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740. |
In which of the following molecules the central atom does not have `sp^(3)` hybridization ?A. `CH_(4)`B. `SF_(4)`C. `BF_(4)^(-)`D. `NH_(4)^(+)` |
Answer» Correct Answer - B `SF_(4)=sp^(3)d` |
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741. |
Some of the properties of the two species, `NO_(3)^(-)` and `H_(3)O^(+)` are described below.Which one of them is correct?A. Dissimilar is hybridization for the central atom with different structuresB. Isostructural with same hybridization for the central atomC. isostructural with different hybridisation for the central atomD. similar in hybridization for the central atom with structures |
Answer» Correct Answer - A `NO_(3)^(Theta) =sp^(2)` |
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742. |
The correct order of bond strength is :A. `O_(2)^(-) lt O_(2) lt O_(2)^(+) lt O_(2)^(2-)`B. `O_(2)^(2-) lt O_(2)^(-1) lt O_(2) lt O_2^(+)`C. `O_(2)^(-) lt O_(2)^(2-) lt O_(2) lt O_(2)^(+)`D. `O_(2)^(+) lt O_(2) lt O_(2)^(-) lt O_(2)^(2-)` |
Answer» Correct Answer - B Bond order for `O_2, O_(2)^(+), O_(2)^(-), O_(2)^(2-)` are ` 2 , 2 . 5, 1 . 5 ` and `1 . 0` respectively . Heigher is bond order more is bond energy . |
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743. |
In the case of alkali metals, the covalent character decreases in the order.A. `MF gt MCl gt MB rgt MI`B. `MFgt MCl gt MI gt MBr`C. `MI gt MBr gt MCl gt MF`D. `MCl gt MI gt MBr gt MF` |
Answer» Correct Answer - C For a given metal ion `(M^(+))`, the degree of polarization of the negative ion by the positive ion is decided by the polarizability of the negative ion which increases with its size (for a given charge). The greater the polarization, the higher the covalent character is: Size of negative ion `(I^(-)gtBr^(-)gtCl^(-)gtF)` Covalent character `(MIgtMBrgtMClgtMF)` |
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744. |
What is the bond order between carbon and nitrogen in `C-= N^(-)` ? |
Answer» Since there are 3 bonds between carbon and nitrogen so , the bond order is 3 . | |
745. |
Assertion : The experimentally determined carbon to oxygen bond length in carbon dioxide is 115 pm. Reason : The lengths of a normal carbon to oxygen double bond `(C=O)` and carbon to oxygen triple bond `(C-=)` are 121 pm and 110 pm respectively.A. If both assertion and reason are true and reason is the correct explanation of assertion.B. If both assertion and reason are true but reason in not the correct explanation of assertion.C. If assertion is true but reason is false.D. If both assertion and reason are false. |
Answer» Correct Answer - B In carbon dioxide, the carbon - oxygen bond lengths lie in between the values for (C = O) and `(C-= O)` bond lengths because carbon dioxide is a resonace hybrid of following structures : `underset(I)( :overset(..)(O) ::C::overset(..)(C): ) harr underset(II)( :underset(..)overset(..^(-))(O: )C vdots vdotsoverset(+)(O): ) harr underset(III)( :overset(+)(O)vdots vdots C :underset(..)overset(..^(-))(O: ))` |
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746. |
Which of the following have identical bond order ?A. `CN^-`B. `O_2^-`C. `NO^+`D. `CN^+` |
Answer» Correct Answer - A,C Both `CN^-` and `NO^+`have 14 electrons each and as such as isoelectronic. Therefore, also have same bond order. |
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747. |
In which of the following molecule, the bond lengths are not equalA. `SiF_4`B. `PF_5`C. `SF_6`D. `CF_4` |
Answer» Correct Answer - B In `PF_5` molecule, the bond length in axial plane will become a little longer than the bond length between atoms in equatorial plane |
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748. |
The structure of `PF_(5)` molecule is _________.A. tetrahedralB. trigonal bipyramidalC. square planarD. pentagonal bipyramidal |
Answer» Correct Answer - B `PF_(5)` involves `sp^(3)d` hybridization and hence has trigonal bipyramidal structure. |
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749. |
Which of the following pairs have identical bond order?A. `F_(2) and O_(2)^(2-)`B. `N_(2) and CO_(2)`C. `O_(2) and O_(2)^(-)`D. `N_(2) and N_(2)^(+)` |
Answer» Correct Answer - A `F_(2) and O_(2)^(2-)` are isoelectronic . `F_(2) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2)) (sigma2p_(z)^(2)=pi2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi ^(**)2p_(y)^(2))` B.O.` = 1/2 xx (10 - 8) = 1` `O_(2)^(2-) : (sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi 2p_(x)^(2) = pi 2p_(y)^(2))(pi^(**)2p_(x)^(2) = pi^(**)2p_(y)^(2))` B.O. ` = (10-8)/2 = 1` |
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750. |
Which of the following bond order is indication of existence of a molecule ?A. Zero bond orderB. Negative bond orderC. Positive bond orderD. All of these. |
Answer» Correct Answer - C A molecule exists only if the bond order is positive. If bond order is zero or negative, the molecule does not exist. |
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