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1001.

`2A rarr B + C`. It would be a zero-order reaction whenA. the rate of reaction is proportional to square of conc. of `A`.B. the rate of reaction reamains same at any conc. of `A`C. the rate remains unchanged at any conc. of `B` and `C`D. the rate reaction doubles if conc. of `B` is increased to double.

Answer» Correct Answer - B
It is a characteristic of zero-order reaction. Rate of reaction depends only on conc. of reactants
1002.

For a relatively fast reaction, the rate constant is relatively………….and half-change time is relatively…………. .

Answer» Correct Answer - large, small
1003.

A substance which itself is not a catalyst but………….. .the reactivity of a catalyst is called a promoter and the one which reduces the activity is called…………for the catalyst.

Answer» Correct Answer - increase, poison
1004.

A catalyst accelerates the reaction by……… the activation energy of the reaction, or by forming an …………..with……………..activation energy.

Answer» Correct Answer - decreaisng, intermediate, low
1005.

The energy profile diagram for the reaction: `CO(g)+NO_(2)(g) hArr CO_(2)(g)+NO(g)` is given below: The activation energy of the backward reaction isA. `x`B. `y`C. `x+y`D. `x-y`

Answer» Correct Answer - C
1006.

Match the column I with column II and mark the appropriate choice. A. (A) `to` (iv), (B) `to` (iii), (C ) `to` (ii), (D) `to` (i)B. (A) `to` (i), (B) `to` (ii) (C ) `to` (iii), (D) `to` (iv)C. (A) `to` (ii), (B) `to` (iii), (C ) `to` (iv), (D) `to` (i)D. (A) `to` (iii), (B) `to` (iv) (C ) `to` (i), (D) `to` (ii)

Answer» Correct Answer - A
1007.

Which of the following statement about the catalyst is/are true?A. A catalyst makes the reaction feasible by making `Delta G` more negative.B. A catalyst makes equilibrium constant more favourable for forward reactionC. A catalyst accelerate rate of reaction by bringing down the activation energyD. A catalyst always increases the rate of reaction.

Answer» Correct Answer - C
1008.

Threshold energy is equal toA. activation energyB. activation energy - energy of moleculesC. activation energy + energy of moleculesD. None of these

Answer» Correct Answer - C
1009.

The energy profile diagram for the reaction: `CO(g)+NO_(2)(g) hArr CO_(2)(g)+NO(g)` is given below: The threshold energy of the reaction isA. `x+y-z`B. `x-y+z`C. `x+y+z`D. `x-y-z`

Answer» Correct Answer - C
1010.

Which of the following statements is correct ?A. An activated complex is formed before a reactionB. An activation complex is formed after a reactionC. An activated complex has longer lifeD. An activated complex has infinite life

Answer» Correct Answer - A
The species temporarily formed by the reactant molecules as a result of the collision before they from the product is called the activated complex. The number of molecularity of an elementary reaction (a more precies definition of molecularity). Thus, a unimolecular process must be preceded by collision between the molecule that is to react and other molecules in the system in order to raise the energy of the reacting molecules to the level of the activatedd complex.
1011.

The energy profile diagram for the reaction: `CO(g)+NO_(2)(g) hArr CO_(2)(g)+NO(g)` is given below: the heat of the reaction isA. `x`B. `y`C. `x+y`D. `x-y`

Answer» Correct Answer - B
1012.

The energy profile diagram for the reaction: `CO(g)+NO_(2)(g) hArr CO_(2)(g)+NO(g)` is given below: the heat of the reaction isA. xB. yC. x+yD. x-y

Answer» Correct Answer - B
1013.

In a reaction, the threshold energy is equal toA. activation energy + normal enrgy of reatantsB. activation energy - normal enrgy of reatantsC. normal energy of reactants - activation energyD. average kinetic energy of molecules of reactants

Answer» Correct Answer - A
1014.

The energy profile diagram for the reaction: `CO(g)+NO_(2)(g) hArr CO_(2)(g)+NO(g)` is given below: The threshold energy of the reaction isA. x+y-zB. x-y+zC. x+y+xD. x-y-z

Answer» Correct Answer - C
1015.

In a reaction, the threshold energy is equal toA. activation energy + entropy of the reactionB. half of activation energyC. activation energy - potential energy of the reactantsD. activation energy + potential energy of the reactants

Answer» Correct Answer - D
The minimum amount of potential energy to be possessed by reacting species to undergo a chemical reaction is called threshold energy while the minimum amount of potential energy to be acquired threugh coolision by two molecules to react is called activation energy.
The value os threshold energy as well as activation energy for a chemical reaction is primaily dependenrt on nature of reacting species.
1016.

The energy that the reactants must acquire through collisions to reach the activatred state is theA. activastion energy for the reverse reactionB. activation energy for the forward reactionC. activation energy for the forward or the reverse reactionD. entropy of activation

Answer» Correct Answer - C
In order to react , the colliding molecules must have a total kinetic energy equal to or greater than the the activation energy `(E_(a))` , which is the minimum amount of energy required to initial a chemical reaction. Lacking this energy, the molecules remain intact , and no charge results from the collision.
1017.

True statement isA. poistive catalyst increases the rate of reaction.B. During the course of the reaction, specific reaction rate remains constant.C. Rate constant always increases with rise in temperature whether the reaction is endothermic or exothermic.D. All are correct.

Answer» Correct Answer - D
1018.

The wrong statement isA. All the colliisons between reactant molecules do not lead to a chemical change.B. A zero order reaction proceeds at a constant rate independent of concentration or time.C. Fast reactions have low activation energies.D. In a first order reaction, the reaction ideally takes finite time to be complete.

Answer» Correct Answer - D
1019.

Collision theory is applicable toA. First order reactionsB. Zero order reactionsC. Bimolecular reactionsD. Intermolecular reactions

Answer» Correct Answer - C
1020.

Collision theory is applicable toA. first order reactionB. second order reactionC. any order reactionD. bimolecular reaction

Answer» Correct Answer - D
Why the rate constant depends on temperature can be explained by collision theory. Collision theory of reaction rates is a theory that assumes that, for reaction to occur, reactant molecules must collide with an energy greater than some minimum value and with the proper oriention. Bimolecular reaction are most common reactions.
1021.

The unit of the rate constant for first order reaction isA. mol / litB. (mol / lit ) ` "time "^(-1)`C. `"time "^(-1) `D. `(mol //lit ) ` time

Answer» Correct Answer - C
1022.

A chemical reaction is the result ofA. oxidationB. reductionC. effecitive collisionsD. activation state

Answer» Correct Answer - C
1023.

Which of the following is a first order reaction ?A. `NH_(4) NO_(2) to N_(2) +2H_(2)O`B. `2HI hArr H_(2) +I_(2)`C. `2NO_(2) hArr 2NO+O_(2)`D. `2NO+O_(2)hArr 2NO_(2)`

Answer» Correct Answer - A
1024.

the Order of reaction can be deduced fromA. chemical EquationB. ExpermentsC. Rate constantD. thermochenical Equation

Answer» Correct Answer - B
1025.

Two unimolecular reactions, I and II have the same rate constant at `25^(@)` C but `E_(a)` for reaction I is larger than `E_(a)` for reaction II . Which statement about these two reaction is correct?A. `k_("reaction I")` is the same as `k_("reaction II")` at all temperatures.B. `k_("reaction I")` is larger than `k_("reaction II")` at lower temperatures but smaller at higher temperatures.C. `k_("reaction I")` is smaller than `k_("reaction II")` at lower temperatures but larger at higher temperatures.D. `k_("reaction I")` is larger than `k_("reaction II")` at temperatures both lower and higher than `25^(@)` C.

Answer» Correct Answer - D
1026.

The activation energy ofr a reaction can be determined by measuring the reaction rate at different:A. temperatureB. catalyst concentrationsC. reactant concentrationsD. times on the reaction curve.

Answer» Correct Answer - D
1027.

For the reaction , `NO_(2)(g)+CO(g)toNO(g)+CO_(2)(g)` At temperatures below 500K , the rate law is rate `=k[NO_(2)]^(2)` which mechanism is consistent with this information? Mechanism1: `NO_(2)+NO_(2)toNO_(3)+NO ("slow")``CO+NO_(3)toCO_(2)+NO_(2)("fast")` Mchanism2: `NO_(2)+NO_(2)toNO_(3)+NO ("fast")` `CO+NO_(3)toCO_(2)+NO_(2)("slow")`A. 1onlyB. 2 onlyC. Either1or2D. Neither1 nor2

Answer» Correct Answer - A
1028.

The rate law for reaction `A+B rarr C` is Rate `=K[A] [B]` Given `K=6.93xx10^(-4)M^(-1)sec^(-1)` Find the time taken(sec) when concentration of `[A]` changes from `10^(-4)` M to `5xx10^(-5)` M Given: `[B] =1M`A. 10B. 100C. 1000D. 10000

Answer» Correct Answer - C
1029.

Radioactive elements can be categorised into (a) Neutron rich nuclide (b) Neutron poor nuclide In order to achieve stable `n/p` ratio these nuclide either emits `beta^(-),beta^(+)` (positron) or `alpha`-particle depending upon the `n/p` ratio of unstable nuclei and stable nuclei `._(53)P^(135) rarr Q+a` `Q rarr R+b` [Note : only stable isotope of element P and Q are `._(53)P^(135)` and `._(54)Q^(137)` respectively] Element P,Q,R do not show any resemblence to currently known element Particles a and b can be respectivelyA. `._(2)He^(4),-1^(e^(o))`B. `.-1^(e^(o)),._(2)He^(4)`C. `.-1^(e^(o)),._(+)e^(o)`D. `._(2)He^(4),._(2)He^(4)`

Answer» Correct Answer - B::C
1030.

Quantium efficiency or quantum yield `(phi)` of photochemical reaction is given by: `phi = ("moles of the substance reacted")/("moles of photons absorbed")` Absorption of UV radiation decomposes A according to the reaction `2A overset (hv) rarr B+3C` In a first order reaction 75% of the reactant disappears in `1.386` h the rate constant of the reaction is close to:A. `7.2xx10^(-1) s^(-1)`B. `3.6xx10^(-3) s^(-1)`C. `1.8xx10^(-3) s^(-1)`D. `2.8xx10^(-4) s^(-1)`

Answer» Correct Answer - D
1031.

The rate law for reaction `A+B rarr C` is Rate `=K[A] [B]` Given `K=6.93xx10^(-4)M^(-1)sec^(-1)` Starting with `[A] = 1 M` and `[B] =2M` what is the rate in (M`sec^(-1)`) when `[A]` changes to `0.25` M?A. `2.16xx10^(-3)`B. `2.16xx10^(-4)`C. `8.64xx10^(-4)`D. `8.64 xx 10^(-3)`

Answer» Correct Answer - B
1032.

The gaseous decomposition reaction, A(g) `rarr` 2B(g) + C(g) is observed to be first order over the excess of liquid water at `25^(@)C`. If is found that after 10 minutes the total pressure of system is 188 torr. The rate costant of the reaction (in `hr^(-1)) is : [Given : vapour pressure of `H_(2)O` at `25^(@)` is 28 torr `("ln" 2=0.7,"ln"3=1.1,"ln"10=2.3)`]A. `0.02`B. `1.2`C. `0.2`D. none of these

Answer» Correct Answer - B
1033.

The half-life of decomposition of gaseous `CH_(3)CHO` at initial pressure of `365 mm` and `170 mm` of `Hg` were `420 sec` and `880 sec` respectively. The order of the reaction is:A. 2B. 4C. 6D. 8

Answer» Correct Answer - 1
`t_(1//2)prop(1)/(a^(n-1))" "["Here "a propP]" "(880)/(410)=[(364)/(170)]^(n-1)" ":.n=2`
1034.

In the following reaction `A rarr B+C`, rate constant is `0.001Ms^(-1)`. If we start with `1M` of A then , cond, of A and B after 10 minutes are respectively.A. `0.5M , 0.5M`B. `0.6 M,0.4M`C. `0.4M,0.6M`D. none of these

Answer» Correct Answer - 3
`A rarr B+C`
rate constant`=0.001Ms^(-1)`
`[C_(0)]_(A)=1M`
From unit of rate constant, we can conclude that rate is of zero order.
Decrease in concentration of A in `10 mi n =0.01xx10xx60=0.6M`
`[C_(O)]_(A)t=10mi n=1-0.6=0.4M`
`[C_(B)]t=10mi n=0.6M`.
1035.

For an elementary reaction , `X(g)toY(g)+Z(g)` the half life period is 10 min. In what period of time would the concentration of X be reduced to 10% of original concentration?A. `20 min`B. `33 min`C. `15 min`D. `25 min`

Answer» Correct Answer - B
Use the formula: `(t_(10%("left")))/(t_(1//2)) = log((100)/(10))/(0.3)`
`t_(10%)("left") = (t_(1//2) xx 1)/(0.3)`
`= (10 min)/(0.3) = 33 min`.Correct Answer - B
Use the formula: `(t_(10%("left")))/(t_(1//2)) = log((100)/(10))/(0.3)`
`t_(10%)("left") = (t_(1//2) xx 1)/(0.3)`
`= (10 min)/(0.3) = 33 min`.
1036.

The given reaction ` 2 NO + O_(2) to 2NO_(2)` is an example ofA. First order reactionB. Second order reactionC. Third order reactionD. None of these

Answer» Correct Answer - c
It is a third order reaction because
Rate = `k [NO]^(2) [O_(2)]^(1) therefore O.R = 2 + 1 = 3`.
1037.

If the rate of the reaction is equal to the rate constant , the order of the reaction isA. 3B. 0C. 1D. 2

Answer» Correct Answer - b
For zero order reaction r = k .
1038.

For a first-order reaction `A rarr B` the reaction rate at reactant concentration of `0.10 M` is found to be `2.0 xx 10^(-5) "mol" L^(-1) s^(-1)`. The half-life period of the reaction isA. 200sB. 30sC. 300sD. 347s

Answer» Correct Answer - D
For first order reaction,
`A to B`
` rate =Kxx[A]`
`rate =Kxx[A]`
`[A]=0.01M`
`SO,2.0xx10^(-5)=Kxx0.01`
`k=(2.0xx10^(-5))/(0.01)s^(-1)`
`=2.0xx10^(-3)S^(-1)`
for first order reaction .
`t_(1//2)=(0.693)/(k)=(0.693)/(2.0xx10^(-3))`
`=346.5=347s`
1039.

The activation energy for a simple chemical reaction `A rarr B` is `E_(a)` in the forward reaction: The activation of the reverse reactionA. can be less than or more than `E_(alpha)`B. is always double of `E_(alpha)`C. is negative of `E_(a)`D. is always less than `E_(a)`

Answer» Correct Answer - A
the energy of activation of reverse reaction is less than or more than energy of activation `(E_(a))` of forward reaction .
`therefore Delta H=(E_(a))_(F)-(E_(a))_(R)`
because it depands upon the nature of reactionn
`if (E_(a))_(F)gt (E_(a))_(R)` reaction is endothermic
`or (E_(a))_(R),` Reaction is exothermic .
1040.

For a first order reaction `A to B ` the reaction rate at reactant concentration of `0.01` M is found to be `2.0 xx 10^(-5)` mol `L^(-1) s^(-1)` . The half life period of the reaction isA. 220 sB. 30 sC. 300 sD. 347 s

Answer» Correct Answer - d
R = k[A]
`2 xx 10^(-5) = k xx 10^(-2)`
`k = 2 xx 10^(-3) sec^(-1)`
`t_(1//2) = (0.693)/(k) = (0.693)/(2 xx 10^(-3)) = (693)/(2) = 347` sec .
1041.

The reaction `A to B` follows first order kinetics . The time taken for 0.8 mole of A to produce 0.8 mole of A to produce 0.6 mole of B is 1 hour . What is the time taken for conversion of 0.9 mole of A to produce to 0.675 mole of BA. 2hoursB. 1 hourC. 0.5 hourD. 0.25 hour

Answer» Correct Answer - b
`k = (2.303)/(t)` log `(0.8)/(0.6) = 2.303` log `(4)/(3)`
`t = (2.303)/(k)` log `(0.9)/(0.675) = (2.303)/(k) "log" (4)/(3) ` , t = 1 hour .
1042.

If the rate of the reaction is equal to the rate constant, the order of the reaction isA. 2B. 3C. 0D. 1

Answer» Correct Answer - C
Consider the simple reaction `ArarrB`
The differential rate law is
Rate `=k[A]^(x)`
where `x` is the order with respect to the reactant `A` as well as overall order of reaction.
If rate of a reaction is equal to the rate constant, then
`[A]^(x)=1`
or, `x=0`
Thus, it is a zero order reaction.
1043.

For a first-order reaction `A rarr B` the reaction rate at reactant concentration of `0.10 M` is found to be `2.0 xx 10^(-5) "mol" L^(-1) s^(-1)`. The half-life period of the reaction isA. 220sB. 30sC. 300sD. 347s

Answer» Correct Answer - D
For a first order reaction `ArarrB` , the differential rate law is
Rate `=k[A]`
`2.0xx10^(-5)molL^(-1)s^(-1)=k(0.01M)`
`k=(2.0xx10^(-5)molL^(-1)s^(-1))/(0.01M)`
`=2.0xx10^(-3)s^(-1)`
For the first order reaction
`t_(1//2)=(0.693)/(k)`
Thus,
`t_(1//2)=(0.693)/(2.0xx10^(-3)s^(-1))`
`=346.5s`
`=347s`
1044.

For a reaction, `A+Brarr` Product, the rate law is given by `r=k[A]^((1)/(2))[B]^(2)`. What is the order of the reaction ?

Answer» Order of reaction = `1//2+2=2.5`
1045.

A reaction is first order in A and of second order in B. Write the differential rate equation for the reaction.

Answer» Rate =` k[A][B]^(2)`
1046.

The reaction between `H_(2)(g)` and `O_(2)` (g) is highly feasible, yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain.

Answer» This is on account of the reason that the activation energy for the reactants is very high at room temperature and is not readily available.
1047.

If `50%` of the rectant is converted into a product in a first order reaction in 25 minutes, how much of it would react in 100 minutes?A. `93.75%`B. `87.5%`C. `75%`D. `100%`

Answer» Correct Answer - A
a) `t=(2.303)/k log (a)/(a-x)`
`loga/(a-x) = (kxxt)/(2.303) = (0.693xx100)/(25xx2.303) = 1.2`
`(a)/(a-x)= "Antilog" 1.2 = 15.8`
`(a-x) = a/(15.8)=100/(15.8)=100/(15.8)=6.329`
`x=100-6.329=93.67%`
1048.

Half life period is independent of initial concentration of reactant forA. First order reactionB. second order reactionC. Zero order reactionD. Third order reaction.

Answer» Correct Answer - A
a) it is the correct answer.
1049.

What is meant by pseudo first order reaction? Given an example of pseudo first order reaction. Write rate equation for the same.

Answer» Rate `= k[CH_(3)COOC_(2)H_(5)]`
1050.

A reaction `SO_(2)Cl_(2) to SO_(2)+ Cl_(2)` is first order reaction with half life period `3.15 xx 10^(4)`s at `320^(@)`C. What percentage of `SO_(2)Cl_(2)` would be decomposed on heating at `320^(@)`C for 90 minutes?

Answer» `k=0.693/t_(1//2)=0.693/(3.15 xx 10^(4)s)= 2.2 xx 10^(-5)s^(-1)`
For the first order reaction, `t=2.303/k log a/(a-x)`
`k=2.2 xx 10^(-5)s^(-1)`, t=90 min `=90 xx 60=5400s`
`(5400s) = 2.303/(2.2 xx 10^(-5)s^(-1)) log a/(a-x)`
(5400s) = `(2.303)/(2.2 xx 10^(-5)s^(-1))log (a/a-x)`
`loga/(a-x) = (5400s)xx(2.2 xx 10^(-5)s^(-1))/(2.303) = 0.0516`
`a/(a-x) = "Antilog" 0.0516=1.126` or `a=1.126a-1.126x`
`0.126a = 1.126x` or `x//a = 0.126/1.126 = 0.112`
or `%`of `SO_(2)Cl_(2)` decompoed `= 0.112 xx 100 = 11.2%`