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4651.

Is common salt a major chemical present in seawater ?

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ANSWER :YES
4652.

Is CH_(3)-CH_(2) -underset(CH_(3))underset(|)(CH_(2)) a brached -chain hydrocarbon ?

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ANSWER :No
4653.

Is burning of a candle wax a physical change or a chemical change ?

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SOLUTION :It is a CHEMICAL CHANGE.
4654.

Is an alkyl group represented by the general formulaC_(n)H_(2n+1) ?

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ANSWER :YES
4655.

Is a true solution homogeneous or heterogeneous ?

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SOLUTION :HOMOGENEOUS
4656.

………..is a substance which furnishes H^(+) ions when dissolved in water and a ……………… is a substance which furnishes OH^(-) ions in water.

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SOLUTION :AID,BASE
4657.

_______isa reactionis whichtwolikemoleculesreactto giveions.

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SOLUTION :SELF - IONISATION
4658.

________isa stateof a physicalchangeat whichthe volumeof allphasesremainunchanged .

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SOLUTION :physicalequilibrium
4659.

Is a mixture of caustic soda and quicklime called sodalime ?

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ANSWER :YES
4660.

Is a mixture of ethonal and water called antifreeeze ?

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ANSWER :YES
4661.

Is a mixture containing 95.6% ethanol and 4.4 % water called rectified spirit ?

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ANSWER :YES
4662.

……………is a double salt.

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SODIUM chloride
Washing soda
Potash alum
Bleaching powder

Answer :A
4663.

Is a combustible substance necessary for combustion to take place ?

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ANSWER :YES
4664.

Irreversible reaction is relatively slow.

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Solution :FALSE
Correct STATEMENT:IRREVERSIBLE REACTION is FAST
4665.

Iron when dipped in conc. HNO_3 becomeschemically inert . Give reason .

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Solution :When IRON is dipped in conc. `HNO_3` , it BECOMES chemically passive or inet due to the formationof a layer of iron OXIDE `(Fe_2O_3)`on its surface .
4666.

Iron will displace which one from its compound?

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Zn
Al
CU
Mg

Solution :Cu
4667.

Iron reacts with dilute HCl to form

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`FeCl_(2)`
`FeCl_(3)`
both (a) and (b)
`FeCl_(3)+H_(2)`

ANSWER :A
4668.

Iron reacts with Chlorine to form …………….

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SOLUTION : FERRIC CHLORIDE
4669.

Iron pyrites are converted to iron oxide by the process of ______.

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ANSWER :ROASTING
4670.

"Iron nails rust in test tube A, but, iron nails do not rust in test tubes B and C." Explain it

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Solution : It is observed in activitythat IRON nails kept in TEST tube A are EXPOSED to both air and water. Hence, iron nails rust in test tube A. In the test tube B, the iron nails are exposed to water only but not to air. Iron nails in test tube C are exposed to dry air only and not to water. Hence, iron nails do not rust in test tubes B and C.
Remember: For rusting, metal must be exposed to both air and water (MOISTURE).
4671.

Iron nails were added to ferrous sulphate solution in a test tube and kept for some time. The colour of iron nails became brownish. The reaction that takes place in categorised as

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Decomposition REACTION.
Combination reaction
Double decomposition reaction.
Displacement reaction.

Solution :Iron DISPLACES COPPER from copper sulphute which deposits on iron NAILS.
4672.

Iron is galvanized by coating it with :

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Nickel
Copper
Chromium
Zinc

Answer :D
4673.

Iron is coated with two metals A and B separately. When the coating is partially worn away, it is still proctected when coated with A and not by B. Explain with reference to electrochemical series.

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SOLUTION :(i) Comparison of electropositivity of A, B and Fe.
(ii) Comparison of standard reduction potential of A, B and iron.
(iii) Relation between standard reduction potential of an ELEMENT and the tendency of GETTING oxidised.
(iv) Relation between the tendency of a metal to get oxidised and its ABILITY to protect iron from corrosion
4674.

Iron is a lustrous greyish white metal and can be magnetised.

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SOLUTION :N/A
4675.

Iron (III) oxide is heated with aluminium powder forms iron in the molten state. This process is known as........

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SOLUTION : THERMIT PROCESS
4676.

Iron displaces copper from copper sulphate solution because

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COPPER is more reactive than iron
copper and iron EQUALLY reactive
iron is more reactive than copper
none of the above is true

Answer :C
4677.

Iron containing 2-4.5% of carbon is called ____________

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SOLUTION :PIG IRON
4678.

Iron can form two types of inos. Compare the ionic sizes of the respective ions.

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Solution :Both `FE^(2+) and Fe^(3+) have the same nume of protons
but the NUMBER of electron in `Fe^(3+)` is less than ltBrgt that of `Fe^(2+)` . HENCE the effective nuclear CHARGE is
more in the case of `Fe^(3+)` and thereby the ionic SIZE
of `Fe^(3+) ` is less than that of `Fe^(2+)` .
4679.

Iron burns in air to from

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`FEO`
`Fe_(2)O_(3)`
`Fe_(3)O_(4)`
`FeO_(2)`

ANSWER :B
4680.

Iqbal treated a lustrous, divalent element M with sodium hydroxide, He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid, Suggest how can he identify the produced gas. Write chemical equations for both the reactions.

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Solution :The ELEMENT is a METAL
`M+2NaOH to Na_2MO_2+H_2`
`M+2HCl to MCl_2+H_2`
The produced gas can be identified by BRINGING a burning matchstick near the reaction vessel . The gas burns with a pop SOUND The confirms that the gas is `H_2`.
4681.

Ions are formedwhen an atom ___________ electrons.

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SOLUTION :LOSE or GAIN
4682.

Ionisation potential increases in a period from left to right because

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ATOMIC RADIUS increases and nuclear CHARGE increases.
atomic radius decreases and nuclear charge decreases.
atomic radius increases and nuclear charge decreases.
atomic radius decreases and nuclear charge increases.

Solution :atomic radius decreases and nuclear charge increases.
4683.

ionisation potential decreases down the group in representative elements while transition elements of the 6th period have greater ionisation potential values compared to the elements of the 5th period. Justify.

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SOLUTION :(i) factors EFFECTING ionisation potential
(II) comparison of the screening effects of s, p, d
and F ELECTRONS
4684.

Ionisation energy decreasesdown the group in periodic table. Give reason .

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Solution :Downthe group, atomic size increases and hencethe VALENCE ELECTRONS are loosely BOUND. They require relatively less ENERGY for the removal . Thus IONISATION energy decreasesdown the group in periodictable.
4685.

Ionic radius increases across the period from left to right.

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Solution :IONIC radius decreases ACROSS the PERIOD from left to RIGHT.
4686.

Ionic radii decreases along the ___________.

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SOLUTION :PERIOD
4687.

Ionic compounds conduct electricity only in solution.

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Solution :False – IONIC COMPOUNDS can CONDUCT electricity in molten state ALSO
4688.

Ionic bond formation takes place between sodium and chlorine. But between hydrogen and chlorine, covalent bond formation takes place. Give reason.

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Solution :Sodium belongs to IA group and is highly ELECTROPOSITIVE. Chlorine belongs to VII A group and is highly electronegative. Sodium has very low IP value and can form `Na^(+)` ion easily. CHLROINE has very high IP value and high EA value and can form `Cl^(-)` ion easily. Thus, ionic bond results between sodium and chlorine. IP value of hydrogen is not as low as alkali metals, that is, Na. Hence, its tendency to form `H^(+)` ion is very less. Sharing of electrons takes place between hydrogen and chlorine RESULTING in the formation of polar covalent bond.
4689.

Iodine is a ........., but it possesses ..........

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SOLUTION : non-metal, LUSTRE
4690.

Intermolecular space is the least in

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water
steam
ICE
all of them

SOLUTION :ice
4691.

Intake of small quantity of methanol can be lethal. Comment.

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SOLUTION :METHANOL is oxidised to methanal in the liver. Methanal REACTS rapidly with the components of cells. It causes the protoplasm to coagulate. It also AFFECTS the optic nerve, causes blindness.
4692.

Intake of small amount of methanol can be fatal. Comment .

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Solution :Methano, when INGESTED, can AFFECT the CENTRAL NERVOUS system and MAY lead to death.
4693.

Insulation of electric wire is done by

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POLY ISOPRENE
neoprene
poly vinyl Chloride
poly Buta - 1, 3 diene

Answer :C
4694.

Inner Transition elements

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Solution :The f-block elements are PLACED at the BOTTOM of the periodic table and they have last three shells INCOMPLETELY filled . These elements are called Inner Transition Elements.
4695.

Inner-Transition Elements.

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SOLUTION :(i) Elements PLACED in two separate rows at thebottom of the periodic table are called innertransition elements.
(ii) They include two series of elements: Lanthanideseries and Actinide series. They belong to f-blockelements of Modem Periodic table.
(iii) 14 elements with atomic number 58 to 71(CERIUM to Lutetium) are called lanthanides.These elements are placed ALONG with lanthanum(La= 57) in group 3 and period 6 because of veryclose resemblance in properties between them.
(iv) 14 elements with atomic number 90 to 103(THORIUM to Lawrencium) are called actinides.These elements are placed along with actinium(Ac= 89) in group 3 and period7 because of veryclose resemblance in their properties.
(v)They have last three shells incompletely filled.
(vi) All these elements are metals.
4696.

Initial number of moles of reactants taken in a closed reaction vessel is given. Percentage degree of dissociation is also given . Identify the correct sequence of steps to calculate k_(c)value. (1) calculation of equilibriumconcentrations of reactants and products (2) calculation of equilibrim concentration number of moles (3) writing equilibrium constant expression for the reaction (4) calculation of k_(c) value by using the equilibrium concentration

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4,2,3,1
2,1,3,4
3,2,1,4
2,1,4,3

Solution :(i) calculate of equilibrium number of moles
(ii) calculation of equilibrium concentrations of reactants and products
(iii) writing equilibrium expression for the reaction
(iv) calculate of `k_(C)` value by USING the equilibrium CONCENTRATION
4697.

Inert gases exist in the form of free atoms.

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Solution :(i) For m ation of molecules is based on the electronicconfiguration of the combining elements.
(ii) In the case of inert gases, all the shells, INCLUDING the outermost shell are completely filled.
(iii) They have electronic configuration with complete duplet or complete octet.
(iv) Due to their stable electronic configuration, ATOMS of these elements do not lose, gain or share electrons with other atoms. Hence, inert gases EXIST in the FORMS of free atoms.
4698.

Inert gases are placed in a separate group in the Modem Periodic Table. (a) State the group number. (b) How many valence electrons do most of these gases have? (c) Why are they unreactive? (d) Name any two inert gases.

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Solution :(a) Group number for inert GASES in the PERIODIC Table is 18.
(b) Except helium, these gases have 8 valence electrons.
(c) Their octet is already complete. Therefore they have no tendency to react.
(d) (i) NEON.
(II) Argon.
4699.

Inert gases are placed in a separate group in the Modern Periodic Table a) State the group number. b) How many valence electrons do most of them have? c) Why are they unreactive? d) Name any two inert gases.

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Solution :(a) GROUP number of INERT gases is 18. (B) 8. (c) They are unreactive since their valence shell is completely filled. Hence they have no tendency to lose or gain ELECTRONS by participating in a chemical reaction. (d) HELIUM and Neon (or any other group 18 elements).
4700.

Inert gases and Normal Elements

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SOLUTION :