InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4652. |
Is CH_(3)-CH_(2) -underset(CH_(3))underset(|)(CH_(2)) a brached -chain hydrocarbon ? |
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| 4653. |
Is burning of a candle wax a physical change or a chemical change ? |
| Answer» SOLUTION :It is a CHEMICAL CHANGE. | |
| 4655. |
Is a true solution homogeneous or heterogeneous ? |
| Answer» SOLUTION :HOMOGENEOUS | |
| 4656. |
………..is a substance which furnishes H^(+) ions when dissolved in water and a ……………… is a substance which furnishes OH^(-) ions in water. |
| Answer» SOLUTION :AID,BASE | |
| 4657. |
_______isa reactionis whichtwolikemoleculesreactto giveions. |
| Answer» SOLUTION :SELF - IONISATION | |
| 4658. |
________isa stateof a physicalchangeat whichthe volumeof allphasesremainunchanged . |
| Answer» SOLUTION :physicalequilibrium | |
| 4661. |
Is a mixture containing 95.6% ethanol and 4.4 % water called rectified spirit ? |
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| 4662. |
……………is a double salt. |
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Answer» SODIUM chloride |
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| 4664. |
Irreversible reaction is relatively slow. |
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Answer» Solution :FALSE Correct STATEMENT:IRREVERSIBLE REACTION is FAST |
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| 4665. |
Iron when dipped in conc. HNO_3 becomeschemically inert . Give reason . |
| Answer» Solution :When IRON is dipped in conc. `HNO_3` , it BECOMES chemically passive or inet due to the formationof a layer of iron OXIDE `(Fe_2O_3)`on its surface . | |
| 4666. |
Iron will displace which one from its compound? |
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Answer» Zn |
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| 4667. |
Iron reacts with dilute HCl to form |
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Answer» `FeCl_(2)` |
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| 4670. |
"Iron nails rust in test tube A, but, iron nails do not rust in test tubes B and C." Explain it |
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Answer» Solution : It is observed in activitythat IRON nails kept in TEST tube A are EXPOSED to both air and water. Hence, iron nails rust in test tube A. In the test tube B, the iron nails are exposed to water only but not to air. Iron nails in test tube C are exposed to dry air only and not to water. Hence, iron nails do not rust in test tubes B and C. Remember: For rusting, metal must be exposed to both air and water (MOISTURE). |
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| 4671. |
Iron nails were added to ferrous sulphate solution in a test tube and kept for some time. The colour of iron nails became brownish. The reaction that takes place in categorised as |
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Answer» Decomposition REACTION. |
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| 4672. |
Iron is galvanized by coating it with : |
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Answer» Nickel |
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| 4673. |
Iron is coated with two metals A and B separately. When the coating is partially worn away, it is still proctected when coated with A and not by B. Explain with reference to electrochemical series. |
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Answer» SOLUTION :(i) Comparison of electropositivity of A, B and Fe. (ii) Comparison of standard reduction potential of A, B and iron. (iii) Relation between standard reduction potential of an ELEMENT and the tendency of GETTING oxidised. (iv) Relation between the tendency of a metal to get oxidised and its ABILITY to protect iron from corrosion |
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| 4674. |
Iron is a lustrous greyish white metal and can be magnetised. |
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| 4675. |
Iron (III) oxide is heated with aluminium powder forms iron in the molten state. This process is known as........ |
| Answer» SOLUTION : THERMIT PROCESS | |
| 4676. |
Iron displaces copper from copper sulphate solution because |
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Answer» COPPER is more reactive than iron |
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| 4678. |
Iron can form two types of inos. Compare the ionic sizes of the respective ions. |
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Answer» Solution :Both `FE^(2+) and Fe^(3+) have the same nume of protons but the NUMBER of electron in `Fe^(3+)` is less than ltBrgt that of `Fe^(2+)` . HENCE the effective nuclear CHARGE is more in the case of `Fe^(3+)` and thereby the ionic SIZE of `Fe^(3+) ` is less than that of `Fe^(2+)` . |
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| 4680. |
Iqbal treated a lustrous, divalent element M with sodium hydroxide, He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid, Suggest how can he identify the produced gas. Write chemical equations for both the reactions. |
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Answer» Solution :The ELEMENT is a METAL `M+2NaOH to Na_2MO_2+H_2` `M+2HCl to MCl_2+H_2` The produced gas can be identified by BRINGING a burning matchstick near the reaction vessel . The gas burns with a pop SOUND The confirms that the gas is `H_2`. |
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| 4682. |
Ionisation potential increases in a period from left to right because |
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Answer» ATOMIC RADIUS increases and nuclear CHARGE increases. |
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| 4683. |
ionisation potential decreases down the group in representative elements while transition elements of the 6th period have greater ionisation potential values compared to the elements of the 5th period. Justify. |
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Answer» SOLUTION :(i) factors EFFECTING ionisation potential (II) comparison of the screening effects of s, p, d and F ELECTRONS |
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| 4684. |
Ionisation energy decreasesdown the group in periodic table. Give reason . |
| Answer» Solution :Downthe group, atomic size increases and hencethe VALENCE ELECTRONS are loosely BOUND. They require relatively less ENERGY for the removal . Thus IONISATION energy decreasesdown the group in periodictable. | |
| 4685. |
Ionic radius increases across the period from left to right. |
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| 4687. |
Ionic compounds conduct electricity only in solution. |
| Answer» Solution :False – IONIC COMPOUNDS can CONDUCT electricity in molten state ALSO | |
| 4688. |
Ionic bond formation takes place between sodium and chlorine. But between hydrogen and chlorine, covalent bond formation takes place. Give reason. |
| Answer» Solution :Sodium belongs to IA group and is highly ELECTROPOSITIVE. Chlorine belongs to VII A group and is highly electronegative. Sodium has very low IP value and can form `Na^(+)` ion easily. CHLROINE has very high IP value and high EA value and can form `Cl^(-)` ion easily. Thus, ionic bond results between sodium and chlorine. IP value of hydrogen is not as low as alkali metals, that is, Na. Hence, its tendency to form `H^(+)` ion is very less. Sharing of electrons takes place between hydrogen and chlorine RESULTING in the formation of polar covalent bond. | |
| 4691. |
Intake of small quantity of methanol can be lethal. Comment. |
| Answer» SOLUTION :METHANOL is oxidised to methanal in the liver. Methanal REACTS rapidly with the components of cells. It causes the protoplasm to coagulate. It also AFFECTS the optic nerve, causes blindness. | |
| 4692. |
Intake of small amount of methanol can be fatal. Comment . |
| Answer» Solution :Methano, when INGESTED, can AFFECT the CENTRAL NERVOUS system and MAY lead to death. | |
| 4693. |
Insulation of electric wire is done by |
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Answer» POLY ISOPRENE |
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| 4694. |
Inner Transition elements |
| Answer» Solution :The f-block elements are PLACED at the BOTTOM of the periodic table and they have last three shells INCOMPLETELY filled . These elements are called Inner Transition Elements. | |
| 4695. |
Inner-Transition Elements. |
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Answer» SOLUTION :(i) Elements PLACED in two separate rows at thebottom of the periodic table are called innertransition elements. (ii) They include two series of elements: Lanthanideseries and Actinide series. They belong to f-blockelements of Modem Periodic table. (iii) 14 elements with atomic number 58 to 71(CERIUM to Lutetium) are called lanthanides.These elements are placed ALONG with lanthanum(La= 57) in group 3 and period 6 because of veryclose resemblance in properties between them. (iv) 14 elements with atomic number 90 to 103(THORIUM to Lawrencium) are called actinides.These elements are placed along with actinium(Ac= 89) in group 3 and period7 because of veryclose resemblance in their properties. (v)They have last three shells incompletely filled. (vi) All these elements are metals. |
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| 4696. |
Initial number of moles of reactants taken in a closed reaction vessel is given. Percentage degree of dissociation is also given . Identify the correct sequence of steps to calculate k_(c)value. (1) calculation of equilibriumconcentrations of reactants and products (2) calculation of equilibrim concentration number of moles (3) writing equilibrium constant expression for the reaction (4) calculation of k_(c) value by using the equilibrium concentration |
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Answer» 4,2,3,1 (ii) calculation of equilibrium concentrations of reactants and products (iii) writing equilibrium expression for the reaction (iv) calculate of `k_(C)` value by USING the equilibrium CONCENTRATION |
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| 4697. |
Inert gases exist in the form of free atoms. |
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Answer» Solution :(i) For m ation of molecules is based on the electronicconfiguration of the combining elements. (ii) In the case of inert gases, all the shells, INCLUDING the outermost shell are completely filled. (iii) They have electronic configuration with complete duplet or complete octet. (iv) Due to their stable electronic configuration, ATOMS of these elements do not lose, gain or share electrons with other atoms. Hence, inert gases EXIST in the FORMS of free atoms. |
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| 4698. |
Inert gases are placed in a separate group in the Modem Periodic Table. (a) State the group number. (b) How many valence electrons do most of these gases have? (c) Why are they unreactive? (d) Name any two inert gases. |
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Answer» Solution :(a) Group number for inert GASES in the PERIODIC Table is 18. (b) Except helium, these gases have 8 valence electrons. (c) Their octet is already complete. Therefore they have no tendency to react. (d) (i) NEON. (II) Argon. |
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| 4699. |
Inert gases are placed in a separate group in the Modern Periodic Table a) State the group number. b) How many valence electrons do most of them have? c) Why are they unreactive? d) Name any two inert gases. |
| Answer» Solution :(a) GROUP number of INERT gases is 18. (B) 8. (c) They are unreactive since their valence shell is completely filled. Hence they have no tendency to lose or gain ELECTRONS by participating in a chemical reaction. (d) HELIUM and Neon (or any other group 18 elements). | |
| 4700. |
Inert gases and Normal Elements |
Answer» SOLUTION :
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