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4701.

Inert elements

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Solution :ELEMENTS present in GROUP 18 on the extremeright of the Modem Periodic table are called Inert elements or Noble GASES. They have all SHELLS including the outermost shell COMPLETELY filled.
4702.

Increases order of atomic radii is

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`CA ltNa LT Mg`
`Mg lt Ca lt Na`
`Mg lt Na lt Ca`
`Na lt Mg lt Ca`

ANSWER :C
4703.

Increase in temperature decreases the conductivity of metallic conductors. Give a reason.

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Solution :Being more electropositive in nature, metals have a TENDENCY to lose their valence electrons. Due to the presence of these FREE electrons metals act as GOOD conductors. But increase in temperature increases the VIBRATIONS of metal kernels in the metal lattice. Increase in the vibrations obstructs the path of the electrons that in turn increases the RESISTANCE of the metal. Therefore, the conductivity decreases.
4704.

Increase in .............. increases the solubility of gases.

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TEMPERATURE
PRESSURE
no. of MOLES
CONCENTRATION

SOLUTION :pressure
4705.

In which type of magnetic material all the domains are aligned in such a way that they cancel out each other

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Paramagnetic
Diamagnetic
Ferrimagnetic
Antiferromagnetic

Answer :D
4706.

In which two types the elements were classified in early attempts ?

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SOLUTION :METALS and non-metals
4707.

In which test tube, reaction has occurred ? Write the balanced chemical equation for the reaction.

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Solution : The FOLLOWING reaction OCCURRED in a test TUBE containing iron NAIL dipped in a copper sulphate solution : `FE(s) + CuSO_4(aq)toFeSO_4(aq) + Cu(s)`
In this reaction, more reactive Fe displaces less reactive Cu.
4708.

In which test tube, iron nails rust?

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SOLUTION :IRON NAILS will rust in test TUBE A.
4709.

In which test tube, iron nails will not rust?

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Solution : IRON nails do not RUST in test TUBES B and C.
4710.

In which test tube is a curdy white solid formed ?

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SOLUTION :The TEST TUBE to which soap solution was added produced a CURDY white solid substance.
4711.

In which test tube do you get more foam ?

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Solution :The test tube which contains SOFT WATER, i.e., distilled water or rain water, PRODUCES FOAM easily.
4712.

In which test tube do you observe a curdy white precipitate ?

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SOLUTION :The TEST tube which CONTAINS hard water, i.e., tube well water, produces curdy white PRECIPITATES.
4713.

In which of the followng chemical equations, the abbreviations represent the correct states of the reactants and products involved at reaction temperature ?

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`2H_(2)(l)+O_(2)(l)to2H_(2)O(G)`
`2H_(2)(g)+O_(2)(l)to2H_(2)O(l)`
`2H_(2)(g)+O_(2)(g)to2H_(2)O(l)`
`2H_(2)(g)+O_(2)(g)to2H_(2)O(g)`

Solution :Water is obtained in vapour PHASE when gaseous hydrogen and oxygen REACT together.
4714.

In which of the following the identity of initial substance remains unchanged?

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Curdling of milk
Formation of crystals by process of CRYSTALLISATION
FERMENTATION of grapes
Digestion of FOOD

SOLUTION :Final substance is the same as initial substance.
4715.

In which of the following states the internal energy of a substance in the lowest ?

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GASEOUS
Liquid
Solid
NONE of these

ANSWER :C
4716.

In which of the following, displacement reaction is possible?

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SOLUTION of NACL + COIN of COPPER
Solution of `MgCl_2`+ coin of ALUMINIUM
Solution of `FeSO_4`+ coin of silver
Solution of `AgNO_3`+ coin of copper

Solution :Solution of `AgNO_3`+ coin of copper
4717.

In which of the following compounds -OH is the functional group? (A) Propane (B) Propanal (C) Propanol (D) Propanone

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Propane
Propanal
PROPANOL
PROPANONE

ANSWER :C
4718.

In which of the following compounds is –OH the functional group ?

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BUTANONE
BUTANOL
BUTANOIC ACID
butanal

Answer :B
4719.

In which of the following chemical equations, the abbreviation represent the correct states of the reactants and products involved at reaction temperature?

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`2H_2(I)+O_2to2H_2O(G)`
`2H_2(g)+O_2(I)to2H_2O(g)`
`2H_2(g)+O_2(g)to2H_2O(I)`
`2H_2(g)+O_2(g)to2H_2O(L)`

ANSWER :C
4720.

In which forms are the metals obtained from the earth's crust?

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Solution :METALS are obtained in the form of OXIDE, carbonate and SULPHIDE ores from the earth.s CRUST.
4721.

In which condition, chlorine reacts with saturated hydrocarbons at room temperature ?

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In the ABSENCE of SUNLIGHT
In the presence of sunlight
In the presence of water
In the presence of HYDROCHLORIC acid

ANSWER :B
4722.

In which case solubility decreases with increase in temperature?

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Endothermic PROCESS
EXOTHERMIC process
Both (a) and (b)
NONE of these

SOLUTION :Exothermic process
4723.

In which case solubility increases with increaşe in temperature?

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Endothermic PROCESS
EXOTHERMIC process
Both (a) and (B)
None of these

SOLUTION :Endothermic process
4724.

In which case rate of diffusion will be faster in water : Honey or Paint

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Honey
Paint
Rate is same in both
None

Answer :B
4725.

In which block of the Modem Periodic table are the non-metals present?

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s-block
p-block
d-block
f-block

SOLUTION : p-block
4726.

In which among the following reactions, the formation of product is favoured by decreasing the temperature or volume ?

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`2SO_(3(g)) hArr 2SO_(2(g)) + O_(2(g)) -q`
`N_(2(g)) + O_(2(g)) hArr 2NO_(g) -q`
`4NH_(3(g)) + 5O_(2(g)) hArr 2NO_((g)) + 6H_(2)O_(g) , DeltaH=-ve`
`2NO_((g)) + O_(2(g)) hArr 2NO_(2(g)), DeltaH=-ve`

Solution :In the REACTION, `2NO + O_(2) hArr 2NO_(2) + ` Heat
Formation of product is favoured by decreasing the TEMPERATURE or volume.
4727.

In what way yeast is important in the fermentation process?

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SOLUTION :Yeasts are single-celled microorganisms, belonging to the class of fungi. The enzymes PRESENT in yeasts CATALYSE many complex organic reactions. Fermentation is conversion of complex organic MOLECULES into simpler molecules by the action of enzymes. E.g. CURDLING of milk
4728.

In what way hygroscopic substances differ from deliquescent substances.

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Solution :Difference between hygroscopic and deliquescent substances is in the extent to which each material can ABSORB moisture. This is because both of these terms are very much related to each other and they refer to the PROPERTY of observing and the retention of moisture from the air. HOWEVER, they differ in the extent of absorption of moisture where hygroscopic materials absorb moisture but not to the extent the original substance dissolves in it, which is the case with deliquescence. Therefore deliquescence can be REGARDED as an extreme condition of hygroscopic ACTIVITY.
4729.

In water two O–H bond dissociation enthalpies are not identical.

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ANSWER :FALSE
4730.

In three moles of ethane (C_(2)H_(6)), calculate the following : Number of moles of hydrogen atoms,

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ANSWER :18 MOLES
4731.

In three moles of ethane (C_(2)H_(6)), calculate the following : Number of moles of carbon atom,

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ANSWER :6 MOLES
4732.

In three moles of ethane (C_(2)H_(6)), calculate the following : Number of molecules of ethane.

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ANSWER :`1.8066xx10^(24)`
4733.

In three moles of ethane (C_(2)H_(6)), calculate the following : (i) Number of moles of carbon atoms (ii) Number of moles of hydrogen atoms (iii) Number of molecules of ethane

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SOLUTION :(i) 1 mole of `C_(2)H_(6)` contains 2moles of carbon atoms
`therefore` 3 MOLES of `C_(2)H_(6)` will C - atoms = 6 moles
(ii) 1 mole of `C_(2)H_(6)` contains 6 moles of hydrogen atoms
`therefore " 3 moles of "C_(2)H_(6)" will contain H - atoms = 18 moles"`
(iii) `"1 mole of "C_(2)H_(6)" contains Avogadro.s number. i.e., "6.023xx10^(23)" molecules."`
`therefore" 3 moles of "C_(2)H_(6)" will contain ethane molecules "=3xx6.023xx10^(23)`
`=18.06xx10^(23)" molecules."`
4734.

In this ladder, symbols of elements are jumbled up. (a) Rearrange these symbols of elements in the increasing order of their atomic numbers in the periodic table. (b) Arrange them in the order of their group alos.

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Solution :H, He, Li, Be, B, C, N, O, F, NE, Na, Mg, Al, SI, P, S, Cl, Ar, K, CA,
4735.

In the upper region of blast furnace ______ helps in the reduction of iron oxide ot iron.

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ANSWER :CARBON MONOXIDE
4736.

In the table below, some of the elements of the periodic table with atomic numbers from 3 to 18 are given . These are represented by letters.Which are not the usual symblos of the elements. (a) which of these (i) is a noble gas (ii) is a halogen (iii) are alkali metals (iv) is an element with valency 4. (b) if A combines with F, what would be the formula of the resulting compound ? (c) what is the electronic arrangement of G ?

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Solution :(a) (i) G is a noble gas.
(ii) F is a halogen.
(iii) A and B are alkali metals.
(IV) D is an element with valency 4.
(b) if A combines with F, the formula of the resulting COMPUND wil be `A^(+)F^(-)`
(C) The electronic arrangement of G is 2,9
4737.

In the sequence of reaction C_(2)H_(2) underset(HgSO_(4))overset(H_(2)SO_(4)//H_(2)O)to A overset([O])to B The compound B is

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ethanoic acid
PROPANONE
ethanol
methanal

SOLUTION :`A to CH_(3)-CHO "" B to CH_(3)COOH`
4738.

In the schematic diagram for the preparation of hydrogen gas as shown in figure, what would happen if following changes are made ? (a) In place of zinc granules, same amount of zinc dust is taken in the test tube. (b) Instead of dilute sulphuric acid, dilute hydrochloric acid is taken. (c) Sodium hydroxide is taken in place of dilute sulphuric acid and the tube is heated.

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Solution :(a) Hydrogen gas would evolve at a greater speed because zinc dust provides more surface area for the reaction as COMPARED to granulated zinc.
(b) Almost same volume of gas would evolve.
(c) Hydrogen gas would evolve UPON heating the TUBE.
`Zn(s) + 2NaOH(aq) to underset("Sod. zincate")(Na_(2)ZnO_(2)(aq)) + H_(2)(G)`
4739.

In the refining of silver, the recovery of silver from silver nitrate solution Write involved displacement by copper metal. down the reaction involved.

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Solution :Silver NITRATE + Copper `to` Copper Nitrate + Silver
`2AgNO(aq)+Cu(s)TOCU(NO_3)_2(aq)+2AG(s)`
4740.

In the refining of silver, the recovery of silver nitrate solution involved displacement by copper metal. Write down the reaction involved.

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SOLUTION :The REACTION involved is :
`underset("SILVER nitrate")(2AgNO_(3))(aq)+Cu(s)tounderset("COPPER nitrate")(Cu(NO_(3))_(2))+2AG(s)`
4741.

In the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reaction involved.

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Solution :`Cu(s)+2AgNO_(3) (AQ) to Cu(NO_(3))_(2)(aq) +2AG(s)`
4742.

In the refining of silver, the recovery of silver from silver nitrate solution involves displacement by copper metal. Write down the reaction involved.

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Solution :`2AgNO_(3)(aq)+CU(s) to Cu(NO_(3))_(2)(aq)+2Ag(s)`
SILVER NITRATE + COPPER `to`Copper nitrate +Silver
4743.

In the reaction ,Zn+H_(2)SO_(4) to ZnSO_(4) +H_(2),zinc acts as

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an OXIDIZING AGENT
a reducing agent
a catalyst agent
NONE of these

ANSWER :B
4744.

In the reaction with acidified K_(2)Cr_(2)O_(7) solution , SO_(2) acts as

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an OXIDIZING AGENT
a reducing agent
a BLEACHING agent
a catalytic agent

Answer :B
4745.

In the reaction of Zn + FeSO_(4) to ZnSO_(4) + Fe

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ZN GETS oxidized
FE gets oxidized
Zn is OXIDISING agent
Zn and Fe both GET oxidized

Answer :A
4746.

In the reaction N_(2)O_(4) hArr 2NO_(2), the degree of dissociation of N_(2)O_(4) increases with the

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INCREASE in pressure
Decrease in temperature
increase in volume
presence of catalyst

Answer :C
4747.

In the reaction N_(2)O_(4) hArr 2NO_(2), the dissociation of N_(2)O was found to be 40 per cent at equilibrium when the reaction is conducted in a 2 L container at 300 K. Find the equilibrium constant and the number of moles of reactants and products.

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Solution :`{:(N_(2)O_(4), hArr,2NO_(2)),("Initial moles "," "1," "0):}`
Number of moles at equilibrium1-0.4=0.6 `""` 0.8
Concentration at equilibrium `0.6//2=0.3 ""0.8//2=0.4`
`THEREFORE K_(C)=([NO_(2)]^(2))/([N_(2)O_(4)])=((0.4)^(2))/(0.3)=0.533` mol/L
4748.

In the reaction N_(2) + O_(2) hArr 2NO- Heat , which of following conditions is suitable to get a good yield of NO ?

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INCREASE in temperature
Decrease in temperature
Increase in pressure
The ADDITION of a catalyst

Answer :A
4749.

In the reaction MnO_(2)+4HCl toMnCl_(2)+2H_(2)O+Cl_(2) (i) Name the compound oxidised (ii) reduced

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SOLUTION :(i) The compound oxidised is `HCL`
(II) The compound reduced is `MnO_(2)`
4750.

In the reaction MnO_(2)+4HCl to MnCl_(2)+2H_(2)O+Cl, the oxidised reactant is :

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`MnO_(2)`
`HCL`
`Cl_(2)`
`H_(2)`

Answer :B