InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4801. |
In the long form of periodic table the total number of groups are |
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Answer» 15 Group `1TO` ALKALI metals Group `17to` halogens Group `18to` noble gases |
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| 4802. |
In the hydrocarbon HC -= C -H,the covalency of carbon is |
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Answer» one |
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| 4803. |
In the Hall's process , cathode used is ………… . |
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Answer» Iron tank |
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| 4804. |
In the given figure of Cotyledon the parts labelled as A and B respectively are |
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Answer» fruit, shoot (B) primary shoot, primary root |
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| 4805. |
In thefraph given below, identify the states of solution atthevarious points A, B, C and E.If thesolution is cooled from point 'A' at which temperature, precipitation normally starts ? Also, find out theamount of solute precipitated at 40^(@)C at A and the amount of solute in thesolution at point 'E'. What would be themaximum amount of solute that can be precipitated in the process? |
| Answer» Solution :Thecurve indicates that thesolubility of thesolute at `100^(@)C` is 250 g. However, the given solution contains only 150 g of solute. THESOLUTION atpoint 'A' is an unsaturated solution. Therefore, no precipitation takes place up topoint 'B' at `60^(@) C`, where thesolution becomes saturated, withjust 150 gas SOLUBILITY. Point 'B'indicates saturated solution andhence, precipitations normally starts at `60^(@)C`. With the fall intemperature, solubility decreases andthe extra amount should get precipitated: Point 'C' at `40^(@)C` indicates that the solution still contained 150 g of solute, whichis a supersaturated solution. THATMEANS, it is possible to cool a solution from `60^(@)C" to" 40^(@)C` without any crystallisation by creating conditions such as absence ofdust particles. At `40^(@)C`, when crystallisation starts, thesolution ULTIMATELY becomes saturated , and this is represented by point D.At pointD (`40^(@)C`), thesolubility is 100 g . That means, 50 g of solute would havebeen precipitated. At 'E' also thesolution remains saturated by precipitating 25 g more ofsolute leaving behing 75 g of solute in the solution. At `0^(@)C`, when water starts to solidify, thesolution still contains 5 g ofsolute without precipitation. That means, 125 g of solute can be precipitated. | |
| 4806. |
In the formation of the compound XY, atoms of X lost one electrons each while atoms of Y gained one electron each. What is the nature of bond in XY? Predict the two properties of XY. |
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Answer» Solution :The atoms of X lose electrons whereas the atoms of Y GAIN electrons. Thus, there is TRANSFER of electrons from atoms of X to atoms of Y. The bond formed by the transfer of electrons is CALLED ionic bond. THEREFORE, the nature of bond in the compound XY is ionic. Properties of ionic compound XY: (i) The compound will be soluble in water. (ii) The compound will CONDUCT electricity when dissolved in water or in molten state. |
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| 4807. |
In the formation of nitrogen molecule. |
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Answer» ONE PAIR of ELECTRONS are SHARED |
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| 4808. |
In the formation of a compound XY_2, atom X donates one electron to each Y atom. Show theelectron dot structure of X and Y and the formation of XY_2 . What is the nature of bond in XY, ? Write any three properties of compound XY_2 . The electronic configurations of the elements X and Y are as follows:X-2,8,2Y-2,7 |
Answer» Solution : The nature of bonds in `XY_2`is ionic. Properties : (i) Ionic compounds have high MELTING and boiling points. (ii) Ionic compounds are generally soluble in WATER and insoluble in KEROSENE and petrol. (III) Solutions of ionic compounds conduct electricity. Molten STATE of such compounds also conductelectricity. |
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| 4809. |
In the following table, the positions of six elements A, B, C, D, E and F are given as they are in the Modern Periodic Table: On the basis of the above table, answer the following questions:(i) Name the element which forms only covalent compounds. (ii) Name the element which is a metal with valency three. (iii) Name the element which is a non-metal with valency three. (iv) Out of B and C, whose atomic radius is bigger and why? (v) Write the common name for the family to which the elements D and F belong. |
| Answer» Solution : (i) E(II) B(iii) C (IV) B, because atomic radius decreases from left to right due to INCREASE in the nuclear charge.(v) Noble gases | |
| 4810. |
In the following table, the positions of six elements A, B, C, D, E and F are given as they are in the Modern Periodic Table : On the basis of the above table, answer the following questions : (i) Name the element which forms only covalent compounds. (ii) Name the element which is a metal with valency three. (iii) Name the element which is a non-metal with valency three. (iv) Out of B and C, whose atomic radius is bigger and why? (v) Write the common name for the family to which the elements D and F belong. |
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Answer» Solution :(i) E (II) B (iii) C (iv) B, because ATOMIC RADIUS decreases from left to right DUE to increase in the nuclear charge. (V) Noble gases. |
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| 4811. |
In the following table, six elements A, B, C, D, E and F of the modern periodic table with atomic numbers 3 to 18 are given: (a) Which of these is (i) Noble gas (ii) halogen? (b) Which of these is the most active metal in 3rd period? (c) Identify the most electronegative element in the third period. (d) In the compound between B and F what type of bond will be formed? (e) What would be the nature of oxide formed by C? |
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Answer» Solution :(a) NOBLE GAS - GHalogen - F (b)Most active metal – B (c) Most electronegative in 3rd period - F (d) Ionic bond (e) Oxide formed by C would be BASIC. |
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| 4812. |
In the following schematic diagram for the preparation of hydrogen gas as shown in figure, what would happens if the following changes are made? (a) In place of zinc granules. Same amount of zinc dust is taken in the test tube. (b) Instead of dilute sulphuric acid, dilute hydrochloric acid is taken. (C) In place of zinc, copper turnings are taken. (D) Sodium hydroxide is taken in place of dilute sulphuric acid and the test tube is heated. |
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Answer» Solution :(a)Rate of reaction will be faster as surface AREA increases. (b) No net effect will be there as both are the strong acids. (c ) No reactions will TAKE place as copper is less reactive than hydrogen. (d) Zinc can also react with NAOH to GIVE hydrogen GAS. `2NaOH+Zn to ^(Delta) Na_2ZnO_2+H_2` |
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| 4813. |
In the following reaction , xAl(OH)_3 rarr Al_2O_3 + yH_2O : x and y are |
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Answer» 2,3 |
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| 4814. |
In the following reaction : x Mg + O_2 rarr 2 MgO Determine x. |
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Answer» 1 |
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| 4815. |
In the following reaction, while reactants undergo oxidation and which reactants undergo reduction ? ZnO+C to Zn+CO |
| Answer» SOLUTION :`ZNO` UNDERGOES REDUCTION. C undergoes OXIDATION. | |
| 4816. |
In the following reaction the substance which is reduced is PbS+4H_(2)O_(2)toPbSO_(4)+4H_(2)O |
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Answer» `H_(2)O_(2)` |
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| 4817. |
In the following reaction : CH_4 + 2O_2 rarr CO_2 + x H_2O Determine x. |
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Answer» 1 |
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| 4818. |
In the following pairs , identify the pair having a different (n+l) value |
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Answer» 4s'3p |
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| 4819. |
In the following equationsNa_2CO_3 + xHCl to 2NaCl + CO_2 + H_2Othe value of x is |
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Answer» 1 ` X= 2` |
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| 4820. |
In the following equation, doesthe abbreviations used represent the correct physical states of the reactants and products ? 2H_(2)(g) +O_(2)(1) to 2H_(2)O(1) |
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Answer» Solution :No. `O_(2) and H_(2)O`are also in the gaseous state. So, the correct FORM of the EQUATION should be `2H_(2)(g) +O_(2)(g) to 2H_(2)O(g)` |
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| 4821. |
In the following equations Na_(2) CO_(3) + x HC1 to 2NaC1 + CO_(2) + H_(2) O the value of x is |
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Answer» 1 |
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| 4822. |
In the following chemical reaction ''zinc oxide reacts with carbon to produce zinc metal and carbon monoxide.'' ZnO+CrarrZn+CO (i) Identify the substance getting oxidised and the one getting reduced. (ii) State the reason for choosing the substances in (i) . (iii) Name the type of reaction and give another example of similar type of reaction . |
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Answer» Solution :(i) C is getting OXIDIZED to CO, ZNO is getting reduced to Zn . (ii) As carbon is gatting oxygen and ZnO is LOSING oxygen . (iii) It is a redox REACTION or oxidation and reduction reaction . `CuO+H_(2)rarrCu+H_(2)O` |
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| 4823. |
In the following chemical reaction, ''zinc oxide reacts with carbon to produce zinc metal and carbon monoxide.'' ZnO+C to Zn+CO (a) Identify the substance getting oxidized and the one getting reduced. (b) State the reason for choosing the substances in (a). (c) Name the type of reaction and give another example of similar type of reaction. |
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Answer» Solution :(a) `ZnO` is getting reduced and C is getting oxidized. (b) `ZnO` is LOSING OXYGEN and C is GAINING oxygen. (c) Redox reaction. `Fe_(2)O_(3)+3CO to 2Fe+3CO_(2),` in this reaction iron (III) oxide undergoes REDUCTION,as it is losing oxygen and `CO` gents oxidized as it is gaining oxygen. |
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| 4824. |
In the extration of iron, the most preferred ores are |
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Answer» HEMATITE and limonite |
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| 4825. |
In the extraction of aluminium from bauxite ______ is added to lower the melting point of bauxite. |
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Answer» |
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| 4826. |
In the equation NaOH + HNO_3toNaNO_3 +H_2Onitric acid is acting as |
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Answer» an OXIDISING agent |
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| 4827. |
In the environment, materials causing biomagnification |
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Answer» get recycled quickly |
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| 4828. |
In the eletroplating of an objectwith silver , _______ is selected as electrolyte . |
| Answer» SOLUTION :SODIUM argentocyanide | |
| 4829. |
In the electroplating of iron by nickel, nickel sulphate solution is taken as an electrolyte. What is the acid that is added to the electrolyte during the process ? |
| Answer» Answer :D | |
| 4830. |
In the electron-dot structure, the valence-shell electrons are represented by crosses or dots. (a) The atomic number of chlorine is 17. Write its electronic configuration . (b) Draw the electron-dot structure of a chlorine molecule. |
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Answer» Solution :a] Chlorine: CL [17] - ELECTRONIC CONFIGURATION is 2,8,7. b] `:underset(ddot)OVERSET(ddot)(Cl):underset(ddot)overset(ddot)(Cl)` Chlorine molecule. |
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| 4831. |
In the electrolytic refining of copper , copper is |
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Answer» DEPOSITED at the ANODE |
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| 4832. |
In the electrolytic refining of a metal M, What would you take as an anode, the cathode and the electrolyte? |
| Answer» Solution : In the electrolytic refining, IMPURE metal (M) is TAKEN as an ANODE and THIN strip of pure metal (M) is taken as a CATHODE and solution of soluble salt of metal (M) is taken as an electrolyte. | |
| 4833. |
In the electrolytic refining a metal M, what would you take as the anode, the cathode and the electrolyte ? |
| Answer» SOLUTION :During the ELECTROREFINING of metal, the impure metal is made as anode, a THIN STRIP of pure metal M is made as CATHODE. The electrolyte used a soluble salt of metal M, to be refined. | |
| 4834. |
In the electrolytic reduction of alumina, the electrolyte is covered with coke powder because it |
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Answer» PREVENTS oxidation of aluminium formed |
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| 4835. |
In the electrolyte refining of a meal M, what would take the anode, the cathode and the electrolyte ? |
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Answer» Solution :Anode `rarr` IMPURE metal Cathode `rarr` PURE metal Electrolyte `rarr` Metal.s salt solution |
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| 4836. |
In the electrolysis refining of blister copper , a thin strip of pure copper is used as _______. |
| Answer» SOLUTION :CATHODE | |
| 4837. |
In the electrolysis of water : Why are few drops of dil. H_(2)SO_(4) added to the water ? |
| Answer» Solution :PURE water does not conduct electricity. A few drops of DIL . `H_(2)SO_(4)` are added to make water CONDUCTING. | |
| 4838. |
In the electrolysis of water : Why is the volume of gas collected at one electrode is double of the other ? |
| Answer» SOLUTION :`H:O=2:1` | |
| 4839. |
In the electrolysis of water : Name the gas collected at the cathode and the anode. |
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Answer» SOLUTION :The FOLLOWING GASES are collected : At Cathode : Hydrogen At Anode : Oxygen |
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| 4840. |
In the electrolysis of water: (i) Name the gas collected at the cathode and anode respectively . (ii) Why is the volume of one gas collected at oneelectrode is double than that at the other ? Name this gas . (iii) How will you test the evolved gases? |
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Answer» Solution :(i) At Cathode : hydrogen gas `(H_(2))` At Anode: oxygen gas `(O_(2))` (II) Since, `2H_(2)O overset ("Electric current ")rarr 2H_(2)+O_(2)` 2 MOLECULES of `H_(2)O`, so the volume of `H_(2)` liberated is double that of `O_(2)` (iii) When a burning SPLINTER is brought near the mouth of the liberated gases, the burning splinter extinguishes near the `H_(2)` gas while the burning splinter keeps burning more near the `O_(2)` gas. |
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| 4841. |
In the electrochemical series, ions are arranged in an increasing order of discharge potentials |
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Answer» |
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| 4842. |
In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate? |
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Answer» LEAD sulphate (INSOLUBLE) |
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| 4843. |
In the double displacement reaction aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing th activity if lead nitrate is not available, which of the following can be used in place of lead nitrate ? |
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Answer» Lead sulphute (insoluble) |
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| 4844. |
In the decomposition , 2N_(2)O_(5) hArr 4NO_(2) + O_(2) oxygen gas is produced at the average rate of 9.1 xx 10^(-4) mol L^(-1) s^(-1) . Over the same period what is the average rate of production of NO_(2) and loss of N_(2)O_(5) |
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Answer» Solution :(i) Rate of reactionrespective to each REACTANT and product (ii) EQUATING RATES of reactions with each other on the basis of stoichiometric coefficients (iii) `3.6xx10^(-3)` mol K`L^(-1) s^(-1), 1.8xx10^(-3)` mol `L^(-1) s^(-1)`. |
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| 4845. |
In the d-block elements as we move along a period the atomic radius decreases in the beginning, reaches minimum and then increases towards the end of the series. Explain with appropriate reasons. |
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Answer» Solution :In a particular series of d-block elements, electron filling TAKES place in the penultimate shell. HENCE their atomic size decreascs up to the `7^(th)` group and reaches minimum and then again increases because with the pairing of electrons, repulsive FORCE also increases. The repulsion among the added electrons exceeds the increased force of attraction (due to the increase of nuclear charge) after the `8^(th)` group. Hence, atomic radius increases slightly. |
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| 4846. |
In the chemical equation, 2Mg + O_2to2MgO, O_2represents |
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Answer» ATOMS of OXYGEN joined together in a MOLECULE |
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| 4847. |
In the brass alloy , which is solvent ? |
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Answer» Zn |
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| 4848. |
In the blast furnace/the flux is |
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Answer» ACIDIC |
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| 4849. |
In the alumino thermic process the role of Al is ………. |
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Answer» OXIDIZING AGENT |
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| 4850. |
In test-tubes Aand B , zinc sulphate solution and silver nitrate solution are taken respectively .Copper trunings are added to both test-tubes . In which of the two test-tubes do you observe the reaction. Justify your answer with scientific reason. |
| Answer» SOLUTION :Test-tube B CONTAINING SILVER NITRATE solution .Because silver from silver nitrate solution. | |