Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Amongst the following compounds the strongest acid is :

Answer»




ANSWER :B
Discussion
2.

Amongst the following compounds, the optically acitve alkane having lowest molecular mass is

Answer»

`CH_(3)-CH_(2)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-overset(CH_(3))overset(|)CH-CH_(3)`

`CH_(3)-CH_(2)-C-=CH`

Solution :
Optically ACTIVE due to PRESENCE of CHIRAL carbon atom.
Discussion
3.

Amongst the following chemical reaction, the one representing Homogenous catalysis is:-

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`N_(2)(g)+3H_(2)(g)overset(Fe)to2NH_(3)(g)`
`2SO_(2)(g)+O_(2)(g)overset(2NO)to2SO_(3)(g)+2NO_(g)`
`CO(g)+3H_(2)(g)overset(NI)toCH_(4)(g)+H_(2)O`
`2SO_(2)(g)+O_(2)(g)overset(V_(2)O_(5))to2SO_(3)(g)`

Solution :`underset((g))(2SO_(2))+underset((g))(O_(2))overset(2NO(g))tounderset((g))(2SO_(3))+2NO_((g))`, reactants and catalyst present in same phase.
Discussion
4.

Amongst OH^(-), CH_(3)COO^(-) and CH_(3)O^(-) ions, nucleophilicity decreases in the order.................. .

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ANSWER :`CH_(3)O^(-) gt OH^(-) gt CH_(3)COO^(-)`
Discussion
5.

Amongst H_2O, H_2S , H_2Seand H_2Tethe one with the highest boiling point is...…...

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`H_2O` because of HYDROGEN BONDING.
`H_2Te` because of HIGHER MOLECULAR WEIGHT.
`H_2Se` because of hydrogen bonding
`H_2Se` because oflower molecular weight.

Answer :A
Discussion
6.

Amongst alkali metals , why is lithium regarded as most apt reducing agent in aqueous solutions ?

Answer»

Solution :Amongst alkali metals , `LI^(+)` has the SMALLEST size and hence has the highest hydration energy . In other words , Li has the lowest ELECTRODE potential `(E^(@) = -3*04 V)` i.e., it has the maximum tendency to lose electrons and hence is the strongest (most apt) reducing agent amongst alkali metals .
Discussion
7.

Among NaCl and CsCl, which is easily formed? Which is strong ionic?

Answer»

Solution :CsCl is easily formed, because ionisation of caesium is easy to form `Cs^(+)` ION. Nacl is strong IONIC, because LATTICE energy is more due to small size of `Na^(+)` ion.
Discussion
8.

Amongest the following phenols which is most acidic?

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PICRIC acid
2-Nitrophenol
2, 4-Dinitrophenol
m-Nitrophenol

Solution :Due to THREE `-NO_(2) (-I)` GROUPS.
Discussion
9.

Amongest the following hydroxides, the which has the lowest value of K_(sp) at ordinary temperature (about 25^(@)C) is

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`Mg(OH)_(2)`
`Ca(OH)_(2)`
`Ba(OH)_(2)`
`Be(OH)_(2)`

Solution :LOWEST VALUE of `K_(sp)` IMPLIES lowest solubility
Discussion
10.

Amongest the following compounds the strongest acid is

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`CH -= CH`
`C_(6)H_(6)`
`C_(2)H_(6)`
`CH_(3)OH`

ANSWER :A
Discussion
11.

Amongest the following, choose the correct statements

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Atomic hydrogen is obtained by passing hydrogen through an electric car
hydrogen GAS will not reduce heated aluminium oxide
Finely divided palladium absorbes large amount hydrogen gas
Pure NASCENT hydrogen is the best obtained by Na with `C_(2)H_(5)OH`

Answer :A::B::C
Discussion
12.

The formal charge on the carbon atom in the following structure underset(* *)overset(* *)O=C=underset(* *)overset(* *)O is …………………….

Answer»

Solution :Structure I of `CO_(2) - UNDERSET(* *)overset(* *)O=C + underset(* *) overset(* *)O`
FORMAL charge on carbon `=N_(V)-[N_(l)+(N_(b))/(2)]=4-[0+(8)/(2)]=4-4=0`
Formal charge on oxygen `= N_(v)-[N_(l)+(N_(b))/(2)]=6-[4+(4)/(2)]=6-6=0`
Structure II of `CO_(2) - :O-=C-underset(* *)overset(* *)O:`
Formal charge on carbon `= N _(v)-[N_(l)+(N_(b))/(2)]=4-[0++(8)/(2)]=4-4=0`
Formal charge on singly bonded oxygen `= N_(v)-[N_(l)+(N_(b))/(2)]=6-[6+(2)/(2)]= 6-7=-1`
Formal charge on triply bonded oxygen `=N_(v)-[N_(l)+(N_(b))/(2)]=6-[2+(6)/(2)]=6-5=+1`
A structure in which all formal charges are zero is preferred over the one with non-zero charges. In CASE of `CO_(2)` structure, structure I is preferred over the structure II as it has zero formal charge for all the atoms.
Discussion
13.

Among the trihalides of nitrogen, which one is the least basic ?

Answer»

`NF_(3)`
`NCl_(3)`
`NBr_(3)`
`NI_(3)`

Solution :`NF_(3)` is LEAST basic because LONE pair of electrons on N is least available for protonation due to high ELECTRONEGATIVITY of F.
Discussion
14.

Among the three metals, zinc, copper and silver, the electron releasing tendency decreases in the following order.

Answer»

ZINC `LT` silver `lt` copper
zinc `lt` copper `lt` silver
silver `lt`copper `lt` zinc
copper `lt` silver `lt` zinc

ANSWER :C
Discussion
15.

Among the three isomers of nitro phenol, which is least soluble in water?

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ORTHO ISOMER
PARA isomer
meta isomer
all are insoluble

Answer :A
Discussion
16.

Among the tetrachlorides of group 14 elements, which one does not undergo hydrolysis?

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SOLUTION :`C Cl_4`
Discussion
17.

Among the structure shown below, which has lowest potential energy?

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SOLUTION :METHYL GROUPS at equtorial is most STABLE
Discussion
18.

Among the statements mentioned below which one is not helpful in explaining the diagonal relationship

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similarity in IONIC sizes
same charge to SIZE ratio
constancy in ionisation energy
similarity in CHEMICAL reaction.

Answer :A
Discussion
19.

Among the second period elements the actual ionization enthalpies are in the order Li lt B lt Be lt C lt O lt N lt F lt Ne. Explain why (i) Be has higherDelta_(i)H" and " B (ii) O has lower Delta_(i)Hthan N and Fthan N and F ?

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Solution :Generally, when we go left to right in periodic table value of ionisation ethalpy increases.
(i) `Delta_(i)H "" Be gt Delta_(i)H B `:Be has higher `Delta _(i)H`than B because Be has the electronic configuration `1 s^(2)2s^(2)` while B has the electronic configuration is `1s^(2)2s^(2)p^(1)`. The LARGE `Delta _(i)H` of Be in comparison to B is due to the fact that.
The electronic configuration of Be is more stable (completely filled 2s orbitals) than that at B.
In Be the electron to be removed during the ionization is an s-electron while the electron to be removed during ionization of B is a p-electron.
The penetration of a 2s-electron to the nucleus is more than that of a 2p-electron and hence 2p-electron of B is more SHIELDED from the nucleus by the inner core of electrons than the 2s-electron of Be.
As a result, 28-electron attracted to the nucleus more than 2p-electron. THEREFORE, it is difficult to remove a 2s-electron from Be than to remove the 2p electron from B. Thus, Be has higher ionization enthalpy than B.
(ii) `DeltaH_(i)(1)O ltDelta_(i)H(1)N` : Oxygen has four electrons in 2p-orbitals and two of the four 2p-electrons must occupy the same 2porbital RESULTING in increased electronelectron repulsion.
On the other hand, N has stable half filled configuration, while F has greater nuclear charge.
Therefore, O has ionization enthalpy less than N as well of F.
`N (Z = 7) [He] 2s^(2) 2p_(x)^(1) 2p_(y)^(1)2p_(z)^(1)` (Half filled subshell)
`O (Z = 8) [He] 2s^(2) 2p_(x)^(2) 2p_(y)^(1) 2p_(z)^(1)` (one) 2p) has two electron)
In nitrogen, unpair electrons present in outermost orbital. (According to Hund.s law)
But, in oxygen having four electrons in 2p orbitals they PAIRED so electron-electron repulsion increases.
So, electron of oxygen is easily removed than electron of nitrogen. So, ionisation enthalpy of nitrogen is higher than oxygen.
Discussion
20.

Amongthe secondperiodelements the actualionizationenergiesare in theorder : Li lt B lt Be lt C lt O lt Nlt F lt Ne. Explainwhy (i)Be hashigher Delta_(i)H than B (ii)O haslowerDelta_(i)H than N and F ?

Answer»

Solution :(i) Theionizationenthalpyamong otherthingsdependsupon thetype ofelectronto beremovedfromthe sameprincipal shell. In CASEOF Be `(1 s^(2) 2 s^(2))` the outermostare morestrongly attractedby thenucleus than 2p- electron, thereforelesser amountof energyis required toknockout a 2p- electron than a 2S- electron . Consequently `Delta_(i) H` of Be ishigherthan that`Delta_(i)H` of B.
(ii)The electronicconfigurationof `N (1 s^(2) 2s^(2)2p_(x)^(1) 2p_(y)^(1) 2p_(Z)^(1))` in which2p-orbitalsare exactlyhalf- FILLED ismore stablethan theelectronicconfigurationof `O(1 s^(2) 2s^(2)2p_(x)^(2) 2p_(y)^(1) 2p_(z)^(1))` in which a the 2p-orbitals are neitherexactlyhalf - fillednorcompletelyfilled. Thereforeit isdifficult to remove anelectron from N than fromO. As aresult `Delta_(i)H` of N ishigherthan thatof O. Furtherthe electronic configurationof F is `1 s^(2)2s^(2)2p_(x)^(2) 2p_(y)^(2) 2p_(z)^(1)`. Because ofhighernuclearcharge (+9)the first ionizationof stabilityof F ishigher thanthat of O. Further, theeffectof increasednuclearcharge outweightseffectof stabilitydueto exactlyhalf -filledorbitalsthereforethe `Delta_(i) H` of N and Oare lowerthan thatof F.
Discussion
21.

Among the radioactive elements tritium is used as better tracer because

Answer»

it is cheaply AVAILABLE
it emits low ENERGY b-rays
it does not emit g-rays
all the above

Answer :D
Discussion
22.

Among the properties (i) reducing (ii) oxidising (iii) complexing the set of properties shown by CN - ion towards metal species is :

Answer»

i,II,iii
ii,iii
iii,i
i,ii

Solution :`CN^(-)` in `K_(4)[Fe(Cunderset(=)(N))_6]` acts as LIGAND and reducing AGENT .
Discussion
23.

Among the paraffins it is generally found that with an increase in the molecular weight

Answer»

the freezing POINT decreases
the BOILING point decreases
the boiling point increases
the VAPOUR DENSITY decreases

Answer :C
Discussion
24.

Among the oxides of nitrogen, a brown coloured gas is

Answer»

`NO_2`
`NO`
`N_2O`
`N_2O_5`

SOLUTION :`NO_2`
Discussion
25.

Among the molecules SO_(2), SF_(4), ClF_(3), BrF_(5)and XeF_(4) which of the following shapedoes not decribe any of these molecules ?

Answer»

Bent
Trigonal bipyramidal
SEE -SAW
T-shape

Solution :`SO_(2) ` bent, `SF_(4)` = see -saw,` CLF_(3)` = T-shape, `BrF_(5)`
= square pyramidal , `XeF_(4)` = sequare planar.
Discussion
26.

Among the mixutre (i) 50 ml of N//10 HCl + 50 ml of N//10 NaOH (ii) 55 ml of N//10 HCl + 45 ml of N//10 NaOH (iii) 75 ml of N//10 HCl + 25 ml of N//10 NaOH (iv) 30 ml of N//5 HCl + 70 ml of N//5 NaOH For how many of the above mixutres pH lies between 1 to 7

Answer»


SOLUTION :N//A
Discussion
27.

Among the metals, Fe, Zn, Pb, Ag and Pt which do not give a metal nitrate on treatment with concentrated HNO_(3)

Answer»

Fe and Zn
Fe and Pt
Pb, Ag and Pt
Fe, Ag and Pt

Solution :When iron is treated with conc. `HNO_(3)`, it BECOMES PASSIVE DUE to the formation of a protective layer of `FeO.Fe_(2)O_(3)` on its surface. Pt, on the other hand, being a noble metal does not react with conc. `HNO_(3)`.
Discussion
28.

Among the metals Cr, Fe, Mn , Ti , Ba and Mg the one that cannot be obtained by reduction of metal oxide by aluminium is

Answer»

Cr
Fe
Mn
Mg

Solution :N//A
Discussion
29.

Among the III A group elements, the difference in the atomic radius is large in between

Answer»

ALUMINIUM and Boron
Gallium and Aluminium
Thallium and Indium
Gallium and Indium

Answer :A
Discussion
30.

Among the hydrides of Group 15 elements, which have the (a) lowest boiling point ? (b) maximum basic character ? (c) highest bond angle ? (d) maximum reducing character ?

Answer»

SOLUTION :(a) `NH_(3)` (B) `NH_(3)` (c) `NH_(3)` (d) `BiH_(3)`.
Discussion
31.

Amongthe halogensthe elementhavingthe mostnegative electron gainenthalpy is………..

Answer»

SOLUTION :CHLORINE
Discussion
32.

Among the halides of Al, the one with maximum solubility in water is-

Answer»

`AlF_(3)`
`AlCl_(3)`
`AlBr_(3)`
`AH_(3)`

ANSWER :A
Discussion
33.

Among the halides(a) BF_(3)(b)BCl_(3)(c ) BBr_(3)(d) BI_(3)The order of decreasing Lewis acid character is

Answer»

a,B,c,d
d,c,b,a
c,d,b,a
b,c,d,a

SOLUTION :Order of LEWIS acid character `BI_(2) gt "BBr"_3 gt BCI_(3) gt BF_3`
due to ` p PI - p pi`back bonding
Discussion
34.

Among the halides(a) BCl_(3)(b)AlCl_(3)(c ) GaCl_(3) (d)InCl_(3) The order of decreasing Lewis acid character is

Answer»

a,b,c,d
d,c,b,a
b,d,a,c
b,c,d,a

Solution :Because of its ATOMIC SIZE.
Discussion
35.

Among the halides

Answer»

`1,2,3,4`
`2,3,4,1`
`3,4,2,1`
`4,3,2,1`

Solution :The ACIDIC character of CHLORIDES increases down the group `BCl_(3)` is weak acid to show `ppi-ppi` BACK BONDING.
Discussion
36.

Among the given sets, which represents the resonating structure?

Answer»

`H-C=OVERSET(o+)N-overset(THETA)underset(..)O:and H-overset(..)underset(..)O-C-=N:`
`H-overset(o+)underset(..)O=C=overset(Theta)overset(..)N:and H-overset(..)underset(..)O-C-=N:`
`H-C=overset(o+)N-overset(Theta)underset(..)O:andH-overset(O)overset(||)C-overset(..)N:`
`H-overset(..)underset(..)O-C-=overset(Theta)N and H-overset(..)N=C=overset(..)O:`

Answer :B
Discussion
37.

Among the given sets, how many of the following not represents the resonating structure :

Answer»


ANSWER :4(I, III, IV, VII)
Discussion
38.

Among the given compounds, the most susceptible to nucleophilic attack at the carbonyl group is

Answer»

`MeCOCl`
`MECHO`
`MeCOOMe`
`MeCOOCOMe`

SOLUTION :Out of the options GIVEN, ACID chloride `MeCOCl` (A) is most susceptible to NUCLEOPHILIC attack
Discussion
39.

Among the given compounds, identify aromatic, anti-aromatic and non-aromatic molecules.

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ANSWER :Aromatic compounds - (b), ( c), (g), (h) and (n).
Anti-aromatic compounds- (a), (F), (J) and (o).
Non-aromatic compounds-(d), ( e), (i), (k) and (m).
Discussion
40.

Among the given cations, the most stable carbonium ion is….

Answer»

SEC. butyl
tert.butyl
n-butyl
isobutyl

Answer :B
Discussion
41.

Among the given cations , the most stable carbonium ion is

Answer»

sec-butyl
tert-butyl
n-butyl
none of these

ANSWER :B
Discussion
42.

Among the gases (i) – (v), the gases that cause greenhouse effect are : (i) CO_2(ii) H_2 O(iii) CFC(iv) O_2(v) O_3

Answer»

i, II, iii, and iv
i, iii, iv and v
i and iv
i, ii, iii and v

Solution :`CO_2 , O_3 , H_2 O` VAPOURS and CFC.s are green HOUSE GASES.
Discussion
43.

Among the following which shows the maximum covalent character?

Answer»

1) `MgCl_(2)`
2) `FeCl_(2)`
3) `SnCl_(2)`
4) `AlCl_(3)`

Solution :`AlCl_(2)`
Discussion
44.

Among the following, which one is mostly present in sea water ?

Answer»

NaCl
NaI
KCl
`MG Br _(2)`

ANSWER :A
Discussion
45.

Among the following which one is more reactive in hydrogenation

Answer»

1-Butene
isobutene
Cis-2-butene
Trans-2-Butene

Solution :EASY of hydrogenation `PROP` HEAT of hydrogenation `prop (1)/("stability of alkene")`
Discussion
46.

Among the following , which one is a wrongstatement ?

Answer»

`PH_(5) and BiCl_(5)` do not EXIST
` p pi-dpi` bonds are present in `SO_(2)`
`SeF_(4) and CH_(4)` have same shape
`I_(3)^(-)` has bent geometry .

Solution :`(a) PH_(5)` does not exist whereas `PCl_(5) and PF_(5)` exist
This is because Cl and F have p-orbitals to overlap
with d-orbitals of P but H does not have p-orbitals .
Again `BiCl_(3)` exists but `BiCl_(3)` does not due to INERT
paireffect
(b) ` p pi - d pi` bonds are present in `SO_(2)`
(c) `SeF_(4) = sp^(3) d, lp = 1 ` shape = see-saw
` CH_(4) = sp^(3) , lp = 0` , shape = tetrahedral
(d) ` I_(3)^(+) = sp^(3), lp = 2 `shape = bent/angular.
Discussion
47.

Among the following which one is having conjugated system :

Answer»




ANSWER :B::D
Discussion
48.

Among the following which one is a wrong statement ?

Answer»

`SeF_(4)` and `CH_(4)` have same shape
`I_(3)^(+)` has bent GEOMETRY
`PH_(5)` and `BiCl_(5)` do not exist
`p pi - d pi` bonds are present in `SO_(2)`

Solution :(A) `SeF_(4)-sp^(3)d, Ip = 1`, shape = see - saw
`CH_(4)-sp^(3), Ip=0`, shape = TETRAHEDRAL
(B) `I_(3)^(+)-sp^(3), Ip=2`, shape = bent / anglar
(C ) `PH_(5)=` d-orbital contraction absent
`BiCl_(5)=` due to inert pair EFFECT
(`Bi^(+5)` act as `OA, Cl^(-)` act as RA)
(D)`SO_(2):O=S=O`
`P pi-d pi, P pi - P pi`both type bonds are present
Discussion
49.

Among thefollowingwhich onehas thehighcation toanionsize ratio ?

Answer»

`CsI `
`CsF`
`LiF`
`NaF`

SOLUTION :Amongstalkali metalscations(i.e., `Cs^(+)Li^(+),Na^(+)`)
`Cs^(+)` has thelargestsize andamonghalidesi.e., `F^(-) ,I^(-) F^(-)` has thesmallestsize .Thereforeratio of`Cs^(+)`and `F^(-)` is thehighest i.e.,option(B) is CORRECT .
Discussion
50.

Among the following which one has bond order as 3?

Answer»

`N_(2)`
`O_(2)`
HCHO
`OVERSET(.)CH_(4)`

Solution :`N_(2)`
Discussion