Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

CH_3 - C -= C-CH_3 underset(Pd-BaSO_4)overset(H_2)to (A) underset(Ni)overset(D_2)to(B), Product (B) of above reaction is

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SOLUTION :
2.

CH_3-C -=C-CH_3 underset("Catalyst")overset(H_2-"Lindlar's")to A underset("addition")overset(Br_2)B CH_3 - C -= C CH_3 underset("addition")overset(Br_2)to C overset(H_2-Ni)to D

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B is RACEMIC mixture ` underset(+ HG^(2+))overset(Dil. H_2SO_4)to`
D is a meso compound
A is alkene `underset("2)" H_2O_2// OH^(-))overset("1)" BH_3// THF)to `
C is trans-1,2-dibromoethane

Solution :`H_3C -C -= C - CH_3 underset("Lindlars catalyst ") overset(H_2)to`
3.

CH_3 - C -= C-CH_3 overset("Cold",KMnO_4)to AProduct A is

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`CH_3-CH_2-UNDERSET(O)underset(||)-underset(O)underset(||)C-H`
`CH_3-underset(O)underset(||)C-underset(O)underset(||)C-CH_3`
`CH_3-overset(OH)overset(|)CH-overset(OH)overset(|)CH-CH_3`
`O= CH - CH_2-CH_2-CH=O`

SOLUTION :`CH_3 - C -= C-CH_3 overset(".COLD"KMnO_4)to CH_3 - underset(O)underset(||)C-underset(O)underset(||)C-CH_3`
4.

CH_(3) C -= C-CH_(3) (H_2)/(Ni) rarr P overset(KMnO_(4)//H^(+))rarr Q. Here Q is

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Alkane
Alkene
ALDEHYDE
CARBOXYLIC ACID

ANSWER :D
5.

CH_3 - C -=C-CH_2CH_2CH_3 overset(BF_3 // C Cl_4)to x. The correct statement is/are

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TOTAL four products are OBTAINED
TWO enanthomeric pairs are formed
Cyclic halenum ion intermediate is involved
The rate of FORMATION of y is greater than the rate of formation of x

Solution :Alkynes properties
6.

In the reaction CH_3-Br+2Na+Br-CH_3 to , the reaction is called

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SUBSTITUTION
Addition
ELIMINATION
REARRANGEMENT

Solution :BROMINE atom is SUBSTITUTED by amino group
7.

CH_(2)=underset((I))(CH)-CH=CH-CH_(3) is more stable than CH_(3)-underset((II))(CH=C)=CH-CH_(3) because

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there is RESONANCE in I but not in II
there is TAUTOMERISM in I but not in II
there is HYPERCONJUGATION in I but not in II
II has more canonical STRUCTURES than I.

Answer :A
8.

CH_2Ounderset(H_3O^(o+))overset(CHD_2MgI)toX underset(Delta)overset(Conc.H_2SO_4)toY In the above reaction compound X & Y respectively will be

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`oversetoverset(OH)(|)CHD-CH_2-OH,CHO-CHO`
`CHD_2-CH_2-OH, CHO-CHO`
`CHD_2-CH_2-OH, CD_2=CH_2`
`undersetunderset(OH)(|)CHD-CH_2-OH,CD_2=CD_2`

SOLUTION :
9.

CH_(2)I_(2) is a ________halide .

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VICINAL
secondary
geminal
VINYL

ANSWER :C
10.

CH_2=CHOH rarr CH_3- overset(O)overset(||)C-H The above reaction is classified as _______ reaction.

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SUBSTITUTION
Addition
Elimination
REARRANGEMENT

SOLUTION :Involves rearrangement of double bond and hydrogen atom.
11.

CH_(2)=CH_(2) underset(KOH//H_(2)O)overset(KMnO_(4))rarr X. Product 'X' in above reaction is

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ETHYLENE glycol
Glucose
Ethanol
All of these

Answer :A
12.

CH_(2)=CH_(2)+O_(3)underset(H_(2)O)overset(Zn)rarrXoverset("Reduction")rarrY.Y is

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`CH_(4)`
`C_(2)H_(5)OH`
`CH_(3)OH`
`HCOH`

Answer :C
13.

CH_(2)=CH_(2)+H_(2)overset(pt,T_(1)K)toC_(2)H_(6) CH_(2)=CH_(2)+H_(2)overset(Ni,T_(2)K)toC_(2)H_(6) the correct relation among the following is

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`T_(1) gt T_(2)`
`T_(2) gt T_(1)`
`T=T_(2)`
`T_(1) gt 2T_(2)`

SOLUTION :PLATINUM is strong RA
14.

CH_(2)=CH_(2)+H_(2)overset(Pt,T_(1)K)rarrC_(2)H_(6) CH_(2)=CH_(2)+H_(2)overset(Ni,T_(2)K)rarrC_(2)H_(6) The correct relation among the following is

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`T_(1)gtT_(2)`
`T_(2)gtT_(1)`
`T=T_(2)`
`T_(1)gt2T_(2)`

ANSWER :B
15.

CH_(2)=CH_(2)+Br_(2)overset(C Cl_(4))rarrXoverset("aq KOH")rarrZ.Z is

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Ethane
Glycol
Ethene
Ethanol

Answer :B
16.

CH_(2)=CH-underset(CH_(2)CH_(3))underset(|)(CH)-underset(Cl)underset(|)C=CH_(2) The IUPAC name of thiscompound is ............. .

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SOLUTION :2-chloro-3-ethyl-1, 4-pentadiene
17.

CH_(2)=CH^(-) is more basic than HC -= C^(-). Explain why ?

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Solution :`CH_(2) = overset(sp^(2))(C)H^(-) "" HC -= overset(sp)(C^(-))`
Since, sp-CARBON is more electronegative than `sp^(2)`-carbon, therefore, `CH -= C^(-)` is less willing to DONATE a pair of electrons than `H_(2)C = CH^(-)`. In other words, `H_(2)C = CH^(-)` is more basic than `HC -= C^(-)`.
18.

CH_(2)=CH^(-) is a better nucleophile than HC -= C^(-). Explain.

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Solution :In `H_(2)C = CH^(-)`, the carbon atom carrying the -ve CHARGE is `SP^(2)` HYBRIDIZED while in `HC -= C^(-)`, the carbon atom carrying the -ve charge is sp-hybridized. Since a `sp^(2)`-hybridized carbon is less electronegative than a sp-hybridized carbon, THEREFORE, `H_(2)C = CH^(-)` is a better nucleophile than `HC -= C^(-)`.
19.

CH_2=CH-CH_3overset(NOCl)toX , X is :

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`undersetunderset(CL)(|)CH_2-undersetunderset(NO)(|)CH-CH_3`
`undersetunderset(NO)(|)CH_2-undersetunderset(Cl)(|)CH-CH_3`
`ON-CH_2-CH_2-CH_2-Cl`
`ON-undersetunderset(Cl)(|)CH-CH_2-CH_3`

ANSWER :B
20.

CH_(2)Br-CH_(2)Brunderset("KOH")overset("Alcoholic")rarrX Xoverset(NaNH_(2),Delta)rarr Acetylene. Here X is

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VINYL bromide
1,1-Dibromoethane
ETHYL bromide
Ethylene DIBROMIDE

ANSWER :A
21.

CH_2Br–CH_2-CH_2Br is a vicinal dihalide. True/False

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ANSWER :F
22.

CH_(2)Br-CH_(2)Broverset(Zn,Delta)toAoverset(H_(2)//Ni)toBoverset(HNO_(3)//450^(@)C)toC Here 'C' is

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`CH_(3)NO_(2)`
`C_(2)H_(5)NO_(2)`
`C_(2)H_(5)-O-N=O`
`CH_(3)-O-N=O`

Answer :B
23.

CH_(2) = overset (-) (C) His more basic thenHC -= C^(-) . Explain why ?

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Solution :` CH_(2) = overset (SP^(2))CH^(-) "" HC -= overset (sp) (C)""^(-)`
`square ` Since sp carbon is more electronegativethen ` sp^(2)` carbon .
` squarethereforeCH -= overset (-) C ` is LESS interested in donating a PAIR of electrons then` CH_(2) -= overset (-) (C)H ` .
24.

CH_(2) is an

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ELECTROPHILE
Nucleophile
Free RADICAL
Ambiphiles

SOLUTION :N/A
25.

CH_2 = CHClreacts with HCl to form

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A)`CH_2Cl - CH_2Cl`
`B)CH_3 - CHCl_2`
C)`CH_2 = CHCL . HCl`
D)none of these

Answer :B
26.

CH_2 = CH_2 overset(Br_2 , NaCl(Aq))to In the above reaction which one of the following products is not possible?

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`overset(BR)overset(|)CH_2 - underset(Br)underset(|)CH_2`
`overset(Br)overset(|)CH_2 - underset(OH)underset(|)CH_2`
`overset(CL)overset(|)CH_2- underset(Br)underset(|)CH_2`
`overset(Cl)overset(|)CH_2 - underset(OH)underset(|)CH_2`

SOLUTION :
27.

CH_2=CH_2+O_(2)overset(" onestepoxidation")underset("metal ions")rarrunderset("90%yied")(CH_3CHO)Oxidation states of metal ions used

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`+ 2, + 4`
`+ 2, + 2 `
`- 2, - 3`
`+ 2, - 3`

ANSWER :D
28.

CH_2= CH-CH=CH_2 overset(Br_2// C Cl_4)to Product. The major product is :

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`Br-CH_2 - CH= CH-CH_2 - C Cl_3`
`CH_2 = CH-underset(Br)underset(|)CH-CH_2- C Cl_3`
`CH_2 = CH-underset(C Cl_3)underset(|)CH-CH_2-Br`
none is CORRECT

SOLUTION :`1,4` ADDITION to dienes
`CH_2 = CH - CH = CH_2 overset( C Cl_3Br)to Br - CH_2 - CH = CH - CH_2 -C Cl_3`
29.

CH_2 = CH-CH_3 overset(Cl_2 500^(@) C)to 'A' the major product . 'A' is formed through

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ELECTROPHILIC addition
electrophilic SUBSTITUTION
FREE RADICAL addition
free radical substitution

Solution :Free radical substitution.
30.

CH_2 = CH - CH = underset(CH_3)underset(|)C-CH_3 overset(+HBr)to CH_3-overset(Br)overset(|)CH-CH = underset(CH_3)underset(|)C-CH_3 + underset((II))(CH_3 - CH ) = CH - underset(CH_3)underset(|)overset(Br)overset(|)C-CH_3 Correct statement about the above reaction is

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'I' is kinetic CONTROLLED PRODUCT
'II' is thermodynamic controlled product
I' is major product at low TEMPERATURE
'II' is major product at low temperature

Solution :
Product from more stable intermediate is CALLED kinetic controlled and it is the major product at low temperature. More stable product is called thermodynamic controlled product and it is the major product at HIGH temperature.
31.

CH_(2)=CH-CH=CH-CH=CH-CH_(3) How many geometrical isomers of this compound are possible?

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2
3
4
8

Solution :GEOMETRICAL isomers are POSSIBLE for DOUBLE bonds at `C_3, C_5` only . `2^2= 4`
32.

CH_2 = CH- CH= CH_2 overset(HBr( 1 " mole"))to major product

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`CH_3-OVERSET(Br)overset(|)CH-CH=CH_2`
`CH_3-CH=CH-CH_2Br`
`H_2C - UNDERSET(Br)underset(|)CH_2-CH=CH_2`
NONE of these

Solution :`CH_2 = CH - CH = CH_2+ HBR to CH_3 - CH = CH- CH_2Br`
33.

CH_2 = C=CH_2 underset((2) H^(oplus))overset((1) Na// NH_3(l))to (P) underset("(Fe) tube")overset("Red hot ")to (Q) Compound 'P' can give white ppt with ammonical silver nitrate, and compound 'Q' is thermodynamically more stable among its position isomers, now maximum number of atoms in "Q" that are in one plane in any possible conformation are x, then find x – 3y? Where 'y' is number of position isomers of (Q)

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SOLUTION :
So = x-3y = 15-3 `XX` 2 = 9
34.

CH_2 = CH - C -= CH overset(HCl)to . The major product is

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`CH_3-underset(CL)underset(|)CH-C -=CH`
`Cl-CH_2 - CH_2 -C -=CH`
`CH_2 = CH-underset(C)underset(|)C=CH_2`
`CH_2=CH-CH=CH-Cl`

Solution :ALKENES are more REACTIVE than ALKINES except hydrogenation .
35.

CH-= CH underset(NH_4Cl)overset(Cu_2 Cl_2)to A underset(Pd//BaSO_4)overset(H_2)to B ?What isB?

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`C_2H_5Cl_2`
`C_2H_4`
`CH_2 = CH-CH = CH_2`
`C_2H_6`

SOLUTION :`2HC -= CH UNDERSET(NH_4Cl)OVERSET(CuCl_2)to underset("VINYL ACETYLENE")(HC-=C-CH = CH_2)underset(Pd//BaSO_4)overset(H_2)to CH_2 = CH - CH = CH_2`
36.

CH -= CH underset(Cl_2)overset("excess")to the product is commercially known as

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WESTRON
WESTROSOL
Lewisite
Marsh gas

SOLUTION :Direct REACTION
37.

CH-=CH overset(O_3)to X overset(Zn//CH_3OH)to Y, Y is

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`CH_2OH-CH_2OH`
`CH_3COOH`
`C_2H_5OH`
`CH_3-CH_3`

SOLUTION :`CH-=CH OVERSET(O_3)to OHC-CHO UNDERSET"(REDUCTION)"overset(Zn//CH_3OH)to underset"Ethane-1,2 -DIOL"(HOCH_2-CH_2OH)`
38.

CH-=CH+HBr rarr X, product X is

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Ethylene bromide
VINYL bromide
Bromo ethane
Ethyledine bromide

Solution :`underset("Acetylene")(CH-=CH+)HBr RARR underset("Vinyl bromide")(CH_(2)=CHBR)`
39.

CH -=CH + 2CH_3COOH underset("2)"300-400^(@)C)overset("1)"Hg^(+2))toproducts is /are

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`CH_3-CH(OCOCH_3)_2`
`CH_3CHO`
`CH_3-OVERSET(O)overset(||)C-O-CH_3`
`CH_3-overset(O)overset(||)C-O-overset(O)overset(||)C-CH_3`

SOLUTION :
40.

CFC'sare effective scavengers for ozone due to

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Photolytic REACTION of `O_(2)` producing CL racidcals
Photolytic DECOMPOSITION of `O_(3)` producing `O_(2)`
Photolytic decomposition of CFC's producing Cl radicals
None of these

Answer :C
41.

CFCl_3 is responsible for the decomposition of ozone to oxygen. Which of the following reacts with ozone to form oxygen>

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`Cl_2`
`CL^(-)`
`F^(-)`
`Cl^(**)`

ANSWER :D
42.

CFC are used extensively, It is because

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They are reactive
They are liquids
They are gases
They are CHEAP and stable

Answer :D
43.

Cetyl trimethyl ammonium bromide is a popular

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ANIONIC detergent<BR>cationic detergent
non-ionic detergent
sweeterner

Solution :Cetyl trimethyl AMMONIUM bromide, `(CH_(3))(CH_(2))_(15)(CH_(3))N^(+)Br^(-)` is a cationic detergent.
44.

Certain weak acid has P^(ka) = 4. Find pH of 0.01M NaA(ag)

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SOLUTION :`pH =(1)/(2) (PK_W +PK_a+log C) `
` = (1)/(2)(14+ 4 + log 10 ^(_2)) = (1)/(2)(16) =8`
45.

Certain volume of oxygen gas undergoes effusion in 15 min. Under similar conditions, what is the time required for the effusion of same volume of chlorine gas?

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ANSWER :22.34min
46.

Certain volume of a gas exerts on its walls some pressure at a particular temperature . It has been found that by reducing the volume of the gas to half of its original value the pressure become twice that of the initial value at constant temperature . this happensbecause

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mass of the gas INCREASES with PRESSURE
speed of the gas MOLECULES decreases
more number of gas molecules strike the surface per second
gas molecules attract each other .

ANSWER :C
47.

Certain thin walled glass bottles generally withstand a pressure difference across their walls of 1.25 atm before they bursts A typical such bottlle is sealed on a day when the temperature is 68^(@) F and the pressure is 0.08atm and it is immediately heated in an oven Estimate the temperature in degress fahrenheit at which it will explode .

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ANSWER :`245.95 F`
48.

Certain metals have a tendency to form compounds which have a "comple structure" and are known as complex. M is a metal with such tendencies and is forming compound like [M(NH_(3))_(5)Br[Br_(2). If it is known that solution of these furnish only those ions which are outside the co-ordination sphere "[ ]" (the bracketed part), then calculate the weight (in g) of AgBr ppt obtained when 1000 g solution of the complex compound containing40 % by wt. of the complex compound is reacted with 1000 g solution of AgNO_(3) containing 17 % AgNO_(3) by weight. [Atomic weight of M = 75]

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ANSWER :188
49.

Certain mass of potassium chlorate is thermally decomposed and 3.36 L of O_(2) is collected at STP. What will be the weight of the residue in the experiment?

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Solution :Potassium chlorate on decomposition given potassium CHLORIDE and OXYGEN.
`2KCl O_(3) to 2KCl+3O_(2)`
3 moles of `O_(2)-="2 moles of "KCl`
`(3 xx 22.4)"L of O"_(2) at STP=(2 xx 74.5)` grams of KCl
The WEIGHT of RESIDUE (KCl) OBTAINED when 3.36L of `O_(2)` is collected at STP= `(3.36)/(3 xx 22.4) xx 2 xx 74.5 =7.45"grams"`
50.

Certain mass of oxygen exerts a pressure of 'P' atm in a vessel of volume 'V' at 25^@C. In the same vessel what be the pressure of gas at 25 K ?

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Solution :GAY = lussac.slawis givenas ` (P_1)/(P_2) = (T_1)/(T_2)`
` {:(P_1 =P atm,T_1 = 298 K),( P_2 =? ,T_2 =25 K):}`
Pressure of the GAS at 25K =
`P_2= (P_1 T_2)/(T_1) = (P xx 25 )/( 298) = 0.084P atm`