This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Gases best follow the facts given below A) An ideal gas obeys the mathematical relation PV=nRT B) Rates of diffusion of two gases are in the reciprocal ratio of square roots of their molecular weight C) Total pressure of a mixture of non reacting gases is given by the algebric sum of their partial pressure An ideal gas is captured in a glass tube of uniform arca of cross section by awater column at a given temperature as shown If the tube is held vertical, by what length the water column descends down? (Density of mercury=13.6gm/cc) (P_(atm)=76cm of Hg) |
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Answer» 2.2 cm `27.2 xx 1 = h_2 xx 13.6 implies h_2 = 2 cm` When HELD vertical , `P_("gas") = P_("atm") + 2 cm of Hg` `= 76+ 2` `= 78 cm of Hg`. `P_1 V_1= P_2V_2 = > 76 xx 40 xx A = 78 xx l xx A` `implies l = 38.97 implies "DESCENT" = 40 - 38.97` `= 1.03 cm`. |
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| 2. |
Gaseous molecules heavy (e.g Br_(2)) or light (H_(2)) in equal number occupy the same volume at same P and T The distance between molcules in a definite volume is much larger than the actual dimension of molecule . |
| Answer» Solution :Statement REPRESENT AVOGADRO's law which is JUSTIFIED by the EXPLANTION . | |
| 3. |
Ground state electronic configuration of p atom can be represented as |
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Answer» `UARR DARR uarr darr uarr uarr uarr` |
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| 4. |
Gaseous elements are monotomic or diatomicComment. |
| Answer» Solution :NOBLE GASES are monoatomic . Elementary gases are diatomic. However , One GASEOUS element is even available as TRIATOMIC, `O_(3)`. | |
| 5. |
Gaseous benzene reacts with hydrogen gas in presence of a nickel catalyst to form gaseous cyclohenane according to the reaction C_(6) H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g) A mixture of C_(6)H_(6) and excess H_(2)has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C_(6)H_(6) (by volume) present in the original volume is |
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Answer» `1//3` Initial pressure = 60 mm Final pressure = 30 mm since `p PROP n` `:.` Initial pressure of 60 mm is because of 4 moles and hence pressure due to one mole = 15 mm Now if `x` is fraction of `C_(6)H_(6)` which combines then for the REACTION `{:(C_(6)H_(6),+,3H_(2) rarr,C_(6) H_(12)),(15 - x,,45 - 3X,x):}` |
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| 7. |
Gas released during Bhopal tragedy was |
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Answer» Methyl isocyanate |
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| 8. |
……gas produce in Duman method but …….gas produce in Kjeldahl's method |
| Answer» SOLUTION :`N_(2), NH_(3)` | |
| 9. |
Name the gas law which gives the relationship between the pressure and temperature of a fixed amount of gas at a constant volume. |
| Answer» SOLUTION :GAY Lussac.s LAW | |
| 10. |
Gas laws are relationship between the measurable properties of gases. Draw the graph to illustrate the relationship between temperature and pressure of a fixed amount of gas at constant volume. |
Answer» SOLUTION :
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| 12. |
Gas laws are relationship between the measurable properties of gases. A definite quantity of an ideal gas is confined in a container of constant volume. When the container is immersed in a bath of melting ice, the pressure of the gas is 800mm of Hg. Find the temperature when the gas pressure is 400mm of Hg. |
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Answer» SOLUTION :`p_1/T_1 = p_2/T_2` `p_1 = 800 `MM of Hg,`p_2` = 400 mm of Hg `T_1` = 273K,`T_2 = ? LT`Substituting we get 800/273 = `400/T_2` `800xxT_2` = `273xx400` `therefore T_2 = (273xx400)/800` = 136.5K = 136.5-273 = `-136.5^@C` |
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| 13. |
……gas is produce in Kjeldahl's method and absorbed in …….. |
| Answer» SOLUTION :`NH_(3), H_(2)SO_(4)` | |
| 14. |
Gas deviates from ideal gas bahaviour because molecules |
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Answer» are colourless |
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| 15. |
Gas equation PV=nRT is obeyed by |
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Answer» only ISOTHERMAL process |
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| 16. |
Gas commonly used in refrigirators is |
| Answer» Answer :C | |
| 17. |
Gas (A_(x)) has the ratio of molar specific heats equal to 1.66. The value of x will be _____ |
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Answer» |
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| 19. |
Gammaxene is .. . . Isomer of benzene hexa chloride. |
| Answer» Solution :`gamma`-FORM | |
| 20. |
Galvanishing of iron sheets is done by |
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Answer» CU PLATING |
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| 21. |
Gallium lies below aluminium in group 13 of the periodictablebut itsatomicradiusis smallerthan that ofaluminium. Why so ? |
| Answer» Solution :DUE to poorshielding of the valenceelectrons of GABY the inner 3d-electrons , the effectivenuclearcharge of GA is greaterin magnitudethan that of AL. As a result , the electronin gallium experience greaterforce of attractionby the NUCLEUS than in Aland hence atomic size of Ga (135pm)is slightly lessmuch higher than that of Al (143pm). | |
| 22. |
Gallium has muchhigher atomicnumberthan aluminium yet its atomicradius is lower thanthat of aluminium. Justify. |
| Answer» Solution :DUE to poorshielding of the valenceelectrons of Gaby the inner 3d-electrons , the effectivenuclearcharge of Ga is greaterin magnitudethan that of Al. As a RESULT , the electronin gallium experience greaterforce of attractionby the nucleus than in ALAND HENCE atomic size of Ga (135pm)is SLIGHTLY lessmuch higher than that of Al (143pm). | |
| 23. |
Gallium acts as reducing agent because |
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Answer» `GA^(3+)` state is less stable than `Ga^(+1)` |
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| 24. |
Gain of electron or electrons is termed |
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Answer» combustion |
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| 25. |
Gadoliniumbelongsto 4f series. Itsatomicnumberis 64.Which of thefollowingis the correctelectronicconfigurationof gadolinium ? |
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Answer» `[Xe] 4f^(9)5s^(1)` |
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| 26. |
[G] Match the salts in Column-I with the ratio of van't Hoff factor in Column-II : {:(,"Column-I",,"Column-II"),("(a)","Glucose, fructose, sucrose","(p)",1:2:3),("(b)","KCl,MgCl"_(2)",FeCl"_(3),"(q)",1:3:4),("(c)",K_(4)[Fe(CN)_(6)],Na_(3)PO_(4)","Al_(2)(SO_(4))_(3),"(r)",2:3:4),("(d)","Urea, KCl, CaCl"_(2),"(s)",1:1:1):} [Note : Assume that the electrolytes are completely ionised. |
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Answer» |
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| 28. |
(G) is NaHCO_(3) The other compound formed with (G) is |
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Answer» `NH_(4)C_(1)` `2NaHCO_(3) overset(triangle)rarrNa_(2)CO_(3)+H_(2)O+CO_(2)` |
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| 29. |
Fusion of AgCl with Na_(2)CO_(3) gives: |
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Answer» `Ag_(2)CO_(3)` |
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| 30. |
Fusion bomb involves |
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Answer» Combinations of lighter nuclei into BIGGER nucleus |
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| 31. |
Fusel oil is a mixture of |
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Answer» Ethers |
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| 33. |
Functional isomer of carboxylic acid is |
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Answer» Amide |
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| 34. |
The function of anhydrous AlCl_(3) in the Friedel-Crafts reaction is to |
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Answer» To ABSORB water |
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| 35. |
Fullerene has 12 rings of 6 memberes and 20 rings of 5 memberes |
| Answer» SOLUTION :FALSE STATEMENT | |
| 36. |
Fuel gas with highest calorific value among the following |
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Answer» COAL GAS |
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| 37. |
Froth floatation process is used for the concentration of |
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Answer» OXIDE ores |
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| 38. |
Fronm where does ozone come in the photochemical smog? |
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Answer» Solution :(i) Photochemical smog is formed by the combination of smoke, DUST and FOG with air pollutants in the presence of sunlight. (ii) Chemically it is oxidising in nature because of high concentration of oxidising agents such as` N_(3)` and `O_(3)` So it is ALSO called oxidising smog. (iii) Photochemical smog is formed by following reactions: `N_(2) + O_(2) rarr 2NO` `2NO + O_(2) rarr 2NO_(2)` `NO_(2) overset("sunlight")rarr NO+(O)` `(O)_(3)NO rarr NO_(2) + O_(2)` `NO_(2) overset("sunlight") rarr NO + (O)` (iv) NO and `O_(3)` are strong oxidising agents and they can REACT with unburnt hydrocarbons in polluted air to FORM formaldehyde, acrolein and PAN. |
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| 39. |
From which source maximum hydrogen is obtained ? |
| Answer» SOLUTION :MAXIMUM HYDROGEN is OBTAINED from PETROCHEMICAL. | |
| 40. |
From which reaction H_(2)O_(2) act as reducing agent? |
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Answer» `Ag_(2)O+H_(2)O_(2)to2Ag+H_(2)O+O_(2)` |
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| 41. |
From which one of the following both ethylene and acetylene could be prepared in a single step reaction ? |
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Answer» `CH_3CH_2OH` `BrCH_2-CH_2Br overset(NaNH_2 "in LIQ."NH_3)to HC-=CH` |
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| 42. |
From which of the places the boiling point will be less ? Why sea and mountain ? |
| Answer» SOLUTION :At HIGH altitudes atmospheric pressure is low therefore liquids at high altitudes BOIL at LOWER temperatures in comparison to that at sea level. | |
| 43. |
From which of the following having maximum and minimum vapour pressure ? Acetone, ether and ethanol ? |
| Answer» SOLUTION :Ether having MAXIMUM vapour pressure and ETHANOL having MINIMUM vapour pressure. | |
| 44. |
From which industry phenol waste produced ? |
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Answer» Sugar |
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| 45. |
From which harmful effect ozone layer protects all living being ? |
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Answer» Ultraviolet radiations COMING from sunlight. |
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| 46. |
From which industry aromatic organic compound are produced ? |
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Answer» Dairy |
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| 47. |
From where does ozone come in the photo-chemical smog ? |
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Answer» Solution :Sunlight cause photochemical decomposition of `NO_2` into NO and O. `NO_2 overset(hv)to NO + [O]` Atomic OXYGEN is a HIGHLY reactive species. It combines with diatomic oxygen and forms ozone. `O_2 + O + M to O_3 + M` Where, M is inert GAS such as NITROGEN. This `O_3` is FORMED during the formation of smog. |
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| 48. |
From where ozone come in the photochemical smog? |
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Answer» Solution :(i) Photochemical smog is formed by the combination of SMOKE, dust and fog with air pollutants in the presence of sunlight. (ii) Chemically it is oxidising in nature because of high concentration of oxidising agents such as `NO_(2) and O_(3)`. So it is also called oxidising smog. (iii) Photochemical smog is formed by following reactions: `N_(2) + O_(2) rarr 2NO` `2NO + O_(2) rarr 2NO_(2)` `NO_(2) overset("sunlight")rarr NO + (O)` `(O) + O_(2) rarr O_(3)` `O_(3) + NO rarr NO_(2) + O_(2)` `NO_(2) overset("sunlight")rarr NO + (O)` (iv) No and `O_(3)` are strong oxidising agents and they can REACT with unburnt HYDROCARBONS in polluted air to FORM formaldehyde, acrolein and PAN. |
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| 49. |
From where the biodegradeble wastes are generated ? |
| Answer» Solution :Biodegradable WASTES are GENERATED by cotton mills, FOOD processing units, paper mills, and textile FACTORIES. | |