Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.	Match Column-I with Column-II
Answer» A-P, B-Q, C-R A-Q, B-R, C-P A-R, B-P, C-Q A-R, B-Q,C-P Answer :C

2.	Match Column (I) with Column (II).
Answer» Solution :(A)`DeltaG (DeltaG^ө)` is 0,reaction is in equilibrium: at this POINT, there is no longer any free ENERGY left to move the reaction. (B) If `DeltaG lt 0`,then K `gt` 1 which indicate a spontaneous reaction or the reaction which proceeds in the forward direction and the products are PRESENT mainly. (C) If `DeltaG gt 0` , then `Klt1`, which indicate a non spontaneous reaction or a reaction which proceeds in the forward direction to such a small DEGREE that only a very minute quantity of PRODUCT is formed.

3.	Match column-I with column-II:
Answer» (a-p), (B-q), (c-r), (d-s) (a-r), (b-q), (c-p), (d-q) (a-r), (b-q), (c-p), (d-s) (a-r), (b-p), (c-q), (d-s) ANSWER :B

4.	Match column-I with column-II:
Answer» (a-s), (B-r), (c-q), (d-p) (a-s), (b-r), (c-p), (d-q) (a-r), (b-s), (c-p), (d-q) (a-s), (b-q), (c-p), (d-r) ANSWER :B

5.	Match column-I with column-II:
Answer» (a-s), (b-r), (c-p), (d-q) (a-s), (b-r), (c-q), (d-p) (a-r), (b-s), (c-p), (d-q) (a-s), (b-p), (c-r), (d-q) ANSWER :A

6.	Match column-I with column-II:
Answer» (a-r), (b-p), (C-q) (a-q), (b-p), (c-r) (a-q), (b-r), (c-p) (a-q), (b-r), (c-s) ANSWER :C

7.	Match column-I with column-II:
Answer» (a-s), (b-r), (c-q), (d-p) (a-p), (b-r), (c-q), (d-s) (a-p), (b-q), (c-r), (d-s) (a-s), (b-r), (c-p), (d-q) ANSWER :A

8.	Match column-I with column-II:
Answer» (a-s), (b-p), (c-q), (d-r) (a-p), (b-q), (c-r), (d-s) (a-q), (b-r), (c-p), (d-s) (a-s), (b-p), (c-q), (d-r) ANSWER :A

9.	Match Column I with Column II.
Answer» Answer :(a)-(iii); (b)-(V); (c)-(i); (d)-(II); (e)-(IV)

10.	Match column I with column II.
Answer» SOLUTION :N//A

11.	Match Column-I with Column-II :
Answer» <P> ANSWER :A-Q ; B-S ; C-R,P ; D-Q,R

12.	Match Column I with Column II .
Answer» ANSWER :(i)-(B,C) ; (II)-(d) ; (III)-(a)

13.	Match column-I and column-II with correct relation.
Answer» SOLUTION :`(i-d), (ii-b), (iii-c), (iv-a)`

14.	Match column I and column II for the oxidation states of the central atoms.
Answer» SOLUTION :`A.to(4)""B.to(5)""C.to(3)""D.to(1)` Suppose that x be the oxidation states of CENTRAL atoms A. Oxidation number of CR in `Cr_(2)O_(7)^(2-)` `2x+7(-2)=-2` `2x-14=-2` `2x=+12` `x=+6` B. Oxidation number of MN in `MnO_(4)^(-)` `x+4(-2)=-1` `x-8=-1` `x=+7` C. Oxidation number of V in `VO_(3)^(-)` `x+3(-2)=-1` `x-6=-1` `x=+5` D. Oxidation number of Fe in `FeF_(6)^(3-)` `x+6(-1)=-3` `x-6=-3` `x=+3`

15.	Match column-A and column-B
Answer» (i-d), (ii-b), (iii-a), (iv-b) (i-e), (ii-d), (iii-C), (iv-d) (i-e), (ii-b), (iii-a), (iv-b) (i-d), (ii-e), (iii-a), (iv-b) ANSWER :C

16.	Match {:(,"Bond type",,"Bond length "(A^(@))),(A,C-H,1,1.09),(B,C-C,2,1.54),(C,C-N,3,1.47),(D,C-O,4,1.43):}
Answer» `{:(A,B,C,D),(1,2,3,4):}` `{:(A,B,C,D),(2,3,1,4):}` `{:(A,B,C,D),(3,2,1,4):}` `{:(A,B,C,D),(4,3,2,1):}` ANSWER :a

17.	Matc the following column-I with column-II .
Answer» ANSWER :A::B::C

18.	Mass ratio of Na_(2)SO_(3) and H_(2)O in Na_(2)SO_(3)*xH_(2)O is 1:1 thus the ratio of their mole number is-
Answer» `1:1` `1:3` `1:7` `7:1` ANSWER :C

19.	Mass proportion of H and O in H_(2)O is ..........
Answer» `1.008:16` `16:3.008` `1.008:8` `8:1.008` ANSWER :A::C

20.	Mass of one atom of an element is 6.66xx10^(-23) g. How many moles of element are there in 0.320 kg?
Answer» SOLUTION :MASS of one atom of an element = `6.66xx10^(-23)` g No. of MOLES =`("Mass")/("Molecular mass")` Molecular mass = Mass of 1 atom `XX` Avogadro number = `6.66xx10 ^(-23)xx 6.023xx10^(23) ` = 6.66`xx`6.023 =40.11318 Number of moles = `("Mass")/("Molecular mass") = (0.320 kgxx10^(3))/40` = `720/180 `= 8 moles

21.	Mass of one atom of an element is 6.645 xx 10^(-23) g. How many mole's of element are there in 0.320 kg?
Answer» Solution :Mass of 1 MOLE=`6.645xx10^(23)xx6.023xx10^(23)` =40g=1mole Number of MOLES=`("mass")/("atomic mass")` 0.320 kg contaims =`320/40` =8 MOL.

22.	Mass % of H in H_(2)O is ..........
Answer» 11.11 88.89 2 20 Solution : Molecular MASS of `H_(2)O = 18 g " mol"^(-1)` Mass % of `H=(2xx1xx100)/(18) = 11.11%`

23.	Mass of electron = 9.1 xx 10^(-3) kg. The kinetic energy of an electron is 4.55 xx 10^(-25)J. What is its wavelength (in nm) ?
Answer» 728 850 896 786 Answer :A

24.	Massof elements9.1 xx 10^(-31) kgfindtotaluncertainty(Delta V .Delta x)(h =6.626xx 10^(-34) J s)
Answer» Solution :h= 6.626 `xx10^(34)J s= 6.626 XX 10^(34) kg m^(2) s^(1)` Accordingto Heisenberguncertainty `Delta v .Delta x = (6.626 xx 10^(34)kg m^(2) s^(-1))/(4 xx 3.1416 ,9.1 xx 10^(31) kg )` `=5.794xx 10^(3) m^(2) s^(-1)` NOTE: thisuncertaintlyis `0.58 xx 10^(4)`it isuseful.soheisenbergprinciple isuseful for electronand particlelikeelectron.

25.	Mass of CO_(2) is 88 g. The number of atoms of oxygen present is :
Answer» `2.41 XX 10^(24)` `1.2 xx 10^(23)` `1.4 xx 10^(23)` `2.41 xx 10^(23)` Solution :44.0 grams of `CO_(2)` contain oxygen ATOMS `= 2xx 6.022 xx 10^(23)` atoms 88.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 2 xx 6.022 xx 10^(23)` `=2.41 xx 10^(24)` atoms.

26.	Mass numbers of Li, Be and B are 7, 9 and 10 respectively. Among B^(+), Be^(2+), Li^(+), Be Which has two electrons, three protons and four neutrons
Answer» ANSWER :LI

27.	Mass number of Li, Be and B are 7,9 and 10 respectively. Which of the following has two electron three protons and four neutrons ?
Answer» `B^(+)` `Be^(2+)` `LI^(+)` Be Answer :C

28.	Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass action A(g)+B(g) harr C(g) + D(g) Q=([C][D])/([A][B]). The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q = K. For non equilibrium process, Q ne K. When Q gt K, reaction will favour backward direction and when Q lt K, it will favour forward direction. The reaction quotient Q for : N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g)) is given by Q = ([NH_3]^2)/([N_2][H_2]^3). lhe reaction will proceed in backward direction, when :
Answer» `Q = K_c` `Q LT K_c` `QgtK_c` `Q = 0` Solution :`Q GT K IMPLIES` reaction PROCEEDS backward

29.	Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass action A(g)+B(g) harr C(g) + D(g) Q=([C][D])/([A][B]). The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q = K. For non equilibrium process, Q ne K. When Q gt K, reaction will favour backward direction and when Q lt K, it will favour forward direction. In a reaction mixture containing H_2, N_2 and NH_3 at partial pressure of 2 atm, and 3 atm respectively, the value of K_p at 725 K is 4.28 xx 10^(-5) atm^(-2). Inwhichdirectionthenetreactionwill go ? N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g))
Answer» FORWARD Backward No net reaction DIRECTION cannot be predicted Solution :`Q_(P)=(P_(NH_(3))^(2))/(P_(H_(2))^(3) xx P_(N_(2)))=((3)^(2))/((2)^(3) xx 1)=(9)/(8) gt K_(P)` `Q gt K_(P) implies` backward direction

30.	Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass action A(g)+B(g) harr C(g) + D(g) Q=([C][D])/([A][B]). The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q = K. For non equilibrium process, Q ne K. When Q gt K, reaction will favour backward direction and when Q lt K, it will favour forward direction. For the reaction : 2A + B harr 3C at 298 K, K_c = 49 A 3L vessel contains 2,1 and 3 moles of A, B and C respectively. The reaction at the same temperature:
Answer» must proceed in forward direction must proceed in backward direction must be in EQUILIBRIUM cannot be predicted Solution :`Q_(C)=([C]^(3))/([A]^(2) XX [B])=((3//3)^(3))/((2//3)^(2) xx (1//3))=(27)/(4) lt K_(C)`

31.	Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass actionl, A(g)+B(g)hArrC(g)+D(g) Q=([C][D])/([A][B]) The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q=K For non-equilibrium process QneK When QgtK, reaction will be favoured in backward direction and when QltK, it will be favoured in forward direction. In the following reaction : 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) The equilibrium is not attained. The rate of forward reaction is greater than that of backward reaction. Thus, which of the following is the correct relation between K_(p) and Q_(p)?
Answer» <P>`K_(p)=Q_(p)` `Q_(p)ltK_(p)` `Q_(p)ltK_(p)` `K_(p)=Q_(p)=1` ANSWER :C

32.	Martk out the correct comparisons
Answer» `3^(@)H gt 2^(@)H gt 1^(@) H` ( REACTIVITY for bromination ) Solution : is more STABLE alkene than so, its hydrogenation is shower .

33.	Marsh gas contains.
Answer» `CH_(4)` `CO_(2)` `C_(2)H_(6)` `N_(2)` Solution :Marsh GAS contains

34.	Markovnikov's rule is followed for the addition of HCl to______
Answer» SYMMETRICAL ALKENE UNSYMMETRICAL alkene symmetrical alkane unsymmetrical alkane Solution :unsymmetrical alkene

35.	In the presence of peroxide addition of HBr to propene takes place according to anti Markownikoff's rule but peroxide effect is not seen inthe case of HCl and HI. Explain.
Answer» ANSWER :T

36.	Markovnikov addition takes place with unsymmetrical alkenes. The positive part of the reagent gets connected to the double bonded carbon with more number of hydrogens. In presence of peroxide and in special cases addition takes place against Markovnikov rule. In which of the following compound addition takes place against Markovnikov rule
Answer» `CF_2 = CF_2` `C Cl_3 - CH = CH_2` `CH_3-underset(Cl)underset(\|)C=CH_2` Solution : `C Cl_3` is a strong with DRAWING group. So `pi` BOND polarise in its direction and ADDITION takes palce against Markovniko rule

37.	Markovnikov addition takes place with unsymmetrical alkenes. The positive part of the reagent gets connected to the double bonded carbon with more number of hydrogens. In presence of peroxide and in special cases addition takes place against Markovnikov rule. 1-methyl cyclohenene on hydroboroation it will give
Answer» cis -2-methyl cyclohenanol trans-2-methyl cyclohenanol Both a and B NONE SOLUTION :ALWAYS forms trans-product

38.	Markovnikov addition takes place with unsymmetrical alkenes. The positive part of the reagent gets connected to the double bonded carbon with more number of hydrogens. In presence of peroxide and in special cases addition takes place against Markovnikov rule. Addition of HCl or HI does not take place against ,Markoņikoff even in presence of peroxide, The reason is
Answer» HCl & HI dissociate into `H^(+)` and `X^(-)` only. The reaction with these reagents is reversible One of the propagation STEPS is ENDOTHERMIC with these reagents Both propagation steps are endothermic SOLUTION :Propoagation stage (OVERALL 3rd stage) during addition of HI and propagation stage -2 (ie overall 4TH stage) during addition of HCl are endothermic

39.	Mark the true statement concerning mesomeric effect ?
Answer» It OCCURS in systems having CONJUGATE DOUBLE bonds in compounds It involves ELECTRONS of `pi` bonds The electron pair is transferred completely It involves lone pair of electrons Solution : Concept of mesomeric effect

40.	Mark the incrrect statement describing the stutural features of Borax
Answer» It ha two terahedral and two triangular units All the boron ATOMS AARE not In same hybrid state Each boron atom of a pair is tetra valent One Boron atom has a LONE pair of electrons Answer :4

41.	Mark the oxide which is amphoteric in character
Answer» `CO_(2)` `SiO_(2)` `SnO_(2)` `CaO` ANSWER :C

42.	Mark the incorrect statement. Pure alumina is
Answer» a bad conductor of electricity. a good conductor of electricity an electrovalent COMPOUND. volatile in NATURE Solution :Pure ALUMINA is not an electrovalent compound. It is a bad conductor of electricity and non-volatile in nature with very HIGH melting point.

43.	Mark the incorrect statement in nitrogen Kjeldhal's method of estimation:
Answer» nitrogen gas is collected over caustic potash solution potassium sulphate is used as BOILING point ELEVATOR of `H_(2)SO_(4)` copper sulphate or mercury ACTS as a CATALYST nitrogen is quantitatively decomposed to give ammonium sulphate ANSWER :A

44.	Mark the incorrect statement from the following
Answer» Benzene has a planar structure Benzene is an unsaturated hydrocarbon and shows addition REACTIONS LIKE alkenes. In benzene CARBON uses two p-orbitals for hybridisation aromatic hydrocarbons contain HIGH percentage of carbon hence burn with sooty flame. Solution :Benzene does not SHOW addition reactions like alkenes due to delocalisation of `pi`-electrons.

45.	Mark the following statements as true or false. (i) Ordinary hydrogen is a mixture of 75% ortho and 25% para - forms.(ii)All the four atoms of molecule of H_(2)O_(2) lie in the same plane. (iii) Hydrogen peroxide is neutral like water. (iv) H_(2)O_(2) can be prepared from BaO_(2) but not from MnO_(2) and PbO_(2)
Answer» (i) and (iv) - true, (II) and (III) - false (i) and (ii) - true, (iii) and (iv) - false (iii) and (iv) - true, (i) and (ii) - false (i) and (iii) - true, (ii) and (iv) - false Solution :All four atoms of `H_(2)O_(2)` do not lie in same plane. Hydrogen peroxide is slightly ACIDIC in NATURE.

46.	Mark the incorect statement regarding the photoelectric effect.
Answer» There is no time lag between the striking of light beam and the EJECTION of electrons from the metal surface. The NUMBER of electrons ejected is INVERSELY proportional to the intensity of light. Photoelectric EFFECT is not observed below threshold frequency. The kinetic energy of the electrons increases with increase in frequency of light used. Solution :The number of electrons ejected is DIRECTLY proportional to the intensity of light.

47.	Mark the false statement.
Answer» A salt bridge is used to ELIMINATE liquid junction potential The Gibb's free energy , `DeltaG` is related with electromotive FORCE as `DeltaG=- n FE` Nernest EQUATION for single electrode potential is `E=E^(@)-(RT)/(NF)"log"_(e)[M^(n+)]` The efficiency of a hydrogen-oxygen fuel CELL is zero. Solution :Correct Nernst equation is `E=E^(@)+(RT)/(nF)"log"_(e)[M^(n+)]`

48.	Mark the false statement
Answer» The electropositive character of alkali METALS DECREASES with increase in ATOMIC number Lithium is a HARD metal and cannot be cut with a knife Alkali metals are strong reducing agents Electronegativities of all alkali metals lie between 1.0 and 0.7 Answer :A

49.	Mark the example which is not correct
Answer» Non-combustible heavy LIQUID used as fire extinguisher - `C CI_(4)` Blocks used to shield RADIOACTIVE materials lead Element which has property of leaving mark on paper - graphite A gas in solid form used as a refrigenrant CARBON monoxide Solution :Solid `CO_(2)` is used as refrigerant

50.	mark the correct statement in a reversible reaction:-
Answer» The CATALYST CATALYSIS the forward reaction The catalyst catalysis the backward reaction The catalyst INFLUENCES the DIRECT and the reverse reaction to the same extent The catalyst increases the rate of forward reaction and DECREASES the rate of backward reaction. Answer :C