Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Sodium nitrate decomposes above 800^(@)C to give

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`N_(2)`
`O_(2)`
`NO_(2)`
`Na_(2)O`

SOLUTION :`NaNO_(3)` DECOMPOSES above `800^(@)C` to give `O_(2)`
`2KNO_(3)(s)overset(800^(@)C)rarr2KNO_(2)(s)+O_(2)(g)`
2.

Sodium metal vaporises on heating and the vapour will have diatomic molecular of sodium (Na_(2)). What type of bonding is presetn in these moleculas ? Justify your answer .

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SOLUTION :Covalent bonds are present in `Na_(2)` . This can be explained on the basis of molecular orbital theory . Electronic
configuration of `""_(11)Na = 1s^(2) 2S^(2) 2p^(6) 3S^(1)` . The 3s atomic ORBITALS of the two sodium atoms combine to form
`sigma _(3s) and sigma _(3s)^(**)`molecular orbitals . The two electrons entre into `sigma_(3s)` . Hence, BOND order = 1 . Thus , the two
sodiium atoms are linked by a single covalent bond .
3.

Sodium metal vapprises on heating and the vapours have diatomic molecules of sodium (Na_(2)). what type of bonding is present in these moleceles ?

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ANSWER :A
4.

Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of ..........

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sodamide
ammoniated electrons
sodium ion-ammonia complex
sodium-ammonia complex

Solution :`Na overset(Liq.NH_(3))to UNDERSET("Deep blue colour")([Na(NH_(3))_(N)]^(2+)) +underset("Ammoniated ELECTRON")(2[E(NH_(3))_(n)]^(-))`
5.

Sodium metal itself is used as

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OXIDISING agent
DEHYDRATING agents
reducing agent
bleaching agent 

ANSWER :C
6.

Sodium metal is stored in ....... to avoid contact with air and water.

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Alcohol
Kerosene
Ether
Water

Answer :B
7.

Sodium metal is extracted by the electrolysis of fused chloride but potassium metal cannot be obtained by electrolysis of fused potassium chloride . Why so ?

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SOLUTION :Since K METAL is more soluble in KCL than NA metal is soluble in NaCl .
8.

Sodium metal preserved under kerosine. This is to prevent

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volatility of METAL
REACTIVITY in air
reactivity with CHLORINE
METALLIC luster 

Answer :B
9.

Sodium metal crystallizes in a body -centred cubic lattice with a unit cell edge of 4.29 Å. The radius of sodium metal is approximately

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5.72 Å
0.93 Å
1.86 Å
3.22 Å

Solution :For BCC, `r=sqrt3/4 a =1.732/4xx4.29 Å=1.86 Å`
10.

Sodium metal crystallizes in a body -centred cubic lattice with a unit cell edge of4. 29 Å. The radius of sodium metal is approximately.

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5.72 Å
0.93 Å
1.86 Å
3.22 Å

Solution :ForBCC, `R = sqrt3/4 a == 1.732/4 XX 4.29 Å= 1.86 Å`
11.

Sodium metal crystallises in body centred cubic lattice with the cell edge , 4.29 Å. What is the radius of sodium atom? What is the length of the body diagonal of the unit cell ?

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Solution :For BODY centred cubic lattice, the RELATIONSHIP between the cell EDGE (a) and the radius of the atom is
`r=sqrt3/4a=1.732/4xx4.29`=1.86 Å
Length of the body DIAGONAL =4r =4 x 1.86 Å=7.44 Å
12.

Sodium lamp emits yellow light of wavelength 5800 Å the wave number of the light is

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`1.72xx10^(6)//m`
`17.2xx10^(8)//m`
`5.17xx10^(14)//s`
`17.2xx10^(7)//m`

Solution :WAVE NUMBER `=1/lambda`
`=1/(5800xx10^(-10)m)=1.724xx10^(6)//m`
13.

Sodium-lead alloy is used in the preparation of which is used as an ............... compound to improve the quality of petrol

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SOLUTION : TETRA ETHYL lead and ANTI KNOCK
14.

Sodium is made by the electrolysis of a molten mixture of about 40% NaCl and 60% CaCl_2 because(a)Ca^(2+)ion can reduce NaCl to Na(b)CaCl_2 helps in conduction of electricity(c)this mixture has a lower melting point than NaCl(d)Ca^(2+) can displace Na fromNaCl.

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`Ca^(2+)`ion can REDUCE NaCl to Na
`CaCl_2` HELPS in conduction of electricity
this mixture has a lower MELTING POINT than NaCl
`Ca^(2+)` can displace Na from`NaCl`.

Solution :this mixture has a lower melting point than NaCl
15.

Sodium is strongly metallic, while chlorine is strongly non-metallic - explain.

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ANSWER :If sodium loses an electron it attains NOBLE GAS CONFIGURATION and if CHLORINE gains an electron, it attains noble gas configuration
16.

Sodium is stored under kerosene. Give reason.

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Solution :Because sodium metals is highly REACTIVE and combies with oxygen, moisture and `CO_(2)` from present in AIR FORMING `Na_(2)O, NAOH` and `Na_(2)CO_(3)` etc,
17.

sodium is stored in

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alcohol
water
KEROSENE
none of these

Solution :kerosene
18.

Sodium ion is isoelectronic with……..atom

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`MG^(2+)`
`Al^(3+)`
`Ne`
`N^(3-)`

SOLUTION :`Mg^(+2) , Al^(+3) , N^(-3)` are iso electronic ions
19.

Sodium in liquid ammonia is called mixed conductor. Comment.

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SOLUTION :Sodium metal as wella as sodium cation. Both are present in a solution of sodium in ammonia. It is a mixture of ELECTRONIC and ELECTROLYTIC conductor.
20.

Sodium hydroxide on reaction with CO_(2)produces .......

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Solution :SODIUM CARBONATE `(Na_(2)CO_(3))`
21.

Sodium hydroxide is also known as......

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SOLUTION :CAUSTIC SODA
22.

Sodium hydroxide is a deliquescent in nature. Why?

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SOLUTION :NaOH is a DELIQUESCENT solid because it absorbs moisture from the AIR and dissolves in that moisture.
23.

Sodium hydrogen carbonate is produce on passing of which gas through the washing soda?

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`O_(2)`
`H_(2)`
CO
`CO_(2)`

SOLUTION :`Na_(2)CO_(3)+H_(2)O+CO_(2) to 2NaHCO_(3)`
24.

Sodium hydrogen carbonate is known as ......

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SOLUTION :BAKING SODA
25.

Sodium hexametaphosphate is known as ……… at commerically.

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calgon
complex
leuco
caglon

Answer :A
26.

Sodium has a bcc structure with nearest neighbour neighbour distance 365.9 pm. Calculate its density (Atomic mass of sodium = 23)

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Solution :For the BCC, structure, nearst NEIGHBOUR distance (d)is related to the edge (a) as ` d= sqrt3/2 a`
or ` a= 2/sqrt3 d = 2 / 1.732 xx 365.9 = 422.5` pm.
For bcc stucture, Z =2
For sodiumM= 23 , ` p = ( Z xx M)/ (a^(3) xx N_(0)) = (2xx23 "g mol"^(-1))/((422.5xx10^(-10) cm)^(3)xx(6.02xx 10^(23)"mol"^(-1)))= 1.51 "g/cm"^(3)`
27.

Sodium has a bcc structure with nearest neighbour distance 365.9 pm. Calculate its density (Atomic mass of sodium =23)

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Solution :For the BCC structure , nearest NEIGHBOUR distance (d) is RELATED to the edge (a) as `d=sqrt3/2 a`
or `a=2/sqrt3 d =2/1.732xx365.9` =422.5 pm
For bcc structure, Z=2
For sodium , M=23 `THEREFORE RHO =(ZxxM)/(a^3xxN_0)=(2xx23 g mol^(-1))/((422.5xx10^(-10)cm)^3xx(6.02xx10^23 mol^(-1))=1.51 g//cm^3`
28.

The violet flame shown by potassium in bunsen flame is due to jumping of the electron from

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SOLUTION :YELLOW, PALE, VIOLET
29.

Sodium fusion extract, obtained from aniline, a treatment with iron (II) sulphate and H_(2)SO_(4) in presence of air gives a prussion blue precipitate. The blue colour is due to the formation of:

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`Fe_(4)[FE(CN)_(6)]_(3)`
`Fe_(3)[Fe(CN)_(6)]_(2)`
`Fe_(4)[Fe(CN)_(6)]_(2)`
`Fe_(3)[Fe(CN)_(6)]_(3)`

Answer :A
30.

Sodium fusion extract, obtained from aniline, on treatment with iron (II) sulphate and H_(2)SO_(4) in presence of air gives a prussian blue precipitate. Hence, the blue colour is due to the formation of

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`Fe_(4)[Fe(CN)_(6)]_(3)`
`Fe_(3)[Fe(CN)_(6)]_(2)`
`Fe_(4)[Fe(CN)_(6)]_(2)`
`Fe_(3)[Fe(CN)_(6)]_(3)`

Answer :A
31.

Sodium fusion extract of an organic compound gives blood red colour with FeSO_(4)//Conc. H_(2)SO_(4) on heating. Fresh extract of the same compound gives black precipitate when mixed with (CH_(3)COO)_(2)Pb and with yellow precipitate when treated with AgNO_(3) solution. Then the organic compound may be

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`C_6H_12NCl`
`C_6H_12NI`
`C_6H_12NSI`
`C_6H_12SI`

ANSWER :C
32.

Sodium forms a crystalline ionic solid with dihydrogen . The solid is non-volatile and non-conducting in nature. It reacts violently with water to produce dihydrogen gas. Write the formula of this compound and its reaction with water. What will happen on electrolysis of the melt of this solid.

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Solution :Sodium reacts with dihydrogen to form sodium hydride which is a CRYSTALLINE ionic solid.
`2Na+H_(2) to 2Na^(+) H^(-)`
It reacts with `H_(2)O` to produce `H_(2)` gas
`2NaH+2H_(2)O to 2NAOH + 2H_(2)`
Although `Na^(+)H^(-)` does not conduct electricity in the solid state but the ELECTROLYSIS of its melt PRODUCES `H_(2)` at the anode and Na at the cathode
`Na^(+)H^(-)(l) overset("Electrolysis")to overset("At cathode")(2Na(l))+ overset("At anode")(H_(2)(g))`
33.

Sodium forms a crystalline ionic solid with dihydrogen. The solid is non-volatile and non conducting in nature. It reacts violently with water to produce dihydrogen gas. Write the formula of this compound and its reaction with water. What will happen on electrolysis of the melt of this solid.

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Solution :Sodium reacts with dihydrogen to FORM sodium HYDRIDE which is a crystalline ionic solid.
`2NA+H_2 to 2Na^(+) H^-`
It reacts with `H_2O` to produce to `H_2` gas.
`2NaH+2H_2O to 2NaOH + 2H_2`
ALTHOUGH `Na^+H` does not conduct ELECTRICITY in the solid state but the electrolysis of its melt produces `H_2` at the anode and Na at the cathode.
`Na^(+)H^(-) overset"Electrolysis"to underset"At cathode"(2Na_((l))) + underset"At Anode"(H_(2(g)))`
34.

Sodium fire in the laboratory should not be extinguished by pouring water . Why ?

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Solution :The reaction of sodium with `H_(2)O` is so exothermic that the `H_(2)` produced CATCHES fire .
`2 Na + 2 H_(2)O to 2 NaOH + H_(2)`
As a result , the fire spreads rather than being extinguished . Therefore , `H_(2)O` should not be USED for EXTINGUISHING sodium fire . instead pyrene `(C Cl_(4))` should be used . When `C Cl_(4)` is sprinkled over fire , it being volatile (b.p. 350 K) immediately forms vapours . These vapours being non-inflammable and heavy , SURROUND the fire . As a result , supply of air is cut off and the fire gets extinguished .
35.

Sodium crystallizes in a bcc unit cell. Calculate the approximate number of unit cells in 92 g of sodium (Atomic mass of Na = 23)

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Solution :BCC has 2 ATOMS PER unit CELL.
36.

Sodium crystallises in the cubic lattice and the edge of the unit cell is 430 pm. Calculate the number of atoms in a unit cell. [Atomic mass of Na=23.0 amu, Density of sodium = 0.9623 "g cm"^(-3), N_A=6.023xx10^23 "mol"^(-1)]

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ANSWER :2, i.e., BCC
37.

Sodium chloride, NaCl, usually crystallizes in a face-centred cubic lattice. How many ions are in contact with any single Na^(+)ion?

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4
6
8
1

Solution :In NaCl having FCC structure, each `Na^(+)`ion is surrounded by SIX `Cl^(-)`ion at the CORNERS of a regular OCTAHEDRON.
38.

Sodium chloride is soluble in water but insoluble in benzene or hexane. Explain in the observation.

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Solution :SODIUM chloride is an ionic solid and water is a polar SOLVENT. Water molecules attract `Na^(+) and Cl^(-)` ions by their negative and positive poles RESPECTIVELY. As a result, theions get detached from the crystal lattice and undergo solvation with the evolution of solvation enegy. in this case, SINCE the solvation ENERGY is greater than lattice energy. NaCl dissolves in water. on the other hand, benzene and hexane are non-polar organic solvents and they cannot solvate `Na^(+) and Cl^(-)` ions. hence, sodium chloride is insoluble in benzene or hexane.
39.

Sodium chloride crystallises into F.C.C lattice with Na+ occupying corner of a cube and the centre of each face, whereas Cl^(-) is occupies the centre of each edge and centre of the cube. The r_c //r_a value for NaCl is 0.53 and coordination number is 6. In NaCl unit cell, the edge length is

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`2r_c+2r_a`
`r_c +r_a`
`(r_c + r_a)/(2)`
`SQRT(3) (r_c +r_a)`

ANSWER :A
40.

Sodium chloride crystallises into F.C.C lattice with Na occupying corner of a cube and the centre of each face, whereas Cl^(-) is occupies the centre of each edge and centre of the cube. The r_c //r_a value for NaCl is 0.53 and coordination number is 6. If all the face centred ions along one of the axis are removed, the stoichiometry of the resulting solid is

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`NACL
`Na_2 CL`
`Na_3 Cl_2`
`Na_3 Cl_4`

ANSWER :D
41.

Sodium chloride crystallises into F.C.C lattice with Nat occupying corner of a cube and the centre of each face, whereas Cl^(-) is occupies the centre of each edge and centre of the cube. The r_c //r_a value for NaCl is 0.53 and coordination number is 6,6. In NaCl crystal lattice each sodium ion is surrounded by — number of chloride ions in ---- fashion

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8, TETRAHEDRAL
6, octahedral
8, square planar
6, DISTORTED octahedron

ANSWER :B
42.

Sodium chloride crystallises into F.C.C lattice with Na occupying corner of a cube and the centre of each face, whereas Cl^(-) is occupies the centre of each edge and centre of the cube. The r_c //r_a value for NaCl is 0.53 and coordination number is 6,6. If all the ions present in one plane that is passing through the centre are removed, the formula of the resulting unit cell is

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`NACL`
`Na_2 Cl_3`
`Na_3 Cl_2`
`NaCl_2`

ANSWER :A
43.

Sodium carbonate (Na_(2)CO_(3)0can be obtained by heating sodium hydrogen carbonate,NaHCO_(3) 2NaHCO_(3)(s) rarr Na_(2)CO_(3)(s)+H_(2)O(g) + CO_(2)(g) Calculate the temperatureabove which NaHCO_(3) decomposes to form products at 1 bar . Given Delta_(f)H^(@) ( kJ mol^(-1)):NaHCO_(3)(s) = =- 947.7 , Na_(2)CO_(3)(s) = - 1130 .9, H_(2)O(g)= - 241.8 , CO_(2)(g) = - 393.5 S^(@) (JK^(-1) mol^(-1)) : NaHCO_(3)(s) = 102.1 , Na_(2)CO_(3) (s)=136.0, H_(2)O(g) = 188.8, CO_(2)(g) 213.7

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Solution : `Delta_(r)H^(@) = ( -1130.9) + ( -241.8) + ( -393.5)- 2 xx ( -947.7 )= 129.2 KJ mol^(-1)`
`Delta_(r)S^(@) = ( 136.0 +188.8 +213.7) - 2( 102.1) = 334.3 JK^(-1) mol^(-1)`
`Delta_(r)G^(@)= Delta_(r)H^(@)-TDelta_(r)S^(@)`,
At equilibrium , `DELTAG^(@)= 0, T - ( Delta_(r)H^(@))/( Delta_(r)S^(@))= ( 129200)/( 334.3) = 386.5K`
Thus, above 386.5 K , `Delta_(r)G^(@)` will be negative and the reactionwill be spontaneous.
44.

Sodium carbonate is manufactured by Solvay process. The products those are recycled are

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`CO_(2)` and NH
`CO_(2)` and `NH_(4)C_(1)`
NaCl and CaO
`CaCl_(2)` and CaO

Answer :A
45.

Sodium carbonate is soluble in water because

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High LATTICE ENTHALPY
LOW lattice enthalpy
Low MOLECULAR weight
High molecular weight 

ANSWER :B
46.

Sodium carbonate is prepared by …….and its formula is ……. .

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Solution :Solvay AMMONIA PROCESS , `Na_(2) CO_(3) . 10 H_(2)O`
47.

Sodium carbonate is generally prepared by a process called ammonia soda process as follows : The above process cannot be used for the manufacturing of K_(2)CO_(3) because

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`KHCO_(3)` is soluble in water and doe not percipitate in carbonating water
`KHCO_(3)` is less soluble than `NaHCO_(3)`
POTASSIUM is LIGHTER than sodium
Sodium reacted with water in carbonating tower

Answer :A
48.

Sodium carbonate is manufactured by Solvay process. The products that are recycled are

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`CO_2and NH_3`
`CO_2 and NH_4Cl`
`NACL, CAO`
`CaCl_2, CO`.

SOLUTION :`CO_2and NH_3`
49.

Sodium carbonate is highly soluble in water, but magnesium carbonate is less soluble. Why?

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Solution :Cation of group IA,`M^(+)` has one unit CHARGE, while that of IIA, `M^(2+)` has two UNITS charge. The GREATER the charge, the greater is the lattice energy. In the case of magnesium carbonate, lattice energy dominates hydration energy. HENCE, it is less soluble.
50.

Sodium carbonate is generally prepared by a process called ammonia soda process as follows : Which of the following is by-product in the above process?

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`NH_(4)CL`
`CaCl_(2)`
`NH_(4)OH`
CaO

Answer :B