Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Ethyl bromide reacts with alcoholic AgCN to form ……………….. .

Answer»

SOLUTION :`CH_3CH_2NC`
2.

Ethyl bromide reacts with alcoholic AgCN to form ……………..

Answer»

`CH_3 CH_2 CN`
`CH_3CN`
`CH_3CH_2NC`
`CH_3NC`

SOLUTION :`CH_3CH_2NC`
3.

Ethyl benzene with Br_(2) in the presence of FeBr_(3)gives

Answer»

PHENYL bromoethane
o and P-bromotoluenes
o and p-bromo ETHYL BENZENES
Mixture of all these

Answer :C
4.

Ethyl benzene on reaction with bromine in presence of FeBr_3, predominantly gives

Answer»




SOLUTION :ETHYL BENZENE + `Br-2 to `
5.

Ethyl benzene on heating with Cl_2 gives A(C_8 H_9CI). A on reaction with alcoholic KOH gives B(C_8 H_8).Compounds A and B are, respectively

Answer»

`C_6H_5 - CH_2CH_2 CL and C_6H_5 - CH_2 - CH_2-OH `
`C_H_5 - overset(Cl)overset(|)CH-CH_3 and C_6H_5-overset(OH)overset(|)CH-CH_3`
`C_6H_5 - CH_2CH_2Cl and C_6H_5-CH =CH_2`
`C_6H_5 - overset(Cl)overset(|)CH-CH_3 and C_6H_5 - CH = CH_2 `

Solution :FREE radical chlorination occur at BENZYLIC carbon followed by E-2 elimination REACTION
6.

Ethyl alcohol reacts with acetyl chloride to form

Answer»

Ethyl chloride
Acetic acid
Methyl acetate
Ethyl acetate

Solution :`H_(3) C - overset(O)overset(||)(C) - Cl + H - OC_(2)H_(5) UNDERSET(-HCL)rarr underset("Ethyl acetate")(H_(3)C - overset(C)overset(||)(C) - OC_(2)H_(5))`
7.

Ethyl alcohol is oxidation with K_(2)Cr_(2)O_(7) gives

Answer»

Acetic acid
Acetaldehyde
Formaldehyde
Formic acid

Solution :`underset("ETHYL alcohol")(C_(2)H_(5)OH)+2[O] overset(K_(2)Cr_(3)O_(7)//H^(+))rarrunderset("Acetic acid")(CH_(3)COOH)+H_(2)O`
8.

Ethyl alcohol is industrially prepared from ethylene by

Answer»

Permanganate oxidation
Catalytic reduction
Absorbing in `H_(2)SO_(4)` followed by hydrolysis
Fermentation

Solution :`H_(2)C=CH_(2)+H_(2)SO_(4) rarrC_(2)H_(5)HCO_(4) underset(-H_(2)SO_(4))overset(H_(2)O //H^(+))RARR underset("Ethanol")(C_(2)H_(5)OH)`
9.

Ethyl alcohol is heated with conc. H_(2)SO_(4). The product formed is:

Answer»

`CH_(3)COOC_(2)H_(5)`
`C_(2)H_(6)`
`C_(2)H_(4)`
`C_(2)H_(2)`

Answer :C
10.

Ethyl alcohol is an organic compound but still freely soluble in water explain.

Answer»

Solution :The solubility of ethyl aclohol in water is due to the PRESENCE of intermolecular hydrogen BONDING between the TWO.
`---H-OVERSET(H)overset(|)O---H-overset(C_(2)H_(3))overset(|)O---overset(H)overset(|)O---H-overset(C_(2)H_(3))overset(|)O---`
Energy is released during teh attraction this helps in the dissolution of alcolol in water.
11.

Ethyl alcohol gives ethyl chloride with the help of

Answer»

`SOCl_(2)`
`NaCl`
`Cl_(2)`
`KCl`

SOLUTION :`NaCl, Cl_(2)` or `KCl` cannot cause REPLACEMENT of OH group of alcohol.
12.

Ethyl alcohol can be used for preparation of which of the following ?

Answer»

All the FOLLOWING compounds
Ethyl acetate
Ethylene
Acetic acid

Answer :A
13.

Ethyl acetate reacts with CH_(3)Mg Br to form

Answer»

Secondary alcohol
TERTIARY alcohol
Primary alcohol and acid
Acid

Solution :`CH_(3) COOC_(2)H_(5) + CH_(3)MG Br rarr CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - OMG Br + H_(2)O overset("Hydrolysis")rarr underset("tertiary butyl alcohol")(CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - OH) + Mg BrOH`
14.

Ethyl acetate is obtained when methyl magnesium iodide reacts with

Answer»

ETHYL formate
ethyl chloroformate
acetyl chloride
carbon dioxide

Solution :
15.

Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as: CH_3COOH_((l)) + C_2H_5OH_((l)) hArr CH_3COOC_2H_(5(l)) + H_2O_((l)) (i)Write the concentration ratio (reaction quotient), Q_c for this reaction (note : water is not in excess and is not a solvent in this reaction) (ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant. (iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached ?

Answer»

Solution :(i)`Q_c=([CH_3COOC_2H_5][H_2O])/([CH_3COOH][C_2H_5OH])`
`{:("EQUILIBRIUM reaction :",CH_3COOH_((l))+,C_2H_5OH_((l)) hArr, CH_3COOC_2H_(5(l))+, H_2O_((l))),("INITIAL mol:",1.0,0.18,0,0),("Change in reaction :",-x,-x,+x,+x),("Mol at equilibrium :",(1.0-x),(0.18-x),x=0.171,x),(,=(1.0-0.171),=(0.18-0.171),0.171,=0.171),(,=0.829,=0.009,0.171,0.171),("Suppose Volume =V So, M:", 0.829/V, 0.009/V,0.171/V,0.171/V):}`
`therefore K_c=([CH_3COOC_2H_5][H_2O])/([CH_3COOH][C_2H_5OH])=(0.171/V)(0.171/V)(V/(0.829))(V/0.009)=(0.171xx0.171)/(0.829xx0.09)`=3.9192
`{:("Equilibrium reaction :",CH_3COOH_((l)) + , C_2H_5OH_((l)) hArr , CH_3COOC_2H_(5(l))+,H_2O_((l))),("Initial mol:", 1.0,0.5,0,0),("Change in reaction :",-x,-x,+x,+x),("Mol at equilibrium:",(1.0-x),(0.5-x),x,x),(,=(1.0-0.214),=(0.5-0.214),=0.214,0.214),(,=0.786,=0.286,,),("At equilibrium M:",0.786/V,0.286/V,0.214/V,0.214/V):}`
`therefore Q_c=([CH_3COOC_2H_5][H_2O])/([CH_3COOH][C_2H_5OH])=(0.214/V)(0.214/V)(V/0.786)(V/0.286)=(0.214xx0.214)/(0.786xx0.286)`=0.2037
`(Q_c = 0.2037) lt (K_c=3.9192)`
`therefore Q_c NE K_c`, So, equilibrium is not .
`Q_c lt K_c` , The VALUE of `Q_c` is not equal to `K_c` , The reaction is continue.
`Q_c` is less ,So, forward reaction occurs and more product is obtain.
16.

Ethyl accetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as : CH_(3) COOH (l) + C_(2) H_(5) OH (l) hArr CH_(3) COOC_(2) H_(5)(l) + H_(2)O (l).

Answer»

Solution :(i) ` Q_(c) = ([CH_(3) COOC_(2) H_(5)][H_(2)O])/([CH_(3) COOH ] [C_(2) H_(5) OH]) `
` {:((ii),CH_(3)COOH,+,C_(2)H_(5)OH,hArr,CH_(3)COOC_(2)H_(5),+,H_(2)O),("Intial",1*00"mol",,0*180 "mol",,,,),("At eqm",1-0*171,,0*180-0*171,,0*171"mol",,0*171 "mol"),(,=0*829 "mol",,=0*009"mol",,,,),("Molar concs.",0*829//V,,0*009 //V,,0*171//V,,0*171//V):} `
` K_(c) = ([CH_(3) COOC_(2)H_(5)][H_(2)O])/([CH_(3)OOH][C_(2)H_(5)OH] )=((0*171//V)(0*171//V))/((0*829//V)(0*009//V))=3*92`
` {:((iii),CH_(3)COOH,+,C_(2)H_(5)OH,hArr,CH_(3)COOC_(2)H_(5),+,H_(2)O),("Intial",1*000 "mol",,0*500"mol",,,,),("After time t",1-0*214,,0*500-0*214,,0*214,,0*214),(,=0*786 "mol",,= 0*286 "mol",,,,):}`
Reaction quotient ` (Q_(c))=((0*214//V)(0*214//V))/((0*786//V)(0*286//V))=0*204`
As `Q_(c) != K_(c)` , EQUILIBRIUM has not been attained .
17.

Ethy alcohol is...... to litmus :

Answer»

Acidic
Basic
NEUTRAL
None of these

Solution :Neutral
18.

Ethene on treating with bromine in presence of sodium chloride forms a mixture of CH_(2)ClCH_(2)Br and CH_(2)BrCH_(2)Br. Give reason.

Answer»

Solution :The ADDITION of bromine FOLLOWS IONIC MECHANISM. The intermediate carbocation formed is attacked by BROMIDE ion as well as chloride ion given by sodium chloride.
19.

Ethene on ozonolysis yields X. To preparesuccessive homologue of X, which of the following should be subjected to ozonolysis?

Answer»

BUTENE - 1
Hexene - 3
Butyne - 2
Butene - 2

Answer :D
20.

Ethene is obtained from ethyne by

Answer»

CATALYTIC hydrogenation
Controlled hydration
Catalytic hydration
Controlled hydrogenation

Answer :D
21.

What are the four condition for aromaticity?

Answer»


ANSWER :F
22.

Ethene, ethyne and benzene gives electrophilic reactions, why ? Give reasons.

Answer»

Solution :All these three possess arrangement of high negativity of `pi`-electrons. (i) Presence of such negativity facilitate ELECTROPHILES to react. (II) `sigma`- BOND EASILY breaks in comparison to `pi`- bond so such compounds gives electrophilic REACTION.
23.

Ethene and ethyne can be distinguished using

Answer»

TOLLEN's reagent
Schiff's reagent
Baeyer's reagent
Nessler's reagent

Answer :A
24.

Ethanol when reacted with PCl_(5) gives A, POCl_(3) and HCl. A reacts with silver nitrite to form B (major product) and AgCl. A and B respectively are

Answer»

`C_(2)H_(4)Cl` and `C_(2)H_(5)OC_(2)H_(5)`
`C_(2)H_(6)` and `C_(2)H_(5)OC_(2)H_(5)`
`C_(2)H_(5)Cl` and `C_(2)H_(5)NO_(2)`
`C_(2)H_(6)` and `C_(2)H_(5)NO_(2)`

SOLUTION :`C_(2)H_(5)OH+PCl_(5) rarr underset((A))(C_(2)H_(5)Cl)+POCl_(3)+HCl`
`C_(2)H_(5)Cl+AgNO_(2) rarr underset((B))(C_(2)H_(5)NO_(2))+AgCl`
25.

Ethanol reacts with methyl magnesium bromide to form

Answer»

ETHANE
METHANOL
PROPANONE
METHANE

ANSWER :D
26.

Ethanol has higher boiling point diethyl ether or ethyl amine. Why ?

Answer»

Solution :In ETHANOL , these is H-bonding but in DIETHYL ether , there is no H-bonding (because O-atom isattached to
C-atom ) and in CASE of ETHYL amine, the H-bonds formed by n-atom are WEAKER then those formed by O-atom.
27.

Ethanol containing some methanol is called

Answer»

ABSOLUTE SPIRIT
Rectified spirit
Power alcohol
Methylated spirit

Solution :Methlated spirit
28.

Ethanol cannot be dried by anhyd. MgCl_(2) because

Answer»

ETHANOL is soluble in water
explosion takes place
ethanol reacts with `MgCl_(2)`
All the above

Solution :It forms ADDITION compoud of FORMULA `MgCl_(2).6C_(2)H_(5)OH`
29.

ethanol and methoxymethane are position isomers. State true or false

Answer»


ANSWER :F
30.

Ethanol boils at 78.4^(@)C and the standard enthalpy of vaporisation of ethanol is 42.4 kJ mol^(-1) . Calculate theentropy of vaporisation of ethanol.

Answer»


Answer :`120 . 7 JK ^(-1) mol^(-1)`
31.

Ethanol and ethylene glycol can be distinguished by

Answer»

LUCAS TEST
Iodoform test
Victor Meyer test
None of these

Solution :Ethanol GIVES positive response to iodoform test while ethlene glycol NEGATIVE response to iodoform test.
32.

Ethanoic anhydride when reduced with LiAlH_(4) produces

Answer»

Ethanal
Ethane
Ethanol
Propanoic ACID

SOLUTION :`(CH_(3)CO)_(2)O overset(LiAlH_(4))rarr 2CH_(3)CH_(2)OH`
33.

Ethanoic acid on reaction with hydrazoic acid (HN_(3)) yields

Answer»

ethylamine
acetamide
methylamine
nitroethane

Solution :Carboxylic acid with `HN_(3)` form primary amines with ONE carbon less (Schmidt reaction).
`CH_(3) COOH + HN_(3) rarr CH_(3) NH_(2) + CO_(2) + N_(2)`
34.

Ethane undergo homolytic cleavage to form ...........

Answer»

SOLUTION :METHYL FREE RADICAL
35.

Ethane rects with HBr to form ………………..

Answer»

SOLUTION :BROMO ETHANE
36.

Ethane is foremd during the formation of chloromethane by chlorinationn of methane because

Answer»

higher MEMBERS of the hydrocarbons are generally formed during reactions
two METHYL free radicals may combine during chlorination to give ethane
two chloromethane molecule react to form ethane
chlorine free radical reacts with methane to give ethane.

Solution :Methyl free radicals may react to form ethane.
`overset(**)(C)H_(3)+overset(Cl^(**)) to CH_(3)Cl` (chloromethane)
or `overset(**)(C)H_(3)+overset(**)(C)H_(3) to CH_(3)-CH_(3)` (ethane)
37.

Ethane is subjected to combustion processes. During the combustion the hybrid state of carbonchanges from

Answer»

`SP^(2) " to " sp^(3) `
`sp^(3) " to " sp`
`sp " to " sp^(3) `
`sp^(2) " to " sp^(2)`

SOLUTION :`sp^(3)` to sp
38.

Ethane can be prepared by

Answer»

HEATING soldalime with SODIUM acetate
ELECTROLYSIS of sodium succinate
electrolysis of acetate
heating sodalime with sodium propionate

Solution :Kolbe's Electrolysis METHOD
39.

Ethane burns completely in air to give CO_(2), while in a limited supply of air gives CO. The same gases are found in automobile exhaust . Both CO and CO_(2) are atmospheric pollutants. How do the pollutants affect the human body ?

Answer»

Solution :Danger associated with CO and `CO_(2)` health hazards to human body
Increase in `CO_(2)` level into the atmosphere is responsible for GLOBAL WARMING. If causes HEADACHE and nausea.
40.

Ethane burns completely in air to give CO_(2) while in a limited supply of air gives CO. The same gases are found in automobile exhaust. Both CO and CO_(2) are atmospheric pollutants (i) What is the danger associated with these gases? (ii) How do the pollutants affect the human body?

Answer»

Solution :Danger ASSOCIATED with CO and `CO_2` & health hazards to human BODY
Carbon monoxide binds with haemoglobin and form carboxyhaemoglobin which IMPAIRS normal oxygen transport by blood and hence the oxygen carrying capacity of blood is reduced. This oxygen DEFICIENCY results in headache, tension, dizziness, loss of consciousness, blurring of eyesight and cardiac arrest.
(b) Increase in `CO_(2)` level in the atmosphere is responsible for global warming. It causes headache and nausea.
41.

Ethane burns in oxygen to form CO_2 and H_2O according to the equation : 2C_2H_6 + 7O_2 rarr 4CO_2 + 6H_2O If 1250 cc of oxygen is burnt with 300 cc of ethane. Calculate : the volume of unused O_2.

Answer»

SOLUTION :The equation involved is
`2C_2 H_6 + 7O_2to4CO_2 + 6H_2O`
`2 " volumes " "" 4 " volumes "`
This equation implies that under similar conditions
2 volumes of ethane (on BURNING completely), will give
4 volumes of `CO_2`. Since the conditions are similar in the
given problem, 2.5 L of ethane will form `2.5 XX 4/2 = 5.0L " of " CO_2 " at " 27^@C` and 1 atm PRESSURE.
42.

Ethane burns in oxygen to form Carbon dioxide and Water vapours. Write the balanced equation.

Answer»

Solution :In this case, the conditions are different. Therefore, we should convert the VOLUME of `CO_2`produced (5.0 L) at `27^@C` and 1 atm to the given conditions i.e., at `50^@C` and 1.5 atm.
Therefore,
`P_1 = 1.0 " atm," "" V_1 = 5.0 L`,
`T_1 = 27 + 273 = 300 K`
and `P_2 = 1.5 " atm," ""V_2` = ?
`T_2 = 50 + 273 = 323 K`
According to the GAS equation,
`(P_1 V_1)/T_1 =(P_2 V_2)/(T_2)`
or`V_2= (P_1 V_1 T_2)/(T_1 P_2) =(1.0 xx 5.0 xx 323)/(300 xx 1.5) = 3.6 L`
Therefore, 3.6 L of `CO_2` will be produced at `50^@C` and 1.5 atm pressure.
43.

Ethane burns completely in air to give CO_(2), while in a limited supply of air gives CO. The same gases are found in automobile exhaust . Both CO and CO_(2) are atmospheric pollutants. What is the danger associeated with these gases

Answer»

Solution :Danger associated with CO and `CO_(2)` health hazards to HUMAN body
Carbon monoxide binds haemoglobin and form carboxy haemoglobin which impairs normal OXYGEN TRANSPORT by blood and hence the oxygen carrying capacity of blood is reduced.This oxygen deficiency results in headache, dizziness, TENSION , loss of consciousness, blurring of EYE sight and cardiac arrest.
44.

Ethane-1,2-diol when heated with ZnCl_(2) gives

Answer»

Ethanal
Ethene
Ethanoic acid
Ethane

Solution : `{:(""OH),("|"),(HO-CH-H underset(-H_(2)O)overset(ZnCl_(2))rarr[CH_(2)=CH] overset("tautomerisation")rarr underset("Ethanal")(CH_(3)CHO)),("|"),(""CH_(2)-OH):}`
45.

"Ethanal" overset(Al(OC_(2)H_(5))_(3))rarr X overset(C_(2)H_(5)ONa)rarr Y In the above reaction X and Y are

Answer»

`CH_(3) - COOH, CH_(3)COOC_(2)H_(5)`
`CH_(3)COOC_(2)H_(5), CH_(3)COCH_(2)COOC_(2)H_(5)`
`CH_(3)COOH, CH_(3)COCH_(3)`
NONE of the above

Solution :`underset"Ethanal"(2CH_(3)CHO) underset("Tischenko reaction")overset(Al(OC_(2)H_(5))_(3))rarr underset((X))(CH_(3) COOC_(2)H_(5)) overset(+C_(2)H_(5)ONa)rarr underset("Ethyl acetoacetate (Y)")(CH_(3) - overset(O)overset(||)(C) - CH_(2) - overset(O)overset(||)(C) - OC_(2)H_(5))`
46.

Ethanal and Vinyl alcohol both are examples of which isomerism?

Answer»

Metamerism
Tauomerism
Position Isomerism
Functional GROUP Isomerism

Answer :B
47.

Ethanal + Aluminium ethoxide rarr X. The product X in the above reaction is

Answer»

ALUMINIUM acetate
Ethanoic anhydride
Ethyl acetate
Propanoic acid

Solution :`CH_(3)CHO + CH_(3) CHO overset(Al(OC_(2) H_(5))_(3))RARR CH_(3)COOH + C_(2)H_(5)OH overset(-H_(2)O)rarr underset("Ethyl acetate")(CH_(3) - overset(O)overset(||)(C) - OC_(2)H_(5))`
48.

Estimate the average S-F bond energyin SF_(6).The standard heat of formation valuesof SF_(6)(g), S(g)andF(g) are : - 1100,275 and80 Kj mol^(-1) respectively.

Answer»

Solution :Aim`:(1)/(6) [SF_(6)(g) rarrS(g) +6F(g)],DeltaH=?`
For the reaction, `SF_(6)(g) rarrS(g) + 6F(g)`
`Delta_(f)H = Delta_(f)h^(@) [S(g)+ 6[Delta_(f)H^(@) F (g)]-[Delta_(f)H^(@) SF_(6)(g)=275 + 6(80)-( -1100) kJ mol^(-1) = 1855kJ mol^(-1)`
`:. ` AverageS-F bond ENERGY `= ( 1855)?( 6) =309.16 kJ mol^(-1)`
49.

Erite the balanced equation for following reaction . (i) Li metal with N_(2) gas. (ii) Heating solid sodium bicarbonate (iii) Solid potassium hydroxide with CO_(2)

Answer»

Solution :(i) `6Li_(S)+3N_(2(g))to2Li_(3)N_(S)`
(ii)`2NaHCO_(3)overset(DELTA)toNa_(2)CO_(3)+CO_(2) uparrow+H_(2)O`
(III) `2KOH_(S)+CO_(2)toK_(2)CO_(3)+H_(2)O`
50.

Equivalent weights of Na_(2)CO_(3) and Al_(2)(SO_(4))_(3)

Answer»

Solution :`Na_(2)CO_(3) 2NA^(+1) +CO_(3)^(-2)`
Equivalent weight of `Na_(2)CO_(3)=(106)/(2)=53`
`Al_(2)(SO_(4))_(3) to 2Al^(+3) +3SO_(4)^(-2)`
Equivalent weight of `Al_(2)(SO_(4))_(3)=(342)/(6)=57`