Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What happen when Lithium Hydride react with dimer of Aluminium chloride ?

Answer»
Discussion
2.

In which of the following, ortho/para substitution by an electrophile is very facile?

Answer»

Nitrobenzene
Phenol
Benzoic acid
Acetophenone

Answer :B
Discussion
3.

In which of the following oxidation no. of nitrogen atom is correctly matched:

Answer»

`HCulN "" -3`
`HulNC "" -3`
`HOCulN""-3`
`(CulN)_2"" -2`

Solution :Oxidation no. of N in `(CN)_2` is -3
`OVERSET(+1)H-overset(-2)O-overset(-2)overset(O)overset(||)underset(-2)underset(O)underset(||)(S_x)-overset(-2)O-underset(-2)underset(O)underset(||)overset(-2)overset(O)overset(||)(S_x)-overset(-2)O-overset(+1)H`
Discussion
4.

In which of the following orientation of electron pairs and shape of the ion is similar

Answer»

`ClO_4^(-)`
`ClO_3^(-)`
`ClO_2^(-)`
`CLO^(-)`

ANSWER :A
Discussion
5.

In which of the follwing options the orders of arrangement does not agree with the variation of property indicated against it ?

Answer»

`IltBrltClltF` (increasing electron GAIN enthalpy)
`LiltNaltKlt`Rb (increasing metallic radius)
`AL^(3+)ltMg^(2+)ltNa^(+)ltF^(-)` (increasing IONIC size)
`BltCltOltN` (increasing FIRST ionization enthalpy)

Answer :a
Discussion
6.

In whichof the followingoptionsthe order ofarrangementdoes notagreewith thevariationof property inindicated against it ?

Answer»

`I lt Na lt C1 lt F` (increasingelectrongain enthalpy)
`Li lt Na lt K lt Rb` (increasingmetallicradius )
`A1^(3+) lt Mg^(2+) lt Na^(+) lt F^(-)` (inreasingionic SIZE )
`B lt C lt N lt O` (inreasingfirstionisationenthalpy )

Solution :Theelectrongainenthalpyof C1 ismorenegativethan thatof F i.e.,negativeelectrongain enthalpyincreases`I lt Br gt f lt C1` .Thusoption ( a) iswrong
Ionizationenergiesof alkalimetalsdecreasesandhencetheirmetalliccharacterincreasesdown thegroup (i.e., `Li lt Ne lt K lt Rb)` Thusoption( b)is correct.
Amongisoelectronicions,ionicsize increase asthe + ve chargedecreasesor the - vechargeincreases `(i.e., A1^(3+) lt Mg^(2+) lt Na^(+) lt F^(-))`
Thusoption (c ) is correct.
Ingeneralalong aperiod, firstionizationenergyincrease from leftto rightas thenuclearcharge increases. Butdue togreaterstabilityof half- filledE.C. of N , itsionizationenergyis higherthant thatof O.Thusthe actualorder is `B lt C lt O lt N` i.e.,OPTION (d ) isalsowrong.
Discussion
7.

In which of the following options the order of arrangement does not agree with the variation of property indicated against it?

Answer»

`I lt Br lt Cl lt F `(electron negativity)
`Li lt Na lt K lt RB `(metallic radius) 
`Al ^(+3) lt Mg^(+2) lt Na^(+) lt F^(-)` (ionic SIZE)
`B lt C lt N lt O` (`1^(st)` ionization ENTHALPY) 

ANSWER :D
Discussion
8.

In which of the following options order of arrangement does not agree with the variation of property indicated against it?

Answer»

`Al^(3+) lt Mg^(2+) lt NA^(+) lt F^(-)` -(INCREASING IONIC size)
`B lt C lt N lt O` (increasing FIRST ionisation enthalpy)
`I lt Br lt CI lt F`(increasing electron gain enthalpy)
`Li lt Nalt K lt RB` (increasing metallic radius)

Solution :As Nitrogen is having greater stability due to its halfed filled ELECTRONIC configuration, then its ionisation enthalpy is higher than that of oxygen. Thus, option (B) is incorrect.
Due to the negative electron gain enthalpy of flourine is lower than of chlorine because of the electron-electron repulsion in the small size of flourine.
Discussion
9.

In Whichof the followingoptionsorder ofarrangementdoes notagree withthe variationof property indicatedagainst it ?

Answer»

`A1^(3+) lt Mg^(2+) lt Na^(+) lt F^(-)` ( increasingionicsize )
`B lt C lt N lt O ` (increasingfirst ionisation enthalpy )
`I lt Br lt C lt F` (increasingelectron gain enthalpy )
`Li lt Na lt K lt Rb` (increasingmetallicradius )

Solution :the ionicsize increasesas the + Ve CHARGEON the cation decreasesor the -vecharge on theanion increase
Thereforeoption(a) iscorrect.
than thatof O.Thusoption(b) isincorrect.
Dueto greaterstabilityof the half-filledelectronicconfigurationor OFN its IONIZATIONENTHALPYIS higher than thatof O. Thusoption ( b) isincorrect.
Duttostrongerelectron- electronrepulsion in thed smallsizeof F thenegativeelectron gainenthalpy ofF ISLOWER thanthat of C1 .Thusoption( c) isincorrect.
Themetalliccharacterincreasesas the sizeof the metallicatomincrease. thusoption (d) iscorrect.
Thusoptions ( b) and (c) AREINCORRECT.
Discussion
10.

In which of the following options order of arrangement does not agree with the variating of property indicated against it ?

Answer»

`Al ^(3+) lt mg ^(2+) lt Na ^(+) lt F ^(-)` (increasing ionic size)
`B lt C lt N lt O` (increasing first ionisation enthalpy)
`I lt Br lt Cl lt K lt Rb` (increasing ELECTRON gain enthalpy)
`Li lt Na lt K lt Rb` (increasing metalic RADIUS)

Solution :For (b) correct order is `B lt C lt O lt N`
For (c ) correct order is `I lt Br lt F lt Cl`
Discussion
11.

In which of the following, one of the product would be t-butyl benzene

Answer»




Solution :ELECTRON `E^(o+)` ATTACK on benzene REACTION.
Discussion
12.

In which of the following NaCl is more soluble

Answer»




SOLUTION : DUE to BOND ENERGY of O-H is LEAST.
Discussion
13.

In which of the following NaOH is not used ?

Answer»

REFINING of PETROLEUM
REAGENT in laboratory
Hardwater into soft
Manufacturing of soap

Answer :C
Discussion
14.

In which of the following molecules, vacant orbitals take part in hybridization ?

Answer»

<P>`B_(2)H_(6)`
`Al_2Cl_6`
`H_3PO_3`
`H_3BO_3`

Solution :`{:(B_2H_6,-sp^2),(Al_2Cl_6-,sp^3):}}`VACANT ORBITAL
`H_(3)PO_3 -sp^3` no vacant p- orbital
`H_3 BO_3-sp^2`
Discussion
15.

ln which of the following molecules, vacant orbitals cake part in hybridization?

Answer»

`B_(2)H_(6)`
`Al_(2)Cl_(6)`
`H_(3)PO_(3)`
`H_(3)BO_(3)`

SOLUTION :`{:(B_(2)H_(6)-SP^(3)),(Al_(2)Cl_(6)-sp^(3)):}}` VACANT orbital.
`H_(3)PO_(3)- sp^(3)` no vacant p - orbital
`H_(3)BO_(3)-sp^(2)` hybridisation
Discussion
16.

In which of the following molecules the central atom does not have sp^(3) hybridization ?

Answer»

`NH_(4)^(+)`
`CH_(4)`
`SF_(4)`
`BF_(4)^(-)`

Solution :`SF_(4)`
(i) `NH_(4)^(+) : sp^(3)` hybridization
(ii) `CH_(4) : sp^(3)` hybridization
(iii) `SF_(4) : sp^(3) d ` dehybridization
(iv) `BF_(4)^(-) : sp^(3)` hybridization
`therefore ` Correct ANSWER : (C)
Discussion
17.

In which of the following molecules, sigma 2p_(z) molecular orbital is filled after pi 2p_(x) and pi 2p_(y) molecular orbitals ?

Answer»

`O_(2)`
`Ne_(2)`
`N_(2)`
`F_(9)`

Solution :`N_(2)`
Total number of electrons present in `N_(2)` molecule is 14. The electronic configuration of `N_(2)`molecule will be ,
`sigma 1s^(2), sigma^(**) , sigma 2s^(2) ,sigma^(**) 2s^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2) , pi 2p_(z)^(2)`
The increasing order of energies of various molecular orbitals for `O_(2) and F_(2)` is given below `sigma 1s lt sigma^(**) lt sigma 2s lt sigma^(**) 2s lt sigma 2p_(z) lt (pi 2p_(x) = pi 2p_(y)) lt (pi^(**) 2p_(x) = pi^(**) 2p_(y) ) lt sigma^(**) 2p_(z)`
HOWEVER, this sequence of energy levels of MO is not CORRECT for the remaining MOLECULES such as `Li_(2) , Be_(2) , B_(2) , C_(2) and N_(2).` for these molecules, the increasing order of energies of various MO is
`sigma 1s lt sigma^(**) 1s lt sigma 2s lt sigma^(**) 2s lt (pi 2p_(x) = pi 2p_(y)) lt sigma 2p_(z) lt (pi^(**) 2p_(x) = pi^(**) 2p_(y)) sigma 2p_(z)`
Discussion
18.

In which of the following molecules,sigma 2p_(z) molecular orbital is filled after pi 2p_(x) and pi 2p_(y) molecular orbitals ?

Answer»

`O_(2) `
`Ne_(2)`
`N_(2)`
`F_(2)`

SOLUTION :In `N_(2) , sigma _(2_(p_(z))) ` is FILLED after `pi_(2_(p_(x)) and pi_(2_(p_(y)))` .
Discussion
19.

In which of the following molecules, sigma bonds formed by the overlap of sp^3 d and P orbitals are absent ?

Answer»

`PCl_5`
`ClF_3`
`SbCl_5`
`HclO_4`

ANSWER :D
Discussion
20.

In which of the following molecules pi- electron density in ring is minimum

Answer»




ANSWER :D
Discussion
21.

In which of the following molecules pi- electron density in ring is maximum :

Answer»




ANSWER :B
Discussion
22.

In whichof thefollowingmoleculesor ionsthe resonanceeffectis NOTPresent

Answer»




ANSWER :B
Discussion
23.

In which of the following molecules/ions BF_3,NO_2^(-), NH_2^(-) and H_2O, the central atom is sp^2 hybrized ?

Answer»

`NO_2^(-) and NH_2^(-)`
`NH_2^(-) and H_2O`
`NO_2^(-) and H_2O`
`BF_3 and NO_2^(-)`

ANSWER :D
Discussion
24.

In which of the following molecules / ions BF_(3), NO_(2)^(-), H_(2) the central atom is sp^(2) hybridised ?

Answer»

`NH_(2)^(-)and H_(2)O`
`NO_(2)^(-) and H_(2)O`
`BF_(3) and NO_(2)^(-)`
`BF_(3)and NH_(2)^(-)`

Solution :CENTRAL ATOM `sp^(2)` hybridised
`NO_(2)^(-)` - Central stom `sp^(2)` hybridised
`BF_(3)` - Central atom `sp^(2)` hybridised
`NH_(2)^(-)` - Central atom `sp^(3)` hybridised
Discussion
25.

In which of the following molecules chiral centre(s) is/are not present

Answer»




SOLUTION :
in this COMPOUND CHIRAL CENTER is not PRESENT
Discussion
26.

In which of the following molecules are all the bond not equal ?

Answer»

`AIF_(3)`
`NF_(3)`
`CIF_(3)`
`BF_(3)`

SOLUTION :
Discussion
27.

Which one of the following molecules has all the effects, namely inductive, mesomeric and hyperconjugative?

Answer»




ANSWER :C
Discussion
28.

In which of the following molecules , all atoms are co-planar ?

Answer»




both `(a)` and `(B)`

ANSWER :A::B::D
Discussion
29.

In which of the following molecules, all atoms are coplanar ?

Answer»




Solution :BIPHENYL, i.e., option (a) is CORRECT since all the carbon are `SP^(2)`-hybridized.
Discussion
30.

In which of the following molecules all atoms are co planar

Answer»




both (a) and (B)

ANSWER :a
Discussion
31.

In Which of the following molecule would you expect the introgen to nitrogen bond to be longest ?

Answer»

`N_(2)O`
`N_(2)O_(4)`
`N_(2)H_(4)`
`N_(2)`

SOLUTION :
Thus , N-N bond in `N_(2) O_(4)` is longest and hence
very weak butthree is no SATISFACTORY EXPLANATION
for it .
` (N-=N)` has shortest bondlength because of triple bond)
Discussion
32.

In which of the following molecule/ion aU the bonds are not equal ?

Answer»

`XeF_(4)`
`BF_(4)^(-)`
`C_(2)H_(4)`
`SiF_(4)`

Solution :`C_(2)H_(4)`
`XeF_(4) rArr ` 4bp + 2l `rArr` square planar `rArr` all bonds are equivalent
`BF_(4)^(-) rArr` bp + 0lp tetrahedral (all bonds are EQUAL )
bond is not equal to C-H bond
`SiF_(4) rArr 4 " bp" + 0lp rArr`tetrahedral (all bonds are equal)
So, in `C_(2)H_(4)` all the bonds are not equal .
Discussion
33.

In which of the following molecule or ion the hybridisation state ofo the N-atom is sp-

Answer»

`NO_(2)^(+)`
`NO_(2)^(-)`
`NO_(3)^(-)`
`NO_(2)`

SOLUTION :In `NO_(2)^(+)` ION, N ATOM is sp-hydridised. O=`overset(o+)(N)=O`
Discussion
34.

In which of the following molecule/ion all the bonds are not equal ?

Answer»

`XeF_(4)`
`BF_(4)^(-)`
`C_(2) H_(4)`
`SiF_(4)`

Solution :`C_(2) H_(4) ` is . Thus , there are two TYPES of bonds present , VIZ. C = C and C-H
Discussion
35.

In which of the following mixtures summation of molarity of cation(s) in the resulting solution is less than 1?

Answer»

`NHO_(3)(0.1 M,10 ML) + NaOH (1 M, 10 mL)`
`NHO_(3)` (0.1 M, 10mL)+`(NHO_(3)` (1.1 M, 10 mL)
NaOH (4%(w/w), 10 mL sp.gr.=1.2) + NaOH [4% (w/w) , 10mL, sp.gr.=12]
`AgNO_(3)` (1M, 10 mL) + NaCl(2M, 10 mL)

Answer :A::B
Discussion
36.

In which of the following minerals, Al is not present

Answer»

Cryolite
Mica
FELDSPAR
Fluorspar

Solution :Fluorspar `(CaF_(2))` does not contain aluminium. Feldspar `(K_(2)O.Al_(2)O_(3).6H_(2)O)`, mica `(KAl_(3)Si_(3)O_(10)(OH)_(2))` and cryolite `(Na_(3)AlF_(6))` contain aluminium.
Discussion
37.

In which of the following mineral aluminium is not present ?

Answer»

Cryolite
Mica
Feldspar
Fluorspar

Solution :ARGENTITE `(Ag_(2)S)` is not an OXIDE ORE. ]
Discussion
38.

In which of the following Lanthanoids oxidation state + 2 is most stable ?

Answer»

Ce
Eu
Tb
Dy

Answer :B
Discussion
39.

In which of the following is (are) the correct order of bond lengths :

Answer»

`C-C GT C=Cgt CequivC gt C EQUIV N`
`C=N gt C=O gt C=C`
`C=Cgt C=N gt C=O`
`C-C gt C=C gt C equiv C gt C-H`

SOLUTION :A) `C- C gt C = C gt C -= C gt C -= N`
C) `C = C gt C = N gt C = O`
D) `C - C gt C = C gt-= C gt C-H`
Discussion
40.

In which of the following ions oxygen is more electronegative ?

Answer»

`CLO^(-)`
`ClO_(2)^(-)`
`ClO_(3)^(-)`
`ClO_(4)^(-)`

SOLUTION :`ClO_(4)^(-)` is more electroneative.
Discussion
41.

In which of the following ionisation processes, the bond order has increased and the magnetic behaviour has changed?

Answer»

`N_(2)toN_(2)^(+)`
`C_(2) to C_(2)^(+)`
`NO to NO^(+)`
`O_(2) to O_(2)^(+)`

ANSWER :C
Discussion
42.

In whichof the following inoization processes, the bond order has increased and the magnetic behaviour has changed ?

Answer»

`N_(2) to N_(2)^(+)`
`C_(2) to C_(2)^(+)`
`NO to NO^(+)`
`O_(2) to O_(2)^(+)`

Solution :`N_(2) (B . O. = 3 ) to N_(2)^(+)` (B. O. = 2.5)
`C_(2) (B. O .= 2 ) to C_(2)^(2+) (B.O. = 1.5)`
`NO (KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(X))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)`,
B . O . = 2.5 PARAMAGNETIC ) `to NO^(+)`
`(KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)`, B.O. = 3, DIAMAGNETIC )
`O_(2) (B.O. = 2 ` , paramagnetic) `to `
`O_(2)^(+) `(B .O. = 2. 5 paramagnetic)
Discussion
43.

In which of the following industries Flyash is produced as waste ?

Answer»

FERTILIZER INDUSTRY
Detergent industry
THERMAL POWER industry
Dairy industry

Solution :Thermal power industry
Discussion
44.

In which of the following hydrides, the law of constant composition does not hold good

Answer»

SALINE HYDRIDES
INTERSTITIAL Hydrides
Covalent Hydrides
MOLECULAR Hydrides

Answer :B
Discussion
45.

In which of the following hyperconjugation is involved

Answer»

`CH_(3)CH_(2)-CH=CH_(2)`

`CH_(3)-CH=CH_(2)`

ANSWER :A::B::C
Discussion
46.

In which of the following hydride law of constant composition does not hold good.

Answer»

`NAH`
`MgH_2`
`LIH`
`ZRH`

ANSWER :D
Discussion
47.

In which of the following has only one pi bond? (a) CH_(3)COCH_(3) (b) CH_(3)CHO (c ) CH_(3)CONH_(2) (d) C_(2)H_(2) (e ) C_(2)H_(4) (f) CH_(3)CH= CH_(2) (g ) CH_(3) - CH= CHCN (h) CH_(3)COOH (i) C_(6)H_(5) COOH

Answer»

SOLUTION :Only one `pi` bond PRESENT in (a), (b), (C ), ( E), (F)
Discussion
48.

In which of the following homolytic bond fission takes place ?

Answer»

Alkaline HYDROLYSIS of ETHYL chloride
Addition of `HBR` to double bond
Photochlorination of methane
Nitration of benzene.

Answer :C
Discussion
49.

In which of the following has minimum torsional strain and minimum vander wall strain.

Answer»

I
II
III
IV

Answer :B
Discussion
50.

In which of the following has minimum torsional strain and minimum Vander waal strain.

Answer»

I
II
III
IV

Solution :Staggard has MINIMUM torsional (electron-electron repulsions) and vander WAAL STRAIN (repulsions AMONG bulky groups)
Discussion