52671 + Interview Questions in Chemistry in Class 11

1.	Ionic radil is // are :
Answer» directly PROPORTIONAL to effective nuclear charge directly proportional to square of effective nuclear charge inversely proportional to effective nuclear charge inversely proportional to square of effective nuclear charge Solution :`["IONIC RADIUS"prop(1)/(("Effective Nuclear charge")^(2))]`

Discussion

2.	lonic radii (in oversetoA) of As^(3+), Sb^(3+) and Bi^(3+) follow the order
Answer» `As^(+3) GT SB^(+3) gt BI^(+3) ` `Sb^(+3) gt Bi^(+3) gt As^(+3)` `Bi^(+3) gt As^(+3) gt Sb^(+3) ` `Bi^(+3) gt Sb^(+3) gt As^(+3)` ANSWER :D

Discussion

3.	Ionic radii vary in....
Answer» inverse proportion to the EFFECTIVE nuclear CHARGE. inverse proportion to the square of effective nuclear charge. DIRECT proportion to the screening effect direct proportion to the square of screening effect. SOLUTION :Ionic RADIUS decreases as the effective nuclear charge increases Ionic radius `prop (1)/("effective nuclear charge")` Further, ionic radius increases as the screening effect increases. Ionic radius a screening effect. Ionic radius`prop` screening effect

Discussion

4.	Ionic radii of (1) Ti^(4+) lt Mn^(7+) (2) ""^(35)Cl^(-) lt ""^(37)Cl^(-) K^(+) gt Cl^(-) Pt^(3+) gt P^(3+)
Answer» Solution :(1) Since `TI^(4+) and Mn^(7+)` are isoelectronic, hence, `Mn^(7+) lt Ti^(4+)`. (2) `""^(35)CL^(-) and ""^(37)Cl^(-)` are isotopes, hence,`""^(35)Cl cong ""^(37)Cl^(-)` (3) Again, `K^+ and Cl^(-)` are isoelectronic, hence, `K^+ lt Cl^(-)` (4) `P^(3+)` has 12 electrons and 15 protons, while `P^(5+)` has 10 electrons and 15 protons, hence `P^(5+) lt P^(3+)`

Discussion

5.	Ionic radii of zirconium and hafnium become almost identical because
Answer» They are 'd' block ELEMENTS They BELONGS to the same Of INCREASED nuclear charge Of Lanthanide CONTRACTION Answer :D

Discussion

6.	Ionicradii vary in
Answer» inverseproportion to theeffectivenuclear charge inverse PROPORTION to THESQUARE of effectivenuclearcharge directproportionto thescreeningeffect directproportionto thesquareof screeningeffect. Solution :Ionicradiusdecreasesas the effectivenuclearcharge increases.Thusoption (a) iscorrectwhileoption(B) isincorrect. furtherionicradiusincreases as the screeningeffectincreases. In otherwordsoption (d)is correctwhileoption(d) isincorrect.

Discussion

7.	Ionic radii are
Answer» Inversly PROPORTIONAL to EFFECTIVE NUCLEAR charge. Inversely proportional to SQUARE of effective nuclear charge. Directly proportional effective nuclear charge. Directly proportional to square of effective nuclear charge. Answer :a

Discussion

8.	Ionic product of water...........with increase of temperature.
Answer» ANSWER :INCREASES

Discussion

9.	Ionic product of water at 310 K is 2.7xx10^(-14) .What is the pH of neutral water at this temperature ?
Answer» Solution :Calculation `[H^+]` : There is FOLLOWING EQUILIBRIUM in water. `H_2O_((l))+ H_2O_((l)) =H_3O_((aq))^(+) + OH_((aq))^(-)` `K_W=[H_3O^+][OH^-]= 2.7xx10^(-14)` but `[H_3O^+]=[OH^-]` `THEREFORE [H_3O^+]^2=2.7xx10^(-14)` `therefore [H_3O^+]= sqrt(2.7xx10^(-14)) =1.6432xx10^(-7)` Calculation of pH : pH=-log `[H^+]` =-log `(1.6432xx10^(-7))` =-(0.2157-7.0)=6.7843

Discussion

10.	Ionic mobility of which of the following alkali metal ions is lowest when aqueous solution of their salts are put under an electric field ?
Answer» K RB LI Na Solution :`Li^(+)` being the smallest alkali metal cation is most HIGHLY hydrated . As a result , the mass of the hydrated species is the highest and its mobility in the electric field is the lowest .

Discussion

11.	Ionic hydrides react with water to give
Answer» BASIC SOLUTION Acidic solution NEUTRAL solution Hydride ion Answer :A

Discussion

12.	Ionic hydrides are usually
Answer» GOOD electrically conductors when SOLID easily reduced good reducing AGENTS liquid at ROOM temperature. Solution :Ionic HYDRIDES are good reducing agents.

Discussion

13.	Ionic hydrides are usallly
Answer» GOOD CONDUCTORS of ELECTICITY in SOLID state volatile non-crystalline stoichiometic compounds Answer :D

Discussion

14.	Ionic hydrides are frequently used to remove last traces of water from organic compounds. How does it happen ? Explain.
Answer» SOLUTION :`H^(-)` being is STRONG Bronsted base REACTS with `H_(2)O` READILY liberating `H_(2)` gas.

Discussion

15.	Ionic hydride contains ......... property.
Answer» Crystal Solid non-valatile All of these Answer :D

Discussion

16.	Ionic hydrides are formed by
Answer» halogens chalogens inert gases GROUP one elements Solution :EG., Sodium hydride `(NA^(+)H^(-))`

Discussion

17.	Ionic, covalent, dative and hydrogen bonds are present in
Answer» ICE `BeSO_4, 4H_2O` `CuSO_4 5H_2O` `BaCl_2.2H_2O` Solution :`CU^(2+) SO_4^(2-)` bond ionic in `SO_4^(2-) S-O` bond is COVALENT. `H_O` molecules are ligands, so they form DATIVE bonds.

Discussion

18.	Ionic compounds are insoluble in ether.
Answer» Solution :Ionic compound does not ionize in ether i.e. ether cannot SEPARATE the CATIONS and ANIONS of ionic SOLIDS.

Discussion

19.	Ionic bond is defined as the electrostatic force of attraction holding the oppositely charged ions. Ionic compounds are mostly crystalline solids having high melting and boiling points, electrical conductivity in molten state, solubility in water etc., Covalent bond is defined as the force which binds atoms of same or different elements by mutual sharing of electrons in a covalent bond. Covalent compounds are solids, liquids or gases. They are low melting and boiling point compounds. They are more soluble in non polar solvents. Examples of covalent compounds are
Answer» UREA BARIUM CHLORIDE Sodium chloride CALCIUM fluoride ANSWER :A

Discussion

20.	Ionic bond is defined as the electrostatic force of attraction holding the oppositely charged ions. Ionic compounds are mostly crystalline solids having high melting and boiling points, electrical conductivity in molten state, solubility in water etc., Covalent bond is defined as the force which binds atoms of same or different elements by mutual sharing of electrons in a covalent bond. Covalent compounds are solids, liquids or gases. They are low melting and boiling point compounds. They are more soluble in non polar solvents. The valence electrons not involved in fonnation of covalent bonds are called
Answer» Bond pairs LONE pairs Unshared pairs NONE of these ANSWER :C

Discussion

21.	Ionic bond is defined as the electrostatic force of attraction holding the oppositely charged ions. Ionic compounds are mostly crystalline solids having high melting and boiling points, electrical conductivity in molten state, solubility in water etc., Covalent bond is defined as the force which binds atoms of same or different elements by mutual sharing of electrons in a covalent bond. Covalent compounds are solids, liquids or gases. They are low melting and boiling point compounds. They are more soluble in non polar solvents. The amount of energy released when one mole of ionic solid fonned by close packing of gaseous ions is called
Answer» Ionization ENERGY SALVATION energy LATTICE energy HYDRATION energy ANSWER :C

Discussion

22.	Iopic & covalent compounds are soluble in water due to
Answer» formation of H - bonds formation of dative bonds Ion-dipole INTERACTIONS dipole-dipole interactions Solution :a) c) Ion - dipole INTERACTINS between ionic of water MOLECULES

Discussion

23.	Ion with maximum number of unpaired electrons
Answer» `LU^(3+)` `Yb^(3+)` `Tm^(3+)` `GD^(3+)` ANSWER :D

Discussion

24.	One mole ion which has two moles of charge
Answer» sulphate nitrate nitrite phosphate Answer :A

Discussion

25.	............ion plays an important role as neuronal messenger.
Answer» `NA^(+)` `K^(+)` `CL^(-)` `MG^(+)` ANSWER :A

Discussion

26.	Ion having -2 chargeposseselectronconfiguration1s^(2)2s^(2) 2p^(6) statethe ion ?
Answer» Solution :`O^(2)`ion .As the chargeis -2so if twoelectrondeletedfromelectronconfigurationthan it willbe `1s^(2) 2S^(2) 2P^(4)`

Discussion

27.	Ion-dipole attractions are present in
Answer» Water NaCl + Water Benzene `C Cl_4+` Benzene Answer :B

Discussion

28.	Iodoform has antiseptic properties. Give one reason to support this.
Answer» SOLUTION :IODOFORM has antiseptic properties due to free LIBERATED IODINE.

Discussion

29.	Iodobenzene can be obtained by-
Answer» `C_(6)H_(6)+I_(2)to` `C_(6)H_(6)+I_(2)overset(HNO_(3))to` `C_(6)H_(5)N_(2)^(+)Cl^(-)+Klto` `C_(6)H_(6)+Hito` Solution :`HNO_(3)` oxidises HI to `HIO_(3)`. And PREVENT back work REACTION.

Discussion

30.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) lodometric titrations (ii) lodimetric titrations. (i) lodometric titrations : It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidic medium or, basic medium in which I_2oxidises into L. Now the liberated I_2can be titrated with Na_(2)S_(2)O_3 .solution. KI overset("Oxidising Agent")rarrI_(2)overset(Na_(2).S_(2)O_(3)//H^(+))rarrI^(-)+Na_(2)S_(4)O_6Although solid I_2is black and insoluble in water, but it converts into soluble I_3ions underset("Black")(I_2(s))+IhArrunderset("Dark brown")(I_3^(-))Starch is used as indicator near the end point or equivalence point. Even small amount of I_2molecules, gives blue colour with starch. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_2A solution containing Cu^(+2) and C_(2)O_(4)^(-2) ions M which on titration with M/10 KMnO_4requires 50 mL. The resulting solution is neutralized with K_(2)CO_(3)then treated with excess of KI. M The liberated I_2required 25 mL M/10 Na_(2)S_(2)O_3in acidic solution, then what is the difference of the number of m mole of Cu^(+2) and C_(2)O_(4)^(-2)ions in the solution ?
Answer» 40 10 30 50 Solution : m mole of `KMnO_4`used `= 50xx(1)/10` = 5 m eq.of `KMnO_4`used (n f = 5 ) = 25 m eq. of m mole of `C_(2)O_4^(-2)` m mole of `C_(2)O_(4)^(2-)(n = 2) =(25)/2= 12.5`m eq. of `Na_(2)S_(2)O_3= 2.5`= m eq. of `CU^(+2)(n=1)`m eq . of `Cu^(+2)(n = 1) = 2.5`DIFFERENCE in NUMBER of m MOLES of `Cu^(+2)` and `C_(2)O_(4)^(2-) =12.5 -2.5 =10`

Discussion

31.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) lodometric titrations (ii) lodimetric titrations. (i) lodometric titrations : It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidic medium or, basic medium in which I_2oxidises into L. Now the liberated I_2can be titrated with Na_(2)S_(2)O_3 .solution. KI overset("Oxidising Agent")rarrI_(2)overset(Na_(2).S_(2)O_(3)//H^(+))rarrI^(-)+Na_(2)S_(4)O_6Although solid I_2is black and insoluble in water, but it converts into soluble I_3ions underset("Black")(I_2(s))+IhArrunderset("Dark brown")(I_3^(-))Starch is used as indicator near the end point or equivalence point. Even small amount of I_2molecules, gives blue colour with starch. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_2When 214 g of KIO_3reacts with excess of KI in presence of H^(+)then it produces I_2Now I_2is completely reacted with 1 MNa_(2)S_(2)O_3solution in basic medium, where it converts into SO_4^(-2)ions. Then what volume of Na_(2)S_(2)O_3is needed to react the end point of the reaction?
Answer» 500 ml 800 ml 1500 ml 750ml Solution :`IO_(3)^(-)+5I^(-) +2H^(+)rarr3I_2+3H_2O` 214 g `KIO_3=1` mol of `KIO_3` mole of `I_2` (in the balanced chemical reaction ) = 6 EQ. of Let the vol.of `I_2` (n f = 2) = 6000 m eq. of `I_2` Let the vol of `Na_(2)S_(2)O_(3)=vmL`. then `(v xx 1 xx 8) = 6000 , v = 750 mL`

Discussion

32.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) lodometric titrations (ii) lodimetric titrations. (i) lodometric titrations : It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidic medium or, basic medium in which I_2oxidises into L. Now the liberated I_2can be titrated with Na_(2)S_(2)O_3 .solution. KI overset("Oxidising Agent")rarrI_(2)overset(Na_(2).S_(2)O_(3)//H^(+))rarrI^(-)+Na_(2)S_(4)O_6Although solid I_2is black and insoluble in water, but it converts into soluble I_3ions underset("Black")(I_2(s))+IhArrunderset("Dark brown")(I_3^(-))Starch is used as indicator near the end point or equivalence point. Even small amount of I_2molecules, gives blue colour with starch. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_2When 79.75 g of CuSO_4sample containing inert impurity is reacted with KI, the liberated I, is reacted with 50 mL (1M) Na_(2)S_(2)O_3in basic medium, where it oxidises into SO_(4)^(2-) ions, and I_2reduces into I^(-)then what will be the % purity of CuSO_4in sample ?
Answer» `60%` `80%` `50%` `95%` Solution :m eq.of `CuSO_4`REACTED = m eq. of `Na_(2)S_(2)O_(2)`reacted (n-f-8) `w/(159.5)=(50xx1xx8)/1000` wt. of `CuSO_(4) = (7.975 xx 8) `g % purity of `CuSO_(4)=( 7.975 xx 8 xx100)/(79.75)=80%`

Discussion

33.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) Iodometric titrations (ii) Iodimetric titrations. (i) Iodometric titrations: It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidix medium or , basic medium in which I^(-) oxidises into I_(2). Now the liberated I_(2) can be titrated with Na_(2)S_(2)O_(3) solution. KI overset("Oxidising Agent")rarr I_(2) overset("Na_(2)S_(2)O_(3)//H^(+))rarr I^(-)+Na_(2)S_(4)O_(6) Although solid I_(2) is black and insoluble in water, but it converts into soluble I_(3) ions {:(I_(2)(s)+I^(-) hArr, I_(3)^(-)),("Black","dark brown"):} Strach is used as indicator near the end point or equivalence point. Even small amount of I_(2) molecules, gives blue colour with strach. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_(2). A solution containing Cu^(+2) and C_(2)O_(4)^(-2)ions M which on titration with M//10 KMnO_(4) requires 50mL. The resulting solution is neutralized with K_(2)CO_(3), then treated with excess of KI. M The liberated I_(2) required 25mL M//10 Na_(2)S_(2)O_(3) in acidic solution, then what is the difference of the number of m mole of Cu^(+2) and C_(2)O_(4)^(-2) ions in the solution?
Answer» 40 10 30 50 Solution :m moles of `KMnO_(4)` used `=50 xx (1)/(10) = 5` m eq. of `KMnO_(4)` used (n F = 5) = 25 m eq. of `C_(2)O_(4)^(-2)` m moles of `C_(2)O_(4)^(-2) (n = 2) = (24)/(2) = 12.5` m eq of `Na_(2)S_(2)O_(3) = 2.5 =m` eq. of `CU^(+2) (n = 1)` m eq. of `Cu^(+2) (n = 1) = 2.5` DIFFERENCEIN number of m moles of `Cu^(+2)` and `C_(2)O_(4)^(-2) = 12.5 - 2.5 = 10`

Discussion

34.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) Iodometric titrations (ii) Iodimetric titrations. (i) Iodometric titrations: It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidix medium or , basic medium in which I^(-) oxidises into I_(2). Now the liberated I_(2) can be titrated with Na_(2)S_(2)O_(3) solution. KI overset("Oxidising Agent")rarr I_(2) overset("Na_(2)S_(2)O_(3)//H^(+))rarr I^(-)+Na_(2)S_(4)O_(6) Although solid I_(2) is black and insoluble in water, but it converts into soluble I_(3) ions {:(I_(2)(s)+I^(-) hArr, I_(3)^(-)),("Black","dark brown"):} Strach is used as indicator near the end point or equivalence point. Even small amount of I_(2) molecules, gives blue colour with strach. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_(2). When 79.75g of CuSO_(4) sample containing inert impurity is reacted with KI, the liberated I_(2) is reacted with 50mL (1M) Na_(2)S_(2)O_(3) in basic medium, where it oxidises into SO_(4) ions, and I_(2) reduces into I^(-), then what will be the % purity of CuSO_(4) in sample?
Answer» `60%` `80%` `50%` `95%` Solution :m EQ of `CuSO_(4)` reacted = m eq of `Na_(2)S_(2)O_(3)` reacted (n-f=8) `(w)/(159.5) = (50 xx 1 xx 8)/(1000)` wt of `CuSO_(4) = (7.975 xx 8)g` `%` purity of `CuSO_(4) = (7.975 xx 8 xx 100)/(79.75) = 80%`

Discussion

35.	Iodine titrations: Compounds containing iodine are widely used in titrations, commonly known as iodine titration. It is of two kinds: (i) Iodometric titrations (ii) Iodimetric titrations. (i) Iodometric titrations: It is nothing but an indirect method of estimating the iodine. In this type of titration, an oxidising agent is made to react with excess of KI, in acidix medium or , basic medium in which I^(-) oxidises into I_(2). Now the liberated I_(2) can be titrated with Na_(2)S_(2)O_(3) solution. KI overset("Oxidising Agent")rarr I_(2) overset("Na_(2)S_(2)O_(3)//H^(+))rarr I^(-)+Na_(2)S_(4)O_(6) Although solid I_(2) is black and insoluble in water, but it converts into soluble I_(3) ions {:(I_(2)(s)+I^(-) hArr, I_(3)^(-)),("Black","dark brown"):} Strach is used as indicator near the end point or equivalence point. Even small amount of I_(2) molecules, gives blue colour with strach. The completion of the reaction can be detected when blue colour disappears at the and point. In iodimetric titration, the strength of reducing agent is determined by reacting it with I_(2). When 214g of KIO_(3) reacts with excess of KI in presence of H^(+), then it produces I_(2). Now I_(2) is completely reacted with 1M Na_(2)S_(2)O_(3) solution in basic medium, where it converts into SO_(4)^(-2) ions. then what volume of Na_(2)S_(2)O_(3) is needed to react the end point of the reaction?
Answer» 500ml 800ml 1500ml 750ml Solution :`IO_(3)^(-) +5I^(-) +2H^(+) RARR 3I_(2) +3H_(2)O` 214 g `KIO_(3) = 1` mole of `KIO_(3)` = 3 mole of `I_(2)` (in the balanced chemical reaction) = 6 eq. of `I_(2) (n f=2) = 6000` m eq. of `I_(2)` LET the vol of `Na_(2)S_(2)O_(3) =V mL`, then `(V xx 1 xx 8) = 6000, v = 750 mL`

Discussion

36.	Iodine titration can be iodemotric or iodimetric depending on using iodine directly or indirectly is an oxidising agent in the redox titration. a. Iodimetric titration in which a standard iodine solution is used as an oxidant and iodine is directly or indirectly titrated against a reducing agent. For example. 2CuSO_(4)+4KJtoCu_(2)I_(2)+2K_(2)SO_(4)+I_(2) b. Iodimetric procedures are used for the datermination of strength of reducing agent such as thiosulphates, sulphites, arsenties adn stanous chloride etc. by titrating them against standard solution of iodine in a burette. 2Na_(2)SO_(3)to2 NaI +Na_(2)S_(4)O_(6) Starch is used as indicator near the end point whilch form blue colour complex with I_(3)^(-). The blue colour disappeams whenthere is not more of free I_(2) . The volume of KI solutioin used for CuSO_(4) will be
Answer» 100 ml 40 ml 400 ml 200 ml Solution :EQ. of `S_(2)O_(3)^(-2)` = Eq. of `I^(-)` `1XX(100)/(1000)xx1=0.5xx1xxV` `V=0.2` lit implies `V=200ml`

Discussion

37.	Iodine solution is prepared by dissolving iodine in :
Answer» NAOH `Na_(2)CO_(3)` `H_(2)O` KI Solution :N//A

Discussion

38.	Iodine oxidises sodium borohydride to give
Answer» `B_2H_6` Sodium HYDRIDE HI `I_3^-` SOLUTION :The OXIDATION of sodium borohydride with iodine in digamy gives diborane. `2NaBH_4 + I_2 overset"DIGLYME"to B_2H_6+2NaI + H_2`

Discussion

39.	Iodine monochloride molecule is formed by the overlap of
Answer» s-s ORBITALS s-p orbitals p-p orbitals END to end P-p orbitals sideways Answer :C

Discussion

40.	Iodine monochloride molecle is formed by the overlap of
Answer» s-s ORBITALS s-p orbitals p-p orbitals END to end pp-orbitals sideways Answer :C

Discussion

41.	Iodine molecules are held in the crystals lattice by ______
Answer» LONDON FORCES DIPOLE -dipole interactions covalent BONDS coulombic forces Answer :a

Discussion

42.	Iodine molecules are held in the crystals lattice by ……..
Answer» London forces dipole-dipole interractions COVALENT BONDS COULOMBIC forces Answer :C

Discussion

43.	Iodine is moresoluble in water in the presence of potassium iodide. Why ?
Answer» Solution :In the PRESENCE of iodide, dipole is induced in IODINE. Due to the ION-induced dipole ATTRACTION, a complex ion, `I_(3)^(-)` is formed which INCREASES solubility.

Discussion

44.	Iodination of alkane is best carried out in the presence of
Answer» `H_2O` `HIO_3` `C_6H_6` `NH_4SH` ANSWER :B

Discussion

45.	Iodination of alkane is carried out in the presence of
Answer» Alcohol `NHO_3" or " HIO_3` Any REDUCING AGENT BENZENE Answer :B

Discussion

46.	Iodate oxidises chromic hydroxide and gives iodide and chromate in basic medium.
Answer» Solution :(a) The ionic SKELETON equation is written as `IO_(3)^(-) +Cr(OH)_(3) OVERSET(OH^(-))to I^(-)+CrO_(4)^(2-)` (b) Writing oxidation numbers `overset(+5)(I) overset(-2)(O_(3)^(-)) +overset(+3)(Cr) overset(-2 +1)(OH_(3)) to overset(-1)(I^(-))+overset(+6)(Cr) overset(-2) (O_(4)^(-2))` (c) Locating atoms undergoing change in oxidation numbers. `overset(+5)(IO_(3)^(-)) +overset(+3)(Cr(OH)_(3)) to overset(-1) (I^(-)) +overset(+6)(Cr) O_(4)^(-2)` (d) Dividing the reaction into two halves and balancing in ACIDIC medium, separately. (e) Equalising the ELEMENTS and adding the two halves `eq (a) xx 2+eq (b) xx 1," we get"` `2Cr(OH)_(3)+10OH^(-) to 6e^(-)+2CrO_(4)^(2-)+8H_(2)O` `IO_(3)^(-)+6H_(2)O+6e^(-) to I^(-)+6OH^(-)` `IO_(3)^(-)+2Cr(OH)_(3)+4OH^(-) to I^(-)+2CrO_(4)^(2-)+5H_(2)O` This is the balanced equation.

Discussion

47.	Inversion temperature of a gas is how many times the Boyle's temperature?
Answer» SOLUTION :`T_i = (2A)/(RB) T_b = a/(Rb)`.

Discussion

48.	Inversion temperature (Ti=2aRb) is defined as the temperature above which if gas is expandedadiabatically it gets warm up but if temperature of gas is lower than Ti then it will cool down. What willhappen to gas if it is adiabatically expanded at 50∘C if its Boyle's temperature is 20∘C
Answer» HEATING Cooling CONSTANT None Solution :`T_b = 290 K IMPLIES T_1 = 2 T_b = 580 K, 600 > Ti ` `:.` Heating.

Discussion

49.	Intramolecular hydrogen bondingis presentin
Answer» WATER o-nitrophenol p-nitrophenol methyl AMINE ANSWER :B

Discussion

50.	Intramolecular hydrogen bond is present in
Answer» orthohydroxy benzaldehyde parahydroxy benzaldehyde ethyl alcohol hydrogen fluoride Answer :A

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Ionic radil is // are :

lonic radii (in oversetoA) of As^(3+), Sb^(3+) and Bi^(3+) follow the order

Ionic radii vary in....

Ionic radii of (1) Ti^(4+) lt Mn^(7+) (2) ""^(35)Cl^(-) lt ""^(37)Cl^(-) K^(+) gt Cl^(-) Pt^(3+) gt P^(3+)

Ionic radii of zirconium and hafnium become almost identical because

Ionicradii vary in

Ionic radii are

Ionic product of water...........with increase of temperature.

Ionic product of water at 310 K is 2.7xx10^(-14) .What is the pH of neutral water at this temperature ?

Ionic mobility of which of the following alkali metal ions is lowest when aqueous solution of their salts are put under an electric field ?

Ionic hydrides react with water to give

Ionic hydrides are usually

Ionic hydrides are usallly

Ionic hydrides are frequently used to remove last traces of water from organic compounds. How does it happen ? Explain.

Ionic hydride contains ......... property.

Ionic hydrides are formed by

Ionic, covalent, dative and hydrogen bonds are present in

Ionic compounds are insoluble in ether.

Iopic & covalent compounds are soluble in water due to

Ion with maximum number of unpaired electrons

One mole ion which has two moles of charge

............ion plays an important role as neuronal messenger.

Ion having -2 chargeposseselectronconfiguration1s^(2)2s^(2) 2p^(6) statethe ion ?

Ion-dipole attractions are present in

Iodoform has antiseptic properties. Give one reason to support this.

Iodobenzene can be obtained by-

Iodine solution is prepared by dissolving iodine in :

Iodine oxidises sodium borohydride to give

Iodine monochloride molecule is formed by the overlap of

Iodine monochloride molecle is formed by the overlap of

Iodine molecules are held in the crystals lattice by ______

Iodine molecules are held in the crystals lattice by ……..

Iodine is moresoluble in water in the presence of potassium iodide. Why ?

Iodination of alkane is best carried out in the presence of

Iodination of alkane is carried out in the presence of

Iodate oxidises chromic hydroxide and gives iodide and chromate in basic medium.

Inversion temperature of a gas is how many times the Boyle's temperature?

Inversion temperature (Ti=2aRb) is defined as the temperature above which if gas is expandedadiabatically it gets warm up but if temperature of gas is lower than Ti then it will cool down. What willhappen to gas if it is adiabatically expanded at 50∘C if its Boyle's temperature is 20∘C

Intramolecular hydrogen bondingis presentin

Intramolecular hydrogen bond is present in