Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The ratio of the rates of diffusion of helium and methane under identical condition of pressure and temperature will be _____

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SOLUTION :`(gamma_(He))/(gamma_(CH_4))= SQRT(16/4) = 2`.
2.

The ratio of the R.M.S. Velocities of Hydrogen and Oxygen molecules at the same temperature is

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`4:1` 
`1:4` 
`8:1` 
`1:8` 

ANSWER :A
3.

The ratio of the radius of the first Bohr orbit for the electron orbiting the hydrogen nucleus to that of the electron orbiting the deuterium nucleus (mass nearly twice that of the hydrogen nucleus) is approximately

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ANSWER :`(r_(1))/(r_(2)) = (1)/(1) = 1:1`
4.

The ratio of the radius of H atom an H^(+)ion is nearly

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10
`10^(2)`
`10^(3)`
`10^(5)`

ANSWER :D
5.

The ratio of the radii of the first three orbits in an atom of hydrogen is

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`1:4:9`
`9:4:1`
`1:2:3`
`3:2:1`

SOLUTION :`r_1 :r_2 :r_3 = 1:4:9`
6.

The ratio of the number of sp, sp^(2) and sp^(3)orbitals in the compound is CH_(3)-CH=C=CH-C -= C-CH_(3)

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`1:1:1`
`2:2:1`
`3:2:2`
`3:3:4`

ANSWER :D
7.

The ratio of the number of sp, sp2 and sp3 carbons in the compound given below is H_(2)C=C=CH-CH_3

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`1:2:1`
`2:1:1`
`1:1:2`
`1:23`

ANSWER :A
8.

The ratio of the number of hybrid and pure orbitals C_(6)H_(6) is

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`3:2`
`2:3`
`1:1`
`4:3`

Solution :BENZENE has 18 HYBRID ORBITALS and 12 pure orbitals
9.

The ratio of the molar volume of the real gas to the molar volume of the same gas if it were ideal is called ……………………..

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ANSWER :COMPRESSIBILITY FACTOR
10.

The ratio of the frequency corresponding to the third line in the Lymas series of hydrogen atomic spectrum to that of the first line in Balmer series of Li^(2+) spectrum is

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`(4)/(5)`
`(5)/(4)`
`(4)/(3)`
`(3)/(4)`

SOLUTION :For Lyman series, `n_(1) = 1`. For 3rd line of Lyman series `n_(2) = 4`
For hydrogen, Z = 1. Hence,
`v_(H) = (c)/(lamda) = c R_(H) Z^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`= c R_(H) (1)^(2) ((1)/(1) - (1)/(4^(2))) = (15)/(16) R_(H.c)`
for lithium, Z = 3
For 1ST line of Balmer series, `n_(1) = 2, n_(2) = 3`
`:. v_(Li) = c.R_(H) (3)^(2) ((1)/(2^(2)) - (1)/(3^(2)))`
`= c.R_(H) xx 9 xx (5)/(36) =(5)/(4) c.R_(H)`
`:. (v_(H))/(v_(Li)) = ((15//16) c R_(H))/((5//4) c R_(H)) = (15)/(16) xx (4)/(5) = (3)/(4)`
11.

The ratio of the kinetic energies of equal number of moles of H_(2)and He at the same temperature is

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`1:1`
`2:1`
`1: 2`
`4:1`

ANSWER :B
12.

The ratio of the average molecular kinetic energy of UF_(6) to that of H_(2). Both at 300K is:

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`1:1`
`7:2`
`176:1`
`2:7`

ANSWER :a
13.

The ratio of specific charge of an electron to that of a hydrogen ion is

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`1 : 1`
`2 : 1`
`1840 : 1`
`1 : 1840`

Solution :Specific charge is E/m. MAGNITUDE of charge on `e^(-)` and `H^(+)` is same. HENCE,
`((e//m)_(e))/((e//m)_(H^(+))) = (m_(H^(+)))/(m_(e)) = (1)/(1//840) = (1840)/(1) = 1840 : 1`
14.

The ratio of specific charge of a proton and an alpha-particle is

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`2:1`
`1:2`
`1:4`
`1:1`

ANSWER :B
15.

The ratio of slopes of K_("max") vs. v and V_0 vs. v curves in the photoelectric effect gives (v= frequency , K_("max") = maximum kinetic energy , V_0 = stopping potential)

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CHARGE of electron
planck.s CONSTANT
work FUNCTION
the ratio of plant.s constant of ELECTRONIC charge

Solution :
16.

The ratio of sigma and pi bonds in benzene is

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2
4
6
8

Solution :RATIO `= (SIGMA "bonds")/(pi "bonds") = (12)/(3) = 4`
17.

The ratio of root mean square velocity to average velocity of amolecule at a particular temperature is

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`1 : 1.086`
`2 : 1.86`
`1086 : 1`
`2.086 : 1`

Solution :(c ) For a gas at temperature T, M is constant.
`THEREFORE` Ratio of `(v_(rms))/(v_(AV))=SQRT((3RT)/(M))xxsqrt((piM)/(8RT))=(sqrt3xxsqrtpi)/(SQRT8)`
`(sqrt3xxsqrt3.14)/(sqrt8)=(1.086)/(1)`
18.

The ratio of rates of diffusion of two gases x and y under similar conditions is 2:1. What will be the ratio of their average speeds if gas X is at -23^@C and gas y is at 273^@C?

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Solution :RATIO of rates of diffusion ` (r_(x))/(r_(y)) = SQRT((M_(y))/(M_(x))) = 2 (or) (M_(y))/(M_(x)) = 4`
Ratio of average SPEEDS is given as, ` (barC_(X))/(C_(y)) = sqrt((T_(X))/(T_(y))(M_(y))/(M_(x)))`
substituting the VALUES, the ratio of speeds ` = sqrt((250)/(500 XX 4) = sqrt(2) : 1 = 1.414 : 1 (or) 1 : 707`
19.

The ratio of rates of diffusion of gases X and Y is 1 : 5 and that of Y and Z is 1 : 6. Then ratio of rates of diffusion Z and X is

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`1:30`
`1:6`
`30:1`
`6:1`

ANSWER :C
20.

The ratio of products, 1 - chloropropane to 2 - chloropropane respectively formed in the chlorination of propane if all the hydrogens are abstrated at equal rates is

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`50:50`
`25:75`
`75:25`
`12.5:87.5`

SOLUTION :`CH_(3)-CH_(2)-CH_(3)`
`6xx1=6, 2xx1=2`
`100xx6//8=75,100xx2//8=25`
21.

The ratio of pure orbitals to hybridized orbitals in ethylene is

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`2:3`
`3:1`
`1:1`
`1:3`

ANSWER :C
22.

The ratio of products, 1-chloropropane to 2-chloropropane respectively formed in the chlorination of propane if all the hdrogens are abstracted at equal rates is

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`50:50`
`25:75`
`75:25`
`12.5:87.5`

SOLUTION :`CH_(3)-CH_(2)-CH_(3)`
`6xx1=6,2xx1=2`
`100x6//8=75,100xx2//8=25`
23.

The ratio of number of sigma ( sigma) and pi (pi) bonds in 2-butynal is

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`8//3`
`5//3`
`8//2`
`9//2`

Solution :`CH_(3) - C -= C - underset(O)underset(||)(C)-H`
2 - butynal
no. of `sigma` BONDS = `8[4C - H, 3C - C, 1C - O]`
no. of `pi` bonds `= 3[2C - C ,1 C - O]`
`:. ` ratio `= (8)/(3)`
24.

The ratio of most probable velocity to the average velocity is

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`(pi//2)`
`2//pi`
`SQRT(pi)//2`
`2//sqrt(pi)`

ANSWER :B::C
25.

The ratio of masses of oxygen and nitrogen of a particular gaseous mixture is 1:4. The ratio of number of molecules is

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`1/4`
`7/32`
`1/8`
`3/16`

ANSWER :B
26.

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1:4 The ratio of number of their molecule is :

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`1:8`
`3:16`
`1:4`
`7:32`

ANSWER :D
27.

A gaseous mixture contains oxygen and nitrogen in the ratio 1 : 4 by weight. Therefore, the ratio of the number of molecules is:

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`1:4`
`7:32`
`1:8`
`3:16`

ANSWER :B
28.

The ratio of mass percent of C and H of an organic compound (C_(X)H_(Y)O_(Z)) is 6: 1. If one molecule of the above compound (C_(X) H_(Y)O_(Z)) contains half as much oxygen as required to burn one molecule of compound C_(X)H_(Y) completely to CO_(2) and H_(2)O. The empirical formula of compound C_(X) H_(Y)O_(Z) is.

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`C_(3)H_(6)O_(3)`
`C_(2)H_(4)O`
`C_(3)H_(4)O_(2)`
`C_(2)H_(4)O_(3)`

SOLUTION :`C_(X)H_(Y) + (X + (Y)/(4)) O_(2) RARR XCO_(2) + (Y)/(2)H_(2)O` according to given information `Z= (1)/(2) (2X + (Y)/(2))`
`:. X=2, Y= 4, Z=3`
29.

The ratio of mass percent of C and H of an organic compound (C_xH_yO_z) is 6 : 1. If one molecule of the above compound (C_xH_yO_z) contains half as much oxygen as required to burn one molecule of compound C_xH_y completely to CO_(2) and H_2O. The empirical formula of compound C_xH_yO_z is:

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`C_(3)H_(6)O_(3)`
`C_(2)H_(4)O`
`C_(3)H_(3)O_(2)`
`C_(2)H_(4)O_(3)`

Answer :D
30.

The ratio of magnetic moments of Fe(III) & Co(ll) is

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`sqrt5 :sqrt7`
`SQRT(35) : sqrt(15)`
`7:3`
`sqrt(24) : sqrt(15)`

Solution :`Fe^(3+)` has 5 unpaired `e^-, CO^(2+) ` has 3 unpaired `e^-`
`sqrt(N(n+2)) = sqrt(35) sqrt(n(n+2)) = sqrt(15)`
31.

The ratio of kinetic energies of lg of H_2 and 2g of CH_4 at the same temperature will be

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`1:4`
` 4:1 `
` 1:2 `
` 2:1`

ANSWER :B
32.

The ratio of K_(p)//K_(c) for reaction CO_((g))+1/2O_(2(g))hArrCO_(2(g)) is

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`R/T`
`RT`
`(RT)^(1//2)`
`(RT)^(-1//2)`

ANSWER :D
33.

The ratio of hydrogen, deuterium and tritium is

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`3:2:1`
`1:2:3`
`3:6:1`
`6:2:1`

ANSWER :B
34.

The ratio of hybrid to pure orbitals in benzene molecule is

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`3:2`
`2:3`
`1:2`
`4:1`

SOLUTION :`4:1(12:3)`
35.

The ratio of hybrid and unhybrid orbitals involved in the bonding of a benzene molecule is

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`3:2`
`1:1`
`3:1`
`1:3`

ANSWER :A
36.

The ratio of energies of photons with wavelengths 2000A^(0) and 4000A^(0) is

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`1:4`
`4:1`
`1:2`
`2:1`

SOLUTION :`(E_1)/(E_2) = (lambda_2)/(lambda_1)`
37.

The ratio of densities of hydrogen, deuterium and tritium under similar conditions of temperature and pressure

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`3:2:1`
`1:2:3`
`3:6:1`
`6:2:1`

ANSWER :B
38.

The ratio of densities of hydrogen, deuterium and tritium is

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`3:2:1`
`1:2:3`
`3:6:1`
`6:2:1`

ANSWER :B
39.

The ratio of de Broglic wavelengths of a deuterium atom to that of an a-particle, when the velocity of the former is five times greater than that of later, is

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4
`0.2`
`2.5`
`0.4`

ANSWER :D
40.

The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?

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`-1.76xx10^(8)` coulombs/g
`1.76xx10^(-8)` coulombs/g
`-1.76xx10^(10)` coulombs/g
`-1.76xx10^(-10)` coulombs/g

Answer :A
41.

The ratio of charge and mass would be greater for

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PROTON 
Electron 
NEUTRON 
Alpha particle 

ANSWER :B
42.

The ratio of cationic radius to anionic radius in an ionic crystals is greater than 0.732. Its coordination number is

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1
4
6
8

Solution :RADIUS ratio falls in the RANGE `0.732 - 1`, thus COORDINATION number must be 8.
43.

The ratio of average speed of an oxygen molcule to the RMS speed of a nitrogen molecule at the same temperature is

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`((3PI)/(7))^(1//2)`
`((7)/(3pi))^(1//2)`
`((3)/(7pi))^(1//2)`
`((7pi)/(3))^(1//2)`

ANSWER :B
44.

Comment over the following statement The ratio of atoms can vary in differently prepared samples of a compound.

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ANSWER :F
45.

The ratio of atomic mass of H and carbon is 1 : 3 in one hydrogen then its empirical formula is.....

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`CH_(4)`
`CH_(2)`
`C_(2)H_(2)`
`CH_(3)`

ANSWER :A::C::D
46.

The ratio of area covered by second orbital to the first orbital is

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`1 : 1`
`1 : 16`
`8 : 1`
`16 : 1`

Solution :`r_(n) prop n^(2) :.` AREA COVERED `(A_(n)) prop n^(4) " " ( :' " Area " = pi^(2))`
`:. (A_(2))/(A_(1)) = (2^(4))/(1^(4)) = (16)/(1)`
47.

The ratio of anion radius to cation radius of a crystal is 10 : 9.3. Then, the coordination number of the cation in the crystal is

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2
8
6
4

Answer :B
48.

The ratio between the root mean square velocity of H_(2) at 50 K and that of O_(2) at 800 K, is

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4
2
1
43469

Solution :(C ) `U_(rms)=sqrt((3RT)/(M))`
`THEREFORE``(U_(1))/(U_(2))=sqrt((3RT_(1))/(M_(1))xx(M_(2))/(3RT_(2)))=sqrt((T_(1)M_(2))/(T_(2)M_(1)))=sqrt((50xx32)/(800xx2))=1`
49.

The ratio between the root mean square velocity of H_(2) at 50 K and that of O_(2) at 800 K is:

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4
2
1
`1/4`.

SOLUTION :1
50.

The ratio between the rms velocity of H_(2) at 50K and that of O_(2) at 800K is:

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4
2
1
`(1)/(4)`

ANSWER :C