Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Thymine is

Answer»

nitrogenase, cytochromes
carboxy PEPTIDASE, HAEMOGLOBIN
haemocyanin, nitrogenase
haemoglobin, cytochromes

Solution :Haemoglobin and cytochromes are both conjugated PROTEINS containing HAEME (containingFe) as the prosthetic group.
2.

Using the standard electrode potentials given in thepredict if the reaction between the following if feasible : (a) Fe^(3+) (a) and I^(-)(aq), (b)ag^(+)(aq)and Cu(s), (c )Fe^(3+)(aq)and Cu (s) (d) Ag(s)and Fe^(3+)(aq),(e )Br_(2)(aq)and Fe^(2+)(aq)

Answer»

Solution :(a) The possible reaction between `Fe^(3+) (aq)` and `I^(-)(aq)` is
`2Fe^(3+)(aq)+2I^(-)(aq)rarr2Fe^(2+)(aq)+I_(2)(s)`
The above redox reaction can be split into the following two half reaction one involving oxidation and the other redcution wiritng electrode potential for each half RECTION from
OVERALL reaction `2Fe^(3+)(aq) +2I^(-)(aq)rarr2Fe^(2+)+I_(2)(s)`
since the EMF for the above reaction `Ag^(+)` (aq) and Cu (s) is
`Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2ag(s)`
The above redox reaction can be split into the following two half reaction writing electrode potential for each half reaction form we have
oxidation`Cu(s)rarrCu^(2)(aq)+2e^(-), E^(@)=-0.34 V`
Reduction `Ag^(+)(aq)+E^(-)rarrAg(s)xx2, E^(@)=+0.80 V`
overall reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+) (aq)+2 (s),E^(@)=+0.46V`
since the EMF of the above reaction comes out to be postive therefore the above reaction is feasible (c ) suppose the reaction between `Fe^(3+)(aq)rarr Cu^(aq)+2Ag(s),E^(@)=+0.46 V`
since the EMF of the above reaction comes oiut to be postive therefore to the following equatin
`Cu(s)+2Fe^(3+)(a)rarr3Cu(aq)+2Fe^(2+)(aq)`
the above reaction can be split into the following two half reaction wirting elecrode potential for each half reaction from we have
oxidation `Cu(s)rarrCu^(2+)(aq)+2e^(-) , E^(@)=-0.34 V`
Reduction `Fe^(3+)(aq)+E^(-)rarrFe^(2+)(aq)xx2 , E^(2)=+0.77V`
overall reaction `Cu(s)_+2Fe^(3+)(aq)rarrCu^(2+)+2Fe^(2+)(aq),E^(@)=+0.43 V`
since the EMF of the reaction is postive therefore the above reaction is feasible
alternatively if the raction between 1 `Fe^(3+)` (aQ) and Cu (s) occurs according to the followng equation
The EMF of the reaction comes out to be -ve -0.36 V(-0.34 V -0.034 V)and hence this rection is not feasible
(d) suppose the reaction between Ag(s) and`Fe^(3+)` (Aq) occurs accoding to the following eqation
The above reaction can be split intothe following two half rection writing electrode potential for each half reaction from we have
oxidation `Ag(s)rarrAg^(+)(aq)+e^(-), E^(@)=-0.80 V`
Reduction `Fe^(3+)(aq)+E^(-)rarrFe^(2+)(aq), E^(@)=+0.77 V`
since the EMF of the reaction is negative therefore the above reaction is not feasible
Alternatively the rection between Ag (s) and `Fe^(3+)` (aQ) MAY occur according to the following equation
`3Ag(s)+Fe^(3+)(aq)rarr3Ag^(+)(aq)+Fe(s)`
on similar lines we can calcualte the EMF of this reaction comes to be even followng equation
`Br_(2)(aq)+2Fe^(2+)(aq)rarr2Br^(-)(aq)+2Fe^(2+)(aq)`
the above reaction can be split in to the followng two half rection writing electrode potential for each half reaction from the we have
oxidation `Fe^(2+)(aq)rarrFe^(3+)(aq)+e^(-)xx2,E^(@)=-0.77 V`
Reduction : `Br_(2)(aq)+2e^(-)rarrBr^(-)rarr2Br^(-)(aq),E^(@)=+1.09 V`
overall reaction `2Fe^(2+)(aq)+Br_(2)(aq)rarr2Fe^(3+)(aq)+2 Br^(-)(aq)'E^(@)=+0.32 V` since the EMF for the above reaction is positive therefore this reaction is feasible
3.

Write a note about gas hydrates.

Answer»

Solution :Gas hydrates are a KIND of inclusion compounds where gas molecules are trapped in the crystal lattice having voids of RIGHT SIZE, without being chemically bonded. An intevesting hydrate is the of The HYDRONIUM ion `(H_3O)` in the gas phase. Similar to methane hydrate. Each water MOLECULE is bonded to three other in the dodecahedron.
4.

Which one of the following is manufactured in Haber's process?

Answer»

`SO_(3)`
`NH_(3)`
`N_(2)`
`H_(2)`

ANSWER :b
5.

What is the range of frequencles used in a microwave oven ?

Answer»

SOLUTION :The microwaves have approximately a frequency RANGE of `3xx 10^(10) " to " 3 XX 10^(12)HZ`
6.

Write preparation of Hydrogen peroxide.

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Solution :(i) Acidifying barium peroxide and removing excess water by EVAPORATION under reduced PRESSURE gives hydrogen peroxide.
`BaO_2. 8H_2O_((s)) + H_2SO_(4(aq)) to BaSO_(4(s)) + H_2O_(2(aq)) + 8H_2O_((l))`
(ii) Peroxodisulphate, obtained by electrolytic oxidation of acidified sulphate SOLUTIONS at high current density, on hydrolysis yields hydrogen peroxide.
`2HSO_(4(aq))^(-) overset"Electrolysis"to HO_3SOOSO_3H_((aq)) overset"Hydrolysis"to 2HSO_(4(aq))^(-) + 2H_((aq))^(+) + H_2O_(2(aq))`
This METHOD is now used for the laboratory preparation of `D_2O_2` .
`K_2S_2O_(8(s)) + 2D_2O_((l)) to 2KDSO_(4(aq)) + D_2O_(2(l))`
(iii)Industrially it is prepared by the auto-oxidation of 2-alklylanthraquinols.
(2-ethyl anthraquinol) `O_2"(air)"to H_2O_2`+ (Oxidised product.)
In this case 1% `H_2O_2` is formed. It is extracted with water and concentrated to ~30% (by mass) by distillation under reduced pressure.
It can be further concentrated to ~85% by careful distillation under low pressure. The remaining water can be frozen out to obtain pure `H_2O_2`.
7.

Which of the following represents schrodinger equations

Answer»

`(del^2/(delx^2)+del^2/(dely^2)+del^2/(delz^2))PSI=(8pi^2m)/h^2[E-V]Psi=0`
`hatHPsi=EPsi`
`(hatT=hatV)Psi=EPsi`
all of them

ANSWER :D
8.

Which of the following will not displace hydrogen?

Answer»

Ba
Pb
HG
Sn

Solution :(C ) Hg will not displace `H_(2)` as it LIES below hydrogen in the ELECTROCHEMICAL series
9.

Which of the following is most reactive in its reaction with C_(2)H_(4)?

Answer»

HI
HCl
HBr
all HAE EQUAL reactivity

Answer :A
10.

The standard enthalpiesof combustion of C_(6)H_(6) (l),C ( graphite) andH_(2)(g) are respectively -3270 kJ mol^(-1), - 394kJ mol^(-1) and-286 kJmol^(-1) . What is the standard enthalpy of formation ofC_(6)H_(6)(l)in kJ mol^(-1) /

Answer»

`- 48`
`+48`
`-480`
`+480`

Solution :(i) ` C_(6)H_(6)+ ( 15)/(2) O_(2) RARR 6CO_(2)+3H_(2) O, DeltaH= - 3270 kJ mol^(-1)`
(ii) `C+ O_(2) rarr CO_(2), DeltaH = -394kJ mol^(-1)`
(iii) `H_(2)+(1)/(2) O_(2) rarr H_(2)O,DetlaH=-286kJ mol^(-1)`
AIM `: 6C+ 3H_(2) rarrC_(6)H_(6) , DeltaH=?`
`6 XX`Eqn. (ii) `+ 3 xx ` Eqn. (iii) -Eqn. (i) ,gives required eqn.with `DeltaH =+ 48 kJ mol^(-1)`
11.

The SI units of the coefficient of viscosity is ………………………….. .

Answer»


ANSWER :`KG m^(-1)s^(-1)`
12.

Which one of the following molecular hydrides acts as a Lewis acid

Answer»

`NH_(3)`
`H_(2)O`
`B_(2)H_(6)`
`CH_(4)`

ANSWER :C
13.

Which one of the following represents 180g of water ?

Answer»

5 Moles of water
` 6 . 0 22 xx 10^(24)`molecules of water
` 180 xx 6 . 022 xx 10^(23)`molecules of water
90 moles of water

Answer :A::B::C::D
14.

Why a person suffering from high blood pressure is advised to take minimum quantity of common salt ?

Answer»

Solution :Osmotic pressure is directly proportional to the conecntration of SOLUTES our body FLUIDS contains a NUMBER of solutes. On large amount of salt ions entering into the body fluids therby raises the concentration of solute .As a result , osmotic pressure increase which may RUPTURE the bloodcells.
15.

What is the hybridisation state of benzyl carbonium ion ?

Answer»

`SP^(2)`
`SPD^(2)`
`sp^(3)`
`sp^(2)d`

ANSWER :A
16.

Which of the following substance is in liquid form at room temperature ?

Answer»

Methane
Hexane
Propane
Butane

ANSWER :B
17.

Which of the following reaction is incorrect according to thermodynamics ?

Answer»

`DELTA G^(@) = - nFE^(@)`
`Delta H = Delta E + P Delta V`
`K= e^(-Delta G //RT)`
`Delta G = Delta H + T Delta S`

Answer :D
18.

The wrong statement among the following regarding alkali metal halides is

Answer»

`Deltaf H^(0)` values becomes less negative from LITHIUM to caesium
For a GIVEN ALKALI metal `Deltaf H^(0)` is in the order fluoride `gt` chloride `gt` bromide `gt` iodide
When saturated aqueous solution of LiI and CsF are mixed , LiF and CsI are crystallised
Lithium HALIDES have more melting points than SODIUM halides

Answer :D
19.

Which among the following alkenes on reductive ozonolysis produces only propanone

Answer»

2-methylpropene
2-methylbut -2-ene
2,3-dimethylbut-2-ene
2,3-dimethylbut -2-ene

ANSWER :d
20.

Which of the following do not respond to flame test

Answer»

Be
Mg
Both (a) and (B)
Ca

Solution :IiA group elements (EXCEPT Be and Mg) impart a characteristic COLOUR to the BUNSEN FLAME. Be and Mg do not show any colour due to their small size and bind their electrons more strongly
21.

Which of the following acids (given below) react with NaHCO_(3) and liberate Co_(2)(g) ?

Answer»


ANSWER :(I,iii,IV,V,VI,VII)
22.

What happens when the concentration of H_(2) and I_(2) are increased in the reaction H_(2)+I_(2)hArr2HI ?

Answer»

Solution :According to Le Chatelier's principle, the effect of increases in concentration of a substance is to SHIFT the equilibrium in a direction that consumes the added substance.
Let us consider the REACTION
`H_(2)(G)+I_(2)(g)hArr2HI(g)`
The addition of `H_(2)` or `I_(2)` to the equilibrium mixture disturbs the equilibrium. In order to minimize the stress, the system shifts the reaction in a direction where `H_(2)` and `I_(2)` are consumed i.e., the formation of additional HI would balance the effect of added reactant. Hence, the equilibrium SHIS to the right (forward direction) i.e. the forward reaction takes place until the equilibrium is re-established. Similarly, REMOVAL of HI (product) also favours the forward reaction.
23.

Which among the following is correct about gamma-rays ?

Answer»

HIGH ENERGY electrons
Low energy electrons
High energy ELECTROMAGNETIC waves
High energy positrons

Answer :C
24.

Which orbitaJ has molecular symmetry ?

Answer»

`PI`
`pi^(**)`
`SIGMA`
`PSI^(**)`

SOLUTION :`sigma`
25.

There are three isotopes of hydrogen and three naturally occuring isotopes of oxygen (""^(16)O, ""^(17)O and ""^(18)O). How many kinds of water molecules are possible . Write their formulae.

Answer»

SOLUTION :18 . Their formulae are :
`H-""^(16)O-H, H-""^(17)O-H, H-""^(18)O-H, H-""^(16)O-D, H-""^(17)O-D,H-""^(18)O-D,H-""^(16)O-T,H-""^(17)O-T,H-""^(18)O-T, D-""^(16)O-D,D-""^(17)O-D,D-""^(18)O-D,T-""^(16)O-D,T-""^(17)O-D,T-""^(18)O-D,T-""^(16)O-T,T-""^(17)O-T,T-""^(18)O-T`
However, most abundant HEAVY water occuring in ordinary water is DEUTERIUM oxide, i.e., `D-""^(16)O-D`.
26.

Zn salt is mixed with (NH_(4))_(2)S of molarity 0.021M. What amount of Zn^(2+) will remain unprecipitated in 12 mL of the solution ? (K_(SP) "of ZxnS" = 4.51xx10^(-24))

Answer»


ANSWER :`1.677xx10^(-22)g//12mL;`
27.

Which of the following ions of element given violet colour in flame test?

Answer»

Ba
K
RB
NA

ANSWER :B
28.

The stability of dihalides of Si, Ge, Sn and Pbincreases steadily in the sequence

Answer»

`PbX_(2) LT lt SnX_(2)lt lt GeX_(2) lt lt SiX_(2)`
`GeX_(2) lt lt SiX_(2) lt lt SnX_(2) lt lt PbX_(2)`
`SiX_(2) lt lt GeX_(2)lt lt PbX_(2) lt lt SnX_(2)`
`SiX_(2) lt lt GeX_(2) lt lt SaX_(2) lt lt PbX_(2)`

SOLUTION :INERT paireffect becomesmore predominant downthe groupand hencethe stabilityof dihalidesincreasesdown the group, i.e,option (d) is correct.
29.

Which of the following halogens has great affinity for hydrogen?

Answer»

F
Cl
Br
I

ANSWER :A
30.

The temperature of K at which DeltaG =0 for a given reaction with DeltaH= -20.5 kJ mol^(-1)and DeltaS =- 50.0 JK^(-1)mol^(-1)

Answer»

`-410 `
`2.44`
`410`
`-2.44`

ANSWER :B
31.

Which one is usedas free radical initiator in polymerisation reaction ?

Answer»

ethylene
butyronitrile
azobisiso butronitrile
TRIPHENYL phospine

SOLUTION :N/A
32.

What is the wavelength for the electron accelerated by 1.0xx10^(4) volts?

Answer»

Solution :Step I.Calculation of the velocity of elctron
ENERGY (kinetic energy)of eectron`=1.0xx10^(4)`volts.
`=1.0xx10^(4)xx1.6xx10^(-19)J=1.6xx10^(-15)J`
`=1.6xx10^(-15)kgm^(2)s^(-2)`
or`(1)//(2) mv^(2)=1.6xx10^(-15)kgm^(2)s^(-2)`
or`v=9((2xx1.6xx10^(-15)kgm^(2)s^(-2))/(9.1xx10^(-31)kg))^(1//2)=5.93xx10^(7)MS^(-1)`
Step II. Calculation of WAVELENGTH of the electron
According to de Broglie equation,
`gamma=h/(mv),gamma=((6..626xx10^(-34)kgm^(2)s^(-1)))/((9.1xx10^(-31)kg)xx(5.93xx10^(7)ms^(-1)))=1.22xx10^(-11)m`
33.

Which colour is shown by Rubidium salts on flame test?

Answer»

RED violet
Violet
Blue violet
Dark red

ANSWER :A
34.

When pottassium permanganate acts as oxidising agent it is converted into MnO_(4)^(-2),Mn_(2)O_(3),MnO_(2)andMn^(+2) then calculate change in electrons.

Answer»

4, 3, 1, 5
1, 4, 3, 5
3, 4, 1, 2
3, 5, 1, 4

Answer :B
35.

Which process of purification is represented by the following equation underset("Impure")Ti+2I_(2) overset(250^(@)C)to Til_(4)overset(1400^(@)C)to underset("pure")Ti+2I_(2)

Answer»

Cupellation
Poling
VAN Arkel
Zone refining

Solution :The EQUATION is of Van - Arkel METHOD.
36.

Which one of the following is the correct statement for respiration in humans?

Answer»

Boric acid is a protonic acid
Beryllium exhibits coordination number of SIX
Chlorides of both beryllium and aluminium have BRIDGED CHLORIDE STRUCTURES in solid phase
`B_(2)H_(6)2NH_(3)` is known as 'inorganic benzene'

Answer :C
37.

What is the meaning of the boiling point of water is 100^@C ?

Answer»

Solution :In close vessel at `100^@C` temperature the vapour PRESSURE of water is ATMOSPHERE (1.013 BAR) and the equilibrium is ESTABLISHED between water and its vapour.
`H_2O_((l)) hArr H_2O_((g))`….(`100^@C` + 1.013 bar)
38.

Which one is biofertilizers ?

Answer»

RHIZOBIUM
Azotobacters
Both (A) and (B)
NONE of these

Solution :Both (A) and (B)
39.

Which of the following has activation effect on benzene ring ? -OH, -COCH_(3), -NO_(2), -NH_(2), -Cl, -Br, -NHCOCH_(3), -COOH

Answer»

Solution :Activator groups : -OH, `-NH_(2), -NHCOCH_(3)`
40.

What is [Ag^(+)] ina solution made by dissolving both Ag_(2)CrO_(4) and Ag_(2)C_(2)O_(4) untilsaturation is reachedwith respect to both salt ? [K_(sp) = (Ag_(2)C_(2)O_(4)) = 2 xx 10^(-11), K_(sp) (Ag_(2)CrO_(4)) = 2 xx 10^(-12)]

Answer»

`2.80 xx 10^(-4)`
`7.6 xx 10^(-5)`
`6.63 xx 10^(-6)`
`3.52 xx 10^(-4)`

Solution :`Ag_(2)CrO_(4)(s) hArr underset(2x+2y)((2AG)^(+)(aq.)) + underset(x)(CrO_(4)^(2-)(aq.))`
`Ag_(2)C_(2)underset(2y+2x)(O_(4)(s))hArr2Ag^(+)underset(y)((aq.))+C_(2)O_(4)^(2-)(aq.)`
`(K_(sp_(1)))/(K_(sp_(1))) = x/y = (2XX10^(-12))/(2 xx 10^(-11)) rArr = 0.1 `
`2 xx 10^(-11) = (2 x + 2y)^(2).y`
`2 xx 10^(-11) = 4.84y^(3)`
`y = 1.6 xx 10^(-4)`
`:. x = 0.16 xx 10^(-4)`
TOTAL`[Ag^(+)] = 2 x + 2y`
`= (2 xx 0.16 + 2 xx 1.6) xx 10^(-4) = 3.52 xx 10^(-4)`
41.

Which electron displacement effect explain the following correct orders of acidity of the carboxylic acids?

Answer»

Solution :`CH_(3)CH_(2)COOH gt (CH_(3))_(2)CHCOOH gt (CH_(3))_(3) CCOOH`
As the number of alkyl group increases, `+I` effect increase and it STRENGTHEN the `O-H` bond. i.e., `O-H` bond dissociation is very difficult.

Therefore `+I` effect explain the correct ORDERS of ACIDITY of the CARBOXYLIC ACIDS.
42.

Which one of the following species has tendency to show -I effect?

Answer»

`-CH_(3)`
`-CH_(2)-CH_(3)`
`-CH(CH_(3))_(2)`
`-C_(6)H_(5)`

ANSWER :D
43.

Which one of the following species has tendency to show +I effect?

Answer»

`-NH_(2)`
`-CI`
`-C_(6)H_(5)`
`-CH_(3)`

Answer :D
44.

Which of the following change requires a reducing agent

Answer»

`CrO_(4)^(2-)RARR Cr_(2)O_(7)^(2-)`
`BrO_(3)^(2-)rarr BrO^(-)`
`NH_(3)rarrNF_(3)`
`AL(OH)_(3)rarrAl(OH)_(4)^(-)`

Answer :B
45.

What will be value of Delta G^(@) for ice at 298 K temperature?

Answer»

`-ve`
0
none of these
`+ve`

ANSWER :A
46.

Which of the reaction are correct ?

Answer»




ANSWER :B,C
47.

When NiO is doped with a small quantity of Li_(2)O

Answer»

both CATION and ANION VACANCIES are generated
Shottky DEFECTS are generated
NiO BECOMES an n-type semiconductor
NiO becomes a p-type semiconductor

Answer :D
48.

What is the mass of the precipitate formed when 50 mL of 16.9 % solution of AgNO_(3) is mixed with 50 mL of 5.8 % NaCl solution ? (Ag = 107.8,N=14,O=16,Na=23,Cl=35.5)

Answer»

3.5 g
7 g
14 g
28 g

Solution :It is the CORRECT answer. For solutio, CONSULT Example 1.97
49.

Which one of the following is not present in trposphere ?

Answer»

`N_2O_2`
`CO_(2)`
`N_(2)`
Water VAPOURS

Solution :`N_(2)O_(2)`
50.

Which of the following pair of compounds does not undergo any chemical change on heating

Answer»

`MgCO_3,KHCO_3`
`Cs_2CO_3, KNO_2`
`Na_2CO_3, NaNO_3`
`Li_2CO_3, KNO_2`

ANSWER :B