Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which of the following salts will have the highest pH in water ?

Answer»

KCL
NaCl
`Na_(2) CO_(3)`
`CuSO_(4)`

Solution :KCl and NaCl are salts of strong acid and strong base. Their aqueous solutions will be neutral with pH = 7. `Na_(2)CO_(3)` is a salt of strong base (NaOH) and weak acid `(H_(2)CO_(3))`. Its solution will be BASIC with `pH gt 7. CuSO_(4)` is a salt of weak base, `CU(OH)_(2)` and strong acid, `H_(2)SO_(4)`. Its solution will be acidic with `pH lt 7`.
2.

Water softening by Clark's process uses

Answer»

`NaHCO_(3)`
`Ca(OH)_(2)`
`Ca(HCO_(3))_(2)`
`Na_(2)CO_(3)`

Answer :B
3.

What kind of molecules show disproportionation reactions ? Give one example of a compound each of nitrogen and phosphorus which show disproportionation reactions. Write chemical equation in each case.

Answer»

Solution :Compounds in which one of elements exists in three different OXIDATION STATES can show disproportionation reactions. For example,
`3Hoverset(+3)NO_(2)toHoverset(+5)NO_(3)+2overset(+2)NO+H_(2)O","4H_(3)OVERSET(+3)PO_(3)overset(Delta)to3H_(3)overset(+5)PO_(4)+overset(-3)PH_(3)`
4.

When potassium acetate is electrolysed, we get

Answer»

methane
ethane
acetylene
ethylene

Answer :B
5.

To study the decomposition of hydrogen iodide, a student fills an evacuated 3 litre flask with 0.3 mol of HI gas and allows the reaction to proceed at 500^(@)C. At eauilibrium he found the concentration of HI which is equal to 0.05 M. Calculate K_(C) and K_(P) for this reaction.

Answer»

Solution :`V=3L`
`[HI]_("initial")=(0.3" mol")/(3L)=0.1M`
`[HI]_(EQ)=0.05M`
`2HI(g)hArrH_(2)(g)+I_(2)(g)`

`K_(C)=([H_(2)][I_(2)])/([HI]^(2))`
`=(0.025xx0.025)/(0.05xx0.05)`
`K_(C)=0.25`
`K_(P)=K_(C)(RT)^(Deltang)`
`Deltan_(g)=2-2=0`
`K_(P)=0.25(RT)^(0)=0.25`
6.

Which of the following reagents can react with phenol to produce phenolphthalein ?

Answer»

phthalic anhydride/`H_(2)SO_(4)`
ethanoic anhydride/`H_(2)SO_(4)`
`CO_(2), C Cl_(4)`
potassium phthalimide

Solution :
7.

Which of the following is used as a source of O_(2) in space capsules, submarines etc?

Answer»

`K_(2)O`
`Na_(2)O_(2)`
`Li_(2)O`
`Na_(2)O`.

SOLUTION :`Na_(2)O_(2)` is used as a source of `O_(2)` in SPACE capsules and SUBMARINES
`2Na_(2)O_(2)+2CO_(2)rarr2Na_(2)CO_(3)+O_(2)`
8.

Whichobservatin arenotexplainby electronmagnetictheoryof physics ?

Answer»

Solution :(i) Thenatureof emissionof radiationfrom hotbodies( black- bodyradiation )
(II) Photoelecticeffect: Ejectionof electronsfrommetalsurfacewhenradiationstrikes
(III) Variationof heatcapacityof SOLIDS as afunctionof temperature .
(iv) Linespectraof atomswithspecialreferenceto hydrogen.
9.

Whatis aromatisation

Answer»

Solution :Alkanes with sixto TEN carbon atoms are converted into homologous of benzen at higher TEMPERATURE and in the PRESENCE of a cataylst this process is known as aromatisationfor example n hexane passed over `Cr_(2)O_(3)`supported on alumina at 873 GIVES benzene
10.

The values of van der Waals' constant 'a' for O_2, N_2, NH_3 " and " CH_4 " are " 1.360, 1.390, 4.170 " and " 2.253 L^2 " atm " mol^(-2) respectively. The most easily liquefiable gas among these is

Answer»

`N_2`
`NH_3`
`O_2`
`CH_4`.

SOLUTION :`NH_3`
11.

The two main chemicals responsible for the depletion of ozone layer are _________ and ____________

Answer»


ANSWER :NITRIC OXIDE, CHLOROFLUOROCARBONS
12.

The relative order of basicity of conjugate bases is

Answer»

`OH^(-) lt OR^(-) lt HC -= C^(-)`
`OH^(-) lt HC -= C^(-) lt OR^(-)`
`HC -= C^(-) lt OH^(-) lt OR^(-)`
`HC -= C^(-) lt OR^(-) lt OH^(-)`

Solution :Strong acid will have a WEAK conjugate BASE and vice versa (Bronsted-Lowery concept of acids-base).
Acidic charatcer of conjugate acids is
`H_(2)O gt ROH gt HC -= CH`
`:.` the order of basicity is
`underset("weakest base")(OH^(-)) lt underset("STRONGEST base")( RO^(-)lt HC -= C^(-))`
13.

Which of the following is an example of carbocyclic alicyclic compound?

Answer»

Pyrrole
Thiophene
Cyclopropane
Phenol

Answer :C
14.

When LiNO_(3) is heated, it gives oxide, Li_(2)O whereas otheralkali metals nitrates decompose to give corresponding

Answer»

NITRITE
peroxide
both nitrite and oxide
none of these

Answer :A
15.

What is Resonance structure ? Why the resonances structure required explain with' suitable example.OR Give resonance of O_(3) , its requirement, delimitation and advantages

Answer»

SOLUTION :Resonance STRUCTURES : Different Lewi , structure of single molecule / ion is KNOWN as resonance structure. According to the concep of resonance, whenever a single Lewis structure cannot describe a molecule accurately so mor than one Lewis structure means resonance structure describe.
Resonance structure of ozone `(O_(3))` : To draw resonance structure the position of nucleus of atom is not change. Every reasons structure the position of bonding and non-bonding electron is change but Lewis structure is not seen different. ·The different resonance structure is represented by a double HEADED arrow. All resonance structure are similar energy.
Two resonance structure of `O_(3)` molecule
(I) and (II) and (III) is resonance hybrid.

Limitation of resonance : Any one is not seen right structure. The O- O bond length is 148 and O = O bond length is 121 pm. Thus single and double bond length is not experimentally present in `O_(3)` .
`therefore ` Correct structure of `O_(3)` is not (I) and (II)
Resonance : Correct structure is resonance hybrid. Experimentally determined oxygen - oxygen (0 - 0) bond length in the `O_(3)` molecule are same 128 pm. So, (III) is a real or accurate structure of `O_(3)` in which single and double bond is not stable. Resonance structure are necessary because it GIVES correct different Lewis structure.
Orientation : Single assumption structure can.t give correct bond length & bond energy.
Advantage : It gives assumption of correct structure.
16.

when the electrons move towards the substituent attached to the conjugated system_______effect occurs .

Answer»

`-R`
`+R `
`-I`
`+I`

SOLUTION :N/A
17.

What is % W//W ?

Answer»



SOLUTION :The GM of SUBSTANCE in 100 gm solution is CALLED `% W//W`.
18.

Which of the following will have the lowest pH when one mole of each of the following is hydrolysed will water ?

Answer»

`(CH_(3)C)_(2)O`
`CH_(3)COCl`
`CH_(3)CONH_(2)`
`CH_(3)COOC_(2)H_(5)`

Solution :`CH_(3)COCl` is most EASILY HYDROLYSED and it gives HCl which is STRONG acid
19.

The temperature below which a gas obeys Joule- Thomoson effect is called ___________.

Answer»

BOYLE TEMPERATURE
INVERSION temperature
Transition temperature
Zeeman effect

Answer :B
20.

Which among the following is a set of nucleophiles ?

Answer»

`BF_3,H_2O,NH_2^-`
`AlCl_3,BF_3,NH_3`
`CN^-,RCH_2^-,ROH`
`H^+,RNH_3^+,:"CC"l_2`

SOLUTION :All can donate electrons.
21.

What electronic transition in Li^(+2) produces the radiation of the same wave length as the first line in the Lyman series of hydrogen ?

Answer»

N = 4 to n = 2
n = 9 to n = 6
n = 9 to n = 3
n = 6 to n = 3

Answer :D
22.

Which element do you think would have been names by-Lawrence Berkely Laboratory & Sseaborg's group?

Answer»

SOLUTION :(1) LAWRENCIUM, LR and BERKELIUM, Bk.
(2) Seaborglum, Sg.
23.

Which of the following is white ?

Answer»

`KMnO_(4)`
`K_(2)Cr_(2)O_(7)`
`KO_(2)`
None of these.

Solution :`KMnO_(4)` is DARK pink COLOURED solid due to pink `MnO_(4)^(-)` ion, `K_(2)Cr_(2)O_(7)` is ORANGE coloured solid due to `Cr_(2)O_(7)^(2-)` ion and `KO_(2)` is an orange yellow coloured solid.
24.

Which iscorrect statement about sigma - and po- molecular orbitals? Statementsare : pi- bonding orbitals are ungerade pi-antibonding orbitals are ungerade sigma-antibondding orbitals are gerade

Answer»

1 only
2 and 3 only
3 only
2 only

SOLUTION :` SIGMA`-ORBITALS are gerade , `sigma^(**)` are
ungerade, `PI` are ungerade whereas `pi^(**)` are gerade .
25.

Which of the following describes the following titration curve?

Answer»

A STRONG BASE is ADDED to a strong acid
A strong base is added to a WEAK acid
A strong base is added to a diopromatic acid
A strong base is added to a weak acid

Solution :N//A
26.

What are the raw materials needed for the manufacture of washing soda by Solvay process ?

Answer»

SOLUTION :`NACL , CaCO_(3) and NH_(3)`.
27.

The reagent used for converting acetylene to oxalic acid is

Answer»

`HgSO_(4)`/aqueous `H_(2)SO_(4)`
`HgSO_(4)//CH_(3)COOH`
`KMnO_(4)//KOH,25^(@)C`
`CrO_(3)//H_(2)SO_(4)`

Answer :C
28.

What is peroxide effect

Answer»

SOLUTION :The ADDITIONOF HBrto an alkanein the PRESENCEOF organicperoxidegivetheanti- Markovnikoffproduct.Thiscalledas PEROXIDEEFFECT
29.

What happens when ? (i) Quick lime is heated with coke ? (ii) Carbon monoxide reacts with CI_(5) (iii) Plants absorb CO_(2) ?

Answer»

SOLUTION :(i) `CaO +3C RARR underset (("CALCIUM Carbide")) (CaC_(2)+CO)`
(ii) `CO+CI_(2) rarr underset (("phosgene")) (COCI_(2))`
(III) `6CO_(2) +6H_(2)O rarr underset ("glucose") (C_(6)H_(12)O_(6))+6O_(2)`.
30.

Which of the following pair is expected to have the same bond order ?

Answer»

`O_(2), N_(2) `
`O_(2)^(+), N_(2)^(-) `
`O_(2)^(-), N_(2)^(+) `
`O_(2)^(-), N_(2)^(-)` ,

Solution :`O_(2)^(+), N_(2)^(-) `
On the base of molecular orbital THEORY we can calculate bond order of molecules ions as
BO = `(1)/(2) (N_(B) - N_(a))`
Molecular orbital electronic configuration (MOEC) of `N_(2)` is :
`sigma 1s^(2), sigma(8*) 1s^(2), sigma 2S^(2), sigma^(**) 2s^(2), pi 2p_(X)^(2) = pi 2p_(y)^(2) , sigma 2p_(x)^(2) `
Bond order of `N_(2)^(+) = (1)/(2) (10 - 4) =3 `
MOEC of `N_(2)^(+) = sigma 1s^(2) , sigma^(**) 1s^(2) , sigma 2s^(2) , sigma^(**) 2s^(2), pi 2p_(x)^(2) = pi 2p_(y)^(2) , sigma 2p_(z)`
BO of `N_(2)^(+) = (1)/(2) (9 - 4) = 2.5 `
MOEC of `N_(2)^(-) = sigma 1s^(2) , sigma^(**) 1s^(2), sigma 2s^(2), sigma^(**) 2s^(2),pi 2p_(x)^(2) = pi 2p_(y)^(2), sigma 2p_(z)^(2) , pi 2p_(x)^(1) = pi^(**) 2p_(y)`
BO of `N_(2)^(-) = (1)/(2) ( 10 - 5)= 2.5`
MOEC of `O_(2) =sigma 1s^(2), sigma^(**) 1s^(2) , sigma^(**) 2s^(2) , sigma 2p_(z)^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2) , pi^(**) 2p_(x)^(2) = pi^(**)2p_(y)^(1)`
BO of `O_(2) = (1)/(2) (10 - 6) = 2 `
MOEC of `O_(2)^(-) = sigma 1s^(2), sigma^(**)1s^(2), sigma 2s^(2), sigma^(**) 2s^(2) , sigma 2p_(z)^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2) , pi^(**) 2p_(x)^(2) = pi^(**) 2p_(y)^(1)`
BO of `O_(2)^(-) = (1)/(2) (10 - 7) =1.5`
MOEC of `O_(2)^(+) = sigma^(**) 1s^(2), sigma 2s^(2), sigma^(**) 2s^(2), sigma 2p_(z)^(2), pi 2p_(x)^(2) = pi 2p_(y)^(2) pi^(**) 2p_(x)^(2) = pi^(**) 2p_(y)`
BO of `O_(2)^(+) = (1)/(2) (10 - 5) = 2.5 `
(A) Bond order of `O_(2) and N_(2)` are 2 and 3, respectively.
(B) Bond order of both `O_(2)^(+) and N_(2)^(-) ` and 1.5 and 2.5
(C) Bond order of `O_(2)^(-) and N_(2)^(+) ` are 1.5 and 2.5, respectively.
Bond order of `O_(2)^(-) and N_(2)^(-)` are 1.5 and 2.5 respectively.
31.

Which of the following reaction is an example for homogenous catalysis:-

Answer»

`2H_(2)O_(2(l))overset(MnO_(2)(s))to2H_(2)O_((l))+O_(2(G))`
`2SO_(2(g))+O_(2(g))overset(V_(2)O_(5)(s))to2SO_(3(g))`
`2CO_((g))+O_(2(g))overset(NO(g))to2CO_(2(g))`
`H_(2(g))+C_(2)H_(4(g))overset(Ni(s))toC_(2)H_(6(g))`

Solution :When the reactants and the catalyst are in the same phase, then this is called HOMOGENOUS catalysis.
32.

Which among the following elements is paramagnetic

Answer»

`KO_(2)`
`K_(2)O_(2)`
`K_(2)O`
`NO_(2)`

SOLUTION :Due to the presence of unpaired electron on `O^(2)` ION in `KO^(2)` and ‘N’ in `NO^(2)` (odd electron BOND)
33.

Write the structures of different isomers correspondingto the 5^(th) member of alkyne series. Write their IUPAC names.

Answer»

Solution :`5^(th)` Member of ALKYNE series is `C_(6)H_(10)`. Since first member of series is `C_(2)H_(2)`.
The possible isomers and their IUPAC names are :
34.

Which of the following reactions is not feasible ?

Answer»




ANSWER :C
35.

The soldiers of Napolean army while at Alps during freezing winter suffered a serious problem as regards to the tin buttons of their uniforms. White metallic tin buttons get converted to grey powder, This transformation is related to

Answer»

an interaction with water vapour CONTAINED in humid AIR
a change in crystalline STRUCTURE of tin
a change in the partial pressure of `O_(2)` in air
an interaction with `N_(2)` of air at low temperature

Answer :B
36.

What happens when BF_3 reacted with NH_3

Answer»


ANSWER :`BF_3+NH_3rarrF_3BlarrNH_3` (COMPLEX)
37.

What temperature is 75^(@) F on the Kelvin scale?

Answer»

24 K
348 K
297 K
215 K

Solution :C) `75^(@)`F= 9/5^(@)`C + 32 = ((43 xx 5)/9)^(@)` C = `23.9^(@)`C
= `(23.9 + 273)`K
= 296.9 -~ 297 K
38.

What arethe atomicnumber of theelementswhichconstitutef- block ( lanthanoidsand actinoids ) ?

Answer»

SOLUTION :LANTHANOIDS `=58 ` to 71, ACTINOIDS =90 to 103 .
39.

Which of the following FCC structure contains cations in alternatetetrahedral voids?

Answer»

NACL
ZNS
`Na_(2) O`
`CaF_(2)`

Answer :B
40.

When B is reacted with conc. H_2 SO_4, the gaseous product is

Answer»

`B_2 O_3`
`SO_2`
`O_2`
`SO_3`

ANSWER :B
41.

Which of the following reagents would be the best reactants for the following synthesis?

Answer»

Solution :The acid HALIDE reacts with the aluminum trichloride to remove the chlorine atom and FORM the acyl CARBOCATION, which is the ELECTROPHILE

42.

Which type of electrolytes are used in a salt bridge?

Answer»

Solution :Only those electrolytes for which CATIONS and anions have NEARLY the same IONIC mobilities (i.e distance travelled by an ion PER second under a POTENTIAL gradient one volt) are used as electrolytes in the salt bridge. Thus KCl, `KNO_3,K_2SO_4 and NH_4NO_3` are preferred over NaCl, `NaNO_3` and `Na_2 SO_4`.
43.

The SI unit of entropy is ………….

Answer»

SOLUTION :`JK^(-1)`
44.

Two elements P and Q react seperately with highely electropositive metal to form binary compounds, which upon hydrolysis yield mixtures of boranes and silanes. P and Q respectively are

Answer»

<P>B,Al
Si,B
B,Si
Al,B

Solution :(C ) P and Q are boron and silicon respectively.
45.

underset((X))("Salt of iron") overset(Na_(2)S_(2)O_(3))rarr Violet complex overset("On standing")rarr underset((Z))("Green solution") Wite oxidation number of Fe in (Z).

Answer»


ANSWER :2
46.

The term that corrects for the attractive forces present in a real gas in the van der Waal's equation is:

Answer»

NB
`(an^(2))/(V^(2))`
`-(an^(2))/(V^(2))`
`-nb`

ANSWER :B
47.

What is amphoteric oxide ?

Answer»

Solution :Which oxide act as BASE with ACID and act as acid with base is KNOWN as AMPHOTERIC OXIDES.
48.

Which of the following oxidation states are the most characteristic for lead and tin respectively :

Answer»

`+2,+2`
`+4,+2`
`+2,+4`
`+4,+4`

Solution :Due to INERT pair EFFECT , +2state of Pb is more stablewhile +4 state of tin is more stable, i.e., OPTION (C ) is CORRECT.
49.

Which of the following statement(s) is/are incorrect?

Answer»

`O_(2)` is paramagnetic, `O_(3)` is also paramagnetic
` O_(2)` is paramagnetic, `O_(3)` is diamagnetic
`B_(2)`is paramagnetic `C_(2)` is also paramagnetic
Different observation is FOUND in their bond length when `NO RARR NO^(+) ` and CO `rarr` CO^(+)`

Answer :A::C::D
50.

When methane is burnt in oxygen to produce CO_2 and H_2O, the oxidation number of carbon changes by

Answer»

8
3
0
4

Solution :`OVERSET(-4)(CH_(4)) + O_(2) to overset(+4)(CO_(2)) +H_(2)O`