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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 10402. |
When propanoic acid is treated with aqueous sodium - bicarbonatate, CO_(2) is liberated. The "C" of CO_(2) comes from |
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Answer» METHYL GROUP |
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| 10403. |
When an electron in an excited Mo atom fall from L to k shell, an X -ray is emitted. These X -rays are diffracted at angle of 7.75^(@) by planes with a separation of 2.64overset(@)A. What is the difference in energy between K-shell and L-shell in Mo assuming a first-order diffraction (sin 7.75^(@)=0.1349) |
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Answer» `36.88xx10^(-19)J` `=0.7123xx10^(-10)m` `E=(HC)/(lambda)=(6.62xx10^(-34)xx3xx10^(8))/(0.7123xx10^(-10))=27.88xx10^(-16)J` |
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| 10404. |
What are biodegradable and non-biodegradable detergents. Give one example of each. |
| Answer» SOLUTION :Detergents having straight HYDROCARBON chains are easily degraded (or DECOMPOSED) by microorganism and hence are called biodegradable detergents while detergents containing branched hydrocarbon chains are not easily degraded by the microorganisms and hence are called non biodegradable detergents. Consequently, non-biodegradable detergents accumulate in rivers and other waterways thereby causing severe water pollution. EXAMPLES of biodegradable detergents are SODIUM lauryl sulphate, sodium 4-(1-dodecyl)benzene sulfonate and sodium 4-(2-dodecyl)benzene sulfonate. An example of non-biodegradable detergent is sodium 4-(1, 3, 5, 7-tetramethyl) octylbenzene sulfonate. | |
| 10405. |
Whichwould undergo S_(N)2reaction faster in the following pair andwhy ? CH_(3) - CH_(2) - Br " and " CH_(3) - CH_(2) - I |
| Answer» Solution :`CH_(3) - CH_(2) - I " UNDERGOES " S_(N)2` reaction FASTER because- I is a better LEAVING group. | |
| 10406. |
Which of the following compound cannot be prepared by Wurtz reaction in pure state? |
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Answer» `CH_(3)CH_(2)-CH_(3)` |
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| 10407. |
What single reagent solution (including H_(2)O) could be used to effect the separation of the following of solides? a. NaOH and Fe(OH)_(3) b. Ni(OH)_(2) and Fe(OH)_(2) c. Cr_(2)O_(3) and Fe(OH)_(3) d. MnS and CuS e. AgCI and AgI |
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Answer» Solution :a.`H_(2)O` can dissolve `NaOH_(2) ,Fe(OH)_(3)` remaininsoluble in water . b. `NH_(4)OH` dissolves `Ni(OH)_(2)` is insoluble `Ni(OH)_(4) + 4NH_(4) OH rarr underset("Soluble")underset("Soluble")([Ni(NH_(3))_(4)]^(2+))` C. Execess of `NaOH` can dissoolve `Cr_(2)O_(3)` but `Fe(OH)_(3)` REMAIN insoluble `Cr_(2)O_(3)+ 3H_(2)O rarr 2Cr(OH)_(3)` `Cr(OH)_(3) + NaOH rarr underset("Soluble")(Na[Cr(OH)_(4)])` d.Dilute `HCI` disolves `MnS` souble while `CoS` remaininsoluble `MnS + 2HCI rarr MnCI_(2) + H_(2)S uarr` E. `Aq,NH_(3)` would dissolve `AgCI` while `AGI` remaininsoluble `AgCI + 2NH_(3)(aq) rarr underset("Soluble")([Ag(NH_(3))_(2)]CI)` |
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| 10408. |
The species that is not hydrolysed in water is |
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Answer» `P_(4)O_(10)` `Mg_(3)N_(2)+6H_(2)O rarr 3Mg(OH)_(2)+2NH_(3)` `CaC_(2)+2H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)` |
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| 10409. |
Write the formulas for the following coordination compounds : Potassium tetracyanonickelate(II) |
| Answer» SOLUTION :`K_(2)[NI(CN)_(4)]` | |
| 10410. |
Which of the following set does not have oxidation state +6 for S? |
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Answer» SULPHURIC ACID, Peroxodisulphuric acid |
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| 10411. |
Which reaction shows oxidising nature of H_2O_2? |
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Answer» `H_2O_2 +2KL rarr 2KOH + I_2` |
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| 10412. |
When an oxide of manganese (A) is fused with KOH in the presence of an oxidising agent and dissolved in water, it gives a dark green solution of compound (B). Compound (B) disproportionates in neutral or acidic solution to give purple compound (C ) oxidises potassium iodide solution to a compound (D) and compound (A) is also formed. Identify compounds A to D and also explain the reactions involved. |
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Answer» Solution :`A: MnO_(2) , B: K_(2)MnO_(4)` `C: KMnO_(4), D : KIO_(3)` `UNDERSET((A))(2MnO_(2)) + 4KOH + O_(2) rarr underset((B))(2K_(2)MnO_(4)) + 2H_(2)O` `3MnO_(4)^(2-) + 4H^(+) rarr underset((C ))(2MnO_(4)^(-)) + MnO_(2) + 2H_(2)O` `2MnO_(4)^(-) + H_(2)O + KI rarr 2MnO_(2) + 2OH^(-) + underset((D))(2KIO_(3))` |
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| 10413. |
Which of the following is correct with respect to the order of basic natures of different amines given below ? |
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Answer» `C_(6)H_(5)NH_(2)gt NH_(3)gtCH_(3)NH_(2)gt(CH_(3))_(2)NH` |
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| 10414. |
which of the following differs from others? |
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Answer» Chalcopyrites |
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| 10415. |
Which of the following statement is//are correct. (1) To prepare ethanol, CH_(3)Mgl is treated with the other reagent HCHO. (2) Urotropine is formed by the action of HCHO with NH_(3) (3) The conversion of acid chlorides into aldehydes by reduction is termed Rosenmund's reduction. (4) Aldehyde show reducing properties duet ot their ready conversion into ketons. |
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Answer» 1 |
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| 10416. |
Which of the following processes is responsible for the formation of delta at a place where rivers meet the sea ? |
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Answer» Emulsification |
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| 10417. |
Which one of the following notations shows the product incorrectly ? |
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Answer» <P>`""_(99)Cm^(242) (alpha, 2n) ""_(97)BK(243)` |
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| 10418. |
Which of the following is not a chlorinated insecticide |
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Answer» BHC 
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| 10419. |
Which reaction will have the greater temperature dependence for the rate constant-one with a small value of energy of activation (E) or one with a large value of E? |
| Answer» SOLUTION :LARGE VALUE of E | |
| 10420. |
Write the IUPAC name of the following compound : C_(6)H_(5)-CH_(2)-CH_(2)-OH |
| Answer» SOLUTION :`underset("2-Phenylethanol")(C_(6)H_(5)-overset(2)CH_(2)-overset(1)CH_(2)-OH)` | |
| 10421. |
When phenol reacts with NH_3 in the presence of ZnCl_2 at 300^@C,it gives ………………. . |
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Answer» `1^@` AMINE |
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| 10422. |
Which of the following white ppts are insoluble in NH_(3)? |
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Answer» `AGCL` |
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| 10423. |
The specific conductivity of a solution containing 1.0 g of anhydrous BaCl_2 in 200 cm^3 of the solution has been found to be 0.0058 S cm^(-1). Calculate the molar conductivity of the solution. (Molecular wt. of BaCl_2 = 208). |
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Answer» Also, Normality of `BaCl_(2) = 0.024 xx 2 = 0.048` N `(therefore N = M xx "VALENCY factor")` Now, `wedge_(m) = k xx (1000)/C_(M) = (0.0058 xx 1000)/0.024` `=241.67 S cm^(2) mol^(-1)` |
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| 10424. |
The total number of isomeric products (including stereomers ) formed at the end of the reaction is : |
Answer» 
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| 10425. |
Which show highest lattice energy :- |
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Answer» Solution :`L.E. prop q_(1)q_(2) prop (1)/("size")` ORDER of size `{:(Mg^(+2) LT Ca^(+2)),(O^(-2)lt S^(-2)):}`so, MgO has highest lattice energy. |
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| 10426. |
When 100 mL of 1.0 M HCl was mixed 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase 5.7^(@)C was measured for the beaker and its contents (Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (-57.0 kJmol^(-1)), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt.2) 100 mL of 2.0 M acetic acid (K_(a)=2.0xx10^(-5)) was mixed with 100 mL of 1.0 M NaOH (under indentical conditions to Expt. 1) where a temperature rise of 5.6^(@)C was measured (Consider heat capacity of all solutions as 4.2 Jg^(-1)K^(-1) and density of al solutions as 1.0 gmL^(-1))The pH of the solution after Expt. 2 is |
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Answer» `2.8` HENCE it is BUFFER solution `pH=pK_(a)+log.([CH_(3)COO^(-)])/([CH_(3)COOH])=5-log2+log.(0.1)/(0.1)=4.7` |
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| 10427. |
Which vitamin is not soluble in fat ? |
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Answer» Vitamin-A |
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| 10428. |
Which is most basic ? |
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Answer» `NH_(3)` |
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| 10429. |
When sodium ethoxide and ethyl bromide are heated, the product formed is |
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Answer» diethyl ether |
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| 10430. |
When 100 mL of 1.0 M HCl was mixed 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase 5.7^(@)C was measured for the beaker and its contents (Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (-57.0 kJmol^(-1)), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt.2) 100 mL of 2.0 M acetic acid (K_(a)=2.0xx10^(-5)) was mixed with 100 mL of 1.0 M NaOH (under indentical conditions to Expt. 1) where a temperature rise of 5.6^(@)C was measured (Consider heat capacity of all solutions as 4.2 Jg^(-1)K^(-1) and density of al solutions as 1.0 gmL^(-1))Enthalpy of dissociation (in KJmol^(-1))of acetic acid obtained from the Expt.2 is |
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Answer» `1.0` Mass of aqueous content in expt. `1=(100+100)xx1=200g` implies Total heat capacity = `(C+200xx4.2)J//K` Moles of acid, base neutralised in expt. `1=0.1xx1=0.1` implies Heat released in expt. `1=0.1xx57=5.7 KJ` `implies5.7xx1000=(C+200xx4.2)xxDeltaT` `5.7xx1000=(C+200xx4.2)xx5.7` `implies (C+200xx4.2)=1000` In second experiment, `n_(CH_(3)COOH)=0.2, n_(NAOH)=0.1` Total mass of aqueous content = 200 g implies Total heat capacity = (C+200`xx`4.2)=1000 implies Heat released = `1000xx5.6=5600 J` Overall, only 0.1 mol of `CH_(3)COOH` undergo neutralization `implies DeltaH_("neutralization")" of "CH_(3)COOH=(-5600)/(0.1)` `=-56000 J//mol=-56 KJ//mol` `impliesDeltaH_("IONIZATION")" of "CH_(3)COOH=57-56=1KJ//mol` |
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| 10431. |
Which is used inside pencils and in many lubricants ? |
| Answer» Solution :graphite | |
| 10432. |
What does Ellingham diagram represent? |
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Answer» Solution :(i) The graphical REPRESENTATION of variation of the standard Gibbs free energy of REACTION for the formation of various metal oxides with temperature is CALLED Ellingham diagram. (ii) Ellingham diagram helps us to select a suitable reducing agent and appropriate temperature RANGE for reduction. |
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| 10433. |
What can be inferred from the magnetic moment values of the following complex species ? {:("Example",,"Magneticmoment (BM)"),(K_(4)[Mn(CN)_(6)],,2.2),([Fe(H_(2)O)_(6)]^(2+),,5.3),(K_(2)[MnCl_(4)],,5.9):} |
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Answer» Solution :Magnetic moment `(mu)=sqrt(n(n+2))` BM When n = 1, `""mu=sqrt(1(1+2))=sqrt(3)=1.73` When n = 2, `""mu=sqrt(2(2+2))=sqrt(8)=2.83` When n = 3, `""mu=sqrt(3(3+2))=sqrt(15)=3.87` When n = 4, `""mu=sqrt(4(4+2))=sqrt(24)=4.89` When n = 5, `""mu=sqrt(5(5+2))=sqrt(35)=5.92` (i) `K_(4)[Mn(CN)_(6)]` : In this complex, Mn is in +2 oxidation state, i.e., as `Mn^(2+)`. `mu=2.2` BM SHOWS that it has only one unpaired electron. Thus, when strong `CN^(-)` ligands approach `Mn^(2+)` ion, pairing of ELECTRONS in 3D orbitals takes place as shown in the FIGURE. The hybridisation involved is `d^(2)sp^(3)` forming inner ORBITAL octahedral complex.  (ii) `[Fe(H_(2)O)_(6)]^(2+)` :In this complex, Fe is in +2 state, i.e., as `Fe^(2+)`. `mu=5.3` BM shows that there are four unpaired electrons. This means that the electrons in 3d do not pair up when the ligands, `H_(2)O` molecules, approach. Thus, `H_(2)O` is a weak ligand. The hybridisation will be `sp^(3)d^(2)`. Hence, it will be an outer orbital octahedral complex.  (iii) `K_(2)[MnCl_(4)]` : In this complex, Mn is in +2 state, i.e., as `Mn^(2+)`. `mu=5.92` BM shows tthat there are five unpaired electrons. Thus, the hybridisation involved will be `sp^(3)` and the complex will be tetrahedral. 
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| 10434. |
Which of the following is an allyl group ? |
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Answer» `C_(6)H_(5)CH_(2)-` |
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| 10435. |
The work done to contract a gas in a cylinder, is 462 joules. 128 joule energy is evolved in the process. What will be the internal energy change in the process |
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Answer» `+ 590` JOULES From the `I^(st)` law of THERMODYNAMICS `DeltaE=q+w=(-128)+(+462)=+334` Joules. |
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| 10436. |
What is the covalence of nitrogen in "N"_(2)"O"_(5) ? |
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Answer» Solution :Number of .O. atoms bonded to each .N. atom in `N_(2)O_(5)` is 2.5. HENCE the covalency of .N. is calculated as 5, based on oxide THEORY. But by the examination of the structure of `N_(2)O_(5)`, one can observe that .N. forms only 4 bonds. Its covalency in NITROGEN pentoxide is 4. 
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| 10437. |
What is the pH of 1MNaPO_(4) solution at 25^(@)C? PO_(4)^(3-)+H_(2)OhArrHPO_(4)^(2-)+OH^(-),K_(b)=2.4xx10^(-2) Assume no hydrolysis of HPO_(4)^(2-) ions. |
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Answer» SOLUTION :`K_(a)=(x^(2))/(1-x)=2.4xx10^(-2)` `x^(2)+(2.4xx10^(-2))xx-2.4xx10^(-2)=0` `x=0.143=[OH^(-)]` `[H^(+)]=(K_(w))/([OH^(-)])=7xx10^(-14)M` `:.pH=13.15` |
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| 10438. |
The standard electrode potential (E^@) for Daniel cell is +1.1V. Calculate the Delta G^@ for the reaction. Zn(s)+Cu^(2+) (aq) to Zn^(2+) (aq)+Cu(s) |
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Answer» Solution :`DELTA G^@=-n Fe^@` `=-2 times 96500 C mol^-1 times 1.1V` `=-212300 J mol^-1` `=-212.3 K J mol^-1` |
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| 10439. |
What is preservative ? How sodium metabisulphite act as preservative and in which food particles it is used ? |
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Answer» SOLUTION :Preservative Chemical substances which are used to PROTECT food against bacteria, yeasts and moulds are called preservatives. The preservative action of sodium meta bisulphate`(Na_(2)S_(2)O_(5))` is due to `SO_(2)` which dissolves in WATER to give sulphurous acid. `Na_(2)S_(2)O_(5) to Na_(2)SO_(3) +SO_(2)` `SO_(2) +H_(2)O to H_(2)SO_(3)` Sulphurous acid inhibits the growth of yeasts, moulds and bacteria. Sodium metabisulphate is used as a preservative for food products such as jams, squashes, PICKLES etc. |
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| 10440. |
Tollen's reagent is used for the detection of aldehyde. When a solution of AgNO_(3) is added to glucose with NH_(4)OH, then gluconic acid is formed. Ag^(+)toe^(-)toAg,E_(red)^(@)=0.8V C_(6)H_(12)O_(6)+H_(2)OtoC_(6)H_(12)O_(7) (Gluconic acid) +2H^(+)+2e^(-),E_(oxd)^(@)=-0.05V Ag(NH_(3))_(2)^(+)+e^(-)toAg(s)+2NH_(3),E^(@)=-0.337V [Use 2.303xx(RT)/(F)=0.0592 and (F)/(RT)=38.92 at 298K] Now answer the following three questions: Q. We have take a saturated solution of AgBr. K_(sp) of AgBr is 12xx10^(-14) if 10^(-7) mole of AgNO_(3) are added to 1 litre of this solution, find conductivity (specific conductance) of this solution in terms of 10^(-7)Sm^(-1) Given lamda_((Ag^(+)))^(@)=6xx10^(-3)Sm^(2)mol^(-1),lamda_((Br^(-)))^(@)=8xx10^(-3)Sm^(2)mol^(-1),lamda_((NO_(3)^(-)))^(@)=7xx10^(-3)Sm^(2)mol^(-1) |
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Answer» `(S+10^(-7))xxS=K_(SP)=12xx10^(-14)` `S=3XX10^(-7)M` `[Ag^(+)]=4xx10^(-7)M,[Br^(-)]=3xx10^(-7)M,[NO_(3)^(-)]=10^(-7)M` `K_("TOTAL")=lamda_((Ag^(+)))^(@)lamda_((Ag^(+)))^(@)+lamda_(Br^(-))^(@)-lamda_(Br^(-))^(@)+lamda_((NO_(3))^(-))^(@)lamda_((NO_(3)^(-)))^(@)` `lamd_(KCl)^(@)=lamda_(k)^(@)+lamda_(CL^(-))^(@)` `K_(KCl)=4xx10^(-4)xx6xx10^(-3)+3xx10^(-4)xx8xx10^(-3)+1xx10^(-4)xx7xx10^(-3)` `K_(KCl)=24+24+7` `K_(KCl)=55Scm^(-1)` |
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| 10441. |
When t-butyl bromide is treated with CH_(3)O^(-) in a mixture of CH_(3)OHandH_(2)O, the rate of formation of t-butyl alcohol and t-butyl methyl ether doesn't change appreciably as the concentration of CH_(3)O^(-) ion is increased. However, increasing the concentration of CH_(3)O caused a marked increase in the rate at which t-butyl bromide disappear from the mxiture. Why? |
| Answer» Solution :t-Butyl alcohol and t-butyl METHYL ether are FORMED through `S_(N)1` MECHANISM and the rate of the reactions in independent of the concentration of `CH_(3)O^(-)`. This was the only reaction that causes t-butyl bromide to disapear. But if we increase the concentration of `CH_(3)O^(-)`,t-butyl bromide STARTS disappearing through E2 mechanism. This reaction is DEPENDENT on the concectration of `CH_(3)O^(-)`. Hence as we increase teh concentration of `CH_(3)O^(-)` the rate of disappearance of t-butyl bromide increase the concentration of `CH_(3)O_(-)` the rate of disappearance of t-butyl bromide increases. | |
| 10442. |
Transitionmetals show variable oxidation states because of : |
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Answer» participation of ND electrons along with np electrons |
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| 10443. |
Which of the following is/are correct order? |
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Answer» ATOMIC rdius `F lt O lt F^(-) lt O^(2-)` (b) Ionisation energy `prop(1)/("size")prop`Effective nuclear charge (c) Normally the electron afinity `(E_(A)) prop(1)/("Size of atom")` |
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| 10444. |
Tollen's reagent is used for the detection of aldehyde. When a solution of AgNO_(3) is added to glucose with NH_(4)OH, then gluconic acid is formed. Ag^(+)toe^(-)toAg,E_(red)^(@)=0.8V C_(6)H_(12)O_(6)+H_(2)OtoC_(6)H_(12)O_(7) (Gluconic acid) +2H^(+)+2e^(-),E_(oxd)^(@)=-0.05V Ag(NH_(3))_(2)^(+)+e^(-)toAg(s)+2NH_(3),E^(@)=-0.337V [Use 2.303xx(RT)/(F)=0.0592 and (F)/(RT)=38.92 at 298K] Now answer the following three questions: Q. Ammonia is always is added inn this reaction. Which of the following must be INCORRECT: |
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Answer» `NH_(3)` combines with `Ag^(+)` to FORM a complex |
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| 10445. |
What are the types of hybridization involved in the following geometrical shapes of the complex? tay square planar(b) Tetrahedral (c) Octahedral |
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Answer» SOLUTION :`dsp^(2)` (B) `Sp^(3)` (c) `d^(2)sp^(3)or sp^(3)d^(2)` |
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| 10448. |
Which one interacts with macromolecular targets such as proteins to produce a therapeutic and useful biological response? |
| Answer» Solution : medicine | |
| 10449. |
Which of the following gives reddish brown precipitate with dilute solution of resorcinol in dilute HCl: |
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Answer» Glucose |
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| 10450. |
Which of the following give self redox reaction ? |
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Answer» Methanal |
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