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10501.

The regionclosestto earthsurface is

Answer»

Stratophere
Mesospher
Troposphere
Themosphere.

ANSWER :C
Discussion
10502.

Which of the following methods would serve to prepare 1-phenylpropan -2-ol.

Answer»

Addition of benzyl GRIGNARD REAGENT to ethanol
Addition of phenyllithium to methyloxirane
Addition of methyl grignard reagent to phenyl acetaldehyde.
Addition of phenyl magnesium bromide with ethanal.

Solution :Option (A) ,(B)and (C) are TRUE
Discussion
10503.

Which of the following will give red colour with NaOH ?

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`R-overset(NH)overset("||")(C)-NO_(2)`
`R-UNDERSET(NO_(2))underset(|)overset(R)overset(|)(C)-NO`
`R_(2)C-NO_(2)`
`R_(3)CONO`.

SOLUTION :`{:(""NOH),("||"),(R-C-NO_(2)):}` is nitrolic ACID and it gives red COLOUR with `NaOH`.
Discussion
10504.

Which of the following sets of elements have the strongest tendency to form anions

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N, O, F
P, S, Cl
As, SE, Br
Sb, Te, I

Answer :A
Discussion
10505.

Which of the following alcohols is dehydrated most readily with conc. H_(2)SO_(4) ?

Answer»

`p-NO_(2) C_(6)H_(4) CH(OH) CH_(3)`
`p-CH_(3)O C_(6)H_(4) CH(OH) CH_(3)`
`p-CI C_(6)H_(4) CH(OH) CH_(3)`
` C_(6)H_(4) CH(OH) CH_(3)`

Answer :B
Discussion
10506.

What are lambda- sulphur?

Answer»

Solution :Sulphur ALSO exists in liquid and GASEOUS states. At around `140^(@)C` the monoclinicsulphur metal to form MOBILE pale yellow liquid CALLED `lambda` sulphur.
Discussion
10507.

Which of the following structures represent the same compound?

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(I) and (II)
(II) and (III)
(I) and (III)
All are same

SOLUTION :NA
Discussion
10508.

What are intrinsic semiconductors ?

Answer»

Solution : In semi conductors, the gap between the valence band and conduction band is SMALL. Therefore, some ELECTRONS may jump to conduction band and show some conductivity.

Electrical conductivity of semiconductors increases with rise in temperature, since more electrons can jump to the conduction band. Substances like silicon and germanium show this TYPE of BEHAVIOUR and are called intrinsic semiconductors. The conductivity of these intrinsic semiconductors are too low for practical USE.
Discussion
10509.

Which of the following is are correct for an ideal binary solution of two volatile liquids (eg. Benzene and toluene) ?

Answer»

Its vapour is always richer in the more volatile component ( compared to the liquid )
The liquid will gradually BECOME richer in the less volatile component if such as mixture is boiled (DISTILLED)
The `p_T` (ie. The total pressure) above the solution will be the sum of the vapour pressures of the two PURE components
The boiling point of the solution will be less than the boiling point of the two components

Solution :(A)`(X'_A)/(X_B)=(P_A^@X_A)/(P_B^@X_B)`
`(X'_A)/(X'_B)gt X_A/X_B ( "If" P_A^@ gt P_B^@)`
(B)If `P_A^@` is more, more A will EVAPORATE more and B will stay BACK in the solution.
(C )`P_T=P_A^@X_A+P_B^@X_BneP_A^@+P_B^@`
(D)`If P_A^@ gt P_B^@` . Then `P_A^@ gt P_T gt P_B^@`
`P_A^@ gt P_A^@X_A + P_B^@X_B gt P_B^@`.Hence boiling point of solution is more than A but less than B.
Discussion
10510.

Write two important uses of formalin.

Answer»

SOLUTION :It is USED (i) in the preservation of anatomical specimens and (II) in the menumfacture of polymers LIKE bakelite, MELMAC, urea-formaldehyde, etc.
Discussion
10511.

Which of the following polymers does not involve cross-linkages ?

Answer»

Vulcanised rubber
BAKELITE
Melamine
Teflon

Solution :Teflon is an ADDITION linear POLYMER of tetrafluoroethene .
Discussion
10512.

Write the structural formulae for the monomers of following polymers : (i) Nylon 6(ii) Natural rubber.

Answer»

Solution :Structural formulae for the monomers of the polymers are given below:
(i) Adiptic acid `HO = overset(O)overset(||)(C) - (CH_(2))_(4) - overset(O)overset(||)(C) - OH`and Hexamethylenediamine , `H_(2)N(CH_(2))_(6)NH_(2)` .
(II) `CH_(2) = underset("Isoprene")underset(CH_(3))underset(|)(C) - CH = CH_(2)`
Discussion
10513.

X g of silveris plated out on a servingtray byelectrolysis of asolutioncontaining silver in +1 oxidationstatefor a periodof 8.0 h at current of 8.46 A whatis the areaof the trayif the thickness of silver plating is 0.0025 cm ? [ Given denisty of silver =10.5 g cm^(-3)]

Answer»

`10.7 xx10^(4) cm^(2)`
`1.02 xx10^(4) cm^(2)`
`4.1 xx10^(23) cmsd^(2)`
`10.0xx10^(4) cm^(2)`

Solution :`(W_("Ag"))/("Equivalent WEIGHT")_("ag")=("it")/(96500)`
`w_(Ag)=(107.8 xx8.46 xx8xx60xx60)/(96500)`
`w_(Ag)=272 .18 g`
volumeof Ag`=(272.18)/(10.5) =25.92 g`
`THEREFORE` surface area `=(25.92)/(0.00254)=1.02 xx10^(4) cm^(2)`
Discussion
10514.

Write the IUPAC name of the following : CH_(3)-CH_(2)-CH=CH-overset(O)overset(||)C-H

Answer»

Solution :The IUPAC name of the compound `CH_(3)CH_(2)CH=CH-CHO` is
`underset("Pent -2- enal")(overset(5)CH_(3)overset(4)CH_(2)overset(3)CH=overset(2)CH-overset(1)CHO)`
Discussion
10515.

Which gaves 2 moles of HCHO. 1 mole of HCOOH and CO_(2) by HIO_(4).

Answer»

`OVERSET(CH_(2)-OH)overset(|)overset(CH-OH)overset(|)overset(C=O)overset(|)overset(CH_(2)-OH)`
`overset(CH=O)overset(|)overset(CH-OH)overset(|)overset(CH-OH)overset(|)overset(CH=O)`
`overset(CH_(2)-OH)overset(|)overset((CH-OH)_(2))overset(|)overset(CH=O)`
All

Answer :A
Discussion
10516.

Which one of the following an oxidation reduction reaction ?

Answer»

`NaOHHCIrarrNacI+H_(2)O`
`2Mg+O_(2)rarr2MgO`
`2Mg+O_(2)rarr2MgO`
`Na_(2)SO_(4)+BaCI_(2)rarrBaSO_(4)+2NaCI`

Solution :An oxidation reduction (redox) REACTION is a TYPE of CHEMICAL reaction that involves a transfer of ELECTRONS between tow species an oxidaion REDUCTIN reaction is any chemical reaction in which the oxidation number of a molecule atom or ion changes by gaining or losing an electron
Discussion
10517.

Which one of the following is a non-reducing sugar ?

Answer»

GLUCOSE
Sucrose
Maltose
LACTOSE

Solution :Sucrose is a non -reducing SUGAR while all OTHERS are reducing SUGARS.
Discussion
10518.

Which on treating with etheral solution of AlCl_(3) gives LiAlH_(4) ?

Answer»

LiOH
Li
LiH
LiCl

Answer :C
Discussion
10519.

The value of rate constant of a pseudo first order reaction ………………… .

Answer»

DEPENDS on the concentration of reactants present in small amount
depends on the concentration of reactants
is independent of the concentration of reactants
depends only on temperature.

Solution :The value of rate constant of a pseudo first order reaction depends not only on temperature but also on concentration of reactant present in excess (See Sample Problem 2, page `4//46`). Hence, (B) is CORRECT.
Discussion
10520.

Write IUPAC name of the following. C_4H_9NC

Answer»

SOLUTION :PENTANE ISONITRILE
Discussion
10521.

Why are the group IV cations not precipitated as sulphides on passing H_(2)S gas through group II solution?

Answer»

Solution :For the PRECIPITATION of cations of group IV, a very large concentration of sulphide ions `(S^(2-))` id required which is not available in the group II as the ionisation of `H_(2)S` is suppressed by HCl (common ion effect). In precipitating the cations of group IV high concentration of `S^(2-)` ions is required as `OH^(ɵ)` ions RELEASED by `NH_(4)OH` unite with `H^(o+)` ions GIVEN by `H_(2)S`. Thus the solubility PRODUCT is exceeded and the cations of group IV are precipitated as ZnS, NiS, MnS and CoS.
Discussion
10522.

Thymineis

Answer»

5-methyluracil
4-methyluracil
3-methyluracil
1-methyluracil

Answer :A
Discussion
10523.

Treatment of with NaNH_(2)//liq.NH_(3) gives

Answer»




SOLUTION :Reaction prcoeeds via BENZYNE MECHANISM with INTERMEDIATE as
Discussion
10524.

Upon mixing 45.0 ml of 0.25 M lead nitrate solution with25 ml of 0.10 M chromic sulphate solution , precipitation of lead sulphate takes place . How many moles of lead sulphate are formed ? Also calculate the concentration of the species left behind in final Solution : Assume that lead sulphate is completely insoluble.

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SOLUTION :N/A
Discussion
10525.

Which compound would give 5-ketone methylhxanal upon ozonolysis?

Answer»




SOLUTION :
Discussion
10526.

What will be the bond angle C-O-H in alcohol if C and O ATOM POSSESS SP^(3) hybridization

Answer»

`109^(@)28`
`111^(@)42`
`109^(@)`
`108^(@)30`

Solution :
Although O-atom is `sp^(3)`-hydrised and the 4 positions are occupied by H and `underset(|)overset(|)C-` group and other two by the lone PAIRS. Due to the bulky nature of `-underset(|)overset(|)C` group the bond ENLARGES to `111^(@)42'` from tetrahedral `109^(@)28'`
Discussion
10527.

The value of colligative properties of colloidal solution are of amall orde in comparison to those shown by true solutions of same concentration because colloidal particles………..

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exhibit enormous surface AREA
remain suspended in the dispersion medium
form lyophilic COLLOIDS
are comparatively less in number

Solution :Colloidal PARTICLES are big in size (macromoolecular) and hence small in number in the some AMOUNT in grams/litre.
Discussion
10528.

Write the IUPAC names of the following compounds :

Answer»

SOLUTION :
Discussion
10529.

Which of the following statements is not true about amorphous solids ?

Answer»

On heating they may become crystalline at CERTAIN temperature.
They may become crystalline on keeping for long time.
AMORPHOUS solids can be MOULDED on heating.
They are anisotropic in nature.

Solution : Amorphous solids are ISOTROPIC in nature.
Discussion
10530.

When hydrochloric acid is added to cobalt nitrate solution at room temperature, the following reaction takes place and the reaction mixture becomes blue. On cooling the mixture it becomes pink. On the basis of this information mark the correct answer.underset(("pink"))([Co(H_(2)O)_(6)]^(3+)(aq))+4Cl^(-)(aq)hArr underset(("blue"))([CoCl_(4)]^(2-))(aq)+6H_(3)O(l)

Answer»

`Delta H gt 0` for the reaction
`Delta H lt 0` for the reaction
`Delta H = 0` for the reaction
The sign of `Delta H` cannot be PREDICTED on the basis of this information.

Solution :SINCE the reaction shifts to backward direction on cooling, this means that the backward reaction is EXOTHERMIC reaction. Therefore, the forward reaction is ENDOTHERMIC reaction and `Delta H gt 0`.
Discussion
10531.

Which of the following compound can not give CO_(2) gas on heating ?

Answer»



`HOOC-CH_(2)-COOH`

Solution :
gives cyclicv ANHYDRIDE on HEATING.
Discussion
10532.

Which of the following has the highest boiling point ?

Answer»

1 - chloropentane 
ISOPENTYL CHLORIDE 
ter-Pentyl chloride 
all have EQUAL BOILING point

Answer :A
Discussion
10533.

When .............. Is heatd with .......... Phosphine is obtained.

Answer»

SOLUTION :PHOSPHORUS ALKALI
Discussion
10534.

Which of the following oxides is most basic in nature?

Answer»

`Al_2O_3`
`SiO_2`
`SO_3`
`Na_2O`

ANSWER :D
Discussion
10535.

Using the valence bond approach, predict the shape and magnetic behaviour of [CoCl_(4)]^(2-).

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Solution :Electronic configuration of CO : [Ar] `4s^(2)3D^(7)`.
Electronic configuration of `Co^(2+) : [Ar] 4s^(0) 3d^(7)`.
`Cl^(-)` does not cause pairing of electrons because it is weak field LIGAND. HENCE,

It has tetrahedral shape and is paramagnetic due to presence of THREE unpaired electrons.
Discussion
10536.

What is the reason for the catalytic activity of transition elements and their compounds ?

Answer»

Solution :The REASON for catalytic activity is DUE to VARIABLE valencies.
Discussion
10537.

Which of the following combination, of compounds/elements and its packing fraction is true? Assume all cations or anions are ideally fitted in the voids without any distortion in lattice.

Answer»

`Na_(2)O, phi=(pi)/(3sqrt(2)) {1+2xx(0.225)^(3)}`
`Cr_(2)O_(3),phi=(pi)/(3sqrt(2)){1+ 2/3xx(0.414)^(3)}`
`Fe_(2), O_(3), phi=(pi)/(3sqrt(2)){1+(0.225)^(3)}`
Diamond, `phi=(pi)/(3sqrt(2)){1+(0.414)^(3)}`

Solution :`Fe_(2)O_(3), phi=(pi)/(3sqrt(2)){1+2/3(0.414)^(3)}`
Diamond `phi=8xx(4pir^(3))/(3xx(2sqrt(2)R)^(3))`
Discussion
10538.

When, acetaldehyde is heated with Tollen's reagent, following is obtained

Answer»

Methyl ALCOHOL
Silver acetate
Silver mirror
Formaldehyde

ANSWER :C
Discussion
10539.

Which of the following particles can be accelerated in a cyclotron ?

Answer»

PROTON
Neutron
ALPHA
Positron

SOLUTION :Proton , `alpha`- PARTICLE , positron
Discussion
10540.

Write the relavant chemical equations : Toluene to benzyl alcohol

Answer»

SOLUTION :
Discussion
10541.

Which oxide of sulfur can act as an oxidising as well as a reducing agent ?

Answer»

Solution :`SO_2` because S can INCREASE its oxidation NUMBER from + 4 to +6 and also decrease it to + 2 or even zero
Discussion
10542.

Which of the following ions show a bonds order of 1.75:

Answer»

`NO_(3)^(-)`
`CO_(3)^(2-)`
`ClO_(4)^(-)`
None of these

ANSWER :C
Discussion
10543.

Vibrational energy is

Answer»

PARTIALLY POTENTIAL and partially kinetic
Only potential
Only electronic
Only kinetic

Answer :A
Discussion
10544.

The Tyndall effect associated with colloidal particles is due to

Answer»

PRESENCE of ELECTRICAL charges
scattering of light
absorption of light
reflection of light

Answer :B
Discussion
10545.

Which one of the following ether produces in higher yield by continuous etherification process ?

Answer»

`C_2H_5OCH_3`
`C_2H_5OC_2H_5`
`CH_3OCH(CH_3)_2`
`C_2H_5OCH_2CH_2CH_3`

ANSWER :B
Discussion
10546.

Which one of the following laws directly explains the law of conservation of mass?

Answer»

HUND's RULE
DALTON's law
Avogadro's law
Berzelius hypothesis

Answer :C
Discussion
10547.

which of the following compound will show stereo isomerism?

Answer»

3-Pentarol
3-Pentanone
But-2-ene
PROPANE

ANSWER :C
Discussion
10548.

Vulcanized rubber resists:

Answer»

WEAR and TEAR DUE to friction
Cryogenic temperature
High temperature
Action of acids

Answer :A
Discussion
10549.

Which type of ores can be concentrated by magnetic separation method?

Answer»

Solution :Magnetic SEPARATION can be used to separate magnetic ORES from the non-magnetic GANGUE. For instance, various ores of IRON such as HAEMATITE `(Fe_(2)O_(3))`, magnetite `(Fe_(3)O_(4))`, iron pyrites `(FeS_(2))` and siderite `(FeCO_(3))` are magnetic. Hence, these can be separated from non-magnetic impurities like silica, by magnetic separation.
Discussion
10550.

Which one of the following gases has the lowest value of Henry's law constant?

Answer»

`N_(2)`
`He`
`H_(2)`
`CO_(2)`

Solution :According to HENRY's law the mass of a gas dissolved PER unit VOLUME of SOLVENT is PROPORTIONAL to the pressure of the gas at constant temperature m = K p i.e.as the solubility increases, value of Henry's law constant decreases. Since `CO_(2)` is most soluble in water among the given set of gases. Therefore `CO_(2)` has the lowest value of Henry's law constant.
Discussion