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10601.

What kind of complex is [Co(NH_(3))_(4)Cl_(2)]^(+) ?

Answer»

SOLUTION :HETEROLEPTIC
Discussion
10602.

When 1 mL of 0.5 M K_(2)SO_(4) is added to 10 mL of 1 M BaSO_(4) precipitate of BaSO_(4) is formed. As a result,

Answer»

Freezing point is INCREASED
Boiling point is increased
Freezing point is LOWERED
Boilint point is lowerd

Solution :(b,c) are both CORRECT STATEMENTS.
Discussion
10603.

Which is the coordination number in both hep and ccp arrangements?

Answer»

12
6
4
8

Answer :A
Discussion
10604.

Which of the following is female sex hormones?

Answer»

Adrenaline
Non-adrenaline
Estrogen
Testosterone

Answer :C
Discussion
10605.

Which one is ambidentate ligand?

Answer»

`SO_(3)^(2-)`
`CN^(-)`
`NH_(3)`
`H_(2)O`

ANSWER :B
Discussion
10606.

Which of the following acids reacts with acetic anhydride to produce a compound which is a pain killar and antipyretic?

Answer»

OXALIC acid
Cinnamic acid
Benzoic acid
Salicylic acid

Answer :D
Discussion
10607.

Which among the following in a paramagnetic copound?

Answer»

`N_2O`
`NO`
`N_2O_3`
`N_2O_4`

ANSWER :B
Discussion
10608.

When a white crystalline compound X is heated with K_(2)Cr_(2)O_(2) and concentrated H_(2)SO_(4) a reddish brown gas A is evolved. On passing A into caustic soda solution, a yellow coloured solution of B is obtained. Neutralizing the solution B with acetic acid and on subsequent addition of lead acetate, a yellow precipitate C is obtained. When X is heated with NaOH solution, a colourless gas is evolved and on passing this gas into KaHgle solution, a reddish brown precipitate D is formed. Identify A, B, C, D and X. Write the equations of reactions involved.

Answer»

Solution :`CrO_(2)`,`Na_(2)CrO_(4)`,`PbCrO_(4)`, iodide of Millon.s base `NH_(4)Cl`
`X = NH_(4)Cl`
`A = CrO_(2)Cl_(2)`
`B = Na_(2)CrO_(4)`
`C = PbCrO_(4)`
The chemical reactions are as FOLLOWS:
`Cr_(2)O_(7)^(-2)+4CI^(-)tounderset(A)underset("Raddish Brown")(2CrO_(2)CI_(2)uarr)+3H_(2)O`
`Cr_(2)O_(2)CI_(2)+4OH^(-)tounderset(B)underset("Yellow solution")(CrO_(4)^(-2))+2CI^(-)+2H_(2)O`
`Pb(OCOCH_(3))_(2)+CrO_(4)^(-2)tounderset(B)underset("Yellow ppt.")(PbCrO_(4))darr+2CH_(3)COO`
`NH_(4)^(+)+4OH^(-)+2[Hgl_(4)]^(-2)to`
Discussion
10609.

Zone refining is used to produce very pure.

Answer»

CU 
SI 
Na 
ZN 

ANSWER :B
Discussion
10610.

True peroxide is :

Answer»

`BaO_2`
`MnO_2`
`PbO_2`
`NO_2`

ANSWER :A
Discussion
10611.

Two gases in adjoining vessels were brought into contact by opening a stopcock between them. One vessel measured 0.25 litre and contained NO at 800 torr and 220 K, the other measured 0.1 litre and contained O_(2) at 600 torr and 220 K. The reaction to form N_(2)O_(4) (solid) exhausts the limiting reactant completely. (a) Neglecting the vapour pressure of N_(2)O_(4) what is the pressure of the gas remaining at 220 K after completion of the reaction ? (b) What weight of N_(2)O_(4) is formed ? (torr = mm)

Answer»

Solution :Let us first calculate o. of moles of NO and `O_(2)` before the reaction tkes place. Let `n_(1)` and `n_(2)` be the no. of moles of NO and `O_(2)` respectively in each vessel.
We have pV = nRT
For NO : `(800)/(760) xx 0.25 = n_(1) xx RT , "" n_(1) = (200)/(760 RT)`.
For `O_(2) : (600)/(760) xx 0.10 = = n_(2) xx RT, ""n_(2) = (60)/(760 RT)`.
Since NO and `O_(2)` react in 2 : 1 molar RATIO
`{:("(2NO",+,O_(2),rarr,N_(2)O_(4)")"),(" "(g),,(g),,(s)):}`
`therefore (60)/(760 RT)` mole of `O_(2)` will react with `(120)/(760 RT)` mole of NO and so only `((200)/(760 RT) - (120)/(760RT))` mole, i.e, `(80)/(760 RT)` mole of NO shall remain after the completion of reaction. The pressure due to remaining NO can thus be calculated as :
pV = nRT
`p(0.25 + 0.1) = (80)/(760 RT) xx RT , p = 0.30` atm or 229 mm.
Further, we know that `(120)/(760 RT)` mole of NO COMPLETELY changed to `N_(2)O_(4)`.
`therefore` applying POAC for N atoms in `NO overset(O_(2))rarr N_(2)O_(4)`
`1 xx` moles of NO = `2 xx` moles of `N_(2)O_(4)`
`(120)/(760 RT) = 2 xx ("WT. of " N_(2)O_(4))/(92), "wt. of " N_(2)O_(4) = 402 g {{:("R = 0.082 LIT. atm K"^(-1) MOL^(-1)),(T = 220 K):}}`.
Discussion
10612.

White blood cells act as

Answer»

As SOURCE of ENERGY
For blood CLOTTING
As defence against infection
As a medium for OXYGEN transport from lungs to tissues

Answer :C
Discussion
10613.

Which of the following statements is correct for the spontaneous adsorption of a gas

Answer»

`DELTAS` is positive and, THEREFORE, `DELTAH` should be NEGATIVE
`DeltaS` is positive and, therefore, `DeltaH` should also be HIGHLY positive
`DeltaS` is negative and, therefore, `DeltaH` should be highly positive
`DeltaS` is negative and therefore, `DeltaH` should be highly negative

Solution :For adsorption `DeltaS=-ve, DeltaH=-ve`.
Discussion
10614.

What is the equilibrium expression for the reaction P_(4(s))+5O_(2(g))hArrP_(4)O_(10(s))

Answer»

`k_(c)=[O_(2)]^(5)`
`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]`
`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`
`K_(c)=1//[O_(2)]^(5)`

Solution :`P_(4(s))+5O_(2(G))hArrP_(4)O_(10(s))`
`K_(c)=([P_(4)O_(10(s))])/([P_(4(s))][P_(2(g))]^(5))`
We know that CONCENTRATION of a solid compnent is always TAKEN as unity `K_(c)=(1)/([O_(2)]^(5))`
Discussion
10615.

Write the IUPAC name of following coordinate compounds. K_3[Fe(CN)_6]

Answer»

SOLUTION :POTASSIUM hexacyano FERRATE (III)
Discussion
10616.

The standard reduction potential of three metallic cations X, Y and Z are +0.52, -3.03 and -1.18 v respectively. The order of reducing power is:

Answer»

`YgtZgtX`
`XgtYgtZ`
`ZGTYGTX`
`ZgtXgtY`

ANSWER :A
Discussion
10617.

The resistance of mercury becomes almost zero at :

Answer»

4 K
10 K
20 K
25 k

Answer :A
Discussion
10618.

Which of the following metal carbonates liberate. CO_(2)(g) on heating :

Answer»

`Na_(2)CO_(3)`
`K_(2)CO_(3)`
`Rb_(2)CO_(3)`
`Ag_(2)CO_(3)`

ANSWER :D
Discussion
10619.

What are the methods by which colloids are prepared?

Answer»

Solution :Colloidal are prepared by the following methods.
(i) Dispersion methods : In this method larger particles are broken to colloidal DIMENSION. (II) Condensation method : In this method, smaller ATOM or molecules are converted into larger colloidal SIZED particles.
Discussion
10620.

Which of the following Werner's complex has least electrical conductivity ?

Answer»




SOLUTION :(C ) Has no ionisable `CL^(-)`
Discussion
10621.

To solutionof a salt in acid medium AgNO_(3) is added awhite ppts repidlychanging toyellow orange , brown andfinaly is obtained .This isd dueto thepresence of

Answer»

`SO_(3)^(2-)`
`S_(2)O_(3)^(2-)`
`CH_(3)COO^(Theta)`
`S_(2)^(Theta)`

ANSWER :B
Discussion
10622.

Which of the following undergoes Mustard oil reaction ?

Answer»

`C_(2)H_(5)NH_(2)`
`(C_(2)H_(5))_(2)NH`
`C_(2)H_(5)CONH_(2)`
`(C_(2)H_(5))_(3)N`

SOLUTION :Mustard OIL reaction is GIVEN by `1^(@)` amine.
Discussion
10623.

Tyloses are found in

Answer»


ANSWER :D
Discussion
10624.

Which reaction is not valid ?

Answer»

`HCl +F_(2) to HF+Cl_(2)`
`HF+Cl_(2) to F_(2)+HCl`
`ZN+HCl to ZnCl_(2)+H_(2)`
`Al+HCl to AlCl_(3)+H_(2)`

Solution :FLUORINE is more electronegative than chlorine hence, it can DISPLACE Cl from Cl from HCl while chlorine cannot displace fluroine from HF. Therefore the FOLLOWING REACTION is not valid.
`HF+Cl_(2) to F_(2)+HCl`
Discussion
10625.

Which of the following compound when heated with HI gives two mole of different alkyl iodide?

Answer»

`C_2H_5-OH`
`C_2H_5-O-C_2H_5`
`CH_3-O-C_2H_5`
`CH_3-O-CH_3`

ANSWER :C
Discussion
10626.

Two moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in V-T diagram below: Heat supplied to the gas during the process AB is :

Answer»

`1200R ln2`
1800 R
1200 R
Zero

Solution :For AB, ISOTHERMAL PROCESS
`:. Q= -W=nRT "In" (V_1/V_2)=2xxRxx600 "In"8/4=1200 R "In"2`
Discussion
10627.

Val't Hoff factor for benzoic acid is less 1 in benzene. Reason : Benzoic acid associates in benzene.

Answer»

If both ASSERTION are REASON are CORRECT and reason is correct EXPLANATION for assertion.
If both assertion and reason are CORRCT but reason is not correct explanation for assertion.
If assertion is corrct but reason is incorrect.
If assertion and reason both are incrrect.

Solution :Reason is the correct explanation for assertion.
Discussion
10628.

The suitable reagent for nuclear iodination of aromatic compounds is-

Answer»

`KI//CH_(3)COCH_(3)`
`I_(2)//CH_(3)CN`
`KI//CH_(3)COCH`
`I_(2)//HNO_(3)`

Solution :Iodobenzene cannot be prepared by direct iodination of aromatic ring because iodine is least reactive among halogens, the REACTION is reversible and the HI formed redues iodobenzene to benzene and `I_(2)`

But, on ADDITION of `HNO_(3)` , HI produced is oxidised to `I_(2)`. As a result, the reaction PROCEEDS in the forward direction to produce iodobenzene.
Discussion
10629.

The set of numerical coefficients that balances the equation K_(2)CrO_(4) + HCl to K_(2)Cr_(2)O_(7) + KCl + H_(2)O is

Answer»

1,1,2,2,1
2,2,1,1,1
2,1,1,2,1
2,2,1,2,1

Solution :`2K_(2)CrO_(4) + 2HCL to K_(2)Cr_(2)O_(7) + 2KCL + H_(2)O`
Discussion
10630.

Which statement is/are correct :

Answer»

Final TEMPERATURE in reversible ADIABATIC expansion is lesser than in irrevesible adiabatic expansion.
When heat is SUPPLIED to an ideal gas in an isothermal process, kinetic ENERGY of gas will increase
When an ideal gas is subjected to adiabatic expansion it GETS cooled
Entropy increases in atomisation of dihydrogen

Answer :A::C::D
Discussion
10631.

Which of the following relates to light as wave motion as well as a stream of particles?

Answer»

Photoelecric EFFECT
`E=mc^(2)`
DIFFRACTION
`E=hv`

ANSWER :D
Discussion
10632.

What is the potential of a cell containing two hydrogen electrodes, the negative one in contact with 10^-8 molar H^+ and the positive one in contact with 0.025 molar H^+?

Answer»

SOLUTION :0.379 VOLT
Discussion
10633.

Which of the following statements is correct if the intermolecular forces in liquids A,B and C are in the order AltBltC?

Answer»

B evaporates more READILY than A.
B evaporates less readily than C.
A and B evaporate at the same rate.
A evaporates more readily than C.

Solution :The LIQUID having LOW INTERMOLECULAR forces evaporate FASTER in comparison to the liquids having high intermolecular forces. Order of intermolecular forces.
`AltBltC`
Evaporation `:AgtBgtC`
Discussion
10634.

The unit of molar conductivity is

Answer»

`OMEGA^(-1)mol^(-1)`
`Omegacm^(-2)mol^(-1)`
`Omega^(-1)cm^(2)mol^(-1)`
`Omegacm^(2)mol`

SOLUTION :Molar conductivity`=(1)/(rhoM)`
So its nit will be `Omega^(-1)cm^(2)mol^(-1)`.
Discussion
10635.

Which of the following chromatography mode method is used to determine molecular mass of polymer ?

Answer»

QELS
DLS
CLS
SEC

SOLUTION :SEC
Discussion
10636.

Which of the following is not correct order of the property mentioned?

Answer»

Oxidising power : `BrO_(4)^(-) gt IO_(4)^(-)gt ClO_(4)^(-)`<BR>Bond ENERGY : `Cl_(2) gt Br_(2) gt F_(2)`
Thermal stability : `NH_(3) gt AsH_(3) gt PH_(3)`
ELECTRON affinity : `Cl gt F gt Br.`

Answer :C
Discussion
10637.

Whenalkyl idodie are exposed to light produces

Answer»

ALKANE and HI
alkanane and `I_(2)`
ALKENE ana HI
alkeneand `I_(2)`

ANSWER :B
Discussion
10638.

What are carbohydrates ? Give two example.

Answer»

Solution :(i) Carbohydrates are polyhydroxy aldehydes or polyhydroxy ketones.
(ii) They are naturally occurring organic SUBSTANCES.
(iii) Carbohydrates are formed in the plants by photosynthesis from water in SUNLIGHT.
(iv) They are classified into two types :
(a)SUGARS Eg: Glucose, Fructose.
(b) Non-sugars Eg: STARCH, CELLULOSE.
Discussion
10639.

Which of the following statement is are true for Borax ?

Answer»

It forms a basic SOLUTION in water
When concentrated `H_2SO_4` is added to hot concentrated solution of `Na_2B_4O_7`, white crystals SEPARATES out
It can react with NaOH
It swells up on heating to give a GLASSY bead CONTAINING `Na_2B_4O_7` and `B_2O_3` only

Solution :`Na_2B_4O_7`+water`to NaBO_2 + H_3BO_3`
Hydrolysis of `NaBO_2` make solution basic.
The `H_3BO_3` can react with NaOH.
It swells up on heating to give a glassy bead containing `NaBO_2 and B_2O_3`.
`H_2SO_4+Na_2B_4O_7toNa_2SO_4+H_3BO_3`(white crystals)
Discussion
10640.

Which of the following biphynyl is optically active?

Answer»




SOLUTION :o-Substituted diphenyl having bulky GROUPS on both the o-positions of each benzene ring are optically active since the two benzene rings due to STERIC hindrance lie in prependicular planes and hence their mirror IMAGES are non-superimposable as shown below:

Non-superimposible mirror images (optically active).
Discussion
10641.

Which of the following will have maximum boiling point ?

Answer»

`C_(3)H_(7)Br`
`C_(3)H_(7)F`
`C_(3)H_(7)CL`
`C_(3)H_(7)I`

ANSWER :D
Discussion
10642.

Whichoneof thefollowinghasthelowestboilingpoint

Answer»

2-Methylbutane
2-Methypropane
2,2 Dimethylpropane
n- PENTANE

ANSWER :B
Discussion
10643.

What happens when methane is heat at 1000 ^(@) C ?

Answer»

Solution :At `1000^(@)`, METHANE DECOMPOSE to produce fine CARBON powder.It is known as carbon black.
Discussion
10644.

Which of the following will give methylamine upon reaction with acetamide ?

Answer»

`PCl_(5)`
NAOH+`Br_2`
SODALIME
Hot CONC. `H_2SO_4`

Answer :B
Discussion
10645.

Which does not have pyramidal geometry:

Answer»

`SO_3^(2-)`
`NO_3^-`
`NH_3 `
`C(C_6H_5)_3^-`

ANSWER :B
Discussion
10646.

Which one of the following is a homoleptic complex ?

Answer»

`[Co(NH_(3))_(3)(Cl_(3))]`
`[PT(NH_(3))_(2)Cl_(2)]`
`[Pt(NO_(2))(H_(2)O)(NH_(3))_(2)]Br`
`[Co(NH_(3))_(6)]Cl_(3)`

ANSWER :C::D
Discussion
10647.

The resistance of a 0.10 M weak acid HA in a conductivity cell is 2.0xx10^(3)ohm. The cell constat of the cell is 0.78 cm^(-1) and wedge_(0) of the acid is 390 S cm^(2)mol^(-1). Consider the following statements: 1. pH of the acid solution=3 2. pK_(a) of the acid=5 3. Degree of dissociation the acid=0.01 Which of the statements given above are correct?

Answer»

1 AD 2 only
1 and 3 only
2 and 3 only
1,2 and 3

Solution :`kappa="Conductance (G)"xx"Cell CONSTANT "(G^(**))`
`=(1)/(2.0xx10^(3))xx0.78=3.9xx10^(-4)Omega^(-1)cm^(-1)`
`wedge=(1000kappa)/("Molarity")=(1000xx3.9xx10^(-4))/(0.10)`
`=3.9" S "cm^(2)MOL^(-1)`.
`thereforealpha=(wedge)/(wedge_(m))=(3.9)/(390)=10^(-2)=0.01`
`HA hArr H^(+)+A^(-)`
`[H^(+)]=Calpha(0.10)(10^(-2))=10^(-3)M`
`K_(a)=([H^(+)][A^(-)])/([HA])=(10^(-3)xx10^(-3))/(0.1)=10^(-5)` `pK_(a)=5`.
Discussion
10648.

The stability of hydrogen halides is in order

Answer»

`HF gt HI gt HBr gt Hcl`
`HI gt HBr gt HCl gt HF`
`HF gt HCl gt HBr gt HI`
`HC gt HBr gt HI gt HF`

SOLUTION :Thermal stability `=Hf gt HCl gt HBr gt HI
Discussion
10649.

Which of the following electrolytes has the same value of van't Hoff's factor (i) as that of Al_(2)(SO_(4))_(3) (if all are 100% ionised) ?

Answer»

`K_(2)SO_(4)`
`K_(3)[FE(CN)_(6)]`
`Al(NO_(3))_(3)`
`K_(4)[Fe(CN)_(6)]`

Solution :van.t HOFF FACTOR of
`Al_(2)(SO_(4))_(3)to 2AL^(+3)+3SO_(4)^(-2)`
so n = 5
`K_(4)[Fe(CN)_(6)]to 4K^(+)+[Fe(CN)_(6)]^(-4)`
so `n=5 rArr i=n=5`
Discussion
10650.

When I^(-) is oxidised by MnO_(4)^(-) in an alkaline medium, I^(-) converts into

Answer»

`IO_(3)^(-)`
`I_(2)`
`IO_(4)^(-)`
`IO^(-)`

ANSWER :A
Discussion