InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12501. |
What are the uses of Benzaldehyde? |
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Answer» Solution :(i) as a flavoring AGENT (ii) in perfumes (iii) in dye intermediates (iv) as STARTING material for the synthesis of several other ORGANIC compounds like CINNAMALDEHYDE, cinnamic acid, benzoyl chloride etc. |
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| 12502. |
The solubility of Al(OH)_3 is 's' mol per litre, the solubility product of Al(OH)_3 is : |
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Answer» `s^3` |
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| 12503. |
Which of the following mixture is chromic acid? |
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Answer» `K_2Cr_2O_7` and CONC.`H_2SO_4` |
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| 12504. |
Which of the following reactions does not yield an alkyl halide |
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Answer» Diethyl ETHER+`CI_(2)` |
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| 12505. |
The strength of bonds formed by overlapping of 2s-2s, 2p-2p and 2p-2s follows the order |
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Answer» `2s-2s GT 2p-2p gt 2s-2p` |
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| 12506. |
Vitamin C deficiency may cause: |
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Answer» Beriberi |
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| 12507. |
What can be inferred from the magnetic moment of the followingcomplex species ? {:("Example ","Magnetic moment(BM)"),([K_(4)[Mn(CN)]_(6)],2.2),([Fe(H_(2)O)_(6)]^(2+),5.3),(K_(2)[MnCl_(4)],5.9):} |
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Answer» Solution :Magnetic moment `(mu) = sqrt(n(n+2))BM` When `n= 1 , mu = sqrt(1(1+1)) = sqrt(3) = 1.73` When `n=2, mu = sqrt(2(2+2))= sqrt(8) = 2.83` When `n = 3 , mu = sqrt( 3( 3+2)) = sqrt(15) = 3.87` When `n=4 , mu = sqrt( 4( 4+2)) = sqrt( 32) = 5.66`, When `n = 5 , mu= sqrt( 5 ( 5+2)) = sqrt( 35) 5.92` (i) `K_(4)[Mn(CN)_(6)]`. In this complex, Mn is in `+2` oxidation state, i.e., as `Mn^(2+)`. `mu = 2.2` BM shows that it has only on unpaired ELECTRON. Thus, when `CN^(-)` ligands approach `Mn^(2+)` ion, the electron in 3d pairup as shown in Figure. Thus, `CN^(-)` is a strong ligand. The hybridisation involved is `d^(2) SP^(3)` forming inner orbital octahedral complex. (ii) `[Fe(H_(2)O)_(6) ]^(2+)`. In this complex, Fe is in `+2` state, i.e., as `Fe^(2+)`. `mu = 5.3` BM shows that there are four unpaired electrons. This means that the electrons in 3d do not pair up when the ligands, `H_(2)O` molecules, approach. Thus, `H_(2)O` is a weak ligand. To accomodate the electrons donated by six `H_(2)O` molecule, the hybridisation will be `sp^(3) d^(2)`. Hence, it will be an outer orbital octahedral complex . (iii) `K_(2)[MnCl_(4)]` . In this complex, Mn is in `+2` state, i.e., as `Mn^(2+), mu = 5.92` BM shows that there are five unpaired electrons. Thus, the hybridisation involved will be`sp^(3)` and the complex will be tetrahedral.
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| 12508. |
Three solution are prepared by adding "wg" of "A" into 1kg of water , 'w' g of B into 1kg of water and 'w' g of c into 1kg of water (A, B, C, are non electrolytic). Dry air is passed from these solutions in sequence (A rarr B rarr C) . The loss in weight of A was found to be 2gm while solution B gained 00.5 gm and solution C lost 1gm then the relation molar masses of A, B and C is : |
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Answer» `M_(A):M_(B):M_(C)=1:2:3` |
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| 12509. |
Vapour presure of pure water at 298 K is 23.8 mm Hg. 50 g of urea (NH_(2)CONH_(2)) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering. |
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Answer» Solution :It is given that vapour pressure of water, `p_(A)^(0)=23.8` mm of Hg Weight of water taken, `w_(1)=850 g` Weight of urea taken, `w_(2)=50 g` Molecular weight of water, `M_(1)=18 g MOL^(-1)` Molecular weight of urea, `M_(2)=60 g mol^(-1)` Now, we have to calculate vapour pressure of water in the solution. We take vapour pressure as `p_(1)`. Now, from Raoult.s law, we have : `(p_(1)^(0)-p_(1))/(p_(1)^(0))=(n_(2))/(n_(2)+n_(2))` `therefore (p_(1)^(0)-p_(1))/(p_(1)^(0))=((w_(2))/(M_(2)))/((w_(1))/(M_(1))+(w_(2))/(M_(2)))` `therefore (23.8-p_(1))/(23.8)=((50)/(60))/((850)/(18))+(50)/(60)` `therefore (23.8-p_(1))/(23.8)=(0.83)/(47.22+0.83)` `therefore (23.8-p_(1))/(23.8)=0.0173` `p_(1)=23.4` mm of Hg Hence, the vapour pressure of water in the given solution is 23.4 mm of Hg and its relative lowering is 0.0173. |
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| 12510. |
What weight of copper will be deposited by passing 2 Faraday's of electricity through a cupric salt (Atomic weight of Cu = 63.5) |
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Answer» `2.0g` 2 Faraday.s will DEPOSITE 1g ATOM of Cu = 63.5 g. |
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| 12511. |
Which type of polymers are used in plastic paints ? |
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Answer» Heavy POLYMER |
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| 12512. |
What is the half life period of a first order reaction having rate constant 10^-2sec^-1? |
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Answer» Solution :GIVE that 1ST ORDER RATE constant,`lambda=10^-2sec^-1` Half-life period,`T_(1/2)=0.693\\lambda=(0.693/10^-2)sec.=0.693xx10^2=69.3sec.` |
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| 12513. |
Write IUPAC names of the following coordination compounds : (i) [Co(NH_(3))_(6)]Cl_(3) (ii) [Co(NH_(3))_(5)Cl]Cl_(2) (iii) K_(3)[Fe(CN)_(6)] (iv) K_(3)[Fe(C_(2)O_(4))_(3)] (v) K_(2)[PdCl_(4)] (vi) [Pt(NH_(3))_(2)Cl(NH_(2)CH_(3))]Cl. |
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Answer» SOLUTION :(i) HEXAAMMINECOBALT (III) chloride (II) pentaamminechloridocobalt (III) chloride (iii) potassium HEXACYANOFERRATE (III) (IV) potassium trioxalatoferrate (III) (v) potassium tetrachloridopalladate (II) (vi) diamminechlorido (methylamine) platinum (II) chloride |
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| 12514. |
Which of the following is considered to be an anti cancer species. |
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Answer» cis-ptatin |
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| 12515. |
Write the formula of the following complexes : Hexaammineplatinum(IV) chloride |
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Answer» SOLUTION :FORMULAE of the COORDINATION compounds are GIVEN below : `[PT(NH_(3))_(6)]Cl_(4)` |
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| 12516. |
Which of the following pairs of metals uis purified by vanarkel method? |
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Answer» GA and In ` Zr (s)+ 2I_2 (G)toZr I_4(g) ` ` Arl_4(g)underset("filement") OVERSET("onthe HOT ")Zr(s)+ 2I_2 (g) ` |
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| 12517. |
Which of the following is non- electrolyte |
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Answer» NaCl |
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| 12518. |
Which one of the following is not applicable to the plenomenon of adsorption ? |
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Answer» `Delta H gt 0` |
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| 12519. |
The vapour pressure of pure components A and B are 200 torr and 100 torr respectively. Assuming a solution of these components obeys Raoult's law, the mole fraction of component. A in vapour phase in equilibrium with a solution containing equimoles of A and B is : |
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Answer» <P>0.22 `P_(B)=100xx0.5=50` torr `P_("(total)")=P_(A)+P_(B)=100+50=150` torr MOLE fraction of A in vapour PHASE `=(100)/(150)=0.67` |
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| 12520. |
Which is used in the Haber.s process for the manufacture of NH_3 ? |
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Answer» `Al_2O_3` |
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| 12521. |
Which of the following electrolytes is used to maintain electrical energy neutralityin the Daneil cell ? |
| Answer» Answer :A | |
| 12522. |
Which one of the following compound have zero dipole moment ? |
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Answer» p-dinitro benzene |
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| 12524. |
Using CH_3MgBr, which substrate would lead to (CH_3)_3COH? |
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Answer» Acetone |
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| 12525. |
What are the uses of diethyl ether. |
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Answer» Solution :1. Diethyl ether is used as a SURGICAL anesthetic agent in surgery. 2. It is a good solvent for organic reactions and extraction. 3. It is used as a volatile STARTING fluid for diesel and GASOLINE engine. 4. It is used as a refrigerant. |
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| 12526. |
Which among the following statements is incorrect? |
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Answer» `XeF_(4) and SbF_(5)` combine to FORM salt. |
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| 12527. |
Which of the following compound gives milky white solution with Lucas reagent ? |
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Answer» Butane-1-ol |
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| 12528. |
The volume of water to be added to 100 cm^(3) of 0.5N H_(2)SO_(4) to get decinormal concentration is |
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Answer» `450 cm^(3)` `=0.05 N xx V_(2) xx` GRAM equivalent of `H_(2)SO_(4)` `(100 xx 0.5)/(0.05 xx2) = 500 cm^(3) = V_(2)` |
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| 12529. |
Which of the following is/are not known? (i) PCl_3 , AsCl_3 , SbCl_3 , NCl_5,PCl_5,BiCl_5 |
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Answer» Solution :(i) `NCl_5` is not known because of the absence of d-orbitals in nitrogen. (ii) `BiCl_5`does not exist because `Bi^(5+)` being an oxidising AGENT OXIDISES `Cl^(-)` ion to `Cl_(2)`and `Cl^(-)` ion being a REDUCING agent reduces `Bi^(5+) to Bi^(3+)` |
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| 12530. |
Which of the following reaction occur during the electrolysis of CuSO_4 solution using copperelectrodes? |
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Answer» `Cu to Cu^(+2) + 2e^(-)` at cathode : reduction takes place i.e. [ GAIN of electrons] `Cu to Cu^(+2) + 2e^(-)` |
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| 12531. |
Which of the following has not a lone pair ? |
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Answer» `NH_3` |
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| 12532. |
Which gives an yellow oil with nitrous acid? |
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Answer» `1^(@)` AMINE |
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| 12533. |
Which of the following is the most basic in character |
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Answer» `H_(2)O` |
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| 12534. |
Write the name of phenyl-substituded groups: a. C_(6)H_(5) overset(|)(C)Hme, b C_(6)H_(5) CH_(2)- C. C_(6) H_(5) CH = CH-, d. C_(6)H_(5) == CHCH_(2)- |
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Answer» SOLUTION :a. `C_(6) H_(5) overset(beta)(CH_(2)) -` (`beta` Phenethyul) C. Stryl, d. Cinnamyl |
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| 12535. |
Which colligative property is preferred for the molar mass determination of macromolecules ? |
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Answer» Solution :Osmotic pressure measurement is preferred for molar mass determination because : (a) EVEN in DILUTE solution the osmotic pressure values are appreciably high and can be MEASURED accurately. (b) osmotic pressure can be measured at room TEMPERATURE. |
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| 12536. |
Write the IUPAC names of (a) C_(2)H_(5)OCH_(3) (ii) C_(6)H_(5)OC_(2)H_(5) |
Answer» SOLUTION :
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| 12537. |
What is RDX ? |
| Answer» SOLUTION :RDX is Research and Development EXPLOSIVE which is prepared by the NITRATION of hexamethylene DIAMINE under controlled conditions. | |
| 12538. |
Which of the following polymer is stored in liver of animals ? |
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Answer» Amylose |
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| 12539. |
Which of the following can not be made by reduction of ketone or aldenhyde with NaBH_4 ? |
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Answer» 1 - Butanol |
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| 12540. |
What is the PH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed? |
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Answer» `2.0` No. of moles of NaOH =`0.1 TIMES x times 10^-3=0.1x times 10^-3` No. of moles of HCl= `0.01 times x times 10^-3=0.01x times 10^-3` =`0.09x times 10^-3` Concentration of NaOH = `(0.09x times 10^-3)/(2x times 10^-3)=0.045` `[OH^-]=0.045` `=2-log 4.5` `=2-0.65=1.35` `pH=14-1.35=12.65` |
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| 12541. |
Which of the following statements is true in case of alkyl halides? |
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Answer» They are polar in nature |
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| 12542. |
Which of the following has longest C-O bond length ? (Free bond length in CO is 1.128 Å) |
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Answer» `[Fe(CO)_(4)]^(2-)` |
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| 12543. |
Which one of the following compounds does not give addition reaction? |
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Answer» Aldehydes |
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| 12544. |
What happens when formaldehyde reacts with ammonia ? |
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Answer» Solution :AMMONIA reacts with formaldehyde to form a condensation product, HEXAMETHYLENE tetramine, commonly named as Urotropine. `6HCHO+4NH_(3) to underset("Hexamethylenetetramine")((CH_(2))_(6)N_(4))+6H_(2)O` |
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| 12545. |
Which method of purification is represented by the following equations ? Ti(s)+2I_(2)(g) overset(523 K) to TiI_(4)(g) overset(1700 K) to K Ti(s) +2I_(2)(g) |
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Answer» Zone |
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| 12546. |
Which statement/relationship is correct? |
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Answer» Use HYDROLYSIS SALT of strong base and weak acid GIVES a solution with phlt7 |
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| 12547. |
Vitamin C is : |
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Answer» Alcohol |
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| 12548. |
Wacker method is used to convert alkene into corresponding……….using PdCl_2 |
| Answer» Answer :C | |
| 12549. |
Which of the following process is used for the extractio of group 1 ? |
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Answer» Electrolysis of AQUEOUS solution of a salt |
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| 12550. |
To 10 ml of 0.1 M BaCl_(2) solution. 0.2 ml "of" 3 M Na_(2)SO_(4) is formed and is compeltely insoluble. All the salts are completely dissociated and change in volume is negligible. The |
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Answer» FREEZING POINT is raised |
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