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14251.

Which of the following is organo-metallic compOlmd ?

Answer»

`Ti(C_(2)H_(4))_(4)`
`Ti(OC_(2)H_(5))_(4)`
`Ti(OCOCH_(3))_(4)`
`Ti(OC_(6)H_(5))_(4)`

SOLUTION :`Ti(C_(2)H_(4))_(4)` is an organometallic COMPOUND due to Ti directly attached to C-atom.
14252.

Which one of the followoing reacitons demonstrates that H_(2)O_(2) acts as an oxidising agent in the basic medium?

Answer»

`Na_(2)CO_(3) + H_(2)O_(2) to Na_(2)O_(2) + H_(2)O + CO_(2)`
`2[Fe(CN)_(6)]^(3-) + H_(2)O_(2) + 2OH^(-) to 2[Fe(CN)_(6)]^(4) + 2H_(2)O + O_(2)`
`Mn^(2+) + H_(2)O_(2) + 2OH^(-) to MnO_(2) + 2H_(2)O`
`MnO_(2) + H_(2)O_(2) + 2H^(+) to Mn^(2+) + 2H_(2)O + O_(2)`

SOLUTION :Here `Mn^(2+)` is oxidised to `MnO_(2)` is BASIC medium by `H_(2)O_(2)`.
14253.

Which of the following is used as catalyst for preparing Grignard reagent

Answer»

IRON powder
Dry ETHER
Activated charcoal
`MnO_(2)`

SOLUTION :`MG + CH_(3)I overset("dry ether")to CH_(3)MgI`
14254.

The standard reduction potential forFe^(2+)|Fe and Sn^(2+)|Snelectrodes are -0.44 and-0.14 volt respectively. For the cell reaction: Fe^(2+)+Sn rarr Fe + Sn^(2+),the standard emf is

Answer»

`0.30V`
`-0.58`V
`+0.58V`
`-0.30V`

ANSWER :D
14255.

When sodium is heated in flame it gives:

Answer»

GOLDEN YELLOW colour
Crimson RED colour
Brick red colour
Violet colour

Answer :A
14256.

Write IUPAC name of (p)O_(2)N-C_(6)H_(4)-OCH_(3).

Answer»

SOLUTION :1 - Methoxy -4- nitro BENZENE.
14257.

which on oxidation will not give acarboxylic acid with the same number of carbon atoms:

Answer»

`CH_3COCH_3`
`C Cl_3CH_2CHO`
`CH_3CH_2CH_2OH`
`CH_3CH_2CHO`

ANSWER :B
14258.

Which of the following does not give brick red precipitate with Fehling's solution :

Answer»

ACETALDEHYDE
FORMALIN
D-glucose
ACETONE

ANSWER :D
14259.

Which of the following cations do (does) not give borax bead test?

Answer»

`Mg^(+2)`
`Mn^(+2)`
`Cu^(+2)`
`PB^(2+)`

Solution :BORAX BEAD TEST gives only Cu, Fe, CR, Ni, Co, Mn but not Mg, Pb
14260.

Which one of the following reaction is not possible ?

Answer»

`Fe + H_(2)SO_(4) to FeSO_(4) + H_(2)`
`Cu + 2 AgNO_(3) to Cu (NO_(3))_(2) +2 AG`
`2 KBr + I_(2) to 2 KI + Br_(2)`
`Cu O + H_(2) to Cu + H_(2)O`

Solution :`I_(2)` is LESS REACTIVE than `Br_(2)` .
14261.

Which of the following statements is/are correct ?

Answer»

The compound (B) is (I).
The compound (B) is (II).
The compound (C ) is (I).
The compound (D) is II.

Solution :The REASONANCE STRUCTURE of 2-napthoxide ion (A) is:

(A) is an AMBIDENT nucleophile and a better nucleophile than `(A_(1))` because negative charge is on more EN oxygen atom. In the presence of polar non-PROTIC solvent (DMF, dimethyl formamide), O-alkylation is favoured to give product II (C ). In the pressence of protic solvent, hydrogen bonding with the O atom occurs, THUS reducing the nuclehilicity of oxygen. Therefore, C-alkylation is favoured to give product I (B).
14262.

Which of the followingis a homoplysaccharide ?

Answer»

Hyaluronic ACID
HEPARIN
Both (a) & (B)
Starch

ANSWER :D
14263.

Which of the following descending order of second ionization enthalpy ?Ti(22), V(23), Cr(24) and Mn(25)

Answer»

`V gt MN gt CR gt TI`
`Mn gt Cr gt Ti gt V`
`Ti gt V gt Cr gt Mn`
`Cr gt Mn gt V gt Ti`

ANSWER :D
14264.

Which of the following statements are correct for H_(2)O_(2) ?

Answer»

it is NEUTRAL towards litmus, but bleaches litmus white
It is more acidic than `H_(2)O`
DENSITY and dielectric constant are higher than dilute solution of `H_(2)O`
`H_(2)O_(2)` is PRODUCED by auto oxidation of 2-ethyl anthraquinol

Answer :A::B::C::D
14265.

Which of the following alcohols CANNOT be preapred by the action of a suitable Grignard reagent on an aldehyde or a ketone followed by hydrolysis/

Answer»

ETHYL alcohol
Isopropyl alcohol
n-Propyl alcohol
Methyl alcohol

Answer :D
14266.

The standard e.m.f. of a cell involving one electron change is found to be 0.591V at 25^(@)C. The equilibrium constant of the reaction is (F = 96,500C mol^(-1) R = 8.314 J K^(-1) mol^(-1))

Answer»

`1.0 XX 10^(10)`
`1.0 xx 10^(5)`
`1.0 xx 10^(1)`
`1.0 xx 10^(30)`

Solution :`E_(CELL) = E_(cell)^(@) - (0.0591)/(N) LOGQ`
At equilibrium
`E_(cell) = 0, Q = K`
`0 = 0.591 - (0.0591)/(1) log K`
`log K = 10`
`K = 10^(10)`
14267.

When a strong acid is titrated using a weak base, the pH value at equivalence point is :

Answer»

7
`GT 7`
`LT 7`
`~~7`

ANSWER :C
14268.

Which of the following is chiral ?

Answer»




a MOLECULE of 3-methyheptane

Solution :N//A
14269.

What happens when hydrated ferric oxide and arsenious sulphide sols are mixed in almost equal proportion ?

Answer»

SOLUTION :MUTUAL PRECIPITION/ coaguation TOOK PLACE .
14270.

Two monosaccharidesar linked by………….to form a disaccharide .

Answer»

GLYCOSIDIC linkage
PEPTIDE bond
` - underset(O) underset(||)(C) - underset(H) underset(|)(N)` - linkage
` - underset(O) underset(||)(C) - ` linakge

ANSWER :A
14271.

What will be the theoretical value of 'spin only' magnetic moment when Fe(SCN)_(3) reacts with a solution containing F^(-) ions to yeild a colourless complex ?

Answer»

2.83 BM
3.87 BM
5.92 BM
1.73 BM

Solution :`[FeF_(6)]^(3-)` is FORMED. `t_(2G)^(1, 1, 1)EG^(1, 1)`
14272.

Which of the following ions is most para-magnetic

Answer»

`Nd^(+2)`
`YB^(+2)`
`Lu^(3+)`
`CE^(2+)`

Answer :A
14273.

What will be the coefficients of water and proton, if the following equation is balaned in acidic medium Cl_(2) + HC_(2)O_(4)^(-) rarr 2Cl^(-)+ 2CO_(3)^(2-)

Answer»

Solution :Balancing the GIVEN equation with respect to number of electrons
`Cl_(2) + HC_(2)O_(4)^(-) rarr 2CL^(-) + 2CO_(3)^(2-)`
Balancing oxygen atom by WATER and proton
`Cl_(2) + HC_(2)O_(4)^(-) + 2H_(2)O rarr 2Cl^(-) + 2CO_(3)^(2-) + 5H^(+)`
Hence the coefficients of water and proton are 2 and 5 RESPECTIVELY
14274.

Whichcell will measures standard electrode potential of copperelectrode ?

Answer»

`PT(s)|H_(2)(g,0.1 bar)|H^(+)(AQ),1 M)||CU^(2+)(aq, 1 M)|Cu`
`Pt(s)|H_(2)(g,1 bar)|H^(+)(aq,1 MM)||(cu^(2+)(aq,2M)|Cu`
`Pt(s)|H_(2)(g,1bar)|H^(+)(aq,1M)||Cu^(2+)(aq,1M)|Cu`
`Pt(s)|H_(2)(g,1bar)H^(+)(Aq , 0.1 M)||Cu^(2+)(aq , 1 M)|Cu`

Solution :`Pt(S)|H_(2)(g,1 bar )|H^(+)(aq,1 M)||Cu^(2+) (aq),1M)|Cu`
14275.

What would be the heat released when an aqueous solution containing 0.5 mole of HNO_(3) is mixed with 0.3 mle of OH^(-)? (Enthalpy of neutralisation is -57.1 kJ)

Answer»

28.5 kJ
17.1 kJ
45.7 kJ
1.7 kJ

Solution :0.5 mole of `HNO_(3)-=0.5` mole of `H^(+)` and 0.3 mole of `OH^(-)`
`0.5H^(+)(AQ)+0.3OH^(-)(aq)to0.5H_(2)O(L)`
`DeltaH=0.3xx57.1=17.13kJ`
14276.

Write the IUPAC names of the following coordination compounds : K_(2)[PdCl_(4)]

Answer»

SOLUTION :POTASSIUM tetrachloridopalladate(II)
14277.

Which one of the following statements are correct for the complex [Co(NH_(3))_(4)(Cl)(NO_(2))]Cl? (P) Cobalt is in +III oxidation state involving d^(2)sp^(3) hybridization. (Q) Cobalt is in +III oxidation state involving sp^(3)d^(2) hybridization. (R ) It shows ionisation as well as linkage isomerism. (S) It also shows geometrical isomerism.

Answer»

<P>P, R and S only
Q, R and S only
P and S only
Q and S only

Answer :A
14278.

Noble gases have vary low boiling point. Why?

Answer»

Solution :HELIUM is NOBLE GAS has the LOWEST boiling POINT.
14279.

Which statement is not correct about internal energy?

Answer»

INTERNAL ENERGY is the sum of kinetic energy and POTENTIAL energy of the particles making up the system.
Internal energy of the system can be measured.
Internal energy is a state function.
`DELTAU` is the heat of reaction at constant volume.

Answer :B
14280.

Which of the following is/are produced when a mixture of benzene vapour and oxygen is passed over V_(2)O_(5) catalyst at 775 K ?

Answer»

OXALIC ACID
Glyoxal
Fumaric acid
Maleic anhydride

Answer :D
14281.

Which has highest e/m ratio ?

Answer»

`He^(2+)`
`H^+`
`He^+`
H

Answer :B
14282.

Which is soluble in CS_2?

Answer»

WHITE P
Red P
Sand
Graphite

Answer :A
14283.

Which among the followings isFibrous protein?

Answer»

Albumin
Keratin
Insulin
None of the above

Answer :B
14284.

Which of the following is an example of zero order reaction ?

Answer»

IODINATION of acetone in acid MEDIUM
Hydrolysis of an ester in acid medium
Decomposition of ACETALDEHYDE
Isomerisation of cyclo PROPANE to propene

Answer :A
14285.

Which is the monomer of Orlon ?

Answer»

VINYL CHLORIDE
STYRENE
Vinyl cynide
Butadiene

Solution :Vinyl cynide
14286.

Which of following does not react with conc. HNO_(3)

Answer»

N
P
As
Pi

Answer :A
14287.

What are ambidentate ligands ? Give an example.

Answer»

SOLUTION :Ambidentate ligands are those which can link through EITHER of the TWO DONOR atoms. For example, `CN^(-)` can link through .C. or .N..
14288.

When an aqueous solution of a colourless mixture of two salts is treated with a drop of chlorine water, the solution becomes brown. Some chloroform is added to the brown solution and the resulting mixture is shaken wel. The chloroform layer becomes violet. (ii) When chlorine water is again added dropwise to the above mixture, the chloroform layer becomes colourless. (iii) On being heated with solid K_(2)Cr_(2)O_(7) and concentrated H_(2)SO_(4), the solid mixture gives vapours of a dark colour which form a yellow solution with aqueous NaOH. On acidification with acetic acid followed by treatment with lead acetate, the yellow solution gives a yellow precipitate. (iv) When boiled with an NaOH solution, the mixture gives a gas that produces thick white fumes with HCl vapours and turns nessler's reagent brown. the mixture does not respond to any other test for cations. (v) The mixture, on being heated, gets completely sublimed. Q. The original mixture contains:

Answer»

`NH_(4)Cl and NH_(4)BR`
`NH_(4)Br and NH_(4)I`
`NH_(4)Cl and NH_(4)I`
`NH_(4)Cl and NH_(4)NO_(3)`

Answer :C
14289.

When an aqueous solution of a colourless mixture of two salts is treated with a drop of chlorine water, the solution becomes brown. Some chloroform is added to the brown solution and the resulting mixture is shaken wel. The chloroform layer becomes violet. (ii) When chlorine water is again added dropwise to the above mixture, the chloroform layer becomes colourless. (iii) On being heated with solid K_(2)Cr_(2)O_(7) and concentrated H_(2)SO_(4), the solid mixture gives vapours of a dark colour which form a yellow solution with aqueous NaOH. On acidification with acetic acid followed by treatment with lead acetate, the yellow solution gives a yellow precipitate. (iv) When boiled with an NaOH solution, the mixture gives a gas that produces thick white fumes with HCl vapours and turns nessler's reagent brown. the mixture does not respond to any other test for cations. (v) The mixture, on being heated, gets completely sublimed. Q. What is the oxidation sate of the central atom in the anion constituting the yellow precipitate obtained in (iii)?

Answer»

0
`+2`
`+4`
`+6`

ANSWER :D
14290.

Which of the following statement(s) is/are correct for given compound :

Answer»

It is a OPTICALLY active compound
It can SHOW geometrical isomerism
It posses centre of symmetry but not PLANE of symmetry
It is a meso compound

Answer :B::C
14291.

Write the chain is isomers of the compound having formula C_(5)H_(11) Cl. Give their IUPAC names also.

Answer»

Solution :`CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)-BR rightarrow` BROMO pentane.
`CH_(3) underset(CH_(3))underset(|)(CH)-CH_(2)CH_(2)-Br -1" Bromo -3-methylbutane"`
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-Br to "1-Bromo-2-methylbutane"`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-Br to "1-Bromo -2, 2-dimethylpropane"`
14292.

When solution of 5g of iodine in CS_(2) was shaken with the same volume of water. The amount of iodine in water is (Distribution coefficient (C_(CS_(2)))/(C_(CS_(2)))=420

Answer»

`1.19`
`0.0019`
`0.0119`
`0.119`

Solution :Let the amount of iodine in water be a GM , `C_(1)=5g` in X MOL of `CS_(2), C_(2)-5-a` g in x ml of `H_(2)O`. Then `(5-a)/(a)=420`, thereforea=0.0118`
14293.

Which of the following reagents would distinguish cis-cyclopenta-1, 2-diol from the trans-isomer ?

Answer»

ALUMINIUM ISOPROPOXIDE
`MnO_2`
Acetone
Ozone

ANSWER :C
14294.

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Qand R arehomonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The incorrect statements is :

Answer»

If R has 15 electrons then bond order of R is GREATER than its parent molecule
If Q has 17 electrons then bond order of Q is less than its parent molecule
If P has 17 electrons then bond order of P is greater than its parent molecule
On addition of TWO electrons inP(having 13 electrons) the bond order remains same

Answer :C
14295.

The source of nitrogen in Gabriel synthesis of amines is

Answer»

Sodium azide `(NaN_3)`
Sodium nitrite `(NaNO_2)`
POTASSIUM CYANIDE (KCN)
Potassium phthalimide `[C_6 H_4 (CO)_2N^(-) K^(+)]`

Solution :`C_6 H_4 (CO_2 ) N^(-) K^(+)`
14296.

Which one of the following is an example of cationic complex ?

Answer»

`NA[Ag(CN)_(2)]`
`[Ag(NH_(3))_(2)]CL`
`[Ni(CO)_(4)]`
`K_(4)[Fe(CN)_(6)]`

Answer :A::B::C
14297.

Which of the following compounds gives iodoform with I_(2) + NaOH

Answer»

`CH_(3)CH_(2)OH`
`CH_(3)CH_(2)CH_(2)OH`
`CH_(3)OH`
`CH_(3)COOH`

SOLUTION :The compounds having FOLLOWING types of STRUCTURE
`CH_(3)-underset(O)underset(||)C-R or CH_(3)-underset(OH)underset(||)CH-R`
(R = H or ALKYL) give IODOFORM with `I_(2) + NaOH`
14298.

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Qand R arehomonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The correct statement is :

Answer»

<P>If P is having 13 ELECTRONS then removal of one electron retains its MAGNETIC behaviour
If Q is having 17 electrons then addition of one electron retains its magnetic behaviour
If R is having 15 electrons then addition of one electron retains its magnetic behaviour
If T is having 12 electrons then addition of one electron retains its magnetic behaviour

Answer :C
14299.

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Qand R arehomonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. According to given information the incorrect match is :

Answer»

`P=N_(2)^(+)`
`R=O_(2)^(+)`
`S-CO^(+)`
`T=CN^(+)`

ANSWER :C
14300.

The transition element that has stable configuration in +1 oxidation state is

Answer»

Cu
Zn
Sc
Mn

Answer :A