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17901.

Which of the following is correct order of decreasing S_(N)2 reactivity ?

Answer»

`R_(2)CHX GT R_(3)CX gt RCH_(2)X`
`RCH_(2)X gt R_(3)CX gt R_(3)CX`
`RCH_(2)X gt R_(2)CHX gt R_(3)CX`
`R_(3)CX gt R_(2)CHX gt RCH_(2)X ""` (X = HALOGEN)

Solution :Reactivity decreases as the STERIC HINDRANCE i.e., number of alkyl substituents at `alpha` - carbon increases, so option (C ) is correct.
Discussion
17902.

The zwitter ion accepts and donates a proton at ___ and ___ pH values.

Answer»

LOW and HIGH
high and low
low and ZERO
high and 7

SOLUTION :low and high
Discussion
17903.

Xenon hexafluoride on partial hydrolysis produces compounds "X and Y" compounds "X" and "Y" and the oxidation state of xenon are respectively............

Answer»

`XeO_(2)F_(2)(+6)` and `XeO_(2) (+4)`
`XeO_(2)(+4)` and `XeO_(3)(+6)`
`XeO_(4)(+6)` and `XeO_(3)(+6)`
`XeOF_(4)(+6)` and `XeO_(2)F_(2) (+6)`

ANSWER :D
Discussion
17904.

Which of the following is an example for auto catalysis

Answer»

`CH_(3)COOC_(2)H_(5)+H_(2)OrarrCH_(3)COOH+C_(2)H_(5)OH`
`N_(2)+3H_(2)rarr2NH_(3)`
`2SO_(2)+O_(2)rarr2 SO_(3)`
`C_(12)H_(12)O_(11)+H_(2)OtoC_(6)H_(12)O_(6)+C_(6)H_(12)O_(6)`

ANSWER :A
Discussion
17905.

Two elements 'A' and 'B' form compounds having formulae AB_(2) and AB_(4). When dissolved in 20g of benzene, 1g of AB_(2) lowers the freezing point by2.3^(@)C whereas 1g of AB_(4) lowers the freezing point by 1.3^(@)C. Calculate the atmoic weights of A and B . (K_(f) for benzene =5.1^(@)Cm^(-1))

Answer»


ANSWER :`25.57`, `42.63`
Discussion
17906.

Which of the following compounds (s) has Z configuration? I. II. III.

Answer»

Only I
Only II
Only III
I and III

Solution :When the groups with higher priority (i.e. with high atomic number) are present on same side of double bond, then the CONFIGURATION is Z but when present on OPPOSITE side of double bond, the configuration is E.

(Priority : `Cl gt H` and `Br gt F`)
(ii)
(Priority : `Cl gt H` and `Br gt F`)

(Priority : `Br gt Cl` and `CH_(3) gt H)`
HENCE, compounds (i) and (iii) have (Z) configuration.
Discussion
17907.

What happens when phenol is treated with ice cold bromine dissolved in CS_2 ?

Answer»

SOLUTION :
Discussion
17908.

Which of the following will show geometric as well as optical isomerism ?

Answer»

`[Pt(NH_(3))_(2)Cl_(2)]`
`[Pt(NH_(3))_(2)Cl_(4)]`
`[Pt(en)_(3)]^(4+)`
`[Pt(en)_(2)Cl_(2)]`

Solution :The cis-isomer of `[Pt(en)_(2)Cl_(2)]` isomerism.
Discussion
17909.

The standard electrode potentials (E_(M^(+)//M)^(@))of four metals A,B,C and D are -1.2 v, 0.6 V, 0.85 V and- 0.76 V, respectively. The sequence of deposition of metals on applying potential is:

Answer»

A,C,B,D
B,D,C,A
C,B,D,A
D,A,B,C

Solution :As the value of reduction potential DECREASES the reducing power INCREASES i.e.
`C LT B lt D lt A`
`(0.85), (0.6),(-0.76)(-1.2)`
Discussion
17910.

What are antibiotics ? Name any two antibiotics which are specific for certain diseases.

Answer»

Solution :Antibiotics. These are the chemical substances produced by micro-organisms (BACTERIA, FUNGI and moulds) which can INHIBIT the growth or EVEN destroy other micro-organisms . Two antibiotics are :
(i) Pencillin
(II) Streptomycin
Discussion
17911.

Which of the following is wrong:

Answer»

ENTHALPY ( NUMERICAL value ) of physisorption is GREATER than that of chemisorption
Physisorption is not very specific but chomisorption is highly specific
Chemisorption takes place at relatively high temperatures
In physisorption GENERALLY multi`-` molecular layers are formed on the adsorbent

Solution :from the knowledge of two TYPES of adsorptions.
Discussion
17912.

Whichof the following pairs of metals is purified by van Arkel method ?

Answer»

ZR an Ti
Ga and In
Ni and Fe
Ag and Au

Answer :A
Discussion
17913.

Which of the following will have the highest coagulating power for As_(2)S_(3) colloid ?

Answer»

`PO_(4)^(3-)`
`SO_(4)^(2-)`
`AL^(3+)`
`Na^(+)`

SOLUTION :According to HardySchulze rule,
(i) Greather the valency of the active ION or flocculating ion, greather will be its coagulating power.
(ii) The ion carrying the charge opposite to that of sol particles are EFFECTIVE in cousing coagulation of the sol. Thus , to COAGULATE negative of `As_(2)S_(3)`, the coagulating power of `Al^(3+)` is more than `Na^(+)`
Discussion
17914.

When excess ammonia is added to CuSO_(4) solution, the deep blue complex obtained is

Answer»

tetrahedral and PARAMAGNETIC
tetrahedral and diamagnetic
square planar and diamagnetic
square planar and paramagnetic

SOLUTION :The deep blue complex obtained is `[Cu(NH_(3))_(4)]^(2+)` which is square planar and paramagnetic.
Discussion
17915.

The well known refrigerant freon has the structure_____.

Answer»

SOLUTION :`CF_(2)Cl_(2)`
Discussion
17916.

The set of compounds in which the reactivity of halogen atom in the ascending order is

Answer»

vinyl chloride, chloroethane, CHLOROBENZENE
vinly chloride, chlorobenzene, chloroethane
chloroethane, chlorobenzene, vinyl chloride
chlorobenzene, vinyl chloriede, chloroethane

Solution :In chloroethane the C-Cl bond is HIGHLY polar, C is the POSITIVE pole and Cl is the negative pole. This makes the C atom susceptible to nucleophilic attack. On the OTHERHAND in chlorobenzene and vinyl chloride Cl atom is bonded to an `sp^(2)` hybridixsed C and the `pi` electrons of Cl are involved in `p-pi` conjugation which gives the C-Cl bond a double bond character and also REDUCES the dipole moment of C-Cl bond. since the Cl atom of chlorobenzene is in conjugation with a benzene ring C-Cl bond is much less polar. owing to the +R effect of Cl atom vinly chloride undergoes `S_(N)` reaction in drastic condition. The ascending order of reactivity of halogen atoms is chlorobenzene
Discussion
17917.

Give an expression for the work done in a reversible isothermal expansion of an ideal gas.

Answer»

ZERO
`-2.303 " R LOG"(V_(2))/(V_(1))`
`-2.303" RT log"(V_(2))/(V_(1))`
`2.303" RT log"(V_(2))/(V_(1))`

ANSWER :C
Discussion
17918.

Which will weigh more at STP

Answer»

ONE LITRE of `Cl_(2)`
One litre of `H_(2)`
One litre of `N_(2)`
One litre of `O_(2)`

Answer :A
Discussion
17919.

Which one of the following statements related to lanthanons is correct ?

Answer»

All the lanthanons are much more reactive than aluminium
`Ce^(+4)` SOLUTION are widely used as oxidizing agent in volumetric analysis
Europium shows +2 oxidation state
The basicity decreases as the ionic radius decreases from Pr to Lu

Solution :(A) Lanthanon.s are less reactive than aluminium due to high IP (Lanthenoid contraction)
(B) `Ce^(+4)` is good oxidising agent and easily converted into `Ce^(+3)`
(C ) Eu (63) = `4f^(7) 5d^(0) 6s^(2), Eu^(+2)= 4f^(7)`
(D) In lanthenoids SERIES .Ce. to Lu ionic radius regular decrases and covalent character increase, basic character of hydroxide decrease.
Discussion
17920.

Which one of the following is not a property of hydrophilic sols ?

Answer»

High concentration of DISPERSED phase can be EASILY attained.
Coagulation is reversible.
Viscosity and SUFACE TENSION are about the same as for water.
None of water.

Solution :The viscosity of hydrophilic sols is higher and SURFACE tension is lower than that of water (dispersionmedium).
Discussion
17921.

Which of the following is a strong electrolyte ?

Answer»

`Ca(NO_(3))_(2)`
`HCN`
`H_(2)SO_(3)`
`NH_(4)OH`

Solution :A salt of STRONG ACID `(S_(A))` and strong base `(S_(B)), e.g., Ca(NO_(3))_(2)` is completely ionized and hence acts as a strong electrolyte.
Discussion
17922.

Which of the following are true for the complex Ni(CN)_4^(2-)ion (A) Hybridisation of Ni^(2+)ion is dsp^2 (B) Shape of the complex ion is planar square (C) Magnetic moment of the complex is 2.83 BM (D) The complex is an example for a high spin complex

Answer»

A and B
C and D
A and C
B and D

ANSWER :A
Discussion
17923.

Which is the correct order of acidity of alcohol ?

Answer»

` 1^(@) gt2^(@) GT 3^(@)`
` 3^(@) gt2^(@) gt 1^(@)`
` 1^(@) lt2^(@) LT 3^(@)`
` 2^(@) gt1^(@) gt 3^(@)`

Solution :
Discussion
17924.

What happen when aniline is treated with bromine ?

Answer»

SOLUTION :
Discussion
17925.

Which ofthefollowingisleasthydrolysed ?

Answer»

` Be Cl_ 2`
`MG CL _ 2`
`CaCl _ 2`
`BaCl_ 2 `

SOLUTION :` BeCl_ 2` iscovalentwhereasall other group - II metalhalides areelectrovalent. THEREFORE,`BeCl _ 2 `is leasthydrolysed.
Discussion
17926.

Which of the following statement is incorrect for electrons of 3d and 4f series?

Answer»

Electrons of 3d-orbital CONTAINS more OXIDATION statethan 4F series
The energy between 3d and 4S orbital is very less
Europium (II) is more stable than CERIUM (II)
While going from scandium to copper diamagnetism in 3d-orbital increases

Answer :D
Discussion
17927.

Which of the following has been arranged in order of decreasing bond length ?

Answer»

`P-O GT S-O gt Cl-O`
`P-O gt Cl-O gt S-O`
`S-O gt Cl-O gt P-O`
`Cl-O gt S-O gt P-O`

ANSWER :A
Discussion
17928.

Which of thefollowingreactionswill notyieldalcoholas themajorproduct ?

Answer»




SOLUTION :NA
Discussion
17929.

Using MOT, compare O_2^(+) and O_2^(-) species and choose the incorrect option.

Answer»

`O_(2)^(-)` is less STABLE
Both `O_(2)^(+) and O_(2)^(-)` are paramagnetic
`O_(2)^(+)` have higher BOND orderthan `O_(2)^(-)`
`O_(2)^(+)` is diamagnetic while `O_(2)^(-)`is paramagnetic .

Solution :Molecular orbital configuration of `sigma1s^(2)"*"1s^(2)sigma2s^(2)sigma "*"2s^(2)sigma2p_(z)^(2) pi2p_(X)^(2)= pi2p_(y)^(2) pi "*"2p_(x)^(1)`
Bond order ` = 1/2 (10-5) = 2.5`
Number of unpaired electrons = 1 , HENCE paramagneticc
Molecular orbital configuration of `O_(2)^(-): sigma1s^(2) sigma^("*")sigma 2s^(2)sigma^"*"2s^(2) sigma 2p_(z)^(2)pi2p_(x)^2 = pi2p_(y)^(2) pi"*" 2p_(x)^(2)= pi"*"2p_(y)^(1)`
Bond order`=1/2 (10-7) = 1.5`
Number of unpaired ELECTRON = 1 , henceparamagnetic
Both `O_(2)^(+) and O_(2)^(-) ` are paramagnetic
`O_(2)^(+)` have higherbondorder than `O_(2)^(-)`
`O_(2)^(-)` is less stable .
Discussion
17930.

The two stereoisomers of 1 - bromo-1, 2-dichloroethene can - not be designated as cis and trans in the normal way because the double bond is trisubstituted. They can, however, be given ( E) and (Z) designations. Write a structural formula for each isomer and give each the proper designation.

Answer»

Solution :We write the structures (below), then note that chlorine has a HIGHER priority than hydrogen, and bromine has a higher priority than chlorine. Thegroup with higher priority on C1 is bromine and the GROUP with higher priority at C2 is chlorine. In the first structure the higher priotrity chlorine and bromine atoms are on opposite sides of the doube bond, and therefore this ISOMER is ( E). In the second structure those chlorine and bromine atoms are on the same side, so the LATTER isomer is (Z).
Discussion
17931.

Total number of geometrical isomers of [M(AB)c_(2)d_(2)]:

Answer»

4
7
6
8

Answer :A
Discussion
17932.

van.t Hoff factor of very dilute solution of Ca(NO_3)_2 is:

Answer»

1
2
3
4

Answer :C
Discussion
17933.

Which of the following electrolytes will be most effective in causing the coagulation of a positively charged ferric hydroxide sol?

Answer»

`K_(2)SO_(4)`
`K _(3) Fe (CN)_(6)`
KCl
`K_(2)CO_(3)`

SOLUTION :The anion having higher CHARGE `[Fe (CN)_(6)]^(3-)`
Discussion
17934.

Which of the following statements is/are correct :

Answer»

Equivalent mass of `Br_3O_8` in the reaction is 23.
`Br_3 O_8+I^(-)+H^+toBr_2+I_2+H_2O`
In case of oxalic acid `(H_2C_2O_4)`, the AVERAGE oxidation number and individual oxidation number of Carbon have the same value.
In case of iodimetric titration, KI is made to react with an oxidising agent and the liberated `I_2` gas is made to titration with hypo solution.
Equivalent mass of `Cu_3P` in the given reaction is `M//11` (where M=mol. Mass)
`Cu_3P+KMnO_4+H^+toCu^(2+)+H_2PO_4^(-)+K^+ + Mn^(2+)`

Solution :(A)v.f. of `Br_3O_8=3(16/3-0)=16 :.` equivalent mass =M/16=368/16=23.
(B)In case of oxalic acid `(H_2C_2O_4)` , the average oxidation number and individual number of Carbon have the same value, equal to +3.
( C )In case of IODOMETRIC titration, Kl is made to react with an oxidising agent and the liberatred `I_2` gas is made to titrate with hypo solution.
(D)v.f. of `Cu_3P=3(2-1)+1(5-(-3))=11 :.` equivalent mass =M/11
Discussion
17935.

Which of the following is aluminium's alloy ?

Answer»

Steel
German SILVER
ALNICO
DELTA metal

Answer :C
Discussion
17936.

Which of the following sets of quantum numbers represents the 19^("th") electron of Cr (Z= 24)?

Answer»

`(4,1,-1,+1/2)`
`(4,0,0,+1/2)`
`(3,2,0,-1/2)`
`(3,2,-2,+1/2)`

Solution :ELECTRONIC CONFIGURATION of
`Cr (24) : 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(1) 3D^(5)`
So, `19^("th")` electron is present in 4s-orbital. For 4s orbital,
n = 4, l= 0, m = 0, s = `pm1//2`
Discussion
17937.

Which of the following gives oximes with acetaldehyde?

Answer»

`H_2"NNH"_2`
2,4 - DNP
`H_2NOH`
`H_2"NNH"CONH_2`

ANSWER :C
Discussion
17938.

Which isomer of C_5 H_(11)Cl has the highest boiling point and which has the least boiling point ? Explain.

Answer»

Solution :1-Chloropentane has the highest boiling point whereas 1-chloro-2,2-dimethylpropane has the least boiling point. 1-Chloropentane is the unbranched CHAIN isomer with STRONGEST intermolecular FORCES.
1-Chloro-2,2-dimethyl propane has weakest inter molecular forces DUE to smallest surface area, with spherical symmetry.
Discussion
17939.

The values of van't Hoff factors for KCl, NaCl and K_(2)SO_(4), respectively, are ……

Answer»

2, 2 and 2
2, 2 and 3
1, 1 and 2
1, 1 and 1

Solution :Explanation : The VALUES of van.t Hoff factor depend UPON the EXTENT of dissociation. KCl, NaCl and `K_(2)SO_(4)` are strong electrolytes. The extent or degree of dissociation would be greatest with `Na_(2)SO_(4)` as compared to that of KCl and NaCl.
Discussion
17940.

Which one of the following does not produce O_2 as the only gaseous product on heating

Answer»

Lead NITRATE
Potassium chlorate
Mercuric oxide
Potassium nitrate

Solution :`(a) Pb(NO_(3))_(2)(s) overset(Delta)toPbO (s) +2NO_(2)(g) +1/2 O_(2)(g)`
`(b) KCl O_(3)(s)overset(Delta)toKCl (s) +3/2 O_(2)(g)`
`(c) HGO (s)overset(Delta)to HG(I) +1/2O_(2)(g)`
`(d) KNO_(3)(s) overset(Delta)to KNO_(2)(s) +1/2 O_(2)(g)`
Discussion
17941.

What would be the change in no. of electron, when silver and gold is obtained by eduction of its ion on adding Zinc respectively ?

Answer»

(2, 1)
(1, 3) 
(2, 2) 
(3, 1) 

SOLUTION :SILVER (AG):
`{:(2[Ag(CN)(2)^(-)]_((aq))+Zn_((s))rarr2A_((s))+[Zn(CN)_(4)]_((aq))^(2-)),(" "UARR""uarr),(2(+1)""("Reduction by")/("Change of e"^(-))""(0)2):}`
GOLD (Au) :
`{:(2(Au(CN)_(2))_((aq))^(-)+Zn_((s))rarr2Au_((s))+(Zn(CN)_(4))_((aq))^(-)),(" "uarr""uarr),(2(+1)""("Reduction by")/("Change of e"^(-))""(0)2):}`
Discussion
17942.

The solution which show positive or negative deviation from Raoult's law are called:

Answer»

IDEAL solutions
True solutions
Non-ideal solutions
Colloidal solutions

Answer :C
Discussion
17943.

Which gives offensive smell with CHl_3 and KOH :

Answer»

`1^@` AMINE
`2^@` amine
`3^@` amine
All

Answer :A
Discussion
17944.

Which of the followingis vaska's compound

Answer»

`[NI(P Ph_(3))_(2)Cl_(2)]`
`[Rh(CO)_(2)Cl]_(2)`
trans-`IRCL(CO) (P Ph_(3))_(2)`
`IrCl(CO)_(2)(P Ph_(3))_(2)`

Solution :Vaska's complex is the trivial name for the CHEMICAL compound trans-chlorocarbonyl-bis- ( triphenylphosphine) iridium (I) , which has the formul a `[IR ( Cl) (CO) (P Ph_(3))_(2) ]`
Discussion
17945.

when citric acid is heated at 150^@ C, the main product formed is :

Answer»

ACETONE
Aconitic ACID
Ethanal
None of these

Answer :B
Discussion
17946.

Which element show the maximum difference in the oxidation state of its compounds ?

Answer»

La
Sm
Gd
Am

Answer :D
Discussion
17947.

Which out of CH_(3)O^(Theta) and CH_(3)S^(Theta) will react with CH_(3)Br in a protic solvent?

Answer»

Solution :Since 'S' of `CH_(3)S^(Theta)` is LESS electornegative and more polarisible than 'O' in `CH_(3)O^(Theta), CH_(3)S^(Theta)` ACTS as BETTER nucleophile to react with `CH_(3)BR` in protic solvent.
Discussion
17948.

The stability of a lyophobic colloid is due to

Answer»

adsorption of COVALENT MOLECULES on the colloid
the SIZE of the particles
the charge on the particles
Tyndall effect.

Answer :C
Discussion
17949.

What is the relationship between Gibbs free energy of the cell reaction is a galvanic cell and the emf of the cell ? When will the maximum work be obtained from a galvanic cell ?

Answer»

Solution :* In general
`Delta_(r)G^(@)=nFE`
Where, `Delta_(r)G^(@)=`Gibbs energy of the cell reaction.
n=Number of moles of electrons TRANSFERRED in the redox reaction taking place in a cell.
F=Faraday CONSTANT
E=Cell emf
* Using standard conditions, the reaction is
`Delta_(r)G^(@)=nFE^(@)`
Where, `Delta_(r)G^(@)=`standard Gibbs energy of the cell reaction,
* `E^(@)=`Standard cel emf
If we want to obtain maximum work from a galvanic cell than charge has to be PASSED reversibly.
Discussion
17950.

Which of the following electronic configuration would you expect to have the highest second ionization enthalpy :

Answer»

`1S^(2) 2S^(2) 2P^(6) 3s^(2)`
`1s^(2) 2s^(2) 2p^(6) 3s^(1)`
`1s^(2) 2s^(2) 2p^(6)3s^(2) 3p^(4)`
`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(5)`

ANSWER :B
Discussion