Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

20301.

Write the monosubstituted compounds formed in each of thefollowing reactions and state whether each reaction is faster or slower than that of benzene. 3 Chlorination of C_6H_5CMe_3

Answer»

<P>

Solution :p-`ClC_6H_4CMe_3` (for this COMPOUND chlorination OCCURS FASTER than BENZENE )
20302.

Write the monosubstituted compounds formed in each of thefollowing reactions and state whether each reaction is faster or slower than that of benzene. 4 Nitration of C_6H_5-C_6H_5

Answer»

SOLUTION :`p-O_2NC_6H_4C_6H_5` (for this compoundnitration OCCURS than BENZENE )
20303.

Write the monosubstituted compounds formed in each of thefollowing reactions and state whether each reaction is faster or slower than that of benzene. 1 Nitration of C_6H_5 NHCOCH_3,

Answer»

<P>

Solution :p-`O_2NC_6H_4NHCOCH_3` (for this compound NITRATION OCCURS FASTER than BENZENE).
20304.

Write the monosubstituted compounds formed in each of thefollowing reactions and state whether each reaction is faster or slower than that of benzene. 2 Bromination of C_6H_5Br_3,

Answer»

SOLUTION :`m-BrC_6H_4CBr` (for this BROMINATION OCCURS SLOWER than BENZENE )
20305.

Which statement is incorrect about transiton elements?

Answer»

All ELEMENTS FORM complexes
All are paramagnetic
All show VARIABLE valency
All are not coloured ions

Answer :B
20306.

Which of the following will form beta - aminoalcohol with ethylene oxide ?

Answer»

`HOH//H^(o+)`
`NH_3`
`(CH_3)_2CuLi`
`CH_3MgBr`

ANSWER :B
20307.

which one can be easily hydrated ?

Answer»

WIDTH="30%">


SOLUTION :One can be EASILY hydrated. Electron with drawing group bonded at Ortho and PARA easily hydrated
` (##AKS_TRG_AO_CHE_XII_V02_B_C03_E03_008_S01.png" width="80%">
20308.

Write the structure of following compounds. [PtCI_4]^(2-)

Answer»

SOLUTION :TETRAHEDRAL
20309.

When Pb O_(2) reacts withconcentrated HNO_(3), the gas evolved is

Answer»

`NO_2`
`O_2`
`N_2`
`N_2O`

SOLUTION :`2bO_2+4HNO_3 rarr2Pb(NO_3)_2+2H_2O+O_2darr`
20310.

Write the IUPAC name of the compound

Answer»

SOLUTION :1-(4-Nitrophenyl) PROPANE
20311.

Which statement is correct:

Answer»

Reactions with LOW activation energy are usually exothermic
The rate law sometimes ENABLES to deduce the mechanism of a reaction
The rate law for a reaction is an algebraic ,expression relating the forward reaction rate to product concentration
INCREASE in the total pressure of a gas PHASE reaction increase the fraction of collisions effective in producing reactions

Answer :D
20312.

Which comopund has higher boiling point than other : Pentane orPentanol ?

Answer»

SOLUTION :PENTANOL
20313.

True statements is//are :

Answer»

STRUCTURE of `X` is
Structure of `X` is
`Y` on MONOCHLORINATION PRODUCE `3` monochloro structral products.
Oxidative OZONOLYSIS PRODUCT of `X` is ,

Solution :
20314.

The tests that confirms the presence the aldehydic group is

Answer»

REDUCTION of Tollen's reagent to metallic silver.
reduction of Felings's SOLUTION of RED cuprous oxide.
both (a) and (b)
non of the above

Solution :both (a) and (b)
20315.

Two moles of an ideal expand spontaneously into a vacuum. The work done is

Answer»

2 Joule
4 Joule
Zero
Infinite

Solution :An IDEAL GAS under going EXPANSION in vacuum shows,
`DeltaE=0,W and q=0`.
20316.

Which of the following are not postulates of Werner? (P) In co-ordination compounds, metals show two types of linkage(valencies) primary and secondary (Q) The primary valencies are normally ionisable. These are satisfied by netural molecules or negative ions. The secondary valency is equal to the co-ordination number and is fixed for a metal The ions/groups bound by the primary and secondary linkagesto the metal have characteristic spatial arrangements corresponding to different coordination numbers (T) Octahedral, Tetrahedral and Square planar geometrical shapes are more common in co-ordination compounds of transition metals

Answer»

(P), (Q), (R ) and (S)
(S) and (T)
(S)
(P), (Q), and (R )

SOLUTION :Spatial ARRANGEMENTS depends only on SECONDARY valencies and not primary valencies.
20317.

Unit of frequency factor A in : KL+AE^(-Ea//RT) is

Answer»

`"TIME"^(-1)`
mole `"LITRE"^(-1)"time"^(-1)`
litre`"MOL"^(-1)t^(-1)`
dependent of order of reaction

Solution :unit of A DEPENDS on order
20318.

Which of the following cannot liberate H_2 with acids ?

Answer»

Al
B
Ti
In

Answer :B
20319.

The substances which have the largest concentration in acid rain.

Answer»

`H_(2)CO_(3)`
`HNO_(3)`
`HCl`
`H_(2)SO_(4)`

Answer :D
20320.

Which one of the following is a protein ?

Answer»

Rayon
Nylon
Natural silk
Dacron

Answer :C
20321.

Write the products formed when (CH_(3))_(3)C-CHO reacts with the following reagents : (i) CH_(3)COCH_(3) in the presence of dilute NaOH. (ii) HCN. (iii) Conc. NaOH.

Answer»

Solution :(i) `CH_(3)COCH_(3)` in the PRESENCE of dilute NAOH
`(CH_(3))_(3)C-UNDERSET(OH)underset(|)CH-CH_(2)COCH_(3)`
(II) HCN

(iii) Conc. NaOH
`(CH_(3))_(3)C-CH_(2)OH` and `(CH_(3))_(3)C-COONa`
20322.

Zn_((s)) + 2[Au(CN)_(2)]_((aq))^(-) rarr [Zn(CN)_(4)]_((aq))^(2-) + 2Au_((s)) In the above equation, the oxidation state of metallic gold is ________

Answer»

1
0
`+2`
`-2`

ANSWER :B
20323.

Which is most acidic ?

Answer»

`C Cl_(3) COOH`
`CHCl_(2)COOH`
`CH_(2)ClCOOH`
`CH_(3)COOH`

ANSWER :A
20324.

What is covalency of chlorine atom in second excited state ?

Answer»


ANSWER :5
20325.

Which of the following compound has highest reactivity towards S_(N)1 reaction ?

Answer»

`C_(6)H_(3)C(CH_(3))(C_(6)H_(5))Br`
`C_(6)H_(5)CH_(2)Br`
`C_(6)H_(5)CH(C_(6)H_(5))Br`
`C_(6)H_(5)CH(CH_(3))Br`

ANSWER :A
20326.

Which is not an oxidizing agent in acidic medium?

Answer»

`CrO_(3)`
`Cr_(2)O_(7)^(2-)`
`WO_(3)`
`MnO_(4)^(-)`

SOLUTION :`WO_(3)` is stable OXIDE
20327.

Which of the following is/are amphoteric?

Answer»

 Beo
 `Ag_(2)O`
 `CO_(2)`
 `SnO_(2)`

Solution :BeO and `SnO_(2)` are AMPHOTERIC, `CO_(2)` is acidic WHEREAS `Ag_(2)O` is BASIC in NATURE.
20328.

Which of the following balides are not soluble in water ?

Answer»

`AGCI`
`AgBr`
`PbCI_(2)`
`AgF`

Answer :a,b,C
20329.

What are emulsion? Mention its type with example. What is emulsification? How the types of emulsions are identified?

Answer»

SOLUTION :(i) Emulsions are colloidal solution in which a liquid dispersed in ANOTHER liquid.
(ii) TWO types of emulsions -
(a) Oil in Water (O/W) e.g., mayonnaise
(b) Water in Oil (W/O) e.g., Butter
(iii) The process of preparation of emulsion by the dispersal of one liquid in another liquid is called emulsification.
(iv) Identification of types of emulsions:
The two types of emulsions can be identified by the following tests
(a) Dye test: A small amount of dye soluble in oil is added to emulsion. The emulsion is shaken well. The aqueous emulsion will not take the colour whereas oily emulsion will take up the colour of the dye.
(b) Viscosity test: Viscosity of the emulsion is determined by experiments. Oily emulsions will have higher VALUE than aqueous emulsions.
(c) CONDUCTIVITY test:- Conductivity of aqueous solutions are always higher than oily emulsions.
(d) Spreading test: Oily emulsions spread readily than aqueous emulsion when spread on an oily surface.
20330.

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules ?

Answer»

`I_(2) GT Br_(2) gt Cl_(2) gt F_(2)`<BR>`Cl_(2) gt Br_(2) gt F_(2) gt I_(2)`
`Br_(2) gt I_(2) gt F_(2) gt Cl_(2)`
`F_(2) gt Cl_(2) gt Br_(2) gt I_(2)`

Answer :C
20331.

Which of the foliowing is a fast reaction ?

Answer»

`H_2+Cl_2 tooverset(HV) to 2HCL`
`NO_2 + CO to NO +CO_2`
`CH_3CHO to CH_4 +CO`
`6CO_2 +6H_2O OVERSET(hv) to C_6H_12O_6 + 6O_2`

Solution :Photosynthesis in plants is a fast REACTION.
20332.

Which of the following are true about silicones?

Answer»

They are formed by hydrolysis of `R_(2) SiCl_(2)`?
They are POLYMER, made up of `R_(2)SiO_(2)` units
They are made uo of `SiO_(4)^(4-)` units
They are marcromolecules

Answer :A::B::D
20333.

Two particles A and B are in motion. If the wavelength associated with the particle A is 5.0xx10^(-8)m ,the wavelength of particle B having momenthalf of A is

Answer»

<P>`2.5xx10^(-8)m`
`1.25xx10^(-8)m`
`1.0xx10^(-7)m`
`1.2xx10^(-8)m`

SOLUTION :`lamda_(A)=h/(p_(a))""lamda_(B)=h/(p_(B))`
`p_(B)=p_(A)//2`
`(lamda_(B))/(lamda_(A))=(P_(A))/(P_(B))=(P_(A))/(P_(A//2))=2`
`:.lamda_(B)=2xxlamda_(a)=2xx5xx10^(-8)m=1xx10^(-7)m`
20334.

What do you understand by the term glycosidic linkage ?

Answer»

Solution :The oxide linkage between two monosaccharide units in disaccharide or POLYSACCHARIDE is called GLYCOSIDIC linkage. The oxide linkage is formed by the loss of water MOLECULE. For example, when maltose is hydrolysed, the two units of gluocose are obtained. Thus, the two GLUCOSE units are LIKED through oxide linkage in a maltose called glycosidic linkage.
20335.

Volume of a gas at STP is 1.12 xx 10^(-7) cm^3.The number of molecules present in it is

Answer»

`3.01 xx 10^8`
`3.01 xx 10^22`
`3.01 xx 10^11`
`3.01 xx 10^12`

SOLUTION :`22400 cm^3` of the gas at STP has molecules ` = 6.02 xx 10^23`
`1.12 xx 10^(-8) cm^3` of the gas at STP will have molecules
` = (6.02 xx 10^23)/(2400) xx 1.12 xx 10^(-8)`
` = 3.01 xx 10^11 ` molecules
20336.

When 1-chloropropane is treated with alc. Potash gives propene. The reacts is

Answer»

elimination
SUBSITUTION
addition
dehyderation

Solution :This is elimination REACTION, in which halogen and HYDROGE areremoved froma ADJACENT carbon atom and produce prepene
20337.

What product is formed when acetic acid heated with P_(2)O_(5)

Answer»

ACETYL chloride
Acetate ester
Acetic anhydride
Acetaldehyde

Answer :C
20338.

Transition temperature between rhombic and monoclinic sulphur is

Answer»

`26^(@)C`
`95.6^(@)C`
`70^(@)C`
`100^(@)C`

Answer :B
20339.

Which of the following can't be prepared by the typical Williamson reaction ?

Answer»

`R_3COCR_3`
`ArOAr`
`RCH=CHOCH=CHR`
`C_6H_5CH_2OC_2H_5`

Solution :TERT and sec carboncations are liable to undergo elmination REACTION in prsence of strong alkoxide bases.Aryl and VINYL HALIDES do not undergo nucleophilic SUBSTITUTION.
20340.

Write important characteristics of transition elements.

Answer»

Solution :The GENERAL CHARACTERISTICS of transition elements are : (1) Most of the transition elements are HARD metals. (2) They have high boiling and melting points. (3) They form metal alloys with transition and other metals. (4) They are very good conductors of heat and electricity. (5) Most of the elements show variable valencies in different COMPOUNDS. (6) They generally form coloured compounds. (7) Their compounds are usually paramagnetic in nature. (8) MAny transition elements and their compounds are used as catalysts in various chemical reactions. (9) Transition elements form INTERSTITIAL compounds. (10) Metal ions have high enthalpies of hydration.
20341.

What happens when n-butyl chloride is treated with alcoholic KOH.

Answer»

SOLUTION :The reactions are explained as under :
`underset("n-Butyl CHLORIDE") (CH_(3)CH_(2) - ) CH_(2) - CH_(2)Cl + KOH (alc.) underset("DEHYDROHALOGENATION ")overset (Delta ) to CH_(3)CH_(2) - CH = CH_(2) + KCl + H_(2) O `
20342.

Which of the following molecules/ions does not contain unpaired electrons ?

Answer»

1. `B_(2)`
2. `N_(2)^(+)`
3. `O_(2)`
4. `O_(2)^(2-)`

Solution :Molecular ORBITAL electronic configuration are :
`O_(2) : KK(sigma_(2S))^(2)(sigma_(2s)^(**))^(2)(sigma_(2s)^(2))^(2)(pi_(2px)^(2))^(2)(pi_(2py)^(2))^(2)`
`(pi_(2px)^(**))^(1)(pi_(2py)^(**))^(1)`(2 unpaired electrons)
`O_(2)^(2-) : KK (sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(sigma_(2pz))^(2)(pi_(2px))^(2)(pi_(2py))^(2) (""^(**)pi_(2px))^(2)(pi_(2py)^(**))^(2)`(no unpaired ELECTRON)
`N_(2)^(+) :KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2px))^(1)(pi_(2py))^(1)` (1 un-paired electrons)
`B_(2) : KK (sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2px))^(1)(pi_(2py))^(1)`(2 unpaired electrons).
20343.

When acetylene passed through red hot Fe tube hybridization of C changes from to

Answer»

`SP^(2), sp`
`sp^(2), sp^(3)`
`sp, sp^(2)`
`sp^(3), sp^(2)`

ANSWER :B
20344.

Which of the following compounds will undergo recemisation when hydrolysed with a solution of KOH-

Answer»

i & ii
ii & IV
iii & iv
i & iv

Solution :No option is CORRECT. Only (iv) undergoes racemisation.
20345.

Which of the following is not a hydrated oxide mineral?

Answer»

Bauxite
Corundum
Diaspore
Gibsite

Answer :2
20346.

Which of the following statements is correct about halogens ?

Answer»

They are all capable of exhibiting more than ONE oxidation STATES
They are all DIATOMIC and form diatomic ions
They are all diatomic and form univalent ions
They are all REDUCING agents .

Answer :C
20347.

Which of the following alcohols on oxidation give carboxylic acids with lesser number of carbon atoms?

Answer»

`(CH_(3))_(3)C-CH_(2)OH`
`(CH_(3))_(3)COH`
`CH_(3)CH_(2)CHOHCH_(3)`
Both (b) and (c)

SOLUTION :Secondary and TERTIARY alcohols on oxidation give carboxylic acids with lesser number of carbon atoms.
20348.

What is the hybridization on the central atom of SiO_(2).

Answer»

`sp`
`sp^(2)`
`sp^(3)`
`sp^(3)d`

SOLUTION :`SiO_(2)` is a giant molecule it MEANS one Si atom with four oxygen atom and one oxygen atom combine with two Si atom
`-underset(|)underset(O)underset(|)OVERSET(|)overset(O)overset(|)(Si)-O-underset(|)underset(O)underset(|)overset(|)overset(O)overset(|)(Si)-O-underset(|)underset(O)underset(|)overset(|)overset(O)overset(|)(Si)-`
hybridisation of`Si=sp^(3)`
20349.

[Ti(H_(2)O)_(6)]^(2+) is coloured whereas [Sc(H_(2)O)_(6)]^(3+) s colourless, though it is a transition metal complex. Explain the observation.

Answer»

SOLUTION :Tit has one electron in the d-orbital `(3d^(1))` which can absorb ENERGY corresponding to yellow wavelength and jump from LOWER energy LEVEL to higher energy level. But `Sc^(3+)`has no electron in d-orbital
20350.

The volume of 0.1 M oxalic acid that can be completely oxidized by 20 mL of 0.025 M KMnO_(4) solution is

Answer»

125 mL
25 mL
12.5 mL
37.5 mL

Solution :The BALANCED equation is
`2 KMnO_(4)+3 H_(2)SO_(4)+5 H_(2)C_(2)O_(4) rarr K_(2)SO_(4)+2 MnSO_(4)+8 H_(2)O+10 CO_(2)`
`:'` Molarity `=n_(B)/V_(ml)xx1000`
`:. 0.025=n_(B)/20xx1000`
`:. n_(B)=0.025/50=5xx10^(-4)` mol of `KMnO_(4)`
SINCE 2 moles of `KMnO_(4)` completely oxidises 5 moles of oxalic ACID
`:. 5xx10^(-4)` mol of `KMnO_(4)` will completely oxidize
`=5/2xx5xx10^(-4)` mol of oxalic acid
`=1.25xx10^(-3)` mol of oxalic acid
`:'` Molarity `=n_(B)/V_(ml)xx1000`
`:. V_(ml)=n_(B)/("molarity")xx1000=(1.25xx10^(-3))/0.1 xx1000`
`( :' " Molarity of oxalic acid"=0.1 M)`
`=12.5 ml or 12.5 CM^(3)`.