This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25051. |
The quantity of .^(14)C as well as that of .^(14)CO_(2) present in the atmosphere remains constant. The concentration of .^(14)C in all living organisms remains almost constant during their life time. After their death, .^(14)C is not taken up by them but the content of .^(14)C assimilated begins to decay by emitting beta- particles, with half-life period of 5568 years. The decay rate at the time of death of plant is 16.1counts per minute per gram of carbon. Hence, by measuring the decay rate of the dead matter, the age of matter can be calculated , e.g. if decay rate of sample of wood is found to be N distengrations per minute per gram of carbon after t years, then N=N_(0)e^(-lambda t) where lambda= disntegration constant and N_(0)= number of disntegrations per minute per gram when the plant had just died. In a dead plant, the decay rate will be |
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Answer» higer than in a living PLANT |
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| 25052. |
The quantity electricity needed separately for the electrolysis of 1 M solution of ZnSO_(4), AlCl_(3) and AgNO_(3) completely is in the ratio of : |
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Answer» `2:3:1` `AL^(3+)+underset(3F)3e^(-) to underset(1mol)(Al)` `Ag^(+)+underset(1F)e^(-) to underset(1 MOL)(Ag)` The NUMBER of FARADAYS needed are in the ratio : `2F:3F:1F "or" 2:3:1`. |
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| 25053. |
The quantify of electricity required to liberate 112 cm^(3) of hydrogen at STP from acidified water is |
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Answer» 0.1 Faraday For liberation `112 cm^(3) H_(2)` at S.T.P required `= (96500 XX 112)/(11200) = 965C` |
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| 25054. |
The quantigy of electricity required to liberate 1 gram equivalent of an element is at |
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Answer» 1 AMPERE |
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| 25055. |
The quality of soap is described interms of .................... and the .................... quantity in the soap better is its quality |
| Answer» SOLUTION :TFM,TFM | |
| 25056. |
The qualitative order of Debrogile wavelegnth for electron, proton and alpha particle is lambda_(e) gt lambda_(P) gt lambda_(alpha) if |
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Answer» If KINETIC energy is same for all particles |
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| 25057. |
The qualitative analysis to the salt solution addition of reagents NH_(4)CI+NH_(4)OH and ammonium carbonate give precipitate in precipitate the oxidation state of anion (only magnitude) |
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Answer» |
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| 25058. |
The pyrolusite ore contains: |
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Answer» Fe |
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| 25060. |
The pyrimidine bases present in DNA are : |
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Answer» CYTOSINE and guanine |
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| 25061. |
The pyrimidinebase presentin DNA are ………. . |
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Answer» Cytosineand ADENINE |
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| 25062. |
The pyramidal inversion from one invertomer of chiral tetrahedral amine to another takes place via |
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Answer» Carbocationic intermediate |
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| 25063. |
The pyknometer density of NaCl crystal is 2.165 xx 10^(3) kg m^(-3) while its X -rays density is 2.178 xx 10^(3) kg m^(-3). The fraction of the unoccupied sites in NaCl crystal is : |
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Answer» 5.96 |
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| 25064. |
The putial pressure of ethane over a saturated solution containing 6.56 xx 10^(-2) g of ethane is 1 bar.if the solution contains 5.0 xx 10^(-2) g of ethane, then what will be the partial pressure of the gas ? |
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Answer» Solution :Let the Henry.s law constant be `K_(H)` and no. of MOLES of solvent be M. Partial pressure of ethane = `K_(H)` x mole fraction of ethane ` I = K_(H) XX (6.56 xx 10^(-2))/((30)/(M)) ` `K_(H) = (M xx 30)/(6.56 xx 10^(-2))` Now the partial pressure of ethane containing 5.0 `xx 10^(-2)` will be ` = (M xx 30)/(6.56 xx 10^(-2)) xx (5.0 xx 10^(-2))/(30 xx M)` = 0.762 BAR. |
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| 25065. |
The purpose of smelting of an ore is : |
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Answer» To oxidise it |
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| 25066. |
The purpose of salt bridge is to: |
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Answer» Allow electron flow |
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| 25067. |
The purpose of addition of KF to HF in the preparation of Fluorine by electrolysis is |
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Answer» to INCREASE the conductance of HF |
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| 25068. |
The purple colour of KMnO_4 is due to ___ |
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Answer» d-d transition |
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| 25069. |
The purple colour of KMnO_(4) is due to |
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Answer» Charge TRANSFER |
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| 25072. |
The purity of an organic compound is best determined by : |
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Answer» Density |
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| 25073. |
The purine heterocycle occurs mainly in the structure of DNA. Identify number of N atoms having localised lone pair of electron. |
Answer»
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| 25074. |
The purine bases present in both DNA and RNA are : |
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Answer» GUANINE and adenine |
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| 25075. |
The purine base present in RNA is |
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Answer» Guanine |
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| 25076. |
The purine base present in DNA is : |
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Answer» Adenine |
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| 25077. |
The purification of a organic compound is varified with |
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Answer» Melting point |
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| 25078. |
The purification of the colloidal particles from crystalloid dimensions through semipermeable membrane is known as: |
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Answer» Coagulation |
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| 25079. |
The purification of colloidal solution could be |
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Answer» ULTRA filtration |
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| 25080. |
The purification method used for mineral Al_2O_3. 2H_2O is : |
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Answer» FROTH floatation |
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| 25081. |
The purestform ofiron is preparedbyoxidisingimpuritiesfrom castiron inareverberatoryfurnace.Whichiron ore is usedtolinethe furnace ?Explainby givingreaction. |
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Answer» Solution :Thereverberatoryfurnaceis linedinsidewithhaematite.It suppliesthenecessaryoxygen requiredfor oxidationofimpurities ofCto`CO _ 2` S to` S O_2`,PTO`P_ 4 O_(10) ` ,MntoMnO ,etc. `Fe_2O_3(s)+3C(s)to2Fe(s)+3 CO(g) ` `2Fe_2O _ 3 (s)+3S(s)TO4 FE (s)+3SO_2 (g) ` |
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| 25082. |
The purest form of iron is prepared by oxidising impurities from cast iron in a reverberatory furnace. Which iron ore is used to line the furnace ? Explain by giving reaction. |
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Answer» Solution :The lining of FURNACE is done by Haematite `(Fe_2O_3)` which oxidises CARBON to `CO`. ` Fe_2O_3 + 3C to 2Fe + 2CO` The impurities of sulphur, silicon and PHOSPHORUS are oxidised to `SO_2, SiO_2 and P_4O_10` respectively `SO_2` ESCAPES out while `SiO_2` and `P_4O_10` are REMOVED as slag. |
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| 25083. |
The purest form of iron is |
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Answer» Pig iron |
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| 25085. |
The purest form of commercial iron is |
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Answer» PIG IRON |
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| 25086. |
The purest form of commercial iron is : |
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Answer» CAST IRON |
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| 25087. |
The pure zince carbonate is prepared by addition of the following reagent to a zinc sulphate solution |
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Answer» Sodium carbonate |
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| 25088. |
The purest form of coal is |
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Answer» PEAT |
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| 25089. |
The purest form of carbon is : |
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Answer» BITUMINOUS coal |
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| 25090. |
The pure ethanol is obtained by |
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Answer» MEMBRANE TECHNOLOGY |
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| 25091. |
The pure crystalline substance on being heated gradually first forms a turbid liquid at constant temperature and still at higher temperature turbidity completely disappears. The behaviour is a characteristics of substance forming: |
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Answer» ALLOTROPIC CRYSTAL |
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| 25092. |
The pupose of additio of KF to HF in the preparation of F_(2) by electrolysis is |
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Answer» to INCREASES the CONDUCTANCE of HF |
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| 25093. |
The pure crystalline substance on being heated gradually first forms a turbid liquid at constant temperature and still at higher temperature turbidity completely disappears. The behaviour is a characteristic of substance forming. |
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Answer» ALLOTROPIC crystals |
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| 25094. |
The pseudohalogen amongst the following is- |
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Answer» NO |
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| 25095. |
The Prussium blue colour obtained in the Lassaigne's test forn nitrogen is due to the formulaof |
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Answer» Iron (II) hexacyanoferrate (III) `underset("compound")underset(" CROM organic")(Na+C+N)OVERSET(Delta)rarrNaCN` `2NaCN + FeSO_(4)rarr Fe(CN)_(2) + Na_(2)SO_(4)` `Fe(CN)_(2)+4NaCNrarrunderset(" Sod.FERROCYANIDE")(Na_(4)[Fe(CN)_(6)]` `3Na_(4)[Fe(CN)_(6)]+4Fe_(3)^(+)rarr underset(" Porusian blue")underset(" Ferric ferrocyanide")(Fe_(4)[Fe(CN)_(6)]_(3)+12Na^(+))` |
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| 25096. |
The prussian blue colour obtained during the test of nitrogen by Lassiagne'stest is due to the formation of |
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Answer» `Fe_(4)[Fe(CN)_(6)]_(3)` |
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| 25097. |
The prussian blue colour obtained during the test of nitrogen by Lassaigne's test is due to the formation of: |
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Answer» `Fe[Fe(CN)_(6)]_(3)` |
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| 25098. |
The prussian blue colour obtained during the test of nitrogen by Lassaigne's test is due the formation of : |
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Answer» `Fe_(4)[Fe(CN)_(6)]_(3)` |
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| 25099. |
The Proudct formedin followingreactionisCH_(3) - overset(NO_(2))overset(|)(CH)-CH_(3) overset(H_(3)O^(+))to ? |
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Answer» `CH_(3)-CH_(2) - CHO` `2CH_(3) -underset(NO_(2))underset(|)(CH) - CH_(3) + H. OHoverset(H^(+))to2CH_(3) underset(O)underset(||) (C) - CH_(3) + N_(2)O + 2H_(2) O` |
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| 25100. |
The prussian blue colour in the test of nitrogen by Lassagine's solution is due to : |
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Answer» `Na_(4)[Fe(CN)_(6)]` |
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