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28201.

The most abundant element in earth's crust is:

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HYDROGEN
oxygen
nitrogen
silicon

Answer :B
28202.

The most abundant element in the earth's atmosphere is

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`O_2`
`N_2`
`F_2`
Ar

Answer :B
28203.

The maximum number of oxidation states which nitrogen can show in its compounds is

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SOLUTION :oxidation states are POSSIBLE, i.e., -3, -2, -1, 0, +1, +2, +3, +4 and +5.
28204.

The most abundant element in the earth crust is :

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O
Si
H
C

ANSWER :A
28205.

Themaximum numberof monochloroderivativespossiblefor 2,6 -dimethylheptane is :

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4
3
5
6

Answer :A
28206.

The maximum number of molecules will be present in

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`16 G " of "NO_2` GAS
`16 g " of "O_2` gas
`7 g " of "N_2` gas
`2 g " of "H_2` gas

Answer :D
28207.

The most abundant element in earth crust is: Si,aluminium,O,Fe

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Si
aluminium
O
Fe

Answer :C
28208.

The most abundant biomol in the living w system is

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PROTEINS
Carboydrate
LIPIDS
NUCLEIC ACID

SOLUTION :Proteins
28209.

The maximum number of molecules is present in

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15 L of `H_(2)` gas at STP
5L of `N_(2)` gas at STP
0.5 g of `H_(2)` gas
10 g of `O_(2)` gas

Solution :At STP, 22.4 L of any gas `=6.02 xx 10^(23)` molecules
`therefore 15 L H_(2) = (6.02 xx 10^(23))/(22.4) xx 15 = 4.03 xx 10^(23)` molecules
`5 L N_(2) = (6.02 xx 10^(23))/22.4 xx 5 = 1.344 xx 10^(23)` molecules
2g `H_(2) = 6.02 xx 10^(23)` molecules
`therefore 0.5 g H_(2) = (6.02 xx 10^(23))/2 xx 0.5` molecules
`=1.505 xx 10^(23)` molecules
32 g of `O_(2) = 6.02 xx 10^(23)` molecules
`therefore 10 g O_(2) = (6.02 xx 10^(23))/32 xx 10` molecules
`=1.88 xx 10^(23)` molecules.
28210.

The monovalent RO group is called

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ALKYL group
alkoxy group
alkenyl group
all of these

Answer :B
28211.

The more paramagnetic in the following is

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Mn
Cr
`FE^(2+)`
`Fe^(3+)`

SOLUTION :`Fe^(2+)`
28212.

The maximum number of molecules is present in:

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15L of `H_(2)` gas at STP
5L of `N_(2)` gas at STP
0.5 g of `H_(2)` gas
10 g of `O_(2)` gas

Solution :Number of molecules in 15L `H_(2)=(15)/(22.4)XxN=0.669N`
Number of molecules in 5L `N_(2)=(5)/(22.4)xxN=0.223N`
Number of molecules in 0.5 g `H_(2)=(0.5)/(2)xxN=0.25N`
Number of molecuels in `10g O_(2)=(10)/(32)xxN=0.312N`
28213.

The more electronegative element is :

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F
Cl
I
Br

Answer :A
28214.

The more electro positive element has

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POSITIVE reduction POTENTIAL
NEGATIVE reduction potential
tendency to gain ELECTRONS
negative oxidation potential

Answer :B
28215.

The monomers of biodegradable polymer , nylon 2-nylon 6 are

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glycine + adipic ACID
glycol +PHTHALIC acid
phenol + UREA
glycine + amino caproicacid .

Solution :It is a COPOLYMER of glycine `(H_(2)N-CH_(2)-COOH)` and amino caproic acid `[H_(2)N(CH_(2))_(5)COOH]`.
28216.

The maximum number of isomers (including steroisomres) that are possible on monochlorination of the following compound. CH_(3)CH_(2)-underset(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)CH_(3), is:

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2
4
6
8

Answer :D
28217.

The more activeness of fluorine is due to

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F-F bond has less energy
`F_(2)` is GAS it normal temperature
Its electron AFFINITY is MAXIMUM
F-F bond has more energy

ANSWER :A
28218.

The monomers used in the production of nylon-6,6 are

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HEXAMETHYLENE DIAMINE and ETHYLENE GLYCOL
ADIPIC acid and ethylene glycol
adipic acid and hexamethylene diamine
dimethyl terepthalate and ethylene glycol Polymers

Answer :C
28219.

Which of the following has maximum number of molecules ?

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5 L of `N_2`GAS at STP
0.5 G of `H_2`gas
10 g of `O_2`gas
15 L of `H_2`gas at STP

Solution :15 L of `H_2`gas at STP
28220.

The monosaccharide units in oligosaccharides and polysaccharides are connected through ..........linkages.

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SOLUTION :GLYCOSIDIC
28221.

The monomers used in the production of nylon-66 are

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Hexamethyl DIAMINE and ETHYLENE glycol
ADIPIC acid and ethylene glycol
Adipic acid and hexamethylene diamine
Dimethyl terephthalate and ethylene glycol

Solution :Adipic acid `(HOOC-(CH_(2))_(4)-COOH)` and Hexamethylene diamine `(NH_(2)-(CH_(2))_(6)-NH_(2))`
28222.

The monomers used in the preparation of nylon 6, 6 are________and___________.

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SOLUTION :HEXAMETHYLENE DIAMINE, ADIPIC ACID
28223.

The maximum possible number of hydrogen bonds a water molecule can form is :

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3
4
1
2

Solution :The molecule of WATER consists of TWO hydrogen atoms bonded to oxygen atom by covalent bonds. Because of polar nature of water molecular the water MOLECULES are held TOGETHER by intermolecular hydrogen bonds . In this arrangement each oxygen is tetrahedrally surrounded by four hydrogen atom , two by covalent bonds and two hydrogen bonds.
28224.

The monomers used in preparation of dexton are

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lactic acid and glycollic acid
3-Hydroxy BUTANOIC acid and 3-Hydroxzy pentanoic acid
STYRENE and 1,3-Butadiene
hexamethylenediamine and adipic acid

Solution :`HO-overset(CH_(3))overset(|)(CH)-overset(O)overset(||)C-H+HO -CH_(2)-underset("Glycolic acid")(CH_(2)-overset(O)overset(||)C-OH) to [-O-overset(CH_(3))overset(|)(CH)-overset(O)overset(||)C-CH_(2)-overset(O)overset(||)C-]`
28225.

The maximum number of hydrogen bonds in which water molecule can participate is:

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1
2
3
4

Answer :D
28226.

The monomers used in addition polymerisation through free radical should be every pure because

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the TRACES of impurities act like inhibitors resulting in SHORT chain polymers
the impurities result in formation of DIFFERENT products
the polymer FORMED is IMPURE
catalyst does not function in presence of impurities .

Answer :A
28227.

The monomers present in glyptal are

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ETHYLENE glycol, caproic acid
vinyl chloride , terepthalic acid
ethylene, glycol , pthalic acid
UREA , formaldehyde

Answer :C
28228.

The maximum number of elements in third period is

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8
18
32
between 8 and18

Solution :Third period involves the FILLING of 3s and 3P- SUBSHELL only and 3d- subshel is FILLED after 4s- and is INCLUDED in fourth period.
28229.

The monomer for polystyrene is

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ETHANE
Ethene
Ethyne
Vinyl BENZENE

Answer :D
28230.

The maximum number of electrons theoritically possible for seventh principal shell is

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49
196
86
98

Solution :No of ELECRONS in a SHELL`=2N^(2)=2xx7^(2)=98`
28231.

The monomer used to produce orlon is

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`CH_2=CHF`
`CH_2=C CI_2`
`CH_2=CHCI`
`CH_2=CH-CN`

ANSWER :D
28232.

The maximum number of electrons in an atom with quantum number n=3, l=2 is

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2
6
10
30

Answer :D
28233.

The monomer used in the preparation of neoprene is

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NEOPENTYL CHLORIDE
NEOPENTANE
2-chlorobuta -1,3-diene
chloropicrin

ANSWER :C
28234.

The monomer units of starch are

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`ALPHA`-GLUCOSE
`BETA`-glucose
Pyranose
Galactose

Answer :A
28235.

The maximum number of electrons in a sub-shellis given by the expression:

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`4l-2`
`4l+2`
`2l+1`
`2n^(2)`

SOLUTION :In a subsshell, the number of ORBITAL aregiven as (2l+1) and therefore,number of ELECTRONS are `2(2l+1)`because each orbital hastwo electrons.
28236.

The monomer used in Novolac, a polymer used in paints

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MELAMINE and FORMALDEHYDE
Phenol and Formaldehyde
BUTADIENE and ACRYLONITRILE
Butadiene and Styrene

Answer :B
28237.

The monomers used in Novolac, a polymer used in paints,

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BUTADIENE and styrene
butadiene and acrylonitrile
PHENOL and FORMALDEHYDE
melamine and formaldehyde

Solution :MONOMERS of NOVOLAC are phenol and formaldehyde.

28238.

The maximum number of electrons in a sub shell having the same values of spin quantum umber is given by

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`L+2`
`2l+1`
`l(l+1)`
`SQRT(l(l+1))`

ANSWER :B
28239.

The monomer used in preparing nylon 6 is

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BUTADIENE + styrene
isoprene
caprolactum
chloroprene

ANSWER :C
28240.

The monomer units in strach are

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`alpha`-GLUCOSE
`beta`-glucose
PYRANOSE
GALACTOSE.

ANSWER :A
28241.

The maximum number of electrons in a sub shell having the same value of spinquantum number is given by

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`L^(2)`
`2l+1`
`4l+2`
`1//2(2l+1)^(2)`

ANSWER :B
28242.

The monomer units of silicons a water repellant,acid resistant and heat resistants polymer is:

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SI
`SiO_2`
`R_2SiO`
NONE of these

Answer :C
28243.

The monomer units of silicone, a water repellant, acid resistant and heat resistant polymer is:

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`Si`
`SiO_2`
`R_2Si(OH)_2`
None of these

Answer :C
28244.

The monomer units of PTFE are:

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`Cl_2CH-CH_3`
`F_2C=CF_2`
`F_3C-CF_3`
`FClC=CF_2`

ANSWER :B
28245.

The maximum number of electrons in a sub-shell for which l=3, is

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4
6
8
14

Answer :D
28246.

The monomer unit of starch are

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`ALPHA`-GLUCOSE
`BETA`-glucose
pyranose
galactose

Answer :A
28247.

The monomer unit of polyvinyl chloride has theformula

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`CH_3 - CH_2Cl`
`CH_2= CH_2`
`CHCL = CHCl`
`CH_2= CHCl`

SOLUTION :`CH_2=CHCl`
28248.

The maximum number of covalent bonds formed by nitrogen is 4.

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Solution :Nitrogen has three UNPAIRED ELECTRONS and one lone pair of electrons in the valence SHELL. Therefore, nitrogen can form three normal covalent bonds and one coordinate bond.
28249.

The monomer that undergo radicalpolymerisation most easily is :

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`CH_(2)=CH_(2)`
`C_(6)H_(5)CH=CH_(2)`

`CH_(3)-CH=CH_(2)`

Solution :N//A
28250.

The maximum number of atoms that may lie in the same plane in (CH_(3))_(2)C=SF_(2)(CH_(3))(2) is ……

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SOLUTION :FACT