Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

28301.

The molecules which diffuse through a cell membrane are of

Answer»

FRUCTOSE
Glycogen
Haemoglobin
CATALASE

SOLUTION :It is a FACT.
Discussion
28302.

The molecules that will have dipole moment are

Answer»

2,2-dimethylpropane
trans-2-pentene
cis-3-hexene
2,2,3,3,-tetramethylbutane

Solution :2,2-dimethylpropane and 2,2,3,3- tetramethyl- butane are symmetrical MOLECULES so their net dipole MOMENT is ZERO. B and C have RESULTANT dipole moment.
Discussion
28303.

The mathematocal expression of Faraday's second law is …………….. .

Answer»

`m = ZIT`
`(m_1)/(E_1) = (m_2)/(E_2) = (m_3)/(E_3)`
`(m_1)/(Z_1) = (m_2)/(Z_2) = (m_3)/(Z_3)`
`Z = m/(It)`

ANSWER :C
Discussion
28304.

The molecules of which of the following gas have highest speed?

Answer»

Nitrogen at `1000^(@)`C
Methane at 298 K
Oxygen at `0^(@)C`
HYDROGEN at `-50^(@)C`

Answer :D
Discussion
28305.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. The rate constant of a reaction increases by

Answer»

CARRYING out the reaction for a LONGER period.
increasing the temperature
increasing the concentration of reactants.
None of these.

Solution :B) logk `= log A - E/(2.303)1/T`
The value of k INCREASES by increasing the temperature.
Discussion
28306.

The molecules of aluminium chloride in vapour state :

Answer»

Have no shape
Are SHAPED LIKE a PLANE triangle
Are round
Are like randomly BROKEN bricks

Answer :B
Discussion
28307.

The mathematical form of the first law of thermodynamics when heat(q) is supplied and W is work done by the system(+ve) is:

Answer»

`triangleU=q+W`
`triangleU=q-W`
`triangleU=-q+W`
`triangleU=-q-W`

ANSWER :B
Discussion
28308.

The molecules of a gas A travel four times faster than the molecules of gas B at the same temperature. The ratio of molecular weights(M_A/M_B) will be :

Answer»

1/16
4
1/6
16

Answer :A
Discussion
28309.

The molecules : CH_(3)-underset(O)underset(||)(C)-CH_(2)-underset(O)underset(||)(C)-O-C_(2)H_(5) and CH_(3)-underset(OH)underset(|)(C)=CH-underset(O)underset(||)(C)-O-C_(2)H_(5) are :

Answer»

GEOMETRICAL ISOMERS
TAUTOMERS
DIASTEREOMERS
metamers

Answer :B
Discussion
28310.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. The rate constant is numerically the same for three reactions of first, second and third order respectively. Which one is true for rates of three reactions if concentrations of the reactant is 1M?

Answer»

`r_(1) = r_(2)=r_(3)`
`r_(1) gt r_(2) lt r_(3)`
`r_(1) lt r_(2) lt r_(3)`
All the above.

Solution :c) `r_(1) = K[A]`
`r_(2)=k[A]^(2)`
`r_(3) = k[A]^(3)`
For the same concentration of [A]=1
Discussion
28311.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. For a reaction N_(2)O_(5) to 2NO_(2) + 1/2O_(2) Given: (-d[N_(2)O_(5)])/(dt) = k_(1)[N_(2)O_(5)] (d[NO_(2)])/(dt) = k_(2)[N_(2)O_(5)] (d[O_(2)])/(dt) = k_(3)[N_(2)O_(5)] the relation between k_(1), k_(2) and k_(3) is:

Answer»

`2k_(1)=k_(2)=4k_(3)`
`k_(1)=k_(2)=k_(3)`
`2k_(1)=4k_(2)=k_(3)`
None of these.

Solution :a) `(-d[N_(2)O_(5)])/(dt) = 1/2d([NO_(2)])/(dt) = (2d[O_(2)])/(dt)`
`k_(1)[N_(2)O_(5)]= k_(2)/k_(1) [N_(2)O_(5)] = 2k_(3)[N_(2)O_(5)]`
or `2k_(1) = k_(2)=4k_(3)`
Discussion
28312.

The molecules BF_(3)&NF_(3) both are covalent. But BF_(3) is non-polar & NF_(3) is polar. The reason is that:-

Answer»

Boron is a metal and nitrogen is a GAS
`BF_(3)` is PLANAR & `NF_(3)` is pyramidal
`DeltaEN` for N-F bond is zero but for B-F bond is non zero
All of the above

Answer :B
Discussion
28313.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. The rate of a gaseous reaction is given by the expression : k[A][B]. If the volume of the reaction mixture is suddenly reduced to 1//4th of its initial volume, the reaction rate relating to original rate will be:

Answer»

`1//10`
`1//8`
8
16

Solution :d) When the VOLUME is REDUCED to `1//4`TH, concentration becomes four TIMES. As the reaction is of second order, rate becomes 16 times.
Discussion
28314.

The molecule XeF_6 has the following structure :

Answer»

SQUARE pyramidal
Pyramidal
DISTORTED OCTAHEDRAL
Square PLANAR

SOLUTION :distorted octahedral
Discussion
28315.

The molecule with zero dipolemoment is:

Answer»

`SO_2`
`CIO_2`
`NO_2`
`HgCI_2`

ANSWER :D
Discussion
28316.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. The concentration of a reactant in a solution falls from 0.2 M to 0.1 M in 2 hours and to 0.05 M inhorus. The order of the reaction is:

Answer»

zero
two
one
HALF.

Solution :c) SINCE half-life PERIOD `(t_(1//2))` REMAINS constant, order of reaction=1.
Discussion
28317.

The moleculewith the phosphategroup is called a ………. .

Answer»

SOLUTION :NUCLEOSIDE
Discussion
28318.

The mathematical expression which describes the reaction rate in terms of molar concentrations of the reactants as determined experimentally is called rate law. The sum of the coefficients of the reacting species that are involved in the rate equation of a particular reaction is known as the order of the reaction, The reactions may be classified as first, second and third order reactions depending upon the number of of reacting species involved in the rate equation. It can be fractional in complex reations and even zero in certain reactions such as photochemicla reactions. The units of the rate constant(k) can help ini predicting the nature of a particular reaction. 1) A substance decomposes in a solution followig first order kinetics. Flask A contains 1L of 1M solution and flask B has 100 mL of 0.6 M solutions. After 8 hours, the concentrations of substance in flask A becomes 0.25 M. What will be the time taken for the concentration of the same substances in flask B to becomes 0.3 M?

Answer»

`0.4` hr
`2.4`hr
`4.0` hr
unpredictable as RATE constant is not given.

Solution :c) In flask A:
`k=(2.303)/8 log 1.0/(0.25) =2.303/4 LOG2`
In flask B:
`t=2.303/k log 0.6/0.3 = (2.303 xx 4)/(2.303) = 4`
Log 2 cancels out
Discussion
28319.

The molecule with maximum boiling point is

Answer»

`CH_(3) - CHOH - CH_(3)`
`CH_(3)CH_(2)CH_(2)CH_(2)CI`
`CH_(3)-CHOH-CH_(2)CH_(2)OH`
`CH_(3)- CHCl-CH_(3)`

Solution :`CH_(3)CHOHCH_(2)CH_(2)OH` has two OH groups and HENCE it undergoes MAXIMUM H-bonding.
Discussion
28320.

The mathematical expression for the standard enthalpy of sublimation is given by _________ . (Here,Delta_("sub")H^@=Delta_("sublimation")H^@, Delta_("fus")H^@=Delta_(fusion)H^@,Delta_(vap)H^@=Delta_("vaporization")H^@,=Delta_(comb)H^@=Delta_(combustion)H^@,Delta_(diss)H^@=Delta_(dissociation)H^@)

Answer»

`Delta_("sub")H^@=Delta_(FUS)H^@-Delta_(VAP)2H^@`
`Delta_("sub")H^@=Delta_(fus)H^@-Delta_(vap)H^@`
`Delta_("sub")H^@=Delta_(fus)H^@+Delta_(vap)H^@`
`Delta_("sub")H^@=Delta_(COMB)H^@-Delta_(diss)2H^@`

Answer :C
Discussion
28321.

The materials required for photosynthesis are

Answer»

`CO_(2) and H_(2)O`
CHLOROPHYLL only
`CO_(2), H_(2)O` and SUNLIGHT
`CO_(2), H_(2)O`, sunlight and chlorophyll

Answer :D
Discussion
28322.

The molecule which has zero dipole moment is :

Answer»

`CH_2CI_2`
`BF_3`
`NF_3`
`CL O_2^-`

ANSWER :B
Discussion
28323.

The material used for the manufacturer of ammonia by cyanamide process is

Answer»

COAL
LIME
NITROGEN
All

Answer :D
Discussion
28324.

The molecule which has/have a fluorite structure

Answer»

`LiO_(2)`
`CaF_(2)`
`PbO_(2)`
`K_(2)O`

ANSWER :B::C
Discussion
28325.

The molecule which has pyramidal shape is :

Answer»

`NF_3`
`CO_2`
`CO_3^(2-)`
`NO_3^(-)`

ANSWER :A
Discussion
28326.

The material used for the lining of Bessemer' s converter in the extraction of copper is:

Answer»

Silica
Lime
Iron
Cu

Answer :B
Discussion
28327.

The moleculewhichhasdipolemoments is :

Answer»

2,2- DIMETHYLPROPANE
trans -2- PENTANE
trans -3- hexane
2,2,3,3- Tetramethybutane .

Answer :B
Discussion
28328.

The molecule which contain sigma bonds, pi bonds and lone pairs in 1 : 1 : 1 ratio :-

Answer»

`C_(2)N_(2)`(Cyanogen)
`C_(6)H_(6)`(Benzene)
`C(CN)_(4)` (Tetracyano methane)
`C_(3)O_(2)` (Carbon SUBOXIDE)

Solution :
Discussion
28329.

The material used for the lining of Bessemer's converter in the extraction of copper is:

Answer»

Silica
Lime
Iron
Cu

Answer :B
Discussion
28330.

The molecule , which are electron deficient having tendency to form back bonding, in which transfer of lone pair of electron from filled orbital of an atom to the vacant orbital of the adjacent atom. While some electron deficient species which are not capable to form back bonding, then driving forces occurs for dimerisation/polymerisation to achieve octet temporily or permanently by the monomeric species. Whichof the following matchingis INCORRECT between molecule and the orbitals of atoms involved in bridge bond.

Answer»

`B_(2)H_(6) (VAP.) tosp^(3) -s -SP^(3)`
`Al_(2)(CH_(3))_(6) (vap)to sp^(3) -sp^(3) -sp^(3)`
`BeH_(2)(s) to sp^(3)-s-sp^(3)`
`Be_(2)H_(4) (vap) to sp^(3) -s-sp^(3)`

ANSWER :A
Discussion
28331.

The material used as coating material for non-stick pans is :

Answer»

polystyrene
terylene
TEFLON
PVC

SOLUTION :teflon
Discussion
28332.

The molecule , which are electron deficient having tendency to form back bonding, in which transfer of lone pair of electron from filled orbital of an atom to the vacant orbital of the adjacent atom. While some electron deficient species which are not capable to form back bonding, then driving forces occurs for dimerisation/polymerisation to achieve octet temporily or permanently by the monomeric species. which of the following species is most acidic and have NO back bonding ?

Answer»

`BF_(3)`
`BI_(3)`
`N(SiH_(3))_(3)`
`O(SiH_(3))_(2)`

Answer :A
Discussion
28333.

The material mixed before ore is subjected for smelting in the extraction of iron are :

Answer»

COKE and silica
coke and LIMESTONE
limestone and silica
coke, limestone and silica

Answer :B
Discussion
28334.

The molecule , which are electron deficient having tendency to form back bonding, in which transfer of lone pair of electron from filled orbital of an atom to the vacant orbital of the adjacent atom. While some electron deficient species which are not capable to form back bonding, then driving forces occurs for dimerisation/polymerisation to achieve octet temporily or permanently by the monomeric species. Which of the following readily gets combined with lewis base (NH_(3),CH_(3)NH_(2),C_(5)H_(5)N "etc")

Answer»

`C_(2)H_(6)`
`I_(2)Cl_(6)`
`B_(2)H_(6)`
`(BeCl_(2))_(N)`

Answer :A
Discussion
28335.

The masses of equal volumes of a gas and hydrogen are 25.6 g and 0.8g respectively under same conditions of temperature and pressure. Find the molecular mass of the gas.

Answer»

SOLUTION :V.D. of the GAS `(25.6)/(0.8)=32.0`
MOLECULAR MASS `=2V.D.=2xx32.0=64.0`
Discussion
28336.

The molecule which behaves as electrophile and nucleophile is

Answer»

`CH_(3)OOH`
`CH_(3)CL`
`CH_(3)CN`
`CH_(3)NH_(2)`

Answer :C
Discussion
28337.

The molecule of which gas has highest speed?

Answer»

`H_(2)" at "-73^(@)C`
`CH_(4)" at "300 K`
`N_(2)" at "1027^(@)C`
He at `127^(@)C`

Answer :A::D
Discussion
28338.

The matel obtained by self reduction process is:

Answer»

Cu
Hg
Pb
All

Answer :D
Discussion
28339.

The molecule /species having one unpaired electron is

Answer»

O
CO
`CN^(-)`
`O_(2)`

Solution :Only NO has ODD number of electrons `=7+8`
`=15`
Discussion
28340.

The molecule of PCl_(5) in the solid state is ............in nature consisting of tetrahedral ..............cation and octahedral.............anion.

Answer»

SOLUTION :IONIC, `PCl_(4)^(+), PCl_(6)^(-)`
Discussion
28341.

The masses of carbon, hydrogen and oxygen in an organic compound are in the ratio 6:1:8 respectively. Which of the following pairs of formula corrspond to above information.

Answer»

`CH_(2)O and CH_(3)CHO`
`CH_(2)O and C_(3)H_(6)O`
`C_(3)H_(6)O and C_(2)H_(6)O_(2)`
`C_(3)H_(6)O_(3)and HCHO`.

SOLUTION :
(The COMPOUND that gives `CH_(3)CHO`).
Discussion
28342.

The molecule of SO_(2) is

Answer»

PLANAR
PYRAMIDAL
Angular
None of these

SOLUTION : - `sp^(3)` hybridisation
Discussion
28343.

The masses of carbon, hydrogen and oxygen in an organic compound are in the ratio 6 : 1 : 8 respectively. Which of the following pairs of formulae correspond to above information?

Answer»

`CH_(2)O` and `CH_(3)CHO`
`CH_(2)O` and `C_(3)H_(6)O`
`C_(2)H_(6)O` and `C_(2)H_(6)O_(2)`
`C_(3)H_(6)O_(3)` and HCHO

Solution :In `C_(3)H_(6)O_(3)`, MASS of 3 `"C-atom"=12 xx 3 = 36`
`"mass of 6-H-atoms"= 1 xx 6=6`
`"mass of 3 O-atom"=16 xx 3 = 48`
`:.` RATIO of masses of C : H : O is 36 : 6 : 48 or 6 :1 : 8.
In HCHO, mass of 1C-atom = 12
mass of 2 H-atoms=2
mass of 1 O-atom=16
`:.` Ratio of masses of C : H : O is 12 : 2 : 16 or 6 : 1 : 8
Discussion
28344.

The molecule/molecules that has/have delocalised lone pair(s) of clectrons is/are

Answer»

I,II and III
I, II and IV
I and III
only III

Solution :In COMPOUND (III) , the lone pair of oxygen gets delocalised on the `PI` -BOND located on the next carbon atom.
Discussion
28345.

The mass ratio of Fe_(2)O and Al in thermite is

Answer»

`1:3`
`1:2`
`3:1`
`2:1`

ANSWER :3
Discussion
28346.

The mass of the substance deposited when one faraday of charge is passed through its solution is equal to____of the substance.

Answer»

SOLUTION :GRAM EQUIVALENT WEIGHT.
Discussion
28347.

The molecule not having pi - bond is

Answer»

1. `Cl_(2)`
2. `O_(2)`
3. `N_(2)`
4. `CO_(2)`

ANSWER :A
Discussion
28348.

The mass of the substance deposited when one coulomb of electricity is passed through its solution is called____of the substance.

Answer»

SOLUTION :ELECTROCHEMICAL EQUIVALENT.
Discussion
28349.

The molecule ML_(x) is planar with 6 electron pairs around M in the valence shell. The value of x is :

Answer»


ANSWER :4
Discussion
28350.

The molecule in which there is no lone pair on xenon atom is

Answer»

`XeF_6`
`XeF_2`
`XeO_4`
`XeF_4`

ANSWER :C
Discussion