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28251.

The monomer unit of orlon is ………….

Answer»

Acrolene
CHLOROPRENE
ACRYLONITRILE
Isoprene

Solution :Acrylonitrile
28252.

The maximum number of bond and pi bond can be formed between two atoms are respectively.

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4,3
3,2
2,3
3,1

Answer :A
28253.

The maximum number of positionalisomers for an alkene with molecular formula C_4H_8 is:

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2
3
4
5

Answer :C
28254.

The maximum number of 90^(@) angles between bond pair - bond pair of electrons is observed in

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1. `dsp^(2)` HYBRIDIZATION
2. `SP^(3)d` hybridization
3. `dsp^(3)`hybridization
4. `sp^(3)d^(2)` hybridization

Answer :D
28255.

The maximum no of atoms in a plane for the compound formed by reaction of SbF_(5) with SO_(2) is :

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8
6
7
9

Solution :`SbF_(5) + SO_(2) RARR F_(5)Sblarr SO_(2)`
28256.

The monomer of the polymer : ~CH_2-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_2-underset(CH_3)underset(|)overset(CH_3)overset(|)C~ is

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`CH_3CH=CHCH_3`
`CH_3-CH=CH_2`
`(CH_3)_2C=C(CH_3)_2`

ANSWER :A
28257.

The maximum number of 3d-electrons having spin quantum number s=+1//2 is

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10
5
2
1

Answer :A
28258.

The monomer of the polymer [-CH_(2)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")"C "-CH_(2)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")"C "-CH_(2)-]_(n)

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`H_(2)C = C(CH_(3)) _(2)`
`(CH_(3)) _(2)C = C(CH, _(3)), _(2)`
`CH_(3)CH = CH.CH_(3)`
`CH_(3)CH = CH_(2)`

Answer :A
28259.

The maximum negative electron gain enthalpy of halogens in their respective periods is because of

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SMALL SIZE in their RESPECTIVE period
HIGH electro negativity in their respective periods
All the above

Solution :Conceptual
28260.

The monomerof the polymerwhich is used as a substitute for wool is

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styrene
tetrafluoroethene
CHLOROETHENE
prop-2-enenitrile

SOLUTION :`CH_2=CH-CN`
28261.

The maximum melting point at about the middle of transition metal series indicates that .......... configuration is favourable for strong .... ...... attraction.

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SOLUTION :`d^(5)` INTER ATOMIC
28262.

The monomer required for the preparation of buna-N is

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`CH_2=CH-CH_2-CH_3 and CH_2=CH-CN`
`CH_2=CH=CH=CH_2 and CH_2=CH-CN`
`CH_2=C=CH-CH_3 and CH_2=CH-CN`
`CH_2=CH-CH=CH_2 and CH_3-CH_2-CN`

ANSWER :B
28263.

The maximum magnetic moment is shown by the ion with the outer electronic configuration of :

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`3d^(6)`
`3d^(9)`
`3d^(5)`
`3d^(4)`

Answer :C
28264.

The monomer of terylene are .............and ...................

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ANSWER :tetrephthalic ACID or its methyl ESTER , ethylene glycol
28265.

The monomer of PVC is

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ethylene
CHLOROETHENE
VINYL cyanide
none of these

Solution :chloroethene
28266.

The maximum efficiency of a heat engine operating between 100^(@)C and 25^(@)C is

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0.2011
0.222
0.2517
None

Answer :A
28267.

The maximum efficiency of a steam engine operating between 100^(@)C and 25^(@)C is

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`20%`
`22.2%`
`25%`
`30%`

ANSWER :A
28268.

The monomer of Teflon polymer is difluoroethene.true or false?

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SOLUTION :tetrafluorothene
28269.

The maximum ease of abstraction of a hydrogen atom by a chlorine atom is shown by

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`(CH_(3))_(3)C - CH_(3)`
`(CH_(3))_(3) CH`
`(C_(6) H_(5))_(3) CH`
`(CH_(3))_(2) CH_2`

Solution :The more stable the RADICAL the more EASILY it is formed . Now the ORDER of stability of free radicals decreases in the order :
`(C_6 H_5)_3 overset(*)(C) gt (CH_3)_(3) overset(*)(C) gt (CH_3)_3 overset(*)(C)CH_2 gt (CH_(3) )_(2) overset(*)(C)H`, therefore , H-atom is most easily abstracted from `(C_6 H_5)_3 overset(*)(C)`.
28270.

Give the structure of the monomer of PVC.

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ethylene
CHLOROETHENE
VINYL cyanide
none of these

Solution :chloroethene
28271.

The maximum displacement perpendicular to the motion of the wave is known as

Answer»

WAVELENGTH
intensity
AMPLITUDE
FREQUENCY

ANSWER :C
28272.

White the names and structures of the monomers of the following polymers : (i) Polystyrene, (ii) Dacron, (iii) Teflon,

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`C_2H_5-CH=CH_2`
`CH_2=CHCl`
`C_6H_5-CH=CH_2`
`CH_2=CHCHO`

ANSWER :A
28273.

The maximum densityof water is reached at a temperature

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273 K
277 K
373 K
none of above

Answer :B
28274.

The monomer of poly acrylonitrile is

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VINYL CHLORIDE 
Vinyl ALCOHOL 
Vinyl cyanide 
Adipic acid

Answer :C
28275.

The maximum covalency for representative elements is equal to (excluding 1st and 2nd period)

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the NUMBER of UNPAIRED p-electrons
the number of PAIRED d-electrons
the number of unpaired s and p-electrons
the ACTUAL number of s and p-electrons in the OUTERMOST shell

Answer :D
28276.

The monomer of PMMA is :

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`CH_2=UNDERSET(CH_3)underset(|)C-COOCH_3`
`CH_2=CHCN`
`CH_2=underset(C_2H_5)underset(|)C-COOCH_3`
`CH_2=CHCl`.

ANSWER :A
28277.

The maximum covalency of boron in sodium borofuoride is :

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4
6
2
8

Solution :`NA[BF_(4)]`. MAXIMUM covalency of BORON is 4.
28278.

The monomer of PAN is ...............

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ANSWER :ACRYLONITRILE
28279.

The maximum covalency of nitrogen is

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2
3
4
5

Answer :3
28280.

The monomer of natural rubber is ..................

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SOLUTION :cis-isoprene( OR ) 2-methyl BUTA -1,3-diene )
28281.

The maximum catenation tendency of carbon is due to :

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1.Its tetravalency
2.Larger strength of carbon to carbon BOND as compared to that of other atoms
3.Its electronegativity value close to other atoms (H, N, O, S) with which it forms BONDS
4.Its tendency to form MULTIPLE bonds.

Solution :The larger catenation tendency of carbon is because of greater strength of `C-C` bond as compared to that other atoms.
28282.

The monomer of Nylon-6 is/are

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`F_2C=CF_2`
`H_(2)C=CH_(2)`

SOLUTION :The MONOMER USED in the preparation of Nylon-6 is caprolactum.
28283.

The maximum amount of BaSO_(4) precipitated on mixing BaCl_(2)(0.5M) with H_(2)SO_(4)(1M) will correspond to

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0.5 M
1.0 M
1.5 M
2.0 M

Answer :A
28284.

The monomer of following polymer is [-O-underset(CH_3)underset(|)CH-CH_2-COO-underset(C_2H_5)underset(|)CH-CH_2-CO-]_n

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`HO-CH_2-CH_2-COOH`
`HO-UNDERSET(CH_3)underset(|)CH-CH_2-COOH`
`HO-underset(C_2H_5)underset(|)CH-CH_2-COOH`
both B and C

ANSWER :D
28285.

The maximum amount of BaSO_(4) that can be obtained on mixing 0.5 mole BaCl_(2) with 1 mole H_(2)SO_(4) is:

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0.5mol
0.1mol
0.15mol
0.2mol

Solution :`H_(2)SO_(4)+BaCl_(2)rarrBaSO_(4)+2HCI`
0.5 MOLE `BaCl_(2)` will react with 0.5 mole `H_(2)SO_(4)` to GIVE 0.5 mole `BaSO_(4)`.
28286.

The maximum and minimum melting points of first and second transition series respectively are observed with

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`Cr and Zn`
`Cr and HG`
`Cr and Cd`
`MO and Cd`

ANSWER :C
28287.

The monomer of Buna-S are :

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`CH_(3)-UNDERSET(CH_(3))underset(|)(CH)-CH=CH_(2)+CH_(2)=CH-CN`

Answer :C
28288.

The maximum amount of BaSO_4precipitatedon mixing BaCl_2(aq. 0.5M) and H_2SO_4 (aq. 1M) will correspond to:

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1.0M
0.5 M
0.25 M
1.5 M

Solution :`BaCl_2 + H_2SO_4 to BaSO_4 + 2HCL`
1 MOL of `BaCl_2` GIVES = 1 mol of `BaSO_4`
0.5 mol of `BaCl_2` gives = 0.5 mol of `BaSO_4`
28289.

The monomer of buna- S rubber are

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VINYL CHLORIDE and sulphur
butadine
styrene and butadine
isoperene and butadiene

Answer :C
28290.

The maximum amount ofBaSO_4 precipitated on mixing 20 ml of 0.5 M BaCl_2 with 20 ml of 1 M H_2SO_4 is :

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0.25 mole
0.5 mole
1 mole
0.01 mole

Answer :D
28291.

The maximum allowable level of Nitrates in drinking water as set by U.S. is 45 mg NO_(3)^(-) ions per dm^(3) , the level in ppm is

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15
30
45
60

Answer :C
28292.

The monomer of acrilon is

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VINYL CYANIDE
vinyl chloride
vinyl bromide
vinyl alcohol

Solution :vinyl cyanide
28293.

The matte obtained in the callurgy of copper has the approximate Composition

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`FES +CUO`
`Cu_2 S + FEO`
`Cu_2 S + FeS`
`CUS +FeS_2`

ANSWER :C
28294.

The matter has highest entropy in:

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SOLID state
Liquid state
Gaseous state
Equal in all

Answer :C
28295.

The momentum of a particle having ade-Broglie wavelenth of 10^(-17)m is (h=6.625xx10^(-34)Js)

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`6.625xx10^(-17)kgms^(-1)`
`3.3125xx10^(-7)kgms^(-1)`
`13.25xx10^(-17)kgm^(-1)`
`26.5xx10^(-7)kgms^(-1)`

SOLUTION :`LAMDA=h/p` or `p=h/(lamda)=(6.625xx10^(-34))/(10^(-17))`
`=6.625xx10^(-17)kgms^(-1)`
28296.

The molerity and molality of an aqueous solution of H_(2)SO_(4) "as" M_(1) and M_(2) respectively. If the molecular mass of H_(2)SO_(4) is M, density of the solution is

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`M_(2)(M_(1)+(M)/(1000))g//ml`
`M_(2)((1)/(M_(1))+(M)/(1000))g//ml`
`M_(2)((1)/(M_(2))+(M)/(1000))g//ml`
`M_(2)(M_(2)+(M)/(1000))g//ml`

ANSWER :C
28297.

The matte obtained in the extraction of copper contains:

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`FeSiO_2`
`SiO_2 + FES`
`FeS + Cu_2S`
`CUS + SiO_2 + FEO`

ANSWER :C
28298.

The matte is impure substance otained during extraction of:

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Cu
Fe
Pb
Al

Answer :A
28299.

The molten matte obtained from the blast furnace during smelting of copper contains approximately:

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`90% Cu`
`45% Cu`
`29% Cu`
`80% Cu`

ANSWER :B
28300.

Which is used for the extraction of cadmium from cadmium sulphate ?

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Roasting
Reduction
Oxidation
Electrolysis

Answer :A