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2851.

The standard reduction potential E^(@) for the half reactions are as Zn=Zn^(2+)+2e^(-),E^(@)=+0.76V Fe=Fe^(2+)+2e^(-),E^(@)=+0.41V The EMF for cell reaction Fe^(2+)+ZntoZn^(2+)+Fe is

Answer»

`-0.35V`
`+0.35V`
`+1.17V`
`-1.17V`

SOLUTION :In this reaction.
EMF=`E_("cathode")-E_("anode")=-0.41-(-0.76)" EMF"=+0.35V`.
Discussion
2852.

What mass of .^(226)Ra, whose t_(1//2)=1620 years will give the activity of 1 millicuries ?

Answer»

Solution :Activity `=(0.693)/(t_(1//2))XX(W)/(At.wt.)xx6.023xx10^(23)`
`implies3.7xx10^(7)=(0.693)/(1620xx365xx24xx3600)xx(W)/(256)xx6.023xx10^(23)`
`:.W=10^(-3)g`.
Discussion
2853.

What is the common oxidationstate of Cu, Ag and Au ?

Answer»

Solution :All these three METALS SHOW a COMMON OXIDATION state of `+1`
Discussion
2854.

Which of the following reactions occurs during smelting in the reduction zone (in iron metallurgy)?

Answer»

`CaO+SiO_(2) RARR CaSiO_(3) `(slag)
`Fe_(2)O_(3)+3C rarrn 2Fe +CO`
`Fe_(2)O_(3)rarr Fe + CO`
`CO_(2)+C rarr 2CO`

Answer :B
Discussion
2855.

The valency of carbon in four. On what principle it can be explained in a better way

Answer»

RESONANCE
HYBRIDIZATION
Electron transfer
None of the above

Solution :CARBON has only TWO unpaired electrons by its configuration but hybridization is a concept by which we can explain its valency 4.
Discussion
2856.

The solvent which can dissolve all the carboxylic acids is :

Answer»

WATER
DILUTE HCl
Conc.`H_2SO_4`
Dilute NaOH

Answer :D
Discussion
2857.

To obtain 5.85 gm nickel how long 10 ampere current should be passed through dilute solution of NiSO_(4) during electrolysis by inert electrodes ? (atomic weight of Ni=58.5 gm)

Answer»

965 second
3860 second
1930 second
9650 second

Solution :`5.85gm` nickel `=(5.85gm)/(58.5" gm mole"^(-1))`
=0.1 mole Ni is obtained
Reaction : `Ni_((aq))^(2+)+2e^(-) to Ni_((S))`
2 mole `e^(-) to 1` mole Ni
`therefore 2F to 1` mole Ni
So, if 0.1 MOL Ni is obtained then,
`=(0.1" mole "Nixx2F)/(1" mole "Ni)`
=0.2 F electricity
=0.2`xx96500` coulomb
Time=`("coulomb")/("AMPERE")=(0.2xx96500)/(10)`
=1930 second.
Discussion
2858.

van't Hoff factor of an electrolyte A_(2)B_(2) assuming that it ionizes 75% in the solution is

Answer»

SOLUTION :`{:(,A_(2)B_(3),hArr,2A^(3+),+,3B^(2-)),("Initial","1 mole",,0,,0),("After IONIZATION",1-0.75,,1.5,,"2.25 MOLES"),(,= 0.25,,,,):}`
`"Total moles after dissociation "=0.25+1.5+2.25`
= 4
`therefore I = 4`
Discussion
2859.

What is the ratio of bond pair and line pair ine Nitrate ion:

Answer»

`2:1`
`1:3`
`2:3`
`1:2`

SOLUTION :
Discussion
2860.

Which of the following molecules does not have co-ordinate bond?

Answer»

`PH_(4)^(+)`
`NO_(2)`
`O_(3)`
`CO_(3)^(2-)`

Answer :D
Discussion
2861.

Which of the following can work as oxidising agent ?

Answer»


SOLUTION :In `H_(2)S`SULPHUR is in lowest oxidation STATE
Discussion
2862.

Which of the following will have the highest coagulating power for Fe(OH)_(3) colloid?

Answer»

`PO_(4)^(3-)`
`SO_(4)^(2-)`
`Ca^(2+)`
`AL^(3+)`

Solution :`FE(OH)_(3)` is a positive sol.
Hence, greater the charge on Anion, more is the COAGULATION power.
Discussion
2863.

Which of the following compounds of elements in group IV would you expect to be most ionic in character

Answer»

`C Cl_(4)`
`SiCl_(4)`
`PbCl_(2)`
`PbCl_(4)`

SOLUTION :`PbCl_(2)` is most ionic because on going down the group the metallic character increases and also the inert pair effect PREDOMINATES.
Discussion
2864.

Vulcanization makes rubber ……………………….

Answer»

more elastic
SOLUBLE in INORGANIC solvent
crystalline
more stiff

Solution :In valcanized rubber, the polymer chains are held TOGETHER by sulphur cross-linkages `(-S-S-)`. These cross LINKS make rubber more hard, elastic and STRONGER.
Discussion
2865.

Which one help in the absorption and transport of fat soluble vitamins?

Answer»

LIPIDS
PROTEIN
ENZYME
WATER

ANSWER :A
Discussion
2866.

Which of the following show enantiomerism?

Answer»

1,2-Propadiene
2,3-Pentadiene
SEC-BUTYL alcohol
All the THREE

Solution :(B,c) : The mirror IMAGE of 1,2-propadiene is superimposable while those of 2,3-pentadiene and sec- butyl alcohol are non-superimposable.
Discussion
2867.

what are X and Y

Answer»




SOLUTION :
Discussion
2868.

Which method is based on distribution law ?

Answer»

MOND's process
Parke's process
Cupellation process
Poling process

Answer :B
Discussion
2869.

Which 0.01 mole of a cobalt complex is treated with excess silver nitralte solution4.305 g silver chloride is precipitated. The formula of the complex is

Answer»

`[Co(NH_(3))_(3)Cl_(3)]`
`[Co(NH_(3))_(5)Cl]Cl_(2)`
`[Co(NH_(3))_(6)]Cl_(3)`
`[Co(NH_(3))_(4)Cl_(2)]No_(3)`

Solution :`4.305` g AgCl = `4.305/143.5` MOLE= `0.03` mole
As `0.01` mole of the complex GIVES `0.03` mole of AgCl, this shows that there are 3 ionisable Cl.
`:.` the formula is `[Co(Nh_(3))_(6)]Cl_(3)` .
Discussion
2870.

The weight of sodium bromate required to prepareofsolution for cell reaction,

Answer»

1.56gm
1.45gm
1.23gm
1.32gm

Solution :Meg .pf `NaBrO_(3)=85.5xxo.672=57.456`
LET WEIGHT of `NaBrO_(3)`=W
`therefore W/(M_(NaBrO_(3)))xx6xx1000=57.456("equivalent weight"=M//6`)of n-factor=6
Hence ,(B)is the correct anwer.
Discussion
2871.

Which of the following elements can form only monoxide and not peroxide and superoxide ?

Answer»

Li
Na
K
all the three

Answer :A
Discussion
2872.

X and Y are anhydrides of sulphurous and sulphuric acid respectively. The hybridisation state and the shape of X and Y are

Answer»

`{:(X, Y),(sp^(2)",angular",sp^(2)", tetrahedral"):}`
`{:(X, Y),(sp^(2)", angular",sp^(2)", angular"):}`
`{:(X, Y),(sp^(2)", angular", sp^(2)", planar triangular"):}`
`{:(X, Y),(sp^(3)"planar",sp^(3)", planar"):}`

ANSWER :C
Discussion
2873.

What do you call the proteins which are crucial to communication system in the body ?

Answer»

SOLUTION :RECEPTOR
Discussion
2874.

Which would be decrease the pH of 25 cm^(3) of a 0.01 M solution of hydrochloric acid

Answer»

The ADDITION of `25cm^(3)` 0.005 M hydrochloric acid
The addition of `25cm^(3)` of 0.02 M hydrochloric acid
The addition of MAGNESIUM metal
None of these

Solution :Given concentration of HCL = 0.01 M
`pH = -log 10^(-2) = 2`
In option (b)
Concentration of HCl = 0.02 M
M.eq `= 0.02 xx 25 = .5 M`. Eq of HCl
M.eq in given condition `= 0.01 xx 25 = 0.25`
Total M.eq in solution `= 0.25 + 0.50 = 0.75 = (.75)/(25+25) = 1.5 xx 10^(-2)N`
Then new pH will be
`= -log 1.5 xx 10^(-2) = 2 - log 1.5`
Which is less than 2 ltbr. So we canvery that that by adding `25cm^(3)` of 0.2 M HCl the pH of `25 cm^(3)` of 0.01 M decrease.
Discussion
2875.

What are the applicationsof the following : (a) Liquation process , (b) Zone refining ?

Answer»

SOLUTION :(a) Liquation method is used for refining the METALS havinglow MELTING point.
(b) ZONE reducing method is used for producinghighly pure metals or sermiconductors like Ge, Si, ETC.
Discussion
2876.

What is the fuel of atomic pile?

Answer»

Thorium
Sodium
Uranium
Petroleum

Solution :Uranium and PLUTONIUM is using now a DAYS as a FULE in ATOMIC pile.
Discussion
2877.

Which acid is formed by P_(2)O_(3)

Answer»

<P>`H_(3)PO_(4)`
`H_(3)PO_(3)`
`HPO_(3)`
`H_(4)P_(2)O_(7)`

Solution :`P_(2)O_(3) +3H_(2)O to 2H_(3)PO_(3)`
Discussion
2878.

Which of the following is the CORRECT decreasing order of the stabilities of the following metal oxides on the basis of Ellingham diagram ?

Answer»

`Al_(2)O_(3) gt Cr_(2)O_(3) gt MgO gt Ag_(2)O gt FeO`
`MgO gt Al_(2)O_(3) gt Cr_(2)O_(3) gt FeO gt Ag_(2)O`
`Cr_(2)O_(3) gt AGO gt Al_(2)O_(3) gt MgO gt FeO`
`Ag_(2)O gt FeO gt Cr_(2)O_(3) gt Al_(2)O_(3) gt MgO`

Answer :B
Discussion
2879.

What is the order of reaction whose rate constant has the same units as the rate of reaction ?

Answer»

SOLUTION :ZERO ORDER.
Discussion
2880.

Which one of the following can act as emulsifier?

Answer»

GLUE
dye
water
starch

Solution : glue
Discussion
2881.

Which of the following statement is(are) false ?

Answer»

`XeO_3` is a colourless explosive solid and has a pyramidral MOLECULAR structure
`XeF_2` is not a better oxidising agent
Xe, Kr and NE all form ciatharate compounds
Fluorine in dilute solution of sodium hydroxide disproportionates in FLUORIDE and hypofluorite

Solution :(A)Statement is correct

(B)Statement is false.
`2e^(-)+2H^(+)+XeF_2toXe+2HF`
SRP= + 2.64V
(C )Statement is false as Ne atoms being smaller do not trap in the cavities formed by water MOLECULES (ice) and thus does not form clatharte compounds .Xe and Krbeing bigger form clathrate compounds.
(D)Statement is false according to the following reaction :`2F_2+2NaOHtoOF_2(g)+2NaF+H_2O`
Discussion
2882.

X overset(HI)larr"Glucose" overset(HNO_3) rarrY. "What are " X and Y?

Answer»

`{:(X,Y),("n-Hexane" ,"Gluconi ACID"):}`
`{:(X,Y),("GLUCONIC acid" ,"Saccharic acid"):}`
`{:(X,Y),("n-Hexanol" ,"Saccharic acid"):}`
`{:(X,Y),("n-Hexane" ,"Saccharic acid"):}`

ANSWER :D
Discussion
2883.

Which of following pairs of name and formula of complexes, is not correct ?

Answer»

Tetraamminecopper(II)sulphate................ `[Cu(NH_(3))_(4)]SO_(4)`
Diamminesilver(I)chloride….`[Ag(NH_(3))_(2)]CL`
Potassiumhexacyanidoferrate(III)……… `K_(4)[FE(CN)_(6)]`
Potassiumamminepentachloridoplatinate(IV) ……… `K[PtCl_(2)(NH_(3))]`

SOLUTION :`K_(4)[Fe(CN)_(6)], O.S.` of Fe = +2
correct name is potassium hexacyanidoferrate (II)
Discussion
2884.

Which is not present in grignard reagent :

Answer»

CARBOXYLIC RADICAL represented by COOH
Magnesium represented by Mg
Alkyl radical represented by R
HALIDE radical represented by X

Answer :A
Discussion
2885.

The reason for the stabilitiy of Gd^(3+) ion is \

Answer»

half filled 4/-subshell
completely filled 4/-subshell
possesses the general electronic configuration of NOBLE gases
empty 4/-subshell.

Solution :`Gd(Z=64)RARR[XE]4f^(7)5d^(1)6s^(2)`
`therefore""Gd^(3+)rarr[Xe]4f^(7)`
Discussion
2886.

There are three elements A, B and C. their atomic number are Z_(1), Z_(2) and Z_(3) respectively. If Z_(1)-Z_(2)=2 and (Z_(1)+Z_(2))/(2)=Z_(3)-2 and the electronic configuration of element A is [Ar]3d^(6)4s^(2), then correct order of magnetic momentum is/are:

Answer»

`B^(+) GT A^(2+) gt C^(2+)`
`A^(3+) gt B^(2+) gt C`
`B gt A gt C^(2+)`
`B=A^(3+) gt C^(3+)`

ANSWER :A::B::C
Discussion
2887.

Which of the following is the correct order of radius?

Answer»

`H^(-) GT H gt H^+`
`Na^(+) gt F^(-) gt O^(2-)`
`F^(-) gt O^(2-) gt Na^+`
`AL^(3+) gt Mg^(2+) gt MN^(3-)`

ANSWER :A
Discussion
2888.

Write IUPAC names for

Answer»

SOLUTION :3-Amino-2-methyl BUTANAMIDE
Discussion
2889.

Which of the following is an inert polymer used in coating,particularly in non - sticking frying pans:

Answer»

TEFLON
Perspex
Bakelite
Orlon

Answer :A
Discussion
2890.

Which of the following oxides behaves as conductor or insulator depending upon temperature?

Answer»

`TiO`
`SiO_2` 
`TiO_3` 
`MGO`

SOLUTION :Because of VARIATION in forbidden GAP between valance band and condition band with the TEMPERATURE.
Discussion
2891.

Which of the following shows disproportionation ?

Answer»

`Cl_(2) underset("dil. NaOH")OVERSET("Cold")to`
`KCl underset(H_(2)SO_(4)) overset("CONC.")to `
`F_(2) overset(H_(2)O) to `
`H_(3)PO_(4) overset((DELTA))to`

Answer :A
Discussion
2892.

What will be the correct order for the wavelengths of absorption in the visible region for the following: [Ni(NO_(2))_(6)]^(4-), [Ni(NH_(3))_(6)]^(2+), [Ni(H_(2)O)_(6)]^(2+)

Answer»

Solution :As metal ion is fixed, the WAVELENGTH of absorption will be decided by the field STRENGTHS (CFSE values) of the ligands.
From the spectrochemical series, the order of CFSE is :`H_(2)OltNH_(3)ltNO_(2)^(-)`
Thus, the ENERGIES absorbed for excitation will be in the order :
`[Ni(H_(2)O)_(6)]^(2+)lt[Ni(NH_(3))_(6)]^(2+)lt[Ni(NO_(2))_(6)]^(4-)`
As wavelength and energy are inversely related `(E=(hc)/(lamda))`
The wavelengths absorbed will be in the OPPOSITE order :
i.e., `[Ni(H_(2)O)_(6)]^(2+)gt[Ni(NH_(3))_(6)]^(2+)gt[Ni(NO_(2))_(6)]^(4-)`
Discussion
2893.

What are hard and soft soap ?

Answer»

Solution :(i) Soap DERIVED from fats and caustic soda are known as hard soap .
USE: Use for washing PURPOSES.
(ii) Soap derived from FAT and caustic potash are known as soft soap.
Use: Used as BATH soap
Discussion
2894.

Which one of the following reaction is an example for calcination process ?

Answer»

`2AG + 2HCl + (O) to 2AgCl + H_(2)O`
`2Zn + O_(2) to 2ZnO`
`2 ZNS + 3O_(2) to 2 ZNO + 2SO_(2)`
`MgCO_(3() to MgO + CO_(2)`

Solution :In calcination, CARBONATES are DECOMPOSED to lose `CO_(2)`.
Discussion
2895.

Which of the following compounds can form H-bonding with each other ?

Answer»

`CH_3COOH and H_2O`
PHENOL and `CH_4`
`CH_3F` and ACETONE
`PH_3 ` and HF

Answer :A
Discussion
2896.

Which of the following is the correct increasing order of basicity of amines in gaseous phase ?

Answer»

`(CH_(3))_(2)NH gt CH_(3)NH_(2) gt (CH_(3))_(3)N gt NH_(3)`
`(CH_(3))_(3)N gt (CH_(3))_(2)NH gt CH_(3)NH_(2) gt NH_(3)`
`(CH_(3))_(2)NH gt (CH_(3))_(3)N gt CH_(3)NH_(2) gt NH_(3)`
`(CH_(3))_(3)N gt CH_(3)NH_(2) gt (CH_(3))_(2)NH gt NH_(3)`.

Solution :Alkyl AMINES `(1^(@), 2^(@), 3^(@))` are stronger bases than ammonia. This can be explained in terms of electron releasing INDUCTIVE effect of alkyl group. As a result, the electron density on the nitrogen ATOM increases and thus, they can donate the lone pair of electros more easily than ammonia.

The electron releasing effect is MAXIMUM in tertiary amines and minimum in primary amines (in GAS phase) `3^(@)` Amine `gt 2^(@)` amine `gt 1^(@)` amine `gt NH_(3)`
Discussion
2897.

Which of the following is used in flash tubes in photography ?

Answer»

Ar
Ne
KR
XE

Solution :Kr and Xe are used in FLASH tubes in PHOTOGRAPHY.
Discussion
2898.

Which method is used to get very pure germanium used is semiconductor ?

Answer»

Electrolysis
vapour PHASE refining
Liquation
Zone refining

Answer :D
Discussion
2899.

Which characteristic is not correct about H_2SO_4 ?

Answer»

REDUCING agent
OXIDISING agent
Sulphonating agent
HIGHLY VISCOUS

Solution :In `H_2SO_4`, the S atom is present in its highest oxidation state of +6 . HENCE `H_2SO_4` can act an reducing agent.
Discussion
2900.

The reagent that cannot be used for the conversion of C_6H_5NO_2 to C_6H_5NH_2.

Answer»

`SN"/"HCL`
`LiAlH_4`
`H_2"/"NI`
`Zn"/"NAOH`

Answer :D
Discussion