94420 + Interview Questions in Chemistry in Class 12 Page 582 InterviewSolution

29051.	The Lanthanoid contraction is responsible forthe fact that
Answer» Zr and Y have about the same RADIUS Zr and Nb have SIMILAR oxidation state Zr and HF have about the same radius Zr and Zn have the same oxidation state Answer :C

Discussion

29052.	The lanthanide contraction relates to :
Answer» Atomic radii Atomic as WELL as `M^(3+)` radii Valence electrons OXIDATION states Answer :B

Discussion

29053.	The lanthanide contraction is responsible for the fact that:
Answer» ZR and Y have ALMOST the same radius Zr and Nb have similar OXIDATION state Zr and Hf have almost the same radius Zr and Zn have same oxidation state Answer :C

Discussion

29054.	Thelanthanidecontractionisresponsiblefor thefactthat
Answer» ZR andZnhave thesameoxidationstate Zr and HF havealmostthe same RADIUS Zr and Nbhave similaroxidationstate Zr and Y havesimilarradius ANSWER :B

Discussion

29055.	The lanthanide contraction is responsible for the fact that
Answer» ZR and YB have same size Zr and NB have same OXIDATION sate Zr and Hf have same radius Zr and ZN have same oxidation state Answer :C

Discussion

29056.	The lanthanide contraction is due to
Answer» perfect shielding of F-orbitals perfect shielding of d-orbitals imperfect shielding of f-orbitals imperfect shielding of d-orbitals Solution :As we move from Ce to Lu, nuclear charge or effective nuclear charge increases by one unit at each ELEMENT because addition of 14-electrons in 4f-orbitals. The shielding EFFECT of 4f-electrons is very less or poor, which is due to diffused shape of 4f-orbital. The shielding effect of orbitals decreases in order. `s gt p gt d gt f.` Hence 4f-electrons are not able to shield perfectly the attraction between nucleus and outermost eletronic orbit. The effect of INCREASED nuclear charge is more than that of shielding effect of 4f-orbitals. hence atomic or ionic size decreases from Ce to Lu.

Discussion

29057.	The Lambda^(@) values of KNO_3 and LiNO_3 are 145.0 and 110.1S cm^(2) mol^(-1) respectively . The lambda^(@) value for K^(+) ion is 73.5 S cm^(2) mol^(-1) . Calculate lambda^(@) (Li^(+)) .
Answer» SOLUTION :`lambda_(m)^(oo) (NO_(3)^(-)) = Lambda^(oo) (KNO_(3)) - lambda^(oo) (K^(+))` `= 145.0 - 73.5 = 71.5 S cm^(2) mol^(-1)` `lambda^(oo) (Li^(+)) = Lambda^(oo) (LiNO_(3)) - lambda^(oo) (NO_(3)^(-))` `= 110.1 - 71.5 = 38.6 S cm^(2) mol^(-1)`

Discussion

29058.	The langmuir adsorption isotherm is given by
Answer» `x/m = - KP^(1//n)` `x/m = (ap)/(1 + bp)` `x/m - (bp)/a` `x/m = kp^n` Answer :B

Discussion

29059.	The Langmuir adsorption isotherm is deduced using the assumption
Answer» the ADSORPTION sites are EQUIVALENT in their ABILITY to adsorb the particles the heat of adsorption VARIES with coverage. the adsorted molecules INTERACT with each other. the adsorption takes place in maltilayers. Answer :A

Discussion

29060.	The lambda for H_alpha line of Balmer series is 6500 overset@A. Thus lambda for H_beta line of Balmer series is:
Answer» 4814 4914 5014 4714 Answer :A

Discussion

29061.	The lack of vitamin C leads to
Answer» beriberi anaemia blindress scurvy Answer :D

Discussion

29062.	The K_w ofneutral solution is 10^(-12) at a particular temperature. What are its pH and pOH values?
Answer» SOLUTION :`pK_w=pH+pOH=10^(-12)` For a NEUTRAL solution, `pH=pOH` So `pH=pOH=6`.

Discussion

29063.	The K_(sp) of Mg(OH)_(2) is 1 xx 10^(-12), 0.01 M Mg(OH)_(2) will precipitate at the limiting pH
Answer» 3 9 5 8 Solution :`Mg(OH)_(2) Mg^(2+) + 2OH^(-)` `K_(sp) = [Mg^(2+)] [OH^(-)]^(2)` `1 XX 10^(-12) = 0.01 [OH^(-)]^(2)` `[OH^(-)]^(2) = 1 xx 10^(-10) rArr [OH^(-)] = 10^(-5)` `[H^(+) = 10^(-14)//10^(-5) = 10^(-9)` `PH = -LOG[H^(+)] = -log[10^(-9)] = 9`.

Discussion

29064.	The K_sp of PbCO_3 and MgCO_3 are 1.5 xx 10^-15 and 1 xx 10^-15 repectively at 298 K. What is the concentration of Pb^2+ ions in saturated solution containing MgCO_3 and PbCO_3 ?
Answer» `1.5xx10^(-4)` M `3XX10^(-8)` M `2 xx 10^(-8)` M `2.5 xx 10^(-8)` M Answer :B

Discussion

29065.	The K_(sp) of CuS, Ag_(2)S and HgS are 10^(-31), 10^(-44) and 10^(-54) respectively. The solubility of these hydrides are in the order :
Answer» `Ag_(2)S GT CUS gt HgS` `Ag_(2)S gt HgS gt CuS` `CuS gt Ag_(2)Sgt HgS` `CuS lt Ag_(2)S lt HgS` ANSWER :A

Discussion

29066.	The K_(sp)ofBaCrO_(4) is 2.4xx10^(-10)M^(2). The maximum concentration of Ba(NO_(3))_(2)possible without precipitation in a 6xx10^(-4)M K_(2)CrO_(4) solution is
Answer» `4xx10^(-7)M` `1.2xx10^(10)M` `6XX10^(-4)M` `3xx10^(-4)M` Solution :`K_(sp)=[Ba^(2+)][CrO_(4)^(2-)]` `2.4xx10^(-10)=[Ba^(2+)](6xx10^(-4))` `therefore [Ba^(2+)]=(2.4xx10^(-10))/(6xx10^(-4))` `=4.0xx10^(-7)M`.

Discussion

29067.	The K_(sp) of Agl is 1.5 times 10^-16. ON mixing equal volume of the following solutions, precipitation will occur only with…..
Answer» `10^-7 M AG^+ and 10^-19 M I^-` `10^-8 M Ag^+ and 10^-8 M I^-` `10^-16 M Ag^- and 10^-16 MI^-` `10^-9 M Ag^+ and 10^-9 M I^-` Solution :`K_(sp) of Agl=1.5 TIMES 10^-16` `10^-8 M Ag^- and 10^-8 M I` Ionic PRODUCT `=10^-16=K_(sp)`

Discussion

29068.	The K_(SP) of Agl is 1.5 xx 10^(-16). On mixing equal volumes of the following solutions, precipitation will occur only with
Answer» `10^(-7) M AG^(+)` and `10^(-19) M I^(-)` `10^(-8) M Ag^(+)` and `10^(-8) M I^(-1)` `10^(-16) M Ag^(+)` and `10^(-16) M I^(-1)` `10^(-9) M Ag^(+)` and `10^(-9) M I^(-1)` Solution :`K_(SP)` of `AgI = 1.5 xx 10^(-3)` `10^(-8)M Ag^(+)` and `10^(-8) M I^(-)` Ionic product `~~ = 10^(-16)` `K_(sp)` = Ionic product.

Discussion

29069.	The K_(sp) of AgI at 25^@C is 1.0 xx 10^(-16) mol^2 L^(-2). The solubilityof AgI in 10^(-14)N solution of KI at 25^@C is approximetely (in mol L^(-1)):
Answer» `1.0 XX 10^(-16)` `1.0 xx 10^(-10)` `1.0 xx 10^(-12)` `1.0 xx 10^(-8)` ANSWER :C

Discussion

29070.	The K_(sp) of Ag_(2)CrO_(4) is 1.1 xx 10^(-12) at 298 K. The solubility (in mol/L) of Ag_(2)CrO_(4) in a 0.1 M AgNO_(3) solution is
Answer» `1.1 XX 10^(-11)` `1.1 xx 10^(-10)` `1.1 xx 10^(-12)` `1.1 xx 10^(-9)` Solution :`{:(Ag_(2)CrO_(4),HARR,"2Ag"^(+),+,CrO_(4)^(2-)),(s,,,,),(,,0.1+2s,,s),(,,~~0.1,,),(1.1 xx 10^(-12) = (0.1)^(2)s,,,,),(s = 1.1 xx 10^(-10),,,,):}`

Discussion

29071.	The K_(sp) of Ag_(2)CrO_(4), AgCl, AgBr and AgI are respectively, 1.1 xx 10^(-12), 1.8 xx 10^(-10), 5.0 xx 10^(-13), 8.3 xx 10^(-17). Which one of the following salts will precipitate last if AgNO_(3) solution is added to the solution containing equal moles of NaCl, NaBr, NaI and Na_(2)CrO_(4)
Answer» AgCl AgBr `Ag_(2)CrO_(4)` AgI Solution :`{:(K_(sp) " of " Ag_(2)CrO_(4),,= 1.1 xx 10^(-12)),(K_(sp) " of " AgCl,,= 1.8 xx 10^(-10)),(K_(sp) " of " AgBr,,= 5.0 xx 10^(-13)),(K_(sp) " of "AgI,,= 8.3 xx 10^(-17)),([Ag^(+)]^(2)[C],,= 1.1 xx 10^(-12)):}` `[Ag^(+)] = sqrt((1.1 xx 10^(-12))/([C]))` If we take [C] = 1 then the MAXIMUM requirement of `[Ag^(+)]` will be CASE of `Ag_(2)CrO_(4)`

Discussion

29072.	The K_(sp) " for " Cr(OH)_(3) " is " 1.6xx10^(-30). The solubility of this compound in water is :
Answer» `root(4)(1.6xx10^(-30))` `root(4)(1.6xx10^(-30)//27)` `1.6xx10^(-30//27)` `sqrt(1.6xx10^(-30)` Solution :`Cr(OH)_(s)(s) hArr Cr^(3+)(aq)underset(S)+3OH^(-)underset(3S)(aq)` `(s) (3s)^(3)=K_(SP)` `27S^(4)=K_(sp)` `s=((K_(sp))/(27))^(1//4)=((1.6xx10^(-30))/(27))^(1//4)`

Discussion

29073.	The K_(sp) for Cr(OH)_(3)is 1.6xx10^(-30). The molar solubility of this compound in water is :
Answer» `root(3)(1.6xx10^(-30))` `root(4)(1.6xx10^(-30)//27)` `1.6xx10^(-30)//27` `root(2)(1.6xx10^(-30))` Solution :If s is the SOLUBILITY of `CR(OH)_(3)` `Cr(OH)_(s)hArr UNDERSET(s)(Cr^(3+))+underset(3S)(3OH^(-))` `K_(sp)=(s)(3s)^(3)=27s^(4)` `therefore 27s^(4)=1.6xx10^(-30)` `s= root(4)(1.6xx10^(-30)//27)`

Discussion

29074.	The K_pvalue for the reaction equilibrium:H_2(g) + I_2 (s) iff 2HI(g)is 871 at 25^@C . If the vapour pressure of iodine is 4 xx 10^(-4) atm, calculate the equilibrium constant in terms of partial pressures at the same temperature.
Answer» SOLUTION :0.3484 ATM

Discussion

29075.	The K_(sp) for AgCl at 298 K is 1.0xx10^(-10). Calculate E for Ag^(+)//Ag electrode immersed in 1.0 M KCl solution. Given : E^(@)Ag^(+)//Ag=0.799" V".
Answer» SOLUTION :`AgCl(s)HARR Ag^(+)+Cl^(-)` `K_(sp)=[Ag^(+)][Cl^(-)]` `[Cl^(-)]=1.0M` `[Ag^(+)]=(k_(sp))/([Cl^(-)])=(1xx10^(-10))/(1)=1xx10^(-10)M` `"Now,"Ag^(+)+e^(-)rarrAg(s)` `E=E^(theta)-(0.059)/(1)log.(1)/([Ag^(+)])` `=0.80-(0.059)/(1)log.(1)/(10^(-10))` `=0.80-0.059xx10=0.21V`

Discussion

29076.	The K_(p) value for a homogeneous gaseous reaction is found to vary with the change in pressure. The correct conclusion is
Answer» the gases behave IDEALLY the gases deviate from IDEAL behaviour the gases in a reaction do not behave ideally `K_(p)` variation with PRESSURE is a consequence of experimental error Answer :B

Discussion

29077.	The K_(p) of a reaction is 10atm at 300K and 4 atm at 400K. The incorrect statement about the reaction is
Answer» The REACTION is exothermic The `E_(a )` of forward reaction is more than that of BACKWARD reaction. The rate of backward reaction increases more than that of forward reaction with INCREASE of temperature. The DIFFERENCE between heat of reaction at constant PRESSURE and that at constant volume is RT. Answer :B

Discussion

29078.	The Kp for reaction A + BhArrC + D is 1.34 at 60° C and 6.64 at 100°C. Determine the standard free energy change of this reaction at each temperature and DeltaH° for the reaction over this range of temperature ?
Answer» SOLUTION :`-810` J/mol , -5872 J/mol and 41.3 KJ/mol

Discussion

29079.	Theknockingwillbemainmumwhenthemixtureof fuel is :
Answer» Strightchained iso-carbonation neo-carbonation NONE of these Answer :C

Discussion

29080.	the Kohinoor diamond was the largest diamond ever found . How many moles of carbon atom were presnent in it , if it is weight 3300 carat. [Given :1 carrat = 200 mg ]
Answer» ANSWER :55

Discussion

29081.	The Kirchhoff's equation given the effect of_____ on heat of reactions:
Answer» Pressure Temperature Volume Molecularity Answer :B

Discussion

29082.	The king of delocalization involving sigma and orbitals is called
Answer» INDUCTIVE EFFECT HYPERCONJUGATION effect clectromeric effect mesomeric effect. ANSWER :B

Discussion

29083.	The kinetically more stable alltrope of phosphorus is
Answer» Redphosphorus Blackphosphorus Yellowphosphorus WHITE PHOSPHORUS Solution :BLACK phosphorous is most stable ALLOTROPE

Discussion

29084.	The kinetic study of a reaction like vA rarr P at 300 K provides the following curve, where concentration is taken in mol dm^(-3) and time in min.
Answer» N = 0, k = 4.0 mol `dm^(-3) min^(-1)` `n=(1//2), k = 2.0 mol^(1/2) dm^(-3//2) min^(-1)` n= 1, k= 8.0 `min^(-1)` n - 2, k = 16.0 `dm^3 mol^(-1) min(-1)` Solution : From the graph, `sqrt(r_0)=4[A]_0` …(i) RATE = `k[A]_0^n` …(ii) `therefore r_0 = 16[A]_0^2` On comparing EQ. (ii) and (iii),we get, k=`16dm^3mol^(-1)min^(-1)`,n = 2

Discussion

29085.	The kinetic molecular theory attributes an average kinetic energy of (3)/(2) kT to each particle. What rms speed would a mist particle of mass 10^(-12) g have at room temperature (27^(@)C) according to the kinetic molecular theory ?
Answer» Solution :KE per MOLECULE `= (3)/(2)kT` `= (3)/(2).(R)/(N).T`. If the mass of ONE molecule is m then KE of this molecule `= (1)/(2) MC^(2)`, where c is the rms SPEED. `therefore (1)/(2)mC^(2) = (3)/(2) (R)/(N).T` or `C = sqrt(3 xx (R)/(N) xx (T)/(m))` `= sqrt((3 xx 8.314 xx 10^(7) xx 300)/(6.022 xx 10^(23) xx 10^(-12))) = 0.35 cm//s`

Discussion

29086.	The kinetic gas equation for 'N' number of molecues in volume V having mass m and root mean squarevelocity mu is :
Answer» `PV = ( 1)/( 3) mN mu ^(2)` `pV = ( 3)/( 2)mN mu^(2)` `pV = ( 2)/(3) mN mu^(2)` `(3)/(2) pV= mN mu^(2)` Answer :A

Discussion

29087.	The kinetic energy of the electron emitted when light of frequency 3.5xx10^(15)Hz is made to strike on a metal surface havng threshold frequency 1.5xx10^(15)Hz is (h=6.6xx10^(-34)Js)
Answer» `1.32xx10^(-18J` `3.3xx10^(-18)J` `6.6xx10^(-19)J` `1.98xx10^(-19)J` Solution :`KE=hv-hv_(0)=H(v-v_(0))` `=6.6xx10^(-34)(3.5xx10^(15)-1.5xx10^(15))` `=1.32xx10^(-18)J`

Discussion

29088.	The kinetic energy of sub-atomic particle is 5.85 xx 10^(-25)J. Calculate the frequency of the particle wave. (Planck’s constant, h = 6.626 xx 10^(-34) Js)
Answer» Solution :`K.E = 1/2 MV^2 = 5.85 xx 10^(-25) J` By de-broglie equation ` lamda = (h)/(mv)` `lamda = (v)/(upsilon)` ` therefroe v/v = (h)/(mv)` or` v = (mv^2)/(h) = (2 xx 5.85 xx 10^(-25)J)/(6.626 xx 10^(-34) JS)` ` = 1.77 xx 10^9 s^(-1)`

Discussion

29089.	The kinetic energy of one mole of any gas depends upon
Answer» PRESSURE of the GAS nature of the gas volume of the gas absolute TEMPERATUE of the gas ANSWER :B

Discussion

29090.	The kinetic energy of molecules at constant temperature in gaseous state is :
Answer» More than those in the LIQUID state Less then those in the liquid state Equal to those in the liquid state None of these Answer :C

Discussion

29091.	The kinetic energy of molecule is zero at :
Answer» `0^@ C` `273^@C` `-273^@C` `116^@C` ANSWER :C

Discussion

29092.	The kinetic energy of electrons ejected by using light having frequency equal to threshold frequency (v_(0)) is
Answer» `hv_(0)` ALMOST zero very LARGE `h//v_(0)` SOLUTION :`K.E. =HV-hv_(0)` or `hv_(0)-hv_(0)=0`

Discussion

29093.	The kinetic energy of an electron is 4.55xx10^(-28) kJ. Calculate the de Broglie's wavelength.
Answer» SOLUTION :`7.2xx10^(-7)m`

Discussion

29094.	The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is (a_(0) is Bohr radius)
Answer» `(h^(2))/(4PI^(2)ma_(0)^(2))` `(h^(2))/(16pi^(2) ma_(0)^(2))` `(h^(2))/(32pi^(2) ma_(0)^(2))` `(h^(2))/(64pi^(2) ma_(0)^(2))` Solution :`mvr= (nh)/(2PI), mv= (nh)/(2pi r) and KE = (1)/(2)mv^(2)= (m^(2)v^(2))/(2M) or E= (n^(2)h^(2))/(4pi^(2) r^(2))xx (1)/(2m)` use `r= n^(2) a_(0) (a_(0)=r_(1))`

Discussion

29095.	The kinetic date for the given reaction A(g)+2B(g)overset(K)toC(g) is provided in the following table for three experiments at 300 K {:("Ex. No.","[A/M]","[B/M]","Initial rate" (M sec^(-1))),(1.,0.01,0.01,6.930xx10^(-6)),(2.,0.02,0.01,1.386xx10^(-5)),(3.,0.2,0.02,1.386xx10^(-5)):} ltbgt In another experiment starting swith initial concentration of 0.5 and 1 M respectively for A and B at 300 K, find the rate of reaction after 50minutes from the starting of edperiment (inM//sec).
Answer» `6.93xx10^(-4)` `0.25xx10^(-7)` `4.33xx10^(-5)` `3.46xx10^(-4)` ANSWER :C

Discussion

29096.	The kind of colloid that does not exist
Answer» SOLID in GAS Gas in solid Solid in solid Gas in gas Answer :D

Discussion

29097.	The key structural feature of protein is:
Answer» ETHER linkage Peptide bond Ester linkage All the three. Answer :B

Discussion

29098.	The key step in cannizzaro's reaction is the intermolecular shift of
Answer» Proton Hydride ION Hydronium ion Hydrogen bond Solution :Cannizzaro REACTION is an example of hydride ion `(H^(-))` transfer reaction.

Discussion

29099.	The keto form of ethyl aceto acetate is indicated by
Answer» Sodium <BR>`NaHSO_(3)` `FeCl_(3)` `Br_(2)` Solution :It GIVES white addition product with `NaHSO_(3)`.

Discussion

29100.	The kinetic energy of the photoelectrons depends upon:
Answer» INTENSITY of radiation FREQUENCY of radiation the intensity and frequency of radiation none of these Answer :B

Discussion

Explore topic-wise InterviewSolutions in .

The Lanthanoid contraction is responsible forthe fact that

The lanthanide contraction relates to :

The lanthanide contraction is responsible for the fact that:

Thelanthanidecontractionisresponsiblefor thefactthat

The lanthanide contraction is responsible for the fact that

The lanthanide contraction is due to

The Lambda^(@) values of KNO_3 and LiNO_3 are 145.0 and 110.1S cm^(2) mol^(-1) respectively . The lambda^(@) value for K^(+) ion is 73.5 S cm^(2) mol^(-1) . Calculate lambda^(@) (Li^(+)) .

The langmuir adsorption isotherm is given by

The Langmuir adsorption isotherm is deduced using the assumption

The lambda for H_alpha line of Balmer series is 6500 overset@A. Thus lambda for H_beta line of Balmer series is:

The lack of vitamin C leads to

The K_w ofneutral solution is 10^(-12) at a particular temperature. What are its pH and pOH values?

The K_(sp) of Mg(OH)_(2) is 1 xx 10^(-12), 0.01 M Mg(OH)_(2) will precipitate at the limiting pH

The K_sp of PbCO_3 and MgCO_3 are 1.5 xx 10^-15 and 1 xx 10^-15 repectively at 298 K. What is the concentration of Pb^2+ ions in saturated solution containing MgCO_3 and PbCO_3 ?

The K_(sp) of CuS, Ag_(2)S and HgS are 10^(-31), 10^(-44) and 10^(-54) respectively. The solubility of these hydrides are in the order :

The K_(sp)ofBaCrO_(4) is 2.4xx10^(-10)M^(2). The maximum concentration of Ba(NO_(3))_(2)possible without precipitation in a 6xx10^(-4)M K_(2)CrO_(4) solution is

The K_(sp) of Agl is 1.5 times 10^-16. ON mixing equal volume of the following solutions, precipitation will occur only with…..

The K_(SP) of Agl is 1.5 xx 10^(-16). On mixing equal volumes of the following solutions, precipitation will occur only with

The K_(sp) of AgI at 25^@C is 1.0 xx 10^(-16) mol^2 L^(-2). The solubilityof AgI in 10^(-14)N solution of KI at 25^@C is approximetely (in mol L^(-1)):

The K_(sp) of Ag_(2)CrO_(4) is 1.1 xx 10^(-12) at 298 K. The solubility (in mol/L) of Ag_(2)CrO_(4) in a 0.1 M AgNO_(3) solution is

The K_(sp) of Ag_(2)CrO_(4), AgCl, AgBr and AgI are respectively, 1.1 xx 10^(-12), 1.8 xx 10^(-10), 5.0 xx 10^(-13), 8.3 xx 10^(-17). Which one of the following salts will precipitate last if AgNO_(3) solution is added to the solution containing equal moles of NaCl, NaBr, NaI and Na_(2)CrO_(4)

The K_(sp) " for " Cr(OH)_(3) " is " 1.6xx10^(-30). The solubility of this compound in water is :

The K_(sp) for Cr(OH)_(3)is 1.6xx10^(-30). The molar solubility of this compound in water is :

The K_pvalue for the reaction equilibrium:H_2(g) + I_2 (s) iff 2HI(g)is 871 at 25^@C . If the vapour pressure of iodine is 4 xx 10^(-4) atm, calculate the equilibrium constant in terms of partial pressures at the same temperature.

The K_(sp) for AgCl at 298 K is 1.0xx10^(-10). Calculate E for Ag^(+)//Ag electrode immersed in 1.0 M KCl solution. Given : E^(@)Ag^(+)//Ag=0.799" V".

The K_(p) value for a homogeneous gaseous reaction is found to vary with the change in pressure. The correct conclusion is

The K_(p) of a reaction is 10atm at 300K and 4 atm at 400K. The incorrect statement about the reaction is

The Kp for reaction A + BhArrC + D is 1.34 at 60° C and 6.64 at 100°C. Determine the standard free energy change of this reaction at each temperature and DeltaH° for the reaction over this range of temperature ?

Theknockingwillbemainmumwhenthemixtureof fuel is :

the Kohinoor diamond was the largest diamond ever found . How many moles of carbon atom were presnent in it , if it is weight 3300 carat. [Given :1 carrat = 200 mg ]

The Kirchhoff's equation given the effect of_____ on heat of reactions:

The king of delocalization involving sigma and orbitals is called

The kinetically more stable alltrope of phosphorus is

The kinetic study of a reaction like vA rarr P at 300 K provides the following curve, where concentration is taken in mol dm^(-3) and time in min.

The kinetic molecular theory attributes an average kinetic energy of (3)/(2) kT to each particle. What rms speed would a mist particle of mass 10^(-12) g have at room temperature (27^(@)C) according to the kinetic molecular theory ?

The kinetic gas equation for 'N' number of molecues in volume V having mass m and root mean squarevelocity mu is :

The kinetic energy of the electron emitted when light of frequency 3.5xx10^(15)Hz is made to strike on a metal surface havng threshold frequency 1.5xx10^(15)Hz is (h=6.6xx10^(-34)Js)

The kinetic energy of sub-atomic particle is 5.85 xx 10^(-25)J. Calculate the frequency of the particle wave. (Planck’s constant, h = 6.626 xx 10^(-34) Js)

The kinetic energy of one mole of any gas depends upon

The kinetic energy of molecules at constant temperature in gaseous state is :

The kinetic energy of molecule is zero at :

The kinetic energy of electrons ejected by using light having frequency equal to threshold frequency (v_(0)) is

The kinetic energy of an electron is 4.55xx10^(-28) kJ. Calculate the de Broglie's wavelength.

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is (a_(0) is Bohr radius)

The kind of colloid that does not exist

The key structural feature of protein is:

The key step in cannizzaro's reaction is the intermolecular shift of

The keto form of ethyl aceto acetate is indicated by

The kinetic energy of the photoelectrons depends upon: