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30551.

The geometry possible in [FeF_(6)]^(4-) and [CoF_(6)]^(4-) is …………………………

Answer»

Trigonal bipyramidal
SQUARE planar
OCTAHEDRAL
TETRAHEDRAL

Answer :C
30552.

The shape of XeOF_(2) is :

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Pyramidal
T - SHAPED
Octahedral
Tetrahedral.

Solution :`XeOF_(2)` MOLECULE has T - shaped GEOMETRY.
30553.

The geometry of XeF_6 molecule and the hybridization of Xe atom in the molecule is :

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Distorted OCTAHEDRAL and `sp^3 d^3`
Square PLANAR and `sp^3d^2`
PYRAMIDAL and `sp^3`
Octahedral and `sp^3 d^3`

Solution :Distorted octahedral and `sp^3 d^3`
30554.

The geometry of [Ni(CO)_(4)] and [Ni("PP"h_(3))_(2)Cl_(2)] are

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both square planar
TETRAHEDRAL and square planar respectively
both tethrahedral
square planar and tetrahedral respectively.

Solution :Oxidation state oif Ni in `[Ni(CO)_(4)]=0`
`Ni^(0)(Z=28):3d^(8)4s^(2)`
Since CO is striong field ligand , it forces electrons to pair up and thus `sp^(3)`hybridisation takes place which results in tetrahedral geometry.

In `[Ni("PP"h_(3))_(2)Cl_(2)]` oxidation station fio `Ni=+2`.
This COMPLEX contsins weak field lignad `(Cl^(-))` as well as strong field `("PP"h_(3))` . Weak field ligand favours tetrahderal geometry and strong field ligand favours square planar geometry. Hence this compound is borderline between these two geometries. But due to steric effect of two larger `"PP"h_(3)` ligands LESS crowded tetradehral geometry is favoured
30555.

The geometry of water molecules is sameas that of

Answer»

`C_2H_4`
BORON TRIFLUORIDE
`CO_2`
Chlorineoxide

ANSWER :D
30556.

The geometry of water molecule is same as that of :

Answer»

`CO_2`
`C_2H_4`
CHLORINE oxide
Boron trifluoride

Answer :C
30557.

The geometry of ethyl amine is :

Answer»

PYRAMIDAL
Tetrahedral
TRIANGULAR
SQUARE planar

Answer :A
30558.

The geometry of Ni(CO)_4 and Ni(PPh_3)_2CI_2 are :

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Both SQUARE PLANAR
TETRAHEDRAL, and square planar respectively
Both tetrahedral
Square planar and tetrahedral respectively

Answer :B
30559.

The geometry of. Ni(CO)_4 and Ni(PPH_3)_2CI_2 are :

Answer»

Both SQUARE PLANAR
TETRAHEDRAL, and square planar respectively
Both tetrahedral
Square planar and tetrahedral respectively

Answer :B
30560.

The geometry of [NiCl_(4)]^(2-) and [NiCl_(2)(Pme_(3))_(2)] are :

Answer»

both square PLANAR
tetrahedral and square planar respectively
both tetrahedral
square planar and tetrahedral respectively

Solution :[NI`Cl_(4)]^(2-) implies sp^(3) , [NiCl_(2) (Pme_(3))_(2)] implies DSP^(2)`
30561.

The geometry of [Ni(CO)_(4)] and [NiCl_(2) (P Ph_(3))_(2)] are:

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both SQUARE PLANAR
TETRAHEDRAL and square planar respectively
both are tetrahedral
square planar and tetrahedral respectively

Answer :C
30562.

The geometry of Ni(CO)_(4) and Ni(P Ph_(3))_(2)Cl_(2) are

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both SQUAR eplanar
tetrahedral and SQUARE planar
both tetrahedral
none of these

Solution :
30563.

Thegeometryof methanemoleculeis :

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TETRAHEDRAL
PYRAMIDAL
octanhedral
squareplaner

ANSWER :A
30564.

The geometry of IF_(7) molecule is :

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1. Trigonal bipyramidal
2. TETRAHEDRAL
3. Pentagonal bipyramidal
4. Octahedral

ANSWER :C
30565.

The geometry of H_2S and its dipole moment are :

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ANGULAR and NON zero
Angular and zero
Linear and zero
Linear and non-zero

Answer :A
30566.

The geometry of FeCl_(4)^(2-), FeCl_(2)(PPh_(3))_(2) and AuCl_(4)^(-) would be respectively.

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All SQUARE PLANAR
All TETRAHEDRAL
Tetrahedral, tetrahedral and square planar
Tetrahedral, square planar and tetrahedral

Answer :C
30567.

The geometry of ]Fe(CN)_(5))^(-) is ………………

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Tetrahedral
Octahedral
Square planar
Trigonamal bipyramidal

Answer :A::B::C::D
30568.

The geometry of compounds formed by sp^3d^2 - hybridisation is :

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SQUARE PLANAR
Octahedral
Trigonal bipyramidal
Pentagonal bipyramidal

Answer :B
30569.

The structure of [Cu(H_2O)_4]^(2+) ions is:

Answer»

SQUARE planar
Tetrahedral
Octahedral
Distorted RECTANGLE

ANSWER :A
30570.

The geometry of [Co(CO)_(4)]^(-)" and "[Cd(CN)_(4)]^(2-) are :

Answer»

both square PLANAR
both tetrahedral
tetrahedral and square planar, respectively
square planar and tetrahedral, respectively

Solution :`[CO(CO)_(4)]^(-)" and "[CD(CN)_(4)]^(2-)` both are tetrahedral (`d^(10)` CONFIG.)
30571.

The geometry of ClO_(3)^(-) according to valence shell electron pair repulsion (VSEPR) theory will be

Answer»

PLANAR triangle
pyramidal
ictrahcdral
SQUARE planar

Solution :HYBRIDISATION is `SP^(3)` and shape pyramidal
30572.

The geometry of ClO_(4)^(-) ion is :

Answer»

TETRAHEDRAL
OCTAHEDRAL
TRIGONAL bipyramidal
PYRAMIDAL.

ANSWER :A
30573.

The geometry of ClO_(3)^(-) according to valence shell electron pair repulsion theory will be

Answer»

PLANAR triangle
Pyramidal
Tetrahedral
Square planar.

Answer :B
30574.

The geometry of ammonia molecule can be best described as

Answer»

NITROGEN at one vertex of a regular tetrahedron, the other three VERTICES being occupied by the three hydrogens
nitrogen at the CENTRE of the tetrahedron, three of the vertices being occupied by three hydrogen
nitrogen at the centre of an equilateral TRIANGLE, three corners beings occupied by three hydrogens
nitrogen at the JUNCTION of a T, three open ends being occupied by three hydrogens

Answer :B
30575.

The geometry of a complex due to dsp^(2) hybridisation in the central metal ion is

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TRIANGULAR planar
tetrahedral
square planar
trigonal bipyramidal

Answer :A::C
30576.

The geometry ion which hs no d electrons in the central metal atom is : [Atomic number Cr=24, Mn=25, Fe=26, Co=27]

Answer»

`[MnO_(4)]^(-)`
`[Co(NH_(3))_(6)]^(3+)`
`[Fe(CN)_(6)]^(3-)`
`[Cr(H_(2)O)_(6)]^(3+)`

SOLUTION :`MnO_(4)^(-) implies Mn implies + 7 `
`d^(@)` CONFIGURATION
30577.

The geometry at which carbon atom in diamond are bonded to each other is

Answer»

Tetrhedral
hexagonal
Octahederal
None of these

Answer :A
30578.

The geometry and hybridisation involved in [CuCl_(2)]^(-) are…………….respectively.

Answer»


ANSWER :LINEAR,SP
30579.

The geometry and magnetic behavior of the complex [Ni(CO)_4] are

Answer»

SQUARE planar geometry and PARAMAGNETIC
tetrahedral geometry and diamagnetic
square planar geometry and diamagnetic
tetrahedral geometry and paramagnetic

Answer :B
30580.

The geometries of the ammonia complexes of Ni^(2+),Pt^(2+) and Zn^(2+), respectively, are

Answer»

OCTAHEDRAL,SQUARE PLANAR andtetrahedral
square planar, octahedral and TETRAHEDRAL
tetrahedral , square planar and octahedral
octahedral , tetrahedral and square planar

Answer :A
30581.

The geometrical arrangement and shape of I_3^-are respectively

Answer»

TRIGONAL bipyramidal geometry, LINEAR shape
hexagonal geometry, T-shape
TRIANGULAR planar geometry, triangular shape
tetrahedral geometry, pyramidal shape

Answer :A
30582.

The geometrical isomerism is shown by

Answer»




ANSWER :D
30583.

The geometry of NF_(5) molecule is :

Answer»

TRIGONAL bipyramidal
Square planar
Tetrahedral
NONE of these

ANSWER :D
30584.

The general valence shell electronic configuration of actinoids is

Answer»

`[XE] 4F^(2-14)5D^(0-2) 6S^(2)`
`[Rn] 4f^(2-14) 5d^(0-2)6s^(2)`
`[Rn] 4f^(2-14) 5d^(0-2)7s^(2)`
`[Rn] 4f^(0-7) 5d^(0-1)6s^(2)`

Solution :`[Rn] 4f^(2-14) 5d^(0-2)7s^(2)`
30585.

The general trend in the properties of elements of carbon family shows that with increase in atomic number

Answer»

the tendency towards CATENATION increases
the tendency to SHOW `+2` oxidation state increases
metallic character decreases
the tendency to FORM complexes with covalency higher than four decreases

Answer :B
30586.

The general outer shell electronic configuration fo transition elements is "….................".

Answer»

SOLUTION :`(n-1)d^(1-10)NS^(0-2)`
30587.

The general order of reactivity of carbonyl compounds towards nucleophilic addition reaction is

Answer»

`H_(2)C = O GT RCHO gt ArCHO gt R_(2)C = O gt Ar_(2)C = O`
`ArCHO gt Ar_(2)C = O gt RCHO gt R_(2)C = O gtH_(2)C = O`
`Ar_(2)C = O gt R_(2)C = O gt ArCHO gt RCHO gtH_(2)C = O`
`H_(2)C = O gt R_(2)C = O gt Ar_(2)C = O gt RCHO gt ArCHO`

Solution :Reactivity DECREASES the magnitude of positive charge on the carbonyl carbon decreases or the steric hindrance in the intermediate increases, hence the correct ORDER of reactivity of carbonyl compounds towards nucleophilic addition reaction is,
`H_(2)C=O gt RCHO gt ArCHO gt R_(2)C=O gt Ar_(2)C=O`
30588.

The general outer electronic configuration of transition elements is

Answer»

`ND^(1-10)`
`(n-1)d^(1-10)NS^2`
`(n-1)d^(1-10)ns^(1-2)`
`nd^(1-10)ns^(1-2)`

ANSWER :C
30589.

The general order of reactivity of carbonyl compounds for nucleophilic addition reaction is

Answer»

`H_(2)C = O gt RCHO gt ArCHO gt R_(2)C =O gt Ar_(2)C =O`
`ArCHO gt Ar_(2)C =O gt RCHO gt R_(2)C = O gt H_(2)C =O`
`Ar_(2)C = O gt R_(2)C =O gt ArCHO gt RCHO gt H_(2)C =O`
`H_(2)C = O gt R_(2)C = O gt Ar_(2)C = O gt RCHO gt ArCHO`

Solution :The size of the alkyl group, CAUSES hindrance to attacking group. As the number and size of the alkyl groups increase the hindrance to the attack to nucleophile also increases. Thus the REACTIVITY follows the ORDER
`H_(2)C = O gt RCHO gt ArCHO gt R_(2)C = O gt Ar_(2)C = O`
30590.

The general molecular formula which represents the homologous series of alkanols is

Answer»

`C_(n)H_(2n+2)O`
`C_(n)H_(2n)O_(2)`
`C_(n)H_(2n)O`
`C_(n)H_(2n+1)O`

ANSWER :A
30591.

The general molecular formula of monohydric alcohols and . . is same.

Answer»

ALDEHYDE
Ketones
ETHERS
Ester

Solution :Both ethers and mono-hydric alcohols have formula `C_(n)H_(2n+2)O`
30592.

The general molecular formula which represents the homologous series of alkanol is

Answer»

`C_n H_(2N) O`
`C_n H_(2n+1) O`
`C_n H_(2n+2) O`
`C_n H_(2n)O_2`

ANSWER :C
30593.

The general formula, which represent the homologous series of alcohol is

Answer»

`C_nH_(2N)O`
`C_nH_(2n+1)O`
`C_nH_(2n)O_2`
`C_nH_(2n+2)O`

ANSWER :D
30594.

The general formula which represents the homologous series of alkanols is :

Answer»

`C_(N)H_(2N)O`
`C_(n)H_(2n+1)O`
`C_(n)H_(2n+2)O`
`C_(n)H_(2n)O_(2)`.

Answer :C
30595.

The general formula (RCO)_2O represents :

Answer»

A ketone
An ether
An ACID anhydride
An ester

Answer :C
30596.

The general formula of quaternary ammoniam salt is

Answer»

`RNH_(2)`
`R_(2)NH`
`R_(3)N`
`R_(4)NX`

Answer :D
30597.

The general formula of quarternary ammonium compound is :

Answer»

`R-NH_2`
`R_3N`
`[R_4N]^+X^-`
`NH_4X`

ANSWER :C
30598.

The general formula of hypophosphorus acid is:

Answer»




ANSWER :A
30599.

The general formula of ferrites is Mfe_(2)O_(4). Where 'M' would not be

Answer»

Mg
Cu
Al
Zn

Answer :C
30600.

The general formula of ethers is

Answer»

`C_nH_(2N)O`
`C_n H_(2n+1) O`
`C_n H_(2n+2) O`
`C_n H_(2n) OC_n H_(2n)`

ANSWER :C