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31401.

The correct set of four quantum numbers for the outermost electron of sodium (Z=11) is

Answer»

`3,1,0,1/2`
`3,1,1,1/2`
`3,2,1,1/2`
`3,0,0,1/2`

SOLUTION :The electronic configuration of Na(Z=11) is`1s^(2)2S^(2)2P^(6)3s^(1)`. The outermost orbital is 3s.
`:.n=3, l=0, m=0, s=+1/2`
Discussion
31402.

The correct set of four quantum numbers for valence electrons of rubidium atom (Z=37) is

Answer»

`5, 0,0, + (1)/(2)`
`5, 1, 0, + (1)/(2)`
`5, ,1, 1, + (1)/(2)`
`5, 0, 1, + (1)/(2)`

Solution :Valence ELECTRON is 5S.
Discussion
31403.

The correct set of decreasing order of electronegativity is:

Answer»

`LI, H, NA`
`Na, H, Li`
`H, Li, Na`
`Li, Na, H`

ANSWER :C
Discussion
31404.

The correct sequence of the melting points of 16 elements is

Answer»

`H_(2)S gt H_(2)O gt H_(2)Se gt H_(2)Te`
`H_(2)S gt H_(2)Se gt H_(2)Te gt H_(2)O`
`H_(2)O gt H_(2)Te gt H_(2)Se gt H_(2)S`
`H_(2)S gt H_(2)Te gt H_(2)Se gt H_(2)S`

ANSWER :C
Discussion
31405.

Thecorrect sequence of the atomic layers in cubic close packing is

Answer»

ABABA
ABACABAC
ABCABC
AABBAABB

Answer :A::B::C
Discussion
31406.

The correct sequence of steps involved in the mechanism of cannizzaro's reaction is……..

Answer»

Nucleophilic attack, transfer of `H^(-)` and transfer of `H^(+)`
Transfer of `H^(-)`, transfer of `H^(+)` and nucleophilic attack
Transfer of `H^(+)`, nucleophilic attack and transfer of `H^(-)`
Electrophilic attack by `OH^(-)`, transfer of `H^(+)` and transfer of `H^(-)`

SOLUTION :`H-OVERSET(H)overset(|)(C )=O+ OH^(-) overset("FAST")underset("Nucleophilic attack")rarr`
Discussion
31407.

The correct sequence of steps involved in the mechanism of Cannizzaro's reaction is …..

Answer»

NUCLEOPHILIC ATTACK, transfer of `H^(-)` and transfer of `H^(+)`
transfer of `H^(-),` transfer of `H^(+)` and nucleophilic attack
transfer of `H^(+)`, nucleophilic attack and transfer of `H^(-)`
ELECTROPHILIC attack by `OH^(-)`, transfer of `H^(+)` and transfer of `H^(-)`.

ANSWER :A
Discussion
31408.

The correct sequence of steps involved in the mechanism of Cannizzaro's reaction is

Answer»

NUCLEOPHILIC attack, transfer of `H^(-_` and transfer of `H^(+)`
transfer of `H^(-)`, transfer of `H^(+)` and nucleophillic attack.
transfer of `H^(+)`, nucleophilic attack and transfer of `H^(-)`
electrophilic attack by `OH^(-)` transfer of `H^(+)` and transfer of `H^(-)`

SOLUTION :
Discussion
31409.

The correct sequence of relatvie reactvityof following alkyl halides1CH_(3)CH_(2)Cl, 2 (CH_(3))_(2)CHCHl, 3 (CH_(3))_(3)C Cl

Answer»

`1 GT 2 gt 3`
`2 gt 3 gt 1`
`3 gt 2 gt 1`
`3 gt 1 gt 2`

SOLUTION :The alkyl halide, which gives the most SUBSTITUTED alkene,is the most reactive halide,this is is know as Saytzeff's rule.
Discussion
31410.

The correct sequence of regents for the following conversion is:

Answer»

`overset(SOCl_(2))rarroverset(Ag)underset(H_(2)O)rarroverset(CH_(2)N_(2))RARR`
`overset(SOCl_(2))rarroverset(CH_(2)N_(2))rarroverset(Ag,H_(2)O)rarr`
`overset(CH_(2)N_(2))rarroverset(SOCl_(2))rarroverset(Ag)underset(H_(2)O)rarr`
`overset(Ag)underset(H_(2)O)rarroverset(SOCl_(2))rarroverset(CH_(2)N_(2))rarr`

Answer :B
Discussion
31411.

The correct sequence of reagents for the following conversion will be :

Answer»

`[AG(NH_(3))_(2)]^(+)OH^(-), H^(+)//CH_(3)OH, CH_(3)MgBr`
`CH_(3)MgBr,H^(+)//CH_(3)OH,[Ag(NH_(3))_(2)]^(+)OH^(-)`
`CH_(3)MgBr, [Ag(NH_(3))_(2)]^(+), H^(+)//CH_(3)OH`
`[Ag(NH_(3))_(2)]^(+)OH^(-),CH_(3)MgBr, H^(+)//CH_(3)OH`

Solution :
Discussion
31412.

The correct sequence of reagents for the following conversion is

Answer»

`OVERSET(SOCl_2)tooverset(AG)UNDERSET(H_2O)tooverset(CH_2N_2)to`
`overset(SOCl_2)tooverset(CH_2N_2)tooverset(Ag)underset(H_2O)to`
`overset(CH_2N_2)tooverset(SOCl_2)tooverset(Ag)underset(H_2O)to`
`overset(Ag)underset(H_2O)tooverset(SOCl_2)tooverset(CH_2N_2)to`

SOLUTION :
Discussion
31413.

The correct sequence of reactions to convert p-nitrophenol into quinol involves

Answer»

REDUCTION, DIAZOTISATION and hydrolysis
hydrolysis, DIAZOTIZATION and reduction
hydrolysis, reduction and diazotization
diazotization, reduction and hydrolysis

Solution :
Discussion
31414.

The correct sequence of reactions to convert p-nitrophenol in to quinol involves

Answer»

REDUCTION, DIAZOTIZATION and HYDROLYSIS
Hydrolysis, diazotization and reduction
Hydrolysis, reduction and diazotization
Diazotization, reduction and hydrolysis

Solution :
Discussion
31415.

The correct sequence of polarity of the following molecule (1)Benzene(2)Inorganci Benzene (3)PCl_(3)F_(2)(4)PCl_(2)F_(3)

Answer»


Solution :
In sheet SILICATES although one `SiO_(4)^(4-)` tetrahedron is linked to other three tetrahedrons but the LAYER/ sheet OBTAINED in not planar, as fourthoxgyen atom is projecting away from sheet.
Discussion
31416.

The correct sequence of reactions to be performed to convert benzene into m-bromoaniline is

Answer»

NITRATION, REDUCTION, BROMINATION
bromination, nitration, reduction
nitration, bromination, reduction
reduction, nitration, bromination.

Solution :
Discussion
31417.

The correct sequence of reaction to convert p-nitrophenol into quinol involves

Answer»

A) REDUCTION, DIAZOTIZATION and HYDROLYSIS
B) hydrolysis, diazotization and reduction
C) hydrolysis, reduction and diazotization
D) diazotization, reduction and hydrolysis.

Solution :
Discussion
31418.

The correct sequence of increasing covalent character is represented by

Answer»

`LiClltNaClltBeCl_(2)`
`BeCl_(2)ltLiClltNaCl`
`NaClltLiClltBeCl_(2)`
`BeCl_(2)ltNaClltLiCl`

SOLUTION :As DIFFERENCE in electronegativity increases, the % ionic character increase and COVALENT character decreases. Electronegativities of LI, Na and Be are 1.0, 0.9, 1.5 and of Cl is 3.0.
Discussion
31419.

The correct sequence in decreasing order of the precentage of nitrogen in the given compounds is

Answer»

Urea GT AMMONIUM chloride gt ammonium nitrate gt Ammonium nitrite
Urea gt Ammonium nitrite gt Ammonium nitrate gtAmmonium chloride
Urea gt Ammonium nitrite gt Ammonium nitrate gt Ammonium chloride
Urea gt Ammonium nitrite gt Ammonium chloride gt ammonium nitrate

SOLUTION :Correct SEQUENCE is
`NH_(2) CONH_(2) gt NH_(4)NO_(2) gt NH_(4)NO_(2) gt NH_(4)Cl`
Discussion
31420.

The correct sequence for activationg power of a group in benzene is

Answer»

`-NH_(2) GT - NHCOCH_(3) gt -CH_(3)`
`-NH_(2) lt -NHCOCH_(3) lt -CH_(3)`
`-NH_(2) gt -NHCOCH_(3) lt -CH_(3)`
`-NH_(2) lt - NHCOCH_(3) gt -CH_(3)`

ANSWER :A
Discussion
31421.

The correct resonance strucuture(s) of p - nitrophenoxide is

Answer»




SOLUTION :
B, C are not RESONATING STRUCTURES
Discussion
31422.

The correct representation of single carbene is

Answer»



both a and b

Answer :A
Discussion
31423.

The correct representation of Nernst equation is

Answer»

`E_(M^(n+)//M)=E_(M^(n+)//M)^(o)+(0.0591)/(n)LOG(M^(n+))`
`E_(M^(n+)//M)=E_(M^(n+)//M)^(@)-(0.0591)/(n)log(M^(n+))`
`E_(M^(n+)//M)=E_(M^(n+)//M)^(o)+(n)/(0.0591)log(M^(n+))`
none of these

Solution :`E=E^(o)-(RT)/(NF)ln(1)/([M^(n+)]),E=E^(o)+(RT)/(nF)ln[M^(n+)]`
`E=E^(o)+(2.303RT)/(nF)log[M^(n+)]`
Substituting the value of R,T (298K) and F we get
`E=E^(o)+(0.0591)/(n)log(M^(n+))`.
Discussion
31424.

The correct representation for solubility product of SnS_(2) is

Answer»

`[SN^(4+)] [S^(2-)]^(2)`
`[Sn^(2+)] [S^(2-)]^(2)`
`[Sn^(2+)][2S^(2-)]`
`[Sn^(4+)][2S^(2-)]^(2)`

SOLUTION :`SnS_(2) HARR Sn^(4+) + 2S^(2-)`
`:. K_(sp) = [Sn^(4+)] [S^(2-)]^(2)`.
Discussion
31425.

The correct relative rate of reaction of the given alkenes for any given electrophiles is

Answer»

I GT IIGT IV gt III
II gt III gt IV gt I
II gt IV gt III gt I
IV gt I gt III gt II

Answer :B
Discussion
31426.

The correct representation for solubility product of SnS_2 is :

Answer»

`[SN^(4+)] [S^(2-)]^2`
`[Sn^(4+)] [S^(2-)]`
`[Sn^(4+)] [2S^(2-)]`
`[Sn^(4+)] [2S^(2-)]^2`

ANSWER :A
Discussion
31427.

The correct relationship between the boilingpoints of very dilute solution of AlCl_3(t_1) and CaCl_2(t_2), having the same molar concentration , as :

Answer»

`t_1 = t_2`
`t_1 GT t_2`
`t_2 gt t_1`
`t_2 GE t_1`

ANSWER :B
Discussion
31428.

The correct relationships among the following are :

Answer»

`E_("cell") = (RT)/(nF)InF`
Cell CONSTANT `(G^*)` = Conductivity (K) `XX` Resistance (R)
`1 S m^(-1) = 100 S CM^(-1)`
Equilibrium constant `(K)=E^(-DeltaG^@//RT)`

Solution :`(B,d)`
Discussion
31429.

The correct relationship between molarity (M) and molality (m) is ( d = density of the solution, in "kg L"^(-1),M_(2)= molar mass of the solute in "kg mol"^(-1))

Answer»

`M=(MD)/(1+nM_(2))`
`M=(m)/(1+mM_(2)d)`
`M=(1+mM_(2))/(md)`
`M=(1+md)/(mM_(2))`

Solution :Molarity M means M MOLES of the SOLUTE are present in 1 L of the solution. If density of the solution is d kg `L^(-1)`, mass of solution = d kg.
Mass of solute =`MM_(2)` kg (`M_(2)` = molar mass of the solute in kg `"mol"^(-1)`). Hence, mass of solvent
`=(d-MM_(2))kg`
`therefore"MOLALITY (m)"=(M)/(d-MM_(2))`
`"or"m(d-MM_(2))=M"or"md-mMM_(2)=M`
`"orM"(1+mM_(2))=md "or"M=(md)/(1+mM_(2))`
Discussion
31430.

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant K_c is

Answer»

`DELTA G = RT LN K_c`
`Delta G = -RT ln K_c`
`Delta G^@ = RT ln K_c`
`Delta G^@ = -RT ln K_c`

SOLUTION :`Delta G^@ = -RT ln K_c`
Discussion
31431.

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant K_(c) is

Answer»

`DELTAG=RTlnK_(C)`
`-DeltaG=RTlnK_(c)`
`DeltaG^(@)=RTlnK_(c)`
`-DeltaG^(@)=RTlnK_(c)`

ANSWER :D
Discussion
31432.

The correct relationship betweenfree energychange in a reaction and the correspondingequilibrium constantK is

Answer»

`-DELTAG^(@)= RT LN K`
`DeltaG= RT ln K`
`-DeltaG= RT ln K`
`DeltaG^(@)= RT ln K`

SOLUTION :`DeltaG^(@) = - RT In K `
Discussion
31433.

The correct relation for hydrolysis constant of NH_4CN is :

Answer»

`SQRT(K_w/K_a)`
`K_w/(K_a XX K_b)`
`sqrt(K_H)/C`
`K_a/K_b`

ANSWER :B
Discussion
31434.

The correct relation between hydrolysis constant (K_(b)) and degree of hydrolysis (alpha) for the following equilibrium is

Answer»

`alpha = sqrt((K_(W).C)/(K_(a)))`
`alpha= sqrt((K_(w))/(K_(a).C))`
`alpha = sqrt((K_(a).C)/(K_(w))`
`alpha = sqrt((K_(a))/(K_(w).C))`

SOLUTION :Salt of weak ACID and strong BASE.
`K_(h) = (K_(w))/(K_(a))`
`h = sqrt((K_(h))/(c))`
`h = sqrt((K_(w))/(K_(a)c))`
Discussion
31435.

The correct relation between compound(s) I and II is/are

Answer»

identical.
Diastereomers
enantiomers
configurational isomers

Answer :C::D
Discussion
31436.

The correct relation between equilibrium constant (K), standard free energy (DeltaG^(@)) and temperature (T) is

Answer»

`DELTAG^(@)=RT LNK`
`K=e^(-DeltaG^(@)//2.303 RT)`
`DeltaG^(@)=-RTlog_(10)K`
`K=10^(-DeltaG^(@)//2.303RT)`

Answer :D
Discussion
31437.

The correct realtionship between free energy change in a reaction and the corresponding equilibrium constant K_(C)is

Answer»

`DeltaG^(@) = RT LN K_(C)`
`DeltaG^(@) = -RT ln K_(C)`
`DeltaG= RT ln K_(C)`
`DELTA = - RT ln _(C)`
Discussion
31438.

The correct reactivity order with the nucleophile is :

Answer»

`CH_(3)COClgtCH_(3)CONH_(2)gtCH_(3)COOCH_(3)`
`CH_(3)COClgtCH_(3)COOCH_(3)gtCH_(3)COONH_(2)`
`CH_(3)CONH_(2)gtCH_(3)COOCH_(3)gtCH_(3)COCl`
`CH_(3)COOCH_(3)gtCH_(3)COClgtCH_(3)CONH_(2)`

Answer :B
Discussion
31439.

The correct reaction between elevation of boiling point and molar of solute is

Answer»

`M_(2) = (K_(b).W_(2))/(DeltaT_(b).W_(1))`
`M_(2) = (K_(b). W_(1))/(DeltaT_(b). W_(2))`
`M_(2) = (DeltaT_(b). K_(b))/(W_(1).W_(2))`
`M_(2) = (DeltaT_(b). W_(1))/(K_(b). W_(2))`

SOLUTION :`DeltaT_(b) = (K_(b) xx W_(2))/(W_(1) xx M_(2))`
HENCE, `M_(2) = (K_(b) xx W_(2))/(DeltaT_(b) xx W_(1))`
Discussion
31440.

The correct reaction for Hofmann mustard oil reaction is

Answer»

`RNH_2 + COCl_2 to ` RNHCONHR + 2HCl

`R NH_2 + S = C =S overset"Warm"toR NH-undersetundersetS(||)C-SH undersetDeltaoverset(HgCl_2)to R-N=C=S`
NONE of the above

Solution :MUSTARD OIL reaction is `RNH_2 + S = C =S overset(DELTA)to R NH-undersetundersetS(||)C-SH overset(HgCl_2)to underset"Alkyl isothiocyanate"(R-N=C=S)+HGS + 2HCl`
Discussion
31441.

The correct products of the following reactions

Answer»




SOLUTION :With excess of CONC. HI iodide are FORMED form ETHER or alcohol but nuclear OH is not replaced by I.
Discussion
31442.

The correct plots among the following are

Answer»




SOLUTION :All except (d) are CORRECT . For 2ND order REACTIONS `t_(1//2) PROP (1)/(["conc."])`
Discussion
31443.

The correct oxidation state of sulphur atoms in H_(2)S_(2)O_(3) is / are

Answer»

`+6, -2`
`+4, -2`
`+2, +4`
`+5, -1`

Solution :`H_(2)S_(2)O_(3)=HO-UNDERSET(O)underset(||)overset(O)overset(||)S-OH, T=-2, C=+6, AV+2`
Discussion
31444.

The correct orders of reactivity tow ards S_N1 reaction is

Answer»

`I gt II gt III`
`II gt III gt I`
`III gt II gt I`
`I gt III gt II`

Solution :Carbocation at bridge HEAD POSITION is very UNSTABLE.
Discussion
31445.

The correct orderof decreasing secondionization enthalpy of Ti(22),V(23), Cr(24)and Mn(25) is

Answer»

`Cr gt Mn gt V gt TI`
`V gt Mngt Cr gt Ti`
`Mn gt Cr gt TigtV`
`Ti gt V gtCr gt Mn`

Solution :Electronic configuration of the givenelements are`Ti=[Ar]^(18)3d^(2) 4S^(2) ,V= [Ar]3d^(3) 4s^(2) `,
`Cr= [Ar]^(18) 3d^(5) 4s^(1) ,Mn= [ Ar]^(18) 3d^(5) 4s^(2)`.
Their effective nuclear charges increase from Ti to Mn, THEREFORE, their 1ST ionization enthalpies increase in the same ORDER, i.e., `Mn gt Cr gt V gt Ti`. However,after the removalof 1st electron,Cr acquiresstable`3d^(5)` configuration. Hence,it shows exceptional behaviour and has very high 2nd ionization enthalpy. For the remaining elements, the trend remains the same.Thus, 2nd ionization enthalpies will be in the order `:`
`Cr gt Mn gt V gt Ti`.
Discussion
31446.

The correct order towards bond length is

Answer»

`C-C LT C =C lt C` `-=``C`
`C-=C`` lt C = C lt C -C`
`C= C lt C` `-=` `C lt C -C`
`C = C lt C -C lt C` `-=` `C`

SOLUTION :`UNDERSET"1.20 Å"(C-=C)lt underset"1.34 Å"(C=C)lt underset"1.54 Å"(C-C)`
Discussion
31447.

The correct order to decreasing acidic strength of oxyacids of group 15 is:

Answer»

`HNO_3 GT H_3SbO_4 gt H_3AsO_4 gt H_3SbO_4 gt HNO_3`
`H_3PO_4 gtH_3AsO_4 gt H_3SbO_4 gt HNO_3`
`HNO_3 gt H_3PO_4 gt H_3AsO_4 gt H_3SbO_4`
`HNO_3gtH_3AsO_4 gt H_3PO_4 gt H_3SbO_4`

ANSWER :C
Discussion
31448.

The correct order/s for the given pair of isomers is /are

Answer»




ANSWER :B::D
Discussion
31449.

The correct order/s for the given pair of isomers is

Answer»




ANSWER :D
Discussion
31450.

The correct order regarding the solubility of alkaline earth metals halides in water is:

Answer»

`BaCl_2 GT MgCl_2 gt CaCl_2 gt SrCl_2 gt BeCl_2`
`MgCl_2 gt CaCl_2 gt BeCl_2 gt BaCl_2 gt SrCl_2`
`BaCl_2 gt MgCl_2 gt CaCl_2 gt BeCl_2 gt SrCl_2`
`BeCl_2 gt MgCl_2 gt CaCl_2 gt SrCl_2 gt BaCl_2`

ANSWER :D
Discussion