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31301.

The correct statement(s) of Charles's law is (are),

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pressure remaining constant, all gases expand (or contract) by the same fraction of its volume at `0^(@)C` for `1^(@)` rise (or fall) in TEMPERATURE.
The volume of a GIVEN amount of any gas at constant pressure increases LINEARLY with temperature at any scale, i.e., `""^(@)CorK`.
In the plot V VS T at constant pressure, a straight line of positive slope is obtained. This line passes through the ORIGIN only if the temperature is in the Kelvin scale.
For any number of gases of the same volume and at the same temperature, the slopes of the above plot ( c) would be same for all these gas samples.

Answer :A::B::C::D
31302.

The correct statement(s) pertaining to the adsorption of a gas on a solid surface is (are) :

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Adsorption is always exothermic.
Physisorption may TRANSFORM into chemisorption at high TEMPERATURE.
Physisorption increases with increasing temperature but chemisorption decreases with increasing temperature.
Chemisorption is more exothermic than physisorption, HOWEVER it is very SLOW due to higher energy of activation.

ANSWER :A::B::D
31303.

The correct statement(s) is/are

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The `PF_(4)^(-)` ION exists
The `NF_(4)^(-)` ion does not exist
N can FORM `p PI - p pi` bonds with itself and with other elements having small size and high E.N.
The catenation tendency is weaker in N than P

Answer :A::B::C::D
31304.

What happen when CaO reacts with P_4O_10 :-

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31305.

The correct statements is/are

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CSCL CRYSTAL likely to show Schottky defect
CsCl crystal likely to show Frenkel defect
PHOTOSENSITIVITY of AgBr is due to the PRESENCE of Frenkel defect in it.
Crystals having F - centres are coloured and paramagnetic

Answer :A::C::D
31306.

The correct statement(s) is /are

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Thermal stability of alkaline earth METAL chloride decrease with increasing molecular mass but reverseorder is true for their MELTING point.
Thermal stability of boron halides increase with decreasing molecular mass but reverse order is true for their melting point
Thermal stability of beryllium halides increase with decreasing molecular mass and same order is ALSO true for their melting point
Thermal stability ofhydra ACIDS of halogens increase with decreasing molecular mass and same order is also true for their melting point

Solution :`(d)IMPLIES` Thermal stability of Hydra acids `HFgtHClgtHBrgtHIimplies` Melting poinr `:HigtHFgtHBrgtHCl`
31307.

The correct statement(s) from among the following is/are i) All the d and f-block elements are metals ii) All the d and f-block elements form coloured ions iii) All the d and f-block elements form paramagnetic ions

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i only
i and II
ii and III
i, ii and iii

Answer :A
31308.

The correct statement(s) is /are :

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Boiling point of m-hydroxybenzaldehyde is greater than o-hydroxybenzaldehyde
Boiling point of `CHCl_(3)` is HIGHER than `CCl_(4)`
Melting point `BeCl_(2)` is higher than `BeF_(2)`
Boiling point HF is greater than `CH_(3)F`

SOLUTION :[melting point of a covalent compound having BOND between metal and non-metal]`prop(1)/("polarizatio")`
Hence, metling point of `BeF_(2)gtBeCl_(2)`
31309.

The correct statements from the following about physical adsorption I) desorption of adsorbate gas from adsorbent is not easy since chemical forces are involved II) Its energy of activation is very low. III)Easily liquifiable gases are more readily adsorbed.

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all are CORRECT 
only (II) and (III
only (I) and (III) 
only I and II 

ANSWER :B
31310.

The correct statement(s) for the following addition reactions is (are):

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(M and O) and (N and P) are two pairs of diastereomers
Bromination PROCEEDS through trans-addition in both the REACTIONS
O and P are identical molecules
(M and O) and (N and P) are two pairs of enantiomers

SOLUTION :N//A
31311.

The correct statement(s) for cubic-closed packed (c.c.p.) three dimensional structure is (are)-

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the number of nearest NEIGHBOURS of an ATOM present in the topmost layer is 12.
the packing efficiency of atom is 74%.
the number of octahedral and tetrahedral voids PER atom are 1 and 2 respectively.
the unit cell edge length is 2V2~ TIMES the radius of the atom.

Answer :B::C::D
31312.

The correct statement(s) for the following addition reactions is (are): .

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(M and O) and (N and P) ar two pairs of enantiomers
Bromination PROCEEDS through TRANS-addition in both the reaction
O and P are identical MOLECULES.
(M and O) and (N and P) are two pairs of diastereomers.

Solution :
(b). Bromination proceeds VIA trans via trans additon in both the cases.
(d). M & N and O & P are two pairs of DIASTEREOMER.
31313.

The correct statements are :

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If (X) is PhCH=O, then (Z) is ALSO PhCH=O
If (x) is PhCH=O, then (y) is also Ph-CH=CH-CH=CH-COOH

x can be `CH_3-CH=O`

SOLUTION :
31314.

The correct statements are :

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Q and T are homologues.

Solution :
31315.

The correct statements are-

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racemic MIXTURE is an equimolecular mixture of a pair of enantiomers
configuration of a molecule means stable three - dimensional arrangement of the groups ATTACHED to a SPECIFIC ATOM of the molecule
melting & boiling points of 2 enantiomers are diferent
a molecule may be optically active or inactive if more than one asymmetric carbon is present in the molecule

Answer :A::B::D
31316.

The correct statements among the following are

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The POTENTIAL of metallic ELECTRODE INCREASES with increase in concentration of metal ions
The potential of metallic electrode decreases with increase in concentration of metal ions
The potential of non-metallic electrode increases with increase in concentration of non-metalions
The potential of non-metallic electrode decreases with increase in concentration of non-metal ions

Solution :`E_("Met") = E^(0) + (0.0591)/(n) log(M^(+n)) , E_(N.M) = E^(0) -(0.0591)/(n) log[X^(-4)]`
31317.

The CORRECT statements about the structure of H_(2)O_(2),O_(2)F_(2) and OF_(2) is /are

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`H_(2)O_(2),O_(2)F_(2),OF_(2)` are polar COMPOUND
`d_(O-O)` of `H_(2)O_(2) GT d_(O-O) ` of `O_(2)F_(2)`
`d_(O-F) ` of `OF_(2) gt d_(O-F) ` of `O_(2)F_(2)`

ANSWER :A
31318.

The correct statement(s) about the following sugars X and Y is (are)

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X is a reducing SUGAR and Y is a non-reducing sugar
X is a non-reducing sugar and Y is a reducing sugar
The glucosidic LINKAGE in X and Y are `ALPHA` and `beta` respectively.
The glucosidic linkages in X and Y are `beta` and `alpha`, respectively.

Answer :B::C
31319.

The correct statement(s) about the following Cumene (C_(9)H_(12))underset((ii)" "H_(3)O^(+))overset((i)" "O_(2))to P underset(NaOH)overset(CHCl_(3)//)toNaOHunderset(("Major"))(Q)+underset(("Minor"))(R)Qunderset(PhhCH_(2)Br)overset(NaOH)toS

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R is steamm VOLATILE
Q gives DARK violet colouration with 1% aqueous `FeCl_(3)` solution
S gives yellow precipitate with 2,4-dinitrophenylhydrazine
S gives dark violet colouration with 1% aqueous `FeCl_(3)` solution.

Solution :
Q being alcohol gives dark violet colouration with 1% aq. `FeCl_(3)` soln. R is not steam volatile S being an ALDEHYDE gives yellow ppt. of 2,4-DNP thus, option (B) and (c) are correct.
31320.

The correct statements about the following reaction sequence is/are

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R' gives an aldol condensation reaction on heating with NaOH solution
The compound 'Q' gives a yellow precipitate in acetone
Step '4' is an AROMATIC NUCLEOPHILIC substitution reaction
The end product is a mixture of three compounds

Solution :
31321.

The correct statement(s) about the following reaction sequence is (are)

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Solution :
(a) `p`-hydroxy benzaldehyde is (R) not steam volatile because its boiling POINT is high
(b) Due to the presence of PHENOLIC GROUP, compound (Q) gives dark violet colouration with 1% aqueous `FeCl_(3)`solution
(c ) Compound (S) gives a yellow precipitate with `2, 4`-dinitroprhenyl hydrazine since it has an aldehydic group present
(d) Compound (S) FAILS to be responsible to `FeCl_(3)` test since it has no phenolic group present. Thus both (b) and (c ) are correct options
31322.

The correct statement(s) about the compound H_(3)C(HO)HC-CH=CH-CH(OH)CH_(3)(X) is (are):

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the TOTAL NUMBER of stereoisomers possible for (X) is 6
the total number of diastereomers possible for (X) is 3
if the stereochemistry about the DOUBLE bond in (X) is TRANS, the number of enantiomers possible for (x) is 4.
if the stereochemistyr about the double bond in (X) is cis, the number of enantiomers possible for (X) is 2 .

Answer :B::C::D
31323.

The correct statement(s) about the compound given below is (are):

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the compound is optically active
the compound possesses centre of symmetry
the compoud possesses plane of symmetry
The compound possesses axis of symmetry.

Solution :
The compound is optically is optically active and has also axis of symmetry. An axis of symmetry is an axis about which the molecule can be rotated by `360^(@)` through a certain ANGLE and produces an indistinguishable FORM compared with the original molecule. the ORGANIC COMPOUNDS with ais of symmetry are optically active in nature. in this, case the rotation. about `180^(@)` gives the indistinguishable form as shown in the figure.
31324.

The correct statement(s) about Cr^(2+) and Mn^(3+) is(are) [Atomic number of Cr=24 and Mn=25]

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`CR^(2+)` is a reducing agent
`Mn^(3+)` is an oxidizing agent
Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)` ELECTRONIC configuration
When `Cr^(2+)` is USED as a reducing agent, the chromium ion attains `d^(5)` electronic configuration

Solution :`Cr^(2+)+Mn^(3+)HARR Cr^(3+)+Mn^(2+)`
`Cr^(2+)` is reducing agent `Mn^(3+)` is an OXIDISING agent both `Cr^(2+)` & `Mn^(3+)` exhibit `d^(4)` electronic configuration.
31325.

The correct statements about adsorption are

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the chemisorption of `H_(2)` as H atoms on the SURFACE of GLASS is endothermic
PHYSICAL adsorption does not REQUIRE activation energy
chemisorption is always unimolecular
in adsorption, only solute from the solution is adsorbed on the surface of the SOLID adsorbent.

Solution :Solvent from the solution may be adsorbed on the adsorbent (negative adsorption).
31326.

The correct statement with respect to the complexes Ni(CO)_(4) and [Ni(CN)_(4)]^(2-) is

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nickel is in the same OXIDATION STATE in both
both have tetrahedral geometry
both have SQUARE planar geometry
have tetrahedral and square planar geometry respectively

Solution :`Ni(CO)_(4)rarrsp^(3)` hybridisation `rarr` tetrahedral.
`[Ni(CN)_(4)]^(2-)rarrdsp^(2)` hybridisation `rarr` square planar.
31327.

The correct statement with respect to product Y is

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It gives a POSITIVE Tollens TEST and is a FUNCTIONAL isomer of X.
It gives a positive Tollens test and is a geometrical isomer of X.
It gives a positive iodoform test and is a functional isomer of X.
It gives a positive iodoform test and is a geometrical isomer of X.

Answer :C
31328.

The correct statement with regard to H_(2)^(+) and H_(2)^(-) is

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Both `H_(2)^(+)` and `H_(2)^(-)` do not EXIST
`H_(2)^(-)` is more stable than `H_(2)^(+)`
`H_(2)^(+)` is more stable than `H_(2)^(-)`
Both `H_(2)^(+)` and `H_(2)^(-)` are equally stable

Solution :`H_(2)^(+): (sigma1s^(-1)), BB.O. =(1)/(2)(1-0)=(1)/(2)`
`H_(2)^(-) : (sigma1s^(2))( SIGMA^( * *) 1s^(1)) , B.O=(1)/(2) (2-1) =(1)/(2)`
Even though the bond order of `H_(2)^(+) and H_(2)^(-)` are equal but `H_(2)^(+)` is more stable than `H_(2)^(-)` as in the latter, an electron is present in the antibonding `(sigma ^(* *) 1s)` orbital of higher energy
31329.

The correct statement with regard to H_(2)^(+) and H_(2)^(-) is :

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both `H_(2)^(+)` and `H_(2)^(-)` do not exist
`H_(2)^(-)` is more stabel than `H_(2)^(+)`
`H_(2)^(+)` is more stable than `H_(2)^(-)`
both `H_(2)^(+)` and `H_(2)^(-)` are equally stable

Solution :`H_(2)^(+),(SIGMA 1 s^(1))`
`:.B.O.=1/2(1-0)=1/2`
`H_(2)^(-):(sigma 1s^(2))(sigma^(***)1s^(1))`
`:.B.O.=1/2(2-1)=1/2`
EVEN THOUGH the bond ordr of `H_(2)^(+)` and `H_(2)^(-)` areequal but `H_(2)^(+)` is more stable than `H_(2)^(-)`are equal but `H_(2)^(+)` is more stable than `H_(2)^(-)` as in th LATTER, an electron is present in the higher energy antibonding `(sigma^(***)1s)` orbital.
31330.

The correct statement/statements is/are:

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The distance between two octahedral voids of a cubic close packing of atoms with radius `r` is `2r`
The distance between two tetrahedral voids of a cubic close packing of atoms with radius `r` is `sqrt(6)xxr` at the body diagonal axes
The distance between tetrahedral and octehedral void is `sqrt(3/2)xxr`, where is the radius of ATOM FORMING the close packing
The distance between the surface of atoms `FCC` ARRANGEMENT ALONG an edge is `2(sqrt(2)-1)r`

Solution :abcd
31331.

The correct statement (s) regarding, (i) HClO. (ii) HClO_(2), (iii) HClO_(3) and (iv) HClO_(4), is (are)

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The number of `CL = O` bonds in (II) and (iii) TOGETHER is two
The number of lone pairs of electrons on Cl in (ii) and (iii) together is three
The hybridization of Cl in (iv) is `sp^(2)`
Amongst (i) to (iv), the strongest acid is (i)

Solution :
31332.

The correct statement (s) is/are with respect to chromy chloride test

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Formation of lead CHROMATE
Formation of chromyl chloridechromate
LIBERATION of chloride
Formation of REDDISH -brown vapours

Answer :a,B,d
31333.

The correct statement (s) is/are

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generally the CALCINATION and roasting is done in Blast furnace
the SANDY and rocky material associated with ore are called matrix.
froath FLOATATION process is suitable for SULPHIDE ores.
Substance that reacts with ganue f to from fusible mass is called slag.

Answer :B::C
31334.

The CORRECT statement (s) is/are:

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In metallurgy of iron, flux is a substance used to convert infusible impurities to fusible MASS.
Cryolite is `Na_(3)AIF_(6)` and is used in the electrolysis of alumina for lowering the melting point of alumina.
Combination of FeO with `SiO_(2)` must be avoided in metallurgy of copper.
Lead can be extracted by SELF REDUCTION of gelena.

Answer :A::B::D
31335.

The correct statement (s) about the oxoacids, HClO_(4) and HClO, is (are)

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the CONJUGATE base of `HClO_(4)` is weaker base than `H_(2)O`
the central atom in both `HClO_(4) and HClO` is `sp^(3)` hybridized
`HClO_(4)` is formed in the reaction between `Cl_(2) and H_(2)O`
`HClO_(4)` is more acidic than HClO because of the resonance stabilization of its ANION

Solution :`Cl_(2)` reacts with `H_(2)` to FORM HCl + HClO. As such it does not GIVE `HClO_(4)` and hence OPTION (c) is wrong. All other options are correct.
31336.

The correct statement (s) from among the following is/are :

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(i) only
(i) and (II)
(ii) and (III)
All

Answer :A
31337.

The correct statement (s) about O_(3) is (are)

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O-O bond length are EQUAL
thermal decomposition of `O_(3)` is ENDOTHERMIC
`O_(3)` is diamagnetic in NATURE
`O_(3)` has a BENT structure

Solution :Thermal decomposition of `O_(3)` is exothermic, i.e., option (B) is wrong.
31338.

The correct statement regarding the racemic mixture is that :

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It is OPTICALLY active
It is dextrorotatory
It is optically inactive
None of these

Answer :C
31339.

The correct statement regarding the transition state of a S_N 2 reaction in alkyl halides

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Lower in energy than the starting materials
Involves both the nucleophile and leaving group
CLOSELY resembles a CARBONIUM ION intermediate
The carbon where substitution takes PLACE is `sp^3` hybridised

Answer :B
31340.

The correct statement regarding the following energy diagrams is

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REACTION M is FASTER and less exothermic than reaction N
reaction M is slower and less exothermic than reaction N
reaction M is faster and more exothermic than reaction N
reaction M is slower and more exothermic than reaction N.

SOLUTION :
`E_a lt E._a`.So,reaction M is faster.
`DeltaH_1 GT DeltaH_2`,so,reaction M is more exothermic.
31341.

The correct statement regarding the following energy diagrams is:

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Reaction M is faster and LESS EXOTHERMIC than reaction N
Reaction M is SLOWER and less exothermic than reaction N
Reactioni M is faster and more exothermic than reaction N
Reaction M is slower and more exothermic than reaction N.

SOLUTION :c) Reaction M is faster and more exothermic than reaction N.
31342.

The correct statement regarding the following compounds is

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all three compounds are chiral
only I and II are chiral
I and III are diastereomers
only I and III are chiral.

Solution :Look at the structures and orientation of GROUPS in 3-D space :

It has no PLANE of symmetry (look at the orientation of -`-CH_(3)` groups), no AXIS of symmetry (rotation through any axis does not generate the indistinguishable structure) or no point of symmctry (which is possible if one side -OH group is represcnted by OH and another side by - OH. Same also for hydrogen.) So, (1) is chiral.

due to the presence of a centre of symmetry, structure (11)is achiral.

Again in this structure, there is no symmetry clement. So, (III) is chiral.
31343.

The correct statement regarding the following compounds :

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all THREE COMPOUNDS are chiral
only I and II are chiral
I and II are diastereomers
only I and III are chiral

Answer :D
31344.

The correct statement regarding the comparison of staggered and eclipsed conformation of ethane, is

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The STAGGERED conformation of ethane is less stable than ECLIPSED conformation, because staggered conformation has TORSIONAL strain
The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has not torsional strain
The eclipsed conformation of ethane is more stable than staggered conformation EVEN through the eclipsed conformation has torsional strain
The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no tosional strain

Solution :
31345.

The correct statement regarding the basiciity of arylamines is

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arylamines are generally more basic than alkylamines because of aryl group
arylamines are generally more basic than alkylamines because the NITROGEN atom in arylamines is sp-hybridised
arylamines are generally LESS basic than alkylamines because the nitrogen lone-pair electrons are delocalised by INTERACTION with the aromatic ring `PI`-ELECTRON system
arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalisedby interaction with the aromatic ring `pi`-electron system.

Solution :Due to nitrogen lone pair of electrons are delocalized by interaction with the aromatic ring `pi`-electrons.
31346.

The correct statement regarding the basicity of arylamines is -

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ARYLAMINES are GENERALLY less basic than alkylamines because the nitrogen lone-pair ELECTRONS are delocalized by interaction with the AROMATIC ring `pi` electron system.
Arylamines are generally more basic thatn alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring `pi` electron system
Arylamines are generally more basic than alkylamines
Arylamines are generally more basic than alkylamines , because the nitrogen atom in arylamines is sp- HYBRIDIZED

Answer :A
31347.

The correct statement regarding the basicity of arylamines is

Answer»

Arylamines are generally more BASIC than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring `pi`-electron system
Arylamines are generally more basic than alkylamines because of aryl group
Arylamines are generally more basic than alkyamines, because the nitrogen ATOM in arylamines is sp-hybridized
Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring `pi`-electron system.

Solution :
Due to delocalisation of lone pair of electrons of N-atom to the BENZENE ring, it losses its basicityt and becomes less basic than alkyl amine.
On the other HAND, alkyl amine has FREE lone pair of electron as well as `+I`-effect of alkyl group increases electron density on N-atom enhancing its basic nature.
31348.

The correct statement regarding RNA and DNA , respectively is

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the sugar COMPONENT in RNA is a arabinose and the sugar component in DNA is ribose
the sugar component in RNA is 2' -dexoyribose and the sugar component in DNA is arabinose
the sugar component in RNA is arabinose and the sugar component in DNA is 2' deoxyribose
ths sugar component in RNA is ribose and the sugar component in DNAIS 2' -deoxyribose.

ANSWER :D
31349.

The correct statementregarding RNAand DNA respectively is ………..

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the sugarcomopnentin RNAis an arabinoseand the sugar componemt in DNA is RIBOSE
the sugarcomponentin RNA is 2 - deoxyriboseand the sugarcomponentin DNAIS arabinose
the sugar componentin RNAis anarabinoseand thesugar componentin DNAis2 - deoxyribose
the sugarcomponent in RNAis ribose and the sugarcomponentin DNAis 2 - deoxyribose

Answer :D
31350.

The correct statement regarding RNA and DNA, respectively is:

Answer»

The sugar component in RNA is RIBOSE and the sugar component in DNA is 2'-DEOXYRIBOSE.
The sugar component in RNA is arabinose and the sugar component in DNA is ribose.
The sugar component in RNA is 2'-deoxyribose and the sugar component in DNA is arabinose.
The sugar component in RNA is arabinose and the sugar component in DNA is 2- deoxyribose.

Solution :The sugar component in RNA is ribose and the sugar component in DNA is 2.-deoxyribose.