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4051.

Which of the following is not true for metal carbonyls

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The oxidation state of the metal in the carbonyls is zero
The secondary carbonyls are obtained from photo-decomposition
Metal carbonyls are SINGLE bonded species
`dpi - p PI` overalp is observed in metal carbonyls

Solution :Metal carbonyls does not show overlapping.
4052.

Which of the following statement is ture ?

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A MIXTURE of ENANTIOMERS can be separated omn the basis of difference in the boiling points (by a mwthod called fractioal distillation ).
A mixture of enantiomers can be separated om the basis of diffenence in the solubility in any solvent
A mixture of enantiomers can be separated by converting then ONTO diastereomers by reacting them an optically active REGENT
A mxture of enantiomers can be separatedby passing polarised through their sloution

Answer :C
4053.

Which among the following is not an aromatic species?

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ANSWER :D
4054.

What is polymer ? What we can say about the molecular mass of polymer ? In which four Industries polymers are mostly used ?

Answer»

Solution :The word .polymer. is coined from two Greek words : poly means many and mer means unit or part.
The term polymer is defined as very large molecules having high molecular mass `(10^(3)-10^(7)u`).
POLYMERS are formed by joining of repeating structural units on a large scale. These are also referred to as MACROMOLECULES.
The polymers are backbone of four MAJOR INDUSTRIES LIKE plastics, elastomers, fibres and paints and varnishes.
4055.

Which form of phosphorus is most stable?

Answer»

RED P
White P
Black P
All are stable

Answer :A
4056.

You are given benzene, cone. H_(2)SO_(4) and NaOH. Write the equations for the preparation of phenol using these reagents.

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SOLUTION :
4057.

The species in which the N-atom is in a state of sp hybridisation is

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`NO_(3)^(-)`
`NO_(2)`
`NO_(3)^(+)`
`NO_(2)^(-)`

Solution :Hybridizatio `(H)=(1)/(2)`. [ no. of valenceelectrons of central +no. of Movement atoms attached to it +(-ve charge if any)- (+ve charge if any)]
`NO_(2)^(+)=(1)/(2)[5+0+0-1]=2`i.e., sp hybridisation
`NO_(2)^(-)=(1)/(2)[5+2+1-0]=3` I.e., `ps^(2)` hybridisation
`NO_(3)^(-)=(1)/(2)[5+0+1-0]=3` i.e., `sp^(2)` hybridisation
The LEWIS STRUCTURE of NO, shows a bent molecular GEOMETRY with trigonal planar electron pair geometry Door hence the hybridization will be `sp^(2)`
4058.

What happens when ammonia reacts with Nessler.s reagent ? Give equations.

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Solution :Nesselr.s reagent is ALKALINE solution of POTASSIUM mercury iodide `K_2[Hg]_4]. AMMONIA gives a BROWN precipitate of the iodide of Millon.s base with Nessler.s reagent.
4059.

Which of the following electrolyte is used for electrorefining of metal M? M gt Z^(-) , X^(-), Y^(-) lt Z^(-), X^(-), gt Z^(-), W^(-), lt X^(-)

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MX
MZ
MY
MW

Answer :A,B,C,D
4060.

Which one of the following molecules will form a linear polymeric structure due to hydrogen bonding?

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`NH_(3)`
`H_(2)O`
`HCL`
`HF`

Solution :HF FORMS linear polymeric structure due to hydrogen bonding
4061.

Which of the following are lewis acids? H_2O,BF_3,H^+ and NH_4^+

Answer»

SOLUTION :`BF_3,H^+` IONS are LEWIS ACIDS.
4062.

Which sulphides are not precipitated in acid or alkaline medium.

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K
Ca
Al
All

Answer :D
4063.

Which isotope of oxygen is used as a tracer in the study of reaction mechanism ?

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SOLUTION :`""^(18)O`
4064.

Which of the following artificial sweeter contains chlorine atoms in its structure ?

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Saccharin
Aspartame
Sucralose
Aliame

Answer :C
4065.

What is the mass in grams of one molecule of caffeine (C_(8)H_(10)N_(4)O_(2))?

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Solution :`"MASS of ONE molecule"=("Molar mass")/("AVOGADRO's No.")=(194)/(6.022xx10^(23))g=3.22xx10^(-22)g`
4066.

What is the potential of a cell containing two hydrogen electrodes the negative one in contact with 10^(-8)M" "H^(+) and positive one in contact with 0.025 M H^(+)

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0.18 V
0.28 V
0.38V
0.48V

Solution :`(1)/(2)H_(2)toH^(+)(10^(-8)M)+E^(-)` (oxidation)
`H^(+)(0.025M)+e^(-)to(1)/(2)H_(2)` (REDUCTION)
Cell REACTION is:
`H^(+)(0.025M)toH^(+)(10^(-8)M),E_(cell)=0.38V`
4067.

Write the namesand structures of the monomersof thefollowingpolymers : (i) Buna-s (ii) Neoprene . (iii) Nylon 6,6

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SOLUTION :The NAMES and STRUCTUREOF themonomersare GIVENBELOW :
4068.

The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)_(6)is

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0
2.84
4.9
5.92

Solution :Chromium in `Cr(CO)_(6)` is in zero OXIDATION state and has `[Ar]^(18)3d^(5)4s^(1)` as the ELECTRONIC CONFIGURATION. However, CO is a strong ligand, HENCE pairing up of electrons takes place leading to following configuration in `Cr(CO)_(6)`.

Since the complex has o unpaired electron, its magnetic moment is zero.
4069.

Whichof the followingis not an isomerofC_(4) H_(6)

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2-buyne
1-Butyne
2-Methyl -1- propene
1,3- BUTADIENE

ANSWER :C
4070.

Which one of the following compounds does not respond to the haloform reaction-

Answer»

`CH_(3)CH_(2)CHOHCH_(3)`
`CH_(3)CH_(2)CH_(2)COCH_(3)`
`CH_(3)COCH_(2)COOC_(2)H_(5)`
`CH_(3)COC_(6)H_(5)`

ANSWER :C
4071.

Which of the following species can act as the strongest base ?

Answer»

`.^(-)OH`
`.^(-)OR`
`.^(-)OC_(6)H_(5)`

SOLUTION :Weakest acid has the strongest CONJUGATE bse. Since ROH is the weakest acid, therefore, `RO^(-)` is the strongest base.
4072.

The SI unit for ionic mobility is

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`cm^(-2) "VOLT"^(-1) sec^(-1)`
`cm^(2) "volt"^(-2) sec^(-1)`
`cm "volt"^(-1) sec^(-1)`
`m^(2) "volt"^(-1) sec^(-1)`

ANSWER :D
4073.

What will be the value of a for a 0.001 M aqueous NH_(3) solution ? [K_(b)=1.6xx 10^(-5) and Lambda_(0)=2.38xx10^(-2) ohm^(-1) m^(2) mol^(-1)]

Answer»


Solution :`K_(b)=Calpha^(2)`
`1.6xx10^(-5)=0.001xxalpha^(2)`
`alpha=0.126`
`alpha=Lambda_(m)^(C)/Lambda_(m)^(oo),`
(`Lambda_(m)^(c)=` MOLAR conductance at concentration 'c' and `Lambda_(m)^(oo)=` molar conductance at infinite DILUTION)
`0.126=Lambda_(m)^(c)/(2.38xx10^(-2))`
`Lambda_(m)^(c)=2.998xx10^(-3) ohm^(-1) cm^(2) mol^(-1)`
4074.

Which of the following hydride is ionic ?

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`H_(2) O`
`NH_(3)`
`CaH_(2)`
`H_(2)S`

SOLUTION :METALIC hydrides are ionic while non METALLIC hydrides are covalent.
4075.

What are promoters? Explain with example.

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Solution :(i) In a CATALYSED reaction, the presence of a certain SUBSTANCE increases the activity of a catalyst. Such substance is called a PROMOTER.
(II) For example, in Haber.s process of manufacture of ammonia, the activity of the iron catalyst is increased by the presence of molybdenum.Hence molybdenum is called in promoter.
`N_(2(g))+3H_(2(g))overset(Fe//Mo)rarr 2NH_(3(g))""{:("Fe - catalyst"),("Mo - promoter"):}`
4076.

When the following aldohexose exists in Pyranose from, the total number of stereoisomers in its pyranose form is

Answer»


ANSWER :16
4077.

Which one of the following statement is false for nickel-dimethyglyoximate complex ?

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The stability of complex is only due to the PRESENCE of intra-molecular hydrogen bonding.
The complex is stable because tridentate DIMETHYL glyoxime LIGAND FORMS a five membered chelate rings.
The complex is stable as it has five membered chelate rings as WELL as intra molecular hydrogen bonding.
(a) and (b) both.

Solution :Stability is more due to chelate effect.
4078.

What are soaps ? What are hard and soft soaps ? Give the limitations of soaps ?

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SOLUTION :SOAPS . Soaps are sodium and potassium salts of higher fatty ACIDS.
Hard SOAP. These are sodium salts of higher fatty acids.
Soft soaps. These are potassium salts of higher fatty acids. Soaps can.t be used as CLEANSING agents in hard water and in acidic medium.
4079.

The treatment of diseases in which parasites are killed and their growth is inhibited by chemical is called ......

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allopathy
CHEMOTHERAPY
yuna's METHOD
natural method 

SOLUTION :Chemotherapy
4080.

Which of the following is incorrect order of property as indicated ?

Answer»

`Na^(+) lt F^(-) lt O^(2-) lt Ne lt AR`: Atomic size
`Br lt Se lt As lt Ge`:Metallic character
`Na lt Al lt SI lt Mg`:Ionisation energy
`I lt Br lt Cl lt F`:ELECTRON affinity

Solution :Correct ORDER is:
(B) `Ge gt Se gt As gt Br`: metallic character
(c) `si gt Mg gt Al gt Na`: Ionisation energy
(d) `Cl gt F gt Br gt I`: electron affinity
4081.

Which is not a reducing sugar :

Answer»

Fructose
Glucose
Lactose
Sucrose

Answer :D
4082.

The 'Z' isomer among the following is:

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ANSWER :C
4083.

Why cationic detergents are limited in use them anionic detergents ?

Answer»

SOLUTION :CATIONIC DETERGENTS are more EXPENSIVE than ANIONIC detergents.
4084.

Which of the following can exhibit geometrical isomerism?

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TETRAHEDRAL - `[Zn(NH_3)_2Cl_2]`
Square planar - `[Pt(NH_3)_2Cl_2]`
Octahedral - `[Co(NH_3)_5Cl]^(2+)`
Linear - `[Cu(CN)_2]^(+)`

Answer :B
4085.

Which of the following compounds are optically inactive due to internal compensation?

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2,3 - pentanediol
1,2-propanediol
2,3-butanediol
3,4,5-tribromoheptane

SOLUTION :(C,d) : COMPOUNDS (c) and (d) CONTAIN PLANE ofsymmetry.
4086.

What is the correct Nernst formula of calculate potential of reaction Zn_((aq))^(2+)+2e^(-) to Zn_((S))

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`E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(THETA)-(0.059)/(2)LOG[Zn_((aq))^(2+)]`
`E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log"(1)/([Zn_((aq))^(2+)])`
`E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(2)log[Zn_((aq))^(2+)]`
`E_(Zn^(2+)|Zn)=E_(Zu^(2+)|Zn)^(Theta)+(0.059)/(2)"log"(1)/([Zn_((aq))^(2+)])`

Solution :`Zn_((aq))^(2+)+2E^(-) to Zn_((S))`
Where, Reactants=`[Zn_((aq))^(2+)],` Product=[Zn]
`therefore "log "K_(c)=(["Product"])/(["Reactant"])=([Zn_((S))])/([Zn_((aq))^(2+)])=(1)/([Zn^(2+)])`
`therefore E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)"log"(1)/([Zn_((aq))^(2+)])`
Or `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(2)log[Zn^(2+)]`
4087.

Which is formed when SiCl_4 vapours are passed over hot Mg?

Answer»

`SiCl_2 + MgCl_2`
`SI + MgCl_2`
`Mg_2Si+Cl_2`
`MgSiCl_6`

ANSWER :B
4088.

The Zn acts as sacrificial or cathodic protection to prevent rusting of iron because

Answer»

E_(op) of ZN = E_(op) of Fe`
`E_(op) of Zn gt E_(op) of Fe`
`E_(op) of Zn LT E_(op) of Fe`
Zn dose MOT REACT with water

Answer :B
4089.

Trans-1-chlroropene has higher dipole moment than cis-1-chloropropene. (R) The resultant of the two vectors in trans-1-chloro propene is more than in cis-1-chloropropene.

Answer»


ANSWER :A
4090.

Zwitter ion is formed by

Answer»

aniline
acetanilide
BENZOIC acid
GLYCINE

Solution :Zwitter ion is FORMED by AMINO acid. Glycine is amino acid. Zwitter ion of glycine is `overset+NH_3 -CH_2 - COO^-`
4091.

Which of the following statements is not true about NaCl struture ?

Answer»

Mg
Zinc
Copper
LITHIUM

Solution :Lithium is BODY CENTRED CUBIC.
4092.

What are emulsion ? What are their different types ? Give example of each type.

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Solution :Liquid-liquid COLLOIDAL systems in which finely divided of a liquid are dispersed into other liquid, are CALLED emulsions. These are formed by shaking the two immiscible liquids with each other.
Type of Emulsions
Oil dispersed in water (O/W type) e.g., MILK, VANISHING cream, etc.
Water dispersed in oil (W/O type) e.g., butter, COLD cream etc.
4093.

Which one of the following is named collodion?

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4% solution of nitro cellulose in a MIXTURE of ALCOHOL and WATER
40% solution of cellulose acetate in acetic acid.
agar-agar ALONG with gel
semipermeable membrane

Solution :4% solution of nitro cellulose in a mixture of alcohol and water
4094.

The vapour pressure of pure water at 25^@C is 30 mm. The vapour pressure of 10% (W/W) glucose solution at 25^@C is

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`31.5mm`
`30.6mm`
`29.67mm`
`26.56mm`

ANSWER :C
4095.

Which of the following is not a Lewis acid

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`BF_(3)`
`FeCl_(3)`
`SiF_(4)`
`C_(2)H_(4)`

Answer :D
4096.

The volume of decamolar aqueous solution of hydrochloric Acid is required to prepare 2dm^(3) of 5M HCl solution is

Answer»

`05L`
`1L`
2L
3L

Answer :B
4097.

Which halogen atom in each compound is more reactive in S_(N)1 reaction? Why? (ii) .

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Solution :In , one iodo group is ATTACHED wiht allylic carbon atom and the other one is attached with NORMAL `sp^(3)` -hybirdised carbon atom. The carbocation formed by the CLEAVAGE of C (allylic) -I bond is STABILISED by resonance. On the other hand, the carbocation formed by the cleavage of C (normal `sp^(3)`-hybridise) -I bond has no such resonance stability. Thus the I atom attached to allylic carbon atom is more reactive in `S_(N)1` reaction.
4098.

The standard entropies of CO_(2)(g),C(s) and O_(2)(g) are 213.5, 5.690 and 205JK^(-1) respectively. The standard entropy of formation of CO_(2)(g) is

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`1.86 JK^(-1)`
`1.96 JK^(-1)`
`2.81 JK^(-1)`
`2.86 JK^(-1)`

Solution :Formation of `CO_(2)` is,
`C_((s))+O_(2(G))rarrCO_(2(g))`
`DeltaS^(@)=213.5-5.690-205=2.81 JK^(-1)`
4099.

Which of the following react with NaHSO_(3)

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`CH_(3)COCH_(3)`
`CH_(3)CHO`
`HCHO`
All of these

Solution :Ketones and ALDEHYDE ADD to `NaHSO_(3)` to give white precipitate
4100.

Which type of hybridization explains that the shape of SF_4 is trigonal bipyramidal ?

Answer»

SOLUTION :`sp^3d.`