InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6551. |
methods of preparation of alkanes |
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| 6552. |
The level of air pollution is higher at a busy trafic intersection. Why |
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Answer» The reason is that a large number of vehicles are stationary for extended periods of time, which makes the smoke and dust accumulate in a higher concentration there. |
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| 6553. |
in the blanks :0 |
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Answer» so1/2*3= 1/6= 1/6*6= 1/361/36*8/38/36*32/27 2/27 is correct... good Answer of this question is 216 |
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| 6554. |
FILL IN THE BLANKSPeat is the_____variety of coal. |
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Answer» Peat organic variety of coalPeat is formed from decaying vegetation, and is considered to be the precursor of coal |
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| 6555. |
i)Whichis not a variety of coal ?(i) Graphite(ii) Peat and lignite(ii) Bituminous(iv) Anthracite |
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Answer» i) Graphite is correct option. Graphite,is a crystalline allotrope of carbon. |
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| 6556. |
CH2 -CH=CHIs ite sight orwrong |
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Answer» It's wrong Correct formula isCH3 - CH = CH2 |
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| 6557. |
The solubility product of AgBr is 4.9 x 10-9, Thesolubility of AgBr will be |
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Answer» solubility product is s² = 4.9×10^-9=> s² = 49×10^-10=> s = √49×10^-10=> s = 7×10^-5 so, solubility is s = 7×10^-5 |
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| 6558. |
Q.3 Give reasons for the following.1.Solubility curves find utility in separation and purification of solutes.Pressuure anmd termnerature inlon |
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Answer» Asolubility curveis a graphical representation of thesolubilityof a particularsolutein a given solvent with respect to varying temperatures. ... Chemists often use the technique of liquid-liquid extraction to identify thesolubilitiesof compounds to separate andpurifythem from reaction mixtures. |
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| 6559. |
structure, isolation and synthesis ofFarnesol and Hirsutidin. |
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Answer» Farnesol is a colorless liquid extracted from oils of plants such as citronella, neroli, cyclamen, and tuberose. It is an intermediate step in the biological synthesis of cholesterol from mevalonic acid in vertebrates. It has a delicate odor and is used in perfumery. |
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| 6560. |
what is geographical isolation |
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Answer» Geographic isolation is a term that refers to a population of animals, plants, or other organisms that are separated from exchanging genetic material with other organisms of the same species. Typically geographic isolation is the result of an accident or coincidence. |
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| 6561. |
वह नुव्म एएललठजरुरूठएसर जरूठ एसनै53=TBH_B S U ¥5का=3 |
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Answer» The rule states that : "when an unsymmetrical alkene reacts with a hydrogen halide to give an alkyl halide, the hydrogen adds to the carbon of the alkene that has the greater number of hydrogen substituents, and the halogen to the carbon of the alkene with the fewer number of hydrogen substituents" |
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| 6562. |
.23 In the experimental setup on CO2 is released during respiration if one forgets to keep the vialwith KOH in the conical flask. How will the result vary? Give details. |
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Answer» The purpose of KOH is to normally absorb the CO2 released during respiration. If they forget to put a conical flask with KOH then the results will vary because the air released will be having CO2 since it was not absorbed as plannned at the beginning of the experiment thus hindering the expected observations. |
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| 6563. |
b] Name the product formed when phenol vapours are passed over heated zidust. Write the chemical equation. |
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Answer» When phenol is heated with zn dust reduction of phenol occurs and it gets converted into Benzene with ZnO as a by-product.Phenol+Zn⟶Benzene+ZnO mechanism; Zn shows an oxidation state of +2. The phenol gets converted into phenoxide ion and proton thus released accepts an electron from Zn forming H radical. Also because of the heating there is homolytic fission of C of phenyl ring and O- The O- thus formed accepts an electron from Zn and forms oxide ion. In this way zinc forms zinc oxide and phenyl radical thus produced forms a bond with H radical. However, the yield of this reaction used for benzene formation is lower. |
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| 6564. |
Name the product formed by the action of chlorine on dry slaked lime ( |
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Answer» when chlorine is passed over dry slaked lime, bleaching powder will form. equation ---: Ca(OH)2 + Cl2 ---> CaOCl2 + H2O. properties --: it is used as an oxidising agent in many chemical industries. it is used for distinfecting drinking water to make it free of germs it is used for bleaching cotton , linen in textile industry. |
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| 6565. |
give reason for the product formed when hexene reacts with Br2 in presence of heat and uv light. |
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Answer» The reaction between hexene and bromine in presence of light gives 3-bromocyclohexene. why it does not show addition reaction |
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| 6566. |
21. Propionic acid is subjected to reduction with hydroiodic acidin the presence of a little P, the product formed is. |
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| 6567. |
Carry out the following ActivityTake about 2 g barium hydroxide in a test tube. Add 1 g of ammonium chloride anwith the help of a glass rod. Touch the bottom of the test tube with your palm. What dfeel? Is this an exothermic or endothermic reaction? |
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Answer» When we mix barium hydroxide with ammonium chloride, the bottom of the test tube becomes cold due to absorption of heat. So, it is an endothermic reaction. This reaction absorbs heat from its environment to be completed, so it is an endothermic reaction. Ba(OH)2+NH4Cl===>BaCl2+NH4OH |
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| 6568. |
A student has set up an apparatus to show that "CO2 is released duringrespiration". After about 1 hour he observes no change in the water levelin the delivery tube. Write two possible reasons for the failure of theexperiment.P.T.C |
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Answer» Respiration in plants can be studied in moist germinating seeds that release carbon dioxide (CO2) during respiration. Potassium hydroxide absorbs carbon dioxide released by the seeds and a partial vacuum is created in the flask as a result. |
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| 6569. |
22 If the speed of light is 3.0 10s m s-1, calculatethedistancecoveredby2.00 ns |
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Answer» thanks |
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| 6570. |
S6. Which of the following hydrocarbon has acidic hydrogen?(b) 2-butende57. I-pentyne can be distinguished from 2-pentyne by using :(a) 1-butene(e) Ethylene (d) 1-propye(b) Grignard reagent(d) Tollens' reagent(a) Bueyer's reagent(c) Wortz reactionThe best suitable catalyst for the dehydrohalogination of sec. butyl bromide i(a) Aqueous KOH(c) KOH58.(b) Alcoholic KOH(d) of these59. Reaction mechanism for the chilorination of alkene involves . as an inter(a) Carbonium ion(b) Chloronium ion |
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Answer» 56. D57. D58. B |
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| 6571. |
What is the product formed when acetylene reacts with hypochlorous acid?(1) CH COOI(2) CICH CHO(3) CL/CHCHO(4) CICH COOH |
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Answer» Answer is (3) Cl2CHCHO |
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| 6572. |
Activation energy of a chemical reaction can(a) determining the rate constant at standardtemperature(b) determining the rate constants at twotemperatures(c) determining probability of collision(a) using catalyst |
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Answer» (b) Activation energy of a chemical reaction is related to rate constant of a reaction at two different temperatures i.e.,K1 and K2 respectively. why a is wrong.thanks but why option a is wrong |
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| 6573. |
The product formed when benezediazonium chloride is treated with CuBr/ HBr is1) Bromobenzene3) 1,3- Dibromobenzene2.2) Cholorobenzene4) 1,4 Dichlorobenzene |
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Answer» bromo benzene. |
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| 6574. |
, ι-D-glucose and β-D-glucose are(a) epimer(c) enantiomer(b) anomer(d) diastereomers. |
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Answer» alpha D glocose and beta D glucose are anomer |
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| 6575. |
Name the end product formed during:1. Oxidation of Glucose in the muscles.II. Oxidation of Glucose in the body cells.III. Breakdown of Glucose anaerobically. |
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Answer» Oxidation of glucose in the body cell |
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| 6576. |
What will be the valency of an element of atomic number 9 (nine)?6 Why does a current arrvconductor exnriences a force wher |
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| 6577. |
If one third of 100 g of 27% aqueous sugar solutionis taken in a beaker and 10 g of sugar is added toit, the concentration of the resulting solution will be |
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| 6578. |
10. 100 ml each 0.5N NaOH, N/5 HCI and N/10 H,SO, are mixed together. The resulting solution will benanidic medium the eauivalent |
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Answer» 100 mL of 0.5 N NaOH, = 0.100 L x 0.5 N = 0.05 equivalent moles 100 mL of N/5 HCL = 0.100 L x 0.2 N = 0.02 equivalent moles 100 mL of N/10 H2SO4 = 0.100 L x 0.1 N = 0.01 equivalent moles 0.02 equivalent moles of HCl will neutralise 0.02 equivalent moles of NaOH And 0.01 equivalent moles of H2SO4 will neutralise 0.01 equivalent moles of NaOH So unreacted equivalent moles of NaOH = 0.05 - (0.02 + 0.01) = 0.02 The resulting solution will be basic containing 0.02 equivalent moles of NaOH = 0.02 / 0.300 L = 0.067 N NaOH |
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| 6579. |
Iron fillings and sulphur were mixed together and divided into two parts A and B. Part A was heatedboth the parts and evolution of gas wasstrongly while part B was not heated. Dil, Hcl was added toseen in both the cases. How will you identify the gases evolved? |
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Answer» When iron mixed with sulphur and heated then it forms Ferrous sulphide (A) which on treatment with dilute HCl produces Ferrous chloride and Hydrogen sulphide gas.FeS + HCl →FeCl₂ + H₂S↑If the mixture is not heated (B) remains as mixture (Fe + S) if it treated with dilute HCl then it produces Hydrogen gas along with Ferrous chloride . Since only iron reacts (Slowly) with HCl.(Fe + S) +2 HCl → FeCl₂ + H₂↑ |
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| 6580. |
The gases evolved in the electrolysis of water are......... and...... |
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Answer» Gases evolved in the electrolysis of water are hydrogen and oxygen h2Omeans hidrogen and oxygen hydrogen and oxygen evolved |
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| 6581. |
51, 154 |
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Answer» Properties of Ozone Ozone absorbs radiation strongly in the ultraviolet region of the atmospheric spectrum between 220-290 nm. This protects the Earth and its inhabitants from the harmful ultraviolet radiation of the Sun. Without this protective layer, more ultraviolet radiation would reach the surface of the Earth and cause damage to plant, animal and human life. Pure ozone is a blue gas, with a strong irritating smell. When inhaled, it causes headache and nausea. In smaller proportions it smells pleasant. It is about 1.5 times heavier than air and has a vapor density of 24, corresponding to the formula O3. It is more soluble than oxygen in water, about 49% by volume at 0°C. It gets liquefied to a deep blue colour liquid, when cooled in liquid air. It boils at 161.2 K and solidifies to violet-black crystals, which melt at 80.6 K. It dissolves readily in turpentine oil and acetic acid. |
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| 6582. |
Calculate the amount of water in grams producby combustion of 16 g methane (CH4)CH, 40,-CO2 +2H2O |
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| 6583. |
A certain positive ion A has 22 neutrons and 18 electrons. What is the mass number of most abundantisotope of A(A) 42(B) 38(C) 40(D) none |
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Answer» 40 is tje correct answer 40 is the correct answer 40 is the right answer 40 is the right answer |
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| 6584. |
9. Equal weights of methane and oxygen aremixed in an empty vessel at 298K. Thefraction of the total pressure exerted bymethane is : |
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Answer» Sol. If x g of both oxygen and methane are mixed then : Mole of oxygen = x/32 Mole of methane = x/16 ⇒ mole fraction of oxygen = (x/32)/(x/32 + x/16) = 1/3 According to law of partial pressure Partial pressure of oxygen (po2) = mole-fraction × total pressure ⇒ 〖Po〗_2/p = 1/3 |
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| 6585. |
Equal weights of CH4 and O2 are mixed in an empty container at 25°C. The fraction of the totalpressure exerted by oxygen is:(C) 2/3(D)2/3 x 273/298 |
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Answer» If x g of both oxygen and methane are mixed then : Mole of oxygen = x/32 Mole of methane = x/16 ⇒ mole fraction of oxygen = (x/32)/(x/32 + x/16) = 1/3 According to law of partial pressure Partial pressure of oxygen (po2) = mole-fraction × total pressure ⇒ Po2/p = 1/3 |
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| 6586. |
Shape of XeOF4 is(a) Octahedral (b) Square pyrami(c) Pyramidal(d) T-shaped |
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Answer» b. Square pyramidal (based on octahedral) thank u |
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| 6587. |
4. What do you think would be thescattering experiment is carriedout using a foil of a metal otherthan gold? |
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| 6588. |
3When K2Cr2O7 is converted into K Croa, the change in oxidation number of Cris(D) 3lato(C) 4(B) 6 |
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Answer» A is the answer of the following When is converted into then the change in oxidation number of chromium is zero. In case of K has charge +1.Cr has charge x.O has charge -2.The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows. 2 + 2x - 14 = 0 x = 6 In case of K has charge +1.Cr has charge x.O has charge -2.The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows. 2 + x - 8 = 0 x = 6 Thus, it can be concluded that there is no change in the oxidation state of Chromium . the answer of the following question is option (a) B is because O. N of o is -2 and k is 1, so let cr be x and 2 + x+(-2×4)=+6 option a is the correct answer of this question (a) is the right answer of following questions option b is the correct answer of the given question option (a) is the right answer. option A is the right answer |
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| 6589. |
95thetha elactronhis valve ? |
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Answer» according to the uncertainty principle,∆x∆p ≥h/4πhere, ∆x=0.002nmtherefore, ∆p≥h/4π*0.002*10^-9∆p≥5.27*10^(-35)/0.002*10^(-9)∆p≥2.635*10^-23 if the momentum of electron is defined with the certainty then there will be uncertainty in the definition of its position due to the Heisenberg's uncertainty principle. whenever we measure momentum of a particle there will be an uncertainty and its position as the two operators of position and Momentum do not commute. |
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| 6590. |
HOwdloes iu enereacts woih C12 inFecis) |
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Answer» In case of substituted aromatic compounds, the functional groups already present directs the next incoming group to a particular position in the aromatic ring. It is called directive influence of the group already attached to the benzene ring. -CH3 group is an ortho and para directing group. define it |
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| 6591. |
Give reason why one drug that is effective against one microbe group may not be effectivagainst another microbe group |
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Answer» Antibiotic resistance occurs whenbacteriachange in response to the use of thesemedicines.Bacteria, not humans or animals, become antibiotic-resistant. Thesebacteriamay infect humans and animals, and the infections theycauseare harder to treat than those caused by non-resistantbacteria. |
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| 6592. |
c12. iv)oloes tolu ene reactsFecis)o sf |
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Answer» Haloarenes react with halogens in the presence of ferric salt as catalyst to give ortho para isomers. |
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| 6593. |
why is the sun seen a little before it Rises and for a short while after its sets |
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Answer» This effect is due to the atmospheric refraction of light. At the time of sunrise or sunset, the sun is just near the horizon. The line XY represents the horizon for an observer O on the surface of the earth. Near the surface of earth, air is a little denser than the outer space. The refractive index of the air near the surface of earth is 1.00029 w.r.t. the outer space. Therefore, a ray of light travelling from the sun towards the earth, travels through air, which becomes more and more optically denser. Due to this, it undergoes refraction and therefore gradually deviates towards the normal. As a result, to the observer O on the surface of earth, the sun appears at S'. The apparent shift in the direction of the sun is only 0.5 and the time difference between the actual sunset and the apparent sunset is about 2 minutes. |
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| 6594. |
(a) Freqdencyb)Wavenumber(c) WavelengthWhat is the ratio of energies of two waves having wavelengths 2000 Ă and 4000 A2al |
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Answer» Option c) |
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| 6595. |
Determine the wavelength for a transition from the v = 0 to the v =1 |
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Answer» If an electron makes a transition from the n = 4 to the n = 1 Bohr orbital in a hydrogen atom, determine the wavelength of the light emitted and the recoil speed of the atom. Solution: To determine the wavelength, we use |
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| 6596. |
what are the frequency and wavelength of a photon during a transition when n=5 to state in He positively ions |
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Answer» n= 5 to which state ? is it ground state your are asking?? sorry ground state |
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| 6597. |
7. Calculate the frequency and wave number of infrared radiations having wavelength 3x10%nm? |
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Answer» frequency=c/wavelengthhencef=3*10^8/3*10^-6=10^14Hz |
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| 6598. |
Calculate the wave number for the shortest wavelengthtransition in the Balmer series of atomic hydrogen. |
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Answer» The shortest wavelength transition in the Barlmer series corresponds to the transitionn = 2 → n = ∞. Hence, n1 = 2, n2 = ∞ Balmer |
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| 6599. |
The ionization energy of hydrogen can be calculated fromthe wave number of these lines |
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Answer» Where are the lines in the figure. Question is not full |
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| 6600. |
Calcutate wave number emdFreauency of yellono radiationhaving owe.length 5300 shren? |
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Answer» wavenumber =1/wavelength=1/5800*10^-101.72*10^6 frequency=c/wavelength=3*10^8/5800*10^-10=51kHz |
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