InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1601. |
The volume of 0.1 M H2504 required to neutralise 30 mL of 2.0 M NaOH isĐ) 100 ml4o 15.B)300 mLC) 400 mLD) 200 mL |
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| 1602. |
hlorideWHAT DO ALL ACIDS AND ALL BASES HACOMMON? |
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Answer» Relies on whether you need to portray them in a Lowry-Bronsted demonstrate or a Lewis corrosive base model. The previous says that all acids give a proton and all bases have an electron match accessible protonation. This covers a ton of acids and bases yet many are likewise missed. For instance, BR3 is an acid however it has no protons to give. Boron has an unfilled valence, however, and can acknowledge an electron match. It is this property, having the capacity to acknowledge an electron match (donated by a base) that characterizes a Lewis corrosive. In this way, as a rule, a corrosive can acknowledge an electron match, a base can give an electron pair, and this characterizes what all acids have in common, and what all bases have in common. |
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| 1603. |
COLICalculate the number of moles of H2PO4 required to neutralise 20.0g of NaOH |
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| 1604. |
What is the weight of sodium hydroxide required toneutralise 100 mL of 0. 1-N-HCI? |
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Answer» Weight of NaOH = N* E.w. * V/1000 Put the values in the above formula Weight of NaOH required.= 0.1 *40 *100/1000 = 0.4gm |
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| 1605. |
volume of O.1M H,S, that is needes toThe volume of 0.1Mcomplately neutralise 30 mlsolution is(I) 15 ml(3) 40 mLMP PMr 2901230 ml(4) 60 ml |
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| 1606. |
curdlinghastofirstneutralisethealkalipresentinit.Q,13. Plaster of Paris should be stored in a moisture-proof container. Explain why ?s Plaster of Paris should he stored in a moisture-proof container because the presence of |
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Answer» so what if gypsum is formed? |
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| 1607. |
would be the molality of the solution?What volume of 10% (w/v) solution of Na,co, will be required to neutralise100 mL of HCl solution containing 3.65 g of HCI? (Assam S.B. 2012)Utda13and what |
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Answer» We write the formulae for the reaction : Na₂CO₃(aq) + 2HCl (aq) - - - - > 2NaCl(aq) + CO₂(g) + H₂O (l) Mole ratio is : 1 : 2 meaning 1 mole of Sodium carbonate reacts with 2 moles of Hydrochloric acid. Given the mass of HCl we can get the reacting moles. Moles = mass of solute / molar mass Molar mass of HCl is : 35.5g (Cl) + 1g (H) =36.5g/mol Moles = 3.65/36.5 =0.1moles. The number of reacting moles of Sodium Carbonate is 0.1/2 = 0.05moles from the mole ratio. The molar mass of Sodium Carbonate is : 23 × 2(Sodium) + 16 × 3(Oxygen) + 12 (Carbon) =106g /mol Reacting mass of Sodium Carbonate = 106 × 0.05 = 5. 3 g Given the density as 10 %=0.1g/cm³ Volume = mass / density 5. 3 / 0.1 =53cm³ |
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| 1608. |
14. Gastric juice containing 3.0 g of HCI per litre. If a person produces about 2.5 litres of28.gastric juice a per day, how many antacid tablets each containing 400 mg of Al(OH)are needed to neutralise all the HCI produced in one day. |
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| 1609. |
4 g of copper was dissolved in conc. nitric acid Tic acid. The copper nitrate so obtained strong heating gave 5 g of itsvide. The equivalent weight of copper is(2)32(3) 12(4) 20(1) 23 |
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Answer» Answer:2)32 Explanation:4g of copper gave 5 gram of copper oxide. Therefore, Mass of oxygen in oxide = 5- 4 = 1g Now, Mass of copper which combined with 1 g oxygen = 4 Mass of copper which will combine with 8 gram oxygen = 4 x 8 = 32 Therefore, equivalent mass of copper is 32 |
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| 1610. |
9.A colourless solid 'X' on heating evolved CO. and also gave a white resid(D) CH,COONa site arfer HCIWhich is soluble in water. 'Y' also gave CO. when treated with dil. HSO4 X 15and also gave a white residue 'Y',[1](A) Na, co,(C) Caco,Uch Usa STA 'X' mfin(B) NaHCO,(D) Ca (HCO), |
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| 1611. |
Calculate the molecular mass of glucose (C,H120)molecule. Given at. massesH-1.008 amu, C 12.011 amu, Oθ16.0 amu. |
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Answer» Molecular formula of glucose = C6H12O6 therefore, molecular mass of glucose = [ 6(12.001) + 12(1.008) + 6(16.00) ] amu [72.066 + 12.096 + 96 ] amu 180.162 amu |
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| 1612. |
12 AS for the reaction: MgCO3(s)-MgO(s)+00(2) -ve(1) Zero3) +ve |
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Answer» ∆S will pe positive. Because, entropy increased due to release of CO2. Please make it clear .... Please explain in details . |
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| 1613. |
When the mixture of mgco3 andcaco3 was heated, the weightdecreased by 50%. How can Icalculate the percentagecomposition of the mixture? |
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| 1614. |
i. A certain compound has the molecular formula X OIf 10 g of XO, has 5.72 g X, then atomic mass of X1S.a. 32 amu b. 42 amuC.98 amud. /amu |
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Answer» mol. wt of X4O6 = 4* atomic mass of X + 6 * atomic mass of O = 4x + 6*16 = 4x+96..where x is atomic mass of element X.so 4x+96 gms of X4O6 contains 4x gms of X.given, 10 g X4O6 contains 5.72 gms of X.so we can write, 4x+96 / 10 = 4x/5.72.solve the equtaion for x .by solving u can getx= 32.074 (answer ) |
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| 1615. |
when the mixture of MgCO3 and CaCO3 was heated for a long time. The weight decreased by 50%. Findthe percentage composition of the mixture. |
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Answer» MgCO3(s)→MgO(s) + CO2(g) CaCO3(s)→CaO(s) + CO2(g) The total initial weight of solid phase = (84x+100y) gm x=the no. of moles of MgCO3 present y=the no. of moles of CaCO3 present. [MgCO3] = [MgO] [CaCO3] = [CaO] Final weight of solid phase = (40x + 56y) gm. Final weight = 50% of the initial weight. So, (84x + 100y)/2 = 40x + 56y Or, 42x + 50y = 40x + 56y Or, 2x = 6y Or, x/y = 6/2 = 3 So, x:y = 3:1. i.e 3 moles of MgCO3 =3×84=252 g And 1 mole of CaCO3=100 g In (252+100=352g) mixture. So % MgCO3=252×100/352=71.59% Ans % CaCO3=100×100/352=28.41% Ans |
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| 1616. |
45.Match the following:i. \46 g ofsodium atoms \ a. 2.51 × 1023ii. 5 g of carbon atoms b. 3.542 x 103ii 0.2 mole of oxygen c. 1.2044x 1023atomsiv. 10g of ammoniad、 1.2044 × 1024A. i d, ii- a, iiic, iv bC.1a, ii d, iii-c, iv b1d, iib, iii-c, iv- aE. of these |
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Answer» Correct option is A |
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| 1617. |
Skating on ice is possible becauseA) the surface of ice is smoothB) ice is coldC) the pressure on the ice dueto skate melts the ice by loweringits melting point forming a thinfilm of waterD) the pressure on the ice due toskate raises its melting point |
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Answer» C) the pressure on the ice due to skate melts the ice by lowering its melting point forming a thin film of water |
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| 1618. |
Example 3.5 Calculate the number ofparticles in each of thefollowing0) 46 g of Na atoms (number frommass) |
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Answer» a)46g of Na atomatomic mass of Na=23uNumber of particles=Number of Moles x N⇒(given weight/ Gram atomic weight) x 6.023 x 10²³=(46/23)x 6.023 x 10²³=2x 6.023 x 10²³⇒12.046 x 10 ²³Na particles∴46 g of Na contains 12.044 x 10 ²³ wrong |
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| 1619. |
If 30 ml of H2 and 20 ml of O2 react to form water,What is the left at the end of the reaction? |
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Answer» 1ml of H₂ reacts with 0.5ml of O₂ to form 1ml of water.30 ml of H₂ will react with 15 ml of O₂ to form water. So at the end of the reaction, 30 ml of water and 5 ml of O₂ will be left. how?? can you please explain in brief |
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| 1620. |
0.2 M HCL pH. |
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| 1621. |
Gattermann reactionth-HCland |
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Answer» TheGattermann reaction, (also known as theGattermannformylation and theGattermannsalicylaldehyde synthesis) is a chemicalreactionin which aromatic compounds are formylated by hydrogen cyanide in the presence of a Friedel–Crafts catalyst (e.g. AlCl3). |
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| 1622. |
1. Which has maximum pH ?a) 0.01m H,SO, b) 0.01 M HC 0.01 Mc) 0.01 M Ca(OH)2 d) 0.01 M NaOH |
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Answer» NaOH , is the most basic so, it will have maximum pH. |
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| 1623. |
NaOH + HCl - Naci +H2Ocalculate the mass s sodium chloride when160gms CH sodium hydroxide is utilized. |
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| 1624. |
(1) 1 M(2) 0.5M(3) 2MThe volume of water that must be added to a mixture of 250 ml of 06 M HCl and em0.2 M HCI to obtain 0.25 M solution of HCl is!(4) 300 m |
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Answer» No. of moles of 0.6M HCl = 0.15 No. of moles of 0.2M HCl = 0.15 letVbe the volume(in ml) of the 0.25M solution. No of moles present = 0.15+0.15 = 0.3 0.25M=(0.3×1000)/ VV=1.2L=1200 ml now total volume is 1200 ml and intial volume was 1000 ml Hence volume of water added is 200 ml |
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| 1625. |
HCl + NaOH gives ? |
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Answer» This type of reactions are called as neutralization reactions. i.e., and acid and base reacts to give salt and water. |
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| 1626. |
what is Hcl |
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Answer» IUPAC name-Chlorane[3] Other names-Muriatic acid[1] Spirits of salt[2] Hydronium chloride Chlorhydric Acid hcl is a hydrochloric acid HCL = HYDRO CHLORIC ACID |
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| 1627. |
molecular mass of HCL |
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Answer» 36.6 is the correct answer of the given question 36.6 is the correct answer 36.6 is the correct for HCL (hydro chloric acid) |
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| 1628. |
87.Sulphur has lowest oxidation number in-(A) H2SO(C) H2SO(B) SO,(D) H,S |
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| 1629. |
what is meant by H bond, why HF and H2O are liquid. whereas HCl, HBr, HC and H2S are gases |
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Answer» a weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in the other. It would be worth specifying that hydrogen fluoride boils at about 20∘C, so if by room temperature you mean 25∘C, then hydrogen fluoride will actually be a gas. Impotant thing is that they havedifferent number of lone pairspresent on the more electronegative atom. In water's case, you have two partial positive hydrogen atoms andtwo lone pairsof electrons on the oxygen atom, which means that each water molecule can form hydrogen bonds withfourother water molecules. Hydrogen fluoride hasthree lone pairsof electrons, but only one hydrogen atom. This means that on average you will have insufficient partial positive hydrogen atoms to allow for the majority of hydrogen fluoride molecules to hydrogen bond at a particular moment. Both HCl and HF are gases at room temperature. But HF has high boiling point than HCl because of the reason that in HF the strength of hydrogen bond is stronger than the strength of hydrogen bond in HCl. |
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| 1630. |
2. The correct order of increasing covalent character is:6o Na cs(b) Be C4 < Na Cl < Li。 |
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Answer» Smaller the size, more is the electronegativity and more is the covalent character. Therefore, option B is correct. |
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| 1631. |
4.416Exercise 18.Which has maximum covalent character?(A) LiF(C) LiBr(B) LiCI(D) Lil |
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Answer» maxit covalent character will be in between those which have the least difference in their electronegativity and we know that Fluorine is the most electronegative atom, so LiF will have most ionic character hence LiI should be the correct answer. |
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| 1632. |
22. In which of the following option, covalent bond ishaving maximum s% character ?(1) S-H bond in H2S(2) P-H bond in PH(3) N-H bond in NH3(4) All have equal s% character |
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Answer» option 3 is the correct answer |
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| 1633. |
5. Match the following:Column-IIColumn-I(i) Cation(i) Anion(ii) Electrostatic force(iv) van der Waals' force(a) Non-metals(b) Covalent bond(c) Metals(d) Ionic bond |
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Answer» a) Cation- Metalsb) Anion- Non-metalsc) Electrostatic force - ionic bondd) van der Waals forces - covalent bond Please hit the like button if this helped you. |
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| 1634. |
4Which property could describe a covalent compound?a. It is conducting in molten (fused) stateb. It is a gas at room temperaturec. It is composed of metal and non-metald. It is a solid with high melting point |
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Answer» a. It is conducting in molten(fused) state |
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| 1635. |
26. One mole of CO, contains() 6.02 x 10 atoms of C(2) 6.02 oms of O(3) 18.1 × 1023 atoms orco2(4) 3 grams of carbon |
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Answer» one atom of CO26.02 x 10^23 atoms of C can you explain plz 3) 1 mole CO2 = 6.02×10^23 ×3 atoms of CO2. 1)1 mole CO2 = 6.02×10^23 ×1 atoms of C. |
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| 1636. |
15.54 mg of SF, contains 3.01 x 1020 molecules. The value of n is-(2) 4(3) 5(4)6i 1 1024 carbon atoms- |
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Answer» can you explain it more |
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| 1637. |
Calculate the mass of 3.011 x 1024 atoms of carbon. |
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| 1638. |
16. What weight of Ribose (CyH100,) will contains 1.2 x 104 carbon atoms-(2)1.99 g(1) 23.9 g(3) 150.1 g(4) 59.8 gu T'anf A contain 'h' atoms, then number of atom |
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Answer» it will be more than 150 because ribose contains Avogadro number of carbon atoms but given are more than Avogadro so 3 will be a better option. |
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| 1639. |
7. Calculate the number of atoms of C and O in 72.5gisopropanol, C3H,OH (molar mass 60)(Ans. C 2.186 x 1024, H 5.83 x 1024, O 7.277x 1023) |
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| 1640. |
If one gram of Carbon contains 'x' atoms Number of Magnesium atoms in its One gram will be |
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Answer» 1 mole of carbon = gram molecular mass of carbon = 12 grams. 12g carbon = 1 mole 1g carbon = 1/12 mole 1g of carbon contains x atoms and 1g = 1/12 mole. Therefore 1/12 mole of carbon has x atoms. Equal number of moles of all the elements contain equal atoms, so 1/12 mole of magnesium also contains x atoms. 1 mole of magnesium = 24g Therefore, 24 gram = 1 mole 1g = 1/24mole. 1/24 mole of magnesium = ( x * 12)/ 24 ( x multiplied by 12, divide by 24) = x/2 atoms |
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| 1641. |
2HCIZnCl, +H, is a react |
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Answer» this is the example of double displacement reaction. |
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| 1642. |
is a combination reaction.(a) Cu + H SoCuSo, +H2(b) H2+ Cl2 2HCl(d) CaCO3CaO+ CO2 |
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Answer» option (b) is a combination reaction as both the reactants combine to produce a single product. |
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| 1643. |
The basic character of Mgo, SrO, K2O and NiO increase in the order(A) NiO < SrO< MgO< K20 |
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Answer» NiO < MgO < SrO < K2O Explanation:Reason – This is the order because the basic character of oxides increases down the group, alkali metal oxides are more basic than alkaline earth metal oxides and oxides of the d- block element is less basic than those of s-block elements. |
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| 1644. |
2mg+o2=Mgo |
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Answer» Magnesium and oxygen combine to from the magnesium oxide .It's a addition reaction that's we are seeing the addition of magnesium and oxygen here. It's a white solidified mineral which is found in nature in the form of periclase.The molecular formula of Mg0 is 44.3044 g/mol.Moreover, magnesium oxide is a mineral and used to maintain the level of magnesium in the body because magnesium is necessary for healthy bones as well as the muscles. Magnesium combine with oxygen |
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| 1645. |
Mg +02 = Mgawhy comanie Onugem 2 and aurite mgo. |
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Answer» The unbalanced equation is: Mg(s)+O2(g)→MgO(s) MultiplyMgOby2to balance the oxygens. Mg(s)+O2(g)→2MgO(s) MultiplyMgon the left side by2to balance the magnesiums. 2Mg(s)+O2(g)→2MgO(s) Now, there are equal amounts of magnesium atoms and oxygen atoms on both sides, and so the equation is balanced. o sa 2 ko kyu remove karta h |
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| 1646. |
why does an aqueous solution of an acid conduct electricity |
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Answer» The aqueous solution of an acid conduct electricity because the acid solution have ions and the movement of these ions in solution helps for flow of electricity current through the solution.And the ions are H+ ions |
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| 1647. |
Which of the following remains unchanged on descending down a group in the Periodic table(a) Valence electron(b) Atomic size(c) Density(d) Metallic characterइनमें से कौन किसी ग्रूप में नीचे जाने पर अपरिवर्तित रहता है ?(a) वेलेन्स इलेक्ट्रॉन(b) परमाण्विक आकार(c) घनत्व(d) धात्विक गुण |
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Answer» Valence electrons remain unchanged on descending down a group in Periodic table.In a group all elements have same valency. The group number is, in fact, valency with respect to oxygen. (a) is correct option |
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| 1648. |
Why does an aqueous solution of an acid conduct electricity? |
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Answer» Because all acid aqueous solutions are conductive, due to the presence of hydrogen ions and acid ions, which can conduct charge exchange between the electrodes and thus conduct electricity. So the acid is also an electrolyte. Aqueous solution of an acid conduct electricity because of the presence of hydrogen ions (H+) in it. |
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| 1649. |
Considering the atomic number andposition in the periodic table, arrange thefollowing elements in the increasing orderof metallic character: Si, Be. Mg. Na, P. |
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| 1650. |
88. Which of the following set of clements is written correctly in the order of theirincreasing metallic character?1. Mg, Al, si 2.C.ON 3. Na, Li, K 4. Be, Mg, Ca. |
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