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Cu is 63.55H is 1.01S is 32.07O is 16.00

Next, determine how many grams of each element are present in one mole of CuSO4*4H2O :

63.55 g (1 mol) of Cu32.07g (1mol) of S8.08 g (8 mole x 1.01gram per mole) of H128.00 g (8 mole x 16.00 gram per mole) of O

The mass of one mole of CuSO4*4H2O is:

63.55g +32.07g + 8.08 g +128.00g = 231.7 g

The mass of the hydrate CuSO4 is63.55g + 32.07 + (4* 16.00) = 159.62g

percent composition of observation

3.44/ 159.62 x 100 = 2.16%

percent composition of observation from the whole hydrate

3.44 / 231.7 x 100 = 1.48%

the percent composition of the hydrate CuSO4

159.62 / 231.7 x 100 = 68.89%

the percent composition of water

100-68.89= 31.11 %

tnx b

CuSO4 , the molar mass is 159.6

now % mass of Cu = 63.6*100/159.6 = 39.84%and % mass of S = 32*100/159.6 = 20.05%

The answer is about 20 grams. The mass of 1 calcium atom is40 amu, so the mass of a mole of calcium atoms would be40 grams.

Molar mass = 32 + (16 x 2 ) = 64 g/mol1 mole => 64 g6.02 x 10^23 molecules => 64 gmass of one molecule = 64 / 6.02 x 10^23 =1.06 x 10^-22 g

CaCO3, calcium carbonate (limestone). The lemon juice (acidic), reacts with the limestone (basic), partially dissolving it creating the milky liquid, CO2.

kindly repost the question, so that another mkderator can solve your doubt.

H2SO4=2H^+ + SO4^-2.

H2=1×2=2S=32O4=16×4=72so total mass of H2So4 is =106

Specific heat of a metal is the measurement of amount of energy required to increase the temperature of 1 Kg of that metal by 1 Kelvin.The formula is ΔE=mcΔT.ΔE is the amount of energy required, m is the mass of the object , c is specific heat capacity, and ΔT is change in temperature.Now, as per this question, Atomic mass = 6.4/specific heat = 6.4/0.16 = 40g.

M has valancy of 2 and phosphate has 3so, formula will be M3(PO4)2

pls explain briefly. I m confuse bcs of o

Ans :- Sodium dihydrogen phosphate

Formula:NaH2PO4

Molar mass:119.98g/mol

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Here p=ps

molar mass of CH2 = 12 + 2(1) = 12 + 2 = 14 Molar mass of CO2 = 12 + 2(8) = 12 + 16 = 28

Polyethene is not a thermoplastic polymerhence option b

each of the digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit is called significant figures

1)ethanoic acid2)methanoic acid3)propene4)propyne5)but-1,3-diene

i) 2+16=18ii) 12+2(16) =12+32 =44

iii) CO2 is 12+4(1) =16

1 mole of Hydrogen at STP occupies 22.4 litres volume.Number of moles of 0.7 litres of Hydrogen at STP is 0.7/22.4 = 0.0313 moles

Weight of element (x) = Moles of Hydrogen times equivalent weight of metal times mass of Hydrogenx = 0.0313*28*2x = 1.7528 grams

At the cathodeCu2+ (aq) + 2e- ---> Cu(s)

At the anode4OH-(aq) ----> 2H2O (l) + O2(g) + 4e-

Faraday’s constant = 96500C/molTo deposit 1 mole of copper, we need 2x96500CSo, 96500C will deposit 0.5 moles of copper = 0.5x63.5 = 31.75gTo liberate one mole of oxygen molecules,we need 4x96500CSo, 96500C will liberate = ¼ = 0.25 moles = 0.25x32 = 8g

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Whensoapis added tohard water, the Ca2+ and Mg2+ ions present inhard waterreact withsoap. The sodium salts present insoapsare converted to their corresponding calcium and magnesium salts which are precipitated as scum. The insoluble scum sticks on theclothesand so the cleaning capacity ofsoapis reduced.

Detergents do not form lather with hard water. Hence, they overcome this problem.

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ans

1. NaCl(s) = Na+(aq) + Cl-(aq) Since NaCl is an ionic solid (s), which consists of cations Na+ and anions Cl-.

2. Sodium(Na) is an atom consisting of 11 electrons. When sodium gives away 1 electron to attain stability, it becomes a positive ion i.e. it has more number of protons than electrons this is denoted by Na+.

Electronic Configuration of Sodium is 1s2 2s2 2p6 3s1

When it gives away one electron it is given away from the s-shell of the 3rd orbit. After formation of Sodium ion(Na+), the configuration becomes 1s2 2s2 2p6.

Thus Sodium ion (Na+) has 3 shells i.e. 1s, 2s and 2p.

3. The chloride ion,Cl−, has a charge of−1, meaning, it had gained 1 electron in its outermost orbital. The overall number of electrons is now18.

Thus, the electron configuration forCl−should be

1s22s22p63s23p6=18 electrons

1) gravitational force is the only attractive force.

Compositionof C = 57.8%Composition of H = 3.6%Total composition of organic compound = 100%Composition of oxygen = 100 - (57.8 + 3.6) = 38.6%

Element composition Atomic mass Ratio of atoms Simplest ratio C 57.8% 12 57.8/12 = 4.82 4.82/2.41 = 2 H 3.6% 1 3.6/1 = 3.6 3.6/2.41 = 1 O 38.6% 16 38.6/16 = 2.41 2.41/2.41 = 1

Therefore the empirical formula of the compound = C2HO

Molecular weight = 2 * vapour density = 2*83 = 166

Emperical formula weight = 24+1+16 = 41

n = Molecular weight/Emperical weightn = 166/41n = 4 (nearly)

Molecular formula = 4(C2HO) = C8H4O4

c) is the correct answer

option C is the answer

answer is option C

a answer is (b) CH2O

henceRT=0.082*300=24.6

According to Henry's law, p = kH x760 = 2 × 10⁵ × x x = 760/2 × 10⁵ = 3.8 × 10⁻³

is mole fraction solubility

Are you asking what is mole fraction solubility? mole fraction solubility = (number of moles of solute)/(number of moles of solute + number of moles of solvent)