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851.

One of the major compnents of cell wall of most fungi isA. ChitinB. PeptidoglycanC. CelluloseD. Hemicellulose

Answer» Correct Answer - A
One of the major components of cell wall of most fungi is chitin.
852.

An association between rots of higher plants and fungi is calledA. lichenB. fernC. mycorrhizaD. BGA.

Answer» Correct Answer - C
An association between roots of higher plants and fungus is called mycorrhiza.The association is mutually beneficial for both of them.Fungus gets shelter and food from plant.It obtains its nourishment from cortical cells of roots.Fungal hyphae are spread in the soil over a large area.They take part in absorption of water, dissolving essential minerals in organic debris and providing it to the plant, absorption of inorganic salts from soil and in some cases, secreting growth promoting substances.Example is roots of Pinus.
853.

Members of phycomycetes are found in (i). Aquatic habitats (ii). On decaying wood (iii). Moist and damp places (iv). As obligate parasites on plants Choose from the following optionsA. None of the aboveB. (i) and (iv)C. (ii) and (iii)D. All of above

Answer» Correct Answer - D
854.

Members of phycomycetes are found in (i). Aquatic habitats (ii). On decaying wood (iii). Moist and damp places (iv). As obligate parasites on plants Choose from the following optionsA. None of the aboveB. I and ivC. ii and iiiD. All of the above

Answer» Correct Answer - D
Members of phycomycetes are found in :
i. Aquatic habitats
ii. On decaying wood
iii. Moist and damp places
iv. As obligate parasites on plants
855.

Members of phycomycetes are found in (i). Aquatic habitats (ii). On decaying wood (iii). Moist and damp places (iv). As obligate parasites on plants Choose from the following optionsA. (i) and (iv)B. (ii) and (iii)C. All of theseD. None of these

Answer» Correct Answer - D
Phycomycetes are the members of fungi that can thrive well on dead decaying wood saprophytes. These prefer to live in moist and damp places and need water for the movement of zoospore and sexual gametes
Few members of phycomycetes are obligate parasites like phytophthora infestans causing late blight of potato and Peronospora viticola causing downy mildew of grapes.
856.

Total number of amino acids in capsid of TMV having 2130 capsomeres isA. 336540B. 162622C. 948D. 387921

Answer» Correct Answer - A
`because` 1 capsomere has = 158 amino acids
`therefore` 2130 capsomeres have `= 158xx2130`= amino acids
857.

The internuclear distance between adjacent chlorine atoms of the two neighboring molecules in the soild state is `360` pm. Thus, the van der Waals radius of chlorine atom is_______.A. `18 Å`B. `1.80 Å`C. `180 Å`D. `0.18 Å`

Answer» Correct Answer - B
The van der Waals radius of `C1` atom is `360 "pm"//2 = 180 "pm" ` ot `1.80 Å`.
858.

Arrange the following elements in the order of incresing first ionizarion enthalpy: `Na, Mg, A1`, and `Si`A. `Na lt Mglt A1 lt Si`B. `Na lt Mg lt Silt A1`C. `Na lt A1 lt Mg lt Si`D. `Na gt Mg gt A1 gt Si`

Answer» Correct Answer - C
First ionization enthalpies generally increase from left to right in the same period, but there are anomalies at groups `13` and `16`. All these elements are members of the `3rd` period and `A1` is a group `13` element with only one electron in its outer `p` orbital `(1s^(2)2s^(2)2p^(6)3s^(2)3p^(1))`. Therefore, there is a slight dip at `A1`.
859.

Which of the following halogens exhibits only `-1` oxidation number in its compounds?A. `F`B. `C1`C. `Br`D. `I`

Answer» Correct Answer - A
Because `F` is always univalent in its compounds and is the most electronegative element.
860.

In which of the following options order of arrangement does not agree with the variation of property indicated against it?A. `Al^(3+)ltMg^(2)ltNa^(+)ltF^(-)` (increasing ionic size)B. BltCltNltO(Increasing first ionisation enthalpy)C. IltBrltFltCl(increasing electron gain enthalpy)D. LiltNaltKltRb(Increasing metallic radius)

Answer» Correct Answer - B
Ionisation enthalpy of BltC but NgtO due to half-filled orbits in N which have extra stability.Electron gain enthalpy of CigtF due to bigger size and lesser electronic repulsion.
861.

The convalent radii for carbon and chlorine are `0.077 nm` and `0.099 nm`, respectively. Find the `C-CI` bond length. Strategy : Use Eq to obtain directly the `C-CI` bond distance.

Answer» `d_(C-CI) = r_(C) +r_(CI) = 0.077nm +0.099 nm = 0.176 nm`
862.

The ` C-Si` single-bond distance is `SiC` (carbondum) or `(CH_(3))_(4)Si` is `194`pm and the convalent radius of `C` is `77`pm. Find the convalent radius of silicon. Strategy: Use Eq. to obtain directly the convalent radius of silicon.

Answer» `d_(C-Si) = r_(C) +r_(Si)`
or `r_(Si) = d_(C-Si) - r_(C)`
`= 194nm - 77`pm
`= 117` pm
Thus, the covalent radius of `Si` is `117`pm.
863.

The English chemist John Alexander Newlands in `1866` profounded theA. law of triadsB. law of octavesC. law of pentavesD. law of hexaves

Answer» Correct Answer - B
It stated that when the known elements are listed by increasing atomic weights, those tat were eight places apart would be similar, much like the notes on a pinao keyboard.
864.

Name the scientist who belived that there existed some mystical connection between music and chemistry.A. de chancourtoisB. `J.W.`DobereinerC. John NewlandsD. `S.`Cannizzaro

Answer» Correct Answer - C
Upon arrangind the known elements in the order of their atomic weights, Newlands noticed that there was a repetition of chemical properties in each eigth element. According to him, the eighth element starting from a given one is a kind of repetition of the first like the eighth not of an octave in music.
865.

The element with the highest electron affinity among the halogens isA. `F`B. `C1`C. `Br`D. `I`

Answer» Correct Answer - B
The correct order of electron affinity (electron gain enthalpy) is
`C1(-349kJ mol^(-1)) gt F(-333) gt Br (-325) gt I(-296)`
866.

The electronic configuration of element `A, B`, and `C`are `[he]2s^(1),[Ne]3s^(1)`, and `[Ar]4s^(1)`, respectively. Which one of the following order is correct for the `IE_(1) ("in" kJ mol^(-1))` of `A`, B,` and `C`?A. `A gt B gt C`B. `C gt B gt A`C. `B gt C gt A`D. `C gt Agt B`

Answer» Correct Answer - A
All these elements are the succeeding members of a group in the periodic table. As we move down the group, the ionization enegry decreases on account of the increase in the number of shells.
867.

In any period, the valency of an element with respect to oxygenA. charges randomlyB. increases one by one from `IA`to `VIIA`C. decreases one by one from `IA`toVIIA`D. `increases one by one from `IA`to `IVA` and then decreases from `VA` to `VIIA` one by one

Answer» Correct Answer - B
Oxygen is the `2nd` most electronagative elemnt, thus, it bringes out the maximum oxidation number of the element as reflected by the formulas of oxides:
`|{:("Group",I,II,III,IV,V,VI,VII),("Formula",E_(2)O,EO,E_(2)O_(3),EO_(2),E_(2)O_(5),EO_(3),E_(2)O_(7)),("Valanvy",1,2,3,4,5,6,7):}:|`
where `E` is the element.
868.

Which of the following is not a periodi0c property for the elements?A. ElectronegativityB. Atomic sizeC. Occurrence n natureD. Ionization energy

Answer» Correct Answer - C
869.

The correct order of acidic character of oxides in third period of periodic table isA. `SiO_(2)ltP_(4)O_(10)ltSO_(3)ltCI_(2)O_(7)`B. `Cl_(2)O_(7)ltSO_(3)ltP_(4)O_(10)ltSiO_(2)`C. `SO_(3)ltCI_(2)O_(7)ltP_(4)O_(10)ltSiO_(2)`D. `SiO_(2)ltCI_(2)O_(7)ltP_(4)O_(10)ltSO_(3)`

Answer» Correct Answer - A
Acidic character of oxides increases as we move from left to right in a period and depends upon oxidation state of central element.
870.

Which is the most non-metallic elements amongs the following?A. `1s^(2)2s^(2)2p^(6)3s^(1)`B. `1s^(2)2s^(2)2p^(5)`C. `1s^(2)2p^(6)3s^(2)`D. `1s^(2)2s^(2)2p^(3)`

Answer» Correct Answer - B
It contains maximum nuber of electrons in the outermost shell.An element with more than 3 electron in outermost shell is non-metallic.
871.

According to the law of triads, when chemically similar elements are arranged in groups of three in the order of increasing atomic weights, then the________element has the atomic weight and properties roughly the average of the other two elements.A. firstB. middleC. thirdD. every

Answer» Correct Answer - B
Elements in a triad not only has similar properties but also the atomic weight of the middle element was approximately an average of the atomic weights of the other two elements of the triad. Also, the properties of the central element were in-between those of the end members.
872.

In the modern long form of the periodic table, elements are arranged in the increasing order ofA. Atomic massB. Atomic numberC. Mass numberD. Metallic character.

Answer» Correct Answer - B
873.

Which of the following is arranged in order of increasing metallic character?A. PltSiltNaltBeltMgB. BeltMgltPltNaltSiC. SiltBegtMgltNaltPD. PltSiltBeltMgltNa

Answer» Correct Answer - D
Metallic character increases down a group and decreases along a period as we move from left to right,Hence the order of increasing metallic character is:PltSiltBeltMgltNa
874.

Match the column I with column II and mark the appropriate choice. A. (A)`to`(ii),(B)`to`(iv),(C)`to`(iii),(D)`to`(i)B. (A)`to`(i),(B)`to`(iv),(C)`to`(ii),(D)`to`(iii)C. (A)`to`(iii),(B)`to`(ii),(C)`to`(i),(D)`to`(iv)D. (A)`to`(ii),(B)`to`(i),(C)`to`(iii),(D)`to`(iv)

Answer» Correct Answer - B
875.

Which one of the following groups represent a collection of isolectronic species ? (At.no `Cs = 55, Br = 35)`A. `Na^(+),Ca^(2+),Mg^(2+)`B. `N^(3-),F^(-),Na^(+)`C. `Be,Al^(3+),Cl^(-)`D. `Ca^(2+),Cs^(+),Br`

Answer» Correct Answer - B
876.

According to the law of triads, when chemically similar elements are arranged in groups of three in the order of increasing atomic weights, then the________element has the atomic weight and properties roughly the average of the other two elements.A. The properties of the middle element were in between those of the other two membersB. Three elements arranged according to increasing weights have similar propertiesC. The elements can be grouped in the group of six elementsD. Every thrid element resembles the first element in periodic table.

Answer» Correct Answer - A
877.

Match the atomic numbers of the elements given in column I with the periods given in column II and mark the appropriate choice. A. (A)`to`(i),(B)`to`,(C)`to`(III),(D)`to`(iv)B. (A)`to`(ii),(B)`to`(i),(C)`to`(iv),(D)`to`(iii)C. (A)`to`(iii),(B)`to`(iv),(C)`to`(i),(D)`to`(ii)D. (A)`to`(iii),(B)`to`(i),(C)`to`(iv),(D)`to`(ii)

Answer» Correct Answer - D
878.

Few values are given in the table in the direction from left to right and top to bottom.Predict the property which could be depicted in the table. A. Atomic numberB. Ionisation enthalpyC. Atomic radiusD. Electron gain enthalphy

Answer» Correct Answer - C
Atomic radius decreases in a period from left to right increases in a group from top to bottom.
879.

Three elements X , Y and Z have atomic numbers 19 , 37 and 55 respectively . Then the correct statements (s) is / areA. Their ionization potential would increase with increasing atomic number.B. Y would have an ionization potential between those of X and Z.C. Z would have the highest ionization potential.D. Y would have the highest ionization potential.

Answer» Correct Answer - B
Element X,Y and Z with atomic numbers 19,37,55 lie in group 1(alkali metals).Within a group,IE decreases from top to bottom.Therefore,IE of y could be between those X and Z.
880.

The first ionzation enegry of oxygen is less than that of nitrogen. Which of the following is the correct reason for this observation?A. Higher electronegative of oxygen than nitrogenB. Greater effective nuclear charge of oxygen then nitrogenC. Lesser atomic size of oxygen than nitrogenD. Greater inter electrobn repulsion between two electrons in the same `p`-orbital conunterbalances the increase in effective nuclear charge on moving from nitrogen to oxygen

Answer» Correct Answer - D
Another reason is that after losing one of the `p` electrons, oxygen acquires stability in the form of excatly halffull `p `subshell:
`O(1s^(2)2s^(2)2p^(4))rarr O^(+) (1s^(2)2s^(2)2p^(3))+e^(-)`
881.

Among `Al_(2)O,SiO_(2),P_(2)O_(3)` and `So_(2)` the correct order of acid strength isA. `SiO_(2) lt SO_(2) lt A1_(2)O_(3) lt P_(2)O_(3)`B. `A1_(2)O_(3) lt SiO_(2) lt SO_(2) lt P_(2)O_(3)`C. `SO_(2) lt P_(2)O_(3) lt SiO_(2) lt A1O_(3)`D. `A1_(2)O_(3) lt SiO_(2) lt P_(2)O_(3) lt SO_(2)`

Answer» Correct Answer - D
Acidic strength increases with the increase of nonmetallic character which increases as we move across the period. Thus, the correct order is
`A1_(2)O_(3) gt SiO_(2) lt P_(2)O_(3) lt SO_(2)`
882.

The oxidation number of oxygen in `H_(2)O_(2)`isA. `-2`B. `-1`C. `-1//2`D. `+1`

Answer» Correct Answer - B
True peroxides such as `H_(2)O_(2)`are characterized by `-1` oxidation number for the `O` atom:
`overset(+1)H-overset(-1)O-overset(-1)O-overset(+1)H`
883.

For `p`-block elements, the normal valence (or group valence is equal to the number of valence electrons only for_______elements (i) group `17` (ii) group `15` (iii) group `14` (iv) group `13`A. `(i),(ii),(iii),(iv)`B. `(i),(ii),(iii)`C. `(ii),(iii),(iv)`D. `(iii),(iv)`

Answer» Correct Answer - D
The normal valence of group `13` elements `(ns^(2)np^(1))` is `3` while the normal valence of group `14` element `(ns^(2)np^(2))` is `4`.
884.

Just as Xenopsylla is to Yersinia pestis, so is:A. Glossina palpalis to Wuchereria bancroftiB. Culex to Plasmodium falciparumC. Homo sapiens to Taenia soliumD. Phlebotomus to Leishmania donovani

Answer» Correct Answer - D
885.

Single-celled eukaryotes are included in KingdomA. MoneraB. ProtistaC. FungiD. Archaea

Answer» Correct Answer - B
886.

Match the following columns:

Answer» Correct Answer - a-r; b-s; c-r; d-p
887.

Match the following columns:

Answer» Correct Answer - a-p,t; b-p,t; c-p,q,s,t; d-p,r,s,t
888.

Which of the following compound is wrongly named ?A. `CH_(3)CH_(2)CH_(2)underset(CI)underset(|)(CH)COOH` 2-chloro pentanoic acidB. Bicyclo-[3,2,1]-oct-1-eneC. `CH_(3)CH_(2)CH=CHCOCH_(3)`, Hex-3-en-2-oneD. `underset(4-"methyl pentanal")(CH_(3)-underset(CH_(3))underset(|)(CH)CH_(2)CH_(2)CHO)`

Answer» Correct Answer - B
889.

Which of the following is not the characteristic feature of metals?A. Close-peacket structureB. Low corrdination numberC. Metallic bondingD. Give alloys with metals

Answer» Correct Answer - B
Metals have high corrdination number in their crystal lattice, usually `12` or `8`.
890.

which of the following configurations represents atoms of the elements having the higest second ionisation energy?A. `1s^(2)2s^(2)2p^(4)`B. `1s^(2)2s^(2)2p^(6)`C. `1s^(2)2s^(2)2p^(6)3s^(1)`D. `1s^(2)2s^(2)2p^(6)3s^(2)`

Answer» Correct Answer - C
Because for removing second electrons, it has to be taken out from stable configuration that needs a large amount of energy.
891.

Sodium sulphate is soluble in water,whereas barium sulphate is sparingly soluble becauseA. the hydration energy of sodium sulphate is more than its lattice energyB. the lattice energy of barium sulphate is more than its hydriation energyC. the lattice energy has no role to play in solubilityD. the hydration energy of sodium sulphate is less than its lattice energy.

Answer» Correct Answer - A::B
When the hydration energy is more than the lattice energy, the salt is soluble in water and vice versa.
892.

If the degree of ionization of water is `1.8xx10^(-9)` at `298K`. Its ionization constant will beA. `1.8xx10^(-16)`B. `1xx10^(-14)`C. `1xx10^(-16)`D. `1.67xx10^(-14)`

Answer» Correct Answer - A
`K_(a)=(K_w)/([H_(2)O])=(10^(-14))/(55.5)=1.8xx10^(-16)` .
893.

A sudden jum- between the values of second and third ionisation energies of an atom would be associated with the electronic configuration.A. `1s^(2),2s^(2)p^(6),3s^(1)`B. `1s^(2),2s^(2)p^(6),3s^(2)p^(1)`C. `1s^(2),2s^(2)p^(6),3s^(2)p^(2)`D. `1s^(2),2s^(2)p^(6),3s^(2)`

Answer» Correct Answer - D
`1s^(2)2s^(2)p^(6)3s^(2)`. In group III transition `e^(-)` is to be removed from stable configuration.
894.

A sudden large jump between the values of second and third ionisation energies of an element would be associated with the electronic configurationA. `1s^(2),2s^(2)p^(6),3s^(1)`B. `1s^(2),2s^(2)p^(6),3s^(2)p^(1)`C. `1s^(2),2s^(2)p^(6),3s^(2)p^(2)`D. `1s^(2),2s^(2)p^(6),3s^(2)`

Answer» Correct Answer - D
`1s^(2)2s^(2)p^(6)3s^(2)`. In group III transition `e^(-)` is to be removed from stable configuration.
895.

Which element having the following electronic configuration has minimum ionisation potential?A. `1s^(1)`B. `1s^(2),2s^(2)2p^(6)`C. `1s^(2),2s^(2)2p^(6),3s^(1)`D. `1s^(2),2s^(2)2p^(2)`

Answer» Correct Answer - C
`1s^(2)2s^(2)2p^(6)3s^(1)`. It belongs to IA group which has least ionisation potential and it decreases down the group.
896.

Which of the following hydrides have unusally high boiling points on account of intermolecular hydrogen bonding?A. `NH_(3)`B. `H_(2)O`C. `HF`D. All of these

Answer» Correct Answer - D
On account of high electronegativity, `N,O`, and `F` from strong intermolecular hydrogen bonds in their hydries.
897.

Which of the following elements cannot from strong `p_(pi)-p_(pi)` multiple bonds?A. `C`B. `N`C. `P`D. `O`

Answer» Correct Answer - C
`P` on account of relatively large size fails to form strong `p_(pi)-p_(pi)` multiple bonds.
898.

Which of the following elements have the most negative electron gain enthalpies corresponding to the largest release of enegry?A. Group `2` elementsB. Group`16`elementsC. Group `17`elementsD. Group`18`elements

Answer» Correct Answer - C
Halogen atoms, which have the oueter electron configuration `ns^(2)np^(5)`, have the most negative electron gain enthalpies because by gaining one extra electron, they form stable anions with noble gas configuration,…. `ns^(2)np^(6)`. Group `2` and group `18` elements on account of stable configuration have positive electron gain enthalpies corresponding to an absorption of energy.
899.

Electron gain enthalpies of free anions are alwaysA. zeroB. negativeC. positiveD. nonzero

Answer» Correct Answer - C
Enegry is always required to bring a negative charge (electron) closer to another negative charge (anion). So the addition of a second electron to a `1`-anion to from an ion with a `2-`charge is always endothermic.
900.

The general horizontal trend is that electron gain enthalpies become more negative (more enegry is released as an extra electron is added) from group `1A` through group `VII A` for a given period. Exceptions occur at the_________and________elements.A. `IIA`and`VA`B. `IIA`and`VIA`C. `IIIA`and`VA`D. `IIA`and`IVA`

Answer» Correct Answer - A
Elements of group `IIA` and `VA` have relatively stable outerlectron configuration `ns^(2)` and `ns^(2)np^(6)`, respectively.