1050 + Interview Questions in CLASS-11 IN GENERAL AWARENESS Page 21 InterviewSolution

1001.	_____ is a parasite of large intestine of human beings and causes the disease____A. Escherichia coli, amoebic dysenteryB. Entamoeba histolytica, amoebic dysenteryC. Plasmodium vivax, malariaD. Trypanosoma gambiense, sleeping sickness
Answer» Correct Answer - B Entamoeba histolytica resodes in the upper part of the human large intestine and causes the diease amoebic dysentery or amoebiasis. The symptoms of the disease are abdominal pain, repeated motions with blood and mucus.

Discussion

1002.	Dental formula in human beings isA. `2122//2122`B. `2114//2114`C. `2123//2124`D. `2123//2123`
Answer» Correct Answer - D Dental formula of adult human is `2123//2123`.

Discussion

1003.	_____ are important, decomposers that cause decay and decomposition of dead bodies of plants and animals.A. Saprophytic bacteriaB. Saprotrophic fungiC. Plants, like SarraceniaD. Both (a) and (b)
Answer» Correct Answer - D Sapeophytic bacteria are free living bacteria which obtain their food from organic remains, e.g., corpses, animal excreta, fallen leaves, vegetables, fruits, meat, jams, jellies, bread and other products of plant and animal origin. Aerobic breakdown og organic compounds is known as decay. In nature saprophytic bacteria along with saprotrophic fungi are the decomposers of organic remains.

Discussion

1004.	(a) Why are many zooflagellates important to human beings ? List any two such zooflagellates which cause disease in human beings. Name the disease as well. (b) Which zooflagellate inhabits the intestine of termites as a symbiont? What role does this organism play in the termite intestine ?
Answer» (a) Many zooflagellates are parasites and cause diseases in human beings. (i) Leishmania donovani. It causes kala-azar disease (visceral leishmaniasis). (ii) Trypanosoma gambiense. It causes sleeping sickness (Trypanosomiasis). (b) Trichonympha is a cellulose-digesting insect-gut zooflagellate which inhabits the intestine of termites as a symbiont. The termites devours wood but fails to digest it. This protozoans secretes glucosidases which convert cellulose into glucose. The digested food is shared by both the partners. Without Trichonympha, the termits starve and die.

Discussion

1005.	Fungal hypahe are soft and delicate structures. Still they are able to penetrate the timbers. How ?
Answer» Some fungi are known to grow on timbers. The delicate and soft hyphae of such fungi secrete exogenous enzymes which decompose the lignin and cutin. These hyphae penetrate the timber by decomposing and decaying the wood.

Discussion

1006.	Write few lines on the utility of hydrogen as a fuel.
Answer» Hydrogen as a fuel : → The heat of combustion of hydrogen is high i.e about 242kj/ mole. Hence hydrogen is used as industrial fuel. → The energy released by the combustion of dihydrogen is more than the petrol (3 times). → Hydrogen is major constituent in fuel gases like coal gas and water gas. → Hydrogen is also used in fuel cells for the generation of electric power. → 5% dihydrogen is used in CNG for running four-wheeler vehicles. → By hydrogen economy principle the storage and transportation of energy in the form of liquid (or) gaseous state. Here energy is transmitted in the form of dihydrogen and not as electric power.

1006.

Write few lines on the utility of hydrogen as a fuel.

Answer»

Hydrogen as a fuel :

→ The heat of combustion of hydrogen is high i.e about 242kj/ mole. Hence hydrogen is used as industrial fuel.

→ The energy released by the combustion of dihydrogen is more than the petrol (3 times).

→ Hydrogen is major constituent in fuel gases like coal gas and water gas.

→ Hydrogen is also used in fuel cells for the generation of electric power.

→ 5% dihydrogen is used in CNG for running four-wheeler vehicles.

→ By hydrogen economy principle the storage and transportation of energy in the form of liquid (or) gaseous state. Here energy is transmitted in the form of dihydrogen and not as electric power.

Discussion

1007.	In Entamoeba histolytica, the presence of chromatid bodies is characteristic ofA. precystic stageB. trophozoite stageC. mature binucleate stageD. both (a) and (b)
Answer» Correct Answer - A

Discussion

1008.	The cyanobacteria are also referred to as:-A. proistsB. golden algaeC. Slime mouldsD. blue-green algae
Answer» Correct Answer - D

Discussion

1009.	Which is wrong about viruses ?A. All are parasitesB. Antibiotics have no effect on themC. All of them have helical symmetryD. They have the ability to synthesise nucleic acids and proteins.
Answer» Correct Answer - C Some viruses have helical symmetry and some have polyhedral symmetry.

Discussion

1010.	Cyanobacteria are also referred to asA. Golden algaeB. Blue-green algaeC. ProtistsD. Slime Moulds.
Answer» Correct Answer - B Cyanobacteria are also referred to as Blue-green algae.

Discussion

1011.	______ bacteria oxidise various inorganic substances such as nitrates, nitrites and ammonia and use the released energy for ATP production. They play an important role in recycling of nutrients (N,P,Fe,S etc).A. Photosynthetic autotrophicB. Chemosyntherit cautotrophicC. ParasiticD. Saprophytic
Answer» Correct Answer - B Chemoautotrophic bacteria or chemosynthetic autotrophic bacteria are able to manufacture their organic food from inorganic raw materials with the help of energy derived from exergonic chemical reactions involving oxidation of an inorganic substance present in the external medium.

Discussion

1012.	Which bacteria oxidise various inorganic substances such as nitrates, nitrites and ammonia and use the released energy for their ATP production ?A. ArchaebacteriaB. Photosynthetic autotrophsC. Chemosynthetic autotrophsD. Heterotrophs
Answer» Correct Answer - C Chemosynthetic autotrophs bacteria oxidisc various inorganic substances such as nitrates, nitrites and ammonia and use the released energy for their ATP production.

Discussion

1013.	An organism with non - cellulosic cell wall and autotrophic nutrition would belong toA. MoneraB. ProtistaC. AnimaliaD. Fungi
Answer» Correct Answer - A An organism with non-cellulosic cell wall and autotrophic nutrition would belong to Monera.

Discussion

1014.	What is the genetic nature of wrinkled phenotype of pea seeds ?
Answer» rr is the genetic nature of the phenotypic wrinkled pea seeds.

Discussion

1015.	Which of the following statements is correctA. all bacteria are heterotrophicB. bacteria are either heterotrophic or chaemoautotrophicC. bacteria can also be photoautotrophicD. bacteria are either chemoautatrophic or photoautotrophic
Answer» Correct Answer - C

Discussion

1016.	Typhoid fever is caused byA. StreptococcusB. StaphylococcusC. SalmonellaD. Mycobacterium
Answer» Correct Answer - C

Discussion

1017.	Select the correct statement `(s)`.A. `Cr^(2+)` compounds are ionic.B. They are oxidised to `Cr^(3+)` by air.C. They are reducing agent in aqueous solution.D. None is correct.
Answer» Correct Answer - A::B::C The variability of oxidation states `(OS)`, a characteristic of transition elements `(TE)` arises out of incomplete filling of `d`-orbitals in such a way that their `OS` differ from each other by unity. `Cr` is most stable in `+3` and `6 OS`. Lower oxidation states of `TE` forms mostly ionic compounds. `Cr (Z = 24) rArr 3d^(5)4s^(1), Cr^(2+) rArr 3d^(4)` `Cr^(2+) rarr cr^(3+) + e^(-) [["Oxidation and thus"],["acts as reducing agent"]]` `[[3d^(4)],["cofiguration"],["less stable"]] [[3d^(3) "configuration is more"],["stable due to half-filled orbitals" ","],[i.e. t_(2g) "level".]]`

Discussion

1018.	In which of the following arrangements, the order is according to the property indicated against it?A. `IE_(1):O gt N gt C gt B`B. `Delta_(eg)H^(o+) ("with -ve sign"): Cl gt F gt Br gt I`C. Metallic radius: `Rb gt K gt Na gt Li`D. Ionic size: `F^(ɵ) gt Na^(o+) gt Mg^(2+) gt Al^(3+)`
Answer» Correct Answer - B::C::D are correct and factual statement. In `(a),IE_(1)` order should be `N gt O gt C gt B`

Discussion

1019.	Which of the following sets contain only isoelectronic species?A. `K^(o+), Ca^(2+), Sc^(3+), Cl^(ɵ)`B. `Zn^(2+), Ca^(2+), Ga^(3+), Al^(3+)`C. `Ti^(4+), Ar, Cr^(6+), V^(5+)`D. `P^(3-), S^(2-), Cl^(ɵ), K^(o+)`
Answer» Correct Answer - A::C::D a. `K^(o+)(19+1=18e^-), Ca^(2+)(20-2=18e^(-)), Sc^(3)(21-3=18e^(-)), Cl^(ɵ)(17+1=18e^(-))` Hence isoelectronic. b. Not isoelectronic `Zn^(+)(30-2=28r^(-),Ca^(2+)(20-2=18e^(-)),Ga^(3+)(31-3=28e^(-)),Al^(3+)(13-3=10e^(-))` c. Isoelectronic: `Ti^(4+)(22-4=18e^(-)),Ar(Z=18e^(-))`, `Cr^(6+)(24-6=18e^(-)),V^(5+)(23-5=18e^(-))` d. Isoelectronic: `p^(3-)(15+3=18e^(-)),S^(2-)(16+2=18e^(-))`, `Cl^(ɵ)(17+1=18e^(-)),K^(o+)(19-1=18e^(-))`

Discussion

1020.	The electronic configuration of given speices `(X)` is `1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(6)3d^(5), 4s^(1)`. This can be itsA. Cationic form `X^(o+)`B. Anionic form `X^(ɵ)`C. Excited stateD. Ground state
Answer» Correct Answer - A::D According to electronic configuration, the element is `Cr (Z = 24)`. Valence electronic configuration of `Cr` in ground state `= [Ar]3d^(4)4s^(1)`. Valence electronic confugration of `Cr` in excited state `= [Ar]3d^(5)4s^(1)`.

Discussion

1021.	Puccinia graminis tritici causesA. Brown rustB. Black rustC. Yellow rustD. White rust
Answer» Correct Answer - B Puccinia graminis tritici causes Black rust.

Discussion

1022.	Enzyme hexokinase is inhibited by excess glucose 6-P. It isA. Competitive inhibitionB. Feedback allosteric inhibitionC. Non-competitive inhibitionD. Positive feedback
Answer» Correct Answer - B Enzyme hexokinase is inhibited by excess glucose 6-P. It is feedback allosteric inhibition.

Discussion

1023.	How many number of CaCO3 moles are present in 200gms of CaCO3?
Answer» n = weight/GMW = 200/100 [∵ GMW(CaCO₃) = 100 = 2

1023.

How many number of CaCO3 moles are present in 200gms of CaCO3?

Answer»

n = weight/GMW

= 200/100 [∵ GMW(CaCO₃) = 100

= 2

Discussion

1024.	What is plaster of paris? Mention its uses.
Answer» The hemi hydrate of calcium sulphate is called plaster of paris. Uses : → It is used in dentistry → It is used in the bone fractures (or) sprain conditions → It is used in manufacturing of statues.

1024.

What is plaster of paris? Mention its uses.

Answer»

The hemi hydrate of calcium sulphate is called plaster of paris.

Uses :

→ It is used in dentistry

→ It is used in the bone fractures (or) sprain conditions

→ It is used in manufacturing of statues.

Discussion

1025.	Derive the Kp and Kc relations for the reaction.PCl5(g) ⇋ PCl3(g) + Cl2(g)
Answer» PCl₅_(g) ⇋ PCl_3(g) + Cl_2(g) K_P = K_C(RT)_∆n ∆n = n_P – n_R = 2 – 1 = 1 ∆n = +Ve ∴ K_P > K_C

1025.

Derive the Kp and Kc relations for the reaction.PCl5(g) ⇋ PCl3(g) + Cl2(g)

Answer»

PCl₅_(g) ⇋ PCl_3(g) + Cl_2(g)

K_P = K_C(RT)_∆n

∆n = n_P – n_R = 2 – 1 = 1

∆n = +Ve

∴ K_P > K_C

Discussion

1026.	The correct sequence which shows decreasing order of the ionic radii of the element isA. `Al^(3+)gtMg^(2+)gtNa^(+)gtFgtO^(2-)`B. `Na^(+)gtMg^(2+)gtAl^(3+)gtO^(2-)gtF^(-)`C. `Na^(+)gtF^(-)gtMg^(2+)gtO^(2-)gtAl^(3+)`D. `O^(2-)gtF^(-)gtNa^(+)gtMg^(2+)gtAl^(3+)`
Answer» Correct Answer - D `O^(2-),F^(-),Na^(2+),Mg^(2+)` and `Al^(3+)` are isoelectronic species , for isoelectronic species , `r prop 1/Z` Thus , the larger the atomic number (effective nuclear charge) the smaller is the ionic radii.

Discussion

1027.	Which of the following has the largest ionic raduis?A. `Na^(+)`B. `Ni^(+)`C. `Cs^(+)`D. `Mg^(+2)`
Answer» Correct Answer - C `Cs^(+)` has the largest ionic radius in the periodic table

Discussion

1028.	Which of the following atoms should have the largest size?A. `Cs`B. `Fr`C. `Kr`D. `Xe`
Answer» Correct Answer - B Fr has the largest ionic in the period table

Discussion

1029.	Which one of the following is expected to have largest size?A. `F^(-)`B. `O^(-2)`C. `Al^(+3)`D. `N^(-3)`
Answer» Correct Answer - D Due to having three atomic size increases . `F^(-) = 9+1 = 10` electrons, `O_(-2) = 8+2=10` electrons `Al^(+3) = 13-3 = 10` electrons `N^(3-) = 7+3 =10e^(-)` Because electrostaic force between nucleus and `bar(e)` cloud is least in nitrogen.

Discussion

1030.	Which of the following has largest radius?A. `Cs^(+)`B. `Li^(+)`C. `Na^(+)`D. `K^(+)`
Answer» Correct Answer - A Ionic radii increase in a group.

Discussion

1031.	What is Poly Dispersity Index?
Answer» Poly Dispersity Index (PDI) : The ratio between weight average molecular mass (bar M_w) and the number average molecular mass (bar M_n) of a polymer is called Poly Dispersity Index (PDI).

Discussion

1032.	Assertion: Of the elements , helium has the highest value of first ionisation enthalpy. Reason : Helium has the most positive electron gain enthalpy of all the elements.A. If both assertion and reason are true and reason is the correct explanation of assertionB. If the assertion and reason are true but reason is not the correct explanation of assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true.
Answer» Correct Answer - C Correct Reason: Helium is the smallest insert gas.

Discussion

1033.	Which one of the following arrangements represents the correct order of electron gain enthalpy of the given atomic species?A. `Cl lt F lt S lt O`B. `S lt O lt Cl lt F`C. `O lt S lt F lt Cl`D. `F lt Cl lt O lt S`
Answer» Correct Answer - C Halogens have very high electron affinity. It may be rated that the electrons affinity of fluorine is unexpectedly low `(lt Cl)`. This may perheps be due to small size of `F` atom. The value of electron gain enthalpies for `Cl, F, S` and `O` are respectively `349,333,200` and `142 kJ//mol` hence correct order is `Cl gt F gt S gt O`.

Discussion

1034.	Which of the following element has the highest value of electron affinity?A. CarbonB. OxygenC. FluorineD. Neon
Answer» Correct Answer - C Halogens have the highest `EA`.

Discussion

1035.	In the ground state of cobalt atom `(Z=27)`, there are ..... Unpaired electrons and thus the atom is ....A. `3`,paramageneticB. `2`, paramageneticC. `3` diamageneticD. `2` diamagnetic
Answer» Correct Answer - B `Co-[Ar]3d^(7)4s^(2)`, it has 3 unpaired `e^(-)` so it is a paramagnetic.

Discussion

1036.	`A rarr A^(+)+e,E_(1)` and `A^(+) rarr A^(2+)+e,E_(2)`. The energy requried to pull out the two electrons are `E_(1)` and `E_(2)` respectively. The correct relationship between two energy would beA. `E_(1) gt E_(2)`B. `E_(1) = E_(2)`C. `E_(1) lt E_(2)`D. `E_(1) != E_(2)`
Answer» Correct Answer - C `E_(1) lt E_(2)` because second `IE` is greater than first `IE`.

Discussion

1037.	Which of the following relation is correct with respect first (I) and second (II) ionisation of sodius and magnesium?A. `I_(mg)=II_(Na)`B. `I_(Na)gtI_(Mg)`C. `II_(Mg)gtII_(Na)`D. `II_(Na)gtII_(Mg)`
Answer» Correct Answer - A Due to the large size of group `IA` elements, the outermost electron is far from the nucleus and can easily be removed. Their ionisation eneries or ionisation potentials are relatively low. Ionisation potential `(eV) = {:(Li,Na,K,Rb,Cs),(5.4,5.1,4.3,4.2,3.9):}`.

Discussion

1038.	The statement that is not correct for periodic classification of elements isA. The properties of elements are periodic function of their atomic numbersB. Non-metallic elements are less in number than metallic elementsC. For transition elements,the 3d orbitals are filled with electrons after 3p orbitals and before 4 s orbitalsD. The first ionization enthalpies of elements generally increase with increase in atomic number as we go along a period.
Answer» Correct Answer - C According to aufbau principle,"in the ground state of the atoms,the orbitals are filled in order of their increasing energies".The increasing order of energy acccording to (n+1) rule is:1s,2s2p,3s,3p,4s,3d,4p,5s….etc. Therefore,the 3d orbitals are filled with electrons after 4s orbitals and before 4p orbitals.

Discussion

1039.	Which of the following statements is not correct for the periodic classification of elements?A. The properties of elements are the periodic functions of their atomic number.B. Non-merallic elements are less in number than merallic elements.C. For transition elements,the last electro entres into(n-2)d-subshell.D. None of these
Answer» Correct Answer - C The last electron in transition elements enters into (n-1)d-subshell.

Discussion

1040.	The common name of pea is simpler than its botanical (scientific) name Pisum sativum why then is the simpler common name not used instead of the complex scientific/botanical name is biology ?
Answer» Common name pea is not a scientific name and in different parts of the world pea word is not know and as per ICBN only scientific names are valid names.

Discussion

1041.	Lanthanoid contraction is caused due to:A. The imperfect shielding on outer electrons by 4f -electrons from the nuclear chargeB. The aapreciable shielding on outer electrons by 4f-electrons from the nuclear chargeC. The aapreciable shielding on outer electrons by 5d-electrons from the nuclear chargeD. The same effective nuclear charge from Ce to Lu
Answer» Correct Answer - A It is the reason for given factor.

Discussion

1042.	Lanthanoid contraction is caused due to:A. The imperfect shielding on outer electrons by 4f -electrons from the nuclear chargeB. The aapreciable shielding on outer electrons by 4f-electrons from the nuclear charge C. The aapreciable shielding on outer electrons by 5d-electrons from the nuclear chargeD. The same effective nuclear charge from Ce to Lu
Answer» Correct Answer - A It is the reason for given factor.

Discussion

1043.	The first `(IE_(1))` and second `(IE_(2))` ionisation energies `(k J mol^(-1))` of a new elements designated by roman numerals are shown below: `{:(,,IE_(1),IE_(2),),(I,,2370,5250,),(II,,520,7300,),(III,,900,1800,),(IV,,1700,3400,):}` Which of the above elements is likely to be : a. A reactive metal b. A reactive non-metal c. a noble gas d. A metal that forms a stable binary halide of the formula `AX_(2)` (`X=` the halogen).A. I,2372,5251B. II,520,7300C. III,900,1760D. IV,1680,3380
Answer» Correct Answer - B As alkali metals have the lowest `IE_(1)` value in their respective periods and also there is a large jump between `IE_(1) and IE_(2)` due to the removal of second electron from the noble gas core,therefore,out of the given `IE_(1)`and `IE_(2)` values,(II) belongs to alkali metals.

Discussion

1044.	The ionization energies of Li and Na are `520 kJ mol ^-1 and 495 kJ mol ^-1` respectively. The energy required to convert all the atoms present in 7 mg of Li vapours and 23 mg of sodium vapours to their respective gaseous captions respectively are :A. 52 J,49.5 JB. 520 J,495 JC. 49.5 J,52 JD. 495 J,520 J
Answer» Correct Answer - B No. of moles of Li=`(7)/(1000X7)=10^(-3)` No. of moles of NA=`(23)/(1000xx23)=10^(-3)` `therefore` The amount of energies required for `10^(-3)` mole each of Li and Na are 520 `KJX10^(-3) and 495 KJ X10^(-3)` or 520 J and 495 J respectibely.

Discussion

1045.	Few elements are matched with their successive ionisation energies,Identify the elements. A. X-A noble gas ,Y-Alkali metal,Z-Alkaline earth metalB. X-Alkali metal,Y-A noble gas,Z-Alkaline earth metalC. X-Alkaline earth metal,Y-Alkali metal,Z-A noble gasD. X-Alkali metal,Y-Alkaline earth metal,Z-A noble gas
Answer» Correct Answer - A X has highest `IE_(1)` and `IE_(2)` hence,it is a noble gas Y has low `IE_(1)`but very high `IE_(2)` hence,it is an alkali metal.Z has low `IE_(1)`than `IE_(2)` and `IE_(2)` is even lower than `IE_(2)` of alkali metal hence,it is an alkaline earth metal.

Discussion

1046.	Ionization enthalpies of transition metals areA. Intermediate between those of s- and p- block elementsB. more than p-block elementsC. lower than s-block elements.D. lower than s-block elements
Answer» Correct Answer - A

Discussion

1047.	First and second ionisation enthalpies(in KJ/mol) of few elements are given below: Which of the above elements will form halides with formula `MX_(2)`?A. (i) and (ii)B. (i) and (iii)C. (ii)and(iii)D. (i) and (iv)
Answer» Correct Answer - C (ii)is a reactive metal from second group,and (iii)is a reactive non-metal from `17^(th)` group. For second group elements,the difference in successive IE is less.The compound formed will be `MX_(2)`

Discussion

1048.	Few values of enthalpies are given below: O=-141 KJ mol^(-1)F=-328 KJ mol^(-1) S=-200 KJ mol^(-1) Cl=-349 KJ mol^(-1) What do these values show?A. Ionisation enthalpyB. Bond enthalpyC. Electron gain enthalpyD. Hydration enthalpy
Answer» Correct Answer - C Negative value of electron gain enthalpy of is more than of oxygen and for Cl it is more than that of fluorine.

Discussion

1049.	The first `(Delta_(i)H_(1)` and second `(Delta_(i)H_(2)` ionization enthalpies (in kJ/mol) and electron gain enthalpy (in kJ/mol) of few elements are given below: `{:("Elements",Delta_(i)H_(1),Delta_(i)H_(2),Delta_(eg)H),(I,520,7300,-60),(II,1681,3374,-328),(III,899,1757,+48),(IV,2372,5251,+48):}` Which of the following is likely to be an alkali metal?A. I and IVB. V and IIC. II and VD. IV and V
Answer» Correct Answer - C I represents Li,II represents K,III represents Br,IV represents iodine,V represents He. So,amongst these,II represents ost reactive metal and V represents least reactive non-metal.

Discussion

1050.	Discuss how classification systems have undergone several changes over a period of time?
Answer» The classification systems have undergone several changes with time. The first attempt of classification was made by Aristotle. He classified plants as herbs, shrubs, and trees. Animals, on the other hand, were classified on the basis of presence or absence of red blood cells. This system of classification failed to classify all the known organisms. Therefore, Linnaeus gave a two kingdom system of classification. It consists of kingdom Plantae and kingdom Animalia. However, this system did not differentiate between unicellular and multicellular organisms and between eukaryotes and prokaryotes. Therefore, there were large numbers of organisms that could not be classified under the two kingdoms. To solve these problems, a five kingdom system of classification was proposed by R.H Whittaker in 1969. On the basis of characteristics, such as cell structure, mode of nutrition, presence of cell wall, etc., five kingdoms, Monera, Protista, Fungi, Plantae, and Animalia were formed.

Discussion

Explore topic-wise InterviewSolutions in .

_____ is a parasite of large intestine of human beings and causes the disease____A. Escherichia coli, amoebic dysenteryB. Entamoeba histolytica, amoebic dysenteryC. Plasmodium vivax, malariaD. Trypanosoma gambiense, sleeping sickness

Dental formula in human beings isA. `2122//2122`B. `2114//2114`C. `2123//2124`D. `2123//2123`

_____ are important, decomposers that cause decay and decomposition of dead bodies of plants and animals.A. Saprophytic bacteriaB. Saprotrophic fungiC. Plants, like SarraceniaD. Both (a) and (b)

(a) Why are many zooflagellates important to human beings ? List any two such zooflagellates which cause disease in human beings. Name the disease as well. (b) Which zooflagellate inhabits the intestine of termites as a symbiont? What role does this organism play in the termite intestine ?

Fungal hypahe are soft and delicate structures. Still they are able to penetrate the timbers. How ?

Write few lines on the utility of hydrogen as a fuel.

In Entamoeba histolytica, the presence of chromatid bodies is characteristic ofA. precystic stageB. trophozoite stageC. mature binucleate stageD. both (a) and (b)

The cyanobacteria are also referred to as:-A. proistsB. golden algaeC. Slime mouldsD. blue-green algae

Which is wrong about viruses ?A. All are parasitesB. Antibiotics have no effect on themC. All of them have helical symmetryD. They have the ability to synthesise nucleic acids and proteins.

Cyanobacteria are also referred to asA. Golden algaeB. Blue-green algaeC. ProtistsD. Slime Moulds.

______ bacteria oxidise various inorganic substances such as nitrates, nitrites and ammonia and use the released energy for ATP production. They play an important role in recycling of nutrients (N,P,Fe,S etc).A. Photosynthetic autotrophicB. Chemosyntherit cautotrophicC. ParasiticD. Saprophytic

Which bacteria oxidise various inorganic substances such as nitrates, nitrites and ammonia and use the released energy for their ATP production ?A. ArchaebacteriaB. Photosynthetic autotrophsC. Chemosynthetic autotrophsD. Heterotrophs

An organism with non - cellulosic cell wall and autotrophic nutrition would belong toA. MoneraB. ProtistaC. AnimaliaD. Fungi

What is the genetic nature of wrinkled phenotype of pea seeds ?

Which of the following statements is correctA. all bacteria are heterotrophicB. bacteria are either heterotrophic or chaemoautotrophicC. bacteria can also be photoautotrophicD. bacteria are either chemoautatrophic or photoautotrophic

Typhoid fever is caused byA. StreptococcusB. StaphylococcusC. SalmonellaD. Mycobacterium

Select the correct statement `(s)`.A. `Cr^(2+)` compounds are ionic.B. They are oxidised to `Cr^(3+)` by air.C. They are reducing agent in aqueous solution.D. None is correct.

In which of the following arrangements, the order is according to the property indicated against it?A. `IE_(1):O gt N gt C gt B`B. `Delta_(eg)H^(o+) ("with -ve sign"): Cl gt F gt Br gt I`C. Metallic radius: `Rb gt K gt Na gt Li`D. Ionic size: `F^(ɵ) gt Na^(o+) gt Mg^(2+) gt Al^(3+)`

Which of the following sets contain only isoelectronic species?A. `K^(o+), Ca^(2+), Sc^(3+), Cl^(ɵ)`B. `Zn^(2+), Ca^(2+), Ga^(3+), Al^(3+)`C. `Ti^(4+), Ar, Cr^(6+), V^(5+)`D. `P^(3-), S^(2-), Cl^(ɵ), K^(o+)`

The electronic configuration of given speices `(X)` is `1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(6)3d^(5), 4s^(1)`. This can be itsA. Cationic form `X^(o+)`B. Anionic form `X^(ɵ)`C. Excited stateD. Ground state

Puccinia graminis tritici causesA. Brown rustB. Black rustC. Yellow rustD. White rust

Enzyme hexokinase is inhibited by excess glucose 6-P. It isA. Competitive inhibitionB. Feedback allosteric inhibitionC. Non-competitive inhibitionD. Positive feedback

How many number of CaCO3 moles are present in 200gms of CaCO3?

What is plaster of paris? Mention its uses.

Derive the Kp and Kc relations for the reaction.PCl5(g) ⇋ PCl3(g) + Cl2(g)

The correct sequence which shows decreasing order of the ionic radii of the element isA. `Al^(3+)gtMg^(2+)gtNa^(+)gtFgtO^(2-)`B. `Na^(+)gtMg^(2+)gtAl^(3+)gtO^(2-)gtF^(-)`C. `Na^(+)gtF^(-)gtMg^(2+)gtO^(2-)gtAl^(3+)`D. `O^(2-)gtF^(-)gtNa^(+)gtMg^(2+)gtAl^(3+)`

Which of the following has the largest ionic raduis?A. `Na^(+)`B. `Ni^(+)`C. `Cs^(+)`D. `Mg^(+2)`

Which of the following atoms should have the largest size?A. `Cs`B. `Fr`C. `Kr`D. `Xe`

Which one of the following is expected to have largest size?A. `F^(-)`B. `O^(-2)`C. `Al^(+3)`D. `N^(-3)`

Which of the following has largest radius?A. `Cs^(+)`B. `Li^(+)`C. `Na^(+)`D. `K^(+)`

What is Poly Dispersity Index?

Which one of the following arrangements represents the correct order of electron gain enthalpy of the given atomic species?A. `Cl lt F lt S lt O`B. `S lt O lt Cl lt F`C. `O lt S lt F lt Cl`D. `F lt Cl lt O lt S`

Which of the following element has the highest value of electron affinity?A. CarbonB. OxygenC. FluorineD. Neon

In the ground state of cobalt atom `(Z=27)`, there are ..... Unpaired electrons and thus the atom is ....A. `3`,paramageneticB. `2`, paramageneticC. `3` diamageneticD. `2` diamagnetic

`A rarr A^(+)+e,E_(1)` and `A^(+) rarr A^(2+)+e,E_(2)`. The energy requried to pull out the two electrons are `E_(1)` and `E_(2)` respectively. The correct relationship between two energy would beA. `E_(1) gt E_(2)`B. `E_(1) = E_(2)`C. `E_(1) lt E_(2)`D. `E_(1) != E_(2)`

Which of the following relation is correct with respect first (I) and second (II) ionisation of sodius and magnesium?A. `I_(mg)=II_(Na)`B. `I_(Na)gtI_(Mg)`C. `II_(Mg)gtII_(Na)`D. `II_(Na)gtII_(Mg)`

The common name of pea is simpler than its botanical (scientific) name Pisum sativum why then is the simpler common name not used instead of the complex scientific/botanical name is biology ?

Ionization enthalpies of transition metals areA. Intermediate between those of s- and p- block elementsB. more than p-block elementsC. lower than s-block elements.D. lower than s-block elements

First and second ionisation enthalpies(in KJ/mol) of few elements are given below: Which of the above elements will form halides with formula `MX_(2)`?A. (i) and (ii)B. (i) and (iii)C. (ii)and(iii)D. (i) and (iv)

Few values of enthalpies are given below: O=-141 KJ mol^(-1)F=-328 KJ mol^(-1) S=-200 KJ mol^(-1) Cl=-349 KJ mol^(-1) What do these values show?A. Ionisation enthalpyB. Bond enthalpyC. Electron gain enthalpyD. Hydration enthalpy

Discuss how classification systems have undergone several changes over a period of time?

_ is a parasite of large intestine of human beings and causes the diseaseA. Escherichia coli, amoebic dysenteryB. Entamoeba histolytica, amoebic dysenteryC. Plasmodium vivax, malariaD. Trypanosoma gambiense, sleeping sickness